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a. Prepare a graph showing P vs x1 and P vs y1 for T = 348.15 K (75 C)A B C
Acetonitrile (1) 14.2724 2945.47 -49.15Nitrometana (2) 14.2043 2972.64 -64.15
T= 348.15
4.42132977 83.2068575
3.73725775 41.9827049
x1 P Y183.2068575 41.9827049 0 41.9827049 083.2068575 41.9827049 0.1 46.1051202 0.1804720583.2068575 41.9827049 0.2 50.2275354 0.3313196983.2068575 41.9827049 0.3 54.3499507 0.459283983.2068575 41.9827049 0.4 58.472366 0.5692046683.2068575 41.9827049 0.5 62.5947812 0.6646469283.2068575 41.9827049 0.6 66.7171965 0.7482945583.2068575 41.9827049 0.7 70.8396117 0.8222066683.2068575 41.9827049 0.8 74.962027 0.88798941
ln P1 sat P1
sat
ln P2 sat P2 sat
P1 sat P2
sat
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83.2068575 41.9827049 0.9 79.0844422 0.9469140883.2068575 41.9827049 1 83.2068575 1
P(kPa)0.6 450.6 59.740550.6 66.715220.6 80
SAAT TEKANAN KONSTAN 1 DAN Y = 0,659.74055 0.659.74055 0.43404425
SAAT TEKANAN KONSTAN 2 DAN X = 0,666.71522 0.666.71522 0.74829455
SAAT KOMPOSISI KONSTAN
X1=Y1
0 0.2 0.4 0.6 0.8 10
20
40
60
80
100
66.7152266.7152259.7405559.74055
45
80f(x) = 27.5642727987x^2 + 12.3648648575x + 42.5343636333R = 0.9988273488
f(x) = 41.224152519x + 41.9827049461R = 1
BUBBLE LINE Linear (BUBBLE LINE)DEW LINE Polynomial (DEW LINE)CONSTANT COMPOSITION COSTANT PRESSURE 1CONSTANT PRESSURE 2
X1,Y1
P(kPa)
Subcooled Liquid
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a. Prepare a graph showing P vs x1 and P vs y1 for T = 348.15 K (75 C)
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Keterangan :
y = 41.224x + 41.983dimana x= fraksi (X1 atau y1)
y= tekanan (P)jika, 0.6maka, P= 66.7174sehingga, 0.7482945497
jika, 0.6maka, P= 59.87604sehingga, 0.43404425
menggunakan persamaan bubble line:
X1=
Y1=
menggunakan persamaan dew line: y = 27.564x2 + 12.365x + 42.534
Y1=
X1=
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b. Prepare graph showing t vs x1 dan t vs y1 for P=70kPaA B C
Acetonitrile (1) 14.2724 2945.47 -49.15Nitrometana (2) 14.2043 2972.64 -64.15
untuk P= 70 kPa ln 4.248495342.9946362.7336
T(K)362.7336 4.8795 131.5604 4.2485 70.0000 0.0000 0.0000
359.15 4.7709 118.0235 4.1276 62.0260 0.1424 0.2401355.15 4.6467 104.2384 3.9890 54.0031 0.3184 0.4742351.15 4.5192 91.7611 3.8467 46.8368 0.5156 0.6759347.15 4.3883 80.5012 3.7003 40.4583 0.7378 0.8484343.15 4.2538 70.3719 3.5497 34.8021 0.9895 0.9948
342.9946 4.2485 70.0001 3.5437 34.5960 1.0000 1.0000
SAAT KOMPOSISI KONSTAN SAAT TEKANAN KONSTAN 1 DAN Y = 0,6X1=Y1 T(K) 352.728 0.6
0.6 362.7336 352.728 0.43510.6 359.150.6 347.15 SAAT TEKANAN KONSTAN 2 DAN X = 0,60.6 343.15 349.572 0.6
T1 sat =T2 sat=
lnP1 P1sat lnP2 P2sat X1 Y1
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0.6 342.9946 349.572 0.7473
dengan persamaan :
dimana
P1sat dan P2sat ditentukan dengan Antoine Equation
Iterasia' P2sat lnP2sat T (K) ln a a a'-a
1.971 44.229 3.789 349.5714 0.678555 1.971027 0.000
dimana
metode iterasi sama dengan di atas, tetapi menggunakan rumus T sebagai berikut
a P1sat lnP1sat T (K) ln a a a'-a1.948 96.534 4.570 352.728 0.66657751 1.948 0.000
Untuk T konstan pada x1 = 0,6 dan P = 70 kPa dievaluasi dari bubble line menggunakan metode iterasi.
Untuk T konstan pada y1 = 0,6 dan P = 70 kPa dievaluasi dari dew line menggunakan metode iterasi.
0 0.2 0.4 0.6 0.8 1 1.2330335340345350355360365
349.572349.572
352.728352.728
362.7336
343.15
f(x) = - 7.4256658694x^2 - 12.1465566483x + 362.6441485907R = 0.9997755086f(x) = 5.6348573683x^2 - 25.304189808x + 362.6850213964R = 0.9999664776
DEW LINE Polynomial (DEW LINE)BUBBLE LINE Polynomial (BUBBLE LINE)CONSTANT COMPOTITION CONSTANT TEMPERATURE 1CONSTANT TEMPERATURE 2
X1Y1
T(K)
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0 0.2 0.4 0.6 0.8 1 1.2330335340345350355360365
349.572349.572
352.728352.728
362.7336
343.15
f(x) = - 7.4256658694x^2 - 12.1465566483x + 362.6441485907R = 0.9997755086f(x) = 5.6348573683x^2 - 25.304189808x + 362.6850213964R = 0.9999664776
DEW LINE Polynomial (DEW LINE)BUBBLE LINE Polynomial (BUBBLE LINE)CONSTANT COMPOTITION CONSTANT TEMPERATURE 1CONSTANT TEMPERATURE 2
X1Y1
T(K)
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SAAT TEKANAN KONSTAN 1 DAN Y = 0,6
SAAT TEKANAN KONSTAN 2 DAN X = 0,6
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jika:P= 70
X1= 0.6X2= 0.4
Jika :
87.18056
Y1= 0.747262
P= 70Y1= 0.6Y2= 0.4
X1= 0.435081
menggunakan metode iterasi.
