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    CI for Two Population PropKelompok 8

    Muhammad Fa

    Muhammad

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    EQUATION

    Confidence interval 100%(1 - ) for difference two population prop2are :

    or

    1

    12/2121

    2

    22

    1

    112/21

    1()(

    )1()1()(

    n

    pZppPP

    n

    pp

    n

    ppZpp

    2

    22

    1

    112/21

    )1()1()(

    n

    pp

    n

    ppZpp

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    EXPLANATION

    = 1st total population from data sample

    = 2nd total population from data sample

    = sample data in population 1

    = sample data in population 2

    = 1st population porportion from data sample

    = 2nd population porportion from data sample

    1p

    1n

    2n

    2p

    n

    xp

    1x

    1x

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    TEMPLATE

    1. Collect all information from the data and determine the value table II

    2. The end points of the confidence interval for p1p2are:

    3. Interprete the confidence interval

    2

    22

    1

    112/21

    )1()1()(

    n

    pp

    n

    ppZpp

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    EXAMPLE

    A study of teenage suicide included a sample of 125 boys abetween ages of 12 and 16 years selected scientifically fromrecords to a private psychiatric hospital. Suicide attempts were reof the boys and 60of the girls. We assume that the girls consti

    random sample from a population of similar girls and likewboys. Construct a 95%confidence interval for the difference betwproportions !

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    Collect all information from the da

    Let is the population of boys and is the population of girlssucidie

    From 95% confidence interval we get:

    So we get Z/2from table II:

    100

    125

    2

    1

    n

    n

    25.0100/25

    48.0125/60

    2

    1

    p

    p

    0.050.95-1

    96.1Z /2

    0.025/2

    1p 2p

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    The end points of the confidence interval fo

    2

    22

    1

    112/21 )

    1(

    )

    1(

    )(n

    ppn

    ppZpp

    125)48.01(48.096.1)25.048.0( =

    100

    75.0(25.0

    125

    )52.0(48.096.1)23.0(

    0019.00.00296.1)23.0(

    =

    =0039.096.1)23.0( = = .1)23.0(

    = 0.12223.0

    352.0108.0

    0.12223.0 0.12223.0

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    Interprete the confidence interva

    We interprete this interval that the differences between the twproportion, p1p2= 0.23. We are 95% confident that the differenboys and girls who try to suicide is somewhere between 0.108 0

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    CASES

    CEWEK

    3 2 2 3

    6 4 3 1

    3 3 2 2

    3 5 2 3

    3

    COWOK

    1 1 7

    2 2 10

    1 4 2

    3 1

    Data diatas adalah studi mengenai waktu para mahasiswa menonton tv selama 2jmahasiswi dan 14 mahasiswa. Dari studi tersebut diketahui ada sebanyak 5 mahasiswyang menonton selama 2 jam. Buatlah selang kepercayaan 90% dari selisih 2 proporsi d

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    PENYELESAIAN

    17

    14

    2

    1

    n

    n

    29.017/5

    36.014/5

    2

    1

    p

    p 0.10.90-1

    65.1Z /20.05/2

    2

    22

    1

    112/21

    )1()1()(

    n

    pp

    n

    ppZpp

    14

    36.01(36.065.1)29.036.0(

    17

    0(29.0

    14

    )64.0(36.0

    65.1)07.0(

    0121.00165.065.1)07.0(

    0286.065.1)07.0(

    )2805.0()07.0( 2105.0 35.0