teachers guide for general mathematics

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    FIRST

    QUARTER

    Hour1

    Hour2

    Hour3

    Hour

    4

    W

    eeka

    Lesson1

    Lesson1,2

    Lesson3

    Lesson

    3

    Weekb

    Lesson4

    Lesson5,6

    Lesson6

    Lesson

    7

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    eekc

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    Review/E

    xam

    Weekd

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    11

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    eeke

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    SECOND

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    College Readiness Standards

    Foundational Skills

    DepEd Functional Skills

    Produce all forms of texts (e.g., written, oral,

    visual, digital) based on:

    1. Solid grounding on Philippine experience

    and culture;

    2.

    An understanding of the self, community,and nation;

    3. Application of critical and creative

    thinking and doing processes;

    4. Competency in formulating

    ideas/arguments logically, scientifically,

    and creatively; and

    5. Clear appreciation of ones responsibility

    as a citizen of a multicultural Philippines

    and a diverse world

    Visual and information literacies

    Media literacy

    Critical thinking and problem solving skills

    Creativity

    Initiative and self-direction

    College Readiness Standards

    Foundational Skills

    DepEd Functional Skills

    Systematically apply knowledge, understanding,

    theory, and skills for the development of the self,

    local, and global communities using prior

    learning, inquiry, and experimentation

    Global awareness

    Scientific and economic literacy

    Curiosity

    Critical thinking and problem solving skills

    Risk taking

    Flexibility and adaptability

    Initiative and self-direction

    College Readiness Standards

    Foundational Skills

    DepEd Functional Skills

    Work comfortably with relevant technologies and

    develop adaptations and innovations for

    significant use in local and global communities;

    Global awareness

    Media literacy

    Technological literacy

    Creativity

    Flexibility and adaptability

    Productivity and accountability

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    College Readiness Standards

    Foundational Skills

    DepEd Functional Skills

    Communicate with local and global communities

    with proficiency, orally, in writing, and through

    new technologies of communication;

    Global awareness

    Multicultural literacy

    Collaboration and interpersonal skills

    Social and cross-cultural skills

    Leadership and responsibility

    College Readiness Standards

    Foundational Skills

    DepEd Functional Skills

    Interact meaningfully in a social setting and

    contribute to the fulfillment of individual and

    shared goals, respecting the fundamental humanity

    of all persons and the diversity of groups andcommunities

    Media literacy

    Multicultural literacy

    Global awareness

    Collaboration and interpersonal skills

    Social and cross-cultural skills

    Leadership and responsibility

    Ethical, moral, and spiritual values

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    (x, y)

    (x, y)

    x

    y

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    f= {(1, 2), (2, 2), (3, 5), (4, 5)} g= {(1, 3), (1, 4), (2, 5), (2, 6), (3, 7)}

    h= {(1, 3), (2, 6), (3, 9), . . . , (n, 3n), . . .}

    f h x

    y g (1, 3) (1, 4)

    x y

    f

    g

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    h

    f g x X y Y h X

    y x = 7 y = 11 13 x = 2

    y= 17 19

    x = a (a, b) (a, c)

    y x= a

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    (a) (b) (c) (d) (e)

    x

    y x

    x y

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    y= 2x + 1

    y= x2 2x + 2 x2 + y2 = 1

    y=

    x + 1

    y=2x + 1

    x 1 y= x + 1 x

    x y x = 0 y +1

    1

    x

    R

    R

    [1, 1]

    [1, +)

    (, 1) (1, +) R

    y f(x) y

    x f

    f(x) = 2x + 1

    q(x) =x2 2x + 2 g(x) =

    x + 1

    r(x) =2x + 1

    x 1 F(x) = x + 1 x

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    C x

    40

    40 C(x) = 40x

    A x

    A = xy x

    x+ 2y = 100 y = (100 x)/2 = 50 0.5x A(x) =x(50 0.5x) = 50x 0.5x2

    300

    1

    m

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    t(m)

    t(m) =

    300 0< m 100300 + m m >100

    8.00

    1.50

    d

    F(d)

    F(d) =

    8 0< d 48 + 1.5d d >4

    d d d 4.1 = 4.9 = 4

    25 0 0

    100

    100

    100

    T(x)

    T(x)

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    15

    1, 000

    400

    f(x) =

    1000 0 x 31000 + 400x 3 x >3

    700

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    f(x) = 700x4 x N

    150

    130 110

    100

    f(x) =

    150x 0 x 20130x 21 x 50110x 51 x 100100x x >100

    x N

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    x

    f a

    a f f(a)

    x= 1.5

    f(x) = 2x + 1

    q(x) =x2 2x + 2 g(x) = x + 1

    r(x) =2x + 1

    x 1 F(x) = x + 1 x

    1.5 x

    f(1.5) = 2(1.5) + 1 = 4

    q(1.5) = (1.5)2 2(1.5) + 2 = 2.25 3 + 2 = 1.25 g(1.5) = 1.5 + 1 = 2.5

    r(1.5) =2x + 1

    x 1 =2(1.5) + 1

    (1.5) 1 =3 + 1

    0.5 = 8

    F(1.5) = x + 1 = 1.5 + 1 = 1 + 1 = 2

    g(4) r(1) g r

    4 g(x) r(x)

    f q

    f(3x 1) q(2x + 3)

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    f(3x 1) x f(x) = 2x + 1 (3x 1)

    f(3x 1) = 2(3x 1) + 1 = 6x 2 + 1 = 6x 1 q(3x + 3) x q(x) =x2

    2x + 2 (2x + 3)

    q(2x + 3) = (2x + 3)2 2(2x + 3) + 2 = (4x2 + 12x + 9) 4x 6 + 2 = 4x2 + 8x + 5

    f(x) =x 2

    f(0) 2 f(3)

    f(1)

    f() 2 f(x + 1) x 1

    f(3x) 3x 2

    f(x) = 4

    x

    f(1) 4

    f(2) 2

    f(1) 4 f(

    2) 2

    2

    f(1/x) 4x

    f(2x) 2/x

    f(x) =

    x 3 f(3) 0

    f(4) 1

    f(12) 3

    f(x 3) x 6 f

    1

    1 x

    3x 21 x

    f(x2 + 4x + 7)

    x2 + 4x + 4 |x + 2|

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    200

    25

    C(x) = 25x +200 x C(x)

