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Name_____________________________________ Class____________________________ Date________________
Lesson ObjectivesFinding common and binomial factorsof quadratic expressionsFactoring special quadratic expressions2
1
NAEP 2005 Strand: AlgebraTopic: Variables, Expressions, and Operations
Local Standards: ____________________________________
Vocabulary and Key Concepts.
Factoring Perfect Square Trinomials
a2 ! 2ab ! b2 " (a b)2
a2 # 2ab ! b2 " (a b)2
Factoring a Difference of Two Squaresa2 # b2 " (a b)(a b)
Factoring is
The greatest common factor (GCF) of an expression is
A perfect square trinomial is
The difference of two squares is
Examples.
Factoring When ac > 0 and b < 0 Factor x2 # 14x ! 33.
Step 1 Find factors with product ac and sum b.Since ac " 33 and b " #14, find negative factors with product 33 and sum #14.
Factors of 33 , ,
#14Sum of factors #34
1
Lesson 5-4 Factoring Quadratic Expressions
95Daily Notetaking Guide Algebra 2 Lesson 5-4
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Lesson 5-4 Factoring Quadratic Expressions 259
Factoring QuadraticExpressions
is rewriting an expression as the product of its factors. Theis a common factor of the
terms of the expression. It’s the common factor with the greatest coefficient and thegreatest exponent. You can factor any expression that has a GCF not equal to 1.
Finding Common Factors
Factor each expression.
a. 4x2 + 20x - 12
4x2 + 20x - 12 = 4x2 + 4(5x) - 4(3) Factor out the GCF, 4.
= 4(x2 + 5x - 3) Rewrite using the Distributive Property.
b. 9n2 - 24n
9n2 - 24n = 3n(3n) - 3n(8) Factor out the GCF, 3n.
= 3n(3n - 8) Rewrite using the Distributive Property.
Factor each expression.
a. 9x2 + 3x - 18 b. 7p2 + 21 c. 4w2 + 2w
11Quick Check
EXAMPLEEXAMPLE11
greatest common factor (GCF) of an expressionFactoring
5-45-4
Lessons 1-2 and 5-1
Simplify each expression.1. x2 + x + 4x - 1 2. 6x2 - 4(3)x + 2x - 3 3. 4x2 - 2(5- x)- 3x
Multiply.4. 2x(5 - x) 5. (2x - 7)(2x - 7) 6. (4x + 3)(4x - 3)
New Vocabulary • factoring • greatest common factor (GCF) of an expression• perfect square trinomial • difference of two squares
What You’ll Learn• To find common and
binomial factors ofquadratic expressions
• To factor special quadraticexpressions
. . . And WhyTo model the cross section ofa pipe, as in Example 8
11 Finding Common and Binomial Factors
Activity: Factoring
1. Since 6 ? 3 = 18, 6 and 3 make up a factor pair for 18. a. Find the other factor pairs for 18, including negative integers.b. Find the sum of the integers in each factor pair for 18.
2. a. Does 12 have a factor pair with a sum of -8? A sum of -9?b. Using all the factor pairs of 12, how many sums are possible?c. How many sums are possible for the factor pairs of -12?
x2 ± 5x – 1 6x2 – 10x – 3
–2x2 ± 10x
3(3x2 ± x – 6) 7(p2 ± 3) 2w(2w ± 1)
–19, –11, –9, 19, 11, 9yes; no
66
16x2 – 9
1a. –1 and –18, –2and –9, –3 and–6, 1 and 18, 2and 9
4x2 – 28x ± 49
4x2 – x – 10
Check Skills You’ll Need GO for Help
One number is a factor ofanother if the first dividesinto the second with noremainder.
Vocabulary Tip
5-45-4
259
1. PlanObjectives1 To find common and binomial
factors of quadraticexpressions
2 To factor special quadraticexpressions
Examples1 Finding Common Factors2 Factoring When ac ! 0 and
b ! 03 Factoring When ac ! 0 and
b " 04 Factoring When ac " 05 Factoring When a # 1 and
ac ! 06 Factoring When a # 1 and
ac " 07 Factoring a Perfect Square
Trinomial8 Real-World Connection
Math Background
A quadratic function of the formƒ(x) = ax2 + bx + c factors intotwo linear factors. When trying tofactor a quadratic function, welook for two factors whose sum isb and whose product is ac.
More Math Background: p. 236C
Lesson Planning andResources
See p. 236E for a list of theresources that support this lesson.
Bell Ringer Practice
Check Skills You’ll NeedFor intervention, direct students to:
Algebraic ExpressionsLesson 1-2: Example 4Extra Skills and Word
Problems Practice, Ch. 1
Modeling Data With Quadratic FunctionsLesson 5-1: Example 1Extra Skills and Word
Problems Practice, Ch. 5
PowerPoint
Special NeedsPair students who have difficulty remembering theirmultiplication facts with students who know themwell. Require students to check their answers bymultiplying their factors using FOIL.
Below LevelHave students make a table summarizing theprocedures in the examples for various combinationsof signs of ac and b.
L2L1
learning style: verbal learning style: visual
A2_3eTE05_04_259-265 10/20/05 9:27 AM Page 259
Lesson 5-4 Factoring Quadratic Expressions 259
Factoring QuadraticExpressions
is rewriting an expression as the product of its factors. Theis a common factor of the
terms of the expression. It’s the common factor with the greatest coefficient and thegreatest exponent. You can factor any expression that has a GCF not equal to 1.
Finding Common Factors
Factor each expression.
a. 4x2 + 20x - 12
4x2 + 20x - 12 = 4x2 + 4(5x) - 4(3) Factor out the GCF, 4.
= 4(x2 + 5x - 3) Rewrite using the Distributive Property.
b. 9n2 - 24n
9n2 - 24n = 3n(3n) - 3n(8) Factor out the GCF, 3n.
= 3n(3n - 8) Rewrite using the Distributive Property.
Factor each expression.
a. 9x2 + 3x - 18 b. 7p2 + 21 c. 4w2 + 2w
11Quick Check
EXAMPLEEXAMPLE11
greatest common factor (GCF) of an expressionFactoring
5-45-4
Lessons 1-2 and 5-1
Simplify each expression.1. x2 + x + 4x - 1 2. 6x2 - 4(3)x + 2x - 3 3. 4x2 - 2(5- x)- 3x
Multiply.4. 2x(5 - x) 5. (2x - 7)(2x - 7) 6. (4x + 3)(4x - 3)
New Vocabulary • factoring • greatest common factor (GCF) of an expression• perfect square trinomial • difference of two squares
What You’ll Learn• To find common and
binomial factors ofquadratic expressions
• To factor special quadraticexpressions
. . . And WhyTo model the cross section ofa pipe, as in Example 8
11 Finding Common and Binomial Factors
Activity: Factoring
1. Since 6 ? 3 = 18, 6 and 3 make up a factor pair for 18. a. Find the other factor pairs for 18, including negative integers.b. Find the sum of the integers in each factor pair for 18.
2. a. Does 12 have a factor pair with a sum of -8? A sum of -9?b. Using all the factor pairs of 12, how many sums are possible?c. How many sums are possible for the factor pairs of -12?
x2 ± 5x – 1 6x2 – 10x – 3
–2x2 ± 10x
3(3x2 ± x – 6) 7(p2 ± 3) 2w(2w ± 1)
–19, –11, –9, 19, 11, 9yes; no
66
16x2 – 9
1a. –1 and –18, –2and –9, –3 and–6, 1 and 18, 2and 9
4x2 – 28x ± 49
4x2 – x – 10
Check Skills You’ll Need GO for Help
One number is a factor ofanother if the first dividesinto the second with noremainder.
Vocabulary Tip
5-45-4
259
1. PlanObjectives1 To find common and binomial
factors of quadraticexpressions
2 To factor special quadraticexpressions
Examples1 Finding Common Factors2 Factoring When ac ! 0 and
b ! 03 Factoring When ac ! 0 and
b " 04 Factoring When ac " 05 Factoring When a # 1 and
ac ! 06 Factoring When a # 1 and
ac " 07 Factoring a Perfect Square
Trinomial8 Real-World Connection
Math Background
A quadratic function of the formƒ(x) = ax2 + bx + c factors intotwo linear factors. When trying tofactor a quadratic function, welook for two factors whose sum isb and whose product is ac.
More Math Background: p. 236C
Lesson Planning andResources
See p. 236E for a list of theresources that support this lesson.
Bell Ringer Practice
Check Skills You’ll NeedFor intervention, direct students to:
Algebraic ExpressionsLesson 1-2: Example 4Extra Skills and Word
Problems Practice, Ch. 1
Modeling Data With Quadratic FunctionsLesson 5-1: Example 1Extra Skills and Word
Problems Practice, Ch. 5
PowerPoint
Special NeedsPair students who have difficulty remembering theirmultiplication facts with students who know themwell. Require students to check their answers bymultiplying their factors using FOIL.
Below LevelHave students make a table summarizing theprocedures in the examples for various combinationsof signs of ac and b.
L2L1
learning style: verbal learning style: visual
A2_3eTE05_04_259-265 10/20/05 9:27 AM Page 259
Lesson 5-4 Factoring Quadratic Expressions 259
Factoring QuadraticExpressions
is rewriting an expression as the product of its factors. Theis a common factor of the
terms of the expression. It’s the common factor with the greatest coefficient and thegreatest exponent. You can factor any expression that has a GCF not equal to 1.
Finding Common Factors
Factor each expression.
a. 4x2 + 20x - 12
4x2 + 20x - 12 = 4x2 + 4(5x) - 4(3) Factor out the GCF, 4.
= 4(x2 + 5x - 3) Rewrite using the Distributive Property.
b. 9n2 - 24n
9n2 - 24n = 3n(3n) - 3n(8) Factor out the GCF, 3n.
= 3n(3n - 8) Rewrite using the Distributive Property.
Factor each expression.
a. 9x2 + 3x - 18 b. 7p2 + 21 c. 4w2 + 2w
11Quick Check
EXAMPLEEXAMPLE11
greatest common factor (GCF) of an expressionFactoring
5-45-4
Lessons 1-2 and 5-1
Simplify each expression.1. x2 + x + 4x - 1 2. 6x2 - 4(3)x + 2x - 3 3. 4x2 - 2(5- x)- 3x
Multiply.4. 2x(5 - x) 5. (2x - 7)(2x - 7) 6. (4x + 3)(4x - 3)
New Vocabulary • factoring • greatest common factor (GCF) of an expression• perfect square trinomial • difference of two squares
What You’ll Learn• To find common and
binomial factors ofquadratic expressions
• To factor special quadraticexpressions
. . . And WhyTo model the cross section ofa pipe, as in Example 8
11 Finding Common and Binomial Factors
Activity: Factoring
1. Since 6 ? 3 = 18, 6 and 3 make up a factor pair for 18. a. Find the other factor pairs for 18, including negative integers.b. Find the sum of the integers in each factor pair for 18.
2. a. Does 12 have a factor pair with a sum of -8? A sum of -9?b. Using all the factor pairs of 12, how many sums are possible?c. How many sums are possible for the factor pairs of -12?
x2 ± 5x – 1 6x2 – 10x – 3
–2x2 ± 10x
3(3x2 ± x – 6) 7(p2 ± 3) 2w(2w ± 1)
–19, –11, –9, 19, 11, 9yes; no
66
16x2 – 9
1a. –1 and –18, –2and –9, –3 and–6, 1 and 18, 2and 9
4x2 – 28x ± 49
4x2 – x – 10
Check Skills You’ll Need GO for Help
One number is a factor ofanother if the first dividesinto the second with noremainder.
Vocabulary Tip
5-45-4
259
1. PlanObjectives1 To find common and binomial
factors of quadraticexpressions
2 To factor special quadraticexpressions
Examples1 Finding Common Factors2 Factoring When ac ! 0 and
b ! 03 Factoring When ac ! 0 and
b " 04 Factoring When ac " 05 Factoring When a # 1 and
ac ! 06 Factoring When a # 1 and
ac " 07 Factoring a Perfect Square
Trinomial8 Real-World Connection
Math Background
A quadratic function of the formƒ(x) = ax2 + bx + c factors intotwo linear factors. When trying tofactor a quadratic function, welook for two factors whose sum isb and whose product is ac.
More Math Background: p. 236C
Lesson Planning andResources
See p. 236E for a list of theresources that support this lesson.
Bell Ringer Practice
Check Skills You’ll NeedFor intervention, direct students to:
Algebraic ExpressionsLesson 1-2: Example 4Extra Skills and Word
Problems Practice, Ch. 1
Modeling Data With Quadratic FunctionsLesson 5-1: Example 1Extra Skills and Word
Problems Practice, Ch. 5
PowerPoint
Special NeedsPair students who have difficulty remembering theirmultiplication facts with students who know themwell. Require students to check their answers bymultiplying their factors using FOIL.
Below LevelHave students make a table summarizing theprocedures in the examples for various combinationsof signs of ac and b.
L2L1
learning style: verbal learning style: visual
A2_3eTE05_04_259-265 10/20/05 9:27 AM Page 259
A quadratic trinomial is an expression in the form ax2 + bx + c. You can factormany quadratic trinomials into two binomial factors. First find two factors with aproduct ac and a sum b. Then find common factors.
If ac and b are positive, then the factors of ac are both positive.
Factoring When ac S 0 and b S 0
Factor x2 + 8x + 7.
Step 1 Find factors with product ac and sum b.
Since ac = 7 and b = 8, find positive factors with product 7 and sum 8.
Step 2 Rewrite the term bx using the factors you found. Group the remainingterms and find the common factors for each group. After removingcommon factors from each group, you should find two identical binomials.
x2 + 8x + 7
x2 + x + 7x + 7 Rewrite bx: 8x ≠ x ± 7x.(')'* (')'*x(x + 1) + 7(x + 1) Find common factors.
Step 3 Rewrite the expression as the product of two binomials.
x(x + 1) + 7(x + 1)
(x + 1)(x + 7) Rewrite using the Distributive Property.
Check (x + 1)(x + 7) = x2 + 7x + x + 7
= x2 + 8x + 7 ✓
Factor each expression. Check your answers.a. x2 + 6x + 8 b. x2 + 12x + 32 c. x2 + 14x + 40
If ac is positive and b is negative, then the factors of ac are both negative.
Factoring When ac S 0 and b R 0
Factor x2 - 17x + 72.
Step 1 Find factors with product ac and sum b.
Since ac = 72 and b = -17, find negative factors with product 72 and sum -17.
Step 2 Rewrite the term bx using the factors you found. Then find commonfactors and rewrite the expression as the product of two binomials.
x2 - 17x + 72
x2 - 8x - 9x + 72 Rewrite bx.(')'* (')'*x(x - 8) - 9(x - 8) Find common factors.
(x - 9)(x - 8) Rewrite using the Distributive Property.
Factors of 72Sum of factors
!1, !72!73
!2, !36!38
!3, !24!27
!4, !18 !22
!6, !12!18
!8, !9!17
EXAMPLEEXAMPLE33
22Quick Check
Factors of 7Sum of factors
1, 78
These are the only positive factors of 7.
EXAMPLEEXAMPLE22
260 Chapter 5 Quadratic Equations and Functions
You can use algebra tiles to factor the expression inExample 2.
(x ± 2)(x ± 4) (x ± 4)(x ± 8) (x ± 4)(x ± 10)
x2 x x x x x x x
x 1 1 1 1 1 1 1
A monomial is anexpression with one term. A binomial has two terms, and atrinomial has three terms.
Vocabulary Tip
260
2. Teach
Guided Instruction
ActivityIn order to factor quadraticexpressions, students must beable to find factor pairs forintegers. Have students completethe Activity to practice findingfactor pairs. Tell students it isimportant to include negativefactors.
Math Tip
In the first part of Step 2, showstudents that the order in whichthey write the addends isimportant. The goal is to have thefirst two terms and the last twoterms have a common factor.
Error Prevention
Some students may look for anynumbers whose sum is -17.Remind them that only the factorpair in the table with a sum of -17 can be used to factor theexpression.
Math Tip
Placement of the signs is veryimportant. To emphasize this,have students switch the signs inthe binomial factors and multiply.
EXAMPLEEXAMPLE44
EXAMPLEEXAMPLE33
EXAMPLEEXAMPLE22
Advanced LearnersChallenge students to use a spreadsheet program tocreate tables like those used in the examples forfinding the sum of possible factors.
English Language Learners ELLMake sure students understand the meaning of theterms factoring and greatest common factor. Useinteger examples and algebraic expressions toillustrate the meaning of each term.
L4
learning style: tactile learning style: verbal
A2_3eTE05_04_259-265 10/20/05 9:27 AM Page 260
A quadratic trinomial is an expression in the form ax2 + bx + c. You can factormany quadratic trinomials into two binomial factors. First find two factors with aproduct ac and a sum b. Then find common factors.
If ac and b are positive, then the factors of ac are both positive.
Factoring When ac S 0 and b S 0
Factor x2 + 8x + 7.
Step 1 Find factors with product ac and sum b.
Since ac = 7 and b = 8, find positive factors with product 7 and sum 8.
Step 2 Rewrite the term bx using the factors you found. Group the remainingterms and find the common factors for each group. After removingcommon factors from each group, you should find two identical binomials.
x2 + 8x + 7
x2 + x + 7x + 7 Rewrite bx: 8x ≠ x ± 7x.(')'* (')'*x(x + 1) + 7(x + 1) Find common factors.
Step 3 Rewrite the expression as the product of two binomials.
x(x + 1) + 7(x + 1)
(x + 1)(x + 7) Rewrite using the Distributive Property.
Check (x + 1)(x + 7) = x2 + 7x + x + 7
= x2 + 8x + 7 ✓
Factor each expression. Check your answers.a. x2 + 6x + 8 b. x2 + 12x + 32 c. x2 + 14x + 40
If ac is positive and b is negative, then the factors of ac are both negative.
Factoring When ac S 0 and b R 0
Factor x2 - 17x + 72.
Step 1 Find factors with product ac and sum b.
Since ac = 72 and b = -17, find negative factors with product 72 and sum -17.
Step 2 Rewrite the term bx using the factors you found. Then find commonfactors and rewrite the expression as the product of two binomials.
x2 - 17x + 72
x2 - 8x - 9x + 72 Rewrite bx.(')'* (')'*x(x - 8) - 9(x - 8) Find common factors.
(x - 9)(x - 8) Rewrite using the Distributive Property.
Factors of 72Sum of factors
!1, !72!73
!2, !36!38
!3, !24!27
!4, !18 !22
!6, !12!18
!8, !9!17
EXAMPLEEXAMPLE33
22Quick Check
Factors of 7Sum of factors
1, 78
These are the only positive factors of 7.
EXAMPLEEXAMPLE22
260 Chapter 5 Quadratic Equations and Functions
You can use algebra tiles to factor the expression inExample 2.
(x ± 2)(x ± 4) (x ± 4)(x ± 8) (x ± 4)(x ± 10)
x2 x x x x x x x
x 1 1 1 1 1 1 1
A monomial is anexpression with one term. A binomial has two terms, and atrinomial has three terms.
Vocabulary Tip
260
2. Teach
Guided Instruction
ActivityIn order to factor quadraticexpressions, students must beable to find factor pairs forintegers. Have students completethe Activity to practice findingfactor pairs. Tell students it isimportant to include negativefactors.
Math Tip
In the first part of Step 2, showstudents that the order in whichthey write the addends isimportant. The goal is to have thefirst two terms and the last twoterms have a common factor.
Error Prevention
Some students may look for anynumbers whose sum is -17.Remind them that only the factorpair in the table with a sum of -17 can be used to factor theexpression.
Math Tip
Placement of the signs is veryimportant. To emphasize this,have students switch the signs inthe binomial factors and multiply.
EXAMPLEEXAMPLE44
EXAMPLEEXAMPLE33
EXAMPLEEXAMPLE22
Advanced LearnersChallenge students to use a spreadsheet program tocreate tables like those used in the examples forfinding the sum of possible factors.
English Language Learners ELLMake sure students understand the meaning of theterms factoring and greatest common factor. Useinteger examples and algebraic expressions toillustrate the meaning of each term.
L4
learning style: tactile learning style: verbal
A2_3eTE05_04_259-265 10/20/05 9:27 AM Page 260
© P
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Algebra 2 Chapter 5 Lesson 5-4 Practice 5
Name Class Date
Practice 5-4 Factoring Quadratic Expressions
Factor each expression completely.
1. x2 + 4x + 4 2. x2 - 7x + 10 3. x2 + 7x - 8
4. x2 - 6x 5. 2x2 - 9x + 4 6. x2 + 2x - 35
7. x2 + 6x + 5 8. x2 - 9 9. x2 - 13x - 48
10. x2 - 4 11. 4x2 + x 12. x2 - 29x + 100
13. x2 - x - 6 14. 9x2 - 1 15. 3x2 - 2x
16. x2 - 64 17. x2 - 25 18. x2 - 81
19. x2 - 36 20. x2 - 100 21. x2 - 1
22. 4x2 - 1 23. 4x2 - 36 24. 9x2 - 4
25. x2 - 7x - 8 26. x2 + 13x + 36 27. x2 - 5x + 6
28. x2 + 5x + 4 29. x2 - 21x - 22 30. x2 + 13x + 40
31. 2x2 - 5x - 3 32. x2 + 10x - 11 33. x2 - 14x + 24
34. 5x2 + 4x - 12 35. 2x2 - 5x - 7 36. 2x2 + 13x + 15
37. 3x2 - 7x - 6 38. 3x2 + 16x + 21 39. x2 + 5x - 24
40. x2 + 34x - 72 41. x2 - 11x 42. 3x2 + 21x
43. x2 + 8x + 12 44. x2 - 10x + 24 45. x2 + 7x - 30
46. x2 - 2x - 168 47. x2 - x - 72 48. 4x2 - 25
49. x2 - 121 50. x2 + 17x + 16 51. 10x2 - 17x + 3
52. 4x2 + 12x + 9 53. 4x2 - 4x - 15 54. 9x2 - 4
55. x2 + 6x - 40 56. 2x2 - 8 57. x2 + 18x + 77
58. 2x2 - 98 59. x2 + 21x + 98 60. x2 + 20x + 84
61. 9x2 + 30x + 16 62. 8x2 - 6x - 27 63. x2 - 3x - 54
64. x2 - 169 65. 25x2 - 9 66. 7x2 + 49
67. 2x2 - 10x - 28 68. x2 + 8x + 12 69. x2 - 2x - 35
70. x2 + 2x - 63 71. 20x2 - 11x - 3 72. 12x2 + 4x - 5
73. 4x2 - 5x - 6 74. 8x2 + 22x - 21 75. 3x2 - 3x - 168
© P
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Algebra 2 Chapter 5 Lesson 5-4 Practice 5
Name Class Date
Practice 5-4 Factoring Quadratic Expressions
Factor each expression completely.