P1 sat=
menggunakan metode iterasi.
1= a 2
1=(1 1 )/
1 = (1 )/1
0 0.2 0.4 0.6 0.8 1 1.2330335340345350355360365
349.572349.572
352.728352.728
362.7336
343.15
f(x) = - 7.4256658694x^2 - 12.1465566483x + 362.6441485907R = 0.9997755086f(x) = 5.6348573683x^2 - 25.304189808x + 362.6850213964R = 0.9999664776
DEW LINE Polynomial (DEW LINE)BUBBLE LINE Polynomial (BUBBLE LINE)CONSTANT COMPOTITION CONSTANT TEMPERATURE 1CONSTANT TEMPERATURE 2
X1Y1
T(K)
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menggunakan persamaan bubble line:
dimana x= fraksi (X1 atau y1)y=suhu(T)
jika, 0.6maka, T= 352.678548sehingga, 0.74829455
menggunakan persamaan dew line:
jika, 0.6maka, T= 59.87604sehingga, 0.43404425
y= -7.4257x2 - 12.147x + 362.64
X1=
Y1=
y = 27.564x2 + 12.365x + 42.534Y1=
X1=0 0.2 0.4 0.6 0.8 1 1.2
330335340345350355360365
349.572349.572
352.728352.728
362.7336
343.15
f(x) = - 7.4256658694x^2 - 12.1465566483x + 362.6441485907R = 0.9997755086f(x) = 5.6348573683x^2 - 25.304189808x + 362.6850213964R = 0.9999664776
DEW LINE Polynomial (DEW LINE)BUBBLE LINE Polynomial (BUBBLE LINE)CONSTANT COMPOTITION CONSTANT TEMPERATURE 1CONSTANT TEMPERATURE 2
X1Y1
T(K)
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species 1 Henry's Law x = fraksi liquid
species 2 water Raoult's Law y = fraksi vapour
sehingga,
diasumsikan bahwa fraksi CO2 dalam air adalah 0.010.010.99990 bar
0.01227 bar (steam table)
Antoine Equation T(K) = 283.15CO2 H2O P(bar)
A 6.81228 16.262 P(kPa)B 1301.679 3799.89C -3.494 -46.8
x1 x2= 2.1577079543 0.01 0.99= 8.6512857745 kPa= 0.0865128577 bar maka fraksi vapor CO2 hampir murni yaitu 0.9988= 0.1846147662= 1.202755009 kPa= 0.0120275501 bar
P1 0 0 990 1.000 0.000
0.6 0.4 0.4 594.00481 0.600 0.400
CO2
x1y1H1P2sat
H1H1
ln P 1satP 1sat
ln P 2sat
x1 y1 x2 x1 x2
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0.5 0.5 0.5 495.00601 0.500 0.5000.4 0.6 0.6 396.00722 0.400 0.6000.3 0.7 0.7 297.00842 0.300 0.7000.2 0.8 0.8 198.00962 0.200 0.8000.1 0.9 0.9 99.010825 0.100 0.9000 1 1 0.0120276 0.000 1.000
0 0.2 0.4 0.6 0.8 1 1.20
200400600800
10001200
f(x) = 0.0120241122 exp( 10.2851802063 x )R = 0.9641783691
f(x) = 989.9879724499x + 0.0120275501R = 1
Chart Title
bubble lineLinear (bubble line)dew lineExponential (dew line)
Axis Title
Axis Title
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99099000
P y1 x1 y2 y19.9121473 1 0.01 0.0012 0.9988
maka fraksi vapor CO2 hampir murni yaitu 0.9988
0.000 1.0000.000 1.000
y2 y1
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0.000 1.0000.000 1.0000.000 1.0000.000 1.0000.000 1.0001.000 0.000
0 0.2 0.4 0.6 0.8 1 1.20
200400600800
10001200
f(x) = 0.0120241122 exp( 10.2851802063 x )R = 0.9641783691
f(x) = 989.9879724499x + 0.0120275501R = 1
Chart Title
bubble lineLinear (bubble line)dew lineExponential (dew line)
Axis Title
Axis Title
0 0.2 0.4 0.6 0.8 1 1.20
200400600800
10001200
f(x) = 352.2492122925 exp( -10.2851802063 x )R = 0.9641783691
f(x) = - 989.9879724499x + 990R = 1
Chart Title
bubble lineLinear (bubble line)dew lineExponential (dew line)
Axis Title
Axis Title
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0 0.2 0.4 0.6 0.8 1 1.20
200400600800
10001200
f(x) = 352.2492122925 exp( -10.2851802063 x )R = 0.9641783691
f(x) = - 989.9879724499x + 990R = 1
Chart Title
bubble lineLinear (bubble line)dew lineExponential (dew line)
Axis Title
Axis Title
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10.1a10.1b10.210.3a