    2700 3950

    t s(t) = 5t2 + 100 g= 10m/s2

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    13

    25

    1

    3+

    2

    5=

    5

    15+

    6

    15=

    5 + 6

    15

    =11

    15

    1

    x 3 2

    x 5

    (x 3)(x 5) (x2 8x + 15) 1

    x 3+ 2

    x 5= x 5

    x2 8x + 15+ 2(x 3)

    x2 8x + 15 =x 5 + 2x 6

    x2 8x + 15=

    3x 11x2 8x + 15

    10

    21

    15

    8

    10

    2115

    8 =

    2 53 7

    3 52 2 2=

    2 5 3 53 7 2 2 2=

    25

    28

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    x2 4x 5x2 3x + 2

    x2 5x + 6x2 3x 10

    x2 4x 5x2 3x + 2

    x2 5x + 6x2 3x 10=

    (x + 1)(x 5)(x 2)(x 1)

    (x 2)(x 3)(x 5)(x + 2)

    =(x + 1)

    (x 5)

    (x 2)(x 3)

    (x 2)(x 1)

    (x 5)(x + 2)

    =(x + 1)(x 3)(x 1)(x + 2) =

    x2 2x 3x2 + x 2

    f g

    f+ g (f+ g)(x) =f(x) + g(x)

    f g (f g)(x) =f(x) g(x)

    f g (f g)(x) =f(x) g(x)

    f /g (f /g)(x) =f(x)/g(x)

    x g(x) = 0

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    f(x) =x + 3

    p(x) = 2x 7

    v(x) =x2 + 5x + 4

    g(x) =x2 + 2x 8 h(x) = x + 7

    2 x t(x) = x 2

    x + 3

    (v+ g)(x)

    (fp)(x) (f+ h)(x)

    (p f)(x) (v/g)(x)

    (v+ g)(x) =

    x2 + 5x + 4

    +

    x2 + 2x 8= 2x2 + 7x 4 (fp)(x) = (x + 3) (2x 7) = 2x2 x 21

    (f+ h)(x) = (x + 3) +x + 7

    2 x = (x + 3) 2 x2 x +

    x + 7

    2 x =(x + 3)(2 x) + (x + 7)

    2 x =

    =6 x x2 + x + 7

    2 x =13 x2

    2 x =13 x2

    2 x 11=

    x2 13x 2

    (p f)(x) = (2x 7) (x + 3) = 2x 7 x 3 =x 10

    (v/g)(x) = (x2 + 5x + 4) (x2 + 2x 8) = x2 + 5x + 4

    x2 + 2x 8

    f(x) = 2x + 1 q(x) =x2 2x + 2 r(x) =2x + 1x 1

    f1(x) =x2 + 3

    q(x) f(x)

    x2 + 3

    q(x) + f(x) = (x2 2x + 2) + (2x + 1)=x2 + 3

    =f1(x)

    f1(x) =q(x) + f(x)

    f2(x) =x24x + 1

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    q(x) f(x) x2 4x + 1 q(x) f(x) = (x2 2x + 2) (2x + 1)

    =x2 4x + 1

    =f2(x) f2(x) =q(x) f(x)

    f3(x) =2x2 + x

    x 1

    2x2 + x

    x 1 x 1 r(x) = 2x + 1

    x 1 f(x) r(x)

    f(x) + r(x) = 2x + 1 +2x + 1

    x 1

    =(2x + 1)(x

    1)

    x 1 +2x + 1

    x 1=

    (2x + 1)(x 1) + (2x + 1)x 1

    =(2x2 x 1) + (2x + 1)

    x 1=

    2x2 + x

    x 1=f3(x)

    (f+ g)(x) =f(x) + g(x)

    f1(x) =q(x) + f(x) = (q+ f)(x)

    f2(x) =q(x) f(x) = (q f)(x) f3(x) =f(x) + r(x) = (f+ r)(x)

    g1(x) = 2x3 3x2 + 2x+ 2

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    2x3 3x2 + 2x + 2 f(x) q(x)

    f(x) q(x) = (2x + 1)(x2 2x + 2)= (2x)(x2 2x + 2) + (x2 2x + 2)

    = (2x3

    4x2

    + 4x) + (x2

    2x + 2)= 2x3 3x2 + 2x + 2=g1(x)

    g1(x) =f(x) q(x)

    g2(x) = x 1

    r(x) = 2x + 1

    x 1 x 1 2x+ 1

    f(x)

    r(x)

    f(x)

    r(x) = (2x + 1) 2x + 1

    x 1= (2x + 1) x 1

    2x + 1

    =2x + 1

    2x + 1 (x 1)

    =x 1=g2(x)

    g2(x) =

    f(x)

    r(x)

    g3(x) = 1

    x 1

    g3(x) = 1

    x 1 r(x) = 2x + 1

    x 1 2x + 1 r(x) f(x) = 2x + 1

    r(x)

    f(x)=

    2x + 1

    x 1 (2x + 1)

    =

    2x + 1

    x 1 1

    2x + 1

    = 1

    x 1=g3(x)

    g3(x) = r(x)

    f(x)

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    f(x) = 2x + 1

    q(x) =x2 2x + 2 (2x + 1)2 2(2x + 1 ) + 2

    f g (f g)

    (f g)(x) =f(g(x)).

    f(x) = 2x + 1 q(x) =x2 2x + 2 r(x) =2x + 1

    x 1

    g(x) = x + 1 F(x) = x + 1

    (g f)(x)

    (g f)(x) =g(f(x))=

    f(x) + 1

    =

    (2x + 1) + 1

    =

    2x + 2

    (q f)(x) (f q)(x)

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    (q f)(x) =q(f(x))= [f(x)]2 2 [f(x)] + 2

    = (2x + 1)

    2

    2(2x + 1) + 2= (4x2 + 4x + 1) (4x + 2) + 2= 4x2 + 1

    (f q)(x) =f(q(x))= 2(x2 2x + 2) + 1= 2x2 4x + 5

    (q f)(x) (f q)(x)

    (f r)(x)

    (f r)(x) =f(r(x))= 2r(x) + 1

    = 2

    2x + 1

    x 1

    + 1

    =4x + 2

    x 1 + 1

    =(4x + 2) + (x 1)

    x 1=

    5x + 1

    x 1

    (F r)(5)