1. x2 + 4x + 4 2. x2 - 7x + 10 3. x2 + 7x - 8
4. x2 - 6x 5. 2x2 - 9x + 4 6. x2 + 2x - 35
7. x2 + 6x + 5 8. x2 - 9 9. x2 - 13x - 48
10. x2 - 4 11. 4x2 + x 12. x2 - 29x + 100
13. x2 - x - 6 14. 9x2 - 1 15. 3x2 - 2x
16. x2 - 64 17. x2 - 25 18. x2 - 81
19. x2 - 36 20. x2 - 100 21. x2 - 1
22. 4x2 - 1 23. 4x2 - 36 24. 9x2 - 4
25. x2 - 7x - 8 26. x2 + 13x + 36 27. x2 - 5x + 6
28. x2 + 5x + 4 29. x2 - 21x - 22 30. x2 + 13x + 40
31. 2x2 - 5x - 3 32. x2 + 10x - 11 33. x2 - 14x + 24
34. 5x2 + 4x - 12 35. 2x2 - 5x - 7 36. 2x2 + 13x + 15
37. 3x2 - 7x - 6 38. 3x2 + 16x + 21 39. x2 + 5x - 24
40. x2 + 34x - 72 41. x2 - 11x 42. 3x2 + 21x
43. x2 + 8x + 12 44. x2 - 10x + 24 45. x2 + 7x - 30
46. x2 - 2x - 168 47. x2 - x - 72 48. 4x2 - 25
49. x2 - 121 50. x2 + 17x + 16 51. 10x2 - 17x + 3
52. 4x2 + 12x + 9 53. 4x2 - 4x - 15 54. 9x2 - 4
55. x2 + 6x - 40 56. 2x2 - 8 57. x2 + 18x + 77
58. 2x2 - 98 59. x2 + 21x + 98 60. x2 + 20x + 84
61. 9x2 + 30x + 16 62. 8x2 - 6x - 27 63. x2 - 3x - 54
64. x2 - 169 65. 25x2 - 9 66. 7x2 + 49
67. 2x2 - 10x - 28 68. x2 + 8x + 12 69. x2 - 2x - 35
70. x2 + 2x - 63 71. 20x2 - 11x - 3 72. 12x2 + 4x - 5
73. 4x2 - 5x - 6 74. 8x2 + 22x - 21 75. 3x2 - 3x - 168
© P
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Algebra 2 Chapter 5 Lesson 5-4 Practice 5
Name Class Date
Practice 5-4 Factoring Quadratic Expressions
Factor each expression completely.
1. x2 + 4x + 4 2. x2 - 7x + 10 3. x2 + 7x - 8
4. x2 - 6x 5. 2x2 - 9x + 4 6. x2 + 2x - 35
7. x2 + 6x + 5 8. x2 - 9 9. x2 - 13x - 48
10. x2 - 4 11. 4x2 + x 12. x2 - 29x + 100
13. x2 - x - 6 14. 9x2 - 1 15. 3x2 - 2x
16. x2 - 64 17. x2 - 25 18. x2 - 81
19. x2 - 36 20. x2 - 100 21. x2 - 1
22. 4x2 - 1 23. 4x2 - 36 24. 9x2 - 4
25. x2 - 7x - 8 26. x2 + 13x + 36 27. x2 - 5x + 6
28. x2 + 5x + 4 29. x2 - 21x - 22 30. x2 + 13x + 40
31. 2x2 - 5x - 3 32. x2 + 10x - 11 33. x2 - 14x + 24
34. 5x2 + 4x - 12 35. 2x2 - 5x - 7 36. 2x2 + 13x + 15
37. 3x2 - 7x - 6 38. 3x2 + 16x + 21 39. x2 + 5x - 24
40. x2 + 34x - 72 41. x2 - 11x 42. 3x2 + 21x
43. x2 + 8x + 12 44. x2 - 10x + 24 45. x2 + 7x - 30
46. x2 - 2x - 168 47. x2 - x - 72 48. 4x2 - 25
49. x2 - 121 50. x2 + 17x + 16 51. 10x2 - 17x + 3
52. 4x2 + 12x + 9 53. 4x2 - 4x - 15 54. 9x2 - 4
55. x2 + 6x - 40 56. 2x2 - 8 57. x2 + 18x + 77
58. 2x2 - 98 59. x2 + 21x + 98 60. x2 + 20x + 84
61. 9x2 + 30x + 16 62. 8x2 - 6x - 27 63. x2 - 3x - 54
64. x2 - 169 65. 25x2 - 9 66. 7x2 + 49
67. 2x2 - 10x - 28 68. x2 + 8x + 12 69. x2 - 2x - 35
70. x2 + 2x - 63 71. 20x2 - 11x - 3 72. 12x2 + 4x - 5
73. 4x2 - 5x - 6 74. 8x2 + 22x - 21 75. 3x2 - 3x - 168
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Algebra 2 Chapter 5 Lesson 5-4 Practice 5
Name Class Date
Practice 5-4 Factoring Quadratic Expressions
Factor each expression completely.
1. x2 + 4x + 4 2. x2 - 7x + 10 3. x2 + 7x - 8
4. x2 - 6x 5. 2x2 - 9x + 4 6. x2 + 2x - 35
7. x2 + 6x + 5 8. x2 - 9 9. x2 - 13x - 48
10. x2 - 4 11. 4x2 + x 12. x2 - 29x + 100
13. x2 - x - 6 14. 9x2 - 1 15. 3x2 - 2x
16. x2 - 64 17. x2 - 25 18. x2 - 81
19. x2 - 36 20. x2 - 100 21. x2 - 1
22. 4x2 - 1 23. 4x2 - 36 24. 9x2 - 4
25. x2 - 7x - 8 26. x2 + 13x + 36 27. x2 - 5x + 6
28. x2 + 5x + 4 29. x2 - 21x - 22 30. x2 + 13x + 40
31. 2x2 - 5x - 3 32. x2 + 10x - 11 33. x2 - 14x + 24
34. 5x2 + 4x - 12 35. 2x2 - 5x - 7 36. 2x2 + 13x + 15
37. 3x2 - 7x - 6 38. 3x2 + 16x + 21 39. x2 + 5x - 24
40. x2 + 34x - 72 41. x2 - 11x 42. 3x2 + 21x
43. x2 + 8x + 12 44. x2 - 10x + 24 45. x2 + 7x - 30
46. x2 - 2x - 168 47. x2 - x - 72 48. 4x2 - 25
49. x2 - 121 50. x2 + 17x + 16 51. 10x2 - 17x + 3
52. 4x2 + 12x + 9 53. 4x2 - 4x - 15 54. 9x2 - 4
55. x2 + 6x - 40 56. 2x2 - 8 57. x2 + 18x + 77
58. 2x2 - 98 59. x2 + 21x + 98 60. x2 + 20x + 84
61. 9x2 + 30x + 16 62. 8x2 - 6x - 27 63. x2 - 3x - 54
64. x2 - 169 65. 25x2 - 9 66. 7x2 + 49
67. 2x2 - 10x - 28 68. x2 + 8x + 12 69. x2 - 2x - 35
70. x2 + 2x - 63 71. 20x2 - 11x - 3 72. 12x2 + 4x - 5
73. 4x2 - 5x - 6 74. 8x2 + 22x - 21 75. 3x2 - 3x - 168
![Page 2: To find common and x Rewrite using the Distributive ... · of signs of ac and b. L1 L2 learning style: verbal learning style: visual A2_3eTE05_04_259-265 10/20/05 9:27 AM Page 259](https://reader036.vdocument.in/reader036/viewer/2022071117/600772bd2a652010e34bebea/html5/thumbnails/2.jpg)
A quadratic trinomial is an expression in the form ax2 + bx + c. You can factormany quadratic trinomials into two binomial factors. First find two factors with aproduct ac and a sum b. Then find common factors.
If ac and b are positive, then the factors of ac are both positive.
Factoring When ac S 0 and b S 0
Factor x2 + 8x + 7.
Step 1 Find factors with product ac and sum b.
Since ac = 7 and b = 8, find positive factors with product 7 and sum 8.
Step 2 Rewrite the term bx using the factors you found. Group the remainingterms and find the common factors for each group. After removingcommon factors from each group, you should find two identical binomials.
x2 + 8x + 7
x2 + x + 7x + 7 Rewrite bx: 8x ≠ x ± 7x.(')'* (')'*x(x + 1) + 7(x + 1) Find common factors.
Step 3 Rewrite the expression as the product of two binomials.
x(x + 1) + 7(x + 1)
(x + 1)(x + 7) Rewrite using the Distributive Property.
Check (x + 1)(x + 7) = x2 + 7x + x + 7
= x2 + 8x + 7 ✓
Factor each expression. Check your answers.a. x2 + 6x + 8 b. x2 + 12x + 32 c. x2 + 14x + 40
If ac is positive and b is negative, then the factors of ac are both negative.
Factoring When ac S 0 and b R 0
Factor x2 - 17x + 72.
Step 1 Find factors with product ac and sum b.
Since ac = 72 and b = -17, find negative factors with product 72 and sum -17.
Step 2 Rewrite the term bx using the factors you found. Then find commonfactors and rewrite the expression as the product of two binomials.
x2 - 17x + 72
x2 - 8x - 9x + 72 Rewrite bx.(')'* (')'*x(x - 8) - 9(x - 8) Find common factors.
(x - 9)(x - 8) Rewrite using the Distributive Property.
Factors of 72Sum of factors
!1, !72!73
!2, !36!38
!3, !24!27
!4, !18 !22
!6, !12!18
!8, !9!17
EXAMPLEEXAMPLE33
22Quick Check
Factors of 7Sum of factors
1, 78
These are the only positive factors of 7.
EXAMPLEEXAMPLE22
260 Chapter 5 Quadratic Equations and Functions
You can use algebra tiles to factor the expression inExample 2.
(x ± 2)(x ± 4) (x ± 4)(x ± 8) (x ± 4)(x ± 10)
x2 x x x x x x x
x 1 1 1 1 1 1 1
A monomial is anexpression with one term. A binomial has two terms, and atrinomial has three terms.
Vocabulary Tip
260
2. Teach
Guided Instruction
ActivityIn order to factor quadraticexpressions, students must beable to find factor pairs forintegers. Have students completethe Activity to practice findingfactor pairs. Tell students it isimportant to include negativefactors.
Math Tip
In the first part of Step 2, showstudents that the order in whichthey write the addends isimportant. The goal is to have thefirst two terms and the last twoterms have a common factor.
Error Prevention
Some students may look for anynumbers whose sum is -17.Remind them that only the factorpair in the table with a sum of -17 can be used to factor theexpression.
Math Tip
Placement of the signs is veryimportant. To emphasize this,have students switch the signs inthe binomial factors and multiply.
EXAMPLEEXAMPLE44
EXAMPLEEXAMPLE33
EXAMPLEEXAMPLE22
Advanced LearnersChallenge students to use a spreadsheet program tocreate tables like those used in the examples forfinding the sum of possible factors.
English Language Learners ELLMake sure students understand the meaning of theterms factoring and greatest common factor. Useinteger examples and algebraic expressions toillustrate the meaning of each term.
L4
learning style: tactile learning style: verbal
A2_3eTE05_04_259-265 10/20/05 9:27 AM Page 260
Lesson 5-4 Factoring Quadratic Expressions 261
Factor each expression.a. x2 - 6x + 8 b. x2 - 7x + 12 c. x2 - 11x + 24
Note in Example 3 that the factors of c,-9 and -8, appear in the binomials of thefactored form, (x - 9)(x - 8). That is also the case for the factors in Example 2,and it is the case whenever a = 1. So when a = 1, you can skip a few steps infactoring. See Example 4.
If ac is negative, then the factors of ac have different signs.
Factoring When ac R 0
Factor x2 - x - 12.
Step 1 Find factors with product ac and sum b.
Since ac = -12 and b = -1, find factors with product -12 and sum -1.
Step 2 Since a = 1, you can write binomials using the factors you found.
x2 - x - 12
(x - 4)(x + 3) Use the factors you found.
Factor each expression.a. x2 - 14x - 32 b. x2 + 3x - 10 c. x2 + 4x - 5
If ac is positive, as in Examples 2 and 3, then the factors of ac have the same sign.This is true even when a 2 1.
Factoring When a u 1 and ac S 0
Factor 3x2 - 16x + 5.
Step 1 Find factors with product ac and sum b.
Since ac = 15 and b = -16, find negative factors with product 15 and sum -16.
Step 2 Rewrite the term bx using the factors you found. Then find commonfactors and rewrite the expression as the product of two binomials.
3x2 - 16x + 5
3x2 - x - 15x + 5 Rewrite bx.(')'* (')'*x(3x - 1) - 5(3x - 1) Find common factors.
(x - 5)(3x - 1) Rewrite using the Distributive Property.
Factor each expression. Check your answers.a. 2x2 + 11x + 12 b. 4x2 + 7x + 3 c. 2x2 - 7x + 6
55Quick Check
Factors of 15Sum of factors
!1, !15 !16
!3, !5 !8
EXAMPLEEXAMPLE55
44Quick Check
Factors of –12Sum of factors
1, !12!11
!1, 12 11
2, !6!4
!2, 6 4
3, !4!1
!3, 4 1
EXAMPLEEXAMPLE44
33Quick Check(x – 2)(x – 4) (x – 3)(x – 4) (x – 3)(x – 8)
(x ± 2)(x – 16) (x ± 5)(x – 2) (x ± 5)(x – 1)
(x ± 4)(2x ± 3) (x ± 1)(4x ± 3) (x – 2)(2x – 3)
261
Alternative Method
Have students draw a square withfour sections, such as the oneshown. Then follow these steps:1. Write the first and the last term
as shown.
2. Multiply a and c. Then findfactors of the product thathave a sum of b.4(-15) = -606(-10) = -60
and 6 + (-10) = -43. Write the factors with their
signs and variables in the othertwo boxes. Order does notmatter. Then find the GCF ofeach column and each row. AGCF is negative if both termsare negative.
(2x - 5)(2x + 3)
Additional Examples
Factor each expression.a. 15x2 + 25x + 100 5(3x2 ± 5x ± 20)b. 8m2 + 4m 4m(2m ± 1)
Factor x2 + 10x + 24. (x ± 4)(x ± 6)
Factor x2 - 14x + 33. (x – 3)(x – 11)
Factor x2 + 3x - 28. (x – 4)(x ± 7)
Factor 6x2 - 31x + 35. (3x – 5)(2x – 7)
Factor 6x2 + 11x - 35. (3x – 5)(2x ± 7)
66
55
44
33
22
11
4x2 6x
-10x -15
4x2
-15
EXAMPLEEXAMPLE66
2x
2x ± 3
–5
PowerPoint
A2_3eTE05_04_259-265 10/20/05 9:27 AM Page 261
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Algebra 2 Chapter 5 Lesson 5-4 Practice 5
Name Class Date
Practice 5-4 Factoring Quadratic Expressions
Factor each expression completely.
1. x2 + 4x + 4 2. x2 - 7x + 10 3. x2 + 7x - 8
4. x2 - 6x 5. 2x2 - 9x + 4 6. x2 + 2x - 35
7. x2 + 6x + 5 8. x2 - 9 9. x2 - 13x - 48
10. x2 - 4 11. 4x2 + x 12. x2 - 29x + 100
13. x2 - x - 6 14. 9x2 - 1 15. 3x2 - 2x
16. x2 - 64 17. x2 - 25 18. x2 - 81
19. x2 - 36 20. x2 - 100 21. x2 - 1
22. 4x2 - 1 23. 4x2 - 36 24. 9x2 - 4
25. x2 - 7x - 8 26. x2 + 13x + 36 27. x2 - 5x + 6
28. x2 + 5x + 4 29. x2 - 21x - 22 30. x2 + 13x + 40
31. 2x2 - 5x - 3 32. x2 + 10x - 11 33. x2 - 14x + 24
34. 5x2 + 4x - 12 35. 2x2 - 5x - 7 36. 2x2 + 13x + 15
37. 3x2 - 7x - 6 38. 3x2 + 16x + 21 39. x2 + 5x - 24
40. x2 + 34x - 72 41. x2 - 11x 42. 3x2 + 21x
43. x2 + 8x + 12 44. x2 - 10x + 24 45. x2 + 7x - 30
46. x2 - 2x - 168 47. x2 - x - 72 48. 4x2 - 25
49. x2 - 121 50. x2 + 17x + 16 51. 10x2 - 17x + 3
52. 4x2 + 12x + 9 53. 4x2 - 4x - 15 54. 9x2 - 4
55. x2 + 6x - 40 56. 2x2 - 8 57. x2 + 18x + 77
58. 2x2 - 98 59. x2 + 21x + 98 60. x2 + 20x + 84
61. 9x2 + 30x + 16 62. 8x2 - 6x - 27 63. x2 - 3x - 54
64. x2 - 169 65. 25x2 - 9 66. 7x2 + 49
67. 2x2 - 10x - 28 68. x2 + 8x + 12 69. x2 - 2x - 35
70. x2 + 2x - 63 71. 20x2 - 11x - 3 72. 12x2 + 4x - 5
73. 4x2 - 5x - 6 74. 8x2 + 22x - 21 75. 3x2 - 3x - 168
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Algebra 2 Chapter 5 Lesson 5-4 Practice 5
Name Class Date
Practice 5-4 Factoring Quadratic Expressions
Factor each expression completely.
1. x2 + 4x + 4 2. x2 - 7x + 10 3. x2 + 7x - 8
4. x2 - 6x 5. 2x2 - 9x + 4 6. x2 + 2x - 35
7. x2 + 6x + 5 8. x2 - 9 9. x2 - 13x - 48
10. x2 - 4 11. 4x2 + x 12. x2 - 29x + 100
13. x2 - x - 6 14. 9x2 - 1 15. 3x2 - 2x
16. x2 - 64 17. x2 - 25 18. x2 - 81
19. x2 - 36 20. x2 - 100 21. x2 - 1
22. 4x2 - 1 23. 4x2 - 36 24. 9x2 - 4
25. x2 - 7x - 8 26. x2 + 13x + 36 27. x2 - 5x + 6
28. x2 + 5x + 4 29. x2 - 21x - 22 30. x2 + 13x + 40
31. 2x2 - 5x - 3 32. x2 + 10x - 11 33. x2 - 14x + 24
34. 5x2 + 4x - 12 35. 2x2 - 5x - 7 36. 2x2 + 13x + 15
37. 3x2 - 7x - 6 38. 3x2 + 16x + 21 39. x2 + 5x - 24
40. x2 + 34x - 72 41. x2 - 11x 42. 3x2 + 21x
43. x2 + 8x + 12 44. x2 - 10x + 24 45. x2 + 7x - 30
46. x2 - 2x - 168 47. x2 - x - 72 48. 4x2 - 25
49. x2 - 121 50. x2 + 17x + 16 51. 10x2 - 17x + 3
52. 4x2 + 12x + 9 53. 4x2 - 4x - 15 54. 9x2 - 4
55. x2 + 6x - 40 56. 2x2 - 8 57. x2 + 18x + 77
58. 2x2 - 98 59. x2 + 21x + 98 60. x2 + 20x + 84
61. 9x2 + 30x + 16 62. 8x2 - 6x - 27 63. x2 - 3x - 54
64. x2 - 169 65. 25x2 - 9 66. 7x2 + 49
67. 2x2 - 10x - 28 68. x2 + 8x + 12 69. x2 - 2x - 35
70. x2 + 2x - 63 71. 20x2 - 11x - 3 72. 12x2 + 4x - 5
73. 4x2 - 5x - 6 74. 8x2 + 22x - 21 75. 3x2 - 3x - 168
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Algebra 2 Chapter 5 Lesson 5-4 Practice 5
Name Class Date
Practice 5-4 Factoring Quadratic Expressions
Factor each expression completely.
1. x2 + 4x + 4 2. x2 - 7x + 10 3. x2 + 7x - 8
4. x2 - 6x 5. 2x2 - 9x + 4 6. x2 + 2x - 35
7. x2 + 6x + 5 8. x2 - 9 9. x2 - 13x - 48
10. x2 - 4 11. 4x2 + x 12. x2 - 29x + 100
13. x2 - x - 6 14. 9x2 - 1 15. 3x2 - 2x
16. x2 - 64 17. x2 - 25 18. x2 - 81
19. x2 - 36 20. x2 - 100 21. x2 - 1
22. 4x2 - 1 23. 4x2 - 36 24. 9x2 - 4
25. x2 - 7x - 8 26. x2 + 13x + 36 27. x2 - 5x + 6
28. x2 + 5x + 4 29. x2 - 21x - 22 30. x2 + 13x + 40
31. 2x2 - 5x - 3 32. x2 + 10x - 11 33. x2 - 14x + 24
34. 5x2 + 4x - 12 35. 2x2 - 5x - 7 36. 2x2 + 13x + 15
37. 3x2 - 7x - 6 38. 3x2 + 16x + 21 39. x2 + 5x - 24
40. x2 + 34x - 72 41. x2 - 11x 42. 3x2 + 21x
43. x2 + 8x + 12 44. x2 - 10x + 24 45. x2 + 7x - 30
46. x2 - 2x - 168 47. x2 - x - 72 48. 4x2 - 25
49. x2 - 121 50. x2 + 17x + 16 51. 10x2 - 17x + 3
52. 4x2 + 12x + 9 53. 4x2 - 4x - 15 54. 9x2 - 4
55. x2 + 6x - 40 56. 2x2 - 8 57. x2 + 18x + 77
58. 2x2 - 98 59. x2 + 21x + 98 60. x2 + 20x + 84
61. 9x2 + 30x + 16 62. 8x2 - 6x - 27 63. x2 - 3x - 54
64. x2 - 169 65. 25x2 - 9 66. 7x2 + 49
67. 2x2 - 10x - 28 68. x2 + 8x + 12 69. x2 - 2x - 35
70. x2 + 2x - 63 71. 20x2 - 11x - 3 72. 12x2 + 4x - 5
73. 4x2 - 5x - 6 74. 8x2 + 22x - 21 75. 3x2 - 3x - 168
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Algebra 2 Chapter 5 Lesson 5-4 Practice 5
Name Class Date
Practice 5-4 Factoring Quadratic Expressions
Factor each expression completely.
1. x2 + 4x + 4 2. x2 - 7x + 10 3. x2 + 7x - 8
4. x2 - 6x 5. 2x2 - 9x + 4 6. x2 + 2x - 35
7. x2 + 6x + 5 8. x2 - 9 9. x2 - 13x - 48
10. x2 - 4 11. 4x2 + x 12. x2 - 29x + 100
13. x2 - x - 6 14. 9x2 - 1 15. 3x2 - 2x
16. x2 - 64 17. x2 - 25 18. x2 - 81
19. x2 - 36 20. x2 - 100 21. x2 - 1
22. 4x2 - 1 23. 4x2 - 36 24. 9x2 - 4
25. x2 - 7x - 8 26. x2 + 13x + 36 27. x2 - 5x + 6
28. x2 + 5x + 4 29. x2 - 21x - 22 30. x2 + 13x + 40
31. 2x2 - 5x - 3 32. x2 + 10x - 11 33. x2 - 14x + 24
34. 5x2 + 4x - 12 35. 2x2 - 5x - 7 36. 2x2 + 13x + 15
37. 3x2 - 7x - 6 38. 3x2 + 16x + 21 39. x2 + 5x - 24
40. x2 + 34x - 72 41. x2 - 11x 42. 3x2 + 21x
43. x2 + 8x + 12 44. x2 - 10x + 24 45. x2 + 7x - 30
46. x2 - 2x - 168 47. x2 - x - 72 48. 4x2 - 25
49. x2 - 121 50. x2 + 17x + 16 51. 10x2 - 17x + 3
52. 4x2 + 12x + 9 53. 4x2 - 4x - 15 54. 9x2 - 4
55. x2 + 6x - 40 56. 2x2 - 8 57. x2 + 18x + 77
58. 2x2 - 98 59. x2 + 21x + 98 60. x2 + 20x + 84
61. 9x2 + 30x + 16 62. 8x2 - 6x - 27 63. x2 - 3x - 54
64. x2 - 169 65. 25x2 - 9 66. 7x2 + 49
67. 2x2 - 10x - 28 68. x2 + 8x + 12 69. x2 - 2x - 35
70. x2 + 2x - 63 71. 20x2 - 11x - 3 72. 12x2 + 4x - 5
73. 4x2 - 5x - 6 74. 8x2 + 22x - 21 75. 3x2 - 3x - 168
Lesson 5-4 Factoring Quadratic Expressions 261
Factor each expression.a. x2 - 6x + 8 b. x2 - 7x + 12 c. x2 - 11x + 24
Note in Example 3 that the factors of c,-9 and -8, appear in the binomials of thefactored form, (x - 9)(x - 8). That is also the case for the factors in Example 2,and it is the case whenever a = 1. So when a = 1, you can skip a few steps infactoring. See Example 4.
