stoichiometry kathleen thorr
DESCRIPTION
Stoichiometry Kathleen Thorr. KF+O. How many grams of Potassium Oxide are needed to produce 4.18g of Oxygen??. Write a complete and balanced chemical equation. K 2 O +2F -----> 2K F+ O 2 2K 2 O +4F ----> 4KF + O 2. Draw a column after each chemical. - PowerPoint PPT PresentationTRANSCRIPT
Stoichiometry
Kathleen
ThorrKF+O
How many grams of Potassium Oxide are
needed to produce 4.18g of Oxygen??
Write a complete and balanced chemical equation
K2O +2F -----> 2K F+ O2
2K2O +4F ----> 4KF + O2
Draw a column after each chemical
4F + 2K2O O2 + 4KF
Write the amount given in the correct column
4F + 2K2O O2
4.18g
+ 4KF
Convert the amount given into moles
4F + 2K2O O2
4.18g 1/31.998
4.18g x 1mole 1 31.998.131 moles
+ 4KF
Do the math and label as moles
4F +.131x 4/1.524mol
2K2O .131 x 2/1 =
.262mol
O2
4.18g 1/31.998
4.18g x 1mole 1 31.998.131 moles
+ 4KF.131 x 4/1=
.524
Convert all moles into grams
4F +.131x 4/1.524 x 19.00=9.96g
2K2O .131 x 2/1 =
.262 x 94.199=-
24.7g
O2
4.18g 1/31.998
4.18g x 1mole 1 31.998.131 moles
+ 4KF.131 x 4/1=
.524 x 58.1=
30.4
Verify the Law of Conservation
4F +.131x 4/1.524 x 19.00=9.96g
9.96 + 24.7 =
34.7g
2K2O .131 x 2/1 =
.262 x 94.199=-
24.7g
O2
4.18g 1/31.998
4.18g x 1mole 1 31.998.131 moles
4.18 + 30.4 =34.6g
+ 4KF.131 x 4/1=
.524 x 58.1=
30.4
Answer
4F +.131x 4/1.524 x 19.00=9.96g
9.96 + 24.7 =
34.7g
2K2O .131 x 2/1 =
.262 x 94.199=-
24.7g
O2
4.18g 1/31.998
4.18g x 1mole 1 31.998.131 moles
4.18 + 30.4 =34.6g
+ 4KF.131 x 4/1=
.524 x 58.1=
30.4