soil mechanics_lecture_stresses

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    302

    //

    .

    2013

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    : , /

    :

    o

    o

    o

    o

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    1. ( )

    2. /

    +

    +

    =

    = = , =

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    o () () :

    () :

    wwsat hz +=

    o () 2 :

    1. = ()

    2.

    = ()

    '

    u +=

    o () :

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    () :

    :

    =

    = + (+)

    = ( )

    = =

    ( )zhu ww +=

    , , .

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    wwsat hz += ( )zhu ww += =

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    +

    :

    =

    dTcosh4

    dwc

    2

    =

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    d)(hhcsatbulk

    ++= du w= =

    ()

    ()

    ()

    +++

    cwhu =

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    ,

    .

    1.5 m

    2.5 m

    5.0 m

    GS

    GWT Sand

    Clay

    dry = 1.70 t/m3

    sat = 1.85 t/m3

    sat = 2.00 t/m3

    Sand

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    1.5 m

    2.5 m

    5.0 m

    GS

    GWT Sand

    Clay

    dry = 1.70 t/m3

    sat = 1.85 t/m3

    sat = 2.00 t/m3

    1

    2

    3

    4

    v (t/m2)u (t/m2)v (t/m

    2)Point

    0001

    2.55-0=2.5501.7x1.5=2.552

    7.175-2.5=4.6751x2.5=2.52.55+1.85x2.5=7.1753

    17.175-7.5=9.6751x7.5=7.57.175+2.0x5.0 =17.1754

    Sand

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    ( )

    /

    +

    +

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    ()

    (/2)

    a = ?

    a = ?

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    ()

    .

    ()

    o

    o

    /

    , (/)

    = /2 (/)

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    .

    . .

    (/2)

    a = ?

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    (/2)

    .

    (/2)

    .

    =

    , ,

    o

    o

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    :

    o = 1 = 2.5

    , :

    o () 2.5/ ()

    o () 2.5/ ()

    = /200

    a

    Total number of divisions

    within the chart = 200

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    ():

    =

    GSq (t/m2)

    a

    zElev.

    qnet = q

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    , ,

    .

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    At point (a)

    (t/m2)f(r/z)r/zr (m)z (m)Load (t)Load

    0.0180.01531.7211.186.550P1

    0.0810.02291.54106.5150P2

    0.0991a

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    (t/m2)f(r/z)r/zr (m)z (m)Load (t)Load

    0.0070.0062.1814.146.550P1

    0.0540.01531.7211.186.5150P2

    0.0611b

    At point (b)

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    (t/m2)f(r/z)r/zr (m)z (m)Load (t)Load

    0.0180.01531.7211.186.550P1

    0.0130.00382.4315.86.5150P2

    0.0311c

    At point (c)

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    qnet = q h = 20 1.70x1.0 = 18.3 t/m2

    Use Newmarks chart

    z = 5.5 m = 1 = 2.5 cm

    L = 10 m 10x2.5/5.5 = 4.54 cm, B = 10 m 10x2.5/5.5 = 4.54 cm,

    na = 128 2a = n/200 (qnet) = 128/200 x 18.3 = 11.7 t/m2

    nb = 74 2b = n/200 (qnet) = 74/200 x 18.3 = 6.77 t/m2

    nc = 47 2c = n/200 (qnet) = 47/200 x 18.3 = 4.3 t/m2

    abc

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    :

    a =1a +2a = 0.099 + 11.7 = 11.8 t/m2

    b =1b +2b = 0.061 + 6.77 = 6.83 t/m2

    c =1c +2c = 0.031 + 4.3 = 4.33 t/m2