If ac is negative, then the factors of ac have different signs.
Factoring When ac R 0
Factor x2 - x - 12.
Step 1 Find factors with product ac and sum b.
Since ac = -12 and b = -1, find factors with product -12 and sum -1.
Step 2 Since a = 1, you can write binomials using the factors you found.
x2 - x - 12
(x - 4)(x + 3) Use the factors you found.
Factor each expression.a. x2 - 14x - 32 b. x2 + 3x - 10 c. x2 + 4x - 5
If ac is positive, as in Examples 2 and 3, then the factors of ac have the same sign.This is true even when a 2 1.
Factoring When a u 1 and ac S 0
Factor 3x2 - 16x + 5.
Step 1 Find factors with product ac and sum b.
Since ac = 15 and b = -16, find negative factors with product 15 and sum -16.
Step 2 Rewrite the term bx using the factors you found. Then find commonfactors and rewrite the expression as the product of two binomials.
3x2 - 16x + 5
3x2 - x - 15x + 5 Rewrite bx.(')'* (')'*x(3x - 1) - 5(3x - 1) Find common factors.
(x - 5)(3x - 1) Rewrite using the Distributive Property.
Factor each expression. Check your answers.a. 2x2 + 11x + 12 b. 4x2 + 7x + 3 c. 2x2 - 7x + 6
55Quick Check
Factors of 15Sum of factors
!1, !15 !16
!3, !5 !8
EXAMPLEEXAMPLE55
44Quick Check
Factors of –12Sum of factors
1, !12!11
!1, 12 11
2, !6!4
!2, 6 4
3, !4!1
!3, 4 1
EXAMPLEEXAMPLE44
33Quick Check(x – 2)(x – 4) (x – 3)(x – 4) (x – 3)(x – 8)
(x ± 2)(x – 16) (x ± 5)(x – 2) (x ± 5)(x – 1)
(x ± 4)(2x ± 3) (x ± 1)(4x ± 3) (x – 2)(2x – 3)
261
Alternative Method
Have students draw a square withfour sections, such as the oneshown. Then follow these steps:1. Write the first and the last term
as shown.
2. Multiply a and c. Then findfactors of the product thathave a sum of b.4(-15) = -606(-10) = -60
and 6 + (-10) = -43. Write the factors with their
signs and variables in the othertwo boxes. Order does notmatter. Then find the GCF ofeach column and each row. AGCF is negative if both termsare negative.
(2x - 5)(2x + 3)
Additional Examples
Factor each expression.a. 15x2 + 25x + 100 5(3x2 ± 5x ± 20)b. 8m2 + 4m 4m(2m ± 1)
Factor x2 + 10x + 24. (x ± 4)(x ± 6)
Factor x2 - 14x + 33. (x – 3)(x – 11)
Factor x2 + 3x - 28. (x – 4)(x ± 7)
Factor 6x2 - 31x + 35. (3x – 5)(2x – 7)
Factor 6x2 + 11x - 35. (3x – 5)(2x ± 7)
66
55
44
33
22
11
4x2 6x
-10x -15
4x2
-15
EXAMPLEEXAMPLE66
2x
2x ± 3
–5
PowerPoint
A2_3eTE05_04_259-265 10/20/05 9:27 AM Page 261
Lesson 5-4 Factoring Quadratic Expressions 261
Factor each expression.a. x2 - 6x + 8 b. x2 - 7x + 12 c. x2 - 11x + 24
Note in Example 3 that the factors of c,-9 and -8, appear in the binomials of thefactored form, (x - 9)(x - 8). That is also the case for the factors in Example 2,and it is the case whenever a = 1. So when a = 1, you can skip a few steps infactoring. See Example 4.
If ac is negative, then the factors of ac have different signs.
Factoring When ac R 0
Factor x2 - x - 12.
Step 1 Find factors with product ac and sum b.
Since ac = -12 and b = -1, find factors with product -12 and sum -1.
Step 2 Since a = 1, you can write binomials using the factors you found.
x2 - x - 12
(x - 4)(x + 3) Use the factors you found.
Factor each expression.a. x2 - 14x - 32 b. x2 + 3x - 10 c. x2 + 4x - 5
If ac is positive, as in Examples 2 and 3, then the factors of ac have the same sign.This is true even when a 2 1.
Factoring When a u 1 and ac S 0
Factor 3x2 - 16x + 5.
Step 1 Find factors with product ac and sum b.
Since ac = 15 and b = -16, find negative factors with product 15 and sum -16.
Step 2 Rewrite the term bx using the factors you found. Then find commonfactors and rewrite the expression as the product of two binomials.
3x2 - 16x + 5
3x2 - x - 15x + 5 Rewrite bx.(')'* (')'*x(3x - 1) - 5(3x - 1) Find common factors.
(x - 5)(3x - 1) Rewrite using the Distributive Property.
Factor each expression. Check your answers.a. 2x2 + 11x + 12 b. 4x2 + 7x + 3 c. 2x2 - 7x + 6
55Quick Check
Factors of 15Sum of factors
!1, !15 !16
!3, !5 !8
EXAMPLEEXAMPLE55
44Quick Check
Factors of –12Sum of factors
1, !12!11
!1, 12 11
2, !6!4
!2, 6 4
3, !4!1
!3, 4 1
EXAMPLEEXAMPLE44
33Quick Check(x – 2)(x – 4) (x – 3)(x – 4) (x – 3)(x – 8)
(x ± 2)(x – 16) (x ± 5)(x – 2) (x ± 5)(x – 1)
(x ± 4)(2x ± 3) (x ± 1)(4x ± 3) (x – 2)(2x – 3)
261
Alternative Method
Have students draw a square withfour sections, such as the oneshown. Then follow these steps:1. Write the first and the last term
as shown.
2. Multiply a and c. Then findfactors of the product thathave a sum of b.4(-15) = -606(-10) = -60
and 6 + (-10) = -43. Write the factors with their
signs and variables in the othertwo boxes. Order does notmatter. Then find the GCF ofeach column and each row. AGCF is negative if both termsare negative.
(2x - 5)(2x + 3)
Additional Examples
Factor each expression.a. 15x2 + 25x + 100 5(3x2 ± 5x ± 20)b. 8m2 + 4m 4m(2m ± 1)
Factor x2 + 10x + 24. (x ± 4)(x ± 6)
Factor x2 - 14x + 33. (x – 3)(x – 11)
Factor x2 + 3x - 28. (x – 4)(x ± 7)
Factor 6x2 - 31x + 35. (3x – 5)(2x – 7)
Factor 6x2 + 11x - 35. (3x – 5)(2x ± 7)
66
55
44
33
22
11
4x2 6x
-10x -15
4x2
-15
EXAMPLEEXAMPLE66
2x
2x ± 3
–5
PowerPoint
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Algebra 2 Chapter 5 Lesson 5-4 Practice 5
Name Class Date
Practice 5-4 Factoring Quadratic Expressions
Factor each expression completely.
1. x2 + 4x + 4 2. x2 - 7x + 10 3. x2 + 7x - 8
4. x2 - 6x 5. 2x2 - 9x + 4 6. x2 + 2x - 35
7. x2 + 6x + 5 8. x2 - 9 9. x2 - 13x - 48
10. x2 - 4 11. 4x2 + x 12. x2 - 29x + 100
13. x2 - x - 6 14. 9x2 - 1 15. 3x2 - 2x
16. x2 - 64 17. x2 - 25 18. x2 - 81
19. x2 - 36 20. x2 - 100 21. x2 - 1
22. 4x2 - 1 23. 4x2 - 36 24. 9x2 - 4
25. x2 - 7x - 8 26. x2 + 13x + 36 27. x2 - 5x + 6
28. x2 + 5x + 4 29. x2 - 21x - 22 30. x2 + 13x + 40
31. 2x2 - 5x - 3 32. x2 + 10x - 11 33. x2 - 14x + 24
34. 5x2 + 4x - 12 35. 2x2 - 5x - 7 36. 2x2 + 13x + 15
37. 3x2 - 7x - 6 38. 3x2 + 16x + 21 39. x2 + 5x - 24
40. x2 + 34x - 72 41. x2 - 11x 42. 3x2 + 21x
43. x2 + 8x + 12 44. x2 - 10x + 24 45. x2 + 7x - 30
46. x2 - 2x - 168 47. x2 - x - 72 48. 4x2 - 25
49. x2 - 121 50. x2 + 17x + 16 51. 10x2 - 17x + 3
52. 4x2 + 12x + 9 53. 4x2 - 4x - 15 54. 9x2 - 4
55. x2 + 6x - 40 56. 2x2 - 8 57. x2 + 18x + 77
58. 2x2 - 98 59. x2 + 21x + 98 60. x2 + 20x + 84
61. 9x2 + 30x + 16 62. 8x2 - 6x - 27 63. x2 - 3x - 54
64. x2 - 169 65. 25x2 - 9 66. 7x2 + 49
67. 2x2 - 10x - 28 68. x2 + 8x + 12 69. x2 - 2x - 35
70. x2 + 2x - 63 71. 20x2 - 11x - 3 72. 12x2 + 4x - 5
73. 4x2 - 5x - 6 74. 8x2 + 22x - 21 75. 3x2 - 3x - 168
© P
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Algebra 2 Chapter 5 Lesson 5-4 Practice 5
Name Class Date
Practice 5-4 Factoring Quadratic Expressions
Factor each expression completely.
1. x2 + 4x + 4 2. x2 - 7x + 10 3. x2 + 7x - 8
4. x2 - 6x 5. 2x2 - 9x + 4 6. x2 + 2x - 35
7. x2 + 6x + 5 8. x2 - 9 9. x2 - 13x - 48
10. x2 - 4 11. 4x2 + x 12. x2 - 29x + 100
13. x2 - x - 6 14. 9x2 - 1 15. 3x2 - 2x
16. x2 - 64 17. x2 - 25 18. x2 - 81
19. x2 - 36 20. x2 - 100 21. x2 - 1
22. 4x2 - 1 23. 4x2 - 36 24. 9x2 - 4
25. x2 - 7x - 8 26. x2 + 13x + 36 27. x2 - 5x + 6
28. x2 + 5x + 4 29. x2 - 21x - 22 30. x2 + 13x + 40
31. 2x2 - 5x - 3 32. x2 + 10x - 11 33. x2 - 14x + 24
34. 5x2 + 4x - 12 35. 2x2 - 5x - 7 36. 2x2 + 13x + 15
37. 3x2 - 7x - 6 38. 3x2 + 16x + 21 39. x2 + 5x - 24
40. x2 + 34x - 72 41. x2 - 11x 42. 3x2 + 21x
43. x2 + 8x + 12 44. x2 - 10x + 24 45. x2 + 7x - 30
46. x2 - 2x - 168 47. x2 - x - 72 48. 4x2 - 25
49. x2 - 121 50. x2 + 17x + 16 51. 10x2 - 17x + 3
52. 4x2 + 12x + 9 53. 4x2 - 4x - 15 54. 9x2 - 4
55. x2 + 6x - 40 56. 2x2 - 8 57. x2 + 18x + 77
58. 2x2 - 98 59. x2 + 21x + 98 60. x2 + 20x + 84
61. 9x2 + 30x + 16 62. 8x2 - 6x - 27 63. x2 - 3x - 54
64. x2 - 169 65. 25x2 - 9 66. 7x2 + 49
67. 2x2 - 10x - 28 68. x2 + 8x + 12 69. x2 - 2x - 35
70. x2 + 2x - 63 71. 20x2 - 11x - 3 72. 12x2 + 4x - 5
73. 4x2 - 5x - 6 74. 8x2 + 22x - 21 75. 3x2 - 3x - 168
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Algebra 2 Chapter 5 Lesson 5-4 Practice 5
Name Class Date
Practice 5-4 Factoring Quadratic Expressions
Factor each expression completely.
1. x2 + 4x + 4 2. x2 - 7x + 10 3. x2 + 7x - 8
4. x2 - 6x 5. 2x2 - 9x + 4 6. x2 + 2x - 35
7. x2 + 6x + 5 8. x2 - 9 9. x2 - 13x - 48
10. x2 - 4 11. 4x2 + x 12. x2 - 29x + 100
13. x2 - x - 6 14. 9x2 - 1 15. 3x2 - 2x
16. x2 - 64 17. x2 - 25 18. x2 - 81
19. x2 - 36 20. x2 - 100 21. x2 - 1
22. 4x2 - 1 23. 4x2 - 36 24. 9x2 - 4
25. x2 - 7x - 8 26. x2 + 13x + 36 27. x2 - 5x + 6
28. x2 + 5x + 4 29. x2 - 21x - 22 30. x2 + 13x + 40
31. 2x2 - 5x - 3 32. x2 + 10x - 11 33. x2 - 14x + 24
34. 5x2 + 4x - 12 35. 2x2 - 5x - 7 36. 2x2 + 13x + 15
37. 3x2 - 7x - 6 38. 3x2 + 16x + 21 39. x2 + 5x - 24
40. x2 + 34x - 72 41. x2 - 11x 42. 3x2 + 21x
43. x2 + 8x + 12 44. x2 - 10x + 24 45. x2 + 7x - 30
46. x2 - 2x - 168 47. x2 - x - 72 48. 4x2 - 25
49. x2 - 121 50. x2 + 17x + 16 51. 10x2 - 17x + 3
52. 4x2 + 12x + 9 53. 4x2 - 4x - 15 54. 9x2 - 4
55. x2 + 6x - 40 56. 2x2 - 8 57. x2 + 18x + 77
58. 2x2 - 98 59. x2 + 21x + 98 60. x2 + 20x + 84
61. 9x2 + 30x + 16 62. 8x2 - 6x - 27 63. x2 - 3x - 54
64. x2 - 169 65. 25x2 - 9 66. 7x2 + 49
67. 2x2 - 10x - 28 68. x2 + 8x + 12 69. x2 - 2x - 35
70. x2 + 2x - 63 71. 20x2 - 11x - 3 72. 12x2 + 4x - 5
73. 4x2 - 5x - 6 74. 8x2 + 22x - 21 75. 3x2 - 3x - 168
© P
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Algebra 2 Chapter 5 Lesson 5-4 Practice 5
Name Class Date
Practice 5-4 Factoring Quadratic Expressions
Factor each expression completely.
1. x2 + 4x + 4 2. x2 - 7x + 10 3. x2 + 7x - 8
4. x2 - 6x 5. 2x2 - 9x + 4 6. x2 + 2x - 35
7. x2 + 6x + 5 8. x2 - 9 9. x2 - 13x - 48
10. x2 - 4 11. 4x2 + x 12. x2 - 29x + 100
13. x2 - x - 6 14. 9x2 - 1 15. 3x2 - 2x
16. x2 - 64 17. x2 - 25 18. x2 - 81
19. x2 - 36 20. x2 - 100 21. x2 - 1
22. 4x2 - 1 23. 4x2 - 36 24. 9x2 - 4
25. x2 - 7x - 8 26. x2 + 13x + 36 27. x2 - 5x + 6
28. x2 + 5x + 4 29. x2 - 21x - 22 30. x2 + 13x + 40
31. 2x2 - 5x - 3 32. x2 + 10x - 11 33. x2 - 14x + 24
34. 5x2 + 4x - 12 35. 2x2 - 5x - 7 36. 2x2 + 13x + 15
37. 3x2 - 7x - 6 38. 3x2 + 16x + 21 39. x2 + 5x - 24
40. x2 + 34x - 72 41. x2 - 11x 42. 3x2 + 21x
43. x2 + 8x + 12 44. x2 - 10x + 24 45. x2 + 7x - 30
46. x2 - 2x - 168 47. x2 - x - 72 48. 4x2 - 25
49. x2 - 121 50. x2 + 17x + 16 51. 10x2 - 17x + 3
52. 4x2 + 12x + 9 53. 4x2 - 4x - 15 54. 9x2 - 4
55. x2 + 6x - 40 56. 2x2 - 8 57. x2 + 18x + 77
58. 2x2 - 98 59. x2 + 21x + 98 60. x2 + 20x + 84
61. 9x2 + 30x + 16 62. 8x2 - 6x - 27 63. x2 - 3x - 54
64. x2 - 169 65. 25x2 - 9 66. 7x2 + 49
67. 2x2 - 10x - 28 68. x2 + 8x + 12 69. x2 - 2x - 35
70. x2 + 2x - 63 71. 20x2 - 11x - 3 72. 12x2 + 4x - 5
73. 4x2 - 5x - 6 74. 8x2 + 22x - 21 75. 3x2 - 3x - 168
![Page 3: To find common and x Rewrite using the Distributive ... · of signs of ac and b. L1 L2 learning style: verbal learning style: visual A2_3eTE05_04_259-265 10/20/05 9:27 AM Page 259](https://reader036.vdocument.in/reader036/viewer/2022071117/600772bd2a652010e34bebea/html5/thumbnails/3.jpg)
Lesson 5-4 Factoring Quadratic Expressions 261
Factor each expression.a. x2 - 6x + 8 b. x2 - 7x + 12 c. x2 - 11x + 24
Note in Example 3 that the factors of c,-9 and -8, appear in the binomials of thefactored form, (x - 9)(x - 8). That is also the case for the factors in Example 2,and it is the case whenever a = 1. So when a = 1, you can skip a few steps infactoring. See Example 4.
If ac is negative, then the factors of ac have different signs.
Factoring When ac R 0
Factor x2 - x - 12.
Step 1 Find factors with product ac and sum b.
Since ac = -12 and b = -1, find factors with product -12 and sum -1.
Step 2 Since a = 1, you can write binomials using the factors you found.
x2 - x - 12
(x - 4)(x + 3) Use the factors you found.
Factor each expression.a. x2 - 14x - 32 b. x2 + 3x - 10 c. x2 + 4x - 5
If ac is positive, as in Examples 2 and 3, then the factors of ac have the same sign.This is true even when a 2 1.
Factoring When a u 1 and ac S 0
Factor 3x2 - 16x + 5.
Step 1 Find factors with product ac and sum b.
Since ac = 15 and b = -16, find negative factors with product 15 and sum -16.
Step 2 Rewrite the term bx using the factors you found. Then find commonfactors and rewrite the expression as the product of two binomials.
3x2 - 16x + 5
3x2 - x - 15x + 5 Rewrite bx.(')'* (')'*x(3x - 1) - 5(3x - 1) Find common factors.
(x - 5)(3x - 1) Rewrite using the Distributive Property.
Factor each expression. Check your answers.a. 2x2 + 11x + 12 b. 4x2 + 7x + 3 c. 2x2 - 7x + 6
55Quick Check
Factors of 15Sum of factors
!1, !15 !16
!3, !5 !8
EXAMPLEEXAMPLE55
44Quick Check
Factors of –12Sum of factors
1, !12!11
!1, 12 11
2, !6!4
!2, 6 4
3, !4!1
!3, 4 1
EXAMPLEEXAMPLE44
33Quick Check(x – 2)(x – 4) (x – 3)(x – 4) (x – 3)(x – 8)
(x ± 2)(x – 16) (x ± 5)(x – 2) (x ± 5)(x – 1)
(x ± 4)(2x ± 3) (x ± 1)(4x ± 3) (x – 2)(2x – 3)
261
Alternative Method
Have students draw a square withfour sections, such as the oneshown. Then follow these steps:1. Write the first and the last term
as shown.
2. Multiply a and c. Then findfactors of the product thathave a sum of b.4(-15) = -606(-10) = -60
and 6 + (-10) = -43. Write the factors with their
signs and variables in the othertwo boxes. Order does notmatter. Then find the GCF ofeach column and each row. AGCF is negative if both termsare negative.
(2x - 5)(2x + 3)
Additional Examples
Factor each expression.a. 15x2 + 25x + 100 5(3x2 ± 5x ± 20)b. 8m2 + 4m 4m(2m ± 1)
Factor x2 + 10x + 24. (x ± 4)(x ± 6)
Factor x2 - 14x + 33. (x – 3)(x – 11)
Factor x2 + 3x - 28. (x – 4)(x ± 7)
Factor 6x2 - 31x + 35. (3x – 5)(2x – 7)
Factor 6x2 + 11x - 35. (3x – 5)(2x ± 7)
66
55
44
33
22
11
4x2 6x
-10x -15
4x2
-15
EXAMPLEEXAMPLE66
2x
2x ± 3
–5
PowerPoint
A2_3eTE05_04_259-265 10/20/05 9:27 AM Page 261
Lesson 5-4 Factoring Quadratic Expressions 261
Factor each expression.a. x2 - 6x + 8 b. x2 - 7x + 12 c. x2 - 11x + 24
Note in Example 3 that the factors of c,-9 and -8, appear in the binomials of thefactored form, (x - 9)(x - 8). That is also the case for the factors in Example 2,and it is the case whenever a = 1. So when a = 1, you can skip a few steps infactoring. See Example 4.
If ac is negative, then the factors of ac have different signs.
Factoring When ac R 0
Factor x2 - x - 12.
Step 1 Find factors with product ac and sum b.
Since ac = -12 and b = -1, find factors with product -12 and sum -1.
Step 2 Since a = 1, you can write binomials using the factors you found.
x2 - x - 12
(x - 4)(x + 3) Use the factors you found.
Factor each expression.a. x2 - 14x - 32 b. x2 + 3x - 10 c. x2 + 4x - 5
If ac is positive, as in Examples 2 and 3, then the factors of ac have the same sign.This is true even when a 2 1.
Factoring When a u 1 and ac S 0
Factor 3x2 - 16x + 5.
Step 1 Find factors with product ac and sum b.
Since ac = 15 and b = -16, find negative factors with product 15 and sum -16.
Step 2 Rewrite the term bx using the factors you found. Then find commonfactors and rewrite the expression as the product of two binomials.
3x2 - 16x + 5
3x2 - x - 15x + 5 Rewrite bx.(')'* (')'*x(3x - 1) - 5(3x - 1) Find common factors.
(x - 5)(3x - 1) Rewrite using the Distributive Property.
Factor each expression. Check your answers.a. 2x2 + 11x + 12 b. 4x2 + 7x + 3 c. 2x2 - 7x + 6
55Quick Check
Factors of 15Sum of factors
!1, !15 !16
!3, !5 !8
EXAMPLEEXAMPLE55
44Quick Check
Factors of –12Sum of factors
1, !12!11
!1, 12 11
2, !6!4
!2, 6 4
3, !4!1
!3, 4 1
EXAMPLEEXAMPLE44
33Quick Check(x – 2)(x – 4) (x – 3)(x – 4) (x – 3)(x – 8)
(x ± 2)(x – 16) (x ± 5)(x – 2) (x ± 5)(x – 1)
(x ± 4)(2x ± 3) (x ± 1)(4x ± 3) (x – 2)(2x – 3)
261
Alternative Method
Have students draw a square withfour sections, such as the oneshown. Then follow these steps:1. Write the first and the last term
as shown.