    (F r)(5) =F(r(5))= r(5) + 1

    =

    2(5) + 1

    5 1

    + 1

    =

    11

    4

    + 1 = 2 + 1 = 3

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    f g f+g f g f g f /g g/f

    f(x) =x + 2 g(x) =x2 4 x2 + x 2 x2 + x + 6 x3 + 2x2 4x 8 1

    x 2 x 2

    f(x) =

    x 1 g(x) =x2 + 4

    x 1 + x2 + 4 x 1 x2 4 x 1(x2 + 4)

    x 1

    x2 + 4 x 2

    f(x) =x 2x + 2

    g(x) = 1

    x

    x 2x + 2

    +1x

    x 2x + 2

    1x

    x 2x(x + 2)

    x(x 2)x + 2

    x + 2x(x 2)

    f(x) = 1

    x + 2 g(x) =

    x 2x

    1

    x + 2+

    x 2x

    1

    x + 2x 2

    x

    x 2x(x + 2)

    x

    (x + 2)(x 2) (x + 2)(x 2)

    x

    f(x) = 1

    x2 g(x) =

    x

    1

    x2+

    x

    1

    x2 x

    x

    x2

    1

    x2

    x x2

    x

    f(x) =x2 + 3x g(x) =x 2 f g g f f f g g x2 x 2 x2 + 3x 2 x4 + 6x3 + 12x2 + 9x x 4

    (f g) = x (g f) =x

    f(x) = 3x 2 g(x) = 13(x + 2) f(x) = x

    2 x g(x) = 2xx 1 f(x) = (x 1)3 + 2 g(x) = 3x 2 + 1

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    p(x) =anxn + an1x

    n1 + an2xn2 + + a1x + a0

    a0, a1, . . . , an R an= 0 n a0, a1, a2, . . . , an

    an anxn

    a0

    100, 000

    y

    x y=100, 000

    x

    x

    y

    750 g(x)

    g(x) =100, 000

    x + 750

    x

    y

    https://www.geogebra.org/downloadhttps://www.desmos.com/calculator
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    f(x) = p(x)

    q(x) p(x) q(x)

    q(x) q(x)0 f(x) x q(x)

    = 0

    v v(t)

    t

    v t

    t

    v

    v(t) =10

    t v t

    c(t) = 5t

    t2 + 1

    t c(t)

    t = 1, 2, 5, 10

    t

    c(t)

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    a b c

    x y

    http://illuminations.nctm.org/Lesson.aspx?id=1968
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    x

    y

    y = a

    x b +c

    x P(x)

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    P(x) =2x2 + 800

    x

    b(t) = 50t

    t + 1 0 t 20

    t b(t)

    t= 1, 2, 5, 10, 15, 20

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    x2 + 3x + 2

    x + 4

    1

    3x2

    x2 + 4x 32

    x + 1

    x3 1

    1

    x + 2x 2

    1

    (x + 2)(x 2)

    f(x) = p(x)

    q(x)

    p(x) q(x)

    q(x)

    2

    x 3

    2x=

    1

    5

    5

    x 3 2

    x f(x) =

    x2 + 2x + 3

    x + 1

    y=x2 + 2x + 3

    x + 1

    x

    x y

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    15x

    1

    5x4 6x7 + 1

    5 x3x

    y= 5x3 2x + 1

    8

    x 8 = x

    2x 1

    x 2 = 4

    x 1x + 1

    =x3

    y=7x3 4x + 1

    x2 + 3

    6x 5x + 3

    0

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    x + 1

    2x = 10

    x + 1

    2x 10

    x 2

    x 3

    2x=

    1

    5

    10x 10x

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    10x

    2

    x

    10x

    3

    2x

    = 10x

    1

    5

    20

    15 = 2x

    5 = 2x

    x=5

    2

    x x

    x + 2 1

    x 2= 8

    x2 4

    x

    x + 2 1

    x

    2

    = 8

    (x

    2)(x + 2)

    (x2)(x+2)

    (x 2)(x + 2) xx + 2

    (x 2)(x + 2) 1x 2= [(x 2)(x + 2)]

    8

    (x 2)(x + 2)

    (x 2)x (x + 2) = 8x2 3x 10 = 0

    x2

    3x 10 = 0(x + 2)(x 5) = 0

    x + 2 = 0 x 5 = 0x= 2 x= 5

    x= 2 x= 5

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    x

    x

    12 + x 25 + x

    12 + x

    25 + x= 0.6

    25 + x

    12 + x

    25 + x = 0.6

    12 + x= 0.6(25 + x)

    12 + x= 0.6(25) + 0.6x

    x 0.6x= 15 120.4x= 3

    x= 7.5

    x

    60%

    v= dt

    v= dt t= dv

    v v+ 10 5v

    5v+10

    43

    5

    v+

    5

    v+ 10=

    4

    3

    3v(v+ 10)

    5

    v+

    5

    v+ 10=

    4

    3

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    3v(v+ 10) 5v

    + 3v(v+ 10) 5v+ 10

    = 3v(v+ 10) 43

    15(v+ 10) + 15v = 4v(v+ 10)

    30v+ 150 = 4v2 + 40v

    4v2 + 10v 150 = 02v2 + 5v 75 = 0

    (2v+ 15)(v 5) = 0v = 15

    2 v = 5

    v

    (a, b) {x|a < x < b} a b[a, b] {x|a x b} a b[a, b) {x|a x < b} a b(a, b]

    {x|a < x

    b} a b

    (a, ) {x|a < x} a

    [a, ) {x|a x} a

    (, b) {x|x < b} b

    (, b] {x|x b} b

    (, ) R

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    x

    2x

    x + 1 1

    2x

    x + 1 1 0

    2x (x + 1)x + 1

    0x

    1

    x + 1 0

    x= 1 x= 1 x = 1

    x= 1

    1

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    1 1 x 1x + 1

    x < 1 1< x 1 x= 2 x= 0 x= 2x 1 +x + 1 + +x 1x + 1

    + +

    x < 1 x 1

    1

    {x R|x

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    x < 1 1< x x

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    8

    x2 > x

    8

    x2 x >0

    8 x3x2

    >0

    (2 x)(x2 + 2x + 4)x2

    >0

    x = 16 x= 28 x = 0 x= 4

    4

    x

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    1120

    x

    1600

    x + 4

    1600

    x + 41120

    x 10

    1600

    x + 41120

    x 10

    160

    x + 4112

    x 1

    160x + 4

    112x

    1 0160x 112(x + 4) (x2 + 4x)

    x(x + 4) 0

    160x 112x 448 x2 4xx(x + 4)

