stoichiometry of chemical reactions ( q3 u2)
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Stoichiometry of Chemical Reactions ( Q3 U2) . Stoichiometry. The study of the quantitative relationships between reactants and products in a reaction It is used to answer questions like; If I have this much reactant, how much product can I make? - PowerPoint PPT PresentationTRANSCRIPT
STOICHIOMETRY OF CHEMICAL REACTIONS
(Q3 U2)
STOICHIOMETRY The study of the quantitative relationships between
reactants and products in a reaction It is used to answer questions like; If I have this much
reactant, how much product can I make? If I want this much product, how much reactant do I need?
These questions have real life application, particularly in manufacturing.
It allows us to convert the mass of a substance to the number of particles (atoms, ions or molecules) it contains.
These numbers can be really large, so they are counted in groups
Much like when we count a lot of pennies we stack them in 10’s and count by 10
The Mole Atoms are very tiny, so small that the grouping we use to count them must be very large MOLE; the group (unit of measure) used to
count atoms, molecules, formula units or ions of a substance
1 mole of a substance has a particular number of particles in it! Much like 1 dozen always means 12; whether it is 12 eggs 12 oranges or 12
gold bars
How many particles are in a mole?
The number of particles in a mole = 6.02 x 10 23 or 602,000,000,000,000,000,000,000 !
This is known as Avogadro’s Number
Using this, We can easily count the number of particles in all kinds of things !
Counting Particles in a MoleThere are 6.02 x 10 23 Carbon atoms in a mole of
carbon There are 6.02 x 10 23 CO2 molecules in a mole of CO2
There are 6.02 x 10 23 sodium ions in a mole of sodium
There are 6.02 x 10 23 marbles in a mole of marbles
That’s a lot of marbles!
The Size of a mole of a substance changes, the bigger the substance the more space a mole of the substance takes up, but the number of particles in a mole is always the same!
A Mole of Water
Molar Mass Chemicals do not come bundled in moles, like a
dozen eggs comes in a 1 dozen or 1 ½ dozen package so we use the mole as a grouping unit.
The mass of 1 mole of a pure substance called it’s molar mass
If I want to produce 500g of methanol using the following equation, CO2 +3H2 CH3OH + H20 how many grams of CO2 and H2 do I need?
These are the questions stoichiometry answers!
What do we need to know to answer this?
If I want to produce 500g of methanol using the following equation;
CO2 +3H2 CH3OH + H20 How many grams of CO2 and H2 do I need?
This equation relates the molecules of reactants and products, NOT THEIR MASSES! 1 molecule of CO2 and 3 molecules of H2 will make 1
molecule of CH3OHWe need to relate the masses to the number of
molecules.
Relating Mass to Moles
Remember; The average atomic masses of the elements are found on the Periodic Table!
We can use the atomic masses on the PT to relate the mass of the compound to the mass of a mole!
Molar Mass and Formula Mass
Molar mass: The mass (in grams)of one mole of a molecule or a formula unit
Molecular mass: mass in atomic mass units of just one molecule
Formula Mass: mass in atomic mass units of one formula unit of an ionic compound
Relating the Mass of an Atom to the Mass of a Mole of substance.
Steps1. Find the average Atomic Mass of the element on
the PT. (state it in grams instead of atomic units)a) Example: molar mass of Fe = 55.847 gb) Example: molar mass of Pt = 195.08 g
2. If the element is a molecule, count the number of atoms in the molecule then multiply the atomic mass by the number of atoms.
a) Example: O2, the mass of O =16.0g There are 2 atoms of O in the O2 molecule , 2 atoms X 16.0g = 32.00g is the molar mass of the molecule.
Let’s PracticeCalculate the molar mass of each of
the following:1. N2
2. Cl23. Br2
4. I25. H2
6. F2
Molar Mass AnswersCalculate the molar mass of each of the
following:1. N2 = 14.007g X 2 =28.014 g/mol2. Cl2 = 35.453g X 2 =70.906 g/mol3. Br2 = 79.904g X 2 =159.808 g/mol 4. I2 = 126.904g X 2 =253.808 g/mol5. H2 = 1.008g X 2 =2.016 g/mol6. F2 = 18.998g X 2 =37.996 g/mol
Now, let’s do the same for an example reaction!
