thermodynamic 2-topic 5 : refrigerant
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2.2. Va ourVa our--com ressioncom ression refri erationrefri eration
processesprocesses
Ron Zevenhovenbo Akademi UniversityThermal and Flow Engineering Laboratory / Vrme- och strmningsteknik
tel. (02 215)3223 ; [email protected]
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2.1 The ideal2.1 The idealvapourvapour--compression cyclecompression cycle
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Reversed Carnot c cleReversed Carnot c cle /1/11-2 and 3-4:reversible and
qu -vapoursaturation
dome
isothermal2-3 and 4-1:isentropic
maximum thermalefficiency = 1 Q /Q
Picture: B98
if reversibleth = 1-TH/TL
Condensation / evaporation of a fluid can be done at almost anytemperature/pressure combination, unlike freezing / melting, andnvo ves grea er ea e ec s vaporisation melting , orexample: water
The Carnot ower c cle can be executed in a reverse within the
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saturation dome of a refrigerant fluid
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Reversed Carnot c cleReversed Carnot c cle /2/21-2 and 3-4:reversible and
qu -vapoursaturation
dome
isothermal2-3 and 4-1:isentropic
maximum thermalefficiencyth = 1 QH/QL
Picture: B98
if reversibleth = 1-TH/TL
The (reversed) Carnot cycle is the most efficient cycle operatingbetween two tem erature levels. But:
process 2-3 involves compression of a two-phase mixture,and
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process 4-1 involves expansion of wet refrigerant
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Ideal va ourIdeal va our--com ression c clecom ression c cle /1/1 Operating the Picture: B98
Carnot cycle
outside the no isothermalconditions, /for heatabsorption andre ec on
-
QH = 23 Tds
QL = 41
Tdsusing a throttling valve (or a capillary tube)
This results in a rocess with 3 reversible ste s, and
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1 irreversible step
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T s dia ramT s dia ram here for Hhere for H OO
LINES OF CONSTANT ENTHALPY IN THE SATURATION REGION
isenthalpic
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Ideal va ourIdeal va our--com ression c clecom ression c cle /2/2 Step 4-1: boiling of
Picture: B98T
Step 1-2: compressionof saturated vapour tohigh p and T
-superheated gas iscooled to saturated
,
Step 3-4: expansion to
low p, also T down Note: sub-cooling a bit(due to someevaporation)
beyond (3) reduces
the risk of flashing
in the eva orator
(Qin - Qout) +
(Win -Wout) +
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mrefr(hin-hout) = 0.
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Pressure levelsPressure levelsA freezer at -18C in
Operation pressures forevaporator and
R-134a
condensor are thevapour pressures forco ot
refrigerantReversible if cold
reservoir Tlow = Tcold ,hot reservoir Thigh = Thot
0F = -18C, 70F = 21C, 250F = 121C
Reversible:or - a, psat
1.44 atm @ -18C,
Trefrigerant = TreservoirThigh = 21C, Tlow = -18CCOP = 1 / T /T -1 = 6.6
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.Picture: T06
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ea vapourea vapour--compress on cyc ecompress on cyc e A vapour-compression refrigeration
c cle uses refri erant R-134a atSource & picture: B98
pressure levels p1 = 1.4 bar and p2 =
8 bar, respectively, with mass flow= . . Calculate:
The rate of heat removal QL andcompressor power input in
The rate of heat rejection QH andthe COPR of the refrigerator
Answer: data for R-134a ives T = -18.8C, T = 31.3C,for (1) h1 = hg = 236.0 kJ/kg; s1 = sg = 0.932 kJ/(kg.K); for (2) s2 =s1 gives h2 = 272.1 kJ/kg, for (3) h3 = hf= 93.42 kJ/kg, s3 = 0.346
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kJ/(kg.K); for (4) h3 h4,
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R134a data:R134a data: saturation ressuresaturation ressure
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R134a data:R134a data: saturation tem eraturesaturation tem erature
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R134a data:R134a data: su erheated va oursu erheated va our
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1.6 MPa
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Exam le:Exam le: ideal va ourideal va our--com ression c clecom ression c cle /2/2Answer (cont.): Source & picture: B98
QL = m(h1-h4) = 7.13 kW
Win = m(h2-h1) = 1.80 kW.
