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Solutions. Definitions. Solution - homogeneous mixture. Solute - substance that dissolves in a solvent and is said to be soluble. Solvent - present in greater amount and dissolves solute. - PowerPoint PPT Presentation

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Page 1: Solutions

Solutions

Page 2: Solutions

Definitions

• Solution - Solution - homogeneous mixture

Solvent Solvent - present in greater amount and dissolves solute

Solute Solute - substance that dissolves in a solvent and is said to be soluble

Page 3: Solutions

Universal Solvent is Water b/c almost everything dissolves in water

Most common solvent among liquids is water

Solute Solute - KMnO4 Solvent Solvent - H2O

Page 4: Solutions

Solvation- process of dissolving

solute particles are separated and pulled into solution (microscopic level)

solute particles are surrounded by solvent particles

Page 5: Solutions

Solvation- process of dissolvingIf you shake or stir the solution it increases the rate of solvation by breaking up solute and surrounding it with solvent

What else can speed up the rate of solvation?

Page 7: Solutions

NONPOLAR

NONPOLAR

POLAR

POLAR

““Like Dissolves Like”Like Dissolves Like”

Non polar solutes are more soluble Non polar solutes are more soluble in nonpolar solventsin nonpolar solvents

““Like Dissolves Like”Like Dissolves Like”

Non polar solutes are more soluble Non polar solutes are more soluble in nonpolar solventsin nonpolar solvents

Page 8: Solutions

NONPOLAR

NONPOLAR

POLAR

POLAR

““Like Dissolves Like”Like Dissolves Like”

Polar dissolves PolarPolar dissolves Polar

Ex. water dissolves salts (ionic & polar Ex. water dissolves salts (ionic & polar molecules)molecules)

““Like Dissolves Like”Like Dissolves Like”

Polar dissolves PolarPolar dissolves Polar

Ex. water dissolves salts (ionic & polar Ex. water dissolves salts (ionic & polar molecules)molecules)

Page 9: Solutions

Solvation

• Soap/DetergentSoap/Detergent– polar “head” with long nonpolar “tail”– dissolves nonpolar grease in polar water

Page 10: Solutions

Electrolyte- solution that conducts electricity

StrongElectrolyte

Non-Electrolyte

solute exists asions only

- +

salt

- +

sugar

solute exists asmolecules

only

- +

acetic acid

WeakElectrolyte

solute exists asions and

molecules DISSOCIATION IONIZATION

View animation online.

Page 11: Solutions

Solubility- the amount of solute that dissolves in given volume of solvent

SATURATED SOLUTION

no more solute dissolves

UNSATURATED SOLUTIONmore solute dissolves

SUPERSATURATED SOLUTION

becomes unstable, crystals form

concentration

Page 12: Solutions

Solubility- the amount of solute that dissolves in given volume of solvent

SATURATED SOLUTION(no more

solute dissolves)

UNSATURATED (dilute)

Small amt. of solute

dissolved

SUPERSATURATED Increase temp. to

dissolve more solute

concentration

Page 13: Solutions

Solubility

• SolubilitySolubility– maximum grams of solute that will dissolve in

100 g of solvent at a given temperature– varies with temp– based on a saturated solution

Page 14: Solutions

Definitions

• Soluble- any substance that dissolves in something else

• Insoluble- Any substance that does not dissolve

Page 15: Solutions

Definitions

• Miscible – one liquid dissolves in another liquid (ex. 2 polar liquids will be miscible)

• Immiscible – one liquid does not dissolve in another liquid (ex. oil and water) don’t mix b/c oil nonpolar and water polar

Page 16: Solutions

Definitions

• Alloy one metal dissolved in another

Page 17: Solutions

Solubility Curve

• Solubility CurveSolubility Curve– shows the

dependence of solubility on temperature

Page 18: Solutions

Solubility• Solids are more soluble at...Solids are more soluble at...

– high temperatures.

