thiet ke so bo

8/7/2019 Thiet ke so bo

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n Tt Nghip Trng i Hc Giao Thng Vn Ti

MC LC

PHN I...........................................................................................3THIT K S B............................................................................3

CHNG I..................................................................................5GII THIU CHUNG.....................................................................5

I. NHIM V THIT K.................................................................................5II. C IM A HNH................................................................................5

III. C IM A CHT..............................................................................5IV. QUY TRNH THIT K V CC NGUYN TC CHUNG..................51. Quy trnh thit k:............................................................52. Cc thng s k thut c bn:...........................................6

V. CC PHNG N K THUT..................................................................6CHNG II.................................................................................7PHNG N S B I CU DM GIN N BTCT......................7MT CT CH I...........................................................................7

I.GII THIU CHUNG V CC PHNG N :..........................................7I.1. S b tr chung ca cu:............................................7I.2. M t tm tt kt cu phn trn.....................................7I.3. M t tm tt kt cu phn di:...................................8I.4. Mt cu v cc cng trnh ph khc:.............................8I.5 . Vt liu ch to. ........................................................10I.6 . Bin php thi cng. ....................................................12

CHNG III..............................................................................15PHNG N S B II CU DM GIN N BTCT...................15MT CT SUPER T.....................................................................15

I.GII THIU CHUNG V CC PHNG N :........................................15

I.1. S b tr chung ca cu:..........................................15I.2. M t tm tt kt cu phn trn...................................15I.3. M t tm tt kt cu phn di:.................................16I.4. Mt cu v cc cng trnh ph khc:...........................16I.5 . Vt liu ch to...........................................................18I.6 . Bin php thi cng. ....................................................20

CHNG III..............................................................................23SO SNH LA CHN PHNG N............................................23V Kinh T................................................................................23

V K Thut..............................................................................23V M Quan..............................................................................23

Sinh vin: Nguyn Thnh Trung Lp TDHTKCD-K47 Page 1


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9.2.Tnh duyt theo TTGH Cng ................................10610.1.Xc nh sc khng ct danh nh............................11110.2.Tnh duyt lc ct theo TTGH cng ....................11310.3.Tnh duyt ct thp doc chu xon...........................114

XI.TNH DUYT BN MT CU V DM NGANG.............................11711.1.Phng php tnh ton bn mt cu........................11711.2.Xc nh ni lc bn mt cu do tnh ti..................11711.3.Xc nh ni lc do hot ti v ngi i b:..............12011.4.Vt liu thit k cho bn mt cu:...........................12211.5.Tnh ton ct thp chu lc:......................................123

PHN I

THIT K S B



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2. Cc thng s k thut c bn:

2.1. Quy m cng trnh:

- Cu vnh cu.

2.2. Ti trng thit k:

- Ti trng thit k : HL93.

- Ti trng ngi i b.

2.3. Kh cu:

Cu c chiu rng nh sau:

- B rng mt ng xe chy: 7m (khng k lan can, g chn bnh, g chn

xe)

- L ngi i b: 2x2m

2.4. Kh thng xe

- Kh thng xe 22.05 x 4.75m

V. CC PHNG N K THUT.

Phng n xy dng cu da trn cc nguyn tc sau:

- Tho mn cc yu cu v tuyn v cu.

- Phng n phi c tnh kh thi.

- Ph hp vi cc iu kin t nhin ti v tr xy dng cu (c bit l iukin a cht, mt bng).

- Tn dng c nguyn liu v cng ngh c sn trong nc.



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CHNG II

PHNG N S B I CU DM GIN N BTCT

MT CT CH I

I.GII THIU CHUNG V CC PHNG N :

I.1. S b tr chung ca cu:

Da vo mt bng cu, kh thng xe, kh vt ng v mt ct a cht,ngi thit k a ra phng n cu dm gin n BTCT mt ct ch I vi s cu nh sau: cu gm 11 nhp vi chiu di cc nhp b tr: 11 x 33.050m

Chiu di ton cu Ltc = 373.55 m

I.2. M t tm tt kt cu phn trn.

I.2.1. Chiu cao dm.

Chiu cao dm c chn theo yu cu sau:

+ Trng lng thp ca dn ch nh.

+ Bo m tnh khng thng xe v vt ng st.

+ m bo m quan v ph hp vi cnh quan khu vc xy cu.

Theo kinh nghim th i vi cu t, chiu cao dm c chn nh sau:

h = (8

1:

25

1)Lnhp = (

8

1:

25

1)x 33 =1.32 4.125 (m).

Ta chn chiu cao dm h = 1.65m.

I.2.2. S dm v khong cch tim cc dm:

S dm v khong cch tim cc dm ca cu do s ln xe quyt nh. Chn 9dm v khong cch cc dm 2.250m. Phn hng tnh n mp lan can 1.35m.

I.2.3. dc dc cu.

Do tnh m quan cng trnh v trnh p t u cu qu ln cu c dcthay i nh sau:

Dc 4% cc nhp: 1, 2, 3, 4 (ln cu); 8, 9, 10, 11 (xung cu).

Dc 0% cc nhp: 5 ,6,7



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I.3. M t tm tt kt cu phn di:

Hai m cu cu to ging nhau, theo kiu m ch U bng BTCT. Thn m ttrn mng cc b thp BTCT Cc cc l cc khoan nhi c ng knh cc

1200mm.Tr: 10 tr ca cu c mt ct ging nhau, l loi tr thn hp , thn tr t

trn h mng cc b thp. Cc cc l cc khoan nhi c ng knh cc

1200mm.

I.4. Mt cu v cc cng trnh ph khc:

Bn mt cu BTCT dy 180mm.

Lp b tng to dc thay i t 0 110mm.

Lp ph mt cu xe chy dy 74 mm. Bao gm phng nc 4 mm ,lp btng nha 70 mm.

Mt cu c dc ngang 2.0 %.

H thng thot nc dng ng gang b tr dc cu thot nc xung gmcu.

Khe co gin loi 50mm.

Gi cu dng gi con ln BTCT.

Lan can trn cu dng lan can thp.



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I.5 . Vt liu ch to.

Vt liu dng cho kt cu phn trn

- B tng dm

+ Cp B tng :M400

+ Cng chu nn tui 28 ngy :fc = 40 Mpa

+ Trng lng ring ca b tng :c = 24.5 kN/m3

+ Modul n hi ca b tng :Es= 32980 Mpa+ H s Poisson : = 0.2

+ H s gin n nhit :c = 1.08E-05 1/oC

- B tng bn

+ Cp B tng :M350



+ Modul n hi ca b tng :Es= 30849.7 Mpa



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+ H s Poisson : = 0.2


- Thp

a. Thp d ng lc : Dng loi tao xon 7 si loiA416 cp 270 t chng thp

+ ng knh danh nh 1 tao :15.2 mm

+ Din tch danh nh mt tao cp :138.7 mm2

+ Trng lng danh nh 1 tao :0.1089kN/m

+ M un n hi :Ep=1975000 Mpa

+ Cng chu ko :f pu=1860 Mpa+ Gii hn chy :f py=1670 Mpa

+ Lc ko t nh nht 1 tao cp :260.4 kN

b. Thp thng

+ Cng chu ko :fu=620 Mpa

+ M un n hi:Es=200000 Mpa

+ Gii hn chy :fy=420 Mpa

Vt liu dng cho kt cu phn di

- B tng

+ Cp B tng :M300



+ Modul n hi ca b tng :Es= 28561.32Mpa



- Thp


+ M un n hi :Es=200000 Mpa


2mm

m

pE

puf

pyf

sR

sE

sR


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+ Gii hn chy:fy=420 Mpa

I.6 . Bin php thi cng.BIN PHP THI CNG M

bc 1: thi cng cc khoan nhi

- san i mt bng thi cng.

- xc nh tim cc ngoi hin trng.

- ng ng vch thp.

- khoan cc bng my khoan.

- thau ra l khoan, h ng thp.

- b tng cc.

- rt ng vch thp.

bc 2: o h mng

- o h mng tr.

- ri lp dm m dy 30 mm.

- b tng to phng dy 10 mm.

- x l u cc.

- th nghim cc.

bc 3: thi cng b cc, thn v tng cnh m

- lp t vn khun v ct thp b cc.

- b tng.

- lp t gio ct thp thi cng tng thn v tng cnh.

- lp t vn khun v ct thp.- b tng.

- di di thit b thi cng v vt t.

- dn dp khu vc thi cng.

BIN PHP THI CNG TR





sE


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- ng ng vch thp.



- b tng cc.- rt ng vch thp.

bc 2: o h mng

- o h mng tr.



- x l u cc.

- th nghim cc.bc 3: thi cng b v thn tr

- lp t vn khun v ct thp b tr.

- b tng.

- lp t gio ct thp thi cng cho tr.

- lp t vn khun v ct thp.

- b tng.

bc 4: thi cng x m tr

- lp t gio ct thp thi cng.

- lp t vn khun v ct thp x m tr.

- b tng.



BIN PHP THI CNG KT CU NHPbc 1: thi cng ng v chun b thit b lao dm

- chun b mt bng , vt t thit b xe my, lp t. ng di chuyn dm.

- lp t gi 3 chn v ng vn chuyn.

- vn chuyn dm super t t bi c ra u cu.

bc 2: lao dm super t nhp 1

- di chuyn gi lao dm ra kt cu tr 1.

- lao dm vo v tr nhp 1 v h dm xung gi.- c nh dm lao cc dm tip theo.



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CHNG III

PHNG N S B II CU DM GIN N BTCT

MT CT SUPER T

I.GII THIU CHUNG V CC PHNG N :

I.1. S b tr chung ca cu:

Da vo mt bng cu, kh thng xe, kh vt ng v mt ct a cht,ngi thit k a ra phng n cu dm gin n BTCT mt ct super T vi s cu nh sau: cu gm 9 nhp vi chiu di cc nhp b tr: 39.2 + 7 x 40 + 39.2m.

Chiu di ton cu Ltc = 368.4 m.

I.2. M t tm tt kt cu phn trn.

I.2.1. Chiu cao dm.

Chiu cao dm c chn theo yu cu sau:

+ Trng lng thp ca dn ch nh.

+ Bo m tnh khng thng xe v vt ng st.

+ m bo m quan v ph hp vi cnh quan khu vc xy cu.

Theo kinh nghim th i vi cu t, chiu cao dm c chn nh sau:

h = (8

1:

25

1)Lnhp = (

8

1:

25

1)x 40 =1.6 5 (m).

Ta chn chiu cao dm h = 1.75m.

I.2.2. S dm v khong cch tim cc dm:

S dm v khong cch tim cc dm ca cu do s ln xe quyt nh. Chn 9dm v khong cch cc dm 2.30m. Phn hng tnh n mp lan can 1.25m.

I.2.3. dc dc cu.

Do tnh m quan cng trnh v trnh p t u cu qu ln cu c dc

thay i nh sau: Dc 4% cc nhp: 1, 2, 3 (ln cu);7, 8, 9(xung cu).



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Dc 0% cc nhp: 4, 5 ,6

I.3. M t tm tt kt cu phn di:

Hai m cu cu to ging nhau, theo kiu m ch U bng BTCT. Thn m t

trn mng cc b thp BTCT Cc cc l cc khoan nhi c ng knh cc 1200mm.

Tr: 10 tr ca cu c mt ct ging nhau, l loi tr thn hp , thn tr t

trn h mng cc b thp. Cc cc l cc khoan nhi c ng knh cc 1200(mm).

