thermodynamic 2-topic 5 : refrigerant

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    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    2.2. Va ourVa our--com ressioncom ression refri erationrefri eration

    processesprocesses

    Ron Zevenhovenbo Akademi UniversityThermal and Flow Engineering Laboratory / Vrme- och strmningsteknik

    tel. (02 215)3223 ; [email protected]

    2.11.2010 bo Akademi Univ - Thermal and Flow EngineeringPiispankatu 8, 20500 Turku

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    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    2.1 The ideal2.1 The idealvapourvapour--compression cyclecompression cycle

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    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    Reversed Carnot c cleReversed Carnot c cle /1/11-2 and 3-4:reversible and

    qu -vapoursaturation

    dome

    isothermal2-3 and 4-1:isentropic

    maximum thermalefficiency = 1 Q /Q

    Picture: B98

    if reversibleth = 1-TH/TL

    Condensation / evaporation of a fluid can be done at almost anytemperature/pressure combination, unlike freezing / melting, andnvo ves grea er ea e ec s vaporisation melting , orexample: water

    The Carnot ower c cle can be executed in a reverse within the

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    saturation dome of a refrigerant fluid

    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    Reversed Carnot c cleReversed Carnot c cle /2/21-2 and 3-4:reversible and

    qu -vapoursaturation

    dome

    isothermal2-3 and 4-1:isentropic

    maximum thermalefficiencyth = 1 QH/QL

    Picture: B98

    if reversibleth = 1-TH/TL

    The (reversed) Carnot cycle is the most efficient cycle operatingbetween two tem erature levels. But:

    process 2-3 involves compression of a two-phase mixture,and

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    process 4-1 involves expansion of wet refrigerant

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    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    Ideal va ourIdeal va our--com ression c clecom ression c cle /1/1 Operating the Picture: B98

    Carnot cycle

    outside the no isothermalconditions, /for heatabsorption andre ec on

    -

    QH = 23 Tds

    QL = 41

    Tdsusing a throttling valve (or a capillary tube)

    This results in a rocess with 3 reversible ste s, and

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    1 irreversible step

    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    T s dia ramT s dia ram here for Hhere for H OO

    LINES OF CONSTANT ENTHALPY IN THE SATURATION REGION

    isenthalpic

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    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    Ideal va ourIdeal va our--com ression c clecom ression c cle /2/2 Step 4-1: boiling of

    Picture: B98T

    Step 1-2: compressionof saturated vapour tohigh p and T

    -superheated gas iscooled to saturated

    ,

    Step 3-4: expansion to

    low p, also T down Note: sub-cooling a bit(due to someevaporation)

    beyond (3) reduces

    the risk of flashing

    in the eva orator

    (Qin - Qout) +

    (Win -Wout) +

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    mrefr(hin-hout) = 0.

    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    Pressure levelsPressure levelsA freezer at -18C in

    Operation pressures forevaporator and

    R-134a

    condensor are thevapour pressures forco ot

    refrigerantReversible if cold

    reservoir Tlow = Tcold ,hot reservoir Thigh = Thot

    0F = -18C, 70F = 21C, 250F = 121C

    Reversible:or - a, psat

    1.44 atm @ -18C,

    Trefrigerant = TreservoirThigh = 21C, Tlow = -18CCOP = 1 / T /T -1 = 6.6

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    .Picture: T06

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    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    ea vapourea vapour--compress on cyc ecompress on cyc e A vapour-compression refrigeration

    c cle uses refri erant R-134a atSource & picture: B98

    pressure levels p1 = 1.4 bar and p2 =

    8 bar, respectively, with mass flow= . . Calculate:

    The rate of heat removal QL andcompressor power input in

    The rate of heat rejection QH andthe COPR of the refrigerator

    Answer: data for R-134a ives T = -18.8C, T = 31.3C,for (1) h1 = hg = 236.0 kJ/kg; s1 = sg = 0.932 kJ/(kg.K); for (2) s2 =s1 gives h2 = 272.1 kJ/kg, for (3) h3 = hf= 93.42 kJ/kg, s3 = 0.346

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    kJ/(kg.K); for (4) h3 h4,

    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    R134a data:R134a data: saturation ressuresaturation ressure

    /testhome

    /

    34a.h

    tml

    /testcenter

    PC/pSatR

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    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    R134a data:R134a data: saturation tem eraturesaturation tem erature