• Gases are more soluble at...Gases are more soluble at...– low temperatures &– high pressures (Henry’s Law).– EX: soda can

Page 19: Solutions

Henry’s Law & Soft Drinks• Soft drinks contain “carbonated water”

carbon dioxide gas dissolved in water• Gas in liquid is more soluble if pressure

above liquid is high (under pressure)

• When bottle opened pressure of CO2

decreases and solubility of CO2 also decreases, according to Henry’s Law.

• Result, bubbles of CO2 escape from solution.

Page 20: Solutions

Solution and Concentration

Concentration- a measure of how Concentration- a measure of how much solute is dissolved in the solutionmuch solute is dissolved in the solution

Page 21: Solutions

Solution and Concentration

Concentration- a measure of how Concentration- a measure of how much solute is dissolved in the solutionmuch solute is dissolved in the solution

Range from Range from

dilutedilute saturated saturated supersaturated supersaturated

Page 22: Solutions

• ways of expressing concentrationways of expressing concentration

–Molarity(M): moles solute / Liter solution

–Mass percent (mass solute / mass of solution) x 100

–Molality (m) - moles solute / Kg solvent

Page 23: Solutions

Molarity(M) = moles solute

Liter solution

Page 24: Solutions

Calculate the molarity of the following solution125 ml which contains 2.50 g NaCl

Page 25: Solutions

Calculate the molarity of the following solution125 ml which contains 2.50 g NaCl Molarity = moles of solute Liter of solution

Page 26: Solutions

Calculate the molarity of the following solution125 ml which contains 2.50 g NaCl Molarity = moles of solute Liter of solution

First change grams to moles2.50 g NaCl x 1 mole NaCl = 0.0428 moles NaCl 58.44 g NaCl

Page 27: Solutions

Calculate the molarity of the following solution125 ml which contains 2.50 g NaCl Molarity = moles of solute Liter of solution

First change grams to moles2.50 g NaCl x 1 mole NaCl = 0.0428 moles NaCl 58.44 g NaCl

M= 0.0428 moles NaCl = 0.342 M NaCl 0.125 L

Page 28: Solutions

Calculate the mass of the solute in the solution750 cm cubed of CaCl2 solution which is 0.500 M Molarity = moles of solute Liter of solution

First change Molarity to moles

Page 29: Solutions

Calculate the mass of the solute in the solution750 cm cubed of CaCl2 solution which is 0.500 M (0.500 moles/1L)

Molarity = moles of solute Liter of solution

First change Molarity to moles0.500 moles = moles CaCl2 1 Liter .750 L

Page 30: Solutions

Calculate the mass of the solute in the solution750 cm cubed of CaCl2 solution which is 0.500 M(0.500moles/1L)

Molarity = moles of solute Liter of solution

First change Molarity to moles0.500 moles = moles CaCl2 1 Liter .750 L 0.500 moles x .750 L = moles CaCl2 1 Liter

Page 31: Solutions

Calculate the mass of the solute in the solution750 cm cubed of CaCl2 solution which is 0.500 M Molarity = moles of solute Liter of solution

First change Molarity to moles0.500 moles = moles CaCl2 1 Liter .750 L 0.500 moles x .750 L = moles CaCl2 1 Liter 0.500 moles x .750 L = 0.375 moles CaCl2 1 Liter

Page 32: Solutions

Calculate the mass of the solute in the solution750 cm cubed of CaCl2 solution which is 0.500 M Molarity = moles of solute Liter of solution

First change Molarity to moles0.500 moles = moles CaCl2 1 Liter .750 L 0.500 moles x .750 L = moles CaCl2 1 Liter 0.500 moles x .750 L = 0.375 moles CaCl2 1 Liter

Next convert moles to grams0.375 moles CaCl2 x 110.98 g CaCl2 = 41.6 g CaCl2

Page 33: Solutions

Calculate how many liters of solution can be made fromA 2.00 M solution using 60.0 g NaOH Molarity = moles of solute