    0

    x2 44x + 448x(x + 4)

    0(x 16)(x 28)

    x(x + 4)

    0

    x= 16 x = 28 x= 0 x = 4

    x 2 2+

    x 2

    x 3 2.5 2.1 2.01 2.001 2.0001 x 2f(x) f(x)

    f(x) + x 2 f(x) x 2

    x 2+

    x 1 1.5 1.9 1.99 1.999 1.9999 x 2+f(x) 3 7 39 399 3999 39999 f(x)

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    f(x) x 2+ f(x) x 2

    x 2 x= 2

    x= a f f

    x a

    a

    x= a

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    x

    f(x) x x +

    f(x) x +

    x x +f(x) f(x) 1

    f(x) x x f(x) x

    x 5 10 100 1000 10000 x f(x) f(x) 1+

    x f(x)

    y= 1

    y = b f f(x)

    b x x + x

    y= b b

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    x 2 x + x

    x

    x =2 x= 2

    x < 2 2< x 2 x= 3 x= 0 x= 3x 2 +x + 2 + +x 2x + 2

    + + x x x

    x x= 2

    y

    f(x)< 1 x + f(x)> 1 x (2, 0)

    f(x)

    x 2

    f(x)

    x 2+

    f(x)

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    y=x 2x + 2

    y = 1 f(x)

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    f(x) (, 1) (1, +)

    f(x) =4x2 + 4x + 1

    x

    2

    + 3x + 2

    x x x +

    x

    x= 1000 4x2 + 4x + 1 4, 004, 001

    4x2 4, 000, 000

    x x2 + 3x+ 2 x2

    x

    f(x)

    4x2

    x2 = 4

    f(x) x y= 4

    f(x) = 2x2 53x2 + x 7

    2x2 53x2 + x 7

    2x2

    3x2 =

    2

    3 x y= 23

    f(x) = 3x + 4

    2x2 + 3x + 1

    3x + 4

    2x2 + 3x + 1

    3x

    2x2 =

    3

    2x x x

    3

    2x

    0 y= 0

    f(x) = 4x3 1

    3x2 + 2x 5

    x

    4x3

    1

    3x2 + 2x 5 4x3

    3x2 =4x

    3

    x 4x

    3 x

    y

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    n m

    n < m y= 0

    n = m y = ab a b

    n > m

    x

    y

    y

    y

    x= 0

    x x

    x

    f(x) =3x2 8x 32x2 + 7x 4

    x

    f(x) (, 4) (4, 12) (12 , +)

    f(x)

    f(x) =3x2 8x 32x2 + 7x 4=

    (3x + 1)(x 3)(2x 1)(x + 4)

    y f(0) = 0 0 30 + 0 4=

    3

    4

    x 3x + 1 = 0 x= 13 x 3 = 0 x= 3

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    2x 1 = 0 x= 12 x + 4 = 0 x= 4

    y= 32

    f(x)

    x

    4, 13 , 12 3

    x < 4 4< x < 13

    13

    < x < 12

    1

    2< x 3

    x= 10 x= 2 x= 0 x= 1 x= 103x + 1 + + +x 3 +2x

    1

    + +

    x + 4 + + + +(3x + 1)(x 3)(2x 1)(x + 4) + + +

    x x x x x

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    y

    x

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    R

    x y

    x

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    f(x) = 2

    x + 1

    f(x) = 2

    x2 + 2x + 1

    f(x) = 3x

    x + 3

    f(x) =2x + 3

    4x 7

    f(x) =(4x 3)(x 1)(2x + 1)(x + 1)

    f(x) =(5x 2)(x 2)(3x 4)(x + 2)

    f(x) = x2 x + 6x2

    6x + 8

    f(x) =x2 4x 5

    x 4

    f(x) = x 1x3 4x

    f(x) =x2 9x2 + 4

    N(t) t

    N(t) = 75t

    t + 5 t 0.

    N

    N(t) t t N(t)75

    c

    t

    c(t) = 20t

    t2 + 2 t 0.

    c(t) c(t) t t c(t) 0

    x = 3 x =3 y = 1 x 5 y 59 f(x) =

    (x 5)2(x2 + 1)(x + 3)(x 3)(x2 + 5)

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    p = 5125000V2 449000V+ 19307

    125V2(1000V 43) p V

    p

    V

    V = 0 V = 43/1000

    p= 0

    p

    V

    V = 0.043

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    TC=5

    9(TF 32)

    TF =9

    5TC+ 32

    F

    C

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    200F 93.33C

    120C 248F

    f x1 x2 f f(x1) =f(x2) y x

    2

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    d

    F(d) =

    8.00 0< d 4(8.00 + 1.50 d) d >4

    d d

    F(3) = 8

    F(3) =F(2) =F(3.5) = 8 F

    y x

    https://www.world-airport-codes.com/
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    y x 2

    y= x24

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    y= 2x 1

    x 4 3 2 1 y 9 7 5 3 1

    y x

    x y

    x 9 7 5 3 1 y 4 3 2 1

    x

    y

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    x 4 3 2 1 y 1 1 1 1 0

    y

    x y= 1 x= 1, 2, 3, 4

    x y

    x 1 1 1 1 0 y 4 3 2 1

    x= 1 y

    x y

    x y

    f A B f

    f1 B A f1(y) = x

    f(x) =y y B

    x y

    y

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    x

    y= f(x)

    x y

    y x

    f(x) = 3x + 1

    y= 3x + 1

    x y x= 3y+ 1

    y x

    x= 3y+ 1

    x 1 = 3yx 1

    3 =y = y= x 1

    3

    f(x) = 3x + 1 f1(x) =x 1

    3

    f(f1(x)) f1(f(x))

    f(x) f1(x)

    f1(x) f(x)

