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Solving Multi-Step Equations Maze

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Page 1: Solving Multi-Step Equations Mazejbellus.weebly.com/uploads/5/7/3/2/57320959/day_20... · 2019-09-20 · This%maze%will%help%students%learn%to%solve%more%complex%equaons%that include%the%distribu7ve%property%and%variables%on%both%sides%of%the%

Solving Multi-Step Equations

Maze

Page 2: Solving Multi-Step Equations Mazejbellus.weebly.com/uploads/5/7/3/2/57320959/day_20... · 2019-09-20 · This%maze%will%help%students%learn%to%solve%more%complex%equaons%that include%the%distribu7ve%property%and%variables%on%both%sides%of%the%

This  maze  will  help  students  learn  to  solve  more  complex  equa7ons  that  include  the  distribu7ve  property  and  variables  on  both  sides  of  the  equa7on.    Students  must  be  able  to  work  with  simple  frac7ons.    Graphics  by  Krista  Wallden  -­‐  hBp://www.teacherspayteachers.com/Store/Krista-­‐Wallden      Font  by  KG  Fonts  -­‐  hBp://www.teacherspayteachers.com/Store/Kimberly-­‐Geswein-­‐Fonts    

Page 3: Solving Multi-Step Equations Mazejbellus.weebly.com/uploads/5/7/3/2/57320959/day_20... · 2019-09-20 · This%maze%will%help%students%learn%to%solve%more%complex%equaons%that include%the%distribu7ve%property%and%variables%on%both%sides%of%the%

4(2x-­‐1)  =  3x+6   x  =  -­‐1    

x  =  2    

-­‐3(x+5)=6  -­‐  3(2x+4)   x  =  3    

-­‐2(8x-­‐1)=4(3x+4)   x  =  -­‐2    

x  =  -­‐1  

   

x  =  10    

3  –  (2x+4)  =  2(3x+1)   x  =  1    

x  =  -­‐3  

8x  –  3(x  –  1)  =  2x  +  6  

   

2(5x-­‐3)  –  4  =  3x  +  4   x  =  2    

x  =  0    

6  –  (2x+2)  =  -­‐3x  +  4   x  =  1    

   

2x  –  3  =  5(x  +  4)  +  1   x  =  -­‐8    

x  =  6  

-­‐2(x-­‐3)  =  5(2x+3)   x  =  13    

x  =  5  

28  –  4(x  –  5)  =  -­‐4    

x  =  -­‐3  

-­‐5(3x+6)=-­‐3(4x-­‐2)  -­‐7(x+9)=9(x-­‐5)-­‐14x  3(x-­‐4)+6=5(x-­‐1)+1      x  =  -­‐12    x  =  -­‐9  

END  

BEGIN  

x = −112

x=1 4

Page 4: Solving Multi-Step Equations Mazejbellus.weebly.com/uploads/5/7/3/2/57320959/day_20... · 2019-09-20 · This%maze%will%help%students%learn%to%solve%more%complex%equaons%that include%the%distribu7ve%property%and%variables%on%both%sides%of%the%

4(2x-­‐1)  =  3x+6   x  =  -­‐1    

x  =  2    

-­‐3(x+5)=6  -­‐  3(2x+4)   x  =  3    

-­‐2(8x-­‐1)=4(3x+4)   x  =  -­‐2    

x  =  -­‐1  

   

x  =  10    

3  –  (2x+4)  =  2(3x+1)   x  =  1    

x  =  -­‐3  

8x  –  3(x  –  1)  =  2x  +  6  

   

2(5x-­‐3)  –  4  =  3x  +  4   x  =  2    

x  =  0    

6  –  (2x+2)  =  -­‐3x  +  4   x  =  1    

   

2x  –  3  =  5(x  +  4)  +  1   x  =  -­‐8    

x  =  6  

-­‐2(x-­‐3)  =  5(2x+3)   x  =  13    

x  =  5  

28  –  4(x  –  5)  =  -­‐4    

x  =  -­‐3  

-­‐5(3x+6)=-­‐3(4x-­‐2)  -­‐7(x+9)=9(x-­‐5)-­‐14x  3(x-­‐4)+6=5(x-­‐1)+1      x  =  -­‐12    x  =  -­‐9  

END  

BEGIN  

x = −112

x=1 4 ANSWER  

KEY