    /test

    home

    /

    34a.htm

    l

    /testcenter

    PC/TSatR

    1

    gy.s

    dsu.e

    du

    ables

    /ta

    bles

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    ics

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    Source

    Test/s

    100C

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    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    R134a data:R134a data: su erheated va oursu erheated va our

    /testhome

    /

    134a.h

    tml

    /testcenter

    PC/super

    R

    gy.s

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    1.6 MPa

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    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    Exam le:Exam le: ideal va ourideal va our--com ression c clecom ression c cle /2/2Answer (cont.): Source & picture: B98

    QL = m(h1-h4) = 7.13 kW

    Win = m(h2-h1) = 1.80 kW.

    .

    QH = QL + Win = 8.93 kW

    COP = / W = 3.96 =

    .

    .

    (h1-h4)/(h2-h1)

    Replacing the throttling valve (34) by an isentropic turbine (34s)

    gives, with h4s = 86.92 kJ/kg a turbine power output of 0.34 kW,reducing the net power input Win to 1.46 kW.

    The removal of heat from the refrigerated space QL increases from7.13 kW to m h h = 7.46 kW.

    .

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    COPR increases from 3.96 to 5.11, an increase of 29%.

    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    2.2 Household refrigerators2.2 Household refrigerators

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    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    Household refri eratorHousehold refri erator /1/1Four Main Components:

    Compressor, which increases the

    htm

    ,pushing it through the system, and

    increasing the vapour's temperature

    edu/A3/A3..

    Condenser, usually behind therefrigerator, where the refrigerant

    .geo4va.vt..

    Expansion valve, which causes asudden drop in refrigerant pressure,

    " "

    ht

    tp://www

    valve, since it passes only as much liquidas can be completely vaporised in the

    ure&text:.

    evaporator, where the latent heat ofrefrigerant vaporisation is absorbed

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    Pic

    .

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    Household refri eratorHousehold refri erator /2/2

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    Picture: T06Picture: B98

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    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    Irreversible heat transferIrreversible heat transferA freezer at -18C in

    Tcold1C or Thot1C

    Heat transfer TO therefrigerant in evaporator

    R-134a

    -

    and FROM the refrigerantin condensor requires a

    o

    Tcold

    TsurrThot Tcold space

    T, say T = 10C

    0F = -18C, 70F = 21C, 250F = 121C

    Irreversible:

    cold

    cold = - psat = .bar),Thot = + 31C (psat =7.93 bar for the

    Trefrigerant Treservoir; ifT =10C Tcold = -28C, Thot = +31C

    = - =

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    refrigerant Picture: T06R hot cold .

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    2.3 Pressure2.3 Pressure -- enthalpy diagramsenthalpy diagrams

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    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    Pressure enthal dia ramsPressure enthal dia ramsIn a p, h diagram

    also. t e vapour-compress on

    refrigeration cycle gives

    possible

    steps, and

    2. the heat transferredQL) is proportional to thelength of the lines

    s s

    ==

    12

    41

    hh

    hh

    W

    QCOP

    in

    LR

    p@hhandp@hh 3f31g1 ==

    ==

    12

    32

    hhWCOP

    in

    HHP The

    correspondingCarnot cycle

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    caseidealthefor

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    h dia ram Rh dia ram R--134a134a

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    Picture: B98

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    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    h dia ram Rh dia ram R--134a134a

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    Picture:96

    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    h dia ram Rh dia ram R--717 NH717 NH

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    Picture:96

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    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    h dia ram Rh dia ram R--2222

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    Picture:96

    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    h dia ram Rh dia ram R--1212

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    Picture:96

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    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    h dia ram Rh dia ram R--744 CO744 CO

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    Picture:http://refrigerant.itri.org.tw/thi.htm

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    2.4 The real2.4 The realvapourvapour--compression cyclecompression cycle

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    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    -- In a real refrigerator

    man irreversibilitiesreduce the

    efficiency: u r ct on(gives heat /)

    with thesurroundings

    The real process differs a bit from the ideal process:

    Picture: B98

    o ensure comp e e vapor sa on, e re r geran s s g yoverheated at the evaporator inlet (8)

    A lon line between eva orator and com ressor ives fluid

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    friction and heat exchange with surroundings (81)

    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    --More differencescompared to theideal process:

    The compression is

    s > 0 (12) or

    by cooling,decreasing the

    volume ! c ure:

    There will be some pressure drop between compressor andcon ensor, n t e con ensor, etween con ensor an

    throttling device (2/245) and in the evaporator -

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    throttling device, located near the evaporator.