2. Multiply a and c. Then findfactors of the product thathave a sum of b.4(-15) = -606(-10) = -60
and 6 + (-10) = -43. Write the factors with their
signs and variables in the othertwo boxes. Order does notmatter. Then find the GCF ofeach column and each row. AGCF is negative if both termsare negative.
(2x - 5)(2x + 3)
Additional Examples
Factor each expression.a. 15x2 + 25x + 100 5(3x2 ± 5x ± 20)b. 8m2 + 4m 4m(2m ± 1)
Factor x2 + 10x + 24. (x ± 4)(x ± 6)
Factor x2 - 14x + 33. (x – 3)(x – 11)
Factor x2 + 3x - 28. (x – 4)(x ± 7)
Factor 6x2 - 31x + 35. (3x – 5)(2x – 7)
Factor 6x2 + 11x - 35. (3x – 5)(2x ± 7)
66
55
44
33
22
11
4x2 6x
-10x -15
4x2
-15
EXAMPLEEXAMPLE66
2x
2x ± 3
–5
PowerPoint
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Algebra 2 Chapter 5 Lesson 5-4 Practice 5
Name Class Date
Practice 5-4 Factoring Quadratic Expressions
Factor each expression completely.
1. x2 + 4x + 4 2. x2 - 7x + 10 3. x2 + 7x - 8
4. x2 - 6x 5. 2x2 - 9x + 4 6. x2 + 2x - 35
7. x2 + 6x + 5 8. x2 - 9 9. x2 - 13x - 48
10. x2 - 4 11. 4x2 + x 12. x2 - 29x + 100
13. x2 - x - 6 14. 9x2 - 1 15. 3x2 - 2x
16. x2 - 64 17. x2 - 25 18. x2 - 81
19. x2 - 36 20. x2 - 100 21. x2 - 1
22. 4x2 - 1 23. 4x2 - 36 24. 9x2 - 4
25. x2 - 7x - 8 26. x2 + 13x + 36 27. x2 - 5x + 6
28. x2 + 5x + 4 29. x2 - 21x - 22 30. x2 + 13x + 40
31. 2x2 - 5x - 3 32. x2 + 10x - 11 33. x2 - 14x + 24
34. 5x2 + 4x - 12 35. 2x2 - 5x - 7 36. 2x2 + 13x + 15
37. 3x2 - 7x - 6 38. 3x2 + 16x + 21 39. x2 + 5x - 24
40. x2 + 34x - 72 41. x2 - 11x 42. 3x2 + 21x
43. x2 + 8x + 12 44. x2 - 10x + 24 45. x2 + 7x - 30
46. x2 - 2x - 168 47. x2 - x - 72 48. 4x2 - 25
49. x2 - 121 50. x2 + 17x + 16 51. 10x2 - 17x + 3
52. 4x2 + 12x + 9 53. 4x2 - 4x - 15 54. 9x2 - 4
55. x2 + 6x - 40 56. 2x2 - 8 57. x2 + 18x + 77
58. 2x2 - 98 59. x2 + 21x + 98 60. x2 + 20x + 84
61. 9x2 + 30x + 16 62. 8x2 - 6x - 27 63. x2 - 3x - 54
64. x2 - 169 65. 25x2 - 9 66. 7x2 + 49
67. 2x2 - 10x - 28 68. x2 + 8x + 12 69. x2 - 2x - 35
70. x2 + 2x - 63 71. 20x2 - 11x - 3 72. 12x2 + 4x - 5
73. 4x2 - 5x - 6 74. 8x2 + 22x - 21 75. 3x2 - 3x - 168
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Algebra 2 Chapter 5 Lesson 5-4 Practice 5
Name Class Date
Practice 5-4 Factoring Quadratic Expressions
Factor each expression completely.
1. x2 + 4x + 4 2. x2 - 7x + 10 3. x2 + 7x - 8
4. x2 - 6x 5. 2x2 - 9x + 4 6. x2 + 2x - 35
7. x2 + 6x + 5 8. x2 - 9 9. x2 - 13x - 48
10. x2 - 4 11. 4x2 + x 12. x2 - 29x + 100
13. x2 - x - 6 14. 9x2 - 1 15. 3x2 - 2x
16. x2 - 64 17. x2 - 25 18. x2 - 81
19. x2 - 36 20. x2 - 100 21. x2 - 1
22. 4x2 - 1 23. 4x2 - 36 24. 9x2 - 4
25. x2 - 7x - 8 26. x2 + 13x + 36 27. x2 - 5x + 6
28. x2 + 5x + 4 29. x2 - 21x - 22 30. x2 + 13x + 40
31. 2x2 - 5x - 3 32. x2 + 10x - 11 33. x2 - 14x + 24
34. 5x2 + 4x - 12 35. 2x2 - 5x - 7 36. 2x2 + 13x + 15
37. 3x2 - 7x - 6 38. 3x2 + 16x + 21 39. x2 + 5x - 24
40. x2 + 34x - 72 41. x2 - 11x 42. 3x2 + 21x
43. x2 + 8x + 12 44. x2 - 10x + 24 45. x2 + 7x - 30
46. x2 - 2x - 168 47. x2 - x - 72 48. 4x2 - 25
49. x2 - 121 50. x2 + 17x + 16 51. 10x2 - 17x + 3
52. 4x2 + 12x + 9 53. 4x2 - 4x - 15 54. 9x2 - 4
55. x2 + 6x - 40 56. 2x2 - 8 57. x2 + 18x + 77
58. 2x2 - 98 59. x2 + 21x + 98 60. x2 + 20x + 84
61. 9x2 + 30x + 16 62. 8x2 - 6x - 27 63. x2 - 3x - 54
64. x2 - 169 65. 25x2 - 9 66. 7x2 + 49
67. 2x2 - 10x - 28 68. x2 + 8x + 12 69. x2 - 2x - 35
70. x2 + 2x - 63 71. 20x2 - 11x - 3 72. 12x2 + 4x - 5
73. 4x2 - 5x - 6 74. 8x2 + 22x - 21 75. 3x2 - 3x - 168
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Algebra 2 Chapter 5 Lesson 5-4 Practice 5
Name Class Date
Practice 5-4 Factoring Quadratic Expressions
Factor each expression completely.
1. x2 + 4x + 4 2. x2 - 7x + 10 3. x2 + 7x - 8
4. x2 - 6x 5. 2x2 - 9x + 4 6. x2 + 2x - 35
7. x2 + 6x + 5 8. x2 - 9 9. x2 - 13x - 48
10. x2 - 4 11. 4x2 + x 12. x2 - 29x + 100
13. x2 - x - 6 14. 9x2 - 1 15. 3x2 - 2x
16. x2 - 64 17. x2 - 25 18. x2 - 81
19. x2 - 36 20. x2 - 100 21. x2 - 1
22. 4x2 - 1 23. 4x2 - 36 24. 9x2 - 4
25. x2 - 7x - 8 26. x2 + 13x + 36 27. x2 - 5x + 6
28. x2 + 5x + 4 29. x2 - 21x - 22 30. x2 + 13x + 40
31. 2x2 - 5x - 3 32. x2 + 10x - 11 33. x2 - 14x + 24
34. 5x2 + 4x - 12 35. 2x2 - 5x - 7 36. 2x2 + 13x + 15
37. 3x2 - 7x - 6 38. 3x2 + 16x + 21 39. x2 + 5x - 24
40. x2 + 34x - 72 41. x2 - 11x 42. 3x2 + 21x
43. x2 + 8x + 12 44. x2 - 10x + 24 45. x2 + 7x - 30
46. x2 - 2x - 168 47. x2 - x - 72 48. 4x2 - 25
49. x2 - 121 50. x2 + 17x + 16 51. 10x2 - 17x + 3
52. 4x2 + 12x + 9 53. 4x2 - 4x - 15 54. 9x2 - 4
55. x2 + 6x - 40 56. 2x2 - 8 57. x2 + 18x + 77
58. 2x2 - 98 59. x2 + 21x + 98 60. x2 + 20x + 84
61. 9x2 + 30x + 16 62. 8x2 - 6x - 27 63. x2 - 3x - 54
64. x2 - 169 65. 25x2 - 9 66. 7x2 + 49
67. 2x2 - 10x - 28 68. x2 + 8x + 12 69. x2 - 2x - 35
70. x2 + 2x - 63 71. 20x2 - 11x - 3 72. 12x2 + 4x - 5
73. 4x2 - 5x - 6 74. 8x2 + 22x - 21 75. 3x2 - 3x - 168
© P
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Algebra 2 Chapter 5 Lesson 5-4 Practice 5
Name Class Date
Practice 5-4 Factoring Quadratic Expressions
Factor each expression completely.
1. x2 + 4x + 4 2. x2 - 7x + 10 3. x2 + 7x - 8
4. x2 - 6x 5. 2x2 - 9x + 4 6. x2 + 2x - 35
7. x2 + 6x + 5 8. x2 - 9 9. x2 - 13x - 48
10. x2 - 4 11. 4x2 + x 12. x2 - 29x + 100
13. x2 - x - 6 14. 9x2 - 1 15. 3x2 - 2x
16. x2 - 64 17. x2 - 25 18. x2 - 81
19. x2 - 36 20. x2 - 100 21. x2 - 1
22. 4x2 - 1 23. 4x2 - 36 24. 9x2 - 4
25. x2 - 7x - 8 26. x2 + 13x + 36 27. x2 - 5x + 6
28. x2 + 5x + 4 29. x2 - 21x - 22 30. x2 + 13x + 40
31. 2x2 - 5x - 3 32. x2 + 10x - 11 33. x2 - 14x + 24
34. 5x2 + 4x - 12 35. 2x2 - 5x - 7 36. 2x2 + 13x + 15
37. 3x2 - 7x - 6 38. 3x2 + 16x + 21 39. x2 + 5x - 24
40. x2 + 34x - 72 41. x2 - 11x 42. 3x2 + 21x
43. x2 + 8x + 12 44. x2 - 10x + 24 45. x2 + 7x - 30
46. x2 - 2x - 168 47. x2 - x - 72 48. 4x2 - 25
49. x2 - 121 50. x2 + 17x + 16 51. 10x2 - 17x + 3
52. 4x2 + 12x + 9 53. 4x2 - 4x - 15 54. 9x2 - 4
55. x2 + 6x - 40 56. 2x2 - 8 57. x2 + 18x + 77
58. 2x2 - 98 59. x2 + 21x + 98 60. x2 + 20x + 84
61. 9x2 + 30x + 16 62. 8x2 - 6x - 27 63. x2 - 3x - 54
64. x2 - 169 65. 25x2 - 9 66. 7x2 + 49
67. 2x2 - 10x - 28 68. x2 + 8x + 12 69. x2 - 2x - 35
70. x2 + 2x - 63 71. 20x2 - 11x - 3 72. 12x2 + 4x - 5
73. 4x2 - 5x - 6 74. 8x2 + 22x - 21 75. 3x2 - 3x - 168
262 Chapter 5 Quadratic Equations and Functions
Again, if ac is negative, then the factors of ac have different signs.
Factoring When a u 1 and ac R 0
Factor 4x2 - 4x - 15.
Step 1 Find factors with product ac and sum b.
Since ac = -60 and b = -4, find factors with product -60 and sum -4.
Step 2 Rewrite the term bx using the factors you found. Then find commonfactors and rewrite the expression as the product of two binomials.
4x2 - 4x - 154x2 + 6x - 10x - 15 Rewrite bx.(')'* (')'*2x(2x + 3) - 5(2x + 3) Find common factors.
(2x - 5)(2x + 3) Rewrite using the Distributive Property.
Factor each expression.a. 2x2 + 7x - 9 b. 3x2 - 16x - 12 c. 4x2 + 5x - 6
A is the product you obtain when you square a binomial. An example is x2 + 10x + 25, which can be written as (x + 5)2. The first term and the third term of the trinomial are always positive, as they represent thesquares of the two terms of the binomial. The middle term of the trinomial is twotimes the product of the terms of the binomial.
Factoring a Perfect Square Trinomial
Factor 9x2 - 42x + 49.
9x2 - 42x + 49 = (3x)2 - 42x + 72 Rewrite the first and third terms as squares.
= (3x)2 - 2(3x)(7) + 72 Rewrite the middle term to verify the perfect square trinomial pattern.
= (3x - 7)2 a2 – 2ab ± b2 ≠ (a – b)2
Factor each expression.a. 4x2 + 12x + 9 b. 64x2 - 16x + 1 c. 25x2 + 90x + 81
77Quick Check
EXAMPLEEXAMPLE77
perfect square trinomial
66Quick Check
Factors of –60Sum of factors
1, !60!59
!1, 60 59
2, !30!28
!2, 30 28
3, !20!17
!3, 2017
Factors of –60Sum of factors
4, !15!11
!4, 15 11
5, !12!7
!5, 12 7
6, !10!4
!6, 10 4
EXAMPLEEXAMPLE66
12 Factoring Special Expressions
Key Concepts Property Factoring Perfect Square Trinomials
a2 + 2ab + b2 = (a + b)2 a2 - 2ab + b2 = (a - b)2
(x – 1)(2x ± 9) (x – 6)(3x ± 2) (x ± 2)(4x – 3)
(2x ± 3)2 (8x – 1)2 (5x ± 9)2
262
Guided Instruction
Teaching Tip
Point out that you can only usethis formula for the difference oftwo squares. If it was the sum oftwo squares, the last term wouldbe positive. Therefore the signs inthe factors would have to be thesame resulting in a middle termwhen multiplied.
Additional Examples
Factor 100x2 + 180x + 81. (10x ± 9)2
A square photo is enclosed ina square frame, as shown in thediagram. Express the area of theframe (the shaded area) incompletely factored form. (x ± 7)(x – 7) in.2
Resources• Daily Notetaking Guide 5-4• Daily Notetaking Guide 5-4—
Adapted Instruction
Closure
Ask: What is usually the first step in factoring a quadratictrinomial that is not a perfectsquare trinomial and whose terms have no common factorgreater than 1? Find twointegers that have product acand sum b.
L1
L3
x in.7 in.
88
77
EXAMPLEEXAMPLE88
PowerPoint
A2_3eTE05_04_259-265 10/20/05 9:27 AM Page 262
262 Chapter 5 Quadratic Equations and Functions
Again, if ac is negative, then the factors of ac have different signs.
Factoring When a u 1 and ac R 0
Factor 4x2 - 4x - 15.
Step 1 Find factors with product ac and sum b.
Since ac = -60 and b = -4, find factors with product -60 and sum -4.
Step 2 Rewrite the term bx using the factors you found. Then find commonfactors and rewrite the expression as the product of two binomials.
4x2 - 4x - 154x2 + 6x - 10x - 15 Rewrite bx.(')'* (')'*2x(2x + 3) - 5(2x + 3) Find common factors.
(2x - 5)(2x + 3) Rewrite using the Distributive Property.
Factor each expression.a. 2x2 + 7x - 9 b. 3x2 - 16x - 12 c. 4x2 + 5x - 6
A is the product you obtain when you square a binomial. An example is x2 + 10x + 25, which can be written as (x + 5)2. The first term and the third term of the trinomial are always positive, as they represent thesquares of the two terms of the binomial. The middle term of the trinomial is twotimes the product of the terms of the binomial.
Factoring a Perfect Square Trinomial
Factor 9x2 - 42x + 49.
9x2 - 42x + 49 = (3x)2 - 42x + 72 Rewrite the first and third terms as squares.
= (3x)2 - 2(3x)(7) + 72 Rewrite the middle term to verify the perfect square trinomial pattern.
= (3x - 7)2 a2 – 2ab ± b2 ≠ (a – b)2
Factor each expression.a. 4x2 + 12x + 9 b. 64x2 - 16x + 1 c. 25x2 + 90x + 81
77Quick Check
EXAMPLEEXAMPLE77
perfect square trinomial
66Quick Check
Factors of –60Sum of factors
1, !60!59
!1, 60 59
2, !30!28
!2, 30 28
3, !20!17
!3, 2017
Factors of –60Sum of factors
4, !15!11
!4, 15 11
5, !12!7
!5, 12 7
6, !10!4
!6, 10 4
EXAMPLEEXAMPLE66
12 Factoring Special Expressions
Key Concepts Property Factoring Perfect Square Trinomials
a2 + 2ab + b2 = (a + b)2 a2 - 2ab + b2 = (a - b)2
(x – 1)(2x ± 9) (x – 6)(3x ± 2) (x ± 2)(4x – 3)
(2x ± 3)2 (8x – 1)2 (5x ± 9)2
262
Guided Instruction
Teaching Tip
Point out that you can only usethis formula for the difference oftwo squares. If it was the sum oftwo squares, the last term wouldbe positive. Therefore the signs inthe factors would have to be thesame resulting in a middle termwhen multiplied.
Additional Examples
Factor 100x2 + 180x + 81. (10x ± 9)2
A square photo is enclosed ina square frame, as shown in thediagram. Express the area of theframe (the shaded area) incompletely factored form. (x ± 7)(x – 7) in.2
Resources• Daily Notetaking Guide 5-4• Daily Notetaking Guide 5-4—
Adapted Instruction
Closure
Ask: What is usually the first step in factoring a quadratictrinomial that is not a perfectsquare trinomial and whose terms have no common factorgreater than 1? Find twointegers that have product acand sum b.
L1
L3
x in.7 in.
88
77
EXAMPLEEXAMPLE88
PowerPoint
A2_3eTE05_04_259-265 10/20/05 9:27 AM Page 262
© P
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Algebra 2 Chapter 5 Lesson 5-4 Practice 5
Name Class Date
Practice 5-4 Factoring Quadratic Expressions
Factor each expression completely.
1. x2 + 4x + 4 2. x2 - 7x + 10 3. x2 + 7x - 8
4. x2 - 6x 5. 2x2 - 9x + 4 6. x2 + 2x - 35
7. x2 + 6x + 5 8. x2 - 9 9. x2 - 13x - 48
10. x2 - 4 11. 4x2 + x 12. x2 - 29x + 100
13. x2 - x - 6 14. 9x2 - 1 15. 3x2 - 2x
16. x2 - 64 17. x2 - 25 18. x2 - 81
19. x2 - 36 20. x2 - 100 21. x2 - 1
22. 4x2 - 1 23. 4x2 - 36 24. 9x2 - 4
25. x2 - 7x - 8 26. x2 + 13x + 36 27. x2 - 5x + 6
28. x2 + 5x + 4 29. x2 - 21x - 22 30. x2 + 13x + 40
31. 2x2 - 5x - 3 32. x2 + 10x - 11 33. x2 - 14x + 24
34. 5x2 + 4x - 12 35. 2x2 - 5x - 7 36. 2x2 + 13x + 15
37. 3x2 - 7x - 6 38. 3x2 + 16x + 21 39. x2 + 5x - 24
40. x2 + 34x - 72 41. x2 - 11x 42. 3x2 + 21x
43. x2 + 8x + 12 44. x2 - 10x + 24 45. x2 + 7x - 30
46. x2 - 2x - 168 47. x2 - x - 72 48. 4x2 - 25
49. x2 - 121 50. x2 + 17x + 16 51. 10x2 - 17x + 3
52. 4x2 + 12x + 9 53. 4x2 - 4x - 15 54. 9x2 - 4
55. x2 + 6x - 40 56. 2x2 - 8 57. x2 + 18x + 77
58. 2x2 - 98 59. x2 + 21x + 98 60. x2 + 20x + 84
61. 9x2 + 30x + 16 62. 8x2 - 6x - 27 63. x2 - 3x - 54
64. x2 - 169 65. 25x2 - 9 66. 7x2 + 49
67. 2x2 - 10x - 28 68. x2 + 8x + 12 69. x2 - 2x - 35
70. x2 + 2x - 63 71. 20x2 - 11x - 3 72. 12x2 + 4x - 5
73. 4x2 - 5x - 6 74. 8x2 + 22x - 21 75. 3x2 - 3x - 168
© P
ears
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All
righ
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Algebra 2 Chapter 5 Lesson 5-4 Practice 5
Name Class Date
Practice 5-4 Factoring Quadratic Expressions
Factor each expression completely.
1. x2 + 4x + 4 2. x2 - 7x + 10 3. x2 + 7x - 8
4. x2 - 6x 5. 2x2 - 9x + 4 6. x2 + 2x - 35
7. x2 + 6x + 5 8. x2 - 9 9. x2 - 13x - 48
10. x2 - 4 11. 4x2 + x 12. x2 - 29x + 100
13. x2 - x - 6 14. 9x2 - 1 15. 3x2 - 2x
16. x2 - 64 17. x2 - 25 18. x2 - 81
19. x2 - 36 20. x2 - 100 21. x2 - 1
22. 4x2 - 1 23. 4x2 - 36 24. 9x2 - 4
25. x2 - 7x - 8 26. x2 + 13x + 36 27. x2 - 5x + 6
28. x2 + 5x + 4 29. x2 - 21x - 22 30. x2 + 13x + 40
31. 2x2 - 5x - 3 32. x2 + 10x - 11 33. x2 - 14x + 24
34. 5x2 + 4x - 12 35. 2x2 - 5x - 7 36. 2x2 + 13x + 15
37. 3x2 - 7x - 6 38. 3x2 + 16x + 21 39. x2 + 5x - 24
40. x2 + 34x - 72 41. x2 - 11x 42. 3x2 + 21x
43. x2 + 8x + 12 44. x2 - 10x + 24 45. x2 + 7x - 30
46. x2 - 2x - 168 47. x2 - x - 72 48. 4x2 - 25
49. x2 - 121 50. x2 + 17x + 16 51. 10x2 - 17x + 3
52. 4x2 + 12x + 9 53. 4x2 - 4x - 15 54. 9x2 - 4
55. x2 + 6x - 40 56. 2x2 - 8 57. x2 + 18x + 77
58. 2x2 - 98 59. x2 + 21x + 98 60. x2 + 20x + 84
61. 9x2 + 30x + 16 62. 8x2 - 6x - 27 63. x2 - 3x - 54
64. x2 - 169 65. 25x2 - 9 66. 7x2 + 49
67. 2x2 - 10x - 28 68. x2 + 8x + 12 69. x2 - 2x - 35
70. x2 + 2x - 63 71. 20x2 - 11x - 3 72. 12x2 + 4x - 5
73. 4x2 - 5x - 6 74. 8x2 + 22x - 21 75. 3x2 - 3x - 168
© P
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Algebra 2 Chapter 5 Lesson 5-4 Practice 5
Name Class Date
Practice 5-4 Factoring Quadratic Expressions
Factor each expression completely.