    f(f1(x)) =x x f1

    f1(f(x)) =x x f

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    g(x) =x3 2

    y= x3 2 x y x= y3 2 y x

    x= y3 2x + 2 =y3

    3

    x + 2 =y = y= 3x + 2 g(x) =x3 2 g1(x) = 3x + 2

    f(x) =2x + 1

    3x 4

    y=2x + 1

    3x 4

    x y x=2y+ 1

    3y

    4 y x

    x=2y+ 1

    3y 4x(3y 4) = 2y+ 13xy 4x= 2y+ 13xy 2y= 4x + 1 y

    y

    y(3x

    2) = 4x + 1

    y=4x + 1

    3x 2

    f(x) f1(x) =4x + 1

    3x 2

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    f(x) =x2 + 4x 2

    y= x2 + 4x 2

    x y x= y2 + 4y 2 y x

    x= y2 + 4y 2

    x + 2 =y2 + 4y

    x + 2 + 4 = y2 + 4y+ 4

    x + 6 = (y+ 2)2

    x + 6 =y + 2x + 6 2 =y = y= x + 6 2

    y =x + 6 2 x y x = 3 y 1 5 f(x) =x2 + 4x 2

    f(x) = |3x|

    y= |3x|

    f1 f

    f(1) =f(1) = 3 x 1 y f

    y= |4x| x y x= |4y|

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    y x

    x= |4y|x= (4y)

    2 |x| =

    x2

    x2 = 4y2

    x2

    4 =y2

    x2

    4 =y = y=

    x2

    4

    x = 2 y = 1 y =1 y =

    x2

    4

    f(x) = |3x|

    k(t) = 59(t32)+273.15 t

    k= 59(t 32) + 273.15 k t

    t k

    k=5

    9

    (t

    32) + 273.15

    k 273.15 =59

    (t 32)9

    5(k 273.15) =t 32

    9

    5(k 273.15) + 32 =t = t= 9

    5(k 273.15)

    t(k) = 95(k 273.15) k

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    f(x) =1

    2x + 4 f1(x) = 2x 8

    f(x) = (x + 3)3 f1(x) = 3x 3 f(x) =

    3

    x 4 f1(x) =

    4x + 3

    x

    f(x) =x + 3

    x 3 f1(x) =

    3x + 3

    x 1 f(x) =

    2x + 1

    4x 1 f1(x) =

    x + 1

    4x 2

    f(x) = |x 1|

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    y= x

    y = x

    y= x

    y =x

    y= x

    http://artforkidshub.com/5-free-symmetry-art-activity/
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    y= x

    x y

    f

    f1 f1(f(x)) =x f1(x) y f(x) x

    x f(x) y f

    1(y) x

    y= x

    y = f1(x) y = f(x) = 2x+ 1

    {x |2 x 1.5} f(x)

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    y= 2x + 1 y= x

    {y R | 3 y 4}

    f1(x) =x 1

    2

    f1(x) = [3, 4] f1(x) = [2, 1.5]

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    f(x) f1(x)

    [2, 1.5] [3, 4] [3, 4] [2, 1.5]

    f(x) = 1

    x

    f(x) = 1

    x y = x

    y= x f(x) f1(x) =f(x)

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    f1(x) =f(x) = 1

    x

    f(x) = 3

    x + 1

    f(x) y= x

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    f(x) =

    3

    x + 1

    y = x

    3

    1

    f1(x) =x3 1

    f(x) = 5x 1x + 2

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    f(x) = (, 2) (2, ) f(x) = (, 5) (5, )

    x= 2

    y= 5 y= x

    x

    y

    y= x

    x= 5 y= 2

    f(x) f1(x)

    (, 2) (2, ) (, 5) (5, ) (, 5) (5, ) (, 2) (2, )

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    y= x

    y= x

    f1

    1(x) =f(x)

    f(x) = (x + 2)2 3 2 =3(x + 2)2

    2

    x 0

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    x 0 x y x=

    3(y+ 2)2

    2 , y 0

    y x

    x=3(y+ 2)2

    22x

    3 = (y+ 2)2

    2x

    3 =y + 2 y 2

    2x

    32x

    3 2 =y = y=

    2x

    3 2

    x= 54

    f1(54) =

    2(54)

    3 2 =

    108

    3 2 =

    36 2 = 6 2 = 4

    t

    d

    t(d) = 12.5d3

    t=

    12.5

    d

    3

    d t

    d t

    t= 12.5d3

    3

    t=12.5

    d

    d=12.5

    3

    t

    d(t) =12.5

    3

    t

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    t= 6.5 d(6.5) = 22.53

    6.5= 12.06

    12.06

    f(x) = x2 + 1

    {0, 0.5, 1, 1.5, 2, 2.5, 3}

    x 0 0.5 1 1.5 2 2.5 3

    f(x) 1 1.25 2 3.25 5 7.25 10 f

    x 1 1.25 2 3.25 5 7.25 10

    f1(x) 0 0.5 1 1.5 2 2.5 3 A ={(4, 4), (3, 2), (2, 1), (0, 1), (1, 3), (2, 5)}

    A1 = {(4, 4), (2, 3), (1, 2), (1, 0), (3, 1), (5, 2)}

    f(x) = 2

    x 2 + 3 [2, )

    [3, ) [2, )

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    f(x) =3x + 2

    x 4 (, 3) (3, )

    (, 4) (4, )

    x= a

    f1

    (a) = 0 1/2

    w l

    w= (3.24 103)l2

    l 0

    l=

    w/(3.4 103)

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    n

    s n= 2s

    b f(x) = bx y = bx

    b >0 b

    = 1

    x = 3, 2, 1, 0, 1, 2 3

    y=13

    x y= 10x y= (0.8)x

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    x 3 2 1

    y=13

    x

    1

    3

    1

    9

    1

    27

    y= 10x 11000

    1100

    110

    y= (0.8)x

    f(x) = 3x f(2) f(2) f12 f(0.4) f()

    f(2) = 32 = 9

    f(2) = 32 = 132

    =1

    9

    f

    1

    2

    = 31/2 =

    3

    f(0.4) = 30.4 = 32/5 = 5

    32 = 5

    9

    3.14159 3 f() = 3 33.14 33.14159

    3

    3

    b

    b

    g(x) =a bxc

    + d

    a c d

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    t t= 0

    t

    t= 0

    t= 100 20(2)

    t= 200 = 20(2)2

    t= 300 = 20(2)3

    t= 400 = 20(2)4

    y= 20(2)t/100

    y T y0

    y t y= y0(2)t/T

    t

    t= 0

    t= 10

    t= 20

    t= 30

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    y= 1012

    t/10

    100, 000 6%

    t

    t= 0 = 100, 000

    t= 1 = 100, 000(1.06) = 106, 000

    t= 2 = 106, 000(1.06) = 112, 360

    t= 3 = 112, 360(1.06) 119, 101.60 t= 4 = 119, 101.60(1.06)