Steps1. Count the number and type of atoms2. Find the Atomic Mass of each atom type,
on the periodic table. Write it in grams.3. Multiply the mass times the # of Atoms.
Then add the totals
How do we calculate Molar Mass?1. Count the number and type of atomsEthanol (C2H5OH)
2. Find the Atomic Mass of each atom type, on the periodic table. Write it in grams.
3. Multiply The mass X the # of Atoms. Then add the totals.
Atom type Amount of each atomC 2H 6O 1
Atom type Amount of atom
Ave. Atomic Mass in g
C 2 12.0H 6 1.00O 1 16.0
Atom type
Amount of atom
Ave. Atomic Mass in g
Total
C 2 12.0 =24.0H 6 1.00 =6.0O 1 16.0 =16.0
Molar Mass Of Ethanol (C2H5OH) = 46.0g/mole
How do We Calculate Molar Mass?
Atom Types
Amount of Atoms
Ave. Atomic
Mass in g
Total
Ca 1 40.1 40.1Cl 2 35.5 71.0
Mass of 1 mol of CaCl2 (molar mass) 111.1 g/mole
Example: Calcium Chloride (CaCl2 )
Now You Do SomeWhat is the molar mass of each of the
following?1. Fe2 O3 2. H2O3. CO2
4. NaCl5. NH3
6. BaI2
Molar Mass Answers Fe2 O3 = 55.85g X 2= 111.7 g 16.0g X 3 = 48.0g = 159.7 g/mol_______________________________________________ H2O = 1.01g X 2 = 2.02 16.0g X 1 = 16.0 = 18.02 g/mol_______________________________________________ CO2 = 12.01g X 1 = 12.01
16.0g X 2 = 32.0 = 44.01 g/mol________________________________________________NaCl = 22.99 gX1 = 22.99 35.45g X1 = 35.45 = 58.44 g/mol________________________________________________NH3 =14.01g X 1 = 14.01 1.01g X 3 = 3.03 = 17.04 g/mol________________________________________________BaI2 = 137.33g X 1 = 137.33 126.90g X 2 = 253.80 = 391.13 g/mol
Now that we know how to find Molar Mass What is the next step?
If I want to produce 500g of methanol using the following equation;
6CO2 +17H2 3C2H5OH + 9H20 How many grams of CO2 and H2 do I need?
The Molar Mass Of Ethanol (C2H5OH)= 46.0g/mole Now we need to find the number of atoms
in the sample. How many molecules of methanol are in
500g?
Finding the number of atoms in a given mass
Steps to finding the number of atoms in a given mass of a sample
1. Use PT to find the molar mass of the substance
2. Convert the mass of the substance to number of moles in the sample (convert using mass of one mole as conversion factor)
3. Use the number of atoms in a mole to find the number of atoms in the sample
4. Solve and check answer by canceling out units
Finding the number of atoms in a sample of an element
The mass of an iron bar is 16.8g. How many iron(Fe) atoms are in the sample?Step 1: Use PT to find the molar mass of the substance : The molar mass of Fe =55.8g/moleStep 2: Convert the given mass of the substance to number of moles in the sample: Fe =55.8g/mole
(16.8g Fe) (1 mol Fe) (6.022 X 1023 Fe atoms)= 1.81 X 10
23 Fe atoms
(55.8g Fe) (1 mol Fe)Step 3: Use the number of atoms in a mole to find the number of atoms in the sample = 1.18 X 1023
Calculate the number of atoms in the given samples
1. 25.0 g silicon, Si
2. 1.29 g chromium, Cr
