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Designing Systems to Compensate for Thermal Expansion and Contraction

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  • Designing Systems

    toCompensate

    forThermal

    Expansionand

    Contraction

  • Things We Have Learned From Being Sued

  • 6 Model MC - 6 CorrugationsAnchor Load @ 150psi - 11,600#

  • This is why you should use guides

  • RiserF3Floor425Room24

  • Use Any Natural Flexibility In The piping layout

  • 2008 ASHRAE Handbook

    Heating, Ventilating, and Air Conditioning Systems and Equipment

    Chapter 45

  • Or this can be simplified to

    L = 6.225 D

    L = 3DE(144in/ft)SA

    Where = Thermal expansion of leg ABD = Pipe Outside DiameterE = Modulus of ElasticitySA = Allowable Stress

    For a Basic Expansion ElbowHard Pipe

    L

    Anchor

    Anchor

    A

    B

    C

  • L = 4 D Where = Thermal expansion of leg ABD = Pipe Outside DiameterE = Modulus of ElasticitySA = Allowable Stress

    For a Basic Expansion Z Bend Hard Pipe

    X

    X

    Guide

    Guide

    AnchorAnchor

    L

    L

    L

    A

    B

    Anchor to Anchor Expansion

  • So what kind of expansion joint to use?

  • L = 6.225 D

    W = L/5H = 2*W

    Where = Thermal expansion of runD = Pipe Outside DiameterE = Modulus of ElasticitySA = Allowable Stress

    For a Basic Expansion Loop Hard Pipe

    XX

    AnchorAnchor

    Guide

    Guide

    Anchor to Anchor Expansion

    2H 2H

    W

    H

  • Hard Loops Pro/Con

    Same material as the rest of piping

    Constructed on site, costly to fabricate, hang and insulate

    Grandfather used em

    Medium anchor loads

    Constructed on site

    Pro

    Needs lots of room

    High lateral loads on moment guides.

    Con

  • Flexible Expansion Loop

  • V Loops

  • The flexible pipe loop is also smaller and has less anchor load than a hard pipe loop

  • Hose Basics

  • Corrugated stainless steel hose by itself

    has great hoop strength, but poor tensile

    strength

  • Virtually any amount of movement

  • Cap weld,

    welding the

    hose, braid and

    collar together

  • Weld the End Fitting to the Hose

  • On a flex loop the braid is the anchor

  • XX

    1

    6

    5

    F

    e

    e

    t

    2

    .

    8

    5

    E

    x

    p

    .

    50 Feet

    .59 Exp.

    1

    9

    F

    e

    e

    t

    19 Feet

    Guides

    4 Sch 40 Carbon Steel With Hard Pipe Expansion 90

    Anchor with 582 pounds force

    X

    X

    1

    6

    5

    F

    e

    e

    t

    2

    .

    8

    5

    E

    x

    p

    .

    50 Feet

    .59 Exp.

    3

    F

    e

    e

    t

    3 Feet

    Guides

    4 Sch 40 Carbon Steel With H&B Dog Leg

    Anchor with 180 pounds force

    Hose & Braid

  • Flexible Loop Pro/Con

    Very compact Some pressure limitations

    No maintenance

    Minimal guiding requirements

    Lowest anchor loads, almost no structural considerations.

    Least expensive optionStandard or custom fit

    Large movement

    Seismic capable

    Pro Con

  • Axial movement Lateral movement Angular movement

    Theres a lot of choices of Bellows

    Axial Bellows Externally Pressurized Axial BellowsUntied Double

    Bellows Gimbal Bellows

    Dual Tied BellowsDouble Hinged

    BellowsSingle Hinge

    Bellows

  • Internally Pressurized

    Externally Pressurized

    Axial movement onlyCapable of Axial, Lateral and

    Angular movements.

  • Expansion

    Compensators

    externally

    pressurized

    Atmosphere

    Built in Liner

  • Squirm- Strut Instability - Limits the movement of internally pressurized bellows

    The balance between the number of convolutions needed for the movement exceeds the stability of the bellows

  • Internally Pressurized Bellows

    Axial

    Are Primarily Designed to Handle

    Axial Movement

  • On the other hand,a dual-tied bellows moves

    And laterally

    Axially

  • Dual-tied bellows joint

  • Anchors

  • Pressure ThrustPressure X effective area ( Use test pressure if greater )

    Calculating forces on anchors

    Deflection Load Published Spring Rate X movement of the joint

    Frictional ResistanceTotal weight of pipe, media, insulation & equip. X coefficient

  • Pressure ThrustPressure X effective area ( Use test pressure if greater )

    Example:4= 35.96 sq. in effective area x 125 PSI = 4495 #.

