starter s-89 1.list the elements and how many there are of each in iron (iii) oxide. 2.multiply the...
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Starter S-89
1. List the elements and how many there are of each in Iron (III) oxide.
2. Multiply the number of each element by the average atomic mass of each.
3. Add these numbers together, this is called the molar mass.
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Starter S-90
1. What is the molar mass of H2S?
2. How many moles of H2S would be found in 100 g?
3. How many formula units (particles) of H2S would be in 100g?
Remember the lab from Tuesday
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Chemical Quantities
Chapter 10
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10.1 The Mole: A Measurement of Matter
Chapter 10
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Quantitative – yield a number value
Most common methods
count
mass
volume
10.1 The Mole
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Words often mean a quantity
pair – 2
dozen – 12
mole?
10.1 The Mole
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10.1 The Mole
Mole – means a specific number of particles
This is called Avogadro’s Number
The unit is used for
atoms
molecules (covalent compounds)
formula units (ionic compounds)
2310022.6 x
10.1 The Mole
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10.1 The MoleTo convert numbers of particles to moles we need
an equality
This could also be
Or
Depending on what type of particle you are trying to convert
atomsxmol 2310022.61
10.1 The Mole
moleculesxmol 2310022.61
unitsformulaxmol .10022.61 23
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10.1 The MoleThe rest is just the conversion we have always done
remember – the unit you have goes on the bottom of the fraction
-the unit you are converting to goes on the top
So to convert 2500 atom of C to moles
10.1 The Mole
atomsCx
molCatomC
2310022.6
12500
molCx 21102.4
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10.1 The MoleConverting from moles to partciles follows the same
process
How many molecules of Carbon Dioxide are in 1.55 mol?
10.1 The Mole
2
223
2 1
10022.655.1
molCO
OmoleculesCxmolCO
2231033.9 OmoleculesCx
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10.1 The MoleConvert the following quantities to moles
1. 9,487,212 formula units of AgNO3
2. 5.78x1023 atoms of Nitrogen
3. 4.1x1024 molecules of Carbon Monoxide
10.1 The Mole
31710575.1 molAgNOx
molN960.0
molCO8.6
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10.1 The MoleConvert the following to the correct type of particle
1. 95 moles of CCl4
2. 7.211x10-3 moles of CuCO3
3. 0.08 moles of Helium
10.1 The Mole
425107.5 ClmoleculesCx
321 .10342.4 unitsCuCOformulax
atomsHex 22105
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10.1 The MoleBy definition, the atomic mass of an element in
grams is the mass of one mole of the element.
This is called the molar mass
10.1 The Mole
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10.1 The MoleFor a compound we must calculate the molar mass
1. Write down what type of atoms, and how many of each are present
C 1
H 4
2. Multiply by the molar mass of each element
10.1 The Mole
CH4
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10.1 The MoleFor a compound we must calculate the molar mass
1. Write down what type of atoms, and how many of each are present
C 1 x 12.0107g =
H 4 x 1.00794g =
2. Multiply by the molar mass of each element
10.1 The Mole
CH4
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10.1 The MoleFor a compound we must calculate the molar mass
1. Write down what type of atoms, and how many of each are present
C 1 x 12.0107g = 12.0107g
H 4 x 1.00794g = 4.03176g
2. Multiply by the molar mass of each element
3. Add to get a total
10.1 The Mole
CH4
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10.1 The MoleFor a compound we must calculate the molar mass
1. Write down what type of atoms, and how many of each are present
C 1 x 12.0107g = 12.0107g unit
H 4 x 1.00794g = 4.03176g
2. Multiply by the molar mass of each element
3. Add to get a total 16.0425g CH4
10.1 The Mole
CH4
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Starter S-92
1. What is the molar mass of CO?
2. How many moles of CO would
be found in 0.56 g?
3. How many molecules of
CO would be found in
3.51 moles?