Answers
(25.0 g Si ) ( 1 mol Si ) (6.02 X 1023 Si atoms ) 1 28.1g Si 1 mol Si = 5.36 X1023 atoms Si
(1.29 g Cr ) ( 1 mol Cr ) (6.02 X 1023 Cr atoms ) 1 52.0g Cr 1 mol Cr= 1.49 X1022 atoms Cr
Practice: Determine the number of Atoms in a given sample
Remember:(change molar mass mass per mole atoms per mole)
1. 98.3g mercury, Hg2. 45.6g gold, Au3. 10.7g lithium, Li4. 144.6g tungsten, W
Answers1. (98.3 g Hg ) ( 1 mol Hg )(6.02 X 1023 Hg atoms) 1 200.6g Hg 1 mol Hg = 2.95 X1023 atoms Hg
2. (45.6 g Au ) ( 1 mol Au )(6.02 X 1023 Au atoms) 1 197.0g Au 1 mol Au = 1.39 X1023 atoms Au
3. (10.7 g Li ) ( 1 mol Li )(6.02 X 1023 Li atoms) 1 6.94g Li 1 mol Li = 9.28 X1023 atoms Li
4. (144.6 g W ) ( 1 mol W )(6.02 X 1023 W atoms) 1 183.8g W 1 mol W = 4.738 X1023 atoms W
Determining the Number of formula units in a sample
Steps1. Use the PT to calculate the molar mass
of one formula unit2. Convert the given mass of the compound
to the number of molecules in the sample (use the molar mass as the conversion factor)
3. Multiply the moles of the compound by the number of the formula units in a mole (Avagadro’s number) and solve
4. Check by evaluating the units
The mass of a quatity of Iron(III) oxide is 16.8g. How many formula units in the sample?
1. Calculate the molar mass (Fe2O3) 2 Fe atoms 2X 55.8 = 111.6 3 O atoms 3 X 16.0 = +48.0
molar mass 159.6 g/mol2. (change given mass mole per mass atoms per mole)
(16.8 g Fe2O3 ) ( 1 mol Fe2O3 )(6.02 X 1023 Fe2O3 Formula units) 1 159.6g Fe2O3 1 mol Fe2O3
= 6.34 X1022 Fe2O3 Formula units
How many molecules in each sample? (Formula Units)
1. 89.0g sodium oxide (Na2O)
2. 10.8g boron triflouride ( BF3)
Answers1. 89.0g sodium oxide (Na2O)Calculate the molar mass (Na2O) 2 Na atoms 2X 23.0 = 46.0 1 O atoms 1 X 16.0 = +16.0
molar mass 62.0 g/mol(change given mass mole per mass molecules per
mole)
(89.0 g Na2O ) ( 1 mol Na2O )(6.02 X 1023 Na2O Molecules) 1 62.0g Na2O 1 mol Na2O = 8.64 X1023 Na2O molecules
Answers Continued2. 10.8g boron triflouride ( BF3)Calculate the molar mass (Na2O) 1 B atom 1X 10.8 = 10.8 3 F atoms 3 X 19.0 = +57.0
molar mass 67.8 g/mol(change given mass mole per mass molecules per
mole)
(10.8 g BF3 ) ( 1 mol BF3 )(6.02 X 1023 BF3 Molecules) 1 67.8g BF3 1 mol BF3
= 9.59 X1022 BF3 molecules
How do we find the number of moles if given the mass?
Steps1. Determine the molar mass2. Change given mass to moles by using
molar mass as the conversion factor.
Example of Grams to molesCalculate the number of moles in 6.84g sucrose (C12H22O11) 12 C atoms 12 X 12.0 = 144.0 22 H atoms 22 X 1.0 = 22.0 11 O atoms 11 X 16.0 = +176.0
molar mass 342.0 g/mol(change molar mass mole per mass)
(6.84 g sucrose ) ( 1 mol sucrose ) 1 342.0g sucrose = 2.0 X10-02 moles of sucrose
Determine the number of moles in each sample
1. 16.0g sulfur dioxide, SO2 2. 68.0g ammonia, NH3 3. 17.5g copper(II) oxide, CuO
Answers1. 0.250 mol SO2
2. 4.00 mol NH3
3. 0.22 mol CuO