    Calculating forces on anchors

  • To calculate the thrust load:Effective Areas

  • Pressure Thrust for the Model MC Ring Controlled Self-Equalizing

    Expansion Joint The average car weighs only

    3000#

  • Deflection Load (spring rate)

    Totally independent of pressure or temperature

  • Published Spring Rate X Actual movement of the joint

    Example:4 with 6 Axial = Spring rate of 143 lbs/in

    X4.3 (total amount of expansion)

    = 614.9 lbs

    Deflection Load on Anchors

  • Frictional ResistanceTotal weight of pipe, media, insulation & equip. X coeff.

    Example4 sch. 40 pipe at 10.8 #/ft x 75 ft = 1890 #

    4 pipe internal area 12.73 sq.in. / 144 in. per sq.ft. = 0.088 cu.ft. x 175 linear ft. = 15.4 cu.ft. total volume

    125 PSI steam = 3.23 cu.ft. per pound = 4.76# weightadd guides & joint & insulation at 500#

    Total 2395# x 0.3 Coeff. = 719# frictional resistance

    Calculating forces on anchors

  • Total Anchor Force

    4495 Pressure Thrust614 Deflection Load719 Friction Resistance5,828.9 lbs force

    The engineer may add other loads such as snow, ice, wind, based on project conditions

  • Intermediate AnchorsIntermediate anchors between expansion devices do not see the full load.

    X

    Intermediate Anchor

    MainAnchor

    X X

    MainAnchor

    Expansion Joint

    EJMA recommends to design intermediate anchors for the spring load of one of the joints

  • XMainAnchor

    X

    X

    Expansion Joint

    Anchors at fittings can have multi-directional loads

    Force

    Force

  • Expansion Joint

    Location

    Makes a Difference

  • Guiding

  • Column strength of pipe.

  • Total Anchor Force

    4495 Pressure Thrust614 Deflection Load719 Friction Resistance5,828.9 lbs force

    Remember our Example

  • LINERSWhen velocity is high and could set up vibration in bellows

    Compressed air lines

    Exhaust gases

    Abrasive flow media

    Rule of Thumb :When velocity > 10 FPS

  • Install 1st. Guide a max. of 4 pipe dia. From the expansion joint.Install 2nd. Guide a max. of 14 pipe dia. From the 1st. Guide. Additional guides as per EJMA recommendations

  • Bellows Pro/Con

    Low/ no pressure drop High anchor loads

    Externally pressurized-large movement

    Easy to insulate

    Custom fit

    No maintenance

    Very compact Engineered anchors

    Considerable guiding requirements

    Pro Con

    Torque can be a problem

  • Slip type Joints

  • Slip Type Joint

  • Slip Joint construction detail

  • Ball Joints

    Always in, at least pairs

    Similar construction with Slip joints

    Same maintenance issues

  • Slip Type Pro/Con

    Low/ no pressure drop High anchor loads

    Custom fit

    Large movementVery compact

    Very expensive

    Low or no cycling is a detriment.

    Very High maintenance packing frequently needed

    Crucial and Considerable guiding requirements

    Engineered anchors

    Pro Con

  • 128

    6

    250 75

    85 75

    1

    5

    0

    1

    5

    0

    7

    5

    Lets Start With Determining The Pipe Size and Pipe Dimensions

  • To Calculate Expansion

    1 Determine design temperature for example 200 F.

    2 Establish installation temperature - For example 50 F

    3 Find the expansion rate per 100 feet 1.179 / 100 feet for steel 1.728 / 100 feet for copper

    4 Determine the length of pipe run for example 165 feet

    5 Multiply the expansion rate by the length.(165 / 100) X 1.179 = 1.94 Expansion

    6 If the joint is for both thermal and seismic, the values must be added together!

  • For An Example

    Lets use

    Pipe Material Carbon SteelService Hot WaterDesign Temperature 200FInstallation Temperature 50 FTemperature Difference T 150FExpansion Rate L 1.179 inches / 100 Feet

  • 128

    6

    250 75

    85 75

    1

    5

    0

    1

    5

    0

    7

    5

    2.95

    1.0

    1

    .

