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TWI Oilfield Fabrication 1560 River Road Fruita, Colorado 81521 Date Printed: 11/27/2012 CUSTOMER TAQA North LTD 1106 West 2nd Street Suite 2 Williston, ND 58801 VESSEL LOCATION TAQA North LTD 1106 West 2nd Street Suite 2 Williston, ND 58801 VESSEL DESCRIPTION 30"x96" 300 MAWP VT Sand Seperator Vessel designed with DesignCalcs, Version: 2013.0 Vessel is ASME Code Stamped Wind Analysis performed in accordance with IBC 2006 Seismic Analysis performed in accordance with IBC 2006 T.M. No: CW15011 Vessel Number: CW15011.1 NAMEPLATE INFORMATION Vessel MAWP: 300.00 PSI at 100 °F MDMT: -20 °F at 300.00 PSI Serial Number(s): CW15011.1 National Board Number(s): __________________________________ Year Built: 2012 Radiography: NONE Postweld Heat Treated: NONE Construction Type: W Signatures Authorized Inspector:_______________________________________________________________ Date: ____/____/____ Jim Radigan Detailing Supervisor:_______________________________________________________________ Date: ____/____/____ Kelly Chamberlain Quality Control Manager:_______________________________________________________________ Date: ____/____/____ Kelly Chamberlain Fabrication Supervisor:_______________________________________________________________ Date: ____/____/____ Kelly Chamberlain

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Page 1: TWI Oilfield Fabrication - twi-fab.comtwi-fab.com/images/CW15011 DesignCalcs Reports.pdf · TWI Oilfield Fabrication 1560 ... 1106 West 2nd Street Suite 2 Williston, ND 58801 VESSEL

TWI Oilfield Fabrication1560 River Road Fruita, Colorado 81521

Date Printed: 11/27/2012

CUSTOMERTAQA North LTD

1106 West 2nd Street Suite 2Williston, ND 58801

VESSEL LOCATIONTAQA North LTD

1106 West 2nd Street Suite 2Williston, ND 58801

VESSEL DESCRIPTION30"x96" 300 MAWP VT Sand Seperator

Vessel designed with DesignCalcs, Version: 2013.0Vessel is ASME Code Stamped

Wind Analysis performed in accordance with IBC 2006Seismic Analysis performed in accordance with IBC 2006

T.M. No: C W 1 5 0 1 1Vessel Number: C W 1 5 0 1 1 . 1

NAMEPLATE INFORMATIONVessel MAWP: 300.00 PSI at 100 °F

M D M T : -20 °F at 300.00 PSISerial Number(s): CW15011.1

National Board Number(s): __________________________________Year Built: 2012

R a d i o g r a p h y : NONEPostweld Heat Treated: NONE

Construction Type: W

Signatures

Authorized Inspector:_______________________________________________________________ Date: ____/____/____ Jim Radigan

Detailing Supervisor:_______________________________________________________________ Date: ____/____/____ Kelly Chamberlain

Quality Control Manager:_______________________________________________________________ Date: ____/____/____ Kelly Chamberlain

Fabrication Supervisor:_______________________________________________________________ Date: ____/____/____ Kelly Chamberlain

Page 2: TWI Oilfield Fabrication - twi-fab.comtwi-fab.com/images/CW15011 DesignCalcs Reports.pdf · TWI Oilfield Fabrication 1560 ... 1106 West 2nd Street Suite 2 Williston, ND 58801 VESSEL

TWI Oilfield Fabrication1560 River Road Fruita, Colorado 81521

Date Printed: 11/27/2012

Page 3: TWI Oilfield Fabrication - twi-fab.comtwi-fab.com/images/CW15011 DesignCalcs Reports.pdf · TWI Oilfield Fabrication 1560 ... 1106 West 2nd Street Suite 2 Williston, ND 58801 VESSEL

TWI Oilfield FabricationShell 1

C u s t o m e r : TAQA North LTDT.M. No: CW15011 Vessel Number: CW15011.1 N u m b e r : 1 Mark Number: S1

Date Printed: 11/27/2012

Cylindrical Shell Design Information

Design Pressure: 300.00 PSI Design Temperature: 100 °FStatic Head: 0.00 PSI Long. Joint Efficiency: 70 %

Shell Material: SA-516 Gr. 70 Factor B Chart: CS-2Material Stress (hot): 20000 PSI

Shell Length: 96.0000 in. Material Stress (cold): 20000 PSICompressive Stress: 16588 PSI

Corrosion Allowance: 0.0625 in. Actual Circumferential Stress: 14522 PSIExternal Corrosion Allowance: 0.0000 in. Actual Longitudinal Stress: 7047 PSI

Outside Diameter (new): 30.0000 in.Outside Diameter (corroded): 30.0000 in. Specific Gravity: 1.00

Shell Surface Area: 62.83 Sq. Ft. Weight of Fluid: 2293.47 lb.Shell Estimated Volume: 274.53 Gal. Total Flooded Shell Weight: 3539.05 lb.

Circ. Joint Efficiency: 70 % Shell Weight: 1245.58 lb.