I.4. Mt cu v cc cng trnh ph khc:

Bn mt cu BTCT dy 180mm.

Lp b tng to dc thay i t 0 110mm.

Lp ph mt cu xe chy dy 74 mm. Bao gm phng nc 4 mm ,lp btng nha 70 mm.

Mt cu c dc ngang 2.0 %.

H thng thot nc dng ng gang b tr dc cu thot nc xung gmcu.

Ton cu c 10 khe co gin loi 50mm.

Gi cu dng gi con ln BTCT.

Lan can trn cu dng lan can thp.



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I.5 . Vt liu ch to

Vt liu dng cho kt cu phn trn

- B tng dm

+ Cp B tng :M500



+ Modul n hi ca b tng :Es=36872.5 Mpa



- B tng bn

+ Cp B tng :M350




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+ Modul n hi ca b tng :Es= 30849.7 Mpa


+ H s gin n nhit :c = 1.08E-05

1/o

C- Thp

a. Thp d ng lc : Dng loi tao xon 7 si loiA416 cp 270 t chng thp

+ ng knh danh nh 1 tao :15.2 mm

+ Din tch danh nh mt tao cp :138.7 mm2

+ Trng lng danh nh 1 tao :0.1089kN/m+ M un n hi :Ep=1975000 Mpa

+ Cng chu ko :f pu=1860 Mpa

+ Gii hn chy :f py=1670 Mpa

+ Lc ko t nh nht 1 tao cp :260.4 kN

b. Thp thng


+ M un n hi :Es=200000 Mpa


Vt liu dng cho kt cu phn di

- B tng

+ Cp B tng :M300



+ Modul n hi ca b tng :Es= 28561.32Mpa



- Thp+ Cng chu ko :fu=6200 Mpa


2mm

m

pE

puf

pyf

sR

sE


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+ M un n hi:Es=200000 Mpa


I.6 . Bin php thi cng.

BIN PHP THI CNG M




- ng ng vch thp.



- b tng cc.

- rt ng vch thp.

bc 2: o h mng

- o h mng tr.



- x l u cc.

- th nghim cc.

bc 3: thi cng b cc, thn v tng cnh m

- lp t vn khun v ct thp b cc.

- b tng.

- lp t gio ct thp thi cng tng thn v tng cnh.- lp t vn khun v ct thp.

- b tng.



BIN PHP THI CNG TR




sR

sE


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- ng ng vch thp.


- thau ra l khoan, h ng thp.- b tng cc.

- rt ng vch thp.

bc 2: o h mng

- o h mng tr.



- x l u cc.- th nghim cc.

bc 3: thi cng b v thn tr

- lp t vn khun v ct thp b tr.

- b tng.

- lp t gio ct thp thi cng cho tr.

- lp t vn khun v ct thp.

- b tng.

bc 4: thi cng x m tr

- lp t gio ct thp thi cng.

- lp t vn khun v ct thp x m tr.

- b tng.


- dn dp khu vc thi cng.BIN PHP THI CNG KT CU NHP

bc 1: thi cng ng v chun b thit b lao dm

- chun b mt bng , vt t thit b xe my, lp t. ng di chuyn dm.

- lp t gi 3 chn v ng vn chuyn.

- vn chuyn dm super t t bi c ra u cu.

bc 2: lao dm super t nhp 1

- di chuyn gi lao dm ra kt cu tr 1.- lao dm vo v tr nhp 1 v h dm xung gi.



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- c nh dm lao cc dm tip theo.

- sau khi lao dm xong tin hnh thi cng cc lin kt, dm ngang.

bc 3: lao dm ti cc nhp khc- y gi 3 chn ti v tr nhp 2.

- di chuyn dm n u nhp 2.

- lao dm vo v tr.

- h dm xung gi ca nhp 2.

- sau khi thi cng nhp 2 tin hnh thi cng cc nhp tip theo.

bc 4: hon thin cu

- di di thit b thi cng v vt t.- b tng bn mt cu, g chn, lan can.

- thi cng lp ph mt cu.

- lp t khe co gin.

- lp t h thng thot nc.



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CHNGIII

SO SNH LA CHN PHNG N

la chn mt phng n tt nht ta phi tin hnh so snh chng v cc chtiu Kinh T K Thut M Quan v iu kin duy tu bo dng cng nh khaithc kh nng ca chng.

V Kinh T

a. Cu dm Super T

Nh tnh ton trong phn thit k s b ta c :

Khi lng btng ca 5 dm ch trong 1 nhp : 30.0898 m3

Khi lng btng ca dm ngang trong 1 nhp : 35,2m

b. Cu dm mt ct ch I

Do ch l phng n s b nn khng tnh chi tit phn ny

V K Thut

a. Cu dm Super T

Thi cng kt cu nhp bng gi 3 chn : u im ca n l thi cng rt an tonnhng cng knh v kh phc tp.

Bn cnh dm cng to sn cng tc cho cc cng vic di mt cu ngay saukhi dm c t vo v tr, to s an ton cho cng nhn.

b. Cu dm mt ct ch I

V M Quan

a. Cu dm Super T

Dm c dng mt y dng dm hp vi t gc cnh nn c xem nh tngng vi cc dm hp hay bn c l c ti ch ang c a chung. y ccnhp v x m lin tc to hiu qu cao v m quan.

Ngoi ra n cn c nhiu u im v kh nng s dng nh : giao thng m

thun, trnh c ting n.b. Cu dm mt ct ch I



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V duy tu bo dng

a. Cu dm Super T

Ngy nay chng ta hiu BTCT v BTCT d ng lc l loi vt liu l tng ckh nng cnh tranh vi thp trong lnh vc xy dng ni chung v trong xy dngcu ni ring. Tnh bn c hc ca btng tuy c thua km thp nhng btng lic kh nng chu mi tt, c kh nng chng li cc tc ng ca mi trng tthn thp nn trong qu trnh s dng trnh c chi ph duy tu bo dng

b. Cu dm mt ct ch I



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PHN II

THIT K K THUT



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I. S LI U THIT K

Chiu di ton dm L = 38.3 m

Khong cch t u dm n

tim gi a = 0.35 mKhu tnh ton Ltt = L-2a 37.6 m

Ti trng thit k Hoat ti HL - 93

Ti trng ngi 3Kpa

Mt xe chy: B1 = 6.8 m

L ngi i B2 = 1.9 m

Lan can B3 = 0.5 m

Di phn cch B4 = 0.2 mTng b rng cu B=B1+2.B2+2.B3+2.B4 B = 12 m

Dng kt cu nh p Cu dm

Dng mt ct Super T

Vt liu kt cu BTCT d ng lc

Cng ngh ch to Cng trc

Cp b tng D m chu f'c1= 50 Mpa

Bn mt cu f'c2= 32 Mpa

T trng b tng c= 2450 kg/m3

Loi ct th p DUL: tao thpTao 7

si xon ng knh Dps = 15.2 mm

Cng chu ko tiu chun fpu = 1860 Mpa

Thp thng G60 f u = 620 Mpafy = 420 Mpa

Quy trnh thit k 22TCVN 272-05



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II. THIT K CU TAO

2.1. La chn kch thc mt ct ngang cu

S lng dm ch 12 12 6 4.82.5 2 2 2.5

B Bn n nm m

chn n= 5 dm

Khong cch gia hai dm ch S = 2300 mm

L ngi i ng mc vi mt cu phn xe chy, v c ngn cch vi nhaubng g phn cch

B tr dm ngang ti cc v tr gi cu: 2 mt ct

S lng dm ngang: Nn=(Nb-1).2 Nn= 8 dm

Phn cnh hng: Sk=(B-(Nb-1)S-0.15*2)/2 Sk= 1.25 mChiu dy trung bnh ca bn hf= 18 cm

L p BT atphal t1= 70 mm

Lp phng nc t2= 4 mm

2.2. Thit k dm ch

on ct khc: Lck= 800 mm

on dm c: Ldac= 1200 mm

Chn chiu cao dm ch H

38.30.045 0.045 38.3 1.72 2.13

18 18

L L H x H m H m

Chn H = 1.75m = 1750mm

2.2.1.Mt ct ngang dm trn gi

Chiu cao dm SuperT: H'= 800 mm

B rng bu dm di b'1= 890 mm



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Chiu cao cnh dm h1= 75 mm

Chiu cao vt trn h2= 75 mm

B rng vt trn b8= 100 mm

B rng cnh dm b2= 1220 mm

2.2.2.Mt ct ngang dm c

Chiu cao dm Super T H= 1750 mm

B rng bu dm di b1= 700 mm

Chiu cao cnh dm h1= 75 mm

Chiu cao vt trn h2= 75 mm

B rng vt trn b8= 100 mm

B rng cnh dm b2= 2260 mm



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Vh= 50 mm

Vb= 25 mm

2.3. Cu to dm ngang

Chiu cao dm ngang: Hnd=H'= 800 mm

B dy dm ngang: tdn=Lck= 800 mm

Chiu di dm ngang: a'dn= 1080 mm

a_dn= 1410 mm

B rng vt trn avdn= 100 mm

Cao vt trn: hvdn= 75 mmDin tch mt ct dm ngang: Adn 0.6278 m2



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III. TINH C TRNG HNH HOC DM SUPER-T

Xt mt ct c trng gm:

Mt ct gi : x0= 0 m

Mt ct ti ch thay i tit din: x1= 1.44 mM ct khng dnh bm 1: x2= 3 m

Mt ct khng dnh bm 2: x3= 6 m

Mt ct L/2: x4=Ltt/218.8 m

Trong qu trnh tnh ton ta s qui i tit din Sper-T v tit din n gin hn thun tin cho vic tnh ton

3.1. Mt ct trn gi x0

3.1.1.Tit din nguyn khi:Tnim X Y Xi - Xi+1 Yi + Yi+1 Yi*Yi+1 Fi Yi Ji

0 0 0

1 -0.61 0 0.61 0 0 0 0 0

2 -0.61 -0.075 0 -0.075 0 0 0 0

3 -0.51 -0.15 -0.1 -0.225 0.01125 0.0225 -0.0039 0.00063

4 -0.445 -0.8 -0.065 -0.95 0.12 0.06175 -0.0509 0.040915 0.445 -0.8 -0.89 -1.6 0.64 1.424 -1.7088 1.82272



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6 0.51 -0.15 -0.065 -0.95 0.12 0.06175 -0.0509 0.04091

7 0.61 -0.075 -0.1 -0.225 0.01125 0.0225 -0.0039 0.00063

8 0.61 0 0 -0.075 0 0 0 0

9 0 0 0.61 0 0 0 0 010 0 0 0 0 0 0 0 0

SUM 1.5925 -1.8184 1.9058

Din tch mt ct :F= 0.796 m2

Ta trng tm mt ct so vi th trn dm

0.381 m

Ta trng tm mt ct so vi th di dm

Yc= 0.419 m3

M men tnh ca mt ct i vi trc y dm

Sx= 0.124 m3

M men qun tnh ca mt ct i vi trc X :

Jx = 0.159 m4

M men qun tnh i vi trc trung ha :

Jthx = 0.043 m4

Din tch ca tit din lin hp:

2 1 20 0 . . 0.796 0.8 2.3 0.18 1.1272

cbang g f

cdam

EA A S h x x m

E= + = + =

Trong :



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T trng ca b tng 32450 /c kg m =

Cng chu nn ca b tng lm bn mt cu fc = 32 MPa

Mun n hi ca bn mt cu:

1.5 ' 1.50.043 0.043.2450 . 32 29498cban c cb E f MPa= = =

Cng chu nn ca b tng lm dm fc = 32 MPa

Mun n hi ca bn mt cu:

1.5 ' 1.50.043 0.043.2450 . 50 36872.5cdam c cd E f MPa= = =

294980.8

36872.5cban

cdam

E

E= =

3.2. Mt ct ti ch thay i tit din X1:3.2.1. Tit din nguyn khi:

BNG TNH CC C TRNG CHO DM

Tn im X Y Xi - Xi+1 Yi + Yi+1 Yi*Yi+1 Fi Yi Ji

0 0

1 -1.13 0 1.13 0 0 0 0 0

2 -1.13 -0.075 0 -0.075 0 0 0 0

3 -0.61-0.075 -0.52 -0.15 0.00563 0.078 -0.0088 0.00088

4 -0.51 -0.15 -0.1 -0.225 0.01125 0.0225 -0.0039 0.00063

5 -0.35 -1.75 -0.16 -1.9 0.2625 0.304 -0.5356 0.937846 0.35 -1.75 -0.7 -3.5 3.0625 2.45 -6.4313 15.0063



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7 0.51 -0.15 -0.16 -1.9 0.2625 0.304 -0.5356 0.93784

8 0.61-0.075 -0.1 -0.225 0.01125 0.0225 -0.0039 0.00063

9 1.13-0.075 -0.52 -0.15 0.00563 0.078 -0.0088 0.00088

10 1.13 0 0 -0.075 0 0 0 011 0 0 1.13 0 0 0 0 0

SUM 3.259 -7.5279 16.885

Din tch mt ct :

F= 1.630 m2

Ta trng tm mt ct :

0.770 m


Yc= 0.980 m3

M men tnh ca mt ct i vi trc X :

Sx= 1.597 m3


Jx = 1.407 m4

M men qun tnh i vi trc trung ha :Jthx = 0.441 m4

3.2.2.Tit din lin h p



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Din tch tit din lin hp:

2 1 21 1 . . 1.630 0.8 2.3 0.18 1.9612

cbang g f

cdam

EA A S h x x m

E= + = + =

3.3. Mt ct gia nhp X4:3.3.1. Tit din nguyn khi:

BNG TNH CC C TRNG CHO DM

Tn im X Y Xi - Xi+1 Yi + Yi+1 Yi*Yi+1 Fi Yi Ji

0 0 0

1 0 -0.075 0 -0.075 0 0 0 02 0.52 -0.075 -0.52 -0.15 0.00563 0.078 -0.0088 0.00088

3 0.62 -0.15 -0.1 -0.225 0.01125 0.0225 -0.0039 0.00063

4 0.78 -1.75 -0.16 -1.9 0.2625 0.304 -0.5356 0.93784

5 1.48 -1.75 -0.7 -3.5 3.0625 2.45 -6.4313 15.0063

6 1.64 -0.15 -0.16 -1.9 0.2625 0.304 -0.5356 0.93784

7 1.74 -0.075 -0.1 -0.225 0.01125 0.0225 -0.0039 0.00063

8 2.26 -0.075 -0.52 -0.15 0.00563 0.078 -0.0088 0.000889 2.26 0 0 -0.075 0 0 0 0



37/127


10 1.54 0 0.72 0 0 0 0 0

11 1.54 -0.05 0 -0.05 0 0 0 0

12 1.515 -0.05 0.025 -0.1 0.0025 -0.0025 0.00019 -1E-05

13 1.515 -0.3 0 -0.35 0.015 0 0 014 1.4275 -1.175 0.0875 -1.475 0.3525 -0.1291 0.15952 -0.1898

15 1.345 -1.475 0.0825 -2.65 1.73313 -0.2186 0.43637 -0.7775

16 1.13 -1.525 0.215 -3 2.24938 -0.645 1.45138 -2.9033

17 0.915 -1.475 0.215 -3 2.24938 -0.645 1.45138 -2.9033

18 0.8325 -1.175 0.0825 -2.65 1.73313 -0.2186 0.43637 -0.7775

19 0.745 -0.3 0.0875 -1.475 0.3525 -0.1291 0.15952 -0.1898

20 0.745 -0.05 0 -0.35 0.015 0 0 021 0.72 -0.05 0.025 -0.1 0.0025 -0.0025 0.00019 -1E-05

22 0.72 0 0 -0.05 0 0 0 0

23 0 0 0.72 0 0 0 0 0

SUM 1.26863 -3.4329 9.14374

Din tch mt ct :F= 0.6343125000 m2

Ta trng tm mt ct :

0.9020100503 m


Yc= 0.848 m3

M men tnh ca mt ct i vi trc y dm

Sx= 0.538 m3




38/127


Jx = 0.7619781445 m4

M men qun tnh i vi trc trung ha :

Jthx = 0.2458874567 m4

3.3.2.Tit din lin h p

Din tch tit din lin hp:

2 1

4 4 . . 0.6343 0.8 2.3 0.18 0.9655cban

g g f

cdam

E A A S h x x

E= + = + =



39/127


IV. TNH H S PHN B TAI TRONG

4.1. H s phn lnS ln xe thit k:

11

1

1

73.5

2 6 7 2

1 6lan

BB m

m

m B m n

B m

< =

4.2. H s phn b hot ti theo ln i vi mmen4.2.1.H s phn b hot ti i vi mmen trong cc dm gia

Kim tra h s phn b tha mn tiu chun 22TCN - 272 -05 i vi phm vi p

dng ca phng php tra bngGA TR(mm) PHAM VI P DNG KIM TRA

S= 2300 1800 3500( )S mm THA

H= 1750 450 1700( ) H mm KHNG THA

Ltt= 37600 6000 73000( )tt L mm THA

Nb= 5 3bN THA

Kt lun: Khng nm trong phm vi p dng

=> Phi dng phng php n by

4.2.1.1.Phng php on by:



40/127


* Vi 1 xe ti thit k

' '

1 2

900 2300 900.1 .1 0.6087

2300

Sy y

S

= = = =

. '

1 2

1 1( . ) . ( ) 1.2 (0.6087) 2 0.7304

2 2

SI

M LL lanm g m y y x x x = + = =

* Vi 2 xe ti thit k

'

3

1800 2300 1800.1 .1 0.2174

2300

Sy

S

= = =

'

4 1y =

'

5

1200 2300 1200.1 .1 0.4783

2300

Sy

S

= = =

'

6 0y =

. ' ' '

3 4 5 6

1 1( . ) . ( ) 1 (0.2174 1 0.3913 0) 0.42394 4

MI

M LL lanm g m y y y y x x = + + + = + + + =

( )( . ) max ( . ) , ( . ) max(0.7304,0.4239) 0.7304I SI MI M LL M LL M LLm g m g m g = = =

* Vi ti trng ln:

Thin v an ton coi ti trng ln theo phng ngang cu l ti trng t p trung.

( . ) 1.2 1 1.2IM la nm g = =

4.2.1.2.La chn h s phn b mmen thit k



41/127


( )( . ) max ( . ) , ( . ) 0.7304I IM M M LLm g m g m g = =

( )( . ) max ( . ) , ( ) 1.2I IM lan M M lanm g m g mg = =

4.2.2.H s phn b hot ti i vi mmen ca dm bin

4.2.2.1.Vi 1 lan thit k: s dng phng php on by tnh

Xt cho xe ti thit k v xe hai trc: v khong cch ca hai trc bnh xe theophng ngang ca hai loi xe ny l nh nhau nn c chung mt h s phn b ngang

Phng trnh tung ng nh hng: ( )dbx

y xS

=

Mt ln thit k => h s ln m = 1.2

* Vi xe ti thit k:

4 3 25150 600 2300 1250 150 200 500 1900 600

0.21742300

kS S B B ByS

+ + + + = = =

6 0y =

4 51 1 1

( . ) . 1.2 ( ) 1.2 (0.2174 0) 0.13042 2 2

SE

M LL im g m y y y x x = = + = + =

* Vi ti trng ngi i

31

150 2300 1250 150 500 1.39132300

kS S ByS

+ + + + = = =



42/127


3 23

150 2300 1250 150 500 19000.5652

2300

kS S B ByS

+ + + + = = =

B2=1.9m

221 2 1.9( ) (1.3913 0.5652) 1.8587

2 2M PL B y y x m = + = + =

2

1.2( . ) . 1.8587 1.1739

1.9SEM PL M PL

mm g x

B = = =

* Vi ti trng ln:

3 2 43

150 2300 1250 150 200 500 19000.4783

2300

kS S B B ByS

+ + + + = = =

3 2 43150

2

2300 1250 150 200 500 19000.4783 263.065

2

kM L an S S B B B y

x

+ + =

+ + = =

1.2( . ) . 263.065 0.1052

3000 3000

SE

M lan M Lam

mm g x = = =

4.2.2.2. Vi hai hoc nhiu lan thit k:

Khong cch t tim dm bin n mp trong b va hoc lan can chn xe

4 3 2150 1250 150 200 500 1900 1200

e kd S B B B mm= + = + =

* Phm vi p dng:

GA TR(mm) PHM VI P DNG KIM TRA

S= 2300 1800 3500( )S mm THA

de= -1200 0 1400( )ed mm KHNG THA

Kt lun: Khng nm trong phm vi p dng=> Khng s dng cng thc tra bng

4.2.2.3.La chn h s phn b mmen thit k

Ta s dng h s phn b ngang trong trng hp 1 ln theo phng php n by thit k

( . ) 0.1304SEM LLm g =

( . ) 1.1739

SE

M PLm g

=

( . ) 0.1052SEM L AN

m g =



43/127


4.3. H s phn b hot ti theo ln i vi lc ct4.3.1.H s phn b hot ti i vi lc ct trong cc dm gia

Kim tra h s phn b tha mn tiu chun 22TCN - 272 -05 i vi phm vi pdng ca phng php tra bng


S= 2300 1800 3500( )S mm THA

H= 1750 450 1700( ) H mm KHNG THA

Ltt= 37600 6000 73000( )tt L mm THA

Nb= 5 3bN THA


=> Phi dng phng php n by

4.3.1.2.Phng php on by:

* Vi 1 xe ti thit k

' '

1 2

900 2300 900.1 .1 0.6087

2300

Sy y

S

= = = =

. '

1 2

1 1( . ) . ( ) 1.2 (0.6087) 2 0.7304

2 2

SI

M LL lanm g m y y x x x = + = =

* Vi 2 xe ti thit k



44/127


'

3

1800 2300 1800.1 .1 0.2174

2300

Sy

S

= = =

'

4 1y =

'5 1200 2300 1200.1 .1 0.4783

2300Sy

S = = =

'

6 0y =

. ' ' '

3 4 5 6

1 1( . ) . ( ) 1 (0.2174 1 0.3913 0) 0.4239

4 4

MI

M LL lanm g m y y y y x x = + + + = + + + =

( )( . ) max ( . ) , ( . ) max(0.7304,0.4239) 0.7304I SI MI M LL M LL M LLm g m g m g = = =

* Vi ti trng ln:

Thin v an ton coi ti trng ln theo phng ngang cu l ti trng t p trung.