    126, 247.70

    t= 5 = 26, 247.70(1.06) 133, 822.56

    y= 100, 000(1.06)t

    P r

    t A= P(1 + r)t

    y= 100000(1.06)t t t

    t = 8 y = 100, 000(1.06)8 159, 384.81 t = 10 y = 100, 000(1.06)10 179, 084.77 200, 000

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    e2.71828 e e

    e

    f(x) =ex

    T t

    T= 170165e0.006t t

    t

    T

    50, 000

    A= 50, 000(1.044)t t

    t= 18 A= 50, 000(1.044)18 108, 537.29 100, 000

    A = 20, 000(1.05)t t

    t = 10, A = 20, 000(1.05)10 32, 577.89 32, 577.89

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    y = 10012

    x/250 x = 0

    x= 500 y= 10012

    500/250= 100

    12

    2= 25

    y = 1, 000(3)x/80 x = 0

    x= 100 y= 1, 000(3)100/80 = 3, 948.22 3, 948

    10, 000

    A = 10, 000(1.02)t t

    A= 10, 000(1.02)12 = 12, 682.42

    12, 682.42

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    4x1

    = 16x

    y= 2x

    2x

    26

    a bx

    c

    +d

    b > 0

    b = 1

    f(x) =bx b >0

    b = 1

    72xx2

    = 1

    343

    52x

    5x+1

    0

    f(x) = ( 1.8)x y =

    (1.8)x

    x

    x y

    f(x) = 2x3

    f(x) = 2x

    y= ex

    22(5x+1) = 500

    625 5x+8

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    a = 0

    a0 = 1

    an = 1

    an

    r s

    aras =ar+s

    ar

    as =ars

    (ar)s =ars

    (ab)

    r

    =a

    r

    b

    r

    ab

    r=

    ar

    br

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    49 = 7x+1

    7 = 2x + 3

    3x = 32x1

    5x1 = 125

    8x= x2 9 x2 = 3x3 + 2x 1 2x + 3> x 1 2x2 >8

    x1=x2 bx1 =bx2 bx1 =bx2 x1= x2

    4x1 = 16

    4x1 = 16

    4x1 = 42

    x 1 = 2x= 2 + 1

    x= 3

    4x1 = 16

    (22)x1 = 24

    22(x

    1)

    = 24

    2(x 1) = 42x 2 = 4

    2x= 6

    x= 3

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    x= 3 431 = 42 =

    16

    125x1 = 25x+3

    125x1 = 25x+3

    (53)x1 = (52)x+3

    53(x1) = 52(x+3)

    3(x 1) = 2(x + 3)3x 3 = 2x + 6

    x= 9

    9x2

    = 3x+3

    (32)x2

    = 3x+3

    32x2

    = 3x+3

    2x2 =x + 3

    2x2 x 3 = 0(2x 3)(x + 1) = 0

    2x

    3 = 0 x + 1 = 0

    x=3

    2 x= 1

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    b > 1 y = bx x

    bx < by x < y

    0 < b < 1 y = bx x

    bx > by x < y

    bm < bn

    m < n m > n b

    3x

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    110 (0.36)x1

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    (0.6)x3 >(0.36)x1

    (0.6)x3 >(0.62)x1

    (0.6)x3

    >(0.6)2(x1)

    (0.6)x3 >(0.6)2x2

    x 3> 2x 23x >1

    x >1

    3

    (0.6)x3 >(0.36)x1

    (0.6)x3 >(0.62)x1

    (0.6)x3

    >(0.6)2(x1)

    (0.6)x3 >(0.6)2x2

    x 3< 2x 23x (0.6)2x2 x

    3 >

    2x

    2

    x > 13

    x

    162x3 = 4x+2 x= 83

    1

    2

    2x= 23x

    1

    2 21 x= 3

    42x+7 322x3

    29

    6 , +

    255x1 254 254 25

    2

    (, 15 ]

    x

    7x+4 = 492x1 x= 2

    4x+2 = 82x x= 1

    2

    35x+2

    = 3

    22x

    2

    7, +

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    f(x) =bx b >1

    f(x) =bx 0< b

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    f(x) = 2x f(x) = 2x

    x

    y x

    y= 0

    g(x) =

    1

    2

    x

    g(x)

    x 3 2 1

    f(x) 1

    2

    1

    4

    1

    8

    1

    16

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    g(x) =1

    2x

    g(x) =1

    2x

    x

    x y= 0

    b > 1 0 < b < 1 f(x) = bx

    b > 1 0< b < 1

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    f(x) =bx b > 0 b = 1 R

    (0, +)

    y x

    y= 0 x

    f(x) = 2x g(x) = 3x

    x 4 3 2 1 f(x)

    g(x)

    x 4 y 1 f(x) g(x)

    y

    f(x) =

    1

    2

    x g(x) =

    1

    3

    x

    x 4 3 2 1 f(x)

    g(x)

    x 4 y 1 f(x) g(x)

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    y

    f(x) = 5x y

    5x = 1

    5x = 1

    5x

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    x 3

    x

    4 y

    1 y= 2x

    y= 2x

    y= 2x y= 3 2x y= 25 2x

    y= 2x + 1

    y= 2x 1 y= 2x+1

    y= 2x1

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    x 3 2 1 y= 2x

    y= 2

    x

    y= 2x 0.125 .25 .5 1 2 4 8 y 1

    y= 3 2x y

    y= 25 2x y

    2/5

    y= 2x + 1

    y= 2x 1 0.875 0.75 0.5

    y= 2x+1

    y= 2x1

    y= 2x y= 2x y= 2x

    y

    x 3 2 1 y= 2x

    y= 2x 0.125 0.25 0.5 1 2 4 8y= 2x

    y y =2x y y= 2x y= 2x y= 2x x

    y = 2x x y = 2x x y = 2x y= 2x y

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    y= f(x) x y= f(x)

    y= f(x) y y= f(x)

    y= 2x y= 3(2x) y= 0.4(2x)