1. x2 + 4x + 4 2. x2 - 7x + 10 3. x2 + 7x - 8
4. x2 - 6x 5. 2x2 - 9x + 4 6. x2 + 2x - 35
7. x2 + 6x + 5 8. x2 - 9 9. x2 - 13x - 48
10. x2 - 4 11. 4x2 + x 12. x2 - 29x + 100
13. x2 - x - 6 14. 9x2 - 1 15. 3x2 - 2x
16. x2 - 64 17. x2 - 25 18. x2 - 81
19. x2 - 36 20. x2 - 100 21. x2 - 1
22. 4x2 - 1 23. 4x2 - 36 24. 9x2 - 4
25. x2 - 7x - 8 26. x2 + 13x + 36 27. x2 - 5x + 6
28. x2 + 5x + 4 29. x2 - 21x - 22 30. x2 + 13x + 40
31. 2x2 - 5x - 3 32. x2 + 10x - 11 33. x2 - 14x + 24
34. 5x2 + 4x - 12 35. 2x2 - 5x - 7 36. 2x2 + 13x + 15
37. 3x2 - 7x - 6 38. 3x2 + 16x + 21 39. x2 + 5x - 24
40. x2 + 34x - 72 41. x2 - 11x 42. 3x2 + 21x
43. x2 + 8x + 12 44. x2 - 10x + 24 45. x2 + 7x - 30
46. x2 - 2x - 168 47. x2 - x - 72 48. 4x2 - 25
49. x2 - 121 50. x2 + 17x + 16 51. 10x2 - 17x + 3
52. 4x2 + 12x + 9 53. 4x2 - 4x - 15 54. 9x2 - 4
55. x2 + 6x - 40 56. 2x2 - 8 57. x2 + 18x + 77
58. 2x2 - 98 59. x2 + 21x + 98 60. x2 + 20x + 84
61. 9x2 + 30x + 16 62. 8x2 - 6x - 27 63. x2 - 3x - 54
64. x2 - 169 65. 25x2 - 9 66. 7x2 + 49
67. 2x2 - 10x - 28 68. x2 + 8x + 12 69. x2 - 2x - 35
70. x2 + 2x - 63 71. 20x2 - 11x - 3 72. 12x2 + 4x - 5
73. 4x2 - 5x - 6 74. 8x2 + 22x - 21 75. 3x2 - 3x - 168
![Page 4: To find common and x Rewrite using the Distributive ... · of signs of ac and b. L1 L2 learning style: verbal learning style: visual A2_3eTE05_04_259-265 10/20/05 9:27 AM Page 259](https://reader036.vdocument.in/reader036/viewer/2022071117/600772bd2a652010e34bebea/html5/thumbnails/4.jpg)
262 Chapter 5 Quadratic Equations and Functions
Again, if ac is negative, then the factors of ac have different signs.
Factoring When a u 1 and ac R 0
Factor 4x2 - 4x - 15.
Step 1 Find factors with product ac and sum b.
Since ac = -60 and b = -4, find factors with product -60 and sum -4.
Step 2 Rewrite the term bx using the factors you found. Then find commonfactors and rewrite the expression as the product of two binomials.
4x2 - 4x - 154x2 + 6x - 10x - 15 Rewrite bx.(')'* (')'*2x(2x + 3) - 5(2x + 3) Find common factors.
(2x - 5)(2x + 3) Rewrite using the Distributive Property.
Factor each expression.a. 2x2 + 7x - 9 b. 3x2 - 16x - 12 c. 4x2 + 5x - 6
A is the product you obtain when you square a binomial. An example is x2 + 10x + 25, which can be written as (x + 5)2. The first term and the third term of the trinomial are always positive, as they represent thesquares of the two terms of the binomial. The middle term of the trinomial is twotimes the product of the terms of the binomial.
Factoring a Perfect Square Trinomial
Factor 9x2 - 42x + 49.
9x2 - 42x + 49 = (3x)2 - 42x + 72 Rewrite the first and third terms as squares.
= (3x)2 - 2(3x)(7) + 72 Rewrite the middle term to verify the perfect square trinomial pattern.
= (3x - 7)2 a2 – 2ab ± b2 ≠ (a – b)2
Factor each expression.a. 4x2 + 12x + 9 b. 64x2 - 16x + 1 c. 25x2 + 90x + 81
77Quick Check
EXAMPLEEXAMPLE77
perfect square trinomial
66Quick Check
Factors of –60Sum of factors
1, !60!59
!1, 60 59
2, !30!28
!2, 30 28
3, !20!17
!3, 2017
Factors of –60Sum of factors
4, !15!11
!4, 15 11
5, !12!7
!5, 12 7
6, !10!4
!6, 10 4
EXAMPLEEXAMPLE66
12 Factoring Special Expressions
Key Concepts Property Factoring Perfect Square Trinomials
a2 + 2ab + b2 = (a + b)2 a2 - 2ab + b2 = (a - b)2
(x – 1)(2x ± 9) (x – 6)(3x ± 2) (x ± 2)(4x – 3)
(2x ± 3)2 (8x – 1)2 (5x ± 9)2
262
Guided Instruction
Teaching Tip
Point out that you can only usethis formula for the difference oftwo squares. If it was the sum oftwo squares, the last term wouldbe positive. Therefore the signs inthe factors would have to be thesame resulting in a middle termwhen multiplied.
Additional Examples
Factor 100x2 + 180x + 81. (10x ± 9)2
A square photo is enclosed ina square frame, as shown in thediagram. Express the area of theframe (the shaded area) incompletely factored form. (x ± 7)(x – 7) in.2
Resources• Daily Notetaking Guide 5-4• Daily Notetaking Guide 5-4—
Adapted Instruction
Closure
Ask: What is usually the first step in factoring a quadratictrinomial that is not a perfectsquare trinomial and whose terms have no common factorgreater than 1? Find twointegers that have product acand sum b.
L1
L3
x in.7 in.
88
77
EXAMPLEEXAMPLE88
PowerPoint
A2_3eTE05_04_259-265 10/20/05 9:27 AM Page 262
262 Chapter 5 Quadratic Equations and Functions
Again, if ac is negative, then the factors of ac have different signs.
Factoring When a u 1 and ac R 0
Factor 4x2 - 4x - 15.
Step 1 Find factors with product ac and sum b.
Since ac = -60 and b = -4, find factors with product -60 and sum -4.
Step 2 Rewrite the term bx using the factors you found. Then find commonfactors and rewrite the expression as the product of two binomials.
4x2 - 4x - 154x2 + 6x - 10x - 15 Rewrite bx.(')'* (')'*2x(2x + 3) - 5(2x + 3) Find common factors.
(2x - 5)(2x + 3) Rewrite using the Distributive Property.
Factor each expression.a. 2x2 + 7x - 9 b. 3x2 - 16x - 12 c. 4x2 + 5x - 6
A is the product you obtain when you square a binomial. An example is x2 + 10x + 25, which can be written as (x + 5)2. The first term and the third term of the trinomial are always positive, as they represent thesquares of the two terms of the binomial. The middle term of the trinomial is twotimes the product of the terms of the binomial.
Factoring a Perfect Square Trinomial
Factor 9x2 - 42x + 49.
9x2 - 42x + 49 = (3x)2 - 42x + 72 Rewrite the first and third terms as squares.
= (3x)2 - 2(3x)(7) + 72 Rewrite the middle term to verify the perfect square trinomial pattern.
= (3x - 7)2 a2 – 2ab ± b2 ≠ (a – b)2
Factor each expression.a. 4x2 + 12x + 9 b. 64x2 - 16x + 1 c. 25x2 + 90x + 81
77Quick Check
EXAMPLEEXAMPLE77
perfect square trinomial
66Quick Check
Factors of –60Sum of factors
1, !60!59
!1, 60 59
2, !30!28
!2, 30 28
3, !20!17
!3, 2017
Factors of –60Sum of factors
4, !15!11
!4, 15 11
5, !12!7
!5, 12 7
6, !10!4
!6, 10 4
EXAMPLEEXAMPLE66
12 Factoring Special Expressions
Key Concepts Property Factoring Perfect Square Trinomials
a2 + 2ab + b2 = (a + b)2 a2 - 2ab + b2 = (a - b)2
(x – 1)(2x ± 9) (x – 6)(3x ± 2) (x ± 2)(4x – 3)
(2x ± 3)2 (8x – 1)2 (5x ± 9)2
262
Guided Instruction
Teaching Tip
Point out that you can only usethis formula for the difference oftwo squares. If it was the sum oftwo squares, the last term wouldbe positive. Therefore the signs inthe factors would have to be thesame resulting in a middle termwhen multiplied.
Additional Examples
Factor 100x2 + 180x + 81. (10x ± 9)2
A square photo is enclosed ina square frame, as shown in thediagram. Express the area of theframe (the shaded area) incompletely factored form. (x ± 7)(x – 7) in.2
Resources• Daily Notetaking Guide 5-4• Daily Notetaking Guide 5-4—
Adapted Instruction
Closure
Ask: What is usually the first step in factoring a quadratictrinomial that is not a perfectsquare trinomial and whose terms have no common factorgreater than 1? Find twointegers that have product acand sum b.
L1
L3
x in.7 in.
88
77
EXAMPLEEXAMPLE88
PowerPoint
A2_3eTE05_04_259-265 10/20/05 9:27 AM Page 262
262 Chapter 5 Quadratic Equations and Functions
Again, if ac is negative, then the factors of ac have different signs.
Factoring When a u 1 and ac R 0
Factor 4x2 - 4x - 15.
Step 1 Find factors with product ac and sum b.
Since ac = -60 and b = -4, find factors with product -60 and sum -4.
Step 2 Rewrite the term bx using the factors you found. Then find commonfactors and rewrite the expression as the product of two binomials.
4x2 - 4x - 154x2 + 6x - 10x - 15 Rewrite bx.(')'* (')'*2x(2x + 3) - 5(2x + 3) Find common factors.
(2x - 5)(2x + 3) Rewrite using the Distributive Property.
Factor each expression.a. 2x2 + 7x - 9 b. 3x2 - 16x - 12 c. 4x2 + 5x - 6
A is the product you obtain when you square a binomial. An example is x2 + 10x + 25, which can be written as (x + 5)2. The first term and the third term of the trinomial are always positive, as they represent thesquares of the two terms of the binomial. The middle term of the trinomial is twotimes the product of the terms of the binomial.
Factoring a Perfect Square Trinomial
Factor 9x2 - 42x + 49.
9x2 - 42x + 49 = (3x)2 - 42x + 72 Rewrite the first and third terms as squares.
= (3x)2 - 2(3x)(7) + 72 Rewrite the middle term to verify the perfect square trinomial pattern.
= (3x - 7)2 a2 – 2ab ± b2 ≠ (a – b)2
Factor each expression.a. 4x2 + 12x + 9 b. 64x2 - 16x + 1 c. 25x2 + 90x + 81
77Quick Check
EXAMPLEEXAMPLE77
perfect square trinomial
66Quick Check
Factors of –60Sum of factors
1, !60!59
!1, 60 59
2, !30!28
!2, 30 28
3, !20!17
!3, 2017
Factors of –60Sum of factors
4, !15!11
!4, 15 11
5, !12!7
!5, 12 7
6, !10!4
!6, 10 4
EXAMPLEEXAMPLE66
12 Factoring Special Expressions
Key Concepts Property Factoring Perfect Square Trinomials
a2 + 2ab + b2 = (a + b)2 a2 - 2ab + b2 = (a - b)2
(x – 1)(2x ± 9) (x – 6)(3x ± 2) (x ± 2)(4x – 3)
(2x ± 3)2 (8x – 1)2 (5x ± 9)2
262
Guided Instruction
Teaching Tip
Point out that you can only usethis formula for the difference oftwo squares. If it was the sum oftwo squares, the last term wouldbe positive. Therefore the signs inthe factors would have to be thesame resulting in a middle termwhen multiplied.
Additional Examples
Factor 100x2 + 180x + 81. (10x ± 9)2
A square photo is enclosed ina square frame, as shown in thediagram. Express the area of theframe (the shaded area) incompletely factored form. (x ± 7)(x – 7) in.2
Resources• Daily Notetaking Guide 5-4• Daily Notetaking Guide 5-4—
Adapted Instruction
Closure
Ask: What is usually the first step in factoring a quadratictrinomial that is not a perfectsquare trinomial and whose terms have no common factorgreater than 1? Find twointegers that have product acand sum b.
L1
L3
x in.7 in.
88
77
EXAMPLEEXAMPLE88
PowerPoint
A2_3eTE05_04_259-265 10/20/05 9:27 AM Page 262
262 Chapter 5 Quadratic Equations and Functions
Again, if ac is negative, then the factors of ac have different signs.
Factoring When a u 1 and ac R 0
Factor 4x2 - 4x - 15.
Step 1 Find factors with product ac and sum b.
Since ac = -60 and b = -4, find factors with product -60 and sum -4.
Step 2 Rewrite the term bx using the factors you found. Then find commonfactors and rewrite the expression as the product of two binomials.
4x2 - 4x - 154x2 + 6x - 10x - 15 Rewrite bx.(')'* (')'*2x(2x + 3) - 5(2x + 3) Find common factors.
(2x - 5)(2x + 3) Rewrite using the Distributive Property.
Factor each expression.a. 2x2 + 7x - 9 b. 3x2 - 16x - 12 c. 4x2 + 5x - 6
A is the product you obtain when you square a binomial. An example is x2 + 10x + 25, which can be written as (x + 5)2. The first term and the third term of the trinomial are always positive, as they represent thesquares of the two terms of the binomial. The middle term of the trinomial is twotimes the product of the terms of the binomial.
Factoring a Perfect Square Trinomial
Factor 9x2 - 42x + 49.
9x2 - 42x + 49 = (3x)2 - 42x + 72 Rewrite the first and third terms as squares.
= (3x)2 - 2(3x)(7) + 72 Rewrite the middle term to verify the perfect square trinomial pattern.
= (3x - 7)2 a2 – 2ab ± b2 ≠ (a – b)2
Factor each expression.a. 4x2 + 12x + 9 b. 64x2 - 16x + 1 c. 25x2 + 90x + 81
77Quick Check
EXAMPLEEXAMPLE77
perfect square trinomial
66Quick Check
Factors of –60Sum of factors
1, !60!59
!1, 60 59
2, !30!28
!2, 30 28
3, !20!17
!3, 2017
Factors of –60Sum of factors
4, !15!11
!4, 15 11
5, !12!7
!5, 12 7
6, !10!4
!6, 10 4
EXAMPLEEXAMPLE66
12 Factoring Special Expressions
Key Concepts Property Factoring Perfect Square Trinomials
a2 + 2ab + b2 = (a + b)2 a2 - 2ab + b2 = (a - b)2
(x – 1)(2x ± 9) (x – 6)(3x ± 2) (x ± 2)(4x – 3)
(2x ± 3)2 (8x – 1)2 (5x ± 9)2
262
Guided Instruction
Teaching Tip
Point out that you can only usethis formula for the difference oftwo squares. If it was the sum oftwo squares, the last term wouldbe positive. Therefore the signs inthe factors would have to be thesame resulting in a middle termwhen multiplied.
Additional Examples
Factor 100x2 + 180x + 81. (10x ± 9)2
A square photo is enclosed ina square frame, as shown in thediagram. Express the area of theframe (the shaded area) incompletely factored form. (x ± 7)(x – 7) in.2
Resources• Daily Notetaking Guide 5-4• Daily Notetaking Guide 5-4—
Adapted Instruction
Closure
Ask: What is usually the first step in factoring a quadratictrinomial that is not a perfectsquare trinomial and whose terms have no common factorgreater than 1? Find twointegers that have product acand sum b.
L1
L3
x in.7 in.
88
77
EXAMPLEEXAMPLE88
PowerPoint
A2_3eTE05_04_259-265 10/20/05 9:27 AM Page 262
262 Chapter 5 Quadratic Equations and Functions
Again, if ac is negative, then the factors of ac have different signs.
Factoring When a u 1 and ac R 0
Factor 4x2 - 4x - 15.
Step 1 Find factors with product ac and sum b.
Since ac = -60 and b = -4, find factors with product -60 and sum -4.
Step 2 Rewrite the term bx using the factors you found. Then find commonfactors and rewrite the expression as the product of two binomials.
4x2 - 4x - 154x2 + 6x - 10x - 15 Rewrite bx.(')'* (')'*2x(2x + 3) - 5(2x + 3) Find common factors.
(2x - 5)(2x + 3) Rewrite using the Distributive Property.
Factor each expression.a. 2x2 + 7x - 9 b. 3x2 - 16x - 12 c. 4x2 + 5x - 6
A is the product you obtain when you square a binomial. An example is x2 + 10x + 25, which can be written as (x + 5)2. The first term and the third term of the trinomial are always positive, as they represent thesquares of the two terms of the binomial. The middle term of the trinomial is twotimes the product of the terms of the binomial.
Factoring a Perfect Square Trinomial
Factor 9x2 - 42x + 49.
9x2 - 42x + 49 = (3x)2 - 42x + 72 Rewrite the first and third terms as squares.
= (3x)2 - 2(3x)(7) + 72 Rewrite the middle term to verify the perfect square trinomial pattern.
= (3x - 7)2 a2 – 2ab ± b2 ≠ (a – b)2
Factor each expression.a. 4x2 + 12x + 9 b. 64x2 - 16x + 1 c. 25x2 + 90x + 81
77Quick Check
EXAMPLEEXAMPLE77
perfect square trinomial
66Quick Check
Factors of –60Sum of factors
1, !60!59
!1, 60 59
2, !30!28
!2, 30 28
3, !20!17
!3, 2017
Factors of –60Sum of factors
4, !15!11
!4, 15 11
5, !12!7
!5, 12 7
6, !10!4
!6, 10 4
EXAMPLEEXAMPLE66
12 Factoring Special Expressions
Key Concepts Property Factoring Perfect Square Trinomials
a2 + 2ab + b2 = (a + b)2 a2 - 2ab + b2 = (a - b)2
(x – 1)(2x ± 9) (x – 6)(3x ± 2) (x ± 2)(4x – 3)
(2x ± 3)2 (8x – 1)2 (5x ± 9)2
262
Guided Instruction
Teaching Tip
Point out that you can only usethis formula for the difference oftwo squares. If it was the sum oftwo squares, the last term wouldbe positive. Therefore the signs inthe factors would have to be thesame resulting in a middle termwhen multiplied.
Additional Examples
Factor 100x2 + 180x + 81. (10x ± 9)2
A square photo is enclosed ina square frame, as shown in thediagram. Express the area of theframe (the shaded area) incompletely factored form. (x ± 7)(x – 7) in.2
Resources• Daily Notetaking Guide 5-4• Daily Notetaking Guide 5-4—
Adapted Instruction
Closure
Ask: What is usually the first step in factoring a quadratictrinomial that is not a perfectsquare trinomial and whose terms have no common factorgreater than 1? Find twointegers that have product acand sum b.
L1
L3
x in.7 in.
88
77
EXAMPLEEXAMPLE88
PowerPoint
A2_3eTE05_04_259-265 10/20/05 9:27 AM Page 262
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Algebra 2 Chapter 5 Lesson 5-4 Practice 5
Name Class Date
Practice 5-4 Factoring Quadratic Expressions
Factor each expression completely.
1. x2 + 4x + 4 2. x2 - 7x + 10 3. x2 + 7x - 8
4. x2 - 6x 5. 2x2 - 9x + 4 6. x2 + 2x - 35
7. x2 + 6x + 5 8. x2 - 9 9. x2 - 13x - 48
10. x2 - 4 11. 4x2 + x 12. x2 - 29x + 100
13. x2 - x - 6 14. 9x2 - 1 15. 3x2 - 2x
16. x2 - 64 17. x2 - 25 18. x2 - 81
19. x2 - 36 20. x2 - 100 21. x2 - 1
22. 4x2 - 1 23. 4x2 - 36 24. 9x2 - 4
25. x2 - 7x - 8 26. x2 + 13x + 36 27. x2 - 5x + 6
28. x2 + 5x + 4 29. x2 - 21x - 22 30. x2 + 13x + 40
31. 2x2 - 5x - 3 32. x2 + 10x - 11 33. x2 - 14x + 24
34. 5x2 + 4x - 12 35. 2x2 - 5x - 7 36. 2x2 + 13x + 15
37. 3x2 - 7x - 6 38. 3x2 + 16x + 21 39. x2 + 5x - 24
40. x2 + 34x - 72 41. x2 - 11x 42. 3x2 + 21x
43. x2 + 8x + 12 44. x2 - 10x + 24 45. x2 + 7x - 30
46. x2 - 2x - 168 47. x2 - x - 72 48. 4x2 - 25
49. x2 - 121 50. x2 + 17x + 16 51. 10x2 - 17x + 3
52. 4x2 + 12x + 9 53. 4x2 - 4x - 15 54. 9x2 - 4
55. x2 + 6x - 40 56. 2x2 - 8 57. x2 + 18x + 77
58. 2x2 - 98 59. x2 + 21x + 98 60. x2 + 20x + 84
61. 9x2 + 30x + 16 62. 8x2 - 6x - 27 63. x2 - 3x - 54
64. x2 - 169 65. 25x2 - 9 66. 7x2 + 49
67. 2x2 - 10x - 28 68. x2 + 8x + 12 69. x2 - 2x - 35
70. x2 + 2x - 63 71. 20x2 - 11x - 3 72. 12x2 + 4x - 5
73. 4x2 - 5x - 6 74. 8x2 + 22x - 21 75. 3x2 - 3x - 168
© P
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Algebra 2 Chapter 5 Lesson 5-4 Practice 5
Name Class Date
Practice 5-4 Factoring Quadratic Expressions
Factor each expression completely.
1. x2 + 4x + 4 2. x2 - 7x + 10 3. x2 + 7x - 8
4. x2 - 6x 5. 2x2 - 9x + 4 6. x2 + 2x - 35
7. x2 + 6x + 5 8. x2 - 9 9. x2 - 13x - 48
10. x2 - 4 11. 4x2 + x 12. x2 - 29x + 100
13. x2 - x - 6 14. 9x2 - 1 15. 3x2 - 2x
16. x2 - 64 17. x2 - 25 18. x2 - 81
19. x2 - 36 20. x2 - 100 21. x2 - 1
22. 4x2 - 1 23. 4x2 - 36 24. 9x2 - 4
25. x2 - 7x - 8 26. x2 + 13x + 36 27. x2 - 5x + 6
28. x2 + 5x + 4 29. x2 - 21x - 22 30. x2 + 13x + 40
31. 2x2 - 5x - 3 32. x2 + 10x - 11 33. x2 - 14x + 24
34. 5x2 + 4x - 12 35. 2x2 - 5x - 7 36. 2x2 + 13x + 15
37. 3x2 - 7x - 6 38. 3x2 + 16x + 21 39. x2 + 5x - 24
40. x2 + 34x - 72 41. x2 - 11x 42. 3x2 + 21x
43. x2 + 8x + 12 44. x2 - 10x + 24 45. x2 + 7x - 30
46. x2 - 2x - 168 47. x2 - x - 72 48. 4x2 - 25
49. x2 - 121 50. x2 + 17x + 16 51. 10x2 - 17x + 3
52. 4x2 + 12x + 9 53. 4x2 - 4x - 15 54. 9x2 - 4
55. x2 + 6x - 40 56. 2x2 - 8 57. x2 + 18x + 77
58. 2x2 - 98 59. x2 + 21x + 98 60. x2 + 20x + 84
61. 9x2 + 30x + 16 62. 8x2 - 6x - 27 63. x2 - 3x - 54
64. x2 - 169 65. 25x2 - 9 66. 7x2 + 49
67. 2x2 - 10x - 28 68. x2 + 8x + 12 69. x2 - 2x - 35
70. x2 + 2x - 63 71. 20x2 - 11x - 3 72. 12x2 + 4x - 5
73. 4x2 - 5x - 6 74. 8x2 + 22x - 21 75. 3x2 - 3x - 168
© P
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Algebra 2 Chapter 5 Lesson 5-4 Practice 5
Name Class Date
Practice 5-4 Factoring Quadratic Expressions
Factor each expression completely.
