task 2 subnetting
DESCRIPTION
Task 2 subnettingTRANSCRIPT
TASK 2Problem 1
Host IP Address 172.30.1.33subnet Mask 255.55.0
Number of Subnet Bit 2^8=256Number of Subnet 8
Number of Host Bits per Subnet
2^-2=256-2=254
Number of Usable Hosts per Subnet
172.30.1.0
Subnet Address for IP Address
172.30.1.1
IP Address of first Hosts on this subnet
172.30.1.255
IP Address of Last Hosts on Subnet
172.30.1.255
Broadcast Address for this Subnet
172.30.1.253
172 30 1 33IP Address 10101100 00011110 0000001 00100001
255 255 255 0Subnet mask
11111111 1111111 11111111 0000000
(NETWORK) (HOST)
Total number of subnet mask :-
Network : 2^8=256
Number of hosts bits per subnet : 5 bits
Number of usable host per subnet
Host : = 2^-22 (256-2)
=254
Network
172 30 1 33IP Address 10101100 00011110 00000001 00100001
Subnet mask
11111111 11111111 11111111 00000000
10101100 00011110 00000001 00000000Network 172 30 1 0
Network= IP Address + Subnet Mask
Broadcast
Subnet mask
1111111 11111111 11111111 00000000
255 255 255 010101100 00011110 000000001 00000000
Network 172 30 1 0Broadcast 10101100 00011110 00000001 11111111
172 30 1 255
Broadcast = replace the number 0 to number 1 appearing on network address .
First Hosts
Subnet mask
1111111 11111111 11111111 00000000
255 255 255 010101100 00011110 00000001 11111111
172 30 1 255Network 1010110 00011110 00000001 0000001
172 30 1 1Broadcast = replace the number 0 to number 1 at 32 bits in the broadcast .
First host
Subnet mask
11111111 11111111 11111111 00000000
255 255 255 010101100 00011110 00000001 00000000
Network 172 30 1 0First host 10101100 00011110 00000001 00000001
1721 30 1 1First host = replace the number 0 to the number 1 at 32 bits in the broadcast .
Last host
Subnet mask
11111111 11111111 11111111 00000000
255 255 255 010101100 000011110 00000001 000000000
Network 172 30 1 0Last host 10101100 00011110 00000001 11111110
172 30 1 254Last host = replace the number 0 to br the number 1 at – 31 bits in the broadcast .
Problem 2
Host IP Address 172.30.1.33Subnet mask 255.255.255.252
Number of subnet bit 14Number of subnet 2^14=16384
Number of host bits per subnet
2
Number of usable hosts per subnet
2^2-2 =4-2=2
Subnet address for this IP Address
172.30.1.32
IP Address of first host on this subnet
172.30.1.32
IP Address of last host on subnet
172.30.1.254
Broadcast Address for this Subnet
172.30.1.35
172 30 1 33IP Address 10101100 00011110 00000001 00100001
255 255 255 252Subnet mask
11111111 1111111 1111111 11111111
Host
network
total number of subnet mask
network : 2^14 = 16384
number of host bits per subnet : 2 bits
number of usable host per subnet host : = 2^2-2 = 4.2 = 2
Network
172 30 1 33IP Address 10101100 00011110 00000001 00100001Subnet mask
11111111 1111111 11111111 11111100
255 255 255 25210101100 00011110 00000001 00100000
Network 172 30 1 1Broadcast 10101100 00011110 00000001 00100011
172 30 1 35Broadcast = replace the number 0 to number 1 appearing on network address .
First host
Subnet mask
11111111 11111111 11111111 11111100
255 255 25 25210101100 00011110 00000001 00100000
Network 172 30 1 32First host 10101100 00011110 00000001 00100001
First host = replace the number 0 be the number 1 at 32 bits in the broadcast .