    y

    x 3 2 1 y= 2x

    y= 3(2x

    )

    y= 0.4(2x)

    y y= 3(2x) y

    y= 2x y y= 0.4(2x)

    y y= 2x

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    R

    y y y= 3(2x)

    y y= 0.4(2x)

    y= 0

    (0, +

    )

    a >0 y= af(x) y

    y= f(x) a

    a >1 0< a

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    R

    y= 2x + 1 (1, +) y= 2x 3 (3, +)

    y

    y

    y= 2x

    y= 2x y= 0

    y = 2x + 1 y = 1 y = 2x 3 y= 3

    d y = f(x) + d d

    d >0 d d

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    x 3 2 1 y= 2x

    y= 2x2

    y= 2x+4

    R

    (0, +) y x= 0 y

    y= 2x+4 24 = 16 y y= 2x2 22 = 0.25

    y= 0

    c y = f(x c) c c > 0 c c < 0

    y= f(x)

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    f(x) =a bxc + d

    b b >1 0< b 0 d d 0 c c

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    x

    24 =x 43 =x 51 =x 16

    12 =x

    1

    5

    1

    4

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    5x = 625

    3x =1

    9

    7x = 0

    10x = 100, 000

    x

    x b logb x b

    x log381 = 4 34 = 81

    log232 = 5 25 = 32

    log51 = 0 50 = 1

    log61

    6

    = (1) 61

    =

    1

    6

    log232

    log9729

    log55

    log 12

    16

    log71

    log51

    5

    4

    15

    1/2

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    a b b = 1 a b logb a b

    logba =a logb a

    b a

    log232 = 5 25 = 32

    log9729 = 3 93 = 729

    log55 = 1 51 = 5

    log1/216 = 412

    4= 16

    log71 = 0 70 = 1

    log515

    = 12 51/2 = 15

    logb a= c

    bc =a

    b c c = logb a

    logb a a log2(8)

    logb x log51

    125= 3 53 = 1

    125

    log x log10 x

    e

    e

    ln ln x loge x

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    53 = 125

    72 = 1

    49 102 = 100

    2

    32

    =4

    9

    (0.1)4 = 10, 000

    40 = 1

    7b = 21

    e2 =x

    (

    2)2 = 4

    log5125 = 3

    log71

    49= 2

    log 100 = 2

    log 23

    4

    9

    = 2

    log0.110, 000 = 4 log41 = 0

    log721 =b

    b= 3 73 = 21 b 71.5645

    ln x= 2

    log m= n

    log381 = 4

    log55 = 2

    log 34

    64

    27= 3

    log42 =1

    2 log100.001 = 3

    ln 8 =a

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    10n =m

    34 = 81

    (5)2 = 5

    3

    4

    3=

    64

    27

    41/2 = 2

    103 = 0.001 103 = 1

    1, 000 ea = 8

    1031

    log 1031 = 31

    R=2

    3log

    E

    104.40

    E 104.40

    1012

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    E= 1012 R=2

    3log

    1012

    104.40 =

    2

    3log 107.6

    log107.6 = 7.6

    107.6 log 107.6 = 7.6

    R=2

    3 (7.6) 5.1

    1012/104.40 = 107.6 39810717

    http://www.phivolcs.dost.gov.ph/index.php?option=com_content&task=view&id=45&Itemid=100
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    D= 10log I

    1012

    I 2 1012 2

    106

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    60

    85

    90 100

    106 m2

    D = log 106

    1012 = 10log106 log 106

    106 log106 = 6

    D= 10(6) = 60

    106

    1012 = 106 = 100, 000

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    [H+]

    pH= log[H+]

    pH= log 1

    [H+]

    105

    log 105 log105

    105 log 105 = 5 log 105 = (5) = 5

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    log3243 5

    log6

    1

    216

    3

    log0.2516

    2

    49x = 7 log497 =x

    63 = 1

    216 log6216 = 3

    102 = 100 log 100 = 2

    log 112

    4

    121= 2 11

    2 2

    = 4

    121

    ln 3 =y ey = 3

    log0.001 = 3 103 = 0.001

    http://www.sciencebuddies.org/science-fair-%20projects/project_ideas/Chem_AcidsBasespHScale.shtml
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    log3(x 2) = 5 ln x 9 y= log 12

    x

    logx2 = 4 ln x2 >(ln x)2 g(x) = log3 x

    x

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    x y

    logx2 = 4

    log2 x= 4 log24 =x

    logx2 = 4 x

    log2 x= 4 4

    log24 =x

    x

    log2 x= 4

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    f(x) = 3x

    x f(x)

    4

    1

    g(x) = log3 x

    x

    x g(x)181

    13

    log2 x= 4 logx16 = 2 log 1000 = x

    log2 x= 4

    24 =x

    x= 16

    logx16 = 2

    x2

    = 16x2 16 = 0(x + 4)(x 4) = 0x= 4, +4 x= 4

    log 1000 = x

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    log 1000

    3 = xx= 3

    log381

    34 = 81

    log41 log33 log442

    log43 = 0 40 = 1

    log33 = 1 31 = 3

    log442 = 2 42 = 42

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    b x b > 0 b = 1

    logb1 = 0

    logb bx =x

    x >0 blogbx =x

    logb1 b b? = 1

    logb bx

    b bx

    x

    logb x b x b

    x

    log214

    23 = 8 24 = 16

    23.8074 14.000

    2log214 = 14

    logb1 = 0 logb bx = x blogbx = x

    log10

    ln e3

    log464

    log5

    1

    125

    5log52

    log1

    log 10 = log10101 = 1

    ln e3 = loge e3 = 3

    log464 = log443 = 3

    log5

    1

    125

    = log55

    3 = 3

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    5log52=2

    log1 = 0

    102 m2

    D= 10log

    I

    I0

    D= 10log

    102

    1012

    D= 10log1010

    D= 10 10 D= 100

    pH= log[H+]3.0 = log[H+]3.0 = log[H+]103.0 = 10logH

    +

    103.0 = [H+]

    103.0

    log749

    log273 1

    3

    ln e

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    log7

    73 78 log773 + log778 log7

    49

    7

    log749 log77

    log775

    5 log77

    log2

    24210

    log22

    4 log2210 6

    log3(27 81) log327 + log381

    b > 0, b = 1 n R u >0, v >0

    logb(uv) = logb u + logb v

    logb

    uv

    = logb u logb v

    logb(un) =n logb u

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    logb(uv) = logb u + logb v log7

