this equation is true for all values of the variable. this is called an identity (many solutions)

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This equation is true for all values of the variable. This is called an identity (many solutions). p. 98 3b. 6(y – 5) = 2(10 + 3y) 6y – 30 = 20 + 6y -6y -6y Subtract 6y on both sides -30 20 False (no solution) 39. Let d = the number of DVD’s they must sell to make a profit production cost = selling price 1500 + .80d = 1.59d

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This equation is true for all values of the variable. This is called an identity (many solutions). p. 98 3b. 6(y – 5) = 2(10 + 3y) 6y – 30 = 20 + 6y -6y -6y Subtract 6y on both sides -30  20 False (no solution) 39. - PowerPoint PPT Presentation

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Page 1: This equation is true for all values of the variable. This is called an identity (many solutions)

This equation is true for all values of the variable. This is called an identity (many solutions).

p. 983b. 6(y – 5) = 2(10 + 3y) 6y – 30 = 20 + 6y -6y -6y Subtract 6y on both sides -30 20 False (no solution)39. Let d = the number of DVD’s they must sell to

make a profitproduction cost = selling price

1500 + .80d = 1.59d - .80d = -.80d 1500 =.79d .79 .79

Page 2: This equation is true for all values of the variable. This is called an identity (many solutions)

d = 1898.7

The company must sell 1,899 DVD’s per day to make a profit.

Let’s do 22.

Page 3: This equation is true for all values of the variable. This is called an identity (many solutions)

GEOMETRY

A = lwA = 12x square units

x units

12 units

16 units

x – 2 units

22. Find the value of x so that the rectangles have the same area.

A = lwA = 16 (x – 2)A = 16x – 32 square

units

Page 4: This equation is true for all values of the variable. This is called an identity (many solutions)

12x = 16(x - 2) 12x = 16x - 32 -16x -16x_____ -4x = -32 -4 -4 x = 8x needs to be 8 in order for the areas to

be the same.

A = lw A = 8(12) = 96 square units

Page 5: This equation is true for all values of the variable. This is called an identity (many solutions)

Example: 6v – 4 = v

8 2 (8) 6v – 4 = v (8) Multiply both

sides by 8 8 2 6v – 4 = 4v -6v -6v Subtract 6v on

both sides -4 = -2v -2 -2 Divide -2 on both

sides 2 = v

Page 6: This equation is true for all values of the variable. This is called an identity (many solutions)

Now do 21.21. 6(3a + 1) – 30 = 3(2a – 4)

Exit Slip p. 97 Guided practice 1B under Example

1

Page 7: This equation is true for all values of the variable. This is called an identity (many solutions)

HW p. 100 10, 12, 16, 20