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    Exam le:Exam le: real va ourreal va our--com ression c cle /1com ression c cle /1 A vapour-compression refrigeration

    c cle uses refri erant R-134a with Picture: B98mass flow = 0.05 kg/s.

    Vapour enters the compressor at -, . ar an eaves t at ,

    bar.

    The vapour enters the condenser at7.2 bar and is cooled to 26C.

    The throttling valve reduces the. .

    Calculate:

    The heat removal QL and thecompressor power Win The adiabatic efficiency of the

    compressor Neglect the heat tranfer and

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    The COPR valuepressure rops n connec ng nes

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    Exam le:Exam le: real va ourreal va our--com ression c cle /2com ression c cle /2 At p1,T1: h1 = 243.4 kJ/kg

    Picture: B98p2, 2: 2 . g At p3,T3: h3 hf= 85.75 kJ/kg h h

    QL = (h1-h4) = 7.88 kW Win = (h2-h1) = 2.05 kW Adiabatic eff. of compressor

    c = 2s 1 2- 1p2s = 8 bar, s2s = s1,

    =s

    gives c = 0.919

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    Finally, COPR = QL/Win = 7.88 kW / 2.05 kW = 3.84

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    2.5 Refrigerants2.5 Refrigerants--

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    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    Refri erants freezin mixturesRefri erants freezin mixtures In a refrigeration process, energy is converted into

    id=841

    , . The heat carrier medium will take up the heat at a low

    il.asp?article

    temperature (and pressure) at another location

    A refri erant sv: kldmedie k lmedel artici ates in the /article_de

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    process by a phase transition and/or pressure changes. Itcan also be electricity !

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    A cooling or freezing mixture(sv: kldblandning) can carry or store

    .machinerylu

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    e:http://www

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    . not a refrigerant..... Pi

    ctur

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    Refri erants for va ourRefri erants for va our--compression (vcompression (v--c) systemsc) systems /1/1

    < 1 bar

    c12ausa.co

    ww.housene

    that expensive pressure vessels and tubing elements areneeded in practice below 20 bar.h

    ttp://www.

    ture:http://w

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    Pi

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    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    Refri erants for vRefri erants for v--c s stemsc s stems /3/3 Used / found in refrigeration systems (see also D03, TW00):

    CFCs (chloro fluoro carbons), HCFCs (hydro chloro fluoro carbons), mperature.gif

    HFCs (hydro fluoro carbons) mostly CFCs: R-11 in water

    chillers in building air conditioning, R-12 in domestic refrigerators, inautomotive air conditionin R-22 in air conditionin in industrial au

    tion-Low-te

    refrigeration, R-134a replaces R-12, R-502 (R-115 / R-22 mix) in

    supermarket refrigeration

    ductimages/C

    - Hydrocarbons (C3, C2, C2= ...) (R-6xx) (Non-)Azeotropic mixtures (R-4xx, R-5xx)

    ns.uk.com/pro

    CO2 (R-744) making a return; used in aircraft Air also used in aircraft; and also: Water

    alth-safety-sig

    , , 2 Halogenated hydrocarbon R-code: rightmost digit = no. of F, 10-digit = 1+no. of

    H, 100-digit = -1+no. of C, 1000-digit = no. of double bonds, a indicates isomerhttp://www.he

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    unbalance, the rest is Cl, B = no. of Br.Picture:

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    Refri erant va our ressureRefri erant va our ressure

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    Vapour pressures of gases and refrigerants Picture: S90

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    Some refri erant dataSome refri erant dataGas Refrigerant T boil C * Gas Refrigerant T boil C *

    2 5 2 - 3 -

    SO2 R-762 -10 CCl2F2 R-12 -30CH3Cl R-40 -24 CHClF2 R-22 -41

    CH2Cl2 R-30 +40 C2Cl3F3 R-113 +48

    NH3 R-717 -34 C2Cl2F4 R-114 +4

    CO2 R-744 -78 C2ClF5 R-115 -38

    CH4 R-850 -162 CF3CH2F R-134a -26

    CHClF2 +2 6 - - C2ClF5 ** - -

    i-C4H10 R-600a -12hydrocarbon

    mix HC-12a -33

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    * for pressure = 1 bar ** azeotrope