1. x2 + 4x + 4 2. x2 - 7x + 10 3. x2 + 7x - 8
4. x2 - 6x 5. 2x2 - 9x + 4 6. x2 + 2x - 35
7. x2 + 6x + 5 8. x2 - 9 9. x2 - 13x - 48
10. x2 - 4 11. 4x2 + x 12. x2 - 29x + 100
13. x2 - x - 6 14. 9x2 - 1 15. 3x2 - 2x
16. x2 - 64 17. x2 - 25 18. x2 - 81
19. x2 - 36 20. x2 - 100 21. x2 - 1
22. 4x2 - 1 23. 4x2 - 36 24. 9x2 - 4
25. x2 - 7x - 8 26. x2 + 13x + 36 27. x2 - 5x + 6
28. x2 + 5x + 4 29. x2 - 21x - 22 30. x2 + 13x + 40
31. 2x2 - 5x - 3 32. x2 + 10x - 11 33. x2 - 14x + 24
34. 5x2 + 4x - 12 35. 2x2 - 5x - 7 36. 2x2 + 13x + 15
37. 3x2 - 7x - 6 38. 3x2 + 16x + 21 39. x2 + 5x - 24
40. x2 + 34x - 72 41. x2 - 11x 42. 3x2 + 21x
43. x2 + 8x + 12 44. x2 - 10x + 24 45. x2 + 7x - 30
46. x2 - 2x - 168 47. x2 - x - 72 48. 4x2 - 25
49. x2 - 121 50. x2 + 17x + 16 51. 10x2 - 17x + 3
52. 4x2 + 12x + 9 53. 4x2 - 4x - 15 54. 9x2 - 4
55. x2 + 6x - 40 56. 2x2 - 8 57. x2 + 18x + 77
58. 2x2 - 98 59. x2 + 21x + 98 60. x2 + 20x + 84
61. 9x2 + 30x + 16 62. 8x2 - 6x - 27 63. x2 - 3x - 54
64. x2 - 169 65. 25x2 - 9 66. 7x2 + 49
67. 2x2 - 10x - 28 68. x2 + 8x + 12 69. x2 - 2x - 35
70. x2 + 2x - 63 71. 20x2 - 11x - 3 72. 12x2 + 4x - 5
73. 4x2 - 5x - 6 74. 8x2 + 22x - 21 75. 3x2 - 3x - 168
Lesson 5-4 Factoring Quadratic Expressions 263
An expression of the form a2 - b2 is defined as theIt also follows a pattern that makes it easy to factor.
Multiple Choice The photo shows the thin ring that is the cross-section of the pipe.Which expression gives the area of the cross-section in completely factored form?
p(3 + r)(3 - r) p(3 - r)(3 - r)p(9 - r2) 9 - pr2
Relate equals
minus
Define Let r = inner radius in feet.
Write = -
area = p(3)2 - pr2
= p(32 - r2)
= p(3 + r)(3 - r)
The cross-sectional area is p(3 + r)(3 - r) ft2. The correct choice is A.
Factor each expression: a. x2 - 64 b. 4a2 - 49
Find the GCF of each expression. Then factor the expression.
1. 3a2 + 9 2. 25b2 - 35 3. x2 - 2x
4. 5t2 + 7t 5. 14y2 + 7y 6. 27p2 - 9p
Factor each expression.
7. x2 + 3x + 2 8. x2 + 5x + 6 9. x2 + 7x + 10
10. x2 + 10x + 16 11. y2 + 15y + 36 12. x2 + 22x + 40
13. x2 - 3x + 2 14. x2 - 13x + 12 15. r2 - 11r + 18
16. x2 - 10x + 24 17. d2 - 12d + 27 18. x2 - 13x + 36
19. x2 - 5x - 14 20. x2 + x - 20 21. x2 - 3x - 40
22. c2 + 2c - 63 23. x2 + 10x - 75 24. t2 - 7t - 44
25. 3x2 + 31x + 36 26. 2x2 - 19x + 24 27. 5r2 + 23r + 26
28. 2m2 - 11m + 15 29. 5t2 + 28t + 32 30. 2x2 - 27x + 36
Example 5(page 261)
Example 4(page 261)
Example 3(page 260)
Example 2(page 260)
Example 1(page 259)
88Quick Check
pr2p(3)2area
the inner area
the outer areapipe’s area
EXAMPLEEXAMPLE Real-World Connection88
difference of two squares.
Practice and Problem SolvingFor more exercises, see Extra Skill and Word Problem Practice.EXERCISES
Practice by ExampleAA
Key Concepts Property Factoring a Difference of Two Squares
a2 - b2 = (a + b)(a - b)
3 ft
r
(x – 8)(x ± 8)
7–30. See margin.
(2a ± 7)(2a – 7)
3; 3(a2 ± 3) 5; 5(5b2 – 7) x; x(x – 2)
t; t(5t ± 7) 7y; 7y(2y ± 1)9p; 9p(3p – 1)GO for
Help
Test-Taking Tip
1 A B C D E
2 A B C D E
3 A B C D E
4 A B C D E
5 A B C D E
B C D E
A correct solution tothe problem may notbe the correct answerto the question asked.
263
7. (x ± 1)(x ± 2)
8. (x ± 2)(x ± 3)
9. (x ± 2)(x ± 5)
10. (x ± 2)(x ± 8)
11. (y ± 3)(y ± 12)
12. (x ± 2)(x ± 20)
13. (x – 1)(x – 2)
14. (x – 12)(x – 1)
15. (r – 2)(r – 9)
16. (x – 4)(x – 6)
17. (d – 3)(d – 9)
18. (x – 4)(x – 9)
19. (x – 7)(x ± 2)
20. (x ± 5)(x – 4)
21. (x – 8)(x ± 5)
22. (c ± 9)(c – 7)
23. (x ± 15)(x – 5)
24. (t – 11)(t ± 4)
25. (3x ± 4)(x ± 9)
26. (x – 8)(2x – 3)
27. (r ± 2)(5r ± 13)
28. (m – 3)(2m – 5)
29. (t ± 4)(5t ± 8)
30. (x – 12)(2x – 3)
3. PracticeAssignment Guide
A B 1-36, 48-50, 67-70
A B 37-47, 51-66C Challenge 71-78
Test Prep 79-84Mixed Review 85-91
Homework Quick CheckTo check students’ understandingof key skills and concepts, go overExercises 25, 45, 49, 66, 68, 70.
2
1
Guided Problem SolvingGPS
Enrichment
Reteaching
© P
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Name Class Date
Practice 5-4 Factoring Quadratic Expressions
Factor each expression completely.
1. x2 + 4x + 4 2. x2 - 7x + 10 3. x2 + 7x - 8
4. x2 - 6x 5. 2x2 - 9x + 4 6. x2 + 2x - 35
7. x2 + 6x + 5 8. x2 - 9 9. x2 - 13x - 48
10. x2 - 4 11. 4x2 + x 12. x2 - 29x + 100
13. x2 - x - 6 14. 9x2 - 1 15. 3x2 - 2x
16. x2 - 64 17. x2 - 25 18. x2 - 81
19. x2 - 36 20. x2 - 100 21. x2 - 1
22. 4x2 - 1 23. 4x2 - 36 24. 9x2 - 4
25. x2 - 7x - 8 26. x2 + 13x + 36 27. x2 - 5x + 6
28. x2 + 5x + 4 29. x2 - 21x - 22 30. x2 + 13x + 40
31. 2x2 - 5x - 3 32. x2 + 10x - 11 33. x2 - 14x + 24
34. 5x2 + 4x - 12 35. 2x2 - 5x - 7 36. 2x2 + 13x + 15
37. 3x2 - 7x - 6 38. 3x2 + 16x + 21 39. x2 + 5x - 24
40. x2 + 34x - 72 41. x2 - 11x 42. 3x2 + 21x
43. x2 + 8x + 12 44. x2 - 10x + 24 45. x2 + 7x - 30
46. x2 - 2x - 168 47. x2 - x - 72 48. 4x2 - 25
49. x2 - 121 50. x2 + 17x + 16 51. 10x2 - 17x + 3
52. 4x2 + 12x + 9 53. 4x2 - 4x - 15 54. 9x2 - 4
55. x2 + 6x - 40 56. 2x2 - 8 57. x2 + 18x + 77
58. 2x2 - 98 59. x2 + 21x + 98 60. x2 + 20x + 84
61. 9x2 + 30x + 16 62. 8x2 - 6x - 27 63. x2 - 3x - 54
64. x2 - 169 65. 25x2 - 9 66. 7x2 + 49
67. 2x2 - 10x - 28 68. x2 + 8x + 12 69. x2 - 2x - 35
70. x2 + 2x - 63 71. 20x2 - 11x - 3 72. 12x2 + 4x - 5
73. 4x2 - 5x - 6 74. 8x2 + 22x - 21 75. 3x2 - 3x - 168
Practice
L3
L4
L2
L3
A2_3eTE05_04_259-265 10/20/05 9:27 AM Page 263
Lesson 5-4 Factoring Quadratic Expressions 263
An expression of the form a2 - b2 is defined as theIt also follows a pattern that makes it easy to factor.
Multiple Choice The photo shows the thin ring that is the cross-section of the pipe.Which expression gives the area of the cross-section in completely factored form?
p(3 + r)(3 - r) p(3 - r)(3 - r)p(9 - r2) 9 - pr2
Relate equals
minus
Define Let r = inner radius in feet.
Write = -
area = p(3)2 - pr2
= p(32 - r2)
= p(3 + r)(3 - r)
The cross-sectional area is p(3 + r)(3 - r) ft2. The correct choice is A.
Factor each expression: a. x2 - 64 b. 4a2 - 49
Find the GCF of each expression. Then factor the expression.
1. 3a2 + 9 2. 25b2 - 35 3. x2 - 2x
4. 5t2 + 7t 5. 14y2 + 7y 6. 27p2 - 9p
Factor each expression.
7. x2 + 3x + 2 8. x2 + 5x + 6 9. x2 + 7x + 10
10. x2 + 10x + 16 11. y2 + 15y + 36 12. x2 + 22x + 40
13. x2 - 3x + 2 14. x2 - 13x + 12 15. r2 - 11r + 18
16. x2 - 10x + 24 17. d2 - 12d + 27 18. x2 - 13x + 36
19. x2 - 5x - 14 20. x2 + x - 20 21. x2 - 3x - 40
22. c2 + 2c - 63 23. x2 + 10x - 75 24. t2 - 7t - 44
25. 3x2 + 31x + 36 26. 2x2 - 19x + 24 27. 5r2 + 23r + 26
28. 2m2 - 11m + 15 29. 5t2 + 28t + 32 30. 2x2 - 27x + 36
Example 5(page 261)
Example 4(page 261)
Example 3(page 260)
Example 2(page 260)
Example 1(page 259)
88Quick Check
pr2p(3)2area
the inner area
the outer areapipe’s area
EXAMPLEEXAMPLE Real-World Connection88
difference of two squares.
Practice and Problem SolvingFor more exercises, see Extra Skill and Word Problem Practice.EXERCISES
Practice by ExampleAA
Key Concepts Property Factoring a Difference of Two Squares
a2 - b2 = (a + b)(a - b)
3 ft
r
(x – 8)(x ± 8)
7–30. See margin.
(2a ± 7)(2a – 7)
3; 3(a2 ± 3) 5; 5(5b2 – 7) x; x(x – 2)
t; t(5t ± 7) 7y; 7y(2y ± 1)9p; 9p(3p – 1)GO for
Help
Test-Taking Tip
1 A B C D E
2 A B C D E
3 A B C D E
4 A B C D E
5 A B C D E
B C D E
A correct solution tothe problem may notbe the correct answerto the question asked.
263
7. (x ± 1)(x ± 2)
8. (x ± 2)(x ± 3)
9. (x ± 2)(x ± 5)
10. (x ± 2)(x ± 8)
11. (y ± 3)(y ± 12)
12. (x ± 2)(x ± 20)
13. (x – 1)(x – 2)
14. (x – 12)(x – 1)
15. (r – 2)(r – 9)
16. (x – 4)(x – 6)
17. (d – 3)(d – 9)
18. (x – 4)(x – 9)
19. (x – 7)(x ± 2)
20. (x ± 5)(x – 4)
21. (x – 8)(x ± 5)
22. (c ± 9)(c – 7)
23. (x ± 15)(x – 5)
24. (t – 11)(t ± 4)
25. (3x ± 4)(x ± 9)
26. (x – 8)(2x – 3)
27. (r ± 2)(5r ± 13)
28. (m – 3)(2m – 5)
29. (t ± 4)(5t ± 8)
30. (x – 12)(2x – 3)
3. PracticeAssignment Guide
A B 1-36, 48-50, 67-70
A B 37-47, 51-66C Challenge 71-78
Test Prep 79-84Mixed Review 85-91
Homework Quick CheckTo check students’ understandingof key skills and concepts, go overExercises 25, 45, 49, 66, 68, 70.
2
1
Guided Problem SolvingGPS
Enrichment
Reteaching
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Name Class Date
Practice 5-4 Factoring Quadratic Expressions
Factor each expression completely.
1. x2 + 4x + 4 2. x2 - 7x + 10 3. x2 + 7x - 8
4. x2 - 6x 5. 2x2 - 9x + 4 6. x2 + 2x - 35
7. x2 + 6x + 5 8. x2 - 9 9. x2 - 13x - 48
10. x2 - 4 11. 4x2 + x 12. x2 - 29x + 100
13. x2 - x - 6 14. 9x2 - 1 15. 3x2 - 2x
16. x2 - 64 17. x2 - 25 18. x2 - 81
19. x2 - 36 20. x2 - 100 21. x2 - 1
22. 4x2 - 1 23. 4x2 - 36 24. 9x2 - 4
25. x2 - 7x - 8 26. x2 + 13x + 36 27. x2 - 5x + 6
28. x2 + 5x + 4 29. x2 - 21x - 22 30. x2 + 13x + 40
31. 2x2 - 5x - 3 32. x2 + 10x - 11 33. x2 - 14x + 24
34. 5x2 + 4x - 12 35. 2x2 - 5x - 7 36. 2x2 + 13x + 15
37. 3x2 - 7x - 6 38. 3x2 + 16x + 21 39. x2 + 5x - 24
40. x2 + 34x - 72 41. x2 - 11x 42. 3x2 + 21x
43. x2 + 8x + 12 44. x2 - 10x + 24 45. x2 + 7x - 30
46. x2 - 2x - 168 47. x2 - x - 72 48. 4x2 - 25
49. x2 - 121 50. x2 + 17x + 16 51. 10x2 - 17x + 3
52. 4x2 + 12x + 9 53. 4x2 - 4x - 15 54. 9x2 - 4
55. x2 + 6x - 40 56. 2x2 - 8 57. x2 + 18x + 77
58. 2x2 - 98 59. x2 + 21x + 98 60. x2 + 20x + 84
61. 9x2 + 30x + 16 62. 8x2 - 6x - 27 63. x2 - 3x - 54
64. x2 - 169 65. 25x2 - 9 66. 7x2 + 49
67. 2x2 - 10x - 28 68. x2 + 8x + 12 69. x2 - 2x - 35
70. x2 + 2x - 63 71. 20x2 - 11x - 3 72. 12x2 + 4x - 5
73. 4x2 - 5x - 6 74. 8x2 + 22x - 21 75. 3x2 - 3x - 168
Practice
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L4
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Algebra 2 Chapter 5 Lesson 5-4 Practice 5
Name Class Date
Practice 5-4 Factoring Quadratic Expressions
Factor each expression completely.
1. x2 + 4x + 4 2. x2 - 7x + 10 3. x2 + 7x - 8
4. x2 - 6x 5. 2x2 - 9x + 4 6. x2 + 2x - 35
7. x2 + 6x + 5 8. x2 - 9 9. x2 - 13x - 48
10. x2 - 4 11. 4x2 + x 12. x2 - 29x + 100
13. x2 - x - 6 14. 9x2 - 1 15. 3x2 - 2x
16. x2 - 64 17. x2 - 25 18. x2 - 81
19. x2 - 36 20. x2 - 100 21. x2 - 1
22. 4x2 - 1 23. 4x2 - 36 24. 9x2 - 4
25. x2 - 7x - 8 26. x2 + 13x + 36 27. x2 - 5x + 6
28. x2 + 5x + 4 29. x2 - 21x - 22 30. x2 + 13x + 40
31. 2x2 - 5x - 3 32. x2 + 10x - 11 33. x2 - 14x + 24
34. 5x2 + 4x - 12 35. 2x2 - 5x - 7 36. 2x2 + 13x + 15
37. 3x2 - 7x - 6 38. 3x2 + 16x + 21 39. x2 + 5x - 24
40. x2 + 34x - 72 41. x2 - 11x 42. 3x2 + 21x
43. x2 + 8x + 12 44. x2 - 10x + 24 45. x2 + 7x - 30
46. x2 - 2x - 168 47. x2 - x - 72 48. 4x2 - 25
49. x2 - 121 50. x2 + 17x + 16 51. 10x2 - 17x + 3
52. 4x2 + 12x + 9 53. 4x2 - 4x - 15 54. 9x2 - 4
55. x2 + 6x - 40 56. 2x2 - 8 57. x2 + 18x + 77
58. 2x2 - 98 59. x2 + 21x + 98 60. x2 + 20x + 84
61. 9x2 + 30x + 16 62. 8x2 - 6x - 27 63. x2 - 3x - 54
64. x2 - 169 65. 25x2 - 9 66. 7x2 + 49
67. 2x2 - 10x - 28 68. x2 + 8x + 12 69. x2 - 2x - 35
70. x2 + 2x - 63 71. 20x2 - 11x - 3 72. 12x2 + 4x - 5
73. 4x2 - 5x - 6 74. 8x2 + 22x - 21 75. 3x2 - 3x - 168
© P
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Algebra 2 Chapter 5 Lesson 5-4 Practice 5
Name Class Date
Practice 5-4 Factoring Quadratic Expressions
Factor each expression completely.
1. x2 + 4x + 4 2. x2 - 7x + 10 3. x2 + 7x - 8
4. x2 - 6x 5. 2x2 - 9x + 4 6. x2 + 2x - 35
7. x2 + 6x + 5 8. x2 - 9 9. x2 - 13x - 48
10. x2 - 4 11. 4x2 + x 12. x2 - 29x + 100
13. x2 - x - 6 14. 9x2 - 1 15. 3x2 - 2x
16. x2 - 64 17. x2 - 25 18. x2 - 81
19. x2 - 36 20. x2 - 100 21. x2 - 1
22. 4x2 - 1 23. 4x2 - 36 24. 9x2 - 4
25. x2 - 7x - 8 26. x2 + 13x + 36 27. x2 - 5x + 6
28. x2 + 5x + 4 29. x2 - 21x - 22 30. x2 + 13x + 40
31. 2x2 - 5x - 3 32. x2 + 10x - 11 33. x2 - 14x + 24
34. 5x2 + 4x - 12 35. 2x2 - 5x - 7 36. 2x2 + 13x + 15
37. 3x2 - 7x - 6 38. 3x2 + 16x + 21 39. x2 + 5x - 24
40. x2 + 34x - 72 41. x2 - 11x 42. 3x2 + 21x
43. x2 + 8x + 12 44. x2 - 10x + 24 45. x2 + 7x - 30
46. x2 - 2x - 168 47. x2 - x - 72 48. 4x2 - 25
49. x2 - 121 50. x2 + 17x + 16 51. 10x2 - 17x + 3
52. 4x2 + 12x + 9 53. 4x2 - 4x - 15 54. 9x2 - 4
55. x2 + 6x - 40 56. 2x2 - 8 57. x2 + 18x + 77
58. 2x2 - 98 59. x2 + 21x + 98 60. x2 + 20x + 84
61. 9x2 + 30x + 16 62. 8x2 - 6x - 27 63. x2 - 3x - 54
64. x2 - 169 65. 25x2 - 9 66. 7x2 + 49
67. 2x2 - 10x - 28 68. x2 + 8x + 12 69. x2 - 2x - 35
70. x2 + 2x - 63 71. 20x2 - 11x - 3 72. 12x2 + 4x - 5
73. 4x2 - 5x - 6 74. 8x2 + 22x - 21 75. 3x2 - 3x - 168
© P
ears
on E
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Algebra 2 Chapter 5 Lesson 5-4 Practice 5
Name Class Date
Practice 5-4 Factoring Quadratic Expressions
Factor each expression completely.
1. x2 + 4x + 4 2. x2 - 7x + 10 3. x2 + 7x - 8
4. x2 - 6x 5. 2x2 - 9x + 4 6. x2 + 2x - 35
7. x2 + 6x + 5 8. x2 - 9 9. x2 - 13x - 48
10. x2 - 4 11. 4x2 + x 12. x2 - 29x + 100
13. x2 - x - 6 14. 9x2 - 1 15. 3x2 - 2x
16. x2 - 64 17. x2 - 25 18. x2 - 81
19. x2 - 36 20. x2 - 100 21. x2 - 1
22. 4x2 - 1 23. 4x2 - 36 24. 9x2 - 4
25. x2 - 7x - 8 26. x2 + 13x + 36 27. x2 - 5x + 6
28. x2 + 5x + 4 29. x2 - 21x - 22 30. x2 + 13x + 40
31. 2x2 - 5x - 3 32. x2 + 10x - 11 33. x2 - 14x + 24
34. 5x2 + 4x - 12 35. 2x2 - 5x - 7 36. 2x2 + 13x + 15
37. 3x2 - 7x - 6 38. 3x2 + 16x + 21 39. x2 + 5x - 24
40. x2 + 34x - 72 41. x2 - 11x 42. 3x2 + 21x
43. x2 + 8x + 12 44. x2 - 10x + 24 45. x2 + 7x - 30
46. x2 - 2x - 168 47. x2 - x - 72 48. 4x2 - 25
49. x2 - 121 50. x2 + 17x + 16 51. 10x2 - 17x + 3
52. 4x2 + 12x + 9 53. 4x2 - 4x - 15 54. 9x2 - 4
55. x2 + 6x - 40 56. 2x2 - 8 57. x2 + 18x + 77
58. 2x2 - 98 59. x2 + 21x + 98 60. x2 + 20x + 84
61. 9x2 + 30x + 16 62. 8x2 - 6x - 27 63. x2 - 3x - 54
64. x2 - 169 65. 25x2 - 9 66. 7x2 + 49
67. 2x2 - 10x - 28 68. x2 + 8x + 12 69. x2 - 2x - 35
70. x2 + 2x - 63 71. 20x2 - 11x - 3 72. 12x2 + 4x - 5
73. 4x2 - 5x - 6 74. 8x2 + 22x - 21 75. 3x2 - 3x - 168
![Page 5: To find common and x Rewrite using the Distributive ... · of signs of ac and b. L1 L2 learning style: verbal learning style: visual A2_3eTE05_04_259-265 10/20/05 9:27 AM Page 259](https://reader036.vdocument.in/reader036/viewer/2022071117/600772bd2a652010e34bebea/html5/thumbnails/5.jpg)
Name_____________________________________ Class____________________________ Date________________
Lesson ObjectivesSolving quadratic equations by factoringand finding square rootsSolving quadratic equations by graphing2
1
NAEP 2005 Strand: AlgebraTopic: Equations and Inequalities
Local Standards: ____________________________________
Vocabulary and Key Concepts.
Zero-Product PropertyIf ab ! 0, then a ! 0 or b ! 0.Example If (x " 3)(x # 7) ! 0, then (x " 3) ! 0 or (x # 7) ! 0.
The standard form of a quadratic equation is
A zero of a function is
Examples.
Solving by Factoring Solve 3x2 # 20x # 7 ! 0.
3x2!
!
# #20x 7
3x2#
3x
x
"
"
#x 7
0
3x2# !20x
#
"
203
7 3x2
3
# !20x
#
#
20
7
! 7
! 7
! 7
! 7
0
! 0
Write in standard form.
Rewrite term.bx
Find the common factors.
Factor using the Property.
( ) ( )! 0( )( )! 0!
! x !
0
The solutions are and .
Check
or
or
( )2 ( )
! 7 ✓
! 7 ✓
( )2 ( )
Use the Property.
