stoichiometry – chemical quantities notes
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Stoichiometry – Chemical Quantities Notes. Stoichiometry. Stoichiometry – Study of quantitative relationships that can be derived from chemical formulas and chemical equations Mole ─ Mole Relationship need a balanced equation - PowerPoint PPT PresentationTRANSCRIPT
Stoichiometry – Chemical Quantities Notes
StoichiometryStoichiometry – Study of quantitative relationships that can be derived
from chemical formulas and chemical equationsMole ─ Mole Relationship
need a balanced equationMole Ratio – the ratio of moles of one substance to moles of another
substance in a balanced chemical equationThe coefficients in a balanced equation give the relative numbers of
molecules, as well as, the relative number of moles.
CO(g) + 2H2(g) CH3OH(l)
Ex: How many moles of O2 are required to produce 10. moles of CO2?2 CO + O2 2 CO2
1 mol CO = 2 mol H2 = 1 mol CH3OH
10. mol CO2 x __________ mol CO2
mol O2
2
1 = 5.0 mol O2
What other relationships do we have for the mole?
• 1 mol = 6.022 x 1023 atoms / molecules / particles
• 1 mol = [molar mass] g
We can add these mole relationships on either end of the mole ratio:
# unit A x 1 mol A x mol B x __ unit B = # unit B
_ unit A _ mol A 1 mol B
mole relationship mole ratio mole relationship
(switch units) (switch substances) (switch units)
*A is the GIVEN substance & B is the WANTED substance
Mass A – Mole B
Ex: Calculate moles of O2 produced if 2.50 g KClO3 decomposes completely:
2 KClO3 2 KCl + 3 O2
x ______________mol O2
mol KClO3
3
2
x ________________mol KClO3
122.6
1
g KClO3
2.50 g KClO3 =
0.0306 mol O2
K 1 x 39.1 = 39.1
Cl 1 x 35.5 = 35.5
O 3 x 16.0 = 48.0
122.6 g/mol
Mass A – Mass B
Ex: Determine the mass of NaCl that decomposes to yield 355 g Cl2
2NaCl 2 Na + Cl2355 g Cl2
mol Cl2
g Cl271.0
1 x _____________ x ______________ mol Cl2
mol NaCl
1
2 x ______________ mol NaCl
g NaCl58.5
1=
585 g NaCl
Cl 2 x 35.5 = 71.0 g/mol
Na 1 x 23.0 = 23.0
Cl 1 x 35.5 = 35.5
58.5 g/mol
Mole A – Mass BEx: Calculate the number of grams of oxygen
required to react exactly with 4.30 mol of propane, C3H8, in the reaction by the following balanced equation:
C3H8(g) + 5O2(g) 3CO2(g) + 4H2O(g)
4.30 mol C3H8 mol O2
mol C3H81
5 x _____________ x __________ mol O2
g O2
1
32.0=
688 g O2O 2 x 16.0 = 32.0 g/mol