.
QH = QL + Win = 8.93 kW
COP = / W = 3.96 =
.
.
(h1-h4)/(h2-h1)
Replacing the throttling valve (34) by an isentropic turbine (34s)
gives, with h4s = 86.92 kJ/kg a turbine power output of 0.34 kW,reducing the net power input Win to 1.46 kW.
The removal of heat from the refrigerated space QL increases from7.13 kW to m h h = 7.46 kW.
.
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COPR increases from 3.96 to 5.11, an increase of 29%.
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2.2 Household refrigerators2.2 Household refrigerators
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Household refri eratorHousehold refri erator /1/1Four Main Components:
Compressor, which increases the
htm
,pushing it through the system, and
increasing the vapour's temperature
edu/A3/A3..
Condenser, usually behind therefrigerator, where the refrigerant
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Expansion valve, which causes asudden drop in refrigerant pressure,
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valve, since it passes only as much liquidas can be completely vaporised in the
ure&text:.
evaporator, where the latent heat ofrefrigerant vaporisation is absorbed
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Pic
.
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Household refri eratorHousehold refri erator /2/2
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Picture: T06Picture: B98
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Irreversible heat transferIrreversible heat transferA freezer at -18C in
Tcold1C or Thot1C
Heat transfer TO therefrigerant in evaporator
R-134a
-
and FROM the refrigerantin condensor requires a
o
Tcold
TsurrThot Tcold space
T, say T = 10C
0F = -18C, 70F = 21C, 250F = 121C
Irreversible:
cold
cold = - psat = .bar),Thot = + 31C (psat =7.93 bar for the
Trefrigerant Treservoir; ifT =10C Tcold = -28C, Thot = +31C
= - =
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refrigerant Picture: T06R hot cold .
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2.3 Pressure2.3 Pressure -- enthalpy diagramsenthalpy diagrams
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Pressure enthal dia ramsPressure enthal dia ramsIn a p, h diagram
also. t e vapour-compress on
refrigeration cycle gives
possible
steps, and
2. the heat transferredQL) is proportional to thelength of the lines
s s
==
12
41
hh
hh
W
QCOP
in
LR
p@hhandp@hh 3f31g1 ==
==
12
32
hhWCOP
in
HHP The
correspondingCarnot cycle
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caseidealthefor
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h dia ram Rh dia ram R--134a134a
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Picture: B98
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h dia ram Rh dia ram R--134a134a
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Picture:96
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h dia ram Rh dia ram R--717 NH717 NH
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Picture:96
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h dia ram Rh dia ram R--2222
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Picture:96
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h dia ram Rh dia ram R--1212
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Picture:96
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h dia ram Rh dia ram R--744 CO744 CO
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Picture:http://refrigerant.itri.org.tw/thi.htm
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2.4 The real2.4 The realvapourvapour--compression cyclecompression cycle
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-- In a real refrigerator
man irreversibilitiesreduce the
efficiency: u r ct on(gives heat /)
with thesurroundings
The real process differs a bit from the ideal process:
Picture: B98
o ensure comp e e vapor sa on, e re r geran s s g yoverheated at the evaporator inlet (8)
A lon line between eva orator and com ressor ives fluid
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friction and heat exchange with surroundings (81)
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--More differencescompared to theideal process:
The compression is
s > 0 (12) or
by cooling,decreasing the
volume ! c ure:
There will be some pressure drop between compressor andcon ensor, n t e con ensor, etween con ensor an
throttling device (2/245) and in the evaporator -
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throttling device, located near the evaporator.
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Exam le:Exam le: real va ourreal va our--com ression c cle /1com ression c cle /1 A vapour-compression refrigeration
c cle uses refri erant R-134a with Picture: B98mass flow = 0.05 kg/s.
Vapour enters the compressor at -, . ar an eaves t at ,
bar.