Solve for x.
1
Lesson 5-5 Quadratic Equations
99Daily Notetaking Guide Algebra 2 Lesson 5-5
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Lesson 5-5 Quadratic Equations 267
Quadratic Equations
The is ax2 + bx + c = 0, where a 2 0.You can solve some quadratic equations in standard form by factoring thequadratic expression and then using the Zero-Product Property.
Solving by Factoring
Solve 2x2 - 11x = -15.
2x2 - 11x + 15 = 0 Write in standard form.
(x - 3)(2x - 5) = 0 Factor the quadratic expression.
x - 3 = 0 or 2x - 5 = 0 Use the Zero-Product Property.
x = 3 or x = Solve for x.
The solutions are 3 and .
Check 2x2 - 11x = -15 2x2 - 11x = -15
2(3)2 - 11(3) 0-15 - 0-15
18 - 33 0-15 - 0-15
-15 = -15 ✓ -15 = -15 ✓
Solve each equation by factoring. Check your answers.a. x2 + 7x = 18 b. 2x2 + 4x = 6 c. 16x2 = 8x
11Quick Check
552
252
11Q52R2Q52R252
52
EXAMPLEEXAMPLE11
standard form of a quadratic equation
5-55-5
Lessons 5-2 and 5-4
Factor each expression.1. x2 + 5x - 14 2. 4x2 - 12x 3. 9x2 - 16
Graph each function.4. y = x2 - 2x - 5 5. y = x2 - 4x + 4 6. y = x2 - 4x
New Vocabulary • standard form of a quadratic equation • Zero-Product Property • zero of a function
What You’ll Learn• To solve quadratic
equations by factoring andby finding square roots
• To solve quadraticequations by graphing
. . . And WhyTo solve equations involvingart, as in Example 5
11 Solving by Factoring and Finding Square Roots
Key Concepts Property Zero-Product Property
If ab = 0, then a = 0 or b = 0.
Example If (x + 3)(x - 7) = 0, then (x + 3) = 0 or (x - 7) = 0.
(x ± 7)(x – 2) 4x(x – 3)4–6. See margin p. 269.
(3x – 4)(3x ± 4)
Check Skills You’ll Need GO for Help
–9, 2 –3, 1 0, 12
1. PlanObjectives1 To solve quadratic equations
by factoring and by findingsquare roots
2 To solve quadratic equationsby graphing
Examples1 Solving by Factoring2 Solving by Finding Square
Roots3 Real-World Connection4 Solving by Tables5 Solving by Graphing
Math Background
The use of the Zero-ProductProperty allows students to solvequadratic equations that can befactored. Other useful techniquesinclude finding square roots andgraphing. However, each of thesetechniques has limitations. Thisshould begin to convince studentsof the need for a method withoutlimitations. Such a method ispresented in Lesson 5-8.
More Math Background: p. 236D
Lesson Planning andResources
See p. 236E for a list of theresources that support this lesson.
Bell Ringer Practice
Check Skills You’ll NeedFor intervention, direct students to:
Properties of ParabolasLesson 5-2: Example 2Extra Skills and Word
Problems Practice, Ch. 5
Factoring Quadratic ExpressionsLesson 5-4: Examples 2, 3Extra Skills and Word
Problems Practice, Ch. 5
5-55-5
267
PowerPoint
Special NeedsHelp students recognize the different methods forsolving quadratic equations. Emphasize that tablesand graphs give approximate solutions, whilealgebraic solutions are exact.
Below LevelRemind students that finding square roots yields twopossible solutions to an equation. x2 = 4 has twosolutions, x = 42.
L2L1
learning style: verbal learning style: verbal
A2_3eTE05_05_267-272 10/20/05 9:28 AM Page 267
Lesson 5-5 Quadratic Equations 267
Quadratic Equations
The is ax2 + bx + c = 0, where a 2 0.You can solve some quadratic equations in standard form by factoring thequadratic expression and then using the Zero-Product Property.
Solving by Factoring
Solve 2x2 - 11x = -15.
2x2 - 11x + 15 = 0 Write in standard form.
(x - 3)(2x - 5) = 0 Factor the quadratic expression.
x - 3 = 0 or 2x - 5 = 0 Use the Zero-Product Property.
x = 3 or x = Solve for x.
The solutions are 3 and .
Check 2x2 - 11x = -15 2x2 - 11x = -15
2(3)2 - 11(3) 0-15 - 0-15
18 - 33 0-15 - 0-15
-15 = -15 ✓ -15 = -15 ✓
Solve each equation by factoring. Check your answers.a. x2 + 7x = 18 b. 2x2 + 4x = 6 c. 16x2 = 8x
11Quick Check
552
252
11Q52R2Q52R252
52
EXAMPLEEXAMPLE11
standard form of a quadratic equation
5-55-5
Lessons 5-2 and 5-4
Factor each expression.1. x2 + 5x - 14 2. 4x2 - 12x 3. 9x2 - 16
Graph each function.4. y = x2 - 2x - 5 5. y = x2 - 4x + 4 6. y = x2 - 4x
New Vocabulary • standard form of a quadratic equation • Zero-Product Property • zero of a function
What You’ll Learn• To solve quadratic
equations by factoring andby finding square roots
• To solve quadraticequations by graphing
. . . And WhyTo solve equations involvingart, as in Example 5
11 Solving by Factoring and Finding Square Roots
Key Concepts Property Zero-Product Property
If ab = 0, then a = 0 or b = 0.
Example If (x + 3)(x - 7) = 0, then (x + 3) = 0 or (x - 7) = 0.
(x ± 7)(x – 2) 4x(x – 3)4–6. See margin p. 269.
(3x – 4)(3x ± 4)
Check Skills You’ll Need GO for Help
–9, 2 –3, 1 0, 12
1. PlanObjectives1 To solve quadratic equations
by factoring and by findingsquare roots
2 To solve quadratic equationsby graphing
Examples1 Solving by Factoring2 Solving by Finding Square
Roots3 Real-World Connection4 Solving by Tables5 Solving by Graphing
Math Background
The use of the Zero-ProductProperty allows students to solvequadratic equations that can befactored. Other useful techniquesinclude finding square roots andgraphing. However, each of thesetechniques has limitations. Thisshould begin to convince studentsof the need for a method withoutlimitations. Such a method ispresented in Lesson 5-8.
More Math Background: p. 236D
Lesson Planning andResources
See p. 236E for a list of theresources that support this lesson.
Bell Ringer Practice
Check Skills You’ll NeedFor intervention, direct students to:
Properties of ParabolasLesson 5-2: Example 2Extra Skills and Word
Problems Practice, Ch. 5
Factoring Quadratic ExpressionsLesson 5-4: Examples 2, 3Extra Skills and Word
Problems Practice, Ch. 5
5-55-5
267
PowerPoint
Special NeedsHelp students recognize the different methods forsolving quadratic equations. Emphasize that tablesand graphs give approximate solutions, whilealgebraic solutions are exact.
Below LevelRemind students that finding square roots yields twopossible solutions to an equation. x2 = 4 has twosolutions, x = 42.
L2L1
learning style: verbal learning style: verbal
A2_3eTE05_05_267-272 10/20/05 9:28 AM Page 267
Lesson 5-5 Quadratic Equations 267
Quadratic Equations
The is ax2 + bx + c = 0, where a 2 0.You can solve some quadratic equations in standard form by factoring thequadratic expression and then using the Zero-Product Property.
Solving by Factoring
Solve 2x2 - 11x = -15.
2x2 - 11x + 15 = 0 Write in standard form.
(x - 3)(2x - 5) = 0 Factor the quadratic expression.
x - 3 = 0 or 2x - 5 = 0 Use the Zero-Product Property.
x = 3 or x = Solve for x.
The solutions are 3 and .
Check 2x2 - 11x = -15 2x2 - 11x = -15
2(3)2 - 11(3) 0-15 - 0-15
18 - 33 0-15 - 0-15
-15 = -15 ✓ -15 = -15 ✓
Solve each equation by factoring. Check your answers.a. x2 + 7x = 18 b. 2x2 + 4x = 6 c. 16x2 = 8x
11Quick Check
552
252
11Q52R2Q52R252
52
EXAMPLEEXAMPLE11
standard form of a quadratic equation
5-55-5
Lessons 5-2 and 5-4
Factor each expression.1. x2 + 5x - 14 2. 4x2 - 12x 3. 9x2 - 16
Graph each function.4. y = x2 - 2x - 5 5. y = x2 - 4x + 4 6. y = x2 - 4x
New Vocabulary • standard form of a quadratic equation • Zero-Product Property • zero of a function
What You’ll Learn• To solve quadratic
equations by factoring andby finding square roots
• To solve quadraticequations by graphing
. . . And WhyTo solve equations involvingart, as in Example 5
11 Solving by Factoring and Finding Square Roots
Key Concepts Property Zero-Product Property
If ab = 0, then a = 0 or b = 0.
Example If (x + 3)(x - 7) = 0, then (x + 3) = 0 or (x - 7) = 0.
(x ± 7)(x – 2) 4x(x – 3)4–6. See margin p. 269.
(3x – 4)(3x ± 4)
Check Skills You’ll Need GO for Help
–9, 2 –3, 1 0, 12
1. PlanObjectives1 To solve quadratic equations
by factoring and by findingsquare roots
2 To solve quadratic equationsby graphing
Examples1 Solving by Factoring2 Solving by Finding Square
Roots3 Real-World Connection4 Solving by Tables5 Solving by Graphing
Math Background
The use of the Zero-ProductProperty allows students to solvequadratic equations that can befactored. Other useful techniquesinclude finding square roots andgraphing. However, each of thesetechniques has limitations. Thisshould begin to convince studentsof the need for a method withoutlimitations. Such a method ispresented in Lesson 5-8.
More Math Background: p. 236D
Lesson Planning andResources
See p. 236E for a list of theresources that support this lesson.
Bell Ringer Practice
Check Skills You’ll NeedFor intervention, direct students to:
Properties of ParabolasLesson 5-2: Example 2Extra Skills and Word
Problems Practice, Ch. 5
Factoring Quadratic ExpressionsLesson 5-4: Examples 2, 3Extra Skills and Word
Problems Practice, Ch. 5
5-55-5
267
PowerPoint
Special NeedsHelp students recognize the different methods forsolving quadratic equations. Emphasize that tablesand graphs give approximate solutions, whilealgebraic solutions are exact.
Below LevelRemind students that finding square roots yields twopossible solutions to an equation. x2 = 4 has twosolutions, x = 42.
L2L1
learning style: verbal learning style: verbal
A2_3eTE05_05_267-272 10/20/05 9:28 AM Page 267
Lesson 5-5 Quadratic Equations 267
Quadratic Equations
The is ax2 + bx + c = 0, where a 2 0.You can solve some quadratic equations in standard form by factoring thequadratic expression and then using the Zero-Product Property.
Solving by Factoring
Solve 2x2 - 11x = -15.
2x2 - 11x + 15 = 0 Write in standard form.
(x - 3)(2x - 5) = 0 Factor the quadratic expression.
x - 3 = 0 or 2x - 5 = 0 Use the Zero-Product Property.
x = 3 or x = Solve for x.
The solutions are 3 and .
Check 2x2 - 11x = -15 2x2 - 11x = -15
2(3)2 - 11(3) 0-15 - 0-15
18 - 33 0-15 - 0-15
-15 = -15 ✓ -15 = -15 ✓
Solve each equation by factoring. Check your answers.a. x2 + 7x = 18 b. 2x2 + 4x = 6 c. 16x2 = 8x
11Quick Check
552
252
11Q52R2Q52R252
52
EXAMPLEEXAMPLE11
standard form of a quadratic equation
5-55-5
Lessons 5-2 and 5-4
Factor each expression.1. x2 + 5x - 14 2. 4x2 - 12x 3. 9x2 - 16
Graph each function.4. y = x2 - 2x - 5 5. y = x2 - 4x + 4 6. y = x2 - 4x
New Vocabulary • standard form of a quadratic equation • Zero-Product Property • zero of a function
What You’ll Learn• To solve quadratic
equations by factoring andby finding square roots
• To solve quadraticequations by graphing
. . . And WhyTo solve equations involvingart, as in Example 5
11 Solving by Factoring and Finding Square Roots
Key Concepts Property Zero-Product Property
If ab = 0, then a = 0 or b = 0.
Example If (x + 3)(x - 7) = 0, then (x + 3) = 0 or (x - 7) = 0.
(x ± 7)(x – 2) 4x(x – 3)4–6. See margin p. 269.
(3x – 4)(3x ± 4)
Check Skills You’ll Need GO for Help
–9, 2 –3, 1 0, 12
1. PlanObjectives1 To solve quadratic equations
by factoring and by findingsquare roots
2 To solve quadratic equationsby graphing
Examples1 Solving by Factoring2 Solving by Finding Square
Roots3 Real-World Connection4 Solving by Tables5 Solving by Graphing
Math Background
The use of the Zero-ProductProperty allows students to solvequadratic equations that can befactored. Other useful techniquesinclude finding square roots andgraphing. However, each of thesetechniques has limitations. Thisshould begin to convince studentsof the need for a method withoutlimitations. Such a method ispresented in Lesson 5-8.
More Math Background: p. 236D
Lesson Planning andResources
See p. 236E for a list of theresources that support this lesson.
Bell Ringer Practice
Check Skills You’ll NeedFor intervention, direct students to:
Properties of ParabolasLesson 5-2: Example 2Extra Skills and Word
Problems Practice, Ch. 5
Factoring Quadratic ExpressionsLesson 5-4: Examples 2, 3Extra Skills and Word
Problems Practice, Ch. 5
5-55-5
267
PowerPoint
Special NeedsHelp students recognize the different methods forsolving quadratic equations. Emphasize that tablesand graphs give approximate solutions, whilealgebraic solutions are exact.
Below LevelRemind students that finding square roots yields twopossible solutions to an equation. x2 = 4 has twosolutions, x = 42.
L2L1
learning style: verbal learning style: verbal
A2_3eTE05_05_267-272 10/20/05 9:28 AM Page 267
Practice 5-5 Quadratic Equations
Solve each equation by factoring, by taking square roots, or by graphing.When necessary, round your answer to the nearest hundredth.
1. x2 - 18x - 40 = 0 2. 16x2 = 56x 3. 5x2 = 15x
4. x2 - 6x - 7 = 0 5. x2 - 49 = 0 6. x2 + 2x + 1 = 0
7. x2 - 1 = 0 8. x2 - 3x - 4 = 0 9. x2 + 9x2 + 20 = 0
10. 6x2 + 9 = -55x 11. (x + 5)2 = 36 12. 2x2 - 3x = 0
13. 2x2 + x - 10 = 0 14. -4x2 + 3x = -1 15. 5x2 - 6x + 1 = 0
16. 3x2 + 1 = -4x 17. -2x2 + 2 = -3x 18. 6x2 + 1 = 5x
19. -2x2 - x + 1 = 0 20. 3x2 + 5x = 2 21. x2 - 6x = -8
22. x2 + 6 = -7x 23. 6x2 + 18x = 0 24. 2x2 + 5 = 11x
25. 3x2 - 7x + 2 = 0 26. 2x2 - 3x = -1 27. 2x2 - x = 6
28. x2 - 144 = 0 29. 4x2 + 2 = 6x 30. 5x2 + 2 = -7x
31. 7x2 + 6x - 1 = 0 32. 2x2 - 6x = -4 33. 11x2 - 12x + 1 = 0
34. 7x2 + 1 = -8x 35. x2 + 9 = -10x 36. (x - 2)2 = 18
37. x2 - 8x + 7 = 0 38. x2 - 16 = 0 39. x2 + 6x = -8
40. x2 + 3 = 4x 41. 2x2 + 6 = -7x 42. 6x2 + 2 = 7x
43. (x + 7)2 = 44. 9x2 - 8x = 1 45. 10x2 + 7x + 1 = 0
46. 4x2 + 2 = -9x 47. 3x2 + 4 = 8x 48. 4x2 + 5 + 9x = 0
49. 9x2 + 10x = -1 50. 2x2 + 9x + 4 = 0 51. 2x2 + 6x = -4
52. 11x2 - 1 = -10x 53. 4x2 = 1 54. 6x2 = 12x
55. 25x2 - 9 = 0 56. 2x2 + 11x = 6 57. 8x2 - 6x + 1 = 0
58. x2 + 11 = -12x 59. 6x2 + 2 = 13x 60. x2 = 121
61. 4x2 - 11x = 3 62. 8x2 + 6x + 1 = 0 63. x2 + 9x + 8 = 0
64. x2 + 8x = -12 65. x2 + 6x = 40 66. 2x2 = 8
67. x2 = x + 6 68. x2 + 2x - 6 = 0 69. x2 - 12 = 0
70. 3x2 + 4x = 6 71. 7x2 - 105 = 0 72. 16x2 = 81
73. x2 + 5x + 4 = 0 74. x2 + 36 = -13x 75. x2 + 6 = 5x
4916
Name Class Date
Lesson 5-5 Practice Algebra 2 Chapter 56
© P
ears
on E
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Practice 5-5 Quadratic Equations
Solve each equation by factoring, by taking square roots, or by graphing.When necessary, round your answer to the nearest hundredth.
1. x2 - 18x - 40 = 0 2. 16x2 = 56x 3. 5x2 = 15x
4. x2 - 6x - 7 = 0 5. x2 - 49 = 0 6. x2 + 2x + 1 = 0
7. x2 - 1 = 0 8. x2 - 3x - 4 = 0 9. x2 + 9x2 + 20 = 0
10. 6x2 + 9 = -55x 11. (x + 5)2 = 36 12. 2x2 - 3x = 0
13. 2x2 + x - 10 = 0 14. -4x2 + 3x = -1 15. 5x2 - 6x + 1 = 0
16. 3x2 + 1 = -4x 17. -2x2 + 2 = -3x 18. 6x2 + 1 = 5x
19. -2x2 - x + 1 = 0 20. 3x2 + 5x = 2 21. x2 - 6x = -8
22. x2 + 6 = -7x 23. 6x2 + 18x = 0 24. 2x2 + 5 = 11x
25. 3x2 - 7x + 2 = 0 26. 2x2 - 3x = -1 27. 2x2 - x = 6
28. x2 - 144 = 0 29. 4x2 + 2 = 6x 30. 5x2 + 2 = -7x
31. 7x2 + 6x - 1 = 0 32. 2x2 - 6x = -4 33. 11x2 - 12x + 1 = 0
34. 7x2 + 1 = -8x 35. x2 + 9 = -10x 36. (x - 2)2 = 18
37. x2 - 8x + 7 = 0 38. x2 - 16 = 0 39. x2 + 6x = -8
40. x2 + 3 = 4x 41. 2x2 + 6 = -7x 42. 6x2 + 2 = 7x
43. (x + 7)2 = 44. 9x2 - 8x = 1 45. 10x2 + 7x + 1 = 0
46. 4x2 + 2 = -9x 47. 3x2 + 4 = 8x 48. 4x2 + 5 + 9x = 0
49. 9x2 + 10x = -1 50. 2x2 + 9x + 4 = 0 51. 2x2 + 6x = -4
52. 11x2 - 1 = -10x 53. 4x2 = 1 54. 6x2 = 12x
55. 25x2 - 9 = 0 56. 2x2 + 11x = 6 57. 8x2 - 6x + 1 = 0
58. x2 + 11 = -12x 59. 6x2 + 2 = 13x 60. x2 = 121
61. 4x2 - 11x = 3 62. 8x2 + 6x + 1 = 0 63. x2 + 9x + 8 = 0
64. x2 + 8x = -12 65. x2 + 6x = 40 66. 2x2 = 8
67. x2 = x + 6 68. x2 + 2x - 6 = 0 69. x2 - 12 = 0
70. 3x2 + 4x = 6 71. 7x2 - 105 = 0 72. 16x2 = 81
73. x2 + 5x + 4 = 0 74. x2 + 36 = -13x 75. x2 + 6 = 5x
4916
Name Class Date
Lesson 5-5 Practice Algebra 2 Chapter 56
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ears
on E
duca
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Practice 5-5 Quadratic Equations
Solve each equation by factoring, by taking square roots, or by graphing.When necessary, round your answer to the nearest hundredth.
1. x2 - 18x - 40 = 0 2. 16x2 = 56x 3. 5x2 = 15x
4. x2 - 6x - 7 = 0 5. x2 - 49 = 0 6. x2 + 2x + 1 = 0
7. x2 - 1 = 0 8. x2 - 3x - 4 = 0 9. x2 + 9x2 + 20 = 0
10. 6x2 + 9 = -55x 11. (x + 5)2 = 36 12. 2x2 - 3x = 0
13. 2x2 + x - 10 = 0 14. -4x2 + 3x = -1 15. 5x2 - 6x + 1 = 0
16. 3x2 + 1 = -4x 17. -2x2 + 2 = -3x 18. 6x2 + 1 = 5x
19. -2x2 - x + 1 = 0 20. 3x2 + 5x = 2 21. x2 - 6x = -8
22. x2 + 6 = -7x 23. 6x2 + 18x = 0 24. 2x2 + 5 = 11x
25. 3x2 - 7x + 2 = 0 26. 2x2 - 3x = -1 27. 2x2 - x = 6
28. x2 - 144 = 0 29. 4x2 + 2 = 6x 30. 5x2 + 2 = -7x
31. 7x2 + 6x - 1 = 0 32. 2x2 - 6x = -4 33. 11x2 - 12x + 1 = 0
34. 7x2 + 1 = -8x 35. x2 + 9 = -10x 36. (x - 2)2 = 18
37. x2 - 8x + 7 = 0 38. x2 - 16 = 0 39. x2 + 6x = -8
40. x2 + 3 = 4x 41. 2x2 + 6 = -7x 42. 6x2 + 2 = 7x
43. (x + 7)2 = 44. 9x2 - 8x = 1 45. 10x2 + 7x + 1 = 0
46. 4x2 + 2 = -9x 47. 3x2 + 4 = 8x 48. 4x2 + 5 + 9x = 0
49. 9x2 + 10x = -1 50. 2x2 + 9x + 4 = 0 51. 2x2 + 6x = -4
52. 11x2 - 1 = -10x 53. 4x2 = 1 54. 6x2 = 12x
55. 25x2 - 9 = 0 56. 2x2 + 11x = 6 57. 8x2 - 6x + 1 = 0
58. x2 + 11 = -12x 59. 6x2 + 2 = 13x 60. x2 = 121
61. 4x2 - 11x = 3 62. 8x2 + 6x + 1 = 0 63. x2 + 9x + 8 = 0
64. x2 + 8x = -12 65. x2 + 6x = 40 66. 2x2 = 8
67. x2 = x + 6 68. x2 + 2x - 6 = 0 69. x2 - 12 = 0
70. 3x2 + 4x = 6 71. 7x2 - 105 = 0 72. 16x2 = 81
73. x2 + 5x + 4 = 0 74. x2 + 36 = -13x 75. x2 + 6 = 5x
4916
Name Class Date
Lesson 5-5 Practice Algebra 2 Chapter 56
© P
ears
on E
duca
tion,
Inc.
, pub
lishi
ng a
s Pe
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entic
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all.
All
righ
ts r
eser
ved.
Practice 5-5 Quadratic Equations
Solve each equation by factoring, by taking square roots, or by graphing.When necessary, round your answer to the nearest hundredth.