Liter of solution

Page 34: Solutions

Calculate how many liters of solution can be made fromA 2.00 M solution using 60.0 g NaOH Molarity = moles of solute

Liter of solution

First change grams of NaOH to moles60.00 g NaOH x 1 mole NaOH = 1.50 moles NaOH 40.00 g NaOH

Page 35: Solutions

Calculate how many liters of solution can be made fromA 2.00 M solution using 60.0 g NaOH Molarity = moles of solute

Liter of solution

Next change Molaririty to moles/liter 2.0 M = 2moles/1L2.00 moles = 1.5 moles NaOH 1 Liter ? L

First change grams of NaOH to moles60.00 g NaOH x 1 mole NaOH = 1.50 moles NaOH 40.00 g NaOH

Page 36: Solutions

Calculate how many liters of solution can be made fromA 2.00 M solution using 60.0 g NaOH Molarity = moles of solute

Liter of solution

Next change Molaririty to moles/liter2.00 moles = 1.5 moles NaOH 1 Liter ? L ? L = 1.5 moles NaOH x 1 Liter 2.0 moles

First change grams of NaOH to moles60.00 g NaOH x 1 mole NaOH = 1.50 moles NaOH 40.00 g NaOH

Page 37: Solutions

Calculate how many liters of solution can be made fromA 2.00 M solution using 60.0 g NaOH Molarity = moles of solute

Liter of solution

Next change Molaririty to moles/liter2.00 moles = 1.5 moles NaOH 1 Liter ? L ? L = 1.5 moles NaOH x 1 Liter 2.0 moles L= 0.750 liter

First change grams of NaOH to moles60.00 g NaOH x 1 mole NaOH = 1.50 moles NaOH 40.00 g NaOH

Page 38: Solutions

Concentration: Molarity Example•How would you prepare the following solution?

1.00 L of a 1.80 M aqueous solution of MgCl2

Molarity(M) = moles solute Liter solution

Page 39: Solutions

Concentration: Molarity Example•How would you prepare the following solution?

1.00 L of a 1.80 M aqueous solution of MgCl2

1.80 M = 1.8 mol MgCl2

1.00 L H20

Page 40: Solutions

Concentration: Molarity Example•How would you prepare the following solution?

1.00 L of a 1.80 M aqueous solution of MgCl2

1.80 M = 1.8 mol MgCl2

1.00 L H20

1.8 mol MgCl2 x 95.21 g MgCl2 = 171.38 g MgCl2

1 mol MgCl2

Take 171.38 g MgCl2 add water until you reach 1 liter

Page 41: Solutions

Concentration: Molarity Example•How would you prepare the following solution?

1 L of a 2.05 M aqueous solution of MgCl2

2.05 M = 2.05 mol MgCl2

1.0 L H20

2.05 mol MgCl2 x 95.21 g MgCl2 = 195.18 g MgCl2

1 mol MgCl2

Take 195 g MgCl2 add water until you reach 1 liter

Page 42: Solutions

Concentration: Molarity Example0.435 g of KMnO4 in 250. mL of solution, what is the molarity of KMnO4?

Molarity(M) = moles solute Liter solution

Page 43: Solutions

Concentration: Molarity Example0.435 g of KMnO4 in 250. mL of solution, what is the molarity of KMnO4?

first step convert the mass of material to

moles.

0.435 g KMnO4 • 1 mol KMnO4 = 0.00275 mol KMnO4

158.0 g KMnO4

Page 44: Solutions

Concentration: Molarity Example0.435 g of KMnO4 in 250. mL of solution, what is the molarity of KMnO4?

Now convert 250 ml to L

250 mL = 0.250 L

0.435 g KMnO4 • 1 mol KMnO4 = 0.00275 mol KMnO4

158.0 g KMnO4

Page 45: Solutions

Concentration: Molarity Example0.435 g of KMnO4 in 250. mL of solution, what is the molarity of KMnO4?