( . ) 1.2 1 1.2IM l anm g = =

4.3.1.3.La chn h s phn b lc ct thit k

( )( . ) max ( . ) , ( . ) 0.7304I IM M M LLm g m g m g = =

( )( . ) max ( . ) , ( ) 1.2I IM lan M M lanm g m g mg = =

4.3.2.H s phn b hot ti i vi lc ct ca dm bin4.3.2.1.Vi 1 lan thit k: s dng phng php on by tnh

Xt cho xe ti thit k v xe hai trc: v khong cch ca hai trc bnh xe theophng ngang ca hai loi xe ny l nh nhau nn c chung mt h s phn b ngang



45/127


Phng trnh tung ng nh hng: ( )dbx

y xS

=

Mt ln thit k => h s ln m = 1.2

* Vi xe ti thit k:

4 3 25

150 600

2300 1250 150 200 500 1900 6000.2174

2300

kS S B B B

yS

+ + =

+ + = =

6 0y =

4 5

1 1 1( . ) . 1.2 ( ) 1.2 (0.2174 0) 0.1304

2 2 2

SE

M LL im g m y y y x x = = + = + =

* Vi ti trng ngi i

31

150 2300 1250 150 5001.3913

2300

kS S ByS

+ + + + = = =

3 23

150 2300 1250 150 500 19000.5652

2300

kS S B ByS

+ + + + = = =

B2=1.9m

221 2

1.9( ) (1.3913 0.5652) 1.8587

2 2

M PL

B y y x m = + = + =



46/127


2

1.2( . ) . 1.8587 1.1739

1.9SEM PL M PL

mm g x

B = = =

* Vi ti trng ln:

3 2 43

150 2300 1250 150 200 500 1900 0.47832300

kS S B B ByS

+ + + + = = =

3 2 43

150 2300 1250 150 200 500 19000.4783 263.065

2 2

kM L an

S S B B By x

+ + + + = = =

1.2( . ) . 263.065 0.1052

3000 3000

SE

M lan M Lam

mm g x = = =

4.3.2.2. Vi hai hoc nhiu lan thit k:

Khong cch t tim dm bin n mp trong b va hoc lan can chn xe de

4 3 2150 1250 150 200 500 1900 1200e kd S B B B mm= + = + =

* Phm vi p dng:


S= 2300 1800 3500( )S mm THA

de= -1200 0 1400( )ed mm KHNG THA


=> Khng s dng cng thc tra bng

4.3.2.3.La chn h s phn b lc ct thit k

Ta s dng h s phn b ngang trong trng hp 1 ln theo phng php n by thit k

( . ) 0.1304SEM LLm g =

( . ) 1.1739SEM PLm g =

( . ) 0.1052SEM L AN m g =

BNG TNG HP H S PHN B NGANG

V tr Ni lc Ti trng xe Ti trng ln Ti trng ngi

Dm gia

Mmen 0.73 1.2 0

Lc ct 0.73 1.2 0



47/127


Dm binMmen 0.13 0.105 1.174

Lc ct 0.13 0.105 1.174

4.4. H s iu chinh t trngH s deo 1D = i vi cc b phn v lin kt thng thng

H s d tha 1R = i vi mc d tha thng thng

H s quan trng 1.05I = Cu thit k l quan trng

H s iu chnh ca ti trng

. . 1.05 0.95 D R I

= = >



48/127


V. XC NH NI LC TA I CC MT CT C TRNG

5.1. Tnh ti tc dng ln 1 dm chu.5.1.1.Tnh ti dm ch

+ Xt on dm ct khc:

Din tch tit din 1 20 0.796gA m=

T trng b tng dm ch 32450 /c kN m =

Trng lng on dm 10 0. . .2 2450 0.796 0.8 2 3120.32d c g ck DC A L x x x kg = = =

+ Xt on dm c:

Din tch tit din1 2

1 1.630gA m=

Trng lng on dm 11 1. . .2 2450 1.630 1.2 2 9584.4d c g dac DC A L x x x= = =

+ Xt on dm cn li:

Din tch tit din 1 24 0.6343gA m=

Trng lng on dm

[ ] ( )1 4. . ( ).2 2450 0.6343 38.3 0.8 1.2 2 53303.4d c g ck dacDC A L L L x x x kg + = = + =

5.1.2.Tnh ti vch ngn

Vi dm c chiu di 38.3 m, ta dng 2 vch ng mng dy 15cm chia dm lm3 khoang, mi khoang di 12.67m. Vch ngn ny c tc dng tng n nh khi culp dm.

S vch ngn: 2

B dy vch ngn: 0.15m

Din tch vch ngn theo phng dc cu

1 1 2

1 4 7. 1.630 0.6343 0.05 0.82 0.9547vn g g h A A A V b x m= = =

Trng lng vch ngn

. . . 2450 0.9547 0.15 2 701.7vn c vn vn vn

DC A t N x x x kg = = =

+ Tnh ti dm ch coi l ti trng ri u sut chiu di dm

0 1 3120.32 9584.4 53303.4 701.7 1741.7738.3

d d d vndc

DC DC DC DC DC

L

+ + + + + += = =

5.1.3.Tnh ti bn mt cu



49/127


+ Dm gia:

Din tch tit din 2. 2.3 0.18 0.414bmg f A S h x m= = =

T trng b tng bn mt cu 32450 /c kg m =

Trng lng bn mt cu dm gia

. 2450 0.414 1014.3 /bmg c bmg DC A x kg m= = =

+ Dm bin :

Din tch tit din

22.3. ( 1.25) 0.18 0.4322 2bmb k f S

A S h x m = + = + =

Trng lng bn mt cu dm gia

. 2450 0.432 1058.4 /bmb c bmb DC A kg m= = =

5.1.4.Tnh ti dm ngang

Din tch mt ct dm ngang And = 0.6278 m2

Trng lng dm ngang

( . ). 0.6278 0.8 8. 2450 51.404 /

. 5 38.3

dn dn ndn c

b

A t N x xDC x kg m

N L x

= = =

5.1.5.Tnh ti vn khun lp ghp

Chiu di vn khun theo phng ngang 7 0.82vkb b m= =

B dy vn khun 0.05vk hh V m= = =0.05m

Trng lng vn khun trn 1m di dc cu

. . 2450 0.82 0.05 100.45 /vk c vk vk DC b h x x kg m= = =

5.1.6.Tnh ti lan can5.1.6.1. Lan can c tay vn

Phn thp c trng lng

16 /tlc

DC kg m=

Chiu cao lan can 0.3lch m=

Phn b tng 3. . 0.5 0.3 2450 367.5 /btlc lc c DC B h x x kg m= = =

Trng lng lan can c tay vn 16 367.5 383.5 /lc tlc btlc DC DC DC kg m= + = + =

* Trng lng lan can do dm bin chu



50/127


2300 12501.5435

` 2300

klcb

S Sy

S

+ += = =

. 383.5 1.5435 591.93 /lcb lc lcb DC DC y x kg m= = =

0lcgy =

. 0lcg lc lcg DC DC y= =

5.1.6.2. G chn

Chiu cao g chn 300 0.3gch mm m= =

Trng lng g chn . 2450 0.3 0.2 147 / gc c gc DC A x x kg m= = =

5.1.7. Tnh ti lp ph m t cu v tin ch cng cng (DW)

*Lp ph

Chiu dy lp b tng Asphal 1 70 0.07t mm m= =

T trng b tng Asphal 1 2250 /kg m =

*Lp phong nc

Chiu dy lp phng nc 2 4mm 0.004mt = =

T trng lp phng nc 32 1800kg / m =



51/127


Tng trng lng lp ph mt cu

1 1 2 2( ) (0.07 2250 0.004 1800) 2.3 378.81kg / m

ti DW xt xt xS x x x = + = + =

*Trng lng tin ch v trang thit b trn cu

0 /lp DW kg m=

378.81 /ti lp DW DW DW kg m= + = =378.81kg/m

* Trng lng DW do dm bin chu

3 4. 0.152

lp

b k ti

DW S DW S B B DW

S

= + + +

378.81 2300(1250 150 200 500 ) 0 304.695kg/m

2300 2= + + + =

* Trng lng DW do dm gia chu

378.81 /g DW DW kg m= =

5.1.8.Tng cng tnh ti tc dng ln cc dm dc ch

5.1.8.1.Dm gia

+ Giai on cha lin hp bn mt cu

0 1 1741.74 /d d d vndc DC DC DC DC

DC kg mL

+ + += =

+ Giai on khai thc: bn mt cu:

2889.58 / g dc bmg dn lcg vk vn DC DC DC DC DC DC DC kg = + + + + + =

378.81 /g DW DW kg m= =

5.1.8.2.Dm binGiai on cha lin hp bn mt cu



52/127


0 1 1741.74 /d d d vndc DC DC DC DC

DC kg mL

+ + += =

Giai on khai thc: bn mt cu:

3672.42 /b dc bmb dn lcb gc vk vn

DC DC DC DC DC DC DC DC kg m= + + + + + + =

304.695 /b DW kg m=

5.2. Hot ti HL935.2.1.Xe ti thit k:

Xe ti thit k: gm trc trc nng 35KN, hai trc sau mi trc nng 145KN,khong cch gia hai trc trc l 4300mm, khong cch hai trc sau thay i t 4300 -9000mm sao cho gy ra ni lc ln nht, Theo phng ngang khong cch gia hai bnh

xe l 1800mm

5.2.2.Xe hai trc thit k:

Xe hai trc thit k gm c hai trc, mi trc nng 110K, khong cch gia haitrc khng i l 1200mm, theo phng ngang khong cch gia hai bnh xe l 1800mm



53/127


5.2.3.Ti trng ln:

Ti trng ln bao gm ti trng ri u 9.3N/m. xp theo phng dc cu , theophng ngang cu ti trng ln phn b theo chiu rng 3000mm, ti trng ln c th xdch theo phng ngang gy ra ni lc ln nht.

5.2.4. Ti trng ngi i b:

L ti trng phn b c qui nh ln l 3E-03 Mpa.

5.2.5. Ti trng xung kch:

L ti trng ln vo ti trng xe 3 trc hay xe 2 trc ly bng 25% ti trng ca mixe.