    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    --Boiling temperatures for 1 bar and 20 bar

    ers.jpg

    Ammonia: -33C and +50C R12: -30C and +70C

    ormal_Cylin

    R11: +25C and +140C R114: +5C and +120C 954

    7/

    _DOT_

    Or_

    N

    R134a: -26C and + 68C

    m/photo/113

    efrigerant_In

    Heat of vaporisation and density at 0C: Ammonia: 1260 k /k , 3.45 k /m3 4350 k /m3 g.a

    libaba.co

    w_

    R134a_

    R

    R22: 207 kJ/kg, 21.23 kg/m3 4400 kJ/m3volumetric heat o va orisation tur

    e:http://i

    re_

    Brand_

    N

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    Pi

    Pu

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    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    Greenhouse asesGreenhouse ases GHGsGHGs Greenhouse gases (GHGs), most importantly carbon

    dioxide CO methane CH and nitrous oxide(N2O) trap the outgoing solar radiation that is

    00.html

    which leads to global warming

    Note that water causes of the reenhouse ahd/g/g0258

    effect; the changing amounts of other GHGscause an enhanced greenhouse effect

    tionary.com/

    t er s an t eir g o a warmingpotential (GWP, CO

    2

    = 1 by definition)www.yourdi

    4 ~ , 2 ~

    HFCs (hydro fluoro carbons) (140-11700)

    PFCs er fluoro carbons 7400 icture:http:/

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    SF6 (23900) Source: ZK01

    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    Ozone de letin substancesOzone de letin substances ODSODS ODS substances do not have a direct global warming

    tropospheric/ stratospheric ozone

    , , -(volatile organic compounds)

    du/~tbw/

    tm zone ep e ng o en a , . . Carbon tetrachloride, methyl chloroform, halons CnFxClyBrz CFCs are re laced b non-ODS but un

    ter.cuny.e

    depletion.2.

    GHG!) compounds: HFCs, PFCs, SF6

    Class II ODS (ODP

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    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    Refi erant use in FinlandRefi erant use in Finland Most important: CFCs R11, R12; HFC R134a

    (R-22 belongs to HCFC group)

    6

    innis ecision : use o or i en exceptin special cases

    EU le islation: roduction and im ort/ex ert of ?Item

    Id=768

    CFCs forbidden as of 1995, as a well as putting CFCcontaining products on the market

    - ontPage.asp

    out during 2000-2015

    Alternatives should be found for HFCs also (mainlym.f

    i/main/Fr

    - - - CFCs, HCFCs and HFCs are hazardous wastes

    Special regulations as to the handling of CFC- End-of-life ://www.e

    kok

    containing coolers, freezers, and isolation materials(R-11 in poly urethane foam !)

    In the future more use of iso-butane R-600a

    refrigeratorhandlingat Ekokem

    Pictures:http

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    propane, propene, CO2 and ammonia Sources: 96, D03, SKL06

    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    2.6 Special vapour2.6 Special vapour--compressioncompressionrefrigeration systemsrefrigeration systems

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    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    --Picture: B98

    In industry, efficiencymay be more importantthan simplicity

    Sometimes thewide for a single v-ccycle use a cascade cycle

    One figure if the same

    Two cycles, a bottoming cycle and a topping cycle are

    connected via a heat exchanger

    For the heat exchanger without heat losses or kinetic /potential energy effects, and mass streams mA, mB :

    &&

    ..

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    )hh(m)hh(mWhhm)hh(m)hh(m

    BA

    B

    in,net

    L

    B

    ABA

    1256

    41

    85

    323285

    +==

    ==

    &&&&

    &&RCOP;

    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    -- -- Consider the system in the Figure: a

    cascade v-c refrigerator operatingPicture: B98

    etween . an ar w t - a asrefrigerant. The heat exchangeroperates at 3.2 bar for both streams. (In

    practice p and T are a bit higher in thebottom cycle.) Mass stream mA = 0.05kg/s. Calculate

    .

    mass stream mB, the heat stream QL taken from the

    refri erated s ace

    .

    compressor power Win the COPR for the process

    .

    kW1.60)()(WWWkW;7.13)(Q

    kg/s;0.039)()(

    1256bottomin,topin,in41L

    32

    3285

    =+=+===

    =

    ==

    hhmhhmhhm

    mhh

    mhhmhhm

    BAB

    ABBA

    &

    &&&&&&

    &&&&

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    4.46kW1.60

    .

