sin𝜃cos𝜃tan𝜃 - white rose maths...powerpoint presentation author test created date...
TRANSCRIPT
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• sin 𝜃 cos 𝜃 tan 𝜃•
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𝟏
𝟐𝒂𝒃𝐬𝐢𝐧𝑪
𝑥
𝑎
𝑏
°
𝑎 𝑏𝑎
𝑏
𝑥𝑥
𝑥
𝑥𝑥
𝑎 𝑏
𝑐
𝑎 = 𝑏 =𝑐 =
𝑎 = 𝑏 =𝑐 =
𝑎 =𝑏
𝑐𝑥
𝑥 =
𝑥
4 =𝑥
204 =
20
𝑥2.8 =
5.3
𝑥2.8 =
𝑥
5.3
𝑥
tan 𝜃 =𝑜𝑝𝑝
𝑎𝑑𝑗
tan ? =𝑥
?? × tan ? = 𝑥
? = 𝑥
𝑥 tan 28 =𝑥
3× tan 28 = 𝑥
1.6 = 𝑥
𝑥
tan 31 =?
?𝑥 × tan31 = ?
𝑥 =?
tan 31𝑥
=𝑥 =
𝑦
𝑥.
𝑥
𝑥
√
sin 63.4 =8
4√5
tan 26.6 =4
8
=
sin 𝜃 =
𝑥
sin−1 𝑥 cos−1 𝑥 tan−1 𝑥
sin 𝑥 sin−1 𝑥
tan 𝑥 =?
?𝑥 = tan−1
?
?𝑥 = ?
𝜃
sin 𝜃 = cos𝜃 = tan 𝜃 =
𝜃
= 𝜃
sin 𝜃 =8
10
𝜃 = sin−18
10
𝜃 =
= ==
122 + 52 = 132 62+ ?2 = 100 162 − 122 = ? 2
=
𝑥
𝑥𝑥 °
𝑥
30°, 60° 45°
𝑥 𝑦
√3
𝑥,
sin 𝑥 =?
?=
1
2
sin ? =1
2
𝑥 =
𝑥√
𝑥
𝑥 𝑥
𝑦
𝑦
0°
90°
𝑥
tan 90°
𝑥sin 0 = 0
opp
hyp=
𝑥
𝑥
tan 0 = 0 cos 0 = 1
𝑥
𝑥)
𝑥
𝑥
𝑥
sin 90 = cos 90 = tan 90 =
=
=
=
1
2× ×
=1
2𝑎𝑏 sin 𝐶
=1
2𝑏𝑐 sin𝐴
=1
2𝑎𝑐 sin𝐵
= = √3
𝜃
4𝑥
𝑥
𝜃
ℎ = 𝑎 sin𝐵
ℎ =
𝑎 sin𝐵 =
𝑎
sin ?=
?
sin 𝐵
ℎ𝑏𝑎
𝑡
sin 105=
25
sin ?
sin 𝐶
𝑐
𝑎
sin 𝐴=
𝑏
sin 𝐵
===
𝑎
sin 𝐴=
𝑏
sin 𝐵
sin 𝐴
𝑎=
sin 𝐵
𝑏
𝜃
𝜃
sin 𝜃
3.8=
sin 93
7sin 𝜃 =
sin 93
7
sin 𝜃 =
𝜃 =
𝑎
𝑐
ℎ𝑏
𝑎
𝑐
𝑑 𝑐 − 𝑑
ℎ2 𝑎2 = 𝑏2 + 𝑐2 − 2𝑐𝑑
cos𝐴 =𝑑
𝑏bcos 𝐴 = 𝑑
bcos𝐴 = 𝑑 𝑎2 = 𝑏2 + 𝑐2 − 2𝑐𝑑𝑎2 = 𝑏2 + 𝑐2 − 2𝑏𝑐 cos 𝐴
ℎ2
𝑏 𝑑
ℎ2 = 𝑎2 − (𝑐 − 𝑑) 2
ℎ2 = 𝑎2 − 𝑐2 + 2𝑐𝑑 − 𝑑2
𝑎2 = 𝑏2 + 𝑐2 − 2𝑏𝑐 cos𝐴𝑏2 = 𝑎2 + 𝑐2 − 2𝑎𝑐 cos𝐵
cos𝐶
𝑐
?2 = ?2+ ?2 − 2 × 13 × 11 × cos𝐴= 290 − ? cos𝐴cos𝐴 = 290 − ?
cos 𝐴 =?
?𝐴 = cos−1 ?
cos𝐴
B
= °= °
𝑏𝜃 𝜃
=