Last host
Subnet mask
11111111 11111111 00000000 00000000
255 255 0 010101100 00010001 00000000 00000000
Network 172 17 0 0Last host 10101100 00010001 11111111 11111110
172 17 255 254
Problem 5
Host IP Address 192.168.3.219Subnet mask 255.255.255.0
Number of subnet bit 8Number of subnet 28=256
Number of host bits per subnet
8
Number of usable hosts per subnet
28-2=256-2=254
Subnet Address for this IP Address
192.192.10.0
IP Address of first host on this subnet
192.192.10.254
IP Address of last host on subnet
192.192.10.254
Broadcast address for this Subnet
192.192.10.255
192 168 3 219IP Address 11000000 10101000 00000011 11011011
255 255 255 0Subnet mask
11111111 11111111 11111111 00000000
(network) (host)
Total number of subnet mask
Network : 28=256
Number of hosts bits per subnet : 8 bits
Number of usable host per subnet
Host : =28-2-256-2=254
Network
192 168 3 219
IP Address 11000000 10101000 00000011 11011011
Subnet mask
11111111 11111111 11111111 00000000
11000000 10101000 00000011 00000000
Network 192 168 3 0
Network = IP Address + Subnet Mask
Broadcast
Subnet mask
11111111 11111111 11111111 00000000
255 255 255 0
11000000 10101000 00000011 00000000
Network 192 168 3 0
Broadcast 10101100 10101000 00000011 11111111
192 168 3 255
Broadcast = replace the number 0 to number 1 appearing on network address
First host
Subnet mask
11111111 11111111 1111111 00000000
255 255 255 0
11000000 10101000 00000011 00000000
Network 192 168 3 0
First host 11000000 10101000 00000011 00000001
192 168 3 1
First host = replace the number 0 to the number 1 at 32 bits in broadcast
Last host
Subnet mask
11111111 11111111 11111111 00000000
255 255 255 0
11000000 10101000 00000011 00000000
Network 192 168 3 254
Last host 10101100 00101000 00000011 11111110
192 168 3 254
Last host = replace the number 0 to the number 1 at 17-31 =
Problem 6
Host IP Address 192.168.3.219
Subnet mask 255.255.255.252
Number of subnet bit 24
Number of subnet 214=16384
Number of host bits per subnet
2
Number of usable hosts per subnet
22=2=4-2=4
Subnet Address for this IP Address
192.168.3.216
IP Address of first host on this subnet
192.168.3.217
IP Address of last host and subnet
192.168.3.218
Broadcast address for this subnet
192.168.3.219
192 168 3 219
IP Address 11000000 10101000 00000011 11011011
255 255 255 252
Subnet mask
11111111 11111111 11111111 11111100
(network) (host)
Total number of subnet mask
Network : 214=16384
Number of host bits per subnet : 2 bits
Number of usable host per subnet
Host : 282-2=4=2=2
Network
192 168 3 219
IP Address 11000000 10101000 00000011 11011011
Subnet mask
11111111 11111111 11111111 11111100
11000000 10101000 00000011 11011000
Network 192 168 3 216
Network = IP Address + Subnet Mask
Broadcast
Subnet mask
11111111 11111111 11111111 11111100
255 255 255 252
11000000 10101000 00000011 11011011
Network 192 168 3 216
Broadcast 10101100 10101000 00000011 11011011
192 168 3 210
Broadcast = replace the number 0 to number 1 appearing on network address
First host
Subnet mask
111111111 11111111 11111111 11111100
255 255 255 252
11000000 10101000 00000011 11011000
Network 192 168 3 217
First host 11000000 10101000 00000011 11011001
192 168 3 217
First host = replace the number 0 be the number 1 at 32 bits in the broadcast
Last host
Subnet mask
11111111 1111111 111111111 11111100
255 255 255 252
11000000 10101000 00000011 11011000
Network 192 168 3 216
Last host 10101100 00101000 00000011 11011010
Network 192 168 3 216
Last host 10101100 00101000 00000011 11011010
192 168 3 218
Last host = replace the number 0 to the number 1 at 17-bits in the broadcast