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  • 7/29/2019 Snap paper solution

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    SNAP 2008 - ACTUAL PAPER Page 1MBATest PrepMBATest Prep

    SNAP 2009

    Answers and Explanations1 b 21 d 41 c 61 b 81 b 101 b 121 c

    2 c 22 NA 42 c 62 a 82 a 102 b 122 a

    3 b 23 d 43 c 63 a 83 c 103 c 123 a

    4 a 24 b 44 c 64 a 84 a 104 b 124 a

    5 c 25 c 45 a 65 b 85 NA 105 a 125 b

    6 d 26 d 46 c 66 d 86 a 106 d 126 b

    7 d 27 d 47 a 67 d 87 b 107 c or b 127 b

    8 b 28 b 48 b 68 c 88 a 108 c 128 d

    9 b 29 b 49 a 69 d 89 d 109 a 129 b

    10 a 30 a 50 a 70 b 90 c 110 b 130 c

    11 b 31 d 51 b 71 b 91 b 111 b 131 d

    12 d 32 b 52 d 72 a 92 b 112 b 132 b

    13 d 33 c 53 d 73 a 93 c 113 c 133 c

    14 a 34 b 54 b 74 c 94 d 114 b 134 d

    15 a 35 d 55 a 75 b 95 b 115 d 135 b16 a 36 c 56 c 76 d 96 d 116 b

    17 b 37 c 57 c 77 a 97 a 117 d

    18 b 38 d 58 d 78 b 98 d 118 d

    19 b 39 b 59 b 79 c 99 d 119 c

    20 d 40 c 60 b 80 b 100 b 120 d

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    SNAP 2008 - ACTUAL PAPERPage 2MBATest PrepMBATest Prep

    1. b We can only find the duration of reported breakdownfrom the above given graph but cannot find the actualloss of production because we do not know the ac-tual production.

    2. c Suppose consecutive pages, numbered n to m aremissing. The only information given is that the sum ofnumbers m, m + 1, m + 2, .. n is 9808. As there is noclue on the problem statement for the values of we do

    not know the values n or m or (n m), elimination ofthe options is the only way to solve this problems. Aswe are given that consecutive pages are missing, weeliminate options (a) as it talks about a single page,numbered 9808. Consider option (c). The sum of num-bers from 291 to 322 is:

    322 323 290 291291 292 293 .... 322

    2 2

    + + + + =

    = 9808.Clearly, option (c) is correct.

    3. b 2 + 12 = 3

    3 + 32 = 1212 + 52 = 3737 + 72 = 86 ..... and so on.Hence there should be 12 in place of 13.

    4. a The two trawlers move in perpendicular directions,as shown below.

    Trawler2

    O

    t=1/2 h r

    t=3/4 hr

    Let the speeds (in km/h) of the two trawlers be x and

    y respectively. After1

    2 hours, the distances covered

    by them arex

    km2

    andy

    km2

    . We have:

    2 22x y 17

    2 2

    + =

    Or

    2 2 2x + y = 34 (1)

    After3

    4hours, one of the trawlers is 10.5 km farther

    from the origin than the other one. We can write:

    3 x 3y=10.5

    4 4 Or

    x- y 14= (2)Solving the two equations, we get x and y as 16 km/hand 30km/h.

    5. c

    Number Of Adult Residents

    Hotel 1- Feb -98 1-Jul-98 Increase

    V 96 114 18.75%

    W 39 55 41.02%

    X 131 139 6.10%

    Y 64 96 50%

    Z 167 193 15.56%

    At 50% increase, hotel Y observed the greatest in-crease in the total number of adult residents.

    6. d From statement I alone, we get the common differ-ence but nothing can be said about the 57 th term.From statement II alone, we get the tenth term butnothing can be said about the 57th term as we do notknow the common difference.Combing both the statement we can answer we canderive both the common difference and the first termof the series.

    7. d 4 21Hectare 10 m=Area of the square field =

    ( )24 2 22624.40 16.4hectare 16.4025 10 m 405 m

    160= = =

    Side of the Square =405 mPerimeter = 4 405 = 1620 mCost of surrounding it with a railing

    =1

    1620 Rs.4054

    =

    Hence (d) is the correct answer.

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    SNAP 2008 - ACTUAL PAPER Page 3MBATest PrepMBATest Prep

    8. bh

    60 m

    300

    x

    600

    We have two equations in variables h and x.

    h= tan60= 3

    x(1)

    And,

    h 1= tan30=

    x 60 3+

    Eliminating x from the two equations, we get:

    60h = = 51.96m

    13

    3

    Hence option (b) is correct.

    For Questions 9 12

    From the given data, we can find out the exact number ofpersons who do not watch any movies. For example, in city A:The percentage of persons who watch movies = 100 60 =40%

    The total number of persons in city A =2400

    100 600040

    =

    The total number of persons in city A, who dont watch

    movies =6000 60

    3600100

    = .

    Similarly, we can find for the other cities as shown in thefollowing table.

    City No Movies One or More Movies

    A 3600 2400

    B 750 3000

    C 13600 2400

    D 3300 2700

    E 24000 8000

    9.b There are 13600 persons who watch less than onemovie in a week. Hence (b) is correct.

    10. a The number of persons who do not watch movies isthe highest, 24000, in city E. Hence (a) is correct.

    11. b In city D, the number of movie watchers is 2700, whichis the second lowest amongst the 5 cities. Henceoption (b) is correct.

    12. d This is calculated as: 3600+ 750+ 13600+ 3300+24000= 45250. Hence(d) is correct.

    13. d In this series we see that a is written once, b twice,c thrice and so on... any alphabet is written numberof times equivalent to its position value. Hence, 288th

    term will be x as sum of 1st 23 natural numbers is 276,and the next 24 terms will be all x.

    14. a The inequality 2p + 5 5p+14< can also be written as

    2p 5p 9 0 < . Find the roots of the quadratic equa-

    tion 2p 5p 9 0 = . The roots are:

    5 61 5 61,2 2+ Or 6.4 and14.

    Hence the inequality can be written as:

    (p 6.4)(p + 1.4) 0