    73 78= log773 + log778logb

    uv

    = logb u logb v

    log7

    49

    7

    = log749 log77

    log2

    24

    210

    = log22

    4 log2210

    logb(un) =n logb u

    log775 = 5 log77

    log3(27 81) = log327 + log381

    r= logb u s= logb v u= br

    v= bs

    logb(uv) = logb(brbs)

    logb(uv) = logb br+s

    logb(uv) =r + s logb(uv) = logb u= logb v

    r= logb u u= br

    un =brn

    un =brn

    logb(un) = logb(brn) logb(un) =rn

    logb(u

    n) =n logb u

    logb un

    (logb u)n

    n

    u n logb u

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    log2(5 + 2) = log25 + log22 log2(5 + 2) = (log25)(log22) log2(5

    2)

    = log25

    log22

    log2(5 2) =log25log22 log2(5

    2 2) = 2log2(5 2)

    log(ab2)

    log3

    3

    x

    3 ln[x(x 5)]

    log(ab2) = log a + log b2 = log a + 2 log b

    log3

    3

    x

    3= 3log3

    3

    x

    = 3(log33 log3 x) = 3(1 log3 x) = 3 3log3 x

    ln[x(x 5)] = ln x + ln(x 5)

    log 2 + log 3 2 ln x ln y

    log5(x2

    ) 3log5 x 2 log5

    log 2 + log 3 = log(2 3) = log 6 2 ln x ln y= ln(x2) ln y= ln

    x2

    y

    log5(x2) 3log5 x= log5(x2) log5(x3) = log5

    x2

    x3

    = log5

    1

    x

    = log5(x

    1) = log5 x 2 log5

    2 = 2(1)

    = 2(log 10) 1 = logb b

    = log 102 n logb u= logb un

    = log 100

    2 log 5 = log 100 = log

    100

    5

    = log 20

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    log3729 6

    log9729 3

    log27729 2

    log1/27729 2 log729729 1

    log81729 3/2

    log81729

    811/4 = 3 36 = 729 (811/4)6 = 729

    816/4

    = 813/2

    = 729

    log81729 = 32

    log3n729 = 6n

    a b x a = 1, b = 1logb x=

    loga x

    loga b

    log3n729 = 6

    n

    log3n729 =log3729

    log33n

    = 6

    n.

    log832

    log2431

    27

    log251

    5

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    log832 =log232

    log28 =

    5

    3

    log2431

    27=

    log31

    27log3243

    =3

    5

    log251

    5=

    log5 15

    log525 =

    1/22

    = 14

    log64

    log 12

    2 e

    log64 = log24

    log26=

    2

    log26

    log 12

    2 = ln 2

    ln

    1

    2

    = ln 2ln 1 ln 2=

    ln 2

    0 ln 2= ln 2

    ln 2= 1

    log

    x3

    2

    3log x log2

    ln(2e)2 (2e)2 = 4e3 2 ln 2 + 2

    log4(16a) 2 + log4 a

    log(x + 2) + log(x 2) log(x2 4) 2log35 + 1 log375

    2 ln

    3

    2

    ln 4 ln

    9

    16

    (log32)(log34) = log38

    (log32)(log34) = log36

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    log22 = (log 2)2

    log4(x 4) =log4 x

    log44

    3log9 x2 = 6log9 x

    3(log9 x)2

    = 6log9 x

    log32x2 = log32 + 2 log3 x

    log32x2 = 2log32x

    log52 0.431 log58, log5

    1

    16

    , log5

    2, log252 log258

    1.2920,

    1.7227, 0.2153, 0.2153, 0.6460

    log6 0.778 log4 0.602 log64, log 24, log46, log

    2

    3

    log

    3

    2

    0.7737, 1.3802, 1.2925, 0.1761, 0.1761

    b x logb x

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    b x logb x

    f(x) = logb x logb u= logb v u= v

    ab= 0 a= 0 b= 0

    x

    log4(2x) = log410

    log3(2x 1) = 2 logx16 = 2

    log2(x + 1) + log2(x 1) = 3 log x2 = 2

    (log x)2 + 2 log x 3 = 0

    log4(2x) = log410

    2x= 10

    x= 5

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    log4(2 5) = log4(10)

    log3(2x 1) = 22x 1 = 32 2x 1 = 92x= 10

    x= 5

    log3(2 (5)1) = log3(9) = 2

    logx16 = 2

    x2 = 16

    x2

    16 = 0(x + 4)(x 4) = 0 a2 b2 = (a + b)(a b)x= 4, 4

    log4(16) = 2 4 log4(16)

    log2(x + 1) + log2(x 1) = 3log2[(x + 1)(x 1)] = 3 logb u + logb v = logb(uv)(x + 1)(x

    1) = 23

    x2 1 = 8 x2 9 = 0(x + 3)(x 3) = 0 a2 b2 = (a + b)(a b)x= 3, 3

    log2(3 + 1) log2(31

    3 log2(3 + 1) = log2(2)

    x= 3

    log x2 = 2

    log x2 = 2

    x2 = 102

    x2 = 100

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    x2 100 = 0(x + 10)(x 10) = 0x= 10, 10 log(10)2 = 2 log(10)2 = 2

    log x2 = 2

    log x2 = log 102 2 = 2(1) = 2(log 10) = log 102

    x2 = 102

    x2 100 = 0(x + 10)(x 10) = 0x= 10, 10 log(10)2 = 2 log(10)2 = 2

    logb un =n logb u

    log x2 = 2

    2log x= 2

    log x= 1

    x= 10

    log x2 = 2log x x >0

    (log x)2 + 2 log x 3 = 0

    log x= A

    A2 + 2A 3 = 0(A + 3)(A 1) = 0A= 3 A= 1

    log x= 3 log x= 1x= 103 =

    1

    1000 x= 10

    log

    1

    1000

    log 10

    x 2x = 3

    2x = 3

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    log2x = log 3

    x log 2 = log 3 logb un =n logb u

    x= log3

    log2 1.58496

    x log 12

    x

    18

    14

    12

    x log2 x

    18

    14

    12

    x log 12

    x

    18

    14

    12

    1 2 3

    x log2