The vapour enters the condenser at7.2 bar and is cooled to 26C.
The throttling valve reduces the. .
Calculate:
The heat removal QL and thecompressor power Win The adiabatic efficiency of the
compressor Neglect the heat tranfer and
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The COPR valuepressure rops n connec ng nes
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Exam le:Exam le: real va ourreal va our--com ression c cle /2com ression c cle /2 At p1,T1: h1 = 243.4 kJ/kg
Picture: B98p2, 2: 2 . g At p3,T3: h3 hf= 85.75 kJ/kg h h
QL = (h1-h4) = 7.88 kW Win = (h2-h1) = 2.05 kW Adiabatic eff. of compressor
c = 2s 1 2- 1p2s = 8 bar, s2s = s1,
=s
gives c = 0.919
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Finally, COPR = QL/Win = 7.88 kW / 2.05 kW = 3.84
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2.5 Refrigerants2.5 Refrigerants--
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Refri erants freezin mixturesRefri erants freezin mixtures In a refrigeration process, energy is converted into
id=841
, . The heat carrier medium will take up the heat at a low
il.asp?article
temperature (and pressure) at another location
A refri erant sv: kldmedie k lmedel artici ates in the /article_de
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process by a phase transition and/or pressure changes. Itcan also be electricity !
brication.co
A cooling or freezing mixture(sv: kldblandning) can carry or store
.machinerylu
eat, w ic can invo ve aphase transition, but little or no pressure
e:http://www
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. not a refrigerant..... Pi
ctur
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Refri erants for va ourRefri erants for va our--compression (vcompression (v--c) systemsc) systems /1/1
< 1 bar
c12ausa.co
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that expensive pressure vessels and tubing elements areneeded in practice below 20 bar.h
ttp://www.
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Pi
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Refri erants for vRefri erants for v--c s stemsc s stems /3/3 Used / found in refrigeration systems (see also D03, TW00):
CFCs (chloro fluoro carbons), HCFCs (hydro chloro fluoro carbons), mperature.gif
HFCs (hydro fluoro carbons) mostly CFCs: R-11 in water
chillers in building air conditioning, R-12 in domestic refrigerators, inautomotive air conditionin R-22 in air conditionin in industrial au
tion-Low-te
refrigeration, R-134a replaces R-12, R-502 (R-115 / R-22 mix) in
supermarket refrigeration
ductimages/C
- Hydrocarbons (C3, C2, C2= ...) (R-6xx) (Non-)Azeotropic mixtures (R-4xx, R-5xx)
ns.uk.com/pro
CO2 (R-744) making a return; used in aircraft Air also used in aircraft; and also: Water
alth-safety-sig
, , 2 Halogenated hydrocarbon R-code: rightmost digit = no. of F, 10-digit = 1+no. of
H, 100-digit = -1+no. of C, 1000-digit = no. of double bonds, a indicates isomerhttp://www.he
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unbalance, the rest is Cl, B = no. of Br.Picture:
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Refri erant va our ressureRefri erant va our ressure
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Vapour pressures of gases and refrigerants Picture: S90
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Some refri erant dataSome refri erant dataGas Refrigerant T boil C * Gas Refrigerant T boil C *
2 5 2 - 3 -
SO2 R-762 -10 CCl2F2 R-12 -30CH3Cl R-40 -24 CHClF2 R-22 -41
CH2Cl2 R-30 +40 C2Cl3F3 R-113 +48
NH3 R-717 -34 C2Cl2F4 R-114 +4
CO2 R-744 -78 C2ClF5 R-115 -38
CH4 R-850 -162 CF3CH2F R-134a -26
CHClF2 +2 6 - - C2ClF5 ** - -
i-C4H10 R-600a -12hydrocarbon
mix HC-12a -33
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* for pressure = 1 bar ** azeotrope
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--Boiling temperatures for 1 bar and 20 bar
