today the - ucsd mathematics | hometkemp/18/math18-lecture5-b00-after.pdftheorem. let a be a matrix...
TRANSCRIPT
Today : § 1.4 : The Matrix Equation Aek
& § 1.5 : Solution Sets
Next : § 1.7 : Linear Independence
Reminders :
My Math Lab Homework # 1 of # 2 : Due Men,
Jan 22
MATLAB Homework # 1 : Due TONIGHT 1
Theorem : Let A be an mxw matrix.
The following four statements are equivalent.
(a) A x. = b. can be solved for I,
for any b. e Rm .
(b) Every vector b. EIRM is a linear combination
of the columns of A.
(c) The columns of A span Rm.
(d) A has a pivot in each row .
Eg .
Let A =
#I
,If } ) .
Do the columns of A spanR3 ?
rew&P§ rref ( MATLAB )
- 4/3 -413
A =L's! ;io1Question : Is /§/ in the span of the columns of A ?KEYIiftp.E.IM#*li3*ili9
1.5 Solution Sets of Linear Systems
Def .
A system of equations is homogeneous ifit has the form A ± =p zero vector ( ¥ )
3×+5*-4×3=0⇒ 1.3.52µ §gfl8)
. 3×, -2×2+4×3 = 0
¢ system of equations matrix equation §s u
xpttxtsfxsffffd ⇒ 13144181
vector equation augmented matrix
Key observation : there is always at least one solution : x. =p.
But there may be mere.
I :{tiled → 635daL → toiii. → patted → Helbigrename
→ § free×
' ii.If µaftmg*fHosts Ml →spandaulisted8k¥49'
Iiidtiiinsxol ¥I¥t¥¥f
parametric solution
smutty =ttµFELl¥ffI¥y
Inhomogeneous systems are linear systems that are net homogeneous.
it.
A x. =b where b. to.
egl :
;taigl→l'ftp.l-teiiiiiil
s :b"
f.l¥*dt÷¥.tt?t.#.ytH+HnwtF.YIri
-
compare to \ \? #
Mfg;D,
I
:ihi:lnl¥*fsH + TH + a
'⇒ HEIM"yd=td ; lY¥
wesawks.yi.gl#ldgIobiiodE..fMgsl↳ s
Wealsesaw =s(4Y|
KEY !
.tl#ldfIobiiflNosdutrn!
Theorem .Let A be a matrix
.
Denote the (parametric)solution set of the homogeneous equation
A ± = e
as Vh.
(a) Even though A x. = e is always consistent ( I =p
is always in vn ),
for given b. ¥ e , the equation
A x. = b. may be Inconsistent.
(b) If A x. = b. is consistent lie.
b. is in the span of the
columns of A ) and if x. =p is any particularsolution
,then the general solution is x. =p + vh .