5.3. ng nh hng mmen v lc ct ti cc mt ct c trng

5.3.1. Xc nh cc mt ct c trng

Mt ct gi: x0= 0 m

Mt ct ti ch thay i tit din: x1= 1.65 m

M ct khng dnh bm 1: x2= 3 m

Mt ct khng dnh bm 2: x3= 6 m

Mt ct L/2: x4=Ltt/2 18.8 m

5.3.2.Xc nh ng nh hng ni lc ti cc mt ct

5.3.2.1.Phng trinh ng anh hng



54/127


* Phng trnh ng nh hng mmen ti mt ct Xknh sau:+ Trn on X = 0 -> Xk

1( , ) .tt k

M ktt

L Xf X X X

L

=

+ Trn on x = Xk-> Ltt

2 ( , ) ( )k

M k tt tt

Xf X X L X

L=

+ Din tch ng nh hng mmen ti Xk

1( , )

2Mk tt M k k L y X X =

* Phng trnh ng nh hng lc ct

+ Trn on X=0 -> Xk

1( , )V ktt

X f X X

L

=

+ Trn on x = Xk-> Ltt

2 ( , ) 1V ktt

X f X X

L=

+ Din tch ng nh hng lc ct ti Xk

Phn h dng:

2

1( ). ( , )

2

Vkd tt k V k k L X f X X =

Phn h m:



55/127


1

1. ( , )

2Vka k V k k

X f X X =

Tng din tch h:

Vk Vkd Vka

= +5.3.2.2.Ti mt ct c trng th 0 ( mt ct gi)

X = Xk= X0 = 0m

1

0

37.6 0( , ) ( , ) . 0 0

37.6

1( , ) 0

2

tt kM k k M k

tt

M tt M k k

L Xy X X f X X X x

L

L y X X

= = = =

= =

1

0 2

( , ) ( , ) 1

1 1( ). ( , ) (37.6 0) 18.8

2 2

tt

V k k V k tt

V tt k V k k

L X

y X X f X X L

L X f X X x

+

+

= = =

= = =

1 0

1( , ) ( , ) 0 0.0 0

2V k k V k V tt

Xy X X f X X x

L

= = = =

5.3.2.3.Ti mt ct c trng th 1

X = Xk= X1 =1.44m



56/127


1

0

37.6 1.44( , ) ( , ) . 1.44 1.385

37.6

1 1( , ) 37.6 1.385 26.035

2 2

tt kM k k M k

tt

M tt M k k

L Xy X X f X X X x

L

L y X X x x

= = = =

= = =

1

0 2

1.44 37.6 1.44( , ) ( , ) 0.962

37.6

1 1( ). ( , ) (37.6 1.44) 0.962 17.388

2 2

ttV k k V k

tt

V tt k V k k

L y X X f X X

L

L X f X X x x

+

+

= = = =

= = =

1 0

1.44 1( , ) ( , ) 0.0383 1.44 ( 0.0383) 0.0276

37.6 2V k k V k V tt

Xy X X f X X x x

L

= = = = = =


X = Xk= X2 =3 m

1

0

37.6 3( , ) ( , ) . 3 2.76

37.6

1 1( , ) 37.6 2.761 51.9

2 2

tt kM k k M k

tt

M tt M k k

L X y X X f X X X x

L

L y X X x x

= = = =

= = =

1

0 2

3 37.6 3( , ) ( , ) 0.920

37.6

1 1

( ). ( , ) (37.6 3) 0.920 15.922 2

ttV k k V k

tt

V tt k V k k

Ly X X f X X

L

L X f X X x x

+

+

= = = =

= = =

1 0

3 1( , ) ( , ) 0.0798 3 ( 0.0798) 0.1197


Xy X X f X X x x

L

= = = = = =


X = Xk= X3 =6 m



57/127


1

0

37.6 6( , ) ( , ) . 6 5.04

37.6

1 1( , ) 37.6 5.04 94.8

2 2

tt kM k k M k

tt

M tt M k k

L Xy X X f X X X x

L

L y X X x x

= = = =

= = =

1

0 2

3 37.6 6( , ) ( , ) 0.840

37.6

1 1( ). ( , ) (37.6 6) 0.840 13.28

2 2

ttV k k V k

tt

V tt k V k k

Ly X X f X X

L

L X f X X x x

+

+

= = = =

= = =

1 0

6 1( , ) ( , ) 0.1596 6 ( 0.1596) 0.479


Xy X X f X X x x

L

= = = = = =


X = Xk= X4 =18.8 m

1

0

37.6 18.8( , ) ( , ) . 18.8 9.4

37.6

1 1( , ) 37.6 9.4 176.72

2 2

tt kM k k M k

tt

M tt M k k

L X y X X f X X X x

L

L y X X x x

= = = =

= = =



58/127


1

0 2

18.8 37.6 18.8( , ) ( , ) 0.5

37.6

1 1( ). ( , ) (37.6 18.8) 0.5 4.7

2 2

ttV k k V k

tt

V tt k V k k

Ly X X f X X

L

L X f X X x x

+

+

= = = =

= = =

1 018.8 1( , ) ( , ) 0.5 18.8 ( 0.5) 4.7


Xy X X f X X x xL

= = = = = =

5.3.3.Bng tng h p din tch ng nh hng ti cc mt ct c trng

M

V + V V

X0 0.00 0.00 18.8 18.80

X1 26.04 -0.03 17.39 17.36X2 51.90 -0.12 15.92 15.80

X3 94.80 -0.48 13.28 12.80

X4 176.72 -4.70 4.7 0.00

5.4. Tnh ni lc do tnh ti tc dng ln dm gia v dm binCng thc tnh l ly gi tr ti trng nhn vi din tch ng nh hng ti mt ct

ang xt. Ta tnh ni lc ti cc mt ct nh sau:5.4.1.Mmen do tnh ti tc dng ln dm bin

5.4.1.1.Giai on cha ban b tng

. . ( . ) DCdc dc M M DC g kN m=

Mt ct M dcDC . . ( . ) DCdc dc M M DC g kN m=

X0 0.00 1741.74 0

X1 26.04 1741.74 440.25

X2 51.90 1741.74 877.46

X3 94.80 1741.74 1602.77

X4 176.72 1741.74 2987.77

5.4.1.2.Giai on a ban b tng

. . ( . )

. . ( . )

DCb b M

DWb b M

M DC g kN m

M DW g kN m

==



59/127


Mt ct M bDC bDW DCbM DWbM

X0 0.00 2889.58 378.81 0.00 0.00

X1 26.04 2889.58 378.81 738.15 96.77

X2 51.90 2889.58 378.81 1471.20 192.87X3 94.80 2889.58 378.81 2687.27 352.29

X4 176.72 2889.58 378.81 5009.44 656.71

5.4.2.Mmen do tnh ti tc dng ln dm gia


. . ( / ) DCdc dc M M DC g kN m=

Mt ct M dcDC . . ( / ) DCdc dc M M DC g kN m=

X0 0 1741.74 0.00

X1 26.04 1741.74 440.25

X2 51.9 1741.74 877.46

X3 94.8 1741.74 1602.77

X4 176.72 1741.74 2987.77


. . ( / )

. . ( / )

DCb g M

DWb g M

M DC g kN m

M DW g kN m

=

=

Mt ct M gDC gDW DCgM DWgM

X0 0.00 2889.58 378.81 0.00 0.00

X1 26.04 2889.58 378.81 738.15 96.77

X2 51.90 2889.58 378.81 1471.20 192.87

X3 94.80 2889.58 378.81 2687.27 352.29

X4 176.72 2889.58 378.81 5009.44 656.71

5.4.3.Lc ct do tnh ti tc dng ln dm bin

5.4.3.1.Giai on cha ban b tng. . ( . ) DCdc dc V V DC g kN m=



60/127


Mt ct V dcDC DCdcV

X0 18.80 1741.74 317.85

X1 17.36 1741.74 293.50

X2 15.80 1741.74 267.13X3 12.80 1741.74 216.41

X4 0.00 1741.74 0.00


. . ( . )

. . ( . )

DCb b M

DWb b M

M DC g V kN m

M DW g V kN m

=

=

Mt ct V bDC bDW DCbV DWbV

X0 18.80 3672.42 304.70 677.30 56.19

X1 17.36 3672.42 304.70 625.42 51.89

X2 15.80 3672.42 304.70 569.22 47.23

X3 12.80 3672.42 304.70 461.14 38.26

X4 0.00 3672.42 304.70 0.00 0.00

5.4.4.Lc ct do tnh ti tc dng ln dm gia


. . ( / ) DCdc dc V V DC g kN m=

Mt ct V dcDC DCdcV

X0 18.80 1741.74 317.85

X1 17.36 1741.74 293.50

X2 15.80 1741.74 267.13

X3 12.80 1741.74 216.41

X4 0.00 1741.74 0.00


. . ( / )

. . ( / )

DCb g M

DWb g M

M DC g V kN m

M DW g V kN m==



61/127


Mt ct V gDC gDW DCgV DWgV

X0 18.80 2871.26 378.81 529.54 69.86

X1 17.36 2871.26 378.81 488.98 64.51

X2 15.80 2871.26 378.81 445.04 58.71X3 12.80 2871.26 378.81 360.54 47.57

X4 0.00 2871.26 378.81 0.00 0.00

5.4.5.Bng tng h p ni lc

+ i vi dm bin

Dm bin

Giai on 1 Giai on 2

DCdcM DCdcV DCbM DWbM DCbV DWbV

X0 0.00 317.85 0.00 0.00 677.30 56.19

X1 440.25 293.50 938.13 77.84 625.42 51.89

X2 877.46 267.13 1869.77 155.13 569.22 47.23

X3 1602.77 216.41 3415.30 283.36 461.14 38.26

X4 2987.77 0.00 6366.59 528.23 0.00 0.00

+ i vi dm gia

Dm binGiai on 1 Giai on 2

DCdcM

DCdcV DCgM DWgM DCgV DWgV

X0 0.00 317.85 0.00 0.00 529.54 69.86

X1 440.25 293.50 738.15 96.77 488.98 64.51

X2 877.46 267.13 1471.20 192.87 445.04 58.71

X3 1602.77 216.41 2687.27 352.29 360.54 47.57

X4 2987.77 0.00 5009.44 656.71 0.00 0.00

5.5. Ni lc do hot ti tc dng ln dm gia v dm bin:5.5.1.Mmen do hot ti HL93 v PL tc dng ti cc mt ct dm

i vi cc mt ct c trng trong phm vi t gi n Ltt/2 ta xt 2 trng hpxp xe bt li nht ln ng nh hng mmen. Ni lc do xe thit k s ly gi tr max

ca 2 trng hp trn.



62/127


* S tnh: S tnh ca dm ch l dm gin n nn khong cch gia cc trc caxe ti thit k (Truck) u ly = 4.3m

* Cch xp ti ln ng nh hng:

+TH1: Xp xe sao cho hp lc ca cc trc xe v trc xe gn nht cch u tung lnnht ca ng nh hng.Vi xe Truck ta c phng trnh xc nh khong cch u

x/2 4.3(x+4.3)+145.x=145.(4.3-x)

=>x/2 = 0.7275m

+TH2: Xp cc trc v cng 1 pha ng nh hng c din tch ln nht sao cho trctrc hoc trc sau ca xe trng vi tung ln nht ca ng nh hng.

* s xp ti

5.5.1.1.S xp tai ln ng anh hng cho tng mt ct c trng

Cng thc xc nh



63/127


2

1

1 1 1 11 2 5

2 2 2 2

1 3 4

1 2

( , ) ( )

( , )

( , ) . 0

35 . 145 . 145 .

145 . 145 . 35 .

( , )

kM k tt k

tt

M k

tt kM k k

tt

Truck M M M

Truck M M M

Truck Truck Truck

X f X X L X X X L

L y X X

L X f X X X X X

L

M kN Y kN Y kN Y

M kN Y kN Y kN Y

M Max M M

=

=

=

= + += + +

=

Mt ct1

1MY1

2MY1

5MY1

TruckM 2

1MY2

3MY2

4MY2

TruckM

TruckM

X0 0.00 0.00 0.00 0.00 0.00 0.00 0.00 0.00 0.00

X1 0.00 0.69 1.25 280.32 1.38 1.22 1.06 414.67 414.67

X2 0.00 2.09 2.48 662.18 2.76 2.42 2.07 823.44 823.44

X3 0.82 4.43 4.47 1319.63 5.04 4.36 3.67 1491.30 1491.30

X4 6.89 9.04 7.61 2655.27 9.40 7.25 5.10 2592.75 2655.27

5.5.1.2.Mmen do xe 2 truc thit k (Tandem) gy ra ti cc mt ct c trng

Cng thc xc nh

2

1

1 1 1

3 4

2 2 2

1 2

1 2

( , ) ( )

( , )

( , ) . 0

110 . 110 .

110 . 110 .