ers.jpg
Ammonia: -33C and +50C R12: -30C and +70C
ormal_Cylin
R11: +25C and +140C R114: +5C and +120C 954
7/
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Or_
N
R134a: -26C and + 68C
m/photo/113
efrigerant_In
Heat of vaporisation and density at 0C: Ammonia: 1260 k /k , 3.45 k /m3 4350 k /m3 g.a
libaba.co
w_
R134a_
R
R22: 207 kJ/kg, 21.23 kg/m3 4400 kJ/m3volumetric heat o va orisation tur
e:http://i
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Brand_
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Pi
Pu
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Greenhouse asesGreenhouse ases GHGsGHGs Greenhouse gases (GHGs), most importantly carbon
dioxide CO methane CH and nitrous oxide(N2O) trap the outgoing solar radiation that is
00.html
which leads to global warming
Note that water causes of the reenhouse ahd/g/g0258
effect; the changing amounts of other GHGscause an enhanced greenhouse effect
tionary.com/
t er s an t eir g o a warmingpotential (GWP, CO
2
= 1 by definition)www.yourdi
4 ~ , 2 ~
HFCs (hydro fluoro carbons) (140-11700)
PFCs er fluoro carbons 7400 icture:http:/
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SF6 (23900) Source: ZK01
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Ozone de letin substancesOzone de letin substances ODSODS ODS substances do not have a direct global warming
tropospheric/ stratospheric ozone
, , -(volatile organic compounds)
du/~tbw/
tm zone ep e ng o en a , . . Carbon tetrachloride, methyl chloroform, halons CnFxClyBrz CFCs are re laced b non-ODS but un
ter.cuny.e
depletion.2.
GHG!) compounds: HFCs, PFCs, SF6
Class II ODS (ODP
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Refi erant use in FinlandRefi erant use in Finland Most important: CFCs R11, R12; HFC R134a
(R-22 belongs to HCFC group)
6
innis ecision : use o or i en exceptin special cases
EU le islation: roduction and im ort/ex ert of ?Item
Id=768
CFCs forbidden as of 1995, as a well as putting CFCcontaining products on the market
- ontPage.asp
out during 2000-2015
Alternatives should be found for HFCs also (mainlym.f
i/main/Fr
- - - CFCs, HCFCs and HFCs are hazardous wastes
Special regulations as to the handling of CFC- End-of-life ://www.e
kok
containing coolers, freezers, and isolation materials(R-11 in poly urethane foam !)
In the future more use of iso-butane R-600a
refrigeratorhandlingat Ekokem
Pictures:http
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propane, propene, CO2 and ammonia Sources: 96, D03, SKL06
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2.6 Special vapour2.6 Special vapour--compressioncompressionrefrigeration systemsrefrigeration systems
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--Picture: B98
In industry, efficiencymay be more importantthan simplicity
Sometimes thewide for a single v-ccycle use a cascade cycle
One figure if the same
Two cycles, a bottoming cycle and a topping cycle are
connected via a heat exchanger
For the heat exchanger without heat losses or kinetic /potential energy effects, and mass streams mA, mB :
&&
..
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)hh(m)hh(mWhhm)hh(m)hh(m
BA
B
in,net
L
B
ABA
1256
41
85
323285
+==
==
&&&&
&&RCOP;
REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz
-- -- Consider the system in the Figure: a
cascade v-c refrigerator operatingPicture: B98
etween . an ar w t - a asrefrigerant. The heat exchangeroperates at 3.2 bar for both streams. (In
practice p and T are a bit higher in thebottom cycle.) Mass stream mA = 0.05kg/s. Calculate
.
mass stream mB, the heat stream QL taken from the
refri erated s ace
.
compressor power Win the COPR for the process
.
kW1.60)()(WWWkW;7.13)(Q
kg/s;0.039)()(
1256bottomin,topin,in41L
32
3285
=+=+===
=
==
hhmhhmhhm
mhh
mhhmhhm
BAB
ABBA
&
&&&&&&
&&&&
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4.46kW1.60
.