    )()(COP

    1256

    41

    ,R ==

    +

    ==

    hhmhhmW BA

    B

    innet

    L

    &&&

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    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    22--sta e com ression refri erationsta e com ression refri eration In a cascade

    system using one Picture: B98

    refrigerant, a

    mixing chambercan be usedinstead of a heatexchanger

    Referred to as multistage compression refrigerationsys ems Saturated vapour from the flash chamber is fed to the high

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    pressure expansion valve

    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    -- Consider the system in the Figure:

    a cascade c-v refrigeratoroperating between 1.4 and 8 barwith R-134a as refrigerant. The

    saturated liquid and is throttled toa flash chamber at 3.2 bar. Thevapour product is mixed with therefrigerant leaving the low

    Assuming that both compressorsare isentropic and that therefrigerant leaves the evaporatoras saturated vapour: (continues)

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    Picture: B98

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    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    --Calculate

    , ,of the refrigerant that is

    evaporated when throttled to the

    The amount of heat that isremoved from the refrigeratedspace and the compressor workper unit mass refrigerant flowingthrou h the condenser, and w,and

    The COPR

    for the system;

    using the given T,s plot

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    Picture: B98

    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    -- The mass fraction, x, of refrigerant

    evaporated as it is throttled to theflash chamber equals x6 = (h6-hf)/(hg-hf) =(h6-h7)/(h3-h7) = 0.205

    e amoun o ea remove romthe refrigerated space per unit massequals qL = QL / m = (1-x6) (h1-h8)= 145.3 kJ/kg

    Enthalpy h9 follows fromh9 = x6 h3 +(1-x6) h2 = 251.9 kJ/kg

    = =.

    tables for R-134a that h4 = 271.1 kJ/kg Compressor work win = (1-x6) (h2-h1)+(h4-h9) = 31.8 kJ/kg

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    COPR = qL/win = 145.3 / 31.8 = 4.56 Picture: B98

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    MultiMulti-- ur ose refri eration with aur ose refri eration with asingle compressorsingle compressor

    Picture: B98

    Refrigeration at more than one temperature (as in an ordinaryouse o re r gerator reezer can e accomp s e w t onecompressor by throttling in two steps

    Usin one throttle valve and one cold tem erature would ive ice

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    in the refrigerator section.

    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    2.72.7 Real vapourReal vapour--compressioncompressioncycles and p,h diagramscycles and p,h diagrams

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    Real vReal v--c refri eration rocessc refri eration rocess A real vapour-

    compression

    refrigeration process ina p, agram: 1s = throttle valve in

    2i = evaporator in = 2k = compressor in

    1k = com ressor out

    Includes pressure drop over

    connection lines 2u-2k and 1k-1i; 1i = condenser in 1u = condenser out

    heat exchange with surroundingsand in the compressor

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    Picture: 96

    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    A commercial vA commercial v--c refri eratorc refri erator

    Using a water-cooled condensor and a heat exchanger

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    Temperature, pressure and heat of vaporisation can be optimised

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    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    Va ourVa our--com ression refri erationcom ression refri erationprocess with superheat / subcoolingprocess with superheat / subcooling

    Heat exchange between evaporator outlet and condensor outletcan improve the COP value.

    Superheating by increased compressor pressure gives no improvedefficiency but only results in larger condensor equipment

    Subcooling also ensures 100% liquid to the throttling valve and giveseither more heat extracted from the refrigerated space, or a smallerrequired refrigerant mass flow

    Less attractive if the suction line to the compressor is long, especially

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    w en us ng ammon a as re r geran

    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    --Picture: 96

    ssor

    compr

    refrigerant at acceptable vapour pressures (a one-stage +10C/-30C unitcan reach -65C with two stages or -100C with three)

    With minimum and maximum pressures p1 and p2 it can be shown that

    the optimum intermediate pressure level pm = (p1p2) Disadvanta es are lower efficienc , hi her ower in ut, increased

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    temperature of refrigerant vapor from first compressor

