the mole

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THE MOLE

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The Mole. Too small to see. Because atoms are so small , it makes more sense to measure large amounts of atoms in reactions . One mole of a substance contains the same number of particles as atoms in 12 grams of Carbon-12. The Avagadro Constant. - PowerPoint PPT Presentation

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Page 1: The  Mole

THE MOLE

Page 2: The  Mole

TOO SMALL TO SEE

• Because atoms are so small, it makes more sense to measure large amounts of atoms in reactions.• One mole of a substance contains the same

number of particles as atoms in 12 grams of Carbon-12

Page 3: The  Mole

THE AVAGADRO CONSTANT

• 1 mole of a substance contains 6.022 x 1023 particles• Thats 602 200 000 000 000 000 000 000

particles!!!

Page 4: The  Mole

EQUATION

• To calculate the moles in a substance we use the following equation:

• Moles of Atoms = Mass/Relative Atomic Mass

Page 5: The  Mole

R.A.M.

• Relative Atomic Mass is the Ar value from the Periodic Table

Page 6: The  Mole

QUESTION

• How many moles of atoms are there in 2.4 g of carbon?

Page 7: The  Mole

ANSWER

• Moles of atoms = mass/R.A.M.• = 2.4/12 = 0.2 moles

Page 8: The  Mole

THE MAGIC TRIANGLE

• Using the magic triangle we can rearrange the equation to find mass instead of moles

Page 9: The  Mole

QUESTION

• What is the mass of 0.1 moles of Carbon Atoms?

Page 10: The  Mole

FOR A COMPOUND

• A compound has more than one type of atom, so we have to find the Relative Formula Mass (R.F.M.)• We do this by adding the Ar of the elements in the

molecule.• So the equation then becomes:• Moles = Mass/R.F.M.

Page 11: The  Mole

QUESTION

• How many moles are there in 8 g of copper(II) oxide (formula CuO)?• 1. Find the RFM

Cu = 64O = 16So the RFM of CuO is 80….then just follow the equation…

Page 12: The  Mole

QUESTIONS

• How many moles of atoms are there in:1. 2 g of hydrogen2. 36 g of carbon3. 160 g of oxygen4. 14 g of nitrogen5. 0.19 g of flourine

Page 13: The  Mole

QUESTIONS

• How many moles of molecules are there in:1. 26 g of H2O

2. 170 g of NH3

3. 1.6 g of CH4

4. O.2 g of C2H6

5. 16 g of NH4NO3