0.435 g KMnO4 • 1 mol KMnO4 = 0.00275 mol KMnO4

158.0 g KMnO4

Molarity KMnO4 = 0.00275 mol KMnO4 = 0.0110 M

0.250 L solution

Page 46: Solutions

Concentration: Molarity Example0.435 g of KMnO4 in 250. mL of solution, what is the molarity of KMnO4?

Now that the number of moles of substance is known, this can be combined with the volume of solution — which must be in liters — to give the molarity. Because 250. mL is equivalent to 0.250 L .

As is almost always the case, the first

step is to convert the mass of material to

moles.

0.435 g KMnO4 • 1 mol KMnO4 = 0.00275 mol KMnO4

158.0 g KMnO4

Molarity KMnO4 = 0.00275 mol KMnO4 = 0.0110 M

0.250 L solution

Page 47: Solutions

Lowering the concentration by adding solvent (water)

The amount of solute remains constant before and after the dilution but there is more solvent:

moles BEFORE = moles AFTER

C1V1 = C2V2

Suppose you have 0.500 M sucrose stock solution. How do you prepare 250 mL of 0.348 M sucrose solution ?

Concentration 0.500 M Sucrose

250 mL of 0.348 M sucrose

Dilution

A bottle of 0.500 M standard sucrose stock solution is in the lab.

Give precise instructions to your assistant on how to use the stock solution to prepare 250.0 mL of a

0.348 M sucrose solution.

A bottle of 0.500 M standard sucrose stock solution is in the lab.

Give precise instructions to your assistant on how to use the stock solution to prepare 250.0 mL of a

0.348 M sucrose solution.

Page 48: Solutions

Dilution Formula and Calculations

Mi x Vi = Mf x Vf How to make dilutions from concentrated stock Solve for VOLUME

What volume of 6.00M HCl must be diluted to obtain 5.00L of 1.50M HCl? Initial concentration of HCl Mi = 6.00M

Final concentration of HCl Mf = 1.50M

Final volume of solution Vf = 5.00L

6.00 M x Vi = 1.50 M x 5.00 L

Vi = 1.25 L

To make the desired quantity of diluted HCl, the chemist should begin with 1.25L of the concentrated solution and add enough water to bring the volume up to 5.00 L.

Page 49: Solutions

Dilution Formula and Calculations

Mi x Vi = Mf x Vf

Solve for MOLARITY

If you add 25 ml of water to 100 ml of KCl with a .30 M KCl what will the molarity of the diluted solution be? Initial concentration of KCl Mi = 0.30 M

Initial volume of KCl = 100 ml Final concentration of KCl Mf = ? M

Final volume of solution Vf = 100 + 25 = 125 ml

0.30 M x 100 ml = ?M x 125 ml 0.30 M x 100 ml = ?M 125 ml

Mf = 0.24 M

Page 50: Solutions

Factors Affecting Solubility1. Nature of Solute / Solvent1. Nature of Solute / Solvent.

2. Temperature -2. Temperature -

3. Pressure Factor (gas)3. Pressure Factor (gas)4. Size of Particle

5. Stirring mixture

Page 51: Solutions

Factors Affecting Solubility1. Nature of Solute / Solvent1. Nature of Solute / Solvent. - Like dissolves like (IMF)

2. Temperature -2. Temperature -i) Solids/Liquids- Solubility increases with Temperature

Increase K.E. increases motion and collision between solute / solvent.

ii) gas - Solubility decreases with Temperature

Increase K.E. result in gas escaping to atmosphere.

3. Pressure Factor -3. Pressure Factor -i) gas - Solubility increases with Pressure.

Increase pressure squeezes gas solute into solvent.

Page 52: Solutions

Solubilities of Solids vs TemperatureSolubilities of several ionic solid as a function of temperature.

MOST salts have greater solubility in hot water.

That is increasing temperature increases solubility of salts

Page 53: Solutions

Colligative Properties

Colligative Properties are properties of a liquid that change when a solute is added.