( , )

kM k tt k

tt

M k

tt kM k k

tt

Tandem M M

Tandem M M

Tandem Tandem Tandem

X f X X L X X X L

L y X X L X

f X X X X X L

M kN Y kN Y

M kN Y kN Y

M Max M M

=

=

=

= +

= +

=

Mt ct 1

3MY 1

4MY 1

TandemM 2

1MY 2 2MY

2

TandemM TandemM

X0 0.00 0.00 0.00 0.00 0.00 0.00 0.00X1 0.81 1.36 238.67 1.38 1.34 299.61 299.61

X2 2.21 2.71 541.34 2.76 2.66 596.81 596.81

X3 4.54 4.95 1043.36 5.04 4.85 1088.30 1088.30

X4 9.10 9.10 2002.00 9.40 8.80 2002.00 2002.00

Vy mmen ti cc mt ct do xe thit k gy ra ( , ) . xetk Truck TandemM Max M M kN m=

BNG TNG HP



64/127


Mt ct TruckM TandemM xetkM

X0 0.00 0.00 0.00

X1 414.67 299.61 414.67

X2 823.44 596.81 823.44X3 1491.30 1088.30 1491.30

X4 2655.27 2002.00 2655.27

5.5.1.4.Mmen gy ra do tai trng lan.

Theo 3.6.1.2.4, ti trng ln ri u sut chiu di v c ln nh sau:

9,3 /lanq KN m=

Mmen do ti trng ln gy ra ti cc mt ct c xc nh bng phng phpng nh hng : Nhn gi tr qlan vi din tch ng nh hng.

. ( . )lan lan M M q kN m=

Gi tr din tch ng nh hng mmen ti cc mt ct c trng c tnh mc 5.3.2

BNG TNG HP

Mt ct 2( )

Mm lanq lanM

X0 0.00 9.30 0.00

X1 26.04 9.30 242.17

X2 51.90 9.30 482.67

X3 94.80 9.30 881.64

X4 176.72 9.30 1643.50

5.5.1.5.Mmen do tai trng ngi i gy ra dm bin

Coi nh dm bin chu ton b ti trng ngi i

2

2

3000 3 /

. . ( . ) PL M

PL Pa KN m

M PL B kN m

= ==

BNG TNG HP

Mt ct 2

( )M m PL PLM

X0 0.00 3 0.00X1 26.04 3 148.43



65/127


X2 51.90 3 295.83

X3 94.80 3 540.36

X4 176.72 3 1007.30

5.5.1.6. T h p mmen do hot tai (a nhn h s phn b m.g)

H s xung kch: 1 + IM = 1+ 0.25 =1.25

* Ti cc mt ct ca dm bin

( . ) .(1 ). ( . ) . ( . ) . ( . )SE SE SE LLb M LL xetk M lan lan M PL PLM m g IM M m g M m g M kN m = + + +

Trong

( . ) 0.1304SE

M LLm g =

( . ) 0.105SEM lanm g =

( . ) 1.174SEM PLm g =

BNG TNG HP

Mt ct (1 )IM+ ( . ) .SE

M LL xetk m g M ( . ) .SE

M lan lanm g M ( . ) .

SE

M PL PLm g M ( . )LLbM kN m

X0 1.25 0.0000 0.0000 0.0000 0.0000

X1 1.25 54.0874 25.4807 174.2416 267.3316X2 1.25 107.4058 50.7853 347.2787 532.3213

X3 1.25 194.5178 92.7639 634.3357 970.2469

X4 1.25 346.3394 172.9244 1182.4873 1788.3360

* Ti cc mt ct ca dm gia

( . ) .(1 ). ( . ) . ( . )I I

LLg M LL xetk M lan lanM m g IM M m g M kN m = + +

Trong

( . ) 0.73IM LLm g =

( . ) ) 1.2IM lanm g =

BNG TNG HP

Mt ct (1 )IM+ ( . ) .I

M LL xetk m g M ( . ) .I

M lan lanm g M ( . )LLgM kN m

X0 1.25 0.0000 0.0000 0.0000

X1 1.25 302.8895 290.6064 669.2183



66/127


X2 1.25 601.4722 579.2040 1331.0443

X3 1.25 1089.2997 1057.9680 2419.5926

X4 1.25 1939.5007 1972.1952 4396.5711

5.5.2.Lc ct do hot ti HL93 v PL tc dng ti cc mt ct dm

i vi cc mt ct c trng trong phm vi t gi n Ltt/2 trng hp xp xe btli nht ln ng nh hng lc ct ca mt ct th hin trong hnh v sau:

5.5.2.1.S xp tai ln ng anh hng cho tng mt ct c trng5.5.2.2.Lc ct do xe tai thit k (Truck) gy ra ti cc mt ct c trng

Cng thc xc nh

1

2

1 3 4

( , ) 0

( , )

( , ) 1

145 . 145 . 35 .

V k k

tt

V k

V k k tt

tt

Truck V V V

X f X X X X

L y X X

X f X X X X L

L

V kN Y kN Y kN Y

=

==

= + +

Mt ct 1VY 3VY 4VY ( )TruckV kN

X0 1.0000 0.8856 0.7713 300.4075

X1 0.9617 0.8473 0.7330 287.9600

X2 0.9202 0.8059 0.6915 274.4870

X3 0.8404 0.7261 0.6117 248.5520

X4 0.5000 0.3856 0.2713 137.9075



67/127


5.5.2.3.Lc ct do xe 2 truc thit k (Truck) gy ra ti cc mt ct c trng

1

2

1 2

( , ) 0

( , )

( , ) 1

110 . 110 .

V k k

tt

V k

V k k tt

tt

Tandem V M

X f X X X X

L y X X

X

f X X X X LL

V kN Y kN Y

=

=

=

= +

Mt ct 1VY 2VY ( )TandemY kN

X0 1.0000 0.9681 216.4910

X1 0.9617 0.9298 208.0650

X2 0.9202 0.8883 198.9350

X3 0.8404 0.8085 181.3790X4 0.5000 0.4681 106.4910

Vy lc ct ti cc mt ct do xe thit k gy ra ( , ) xetk Truck TandemV Max V V kN =

BNG TNG HP

Mt ct TruckV TandemV ( )xetkV kN

X0 300.408 216.491 300.4075

X1 287.96 208.065 287.9600

X2 274.487 198.935 274.4870

X3 248.552 181.379 248.5520

X4 137.908 106.491 137.9075

5.5.2.4.Lc ct gy ra do tai trng lanLc ct do ti trng ln gy ra ti cc mt ct ti cc mt ct xc nh bng phng

php ng nh hng , nhn gi tr qlan vi din tch ng nh hng phn dng(i vi mt ct t gi tri n Ltt/2:

Gi tr din tch ng nh hng lc ct phn din tch dng ti cc mt ct ctrng c tnh trn mc 5.3.2

9,3 /

.

lan

lan lan V

q KN m

V q

+

=

=BNG TNG HP



68/127


Mt ct ( )V m+ lanq ( )lanV kN

X0 18.8 9.3 174.8400

X1 17.39 9.3 161.7270X2 15.92 9.3 148.0560

X3 13.28 9.3 123.5040

X4 4.7 9.3 43.7100

5.5.2.5.Lc ct do tai trng ngi i gy ra dm bin

Coi nh dm bin chu ton b ti trng ngi i

2

2

3000 3 /

. . ( ) PL V

PL Pa KN m

V PL B kN += =

=

BNG TNG HP

Mt ct ( )V m+

PL ( )PLV kN

X0 18.8 3 107.1600

X1 17.39 3 99.1230

X2 15.92 3 90.7440X3 13.28 3 75.6960

X4 4.7 3 26.7900

5.5.2.6. T h p lc ct do hot tai (a nhn h s phn b m.g)

H s xung kch: 1 + IM = 1+ 0.25 = 1.25

* Ti cc mt ct ca dm bin

( ) .(1 ). ( . ) . ( . ) .SE SE E LLb V LL xetk V Lan lan V PL PLV mg IM V m g V m g V = + + +

BNG TNG HP

Mt ct (1 )IM+ ( . ) .SE

V L L xetk m g V ( . ) .SE

V lan lanm g V ( . ) .

SE

V PL PLm g V ( )LLbV kN

X0 1.25 39.1836 18.3962 125.7965 193.1722

X1 1.25 37.5600 17.0165 116.3618 180.3283

X2 1.25 35.8027 15.5781 106.5256 166.8571

X3 1.25 32.4198 12.9948 88.8605 142.3801X4 1.25 17.9879 4.5991 31.4491 58.5331



69/127


* Ti cc mt ct ca dm gia

( ) .(1 ). ( . ) .I I LLg V LL xetk V Lan lanV mg IM V m g V = + +

BNG TNG HP

Mt ct (1 )IM+ ( . ) .I

V L L xetk m g V ( . ) .I

V lan lanm g V ( )LLgV kN

X0 1.25 219.4281 209.8080 484.0931

X1 1.25 210.3360 194.0724 456.9924

X2 1.25 200.4949 177.6672 428.2858

X3 1.25 181.5510 148.2048 375.1436

X4 1.25 100.7324 52.4520 178.3675

5.6. T hp ti trng ti cc mt ct c trng5.6.1.Th p ni lc theo cc TTGH ti cc mt ct dm gia

5.6.2.1.Trng thi gii hn cng I.

* Mmen: n v kN.m

1 .(1.75 1.25 1.5 )uCD g LLg DCg DWg M M M M = + +

Mt ct LLgM DCgM DWgM 1uCD gM

X0 1.05 0.00 0.00 0.00 0.000

X1 1.05 669.22 738.15 96.77 2350.923

X2 1.05 1331.04 1471.20 192.87 4680.514

X3 1.05 2419.59 2687.27 352.29 8527.900

X4 1.05 4396.57 5009.44 656.71 15687.908

* Lc ct: n v kN

1 .(1.75 1.25 1.5 )uCD g LLg DCg DWg V V V V = + +

Mt ct LLgV DCgV DWgV 1 ( )uCD gV kN

X0 1.05 484.09 529.54 69.86 1694.5718

X1 1.05 456.99 488.98 64.51 1583.113

X2 1.05 428.29 445.04 58.71 1463.5584



70/127


X3 1.05 375.14 360.54 47.57 1237.4579

X4 1.05 178.37 0.00 0.00 327.7503

5.6.1.2.Trng thi gii hn cng II.* Mmen:n v kN.m

2 .(0. 1.25 1.5 )uCD g LLg DCg DWg M M M M = + +

Mt ct LLgM DCgM DWgM 2uCD g M

X0 1.05 0.00 0.00 0.00 0.0000

X1 1.05 669.22 738.15 96.77 1121.2346

X2 1.05 1331.04 1471.20 192.87 2234.7203X3 1.05 2419.59 2687.27 352.29 4081.8986

X4 1.05 4396.57 5009.44 656.71 7609.2083

* Lc ct: n v kN

2 .(0. 1.25 1.5 )uCD g LLg DCg DWg V V V V = + +

5.6.1.3.Trngthi gii hncng III.

