traffic example
TRANSCRIPT
-
7/26/2019 traffic example
1/5
FL
-
7/26/2019 traffic example
2/5
1. q = au +bu ,u = 50q = 2900
2900 = 2500 a + 50 b (I)
dqdu
=2au+b=0, u = 50 at
qm
0 = 100 a + b (II)
III a = -1.16, b = 116
Free Flow Spee!
q = au +bu = u(au+b)= 0 au+b=0a=1.16,b=116 u=100km
h
u=0; whichis not the answer
-
7/26/2019 traffic example
3/5
2. S =S f (1- (D /Dj)
3.5
)
"# = $%00 &e''
* = 10
" = S " =S f (
D3.5
D4.5 )
D /Dj
D /Dj
14.5 ( 3.5 )=0dV
dD=S
f
For "#!
S0=S f(1 14.5 )=0.778S f
"# =S
0D
0
$%00 = 0.% S f (1/4.5)1/3.5DjDj=140
Sf=53.69kmh
S0=41.77
km
h
-
7/26/2019 traffic example
4/5
$. %0 0.%/ = 0 / = 100
q = 000 &e''(5100)000 = $000 $000 = %0/ - 0.
/ = 50 , 150
S = " {
3000
150=20
km
h
3000
50=60
km
h
-
7/26/2019 traffic example
5/5
. er#33&e!
Y>2.5+
60km
h(10
36 )2 (3.4+0 )
=4.95 sec
Y>4.95 sec
Y>2.5+60(
10
36)
2(3.4 )+
(12+6)
60 (10
36)=6.03 sec
Y>6.03 sec