)()(COP
1256
41
,R ==
+
==
hhmhhmW BA
B
innet
L
&&&
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REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz
22--sta e com ression refri erationsta e com ression refri eration In a cascade
system using one Picture: B98
refrigerant, a
mixing chambercan be usedinstead of a heatexchanger
Referred to as multistage compression refrigerationsys ems Saturated vapour from the flash chamber is fed to the high
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pressure expansion valve
REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz
-- Consider the system in the Figure:
a cascade c-v refrigeratoroperating between 1.4 and 8 barwith R-134a as refrigerant. The
saturated liquid and is throttled toa flash chamber at 3.2 bar. Thevapour product is mixed with therefrigerant leaving the low
Assuming that both compressorsare isentropic and that therefrigerant leaves the evaporatoras saturated vapour: (continues)
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Picture: B98
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REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz
--Calculate
, ,of the refrigerant that is
evaporated when throttled to the
The amount of heat that isremoved from the refrigeratedspace and the compressor workper unit mass refrigerant flowingthrou h the condenser, and w,and
The COPR
for the system;
using the given T,s plot
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Picture: B98
REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz
-- The mass fraction, x, of refrigerant
evaporated as it is throttled to theflash chamber equals x6 = (h6-hf)/(hg-hf) =(h6-h7)/(h3-h7) = 0.205
e amoun o ea remove romthe refrigerated space per unit massequals qL = QL / m = (1-x6) (h1-h8)= 145.3 kJ/kg
Enthalpy h9 follows fromh9 = x6 h3 +(1-x6) h2 = 251.9 kJ/kg
= =.
tables for R-134a that h4 = 271.1 kJ/kg Compressor work win = (1-x6) (h2-h1)+(h4-h9) = 31.8 kJ/kg
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COPR = qL/win = 145.3 / 31.8 = 4.56 Picture: B98
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REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz
MultiMulti-- ur ose refri eration with aur ose refri eration with asingle compressorsingle compressor
Picture: B98
Refrigeration at more than one temperature (as in an ordinaryouse o re r gerator reezer can e accomp s e w t onecompressor by throttling in two steps
Usin one throttle valve and one cold tem erature would ive ice
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in the refrigerator section.
REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz
2.72.7 Real vapourReal vapour--compressioncompressioncycles and p,h diagramscycles and p,h diagrams
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REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz
Real vReal v--c refri eration rocessc refri eration rocess A real vapour-
compression
refrigeration process ina p, agram: 1s = throttle valve in
2i = evaporator in = 2k = compressor in
1k = com ressor out
Includes pressure drop over
connection lines 2u-2k and 1k-1i; 1i = condenser in 1u = condenser out
heat exchange with surroundingsand in the compressor
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Picture: 96
REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz
A commercial vA commercial v--c refri eratorc refri erator
Using a water-cooled condensor and a heat exchanger
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Temperature, pressure and heat of vaporisation can be optimised
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REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz
Va ourVa our--com ression refri erationcom ression refri erationprocess with superheat / subcoolingprocess with superheat / subcooling
Heat exchange between evaporator outlet and condensor outletcan improve the COP value.