* Mmen: n vkN.m

3 .(1.35. 1.25 1.5uCD g LLg DCg DWg M M M M = + +

Mt ct LLgM DCgM DWgM 3uCD gM

X0 1.05 0.00 0.00 0.00 0.0000

X1 1.05 669.22 738.15 96.77 2069.8516

X2 1.05 1331.04 1471.20 192.87 4121.4755

X3 1.05 2419.59 2687.27 352.29 7511.6711

X4 1.05 4396.57 5009.44 656.71 13841.3478

* Lc ct: n v kN


Mt ct LLgV DCgV DWgV 2 ( )uCD g V kN

X0 1.05 484.09 529.54 69.86 805.0508

X1 1.05 456.99 488.98 64.51 743.3895

X2 1.05 428.29 445.04 58.71 676.5833

X3 1.05 375.14 360.54 47.57 548.1315

X4 1.05 178.37 0.00 0.00 0.0000


71/127


3 .(1.35. 1.25 1.5 )uCD g LLg DCg DWg V V V V = + +

Mt ct LLgV DCgV DWgV 3 ( )uCD gV kN

X0 1.05 484.09 529.54 69.86 1491.2527

X1 1.05 456.99 488.98 64.51 1391.1762

X2 1.05 428.29 445.04 58.71 1283.6784

X3 1.05 375.14 360.54 47.57 1079.8976

X4 1.05 178.37 0.00 0.00 252.8359

5.6.1.4.Trng thi gii hn s dung.

* Mmen: n v kN.m

.(1. 1 1. )uSDg LLg DCg DWg M M M M = + +

Mt ct LLgM DCgM DWgM uSDgM

X0 1.05 0.00 0.00 0.00 0.0000

X1 1.05 669.22 738.15 96.77 1579.3452

X2 1.05 1331.04 1471.20 192.87 3144.8700

X3 1.05 2419.59 2687.27 352.29 5732.1102

X4 1.05 4396.57 5009.44 656.71 10565.8572

* Lc ct: n v kN

.(1.. 1. 1. )uSDg LLg DCg DWg V V V V = + +

Mt ct LLgV DCgV DWgV ( )uSDgV kN

X0 1.05 484.09 529.54 69.86 1137.6678

X1 1.05 456.99 488.98 64.51 1061.0065

X2 1.05 428.29 445.04 58.71 978.6376

X3 1.05 375.14 360.54 47.57 822.4163

X4 1.05 178.37 0.00 0.00 187.2859

5.6.2.Th p ni lc theo cc TTGH ti cc mt ct ca dm bin

5.6.1.1.Trng thi gii hn cng I.

* Mmen: n v kN.m



72/127


1 .(1.75 1.25 1.5 )uCD b LLb DCb DWbM M M M = + +

Mt ct LLbM DCbM DWbM 1uCD bM

X0 1.05 0.00 0.00 0.00 0.0000

X1 1.05 267.33 938.13 77.84 1845.1154X2 1.05 532.32 1869.77 155.13 3676.5433

X3 1.05 970.25 3415.30 283.36 6711.7019

X4 1.05 1788.34 6366.59 528.23 12474.1790

* Lc ct: n v kN

1 .(1.75 1.25 1.5 )uCD b LLb DCb DWbV V V V = + +

Mt ct LLbV DCbV DWbV 1 ( )uCD bV kN

X0 1.05 193.17 677.30 56.19 1332.4094

X1 1.05 180.33 625.42 51.89 1233.9438

X2 1.05 166.86 569.22 47.23 1128.0884

X3 1.05 142.38 461.14 38.26 927.1292

X4 1.05 58.53 0.00 0.00 107.5546

5.6.1.2.Trng thi gii hn cng II.* Mmen:n v kN.m

2 .(0. 1.25 1.5 )uCD b LLb DCb DWbM M M M = + +


X0 1.05 0.00 0.00 0.00 0.0000

X1 1.05 267.33 938.13 77.84 1353.8936

X2 1.05 532.32 1869.77 155.13 2698.4029

X3 1.05 970.25 3415.30 283.36 4928.8733

X4 1.05 1788.34 6366.59 528.23 9188.1116

* Lc ct: n v kN

2.(0. 1.25 1.5 )

uCD g LLb DCb DWbV V V V = + +


X0 1.05 193.17 677.30 56.19 977.4555

X1 1.05 180.33 625.42 51.89 902.5905

X2 1.05 166.86 569.22 47.23 821.4885



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X3 1.05 142.38 461.14 38.26 665.5058

X4 1.05 58.53 0.00 0.00 0.0000

5.6.1.3.Trng thi gii hn cng III.

* Mmen: n v kN.m

3 .(1.35. 1.25 1.5 )uCD g LLb DCb DWbM M M M = + +


X0 1.05 0.00 0.00 0.00 0.0000

X1 1.05 267.33 938.13 77.84 1732.8362

X2 1.05 532.32 1869.77 155.13 3452.9683

X3 1.05 970.25 3415.30 283.36 6304.1982

X4 1.05 1788.34 6366.59 528.23 11723.0779

* Lc ct: n v kN

3 .(1.35. 1.25 1.5 )uCD g LLb DCb DWbV V V V = + +


X0 1.05 193.17 677.30 56.19 1251.2771

X1 1.05 180.33 625.42 51.89 1158.2059

X2 1.05 166.86 569.22 47.23 1058.0084

X3 1.05 142.38 461.14 38.26 867.3295

X4 1.05 58.53 0.00 0.00 82.9707

5.6.1.4.Trng thi gii hn s dung.

* Mmen: n v kN.m

.(1. 1 1. )uSDb LLb DCb DWbM M M M = + +

Mt ct LLbM DCbM DWbM uSDbM

X0 1.05 0.00 0.00 0.00 0.0000

X1 1.05 267.33 938.13 77.84 1347.4667

X2 1.05 532.32 1869.77 155.13 2685.0824

X3 1.05 970.25 3415.30 283.36 4902.3522X4 1.05 1788.34 6366.59 528.23 9117.3138



74/127


* Lc ct: n v kN

.(1.. 1. 1. )uSDb LLb DCb DWb

V V V V = + +

Mt ct LLbV DCbV DWbV ( )uSDbV kN

X0 1.05 193.17 677.30 56.19 972.9953

X1 1.05 180.33 625.42 51.89 900.5202

X2 1.05 166.86 569.22 47.23 822.4725

X3 1.05 142.38 461.14 38.26 673.8691

X4 1.05 58.53 0.00 0.00 61.4598

Ta c bng tng hp ni lc tnh ton ca dm bin v dm gia:

DM BIN DM GIA

1max( )uCD bM 1max( )uCD gM

12474.1790 15687.908

9117.3138 10565.8572

Cn c vo cc gi tr ni lc tnh ton th dm gia l dm bt li hn nn ta s chondm gia l dm tnh duyt.


)max( 2buCDM )max( 3buCDM )max( uSDgM


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VI. TNH TON V B TRI CT THEP

6.1. Tnh ton din tich ct thp+ Dng loi tao c t chng thp Dps= 15.2mm tiu chun ASTM A416 Grade 270.

+ Loi tao thp DL: Tao thp c t chng thp

+ Cng tiu chun:91.86 10pu f x Pa=

+ H s qui i ng sut: 1 0.9 =

+ Cp ca thp: 270

+ Gii hn chy(TCN 5.9.4.4.1): 30.9 1.674 10 py pu f xf x MPa= =

+ ng sut trong thp DL khi kch( TCN 5.9.3.1):3

0.75 1.395 10 pj pu f xf x MPa= =

+ Din tch 1 tao cp: 21 140ps A mm=

+ Mdun n hi cp: 197000p E MPa=

+ Btong dm cp: '1 50c f MPa=

+ Mmen tnh ton: 1 1max( , ) 15687.90kN.u uCD g uCD bM M M= =

+i vi cu kin BTCT chu un v chu ko DL th h s sc khng: 1 =

+ :psA Din tch mt ct ngang ct thp DL:

+ :psgA Din tch mt ct ngang ct thp DL tnh theo kinh nghim.

C th tnh gn ng din tch ct thp theo cng thc kinh nghim sau:

33 2

9

15687.9 106.3 10

0.85 0.9 0.85 1.86 10 0.9 1.75

upsg

pu

M x A x m

f H x x x x

= = =

ps psg A A

S tao cp DL cn thit theo cng thc trn l:

630045

.1 140

psg

cg

ps

An

A= = =

Ta chn 45cn = tao thp Dps=15.2mm

6.2. B tr ct thp DL6.2.1.B tr ct thp DL ti mt ct ngang dm

* Mt ct ti gi: X0



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* Mt ct kim ton ct: X1

* Mt ct khng dnh bm 1: X2



77/127


* Mt ct khng dnh bm 2: X3



78/127


* Mt ct gia nhp L/2: X4



79/127


6.2.2.B tr ct thp theo phng dc dm

Theo phng dc cu ct thp DL c ko thng, trnh xut hin ng sut

ko gy nt th trn do lc d ng lc, v tr dm gim ng sut ko ta s thit kcc oncp khng dnh bm vi b tng c v tr i xng vi tim dm.

S tao thp dnh dm ti cc mt ct nh sau:

Hng Ta X0 X1 X2 X3 X4

A 75 0 7 9 11 11

B 125 0 9 11 13 13

C 175 0 9 11 13 13

D 225 0 2 4 4 4E 275 0 2 2 2 2

F 1690 2 2 2 2 2

Ta cc nhm ct thp d ng lc tnh n y dm c n v l mm

Tnh ta trng tm ct thp DL ti cc mt ct:

*Mt ct ti gi: X0 = 0m

+ Din tch ct thp DL bu dm ti mt ct:



80/127


5

ps0 ps.1 0

1

A = (A . ) 140 (0 0 0 0 0) 0 ps ii

n x=

= + + + + =

+ Din tch ct thp DL th trn dm ti mt ct:

2

ps' ps.1A 2.A 2 140 280 x mm= = =

+ Ta trng tm cc ct thp DL bu dm ti gi( tnh n y dm):

5

01

0 5

01

( . )0

psi ps ii

ps

ps ii

y nC

n

=

=

= =

+ Ta trng tm cc ct thp DLth trn:

20' ' 60 800 60 740psC H mm= = =

Khong cch t ta trng tm ct thp n th trn dm SuperT:

0 0

0' 0'

' 800mm 0.8m

' 60mm 0.06m

ps ps

ps Cps

d H C

d H

= = =

= = =

Trong :

yps:ta tao cp DL

nps : S tao cp ti cc hng*Mt ct duyt lc ct: X1 = 1.44m


52

ps1 ps.1 11

A = (A . ) 140 (7 9 9 2 2) 4060ps ii

n x mm=

= + + + + =


5

11

1 5

1

1

( . ) 75 7 125 9 175 9 225 2 275 2145.69 0.1457

7 9 9 2 2

psi ps ii

ps

ps i

i

y n x x x x xC mm m

n

=

=

+ + + += = = =+ + + +


1 1 1.75 0.1457 1.6043 ps psd H C m= = =

*Mt khng dnh bm 1: X2 = 3 m




81/127


52

ps2 ps.1 21

A = (A . ) 140 (9 11 11 2 2) 4900ps ii

n x mm=

= + + + + =


5

21

2 5

21

( . ) 75 9 125 11 175 11 225 2 275 2142.14 0.1421

9 11 11 2 2

psi ps ii

ps

ps ii

y n x x x x xC mm m

n

=

=

+ + + += = = =

+ + + +


2 21.75 0.1421 1.6079

ps psd H C m= = =

*Mt khng dnh bm 2: X3 = 6 m

+ Din tch ct thp DL bu dm ti mt ct:5

2

ps3 ps.1 3

1

A = (A . ) 140 (11 13 13 4 2) 6020 ps ii

n x mm=

= + + + + =


5

3

13 5

3

1

( . )75 11 125 13 175 13 225 4 275 2

143.6 0.143611 13 13 4 2

psi ps i

ips

ps i

i

y n x x x x x

C mm

n

=

=

+ + + += = = =

+ + + +


3 31.75 0.1436 1.6064

ps psd H C m= = =

*Mt gia nhp L/2: X4 = 18.8 m


52

ps4 ps.1 41

A = (A . ) 140 (11 13 13 4 2) 6020ps ii

n x mm=

= + + + + =


5

41

4 5

41

( . )75 11 125 13 175 13 225 4 275 2

143.6 0.143611 13 13 4 2

psi ps ii

ps

ps ii

y nx x x x x

C mm mn

=

=

+ + + += = = =

+ + + +


4 4 1.75 0.1436 1.6064 ps psd H C m= = =

BNG TNG HP



82/127


Mt ct Apsi (mm2) Dpsi (mm) dpi (m)