    7

    7

    1

    .

    7

    7

    0

    .

    8

    8

    0.88

    0.88

    Lets Calculate How Much The Pipe Will Expand

  • 128

    6

    250 75

    85 75

    1

    5

    0

    1

    5

    0

    7

    5

    2.95

    1.0

    1

    .

    7

    7

    1

    .

    7

    7

    0

    .

    8

    8

    0.88

    0.88

    Lets Establish The Anchor Points

    X

    X X

    X

    X

    X

    Anchor(typ)

    Anchor(typ)

  • First check for Natural

    Flexibility

    First check for Natural

    Flexibility

  • Keep in Mind

    90 changes in direction are the most efficient piping configuration to use to take up thermal expansion or contraction.

    Smaller angles will compound the movements!

  • 128

    6

    250 75

    85 75

    1

    5

    0

    1

    5

    0

    7

    5

    2.95

    1.0

    1

    .

    7

    7

    1

    .

    7

    7

    0

    .

    8

    8

    0.88

    0.88

    Next, Use Any Natural Flexibility Of The System

    X

    X X

    X

    X

    X

    Anchor(typ)

    Anchor(typ)

    2

    2

    1

    3

  • 128

    6

    250 75

    85 75

    1

    5

    0

    1

    5

    0

    7

    5

    2.95

    1.0

    1

    .

    7

    7

    1

    .

    7

    7

    0

    .

    8

    8

    0.88

    0.88

    Next, Complete The System WithFlexible Pipe Loops

    X

    X X

    X

    X

    X

    Anchor(typ)

    Anchor(typ)

    2

    2

    1

    3

    MLW81200

    MLW80800

    MLW30600

  • 128

    6

    250 75

    85 75

    1

    5

    0

    1

    5

    0

    7

    5

    2.95

    1.0

    1

    .

    7

    7

    1

    .

    7

    7

    0

    .

    8

    8

    0.88

    0.88

    X

    X X

    X

    X

    X

    Anchor(typ)

    Anchor(typ)

    2

    2

    1

    3

    Or, Complete The System WithExpansion Joints

    Dont forget about the guides. Note the placementof the Metragators

  • 128

    6

    250 75

    85 75

    1

    5

    0

    1

    5

    0

    7

    5

    2.95

    1.0

    1

    .

    7

    7

    1

    .

    7

    7

    0

    .

    8

    8

    0.88

    0.88

    What if the 75 foot run was only 18 feet?

    X

    X X

    X

    X

    X

    Anchor(typ)

    Anchor(typ)

    2

    2

    1

    3

  • 128

    6

    250 18

    85 75

    1

    5

    0

    1

    5

    0

    7

    5

    2.95

    1.0

    1

    .

    7

    7

    1

    .

    7

    7

    0

    .

    8

    8

    0.21

    0.88

    Option 1Use a Hose & Braid Dog Leg

    X

    X X

    X

    X

    X

    Anchor(typ)

    Anchor(typ)

    4

    0

    1

    3

  • 128

    6

    250 18

    85 75

    1

    5

    0

    1

    5

    0

    7

    5

    2.95

    1.0

    1

    .

    7

    7

    1

    .

    7

    7

    0

    .

    8

    8

    0.21

    0.88

    Option 2Add an Anchor, and another expansion device

    X

    X X

    X

    X

    X

    Anchor(typ)

    Anchor(typ)

    1

    8

    1

    3

    X

  • 128

    6

    250 18

    85 75

    1

    5

    0

    1

    5

    0

    7

    5

    2.95

    1.0

    1

    .

    7

    7

    1

    .

    7

    7

    0

    .

    8

    8

    0.21

    0.88

    Next, Complete The System WithFlexible Pipe Loops

    X

    X X

    X

    X

    X

    Anchor(typ)

    Anchor(typ)

    1

    8

    1

    3

    MLW81200

    MLW80800

    MLW30600

    X

    MLW30800

  • 128

    6

    250 18

    85 75

    1

    5

    0

    1

    5

    0

    7

    5

    2.95

    1.0

    1

    .

    7

    7

    1

    .

    7

    7

    0

    .

    8

    8

    0.21

    0.88

    Or with Expansion Joints

    X

    X X

    X

    X

    X

    Anchor(typ)

    Anchor(typ)

    2

    2

    1

    3

    X