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10.2 Mole-Mass and Mole-Volume
Chapter 10
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10.1 The Mole
10.2 Mole-Mass and Mole-Volume
We don’t convert from particles to moles nearly as often as we do from moles to grams.
The reason is that we usually measure the amount of a substance on the balance
We need to know numbers of
particles so that we can
compare ratios of atom or
compounds
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10.1 The Mole
10.2 Mole-Mass and Mole-Volume
This is just another conversion problem
The equality is
Again, the quantity you have goes on the bottom, the quantity you want goes on top
So if you have 9.5g of Carbon
Value Molar Mass = 1 mole
molCgC
molCgC 79.0
0107.12
15.9
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10.1 The Mole
3AgNO
10.2 Mole-Mass and Mole-Volume
If you have 2.2 moles of Silver Nitrate convert to mass
First we need to know the formula of Silver Nitrate
Then the molar mass
And finally we can convert
g8731.169
33
33 370
1
8731.1692.2 gAgNO
molAgNO
gAgNOmolAgNO
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Try the following example: How many moles is 8.2g of Copper (II) Chloride
Formula
Molar mass
Moles
10.1 The Mole
2CuCl
10.2 Mole-Mass and Mole-Volume
g451.134
22
22 061.0
451.134
12.8 molCuCl
gCuCl
molCuClgCuCl
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And another one: How many grams is 2.4 mol of Iron (III) Sulfate
Formula
Molar mass
Moles
10.1 The Mole
342 SOFe
10.2 Mole-Mass and Mole-Volume
g881.399
342
342
342342 960
1
881.3994.2 SOgFe
SOmolFe
SOgFeSOmolFe
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In 1811, Amedeo Avogadro proposed
Avagador’s Hypothesis – equal volumes of gases at the same temperature and pressure contain equal numbers of particles
10.1 The Mole
10.2 Mole-Mass and Mole-Volume
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Standard Temperature and Pressure (STP)
T – 0oC or 273K
P – 101.3 kPa, or 1 atm
At STP the volume of one mole is 22.4L
So the equality for conversion is
10.1 The Mole
10.2 Mole-Mass and Mole-Volume
Lmol 4.221
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To do these problems, the identity of the gas doesn’t really matter.
If we have 15 L of Chlorine gas
The number of moles would be
10.1 The Mole
2Cl
10.2 Mole-Mass and Mole-Volume
22
22 67.0
4.22
115 molCl
LCl
molClLCl
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If instead we calculate for a more complicated gas such as propane
And we also have 15 L of propane gas
The number of moles would be
10.1 The Mole
83HC
10.2 Mole-Mass and Mole-Volume
8383
8383 67.0
4.22
115 HmolC
HLC
HmolCHLC
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Starter S-96
1. What is the molar mass of Pb(SO4)2?
2. How many moles of Pb(SO4)2 would be found in 250 g?
3. How many moles of H2 gas are found in 250 L?
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10.3 Percent Composition and Chemical Formulas
Chapter 10
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The relative amounts of the elements in a compound is called the percent composition
The percent by mass of an
element is the number of
grams of the element
divided by the mass in
grams of the compound multiplied by 100%
10.1 The Mole
10.3 Percent Composition
.% 100%
.
mass elementmass x
mass compound
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Calculating the mass percent from a formula
1. Formula
2. Calculate the total
mass of each element
3. Calculate the total
mass of
the compound
4. Calculate the
percent by
mass for
each element
10.1 The Mole
1 12.0107 12.0107
4 1.00794 4.03176
C x g g
H x g
4CH
10.3 Percent Composition
4 12.0107 4.03176 16.0425CH g
12.0107100% 74.8680%
16.0425
4.03176100% 25.1317%
16.0425
C x
H x
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Calculate the mass percent
1. Formula
2. Mass of each element
3. Total mass
4. Mass Percent
10.1 The Mole
1 12.0107 12.0107
4 1.00794 4.03176
1 15.9994 15.9994
C x g g
H x g
O x g
3CH OH
10.3 Percent Composition
3 12.0107 4.03176 15.9994 32.0419CH OH g
12.0107100% 37.4844%
32.0419
4.03176100% 12.5828%
32.0419
15.9994100% 49.9327%
32.0419
C x
H x
O x
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Starter S-95
What is the percent by mass of the all the elements in Cu(NO3)2.