X0 0 0.000 0.800

X1 4060 145.690 1.604

X2 5180 146.622 1.603X3 6020 143.605 1.606

X4 6020 143.605 1.606



83/127


VII. DC TRNG HNH HOC CUA CC MT CT DM

7.1. Chiu rng c hiu ca dmchiu rng c hiu ca dm gia ly gi tr nh nht trong cc gi tr sau:

- 1/4 chiu di nhpbch1= Ltt/4 = 37.6/4 = 9.4 m

-12 ln b dy trung bnh ca bn cng gi tr ln hn trong hai gi tr b rng sn dmv na b rng bn trn dm super T

bch2=12.hf+ max(bw,b6)

-khong cc trung bnh gia cc dm: bch3= S

lp bng tng hp (m)

X bch1 bch2 bch3 bch

0 9.4 3.05 2.3 2.3

1 9.4 3.29 2.3 2.3

2 9.4 2.88 2.3 2.3

3 9.4 2.88 2.3 2.3

4 9.4 2.88 2.3 2.3

M un n hi ca b tng:Ecdam=36872.5Mpa

M un n hi ca thp:Eps=197000Mpa

H s qui i thp sang b tngps

cdam

En 5.343

E= =

T l m un n hi gia bn mt cu v dm ch:cban

cdam

En ' 0.800

E= =

7.2. t trng hnh hc mt ct dm Super T giai on I.7.2.1.Mt ct ti gi X0

*Din tch mt ct: Ag01=0.796m2

*Ta trng tm mt ct so vi th di dm: Yc0=0.419 m3

*M men tnh ca mt ct i vi trc y dm: Sx0=0.334 m3

*M men qun tnh ca mt ct i vi trc X: Jx0 = 0.159 m4

*M men qun tnh i vi trc trung ha :Jthx0 = 0.043 m4

*Din tch mt ct quy i



84/127


Ag0. = A0g1 + (n-1).Aps0 = 0.79625 + (5.343 - 1).0 = 0.796m2

* Mmen tnh ca ct thp cng cao i vi trc trung ha ca mt ct nguyn

Sx-x0 = (n1-1).Aps0.(Dps0-(H-Yc)) = 0 m3

* Khong cch t trng tm ca tit din c ct thp n trng tm ca tit din nguynZ0 = Sx-x0/Ag0 = 0 m3

* Khong cch t trng tm ca tit din c ct thp n th trn dm

ytg0 = H-ybg0 = 0.381m

* Khong cch t trng tm ca tit din c ct thp n th di dm

ybg0 = Yc-Z0 = 0.419 m

* Mmen qun tnh tnh so vi trc trung ha ca mt ct c ct thpIg0.= Ig0 + Z02*Ag0 = 0.043 m4

7.2.2.Mt ct ti on khc X1

*Din tch mt ct : F1 = 1.63 m2

*Ta trng tm mt ct so vi th di dm Yc1 = 0.98 m3

*M men tnh ca mt ct i vi trc X: Sx1 = 1.597 m3

*M men qun tnh ca mt ct i vi trc X : Jx1 = 1.407 m4

*M men qun tnh i vi trc trung ha: Jthx1 = 0.441 m4


Ag1. = A0g1 + (n-1).Aps1= 1.63 + (5.343 - 1).0.00406 = 1.648 m2

* Mmen tnh ca m ct thp i vi trc trung ha ca mt ct nguyn

Sx-x1= (n - 1).Aps1.(dps1 - (H - Yc1)) = (5.343-1)x0.00406x(1.604 (1.75 0.98))

= 0.0147 m3

* Khong cch t trng tm ca m ct thp n trng tm ca tit din

Z1=Sx-x1/A0g1 = 0.0089 m


ytg1= H - ybg1= 0.780 m


ybg1 = Yc1-Z1=0.98 0.0089 = 0.970 m

* Mmen qun tnh tnh so vi trc trung ha ca mt ct c ct thp



85/127


Ig1.= Ig1 + Z12xA0g1+ Aps1x(Yc1 - (H - dp1 - Z1 ))2

= 0.441+ 0.00892x1.63 + 0.00406x(0.98 (1.75 1.604 0.0089))2 = 0.444 m4

7.2.3.Mt ct khng dnh bm 1: X2

*Din tch mt ct : F2 = 0.6343 m2






Ag2. = A0g2 + (n-1).Aps2= 0.6343 + (5.343 - 1).0.00518 = 0.6568 m2


Sx-x2= (n - 1).Aps2.(dps2 - (H - Yc2)) =

= (5.343-1)x0.00518x(1.603 (1.75 0.848)) = 0.0158 m3


Z2=Sx-x2/A0g2 = 0.0158/0.6568 = 0.0240 m


ytg2= H - ybg2= 1.75 0.824 = 0.926 m


ybg2 = Yc2-Z2= 0.848 0.0240 =0.824 m


Ig2.= Ig2 + Z22xA0g2+ Aps2x(Yc2 - (H - dp2 Z2 ))2

= 0.2459+ 0.02402x0.6343 + 0.00518x(0.848 (1.75 1.603 0.0240))2

= 0.2506 m4


*Din tch mt ct : F3 = 0.6343 m2







86/127



Ag3 = A0g3 + (n-1).Aps3= 0.6343 + (5.343 - 1).0.00602 = 0.6604 m2


Sx-x3= (n - 1).Aps3.(dps3 - (H - Yc3)) == (5.343-1)x0.00602x(1.606 (1.75 0.848)) = 0.0184 m3


Z3=Sx-x3/A0g3 = 0.0185/0.6604 = 0.0279 m


ytg3= H - ybg3= 1.75 0.824 = 0.9299 m

* Khong cch t trng tm ca tit din c ct thp n th di dmybg3 = Yc3-Z3= 0.848 0.0279 = 0.8201 m


Ig3.= Ig3 + Z32xA0g3+ Aps3x(Yc3 - (H - dp3 Z3 ))2

= 0.2459+ 0.02792x0.6343 + 0.00602x(0.848 (1.75 1.606 0.0279))2

= 0.2514 m4

7.2.4.Mt ct gia nhp: X4

*Din tch mt ct : F4 = 0.6343 m2






Ag4. = A0g4 + (n-1).Aps4= 0.6343 + (5.343 - 1).0.00602 = 0.6604 m2


Sx-x4= (n - 1).Aps4.(dps4 - (H - Yc4)) =

= (5.343-1)x0.00602x(1.606 (1.75 0.848)) = 0.0184 m3


Z4=Sx-x4/A0g4 = 0.0185/0.6604 = 0.0279 m




87/127


ytg4= H - ybg4= 1.75 0.824 = 0.9299 m


ybg4 = Yc4-Z4= 0.848 0.0279 = 0.8201 m

* Mmen qun tnh tnh so vi trc trung ha ca mt ct c ct thpIg4.= Ig4 + Z32xA0g3+ Aps3x(Yc3 - (H - dp3 Z3 ))2

= 0.2459+ 0.02792x0.6343 + 0.00602x(0.848 (1.75 1.606 0.0279))2

= 0.2514 m4

7.3. t trng hnh hc mt ct dm Super T giai on II.7.3.1.Mt ct ti gi X0

* Din tch nguyn khi

A.g0 = A2g0+ (n-1).Aps0 = 1.12745 + (5.343 - 1).0 = 1.12745 m2

* Mmen tnh ca tit din i vi TTH I-I (ca giai on 1)

SI-I0 = n'.S.hf(hf/2+ytg0) = 0.8x2.3x0.18(0.09+0.381) = 0.156m3

* Khong cch t trng tm dm n trng tm tit din lin hp.

Z.0 = SI-I0/A.g0 = 0.156/1.12745 = 0.138 m

* Khong cch t trng tm ca tit din lin hp n y dm

y.bg0 = ybg0 + Z.0= 0.419 + 0.138 = 0.557 m

* Khong cch t trng tm tit din lin hp n mp trn dm

y.tg0 = H_ - y.bg0 = 0.8 - 0.557 = 0.243 m

* Mmen qun tnh

2 3 2

. 0 0. 0. .0 . 0

2 3 2 4

1'( . . .( ) )12 2

1 0.18

0.043 0.796 0.138 0.8 ( 2.3 0.18 2.3 0.18 (0.243 )) 0.09612 2

f

g g f f tg

h I I Ag xZ n S h S h y

x x x x x x m

= + + + + =

+ + + + =

7.3.2.Mt ct ti mt ct tnh duyt lc ct X1

* Din tch nguyn khi

A.g1 = A2g1+ (n-1).Aps1 = 1.961 + (5.343 - 1).0.00406 = 1.9786 m2


SI-I1 = n'.S.hf(hf/2+ytg1) = 0.8x2.3x0.18(0.09+0.7789) = 0.2878 m3

* Khong cch t trng tm dm n trng tm tit din lin hp.Z.1 = SI-I1/A.g1 = 0.2878/1.9786 = 0.146 m



88/127



y.bg1 = ybg1 + Z.1= 0.9711 + 0.146= 1.1171 m


y.tg1 = H - y.bg1 = 1.75 1.1171 = 0.6329 m* Mmen qun tnh

2 3 2. 1 1. 1. .1 . 1

2 3 2 4

1'( . . .( ) )12 2

1 0.180.444 1.6471 0.146 0.8 ( 2.3 0.18 2.3 0.18 (0.6329 )) 0.653

12 2

fg g f f tg

hI I Ag xZ n S h S h y

x x x x x x m

= + + + + =

+ + + + =


* Din tch nguyn khiA.g2 = A2g2+ (n-1).Aps2 = 0.966 + (5.343 - 1)x0.00518 = 0.9890 m2




Z.2 = SI-I1/A.g2 = 0.3365/0.9890 = 0.340 m


y.bg2= ybg2 + Z.2= 0.8240 + 0.340= 1.164 m


y.tg2 = H_ - y.bg2 = 1.75 1.164 = 0.586 m

* Mmen qun tnh

2 3 2. 2 2. 2. .2 . 2

2 3 2 4

1'( . . .( ) )12 2

1 0.180.2506 0.6568 0.340 0.8 ( 2.3 0.18 2.3 0.18 (0.586 )) 0.47912 2

fg g f f tg

hI I Ag xZ n S h S h y

x x x x x x m

= + + + + =

+ + + + =


* Din tch nguyn khi

A.g3 = A2g3+ (n-1).Aps3 = 0.966 + (5.343 - 1)x0.00602 = 0.9921 m2






89/127


Z.3 = SI-I1/A.g3 = 0.3378/0.9921 = 0.3405 m


y.bg3= ybg3+ Z.3= 0.8201 + 0.3405= 1.1606 m

* Khong cch t trng tm tit din lin hp n mp trn dmy.tg3 = H - y.bg3 = 1.75 1.1606 = 0.5849 m

* Mmen qun tnh

2 3 2. 3 3. 3. .3 . 3

2 3

thiet ke so bo

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