Superheating by increased compressor pressure gives no improvedefficiency but only results in larger condensor equipment
Subcooling also ensures 100% liquid to the throttling valve and giveseither more heat extracted from the refrigerated space, or a smallerrequired refrigerant mass flow
Less attractive if the suction line to the compressor is long, especially
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w en us ng ammon a as re r geran
REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz
--Picture: 96
ssor
compr
refrigerant at acceptable vapour pressures (a one-stage +10C/-30C unitcan reach -65C with two stages or -100C with three)
With minimum and maximum pressures p1 and p2 it can be shown that
the optimum intermediate pressure level pm = (p1p2) Disadvanta es are lower efficienc , hi her ower in ut, increased
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temperature of refrigerant vapor from first compressor
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REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz
Cascade vCascade v--c s stemsc s stems /1/1 A two-stage
Picture: D03
differentrefrigerants andheat exchange
Allows for a lowerempera ure an
with a single-stagesystem
Typically -150C
can be reached Compressor workdecreases COP
Condenser B of system I is cooled
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by evaporator C of system 2
REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz
Cascade vCascade v--c s stemsc s stems /2/2Cascade systems arecommonly used for Pictures: D03
CO2 or
natura gas liquefaction
Linde-Hampsonsystem
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Picture: B98compression
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2.8 Final remarks2.8 Final remarks
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REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz
Defrostin ur in airDefrostin ur in air Defrosting is
necessary from timePicture: D03
to time to removeice (from airhumidit
An effective methodis to use hot
compressor;otherwise warm air,wa er or e ec r c ycan be used
immiscible with the refrigerant it acts as an insulator at heattransfer surfaces, making the condensor smaller)
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Manual or automatic purging methods can remove this air
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REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz
Tons of refri erationTons of refri eration For refrigerators used for producing ice, one way to
26.jpg
1 ton of refrigeration = heat needed to freeze 1 short= = ood/c
h16fig1
24 hours
1 ton of refri eration docs/wwii/bl
= 211 kJ/min = 200 BTU/min= 3.52 kW heat removal from
my.m
il/book
the refrigerated space
ory
.amedd.ar
re:http://hist
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Pictu
REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz
Heat exchan er irreversibilitiesHeat exchan er irreversibilities vS91vS91 A simple steady-state
heat transfer rocess; Thermodynamic analysis
balanceEner
heat is transported frommedium 1 to medium 2
= 21
balanceEntropy
QQ &&
by conduction through amaterial that separates =+2
2
1
1
TQS
TQ
gen&&&
. Temperature T1 > T2
0>
=
1
1=
21
211
12
1 TT
TTQ
TTQSgen
&&&
This shows that Sgen islar e for lar e tem erature
.
differences (T1-T2) and lowtemperatures T1 and T2Q1.
Q2.
T = T T = T
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REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz
2.9 Vapour2.9 Vapour--compression cyclecompression cycleheat pumpsheat pumps
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REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz
Heat um s usin vHeat um s usin v--c c clec c cle
A heat pump vapour-compression system with reversing valve forsummer / coolin a or winter / heatin o eration b
NOTE:
HP=
COPR+1
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Pictures: KJ05
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REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz
Heat um s in FinlandHeat um s in Finland
Total capacity (2004)Total capacity (2004)
Waste heat
Air heat
Geothermal
~~ ~~ ~~
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Source / picture: http://www.sulpu.fi/index.phpHeat pumps: to be continued
REFRIGERATIONREFRIGERATION ((svsv: Kylteknik): Kylteknik) 424503 E 2010 #2424503 E 2010 #2 -- rzrz
Sources #2Sources #2 CB98: Y.A. engel, M.A. Boles Thermodynamics. An Engineering Approach, McGraw-
Hill (1998) D03: . Diner Refri eration s stems and a lications Wile 2003 KJ05: D. Kaminski, M. Jensen Introduction to Thermal and Fluids Engineering, Wiley
(2005) SEHB06: P.S. Schmidt, O. Ezekoye, J. R Howell, D. Baker Thermodynamics: An oa
t09.jpg
Integrated Learning System (Text + Web) Wiley (2006) S90: A.L. Stolk Koudetechniek A1, Delft University of Technology (1990) SKL06: Suomen Kylmliikkeiden Liitto (2006) http://www.skll.fi/
3/0809bee
rfl
T06: S.R. Turns Thermal Fluid Sciences, Cambridge Univ. Press (2006) TW00: A.R. Trott, T.C. Welsh Refrigeration and Air-Conditioning
3rd Ed. Butterworths-Heineman (2000)l.com/ent/gif
ZK01: R. Zevenhoven, P. Kilpinen Control of pollutants in fluegases and fuel gases Picaset (Espoo), 2001 (Chapter 9)
96: G. hman Kylteknik, bo Akademi University (1996)ww.azcentra
See also: Martinez, I. Lectures on Thermodynamics lecture 18 (English or Spanish)http://webserver.dmt.upm.es/~isidoro/bk3/index.htmlupdated and based on re
:http://w