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Empirical Formula – smallest whole number ratio of the elements in a
compound
The empirical formula
can be calculated
from the percent
composition
10.1 The Mole
10.3 Percent Composition
Compound Empirical Formula
H2O H2O
CH3COOH CH2O
CH2O CH2O
C6H12O6 CH2O
S8 S
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To calculate the empirical formula
1. List the elements and their
percent compositions
2. Convert the percent
compositions to moles
3. Calculate the mole ratio (divide
by the smallest number of moles)
4. Smallest Whole Number ratio
5. Write the Formula
10.1 The Mole
25.9%
74.1%
N
O
10.3 Percent Composition
125.9 1.85
14.0
174.1 4.63
16.0
molNN gN molN
gN
molOO gO molO
gO
1.851.00
1.85
4.632.50
1.85
molN
mol
molO
mol
2
5
N
O
2 5N O
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To calculate the empirical formula
1. Elements
2. Convert to Moles
3. Mole ratio
4. Whole Number ratio
5. Write the Formula
10.1 The Mole
67.6%
10.8%
21.6%
Hg
S
O
10.3 Percent Composition
167.6 0.337
200.59
110.8 0.337
32.06
121.6 1.35
16.0
molHgHg gHg molHg
gNg
molSS gS molS
gS
molOO gO molO
gO
0.3371.00
0.337
0.3371.00
0.337
1.354.01
0.337
molHg
mol
molS
mol
molO
mol
1
1
4
Hg
S
O
4HgSO
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Starter S-97
What is the empirical formula if
Lead is 59.7%
Hydrogen is 2.9%
Arsenic is 21.6%
Oxygen is 18.4%
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The molecular formula can be calculated from the empirical formula and the molar mass
10.1 The Mole10.3 Percent Composition
Comparison of Empirical and Molecular Formulas
Formula Classification Molar Mass
CH Empirical 13
C2H2 Molecular 26 (2x13)
C6H6 Molecular 78 (6x13)
CH2O Empirical 30
C2H4O2 Molecular 60 (2x30)
C6H12O6 Molecular 180 (6x30)
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Steps in calculations (if mass=60.0g)
1. Determine the empirical formula
2. Calculate the mass
of the empirical formula
3. Divide the actual molar mass by
this number
4. Multiply the empirical formula
10.1 The Mole10.3 Percent Composition
4CH N1 12.0 12.0
4 1.01 4.04
1 14.0 14.0
C x gC
H x gH
N x gN
4 30.0CH N g
60.02.00
30.0
g
g
2 8 2C H N
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Starter S-99
What is the empirical formula if
Silver – 63.5%
Nitrogen – 8.2 %
Oxygen – 28.2%
If the formula mass is 170g, what is the formula of this compound?
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Practice Problem 1
A. How many moles of AgNO3 are found in 125 g?
B. How many grams of AgNO3 are found in 2.99 moles?
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Practice Problem 2
A. How many molecules are found in 19.5 moles of CH2O?
B. How many grams of CH2O are found in 1.8x1024 molecules?
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Practice Problem 3
A. What is the empirical formula of the following compound
Na-43.4%
C – 11.3%
O – 45.3%
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Practice Problem 4
A. What is the empirical formula
C – 3.2g
H – 0.53g
O – 4.3 g
B. If the molar mass is 330, what is the molecular formula?
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Starter S-102
Test Day
Great and Glorious Test Day
Yahoo
Yipee
Yah
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Starter S-105
What is the empirical formula if
Carbon – 49.5%
Hydrogen – 5.2%
Nitrogen – 28.9%
Oxygen – 16.5%
What if the molecular formula, if the molar mass is 194g?