Page 54: Solutions

Colligative Properties

Dissolving solute in pure liquid will change all physical properties of liquid, Density, Vapor Pressure, Boiling Point, Freezing Point,Osmotic Pressure

Page 55: Solutions

Colligative Properties

The magnitude of the change depends on the numbernumber of solute particles in the solution, NOT on the identityidentity of the solute particles.

Page 56: Solutions

Boiling Point ElevationWhen solute is added, Boiling Point increases over Normal BPBoiling point is elevated because solute interferes with solvent forming into vapor.

Page 57: Solutions

Boiling Point Elevation

Some Boiling Point Elevation and Freezing Point Depression Constants

Normal bp (°C) Kb Normal fp (°C) Kf

Solvent pure solvent (°C/m) pure solvent (°C/m)

Water Water 100.00100.00 +0.5121 +0.5121 0.0 0.0 1.861.86BenzeneBenzene 80.10 80.10 +2.53+2.53 5.50 5.50 4.904.90CamphorCamphor 207 207 +5.611 +5.611 179.75 179.75 39.739.7Chloroform Chloroform 61.70 61.70 +3.63+3.63 - 63.5 - 63.5 4.70 4.70 (CH(CH33Cl)Cl)

Some Boiling Point Elevation and Freezing Point Depression Constants

Normal bp (°C) Kb Normal fp (°C) Kf

Solvent pure solvent (°C/m) pure solvent (°C/m)

Water Water 100.00100.00 +0.5121 +0.5121 0.0 0.0 1.861.86BenzeneBenzene 80.10 80.10 +2.53+2.53 5.50 5.50 4.904.90CamphorCamphor 207 207 +5.611 +5.611 179.75 179.75 39.739.7Chloroform Chloroform 61.70 61.70 +3.63+3.63 - 63.5 - 63.5 4.70 4.70 (CH(CH33Cl)Cl)

Page 58: Solutions

Solute particles do not fit into the crystal lattice of the solvent because of the differences in size. The solute essentially blocks the solvent from fitting into the crystal lattice during the freezing process.

Freezing Point DepressionFP is depressed (lowered) when solute blocks

solvent from crystallizing.

Page 59: Solutions

Dissolution at the molecular level?• Consider the dissolution of NaOH in H2O

Page 60: Solutions

Temperature & the Solubility of GasesThe solubility of gases DECREASES at higher temperatures

Page 61: Solutions

Vapor Pressure Lowering for a Solution

• The diagram below shows how a phase diagram is affected by dissolving a solute in a solvent.

• The black curve represents the pure liquid and the blue curve represents the solution.

• Notice the changes in the freezing & boiling points.

Page 62: Solutions

Vapor Pressure Lowering

• The presence of a non-volatile solute means that fewer solvent particles are at the solution’s surface, so less solvent evaporates!

Page 63: Solutions

Application of Vapor Pressure Lowering

• Describe what is happening in the pictures below.• Use the concept of vapor pressure lowering to

explain this phenomenon.

Page 64: Solutions

Osmotic pressure• Osmosis is the spontaneous movement of water across a semi-

permeable membrane from an area of low solute concentration to an area of high solute concentration

• Osmotic Pressure - The Pressure that must be applied to stop osmosis

= i CRT

where P = osmotic pressure i = van’t Hoff factor C = molarity R = ideal gas constant T = Kelvin temperature

Page 65: Solutions

Osmosis and Blood Cells(a) A cell placed in an isotonic solution. The net movement of water in and out of the cell is zero because the concentration of solutes inside and outside the cell is the same.

(b) In a hypertonic solution, the concentration of solutes outside the cell is greater than that inside. There is a net flow of water out of the cell, causing the cell to dehydrate, shrink, and perhaps die.

(c) In a hypotonic solution, the concentration of solutes outside of the cell is less than that inside. There is a net flow of water into the cell, causing the cell to swell and perhaps to burst.Isotonic solution Hypertonic solution Hypotonic solution