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The Solubility Product Principle Chapter 20

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Page 1: The Solubility Product Principle Chapter 20. Solubility: the amount of compound that dissolves in a specified volume. Usually expressed as grams per Liter

The Solubility Product Principle

Chapter 20

Page 2: The Solubility Product Principle Chapter 20. Solubility: the amount of compound that dissolves in a specified volume. Usually expressed as grams per Liter

Solubility: the amount of compound that dissolves in a specified volume. Usually expressed as grams per Liter or grams per 100 mL

Molar solubility: number of moles of a compound that dissolve to give 1 Liter of saturated solution.

Page 3: The Solubility Product Principle Chapter 20. Solubility: the amount of compound that dissolves in a specified volume. Usually expressed as grams per Liter

Solubility Product Expression: for a compound it is the product of the concentrations of its ions each raised to a power that corresponds to the number of ions formed.

Common ion effect: the solubility of a compound is less in a solution that contains an ion common to the compound than it is in pure water.

Page 4: The Solubility Product Principle Chapter 20. Solubility: the amount of compound that dissolves in a specified volume. Usually expressed as grams per Liter

Ex. 1) a. What is the solubility product expression for the dissociation of calcium carbonate?

(Ksp = solubility product constant.)

Page 5: The Solubility Product Principle Chapter 20. Solubility: the amount of compound that dissolves in a specified volume. Usually expressed as grams per Liter

b. For aluminum fluoride?

Page 6: The Solubility Product Principle Chapter 20. Solubility: the amount of compound that dissolves in a specified volume. Usually expressed as grams per Liter

c. For barium nitride?

Page 7: The Solubility Product Principle Chapter 20. Solubility: the amount of compound that dissolves in a specified volume. Usually expressed as grams per Liter

Ex. 2) Calculate the molar solubility, concentrations of the constituent ions, and solubility in grams per liter of copper(II) hydroxide. Ksp = 1.6 x 10-19

Page 8: The Solubility Product Principle Chapter 20. Solubility: the amount of compound that dissolves in a specified volume. Usually expressed as grams per Liter

Ex. 3) Find [S2-] in saturated iron(III) sulfide Ksp = 1.40x10-88

Page 9: The Solubility Product Principle Chapter 20. Solubility: the amount of compound that dissolves in a specified volume. Usually expressed as grams per Liter

Ex. 4) 0.750 M FeI3 is added to Ex. 3. What is the final concentration of iron and sulfur ions?

Page 10: The Solubility Product Principle Chapter 20. Solubility: the amount of compound that dissolves in a specified volume. Usually expressed as grams per Liter

Ex. 5) Calculate the molar solubility and ion concentrations of aluminum fluoride in pure water and its solubility in grams per 100 mL. Ksp = 6.4 x 10-19. Then using the common ion effect, find the molar solubility of AlF3 in 0.20 M potassium fluoride solution along with the ion concentrations and compare the molar solubilities.

Page 11: The Solubility Product Principle Chapter 20. Solubility: the amount of compound that dissolves in a specified volume. Usually expressed as grams per Liter

Ex. 6) What is the solubility product constant if 0.477 g of silver dichromate is in a one liter solution?

Page 12: The Solubility Product Principle Chapter 20. Solubility: the amount of compound that dissolves in a specified volume. Usually expressed as grams per Liter

Fractional precipitation: a separation process that removes some ions from solution while leaving other ions with similar properties in the solution.

Page 13: The Solubility Product Principle Chapter 20. Solubility: the amount of compound that dissolves in a specified volume. Usually expressed as grams per Liter

Ex. 7) Solid silver nitrate is slowly added to a solution that is 0.010 M each in sodium bromide and sodium iodide. Calculate the [Ag+ ] required to initiate the precipitation of each silver halide. Which precipitates first? For AgBr: Ksp = 3.3 x 10-13 for AgI: Ksp = 1.5 x 10-16

For AgCl the Ksp = 1.8 x 10-10. Compare that to AgBr and AgI to determine which would precipitate last.

Page 14: The Solubility Product Principle Chapter 20. Solubility: the amount of compound that dissolves in a specified volume. Usually expressed as grams per Liter

Ex. 8) Using your answer from #7, find the percentage of Iodine ions that precipitated before silver bromide precipitates.

Page 15: The Solubility Product Principle Chapter 20. Solubility: the amount of compound that dissolves in a specified volume. Usually expressed as grams per Liter

Ex. 9) How many moles of bismuth(III) hydroxide will dissolve in 1.00 L of a solution with a pH=4.77 Ksp = 3.2x10-40

Page 16: The Solubility Product Principle Chapter 20. Solubility: the amount of compound that dissolves in a specified volume. Usually expressed as grams per Liter

Reaction Quotient in Precipitation Reactions If Qsp < Ksp Forward process is favored

◦No precipitation occurs; if solid is present, more solid can dissolve

If Qsp = Ksp Solution is just saturated◦Solid and solution are in equilibrium; neither

forward nor reverse process is favored.

If Qsp > Ksp Reverse process is favored◦Precipitation occurs to form more solid

Page 17: The Solubility Product Principle Chapter 20. Solubility: the amount of compound that dissolves in a specified volume. Usually expressed as grams per Liter

Extra Credit Opportunity Many industries require extremely large

amounts of water as a coolant in heat exchange processes. Muddy or cloudy water usually doesn’t work b/c the solids may clog filters or deposit sediment in the pipes and pumps. Murky water can be clarified by adding agents that form colloids which settle out in holding tanks or ponds before the clarified water is moved to the plant intakes. If 56 g of Ca(OH)2 and 75 g of MgSO4 were added to 520 liters of water, would any of the compounds form precipitates?

Page 18: The Solubility Product Principle Chapter 20. Solubility: the amount of compound that dissolves in a specified volume. Usually expressed as grams per Liter

Ksp Ca(OH)2 = 7.9 x 10-6

Ksp MgSO4 = 4.8 x 10-5

Ksp CaSO4 = 2.4 x 10-5

Ksp Mg(OH)2 = 1.5 x 10-11