1. x2 - 18x - 40 = 0 2. 16x2 = 56x 3. 5x2 = 15x
4. x2 - 6x - 7 = 0 5. x2 - 49 = 0 6. x2 + 2x + 1 = 0
7. x2 - 1 = 0 8. x2 - 3x - 4 = 0 9. x2 + 9x2 + 20 = 0
10. 6x2 + 9 = -55x 11. (x + 5)2 = 36 12. 2x2 - 3x = 0
13. 2x2 + x - 10 = 0 14. -4x2 + 3x = -1 15. 5x2 - 6x + 1 = 0
16. 3x2 + 1 = -4x 17. -2x2 + 2 = -3x 18. 6x2 + 1 = 5x
19. -2x2 - x + 1 = 0 20. 3x2 + 5x = 2 21. x2 - 6x = -8
22. x2 + 6 = -7x 23. 6x2 + 18x = 0 24. 2x2 + 5 = 11x
25. 3x2 - 7x + 2 = 0 26. 2x2 - 3x = -1 27. 2x2 - x = 6
28. x2 - 144 = 0 29. 4x2 + 2 = 6x 30. 5x2 + 2 = -7x
31. 7x2 + 6x - 1 = 0 32. 2x2 - 6x = -4 33. 11x2 - 12x + 1 = 0
34. 7x2 + 1 = -8x 35. x2 + 9 = -10x 36. (x - 2)2 = 18
37. x2 - 8x + 7 = 0 38. x2 - 16 = 0 39. x2 + 6x = -8
40. x2 + 3 = 4x 41. 2x2 + 6 = -7x 42. 6x2 + 2 = 7x
43. (x + 7)2 = 44. 9x2 - 8x = 1 45. 10x2 + 7x + 1 = 0
46. 4x2 + 2 = -9x 47. 3x2 + 4 = 8x 48. 4x2 + 5 + 9x = 0
49. 9x2 + 10x = -1 50. 2x2 + 9x + 4 = 0 51. 2x2 + 6x = -4
52. 11x2 - 1 = -10x 53. 4x2 = 1 54. 6x2 = 12x
55. 25x2 - 9 = 0 56. 2x2 + 11x = 6 57. 8x2 - 6x + 1 = 0
58. x2 + 11 = -12x 59. 6x2 + 2 = 13x 60. x2 = 121
61. 4x2 - 11x = 3 62. 8x2 + 6x + 1 = 0 63. x2 + 9x + 8 = 0
64. x2 + 8x = -12 65. x2 + 6x = 40 66. 2x2 = 8
67. x2 = x + 6 68. x2 + 2x - 6 = 0 69. x2 - 12 = 0
70. 3x2 + 4x = 6 71. 7x2 - 105 = 0 72. 16x2 = 81
73. x2 + 5x + 4 = 0 74. x2 + 36 = -13x 75. x2 + 6 = 5x
4916
Name Class Date
Lesson 5-5 Practice Algebra 2 Chapter 56
© P
ears
on E
duca
tion,
Inc.
, pub
lishi
ng a
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268 Chapter 5 Quadratic Equations and Functions
You can solve an equation in the form ax2 = c by finding square roots.
Solving by Finding Square Roots
Solve 5x2 - 180 = 0.
5x2 - 180 = 0
5x2 = 180 Rewrite in the form ax2 ≠ c.
= Isolate x2.
x2 = 36 Simplify.
x = 46 Find square roots.
Solve each equation by finding square roots.a. 4x2 - 25 = 0 b. 3x2 = 24 c. x2 - = 0
Firefighting Smoke jumpers are in free fall from the time they jump out of a planeuntil they open their parachutes. The function y =-16t2 + 1600 models a jumper’sheight y in feet at t seconds for a jump from 1600 ft. How long is a jumper in freefall if the parachute opens at 1000 ft?
y = -16t2 + 1600
1000 = -16t2 + 1600 Substitute 1000 for y.
-600 = -16t2 Isolate t2.
37.5 = t2
46.1 < t Find square roots.
The jumper is in free fall for about 6.1 seconds.
Check Is the answer reasonable? The negative number -6.1 is also a solution tothe equation. However, since a negative value for time has no meaning inthis case, only the positive solution is reasonable.
a. A smoke jumper jumps from 1400 ft. The function describing the height is y = -16t2 + 1400. Using square roots, find the time during which the jumper is in free fall if the parachute opens at 1000 ft.
b. Solve the equation in part (a) by factoring. Which method do you prefer—usingsquare roots or factoring? Explain.
Not every quadratic equation can be solved by factoring or by finding square roots.You can solve ax2 + bx + c = 0 by graphing y1 = ax2 + bx + c— its relatedquadratic function. The value of y1 is 0 where the graph intersects the x-axis. Eachx-intercept is a and a root of the equation.
You can also solve ax2 + bx + c = 0 by displaying values of y1 = ax2 + bx + cin a table. Scroll through the table to find where y1 changes sign, effectively wherethe graph crosses the x-axis. Then “zoom-in” on the y1 values by adjusting TblStartand ∆ Tbl.
zero of the function
33Quick Check
EXAMPLEEXAMPLE Real-World Connection33
14
22Quick Check
1805
5x25
EXAMPLEEXAMPLE22
12 Solving by Graphing
ConnectionReal-World
Careers Smoke jumpers arefirefighters who parachuteinto areas near forest fires.
– , 5252 –2 , 2"2"2 – , 12
12
5 s
t ≠ 5 or t ≠ –5, and use positivesolution because it describes time; check students’ work.
268
2. Teach
Guided Instruction
Connection to Logic
Point out that the word or is theappropriate word to use whenthe Zero-Product Property isbeing used. This is so, because x = 3 and x = cannot simulta-neously be true. On the otherhand, the word and is theappropriate word when you arelisting the solutions, because eachof the numbers will make theoriginal equation true.
Careers
This example demonstrates justhow important Algebra is tosmoke jumpers or any otherskydivers. Without equations suchas these, they would not knowwhen to release their parachutes,possibly endangering their lives.
Additional Examples
Solve 3x2 - 20x - 7 = 0. , 7
Solve 6x2 - 486 = 0. w9
The function y = -16x2 + 270models the height y in feet of aheavy object x seconds after it isdropped from the top of abuilding that is 270 feet tall. Howlong does it take the object to hitthe ground? about 4.1 s
33
22
21311
EXAMPLEEXAMPLE33
52
EXAMPLEEXAMPLE11
Advanced LearnersHave students research the trajectory of a specificprojectile, and graph the equation.
English Language Learners ELLAsk students what the term similar means in everydaylanguage. Use this definition to help studentsunderstand the geometric meaning of similar figuresas having the same shape (angles) but different size(sides are proportionally related).
L4
learning style: verbal learning style: verbal
PowerPoint
A2_3eTE05_05_267-272 10/20/05 9:28 AM Page 268
![Page 6: To find common and x Rewrite using the Distributive ... · of signs of ac and b. L1 L2 learning style: verbal learning style: visual A2_3eTE05_04_259-265 10/20/05 9:27 AM Page 259](https://reader036.vdocument.in/reader036/viewer/2022071117/600772bd2a652010e34bebea/html5/thumbnails/6.jpg)
268 Chapter 5 Quadratic Equations and Functions
You can solve an equation in the form ax2 = c by finding square roots.
Solving by Finding Square Roots
Solve 5x2 - 180 = 0.
5x2 - 180 = 0
5x2 = 180 Rewrite in the form ax2 ≠ c.
= Isolate x2.
x2 = 36 Simplify.
x = 46 Find square roots.
Solve each equation by finding square roots.a. 4x2 - 25 = 0 b. 3x2 = 24 c. x2 - = 0
Firefighting Smoke jumpers are in free fall from the time they jump out of a planeuntil they open their parachutes. The function y =-16t2 + 1600 models a jumper’sheight y in feet at t seconds for a jump from 1600 ft. How long is a jumper in freefall if the parachute opens at 1000 ft?
y = -16t2 + 1600
1000 = -16t2 + 1600 Substitute 1000 for y.
-600 = -16t2 Isolate t2.
37.5 = t2
46.1 < t Find square roots.
The jumper is in free fall for about 6.1 seconds.
Check Is the answer reasonable? The negative number -6.1 is also a solution tothe equation. However, since a negative value for time has no meaning inthis case, only the positive solution is reasonable.
a. A smoke jumper jumps from 1400 ft. The function describing the height is y = -16t2 + 1400. Using square roots, find the time during which the jumper is in free fall if the parachute opens at 1000 ft.
b. Solve the equation in part (a) by factoring. Which method do you prefer—usingsquare roots or factoring? Explain.
Not every quadratic equation can be solved by factoring or by finding square roots.You can solve ax2 + bx + c = 0 by graphing y1 = ax2 + bx + c— its relatedquadratic function. The value of y1 is 0 where the graph intersects the x-axis. Eachx-intercept is a and a root of the equation.
You can also solve ax2 + bx + c = 0 by displaying values of y1 = ax2 + bx + cin a table. Scroll through the table to find where y1 changes sign, effectively wherethe graph crosses the x-axis. Then “zoom-in” on the y1 values by adjusting TblStartand ∆ Tbl.
zero of the function
33Quick Check
EXAMPLEEXAMPLE Real-World Connection33
14
22Quick Check
1805
5x25
EXAMPLEEXAMPLE22
12 Solving by Graphing
ConnectionReal-World
Careers Smoke jumpers arefirefighters who parachuteinto areas near forest fires.
– , 5252 –2 , 2"2"2 – , 12
12
5 s
t ≠ 5 or t ≠ –5, and use positivesolution because it describes time; check students’ work.
268
2. Teach
Guided Instruction
Connection to Logic
Point out that the word or is theappropriate word to use whenthe Zero-Product Property isbeing used. This is so, because x = 3 and x = cannot simulta-neously be true. On the otherhand, the word and is theappropriate word when you arelisting the solutions, because eachof the numbers will make theoriginal equation true.
Careers
This example demonstrates justhow important Algebra is tosmoke jumpers or any otherskydivers. Without equations suchas these, they would not knowwhen to release their parachutes,possibly endangering their lives.
Additional Examples
Solve 3x2 - 20x - 7 = 0. , 7
Solve 6x2 - 486 = 0. w9
The function y = -16x2 + 270models the height y in feet of aheavy object x seconds after it isdropped from the top of abuilding that is 270 feet tall. Howlong does it take the object to hitthe ground? about 4.1 s
33
22
21311
EXAMPLEEXAMPLE33
52
EXAMPLEEXAMPLE11
Advanced LearnersHave students research the trajectory of a specificprojectile, and graph the equation.
English Language Learners ELLAsk students what the term similar means in everydaylanguage. Use this definition to help studentsunderstand the geometric meaning of similar figuresas having the same shape (angles) but different size(sides are proportionally related).
L4
learning style: verbal learning style: verbal
PowerPoint
A2_3eTE05_05_267-272 10/20/05 9:28 AM Page 268
Practice 5-5 Quadratic Equations
Solve each equation by factoring, by taking square roots, or by graphing.When necessary, round your answer to the nearest hundredth.
1. x2 - 18x - 40 = 0 2. 16x2 = 56x 3. 5x2 = 15x
4. x2 - 6x - 7 = 0 5. x2 - 49 = 0 6. x2 + 2x + 1 = 0
7. x2 - 1 = 0 8. x2 - 3x - 4 = 0 9. x2 + 9x2 + 20 = 0
10. 6x2 + 9 = -55x 11. (x + 5)2 = 36 12. 2x2 - 3x = 0
13. 2x2 + x - 10 = 0 14. -4x2 + 3x = -1 15. 5x2 - 6x + 1 = 0
16. 3x2 + 1 = -4x 17. -2x2 + 2 = -3x 18. 6x2 + 1 = 5x
19. -2x2 - x + 1 = 0 20. 3x2 + 5x = 2 21. x2 - 6x = -8
22. x2 + 6 = -7x 23. 6x2 + 18x = 0 24. 2x2 + 5 = 11x
25. 3x2 - 7x + 2 = 0 26. 2x2 - 3x = -1 27. 2x2 - x = 6
28. x2 - 144 = 0 29. 4x2 + 2 = 6x 30. 5x2 + 2 = -7x
31. 7x2 + 6x - 1 = 0 32. 2x2 - 6x = -4 33. 11x2 - 12x + 1 = 0
34. 7x2 + 1 = -8x 35. x2 + 9 = -10x 36. (x - 2)2 = 18
37. x2 - 8x + 7 = 0 38. x2 - 16 = 0 39. x2 + 6x = -8
40. x2 + 3 = 4x 41. 2x2 + 6 = -7x 42. 6x2 + 2 = 7x
43. (x + 7)2 = 44. 9x2 - 8x = 1 45. 10x2 + 7x + 1 = 0
46. 4x2 + 2 = -9x 47. 3x2 + 4 = 8x 48. 4x2 + 5 + 9x = 0
49. 9x2 + 10x = -1 50. 2x2 + 9x + 4 = 0 51. 2x2 + 6x = -4
52. 11x2 - 1 = -10x 53. 4x2 = 1 54. 6x2 = 12x
55. 25x2 - 9 = 0 56. 2x2 + 11x = 6 57. 8x2 - 6x + 1 = 0
58. x2 + 11 = -12x 59. 6x2 + 2 = 13x 60. x2 = 121
61. 4x2 - 11x = 3 62. 8x2 + 6x + 1 = 0 63. x2 + 9x + 8 = 0
64. x2 + 8x = -12 65. x2 + 6x = 40 66. 2x2 = 8
67. x2 = x + 6 68. x2 + 2x - 6 = 0 69. x2 - 12 = 0
70. 3x2 + 4x = 6 71. 7x2 - 105 = 0 72. 16x2 = 81
73. x2 + 5x + 4 = 0 74. x2 + 36 = -13x 75. x2 + 6 = 5x
4916
Name Class Date
Lesson 5-5 Practice Algebra 2 Chapter 56
© P
ears
on E
duca
tion,
Inc.
, pub
lishi
ng a
s Pe
arso
n Pr
entic
e H
all.
All
righ
ts r
eser
ved.
Practice 5-5 Quadratic Equations
Solve each equation by factoring, by taking square roots, or by graphing.When necessary, round your answer to the nearest hundredth.
1. x2 - 18x - 40 = 0 2. 16x2 = 56x 3. 5x2 = 15x
4. x2 - 6x - 7 = 0 5. x2 - 49 = 0 6. x2 + 2x + 1 = 0
7. x2 - 1 = 0 8. x2 - 3x - 4 = 0 9. x2 + 9x2 + 20 = 0
10. 6x2 + 9 = -55x 11. (x + 5)2 = 36 12. 2x2 - 3x = 0
13. 2x2 + x - 10 = 0 14. -4x2 + 3x = -1 15. 5x2 - 6x + 1 = 0
16. 3x2 + 1 = -4x 17. -2x2 + 2 = -3x 18. 6x2 + 1 = 5x
19. -2x2 - x + 1 = 0 20. 3x2 + 5x = 2 21. x2 - 6x = -8
22. x2 + 6 = -7x 23. 6x2 + 18x = 0 24. 2x2 + 5 = 11x
25. 3x2 - 7x + 2 = 0 26. 2x2 - 3x = -1 27. 2x2 - x = 6
28. x2 - 144 = 0 29. 4x2 + 2 = 6x 30. 5x2 + 2 = -7x
31. 7x2 + 6x - 1 = 0 32. 2x2 - 6x = -4 33. 11x2 - 12x + 1 = 0
34. 7x2 + 1 = -8x 35. x2 + 9 = -10x 36. (x - 2)2 = 18
37. x2 - 8x + 7 = 0 38. x2 - 16 = 0 39. x2 + 6x = -8
40. x2 + 3 = 4x 41. 2x2 + 6 = -7x 42. 6x2 + 2 = 7x
43. (x + 7)2 = 44. 9x2 - 8x = 1 45. 10x2 + 7x + 1 = 0
46. 4x2 + 2 = -9x 47. 3x2 + 4 = 8x 48. 4x2 + 5 + 9x = 0
49. 9x2 + 10x = -1 50. 2x2 + 9x + 4 = 0 51. 2x2 + 6x = -4
52. 11x2 - 1 = -10x 53. 4x2 = 1 54. 6x2 = 12x
55. 25x2 - 9 = 0 56. 2x2 + 11x = 6 57. 8x2 - 6x + 1 = 0
58. x2 + 11 = -12x 59. 6x2 + 2 = 13x 60. x2 = 121
61. 4x2 - 11x = 3 62. 8x2 + 6x + 1 = 0 63. x2 + 9x + 8 = 0
64. x2 + 8x = -12 65. x2 + 6x = 40 66. 2x2 = 8
67. x2 = x + 6 68. x2 + 2x - 6 = 0 69. x2 - 12 = 0
70. 3x2 + 4x = 6 71. 7x2 - 105 = 0 72. 16x2 = 81
73. x2 + 5x + 4 = 0 74. x2 + 36 = -13x 75. x2 + 6 = 5x
4916
Name Class Date
Lesson 5-5 Practice Algebra 2 Chapter 56
© P
ears
on E
duca
tion,
Inc.
, pub
lishi
ng a
s Pe
arso
n Pr
entic
e H
all.
All
righ
ts r
eser
ved.
Practice 5-5 Quadratic Equations
Solve each equation by factoring, by taking square roots, or by graphing.When necessary, round your answer to the nearest hundredth.
1. x2 - 18x - 40 = 0 2. 16x2 = 56x 3. 5x2 = 15x
4. x2 - 6x - 7 = 0 5. x2 - 49 = 0 6. x2 + 2x + 1 = 0
7. x2 - 1 = 0 8. x2 - 3x - 4 = 0 9. x2 + 9x2 + 20 = 0
10. 6x2 + 9 = -55x 11. (x + 5)2 = 36 12. 2x2 - 3x = 0
13. 2x2 + x - 10 = 0 14. -4x2 + 3x = -1 15. 5x2 - 6x + 1 = 0
16. 3x2 + 1 = -4x 17. -2x2 + 2 = -3x 18. 6x2 + 1 = 5x
19. -2x2 - x + 1 = 0 20. 3x2 + 5x = 2 21. x2 - 6x = -8
22. x2 + 6 = -7x 23. 6x2 + 18x = 0 24. 2x2 + 5 = 11x
25. 3x2 - 7x + 2 = 0 26. 2x2 - 3x = -1 27. 2x2 - x = 6
28. x2 - 144 = 0 29. 4x2 + 2 = 6x 30. 5x2 + 2 = -7x
31. 7x2 + 6x - 1 = 0 32. 2x2 - 6x = -4 33. 11x2 - 12x + 1 = 0
34. 7x2 + 1 = -8x 35. x2 + 9 = -10x 36. (x - 2)2 = 18
37. x2 - 8x + 7 = 0 38. x2 - 16 = 0 39. x2 + 6x = -8
40. x2 + 3 = 4x 41. 2x2 + 6 = -7x 42. 6x2 + 2 = 7x
43. (x + 7)2 = 44. 9x2 - 8x = 1 45. 10x2 + 7x + 1 = 0
46. 4x2 + 2 = -9x 47. 3x2 + 4 = 8x 48. 4x2 + 5 + 9x = 0
49. 9x2 + 10x = -1 50. 2x2 + 9x + 4 = 0 51. 2x2 + 6x = -4
52. 11x2 - 1 = -10x 53. 4x2 = 1 54. 6x2 = 12x
55. 25x2 - 9 = 0 56. 2x2 + 11x = 6 57. 8x2 - 6x + 1 = 0
58. x2 + 11 = -12x 59. 6x2 + 2 = 13x 60. x2 = 121
61. 4x2 - 11x = 3 62. 8x2 + 6x + 1 = 0 63. x2 + 9x + 8 = 0
64. x2 + 8x = -12 65. x2 + 6x = 40 66. 2x2 = 8
67. x2 = x + 6 68. x2 + 2x - 6 = 0 69. x2 - 12 = 0
70. 3x2 + 4x = 6 71. 7x2 - 105 = 0 72. 16x2 = 81
73. x2 + 5x + 4 = 0 74. x2 + 36 = -13x 75. x2 + 6 = 5x
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Lesson 5-5 Practice Algebra 2 Chapter 56
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268 Chapter 5 Quadratic Equations and Functions
You can solve an equation in the form ax2 = c by finding square roots.
Solving by Finding Square Roots
Solve 5x2 - 180 = 0.
5x2 - 180 = 0
5x2 = 180 Rewrite in the form ax2 ≠ c.
= Isolate x2.
x2 = 36 Simplify.
x = 46 Find square roots.
Solve each equation by finding square roots.a. 4x2 - 25 = 0 b. 3x2 = 24 c. x2 - = 0
Firefighting Smoke jumpers are in free fall from the time they jump out of a planeuntil they open their parachutes. The function y =-16t2 + 1600 models a jumper’sheight y in feet at t seconds for a jump from 1600 ft. How long is a jumper in freefall if the parachute opens at 1000 ft?
y = -16t2 + 1600
1000 = -16t2 + 1600 Substitute 1000 for y.
-600 = -16t2 Isolate t2.
37.5 = t2
46.1 < t Find square roots.
The jumper is in free fall for about 6.1 seconds.
Check Is the answer reasonable? The negative number -6.1 is also a solution tothe equation. However, since a negative value for time has no meaning inthis case, only the positive solution is reasonable.
a. A smoke jumper jumps from 1400 ft. The function describing the height is y = -16t2 + 1400. Using square roots, find the time during which the jumper is in free fall if the parachute opens at 1000 ft.
b. Solve the equation in part (a) by factoring. Which method do you prefer—usingsquare roots or factoring? Explain.
Not every quadratic equation can be solved by factoring or by finding square roots.You can solve ax2 + bx + c = 0 by graphing y1 = ax2 + bx + c— its relatedquadratic function. The value of y1 is 0 where the graph intersects the x-axis. Eachx-intercept is a and a root of the equation.
You can also solve ax2 + bx + c = 0 by displaying values of y1 = ax2 + bx + cin a table. Scroll through the table to find where y1 changes sign, effectively wherethe graph crosses the x-axis. Then “zoom-in” on the y1 values by adjusting TblStartand ∆ Tbl.
zero of the function
33Quick Check
EXAMPLEEXAMPLE Real-World Connection33
14
22Quick Check
1805
5x25
EXAMPLEEXAMPLE22
12 Solving by Graphing
ConnectionReal-World
Careers Smoke jumpers arefirefighters who parachuteinto areas near forest fires.
– , 5252 –2 , 2"2"2 – , 12
12
5 s
t ≠ 5 or t ≠ –5, and use positivesolution because it describes time; check students’ work.
268
2. Teach
Guided Instruction
Connection to Logic
Point out that the word or is theappropriate word to use whenthe Zero-Product Property isbeing used. This is so, because x = 3 and x = cannot simulta-neously be true. On the otherhand, the word and is theappropriate word when you arelisting the solutions, because eachof the numbers will make theoriginal equation true.
Careers
This example demonstrates justhow important Algebra is tosmoke jumpers or any otherskydivers. Without equations suchas these, they would not knowwhen to release their parachutes,possibly endangering their lives.
Additional Examples
Solve 3x2 - 20x - 7 = 0. , 7
Solve 6x2 - 486 = 0. w9
The function y = -16x2 + 270models the height y in feet of aheavy object x seconds after it isdropped from the top of abuilding that is 270 feet tall. Howlong does it take the object to hitthe ground? about 4.1 s
33
22
21311
EXAMPLEEXAMPLE33
52
EXAMPLEEXAMPLE11
Advanced LearnersHave students research the trajectory of a specificprojectile, and graph the equation.
English Language Learners ELLAsk students what the term similar means in everydaylanguage. Use this definition to help studentsunderstand the geometric meaning of similar figuresas having the same shape (angles) but different size(sides are proportionally related).
L4
learning style: verbal learning style: verbal
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