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    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    Cascade vCascade v--c s stemsc s stems /1/1 A two-stage

    Picture: D03

    differentrefrigerants andheat exchange

    Allows for a lowerempera ure an

    with a single-stagesystem

    Typically -150C

    can be reached Compressor workdecreases COP

    Condenser B of system I is cooled

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    by evaporator C of system 2

    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    Cascade vCascade v--c s stemsc s stems /2/2Cascade systems arecommonly used for Pictures: D03

    CO2 or

    natura gas liquefaction

    Linde-Hampsonsystem

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    Picture: B98compression

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    2.8 Final remarks2.8 Final remarks

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    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    Defrostin ur in airDefrostin ur in air Defrosting is

    necessary from timePicture: D03

    to time to removeice (from airhumidit

    An effective methodis to use hot

    compressor;otherwise warm air,wa er or e ec r c ycan be used

    immiscible with the refrigerant it acts as an insulator at heattransfer surfaces, making the condensor smaller)

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    Manual or automatic purging methods can remove this air

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    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    Tons of refri erationTons of refri eration For refrigerators used for producing ice, one way to

    26.jpg

    1 ton of refrigeration = heat needed to freeze 1 short= = ood/c

    h16fig1

    24 hours

    1 ton of refri eration docs/wwii/bl

    = 211 kJ/min = 200 BTU/min= 3.52 kW heat removal from

    my.m

    il/book

    the refrigerated space

    ory

    .amedd.ar

    re:http://hist

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    Pictu

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    Heat exchan er irreversibilitiesHeat exchan er irreversibilities vS91vS91 A simple steady-state

    heat transfer rocess; Thermodynamic analysis

    balanceEner

    heat is transported frommedium 1 to medium 2

    = 21

    balanceEntropy

    QQ &&

    by conduction through amaterial that separates =+2

    2

    1

    1

    TQS

    TQ

    gen&&&

    . Temperature T1 > T2

    0>

    =

    1

    1=

    21

    211

    12

    1 TT

    TTQ

    TTQSgen

    &&&

    This shows that Sgen islar e for lar e tem erature

    .

    differences (T1-T2) and lowtemperatures T1 and T2Q1.

    Q2.

    T = T T = T

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    2.9 Vapour2.9 Vapour--compression cyclecompression cycleheat pumpsheat pumps

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    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    Heat um s usin vHeat um s usin v--c c clec c cle

    A heat pump vapour-compression system with reversing valve forsummer / coolin a or winter / heatin o eration b

    NOTE:

    HP=

    COPR+1

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    Pictures: KJ05

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    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    Heat um s in FinlandHeat um s in Finland

    Total capacity (2004)Total capacity (2004)

    Waste heat

    Air heat

    Geothermal

    ~~ ~~ ~~

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    Source / picture: http://www.sulpu.fi/index.phpHeat pumps: to be continued

    REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz

    Sources #2Sources #2 CB98: Y.A. engel, M.A. Boles Thermodynamics. An Engineering Approach, McGraw-

    Hill (1998) D03: . Diner Refri eration s stems and a lications Wile 2003 KJ05: D. Kaminski, M. Jensen Introduction to Thermal and Fluids Engineering, Wiley

    (2005) SEHB06: P.S. Schmidt, O. Ezekoye, J. R Howell, D. Baker Thermodynamics: An oa

    t09.jpg

    Integrated Learning System (Text + Web) Wiley (2006) S90: A.L. Stolk Koudetechniek A1, Delft University of Technology (1990) SKL06: Suomen Kylmliikkeiden Liitto (2006) http://www.skll.fi/

    3/0809bee

    rfl

    T06: S.R. Turns Thermal Fluid Sciences, Cambridge Univ. Press (2006) TW00: A.R. Trott, T.C. Welsh Refrigeration and Air-Conditioning

    3rd Ed. Butterworths-Heineman (2000)l.com/ent/gif

    ZK01: R. Zevenhoven, P. Kilpinen Control of pollutants in fluegases and fuel gases Picaset (Espoo), 2001 (Chapter 9)

    96: G. hman Kylteknik, bo Akademi University (1996)ww.azcentra

    See also: Martinez, I. Lectures on Thermodynamics lecture 18 (English or Spanish)http://webserver.dmt.upm.es/~isidoro/bk3/index.htmlupdated and based on re

    :http://w