stoichiometry: the mole

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Stoichiometry: The Mole

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Stoichiometry: The Mole. Stoichiometry. The study of the quantitative aspects of chemical reactions. “The Mole”. A counting unit 1 mole = 602 billion trillion: 602,000,000,000,000,000,000,000 6.02 X 10 23 (in scientific notation) 1 dozen eggs = 12 1 “mole” of eggs = 6.02 x 10 23 eggs - PowerPoint PPT Presentation

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Stoichiometry: The Mole

Stoichiometry: The MoleStoichiometryThe study of the quantitative aspects of chemical reactions.

The MoleA counting unit1 mole = 602 billion trillion: 602,000,000,000,000,000,000,000

6.02 X 1023 (in scientific notation)

1 dozen eggs = 121 mole of eggs = 6.02 x 1023 eggs

1 dozen cars = 12 cars1 mole of cars = 6.02 x 1023 cars

Note that the NUMBER is always the same, but the MASS is very different!

Mole is abbreviated mol

= 6.02 x 1023 C atoms= 6.02 x 1023 H2O moleculesA Mole of Particles Contains 6.02 x 1023 particles 1 mole C

1 mole H2O

Note that a particle could be an atom OR a molecule!

6.02 x 1023 particles 1 mole or

1 mole6.02 x 1023 particles

Avogadros Number as a Conversion Factor1. Number of atoms in 0.500 mole of Ala) 500 Al atoms b) 6.02 x 1023 Al atomsc) 3.01 x 1023 Al atoms

2.Number of moles of S in 1.8 x 1024 S atomsa) 1.0 mole S atomsb) 3.0 mole S atomsc) 1.1 x 1048 mole S atoms

Learning Check

The Mass of 1 mole (in grams)Equal to the numerical value of the average atomic mass (get from periodic table)

1 mole of C atoms= 12.0 g1 mole of Mg atoms =24.3 g1 mole of Cu atoms =63.5 gMolar MassFind the molar mass: (usually we round to the tenths place)Learning Check!1 mole of Br atoms1 mole of Sn atoms=79.9 g/mole= 118.7 g/moleChemical Formulas of Compounds

Formulas give the relative numbers of atoms or moles of each element in a formula unit - always a whole number ratio (the law of definite proportions).

NO2 2 atoms of O for every 1 atom of N 1 mole of NO2 : 2 moles of O atoms to every 1 mole of N atoms

If we know or can determine the relative number of moles of each element in a compound, we can determine a formula for the compound.Mass in grams of 1 mole sum of the atomic masses1 mole of CaCl2 = 111.1 g/mol 1 mole Ca x 40.1 g/mol + 2 moles Cl x 35.5 g/mol = 111.1 g/mol CaCl21 mole of N2O4 = 92.0 g/mol Molar Mass of Molecules and CompoundsMolar Mass of K2O = ? Grams/mole

B. Molar Mass of antacid Al(OH)3 = ? Grams/moleLearning Check!

The artificial sweetener aspartame (Nutra-Sweet) formula C14H18N2O5 is used to sweeten diet foods, coffee and soft drinks. How many moles of aspartame are present in 225 g of aspartame?

Learning Check!

molar mass Avogadros number Grams Moles particles

You can convert Grams to Particles, but you always must go through moles first.CalculationsFlowchartAtoms or MoleculesMolesMass (grams)Divide by 6.02 X 1023Multiply by 6.02 X 1023Multiply by atomic/molar mass from periodic tableDivide by atomic/molar mass from periodic tableAtoms/Molecules and GramsHow many atoms of Cu are present in 35.4 g of Cu?35.4 g Cu 1 mol Cu 6.02 X 1023 atoms Cu 63.5 g Cu 1 mol Cu= 3.4 X 1023 atoms Cu

Learning Check!How many atoms of K are present in 78.4 g of K?

Learning Check!What is the mass (in grams) of 1.20 x 1024 molecules of glucose (C6H12O6)?

Using EquationsChemical equations also show mole ratios.

In the equation:

2LiOH + CO2 Li2CO3 + H2O

For every 2 moles of LiOH and 1 mole of CO2, 1 mole of Li2CO3 and 1 mole of H2O are produced. Mole-Mass ConversionsMost of the time in chemistry, the amounts are given in grams instead of molesWe still go through moles and use the mole ratio, but now we also use molar mass to get to gramsExample: How many grams of chlorine are required to react completely with 5.00 moles of sodium to produce sodium chloride?2 Na + Cl2 2 NaCl5.00 moles Na 1 mol Cl2 70.90g Cl2 2 mol Na 1 mol Cl2 = 177g Cl2Learning CheckFor each of the following equations, calculate the moles of product that would be produced by reacting 4.0 moles of oxygen, O2. Show your work.4Fe + 3O2 Fe2O32Mg + O2 2MgO2Cu + O2 2CuOLearning CheckGiven the following reaction: N2 + O2 2NO

How many moles of NO can form when 40.0 g of N2 react with excess oxygen?How many grams of NO can form, using the amounts in part A?