Minimum Design Metal Temperature Data

Min. Temperature Curve: B Pressure at MDMT: 300.00 PSIUCS-66(b) reduction: Yes Minimum Design Metal Temperature: -20 °FUCS-68(c) reduction: No Computed Minimum Temperature: -50 °F

Design Thickness Calculations

Longitudinal Stress Calculations per Paragraph UG-27(c)(2)

t = PR

2SE + 0.4P =

300.00 * 14.5625

2 * 20000 * 0.70 + 0.4 * 300.00 = 0.1554 + 0.0625 ( c o r r o s i o n ) + 0.0000 (ext. corrosion) = minimum of 0.2179 i n .

Circumferential Stress Calculations per Appendix 1-1(a)(1)

t = PRo

SE + 0.4P=

300.00 * 15.0000

20000 * 0.70 + 0.4 * 300.00 = 0.3187 + 0.0625 ( c o r r o s i o n ) + 0.0000 (ext. corrosion) = minimum of 0.3812 i n .

Extreme Fiber Elongation Calculation per Paragraph UCS-79

Elongation = 50t

Rf=

50 * 0.5000

14.7500 = elongation of 1.69 %

External loads do not control design.

Nominal Shell Thickness Selected = 0.5000 i n .

DesignCalcs version: 2013.0 ©CEI 2013Page 1 of 48

Page 4: TWI Oilfield Fabrication - twi-fab.comtwi-fab.com/images/CW15011 DesignCalcs Reports.pdf · TWI Oilfield Fabrication 1560 ... 1106 West 2nd Street Suite 2 Williston, ND 58801 VESSEL

TWI Oilfield FabricationHead 1

C u s t o m e r : TAQA North LTDT.M. No: CW15011 Vessel Number: CW15011.1 N u m b e r : 1 Mark Number: H1

Date Printed: 11/27/2012

Ellipsoidal Head Design Information

Design Pressure: 300.00 PSI Design Temperature: 100 °FStatic Head: 0.00 PSI Joint Efficiency: 70 %

Head Material: SA-516 Gr. 70 Factor B Chart: CS-2Material Stress (hot): 20000 PSI

Corrosion Allowance: 0.1250 in. Material Stress (cold): 20000 PSIExternal Corrosion Allowance: 0.0000 in. Actual Head Stress: 19984 PSI

Head Location: Left Straight Flange : 0.0000 in.Outside Diameter : 30.0000 in. Head Depth (ho) : 7.7500 in.

Thin Out : 0.0625 in.

K = 1

6 [2 + (D/2h)² ] : 0.99

Head Surface Area: 6.59 Sq. Ft. Specific Gravity: 1.00Head Estimated Volume: 13.82 Gal. Weight of Fluid: 115.28 lb.

Head Weight: 132.80 lb. Total Flooded Head Weight: 248.08 lb.

Minimum Design Metal Temperature Data

Min. Temperature Curve: C Pressure at MDMT: 300.00 PSIUCS-66(b) reduction: Yes Minimum Design Metal Temperature: -20 °FUCS-68(c) reduction: No Computed Minimum Temperature: -55 °F

Design Thickness Calculations

Design Thickness Calculations per Appendix 1-4(c)

t = PDoK

2SE + 2P(K - 0.1) =

300.00 * 30.0000 * 0.99

2 * 20000 * 0.70 + 2 * 300.00 * (0.99 - 0.1)

= 0.3123 + 0.1250 ( c o r r o s i o n ) + 0.0000 (ext. corrosion) + 0.0625(thin out) = minimum of 0.4998 i n .

Extreme Fiber Elongation Calculation per Paragraph UCS-79

elongation = 75t

Rf =

75 * 0.5000

5.0150 = elongation of 7.48 %

Nominal Head Thickness Selected = 0.5000 i n .Minimum Thickness after forming, ts (uncorroded) = 0.4375 i n .

DesignCalcs version: 2013.0 ©CEI 2013Page 2 of 48

Page 5: TWI Oilfield Fabrication - twi-fab.comtwi-fab.com/images/CW15011 DesignCalcs Reports.pdf · TWI Oilfield Fabrication 1560 ... 1106 West 2nd Street Suite 2 Williston, ND 58801 VESSEL

TWI Oilfield FabricationHead 2

C u s t o m e r : TAQA North LTDT.M. No: CW15011 Vessel Number: CW15011.1 N u m b e r : 2 Mark Number: H2

Date Printed: 11/27/2012

Ellipsoidal Head Design Information

Design Pressure: 300.00 PSI Design Temperature: 100 °FStatic Head: 0.00 PSI Joint Efficiency: 70 %

Head Material: SA-516 Gr. 70 Factor B Chart: CS-2Material Stress (hot): 20000 PSI

Corrosion Allowance: 0.1250 in. Material Stress (cold): 20000 PSIExternal Corrosion Allowance: 0.0000 in. Actual Head Stress: 19984 PSI

Head Location: Right Straight Flange : 0.0000 in.Outside Diameter : 30.0000 in. Head Depth (ho) : 7.7500 in.

Thin Out : 0.0625 in.

K = 1

6 [2 + (D/2h)² ] : 0.99

Head Surface Area: 6.59 Sq. Ft. Specific Gravity: 1.00Head Estimated Volume: 13.82 Gal. Weight of Fluid: 115.28 lb.

Head Weight: 132.80 lb. Total Flooded Head Weight: 248.08 lb.

Minimum Design Metal Temperature Data

Min. Temperature Curve: C Pressure at MDMT: 300.00 PSIUCS-66(b) reduction: Yes Minimum Design Metal Temperature: -20 °FUCS-68(c) reduction: No Computed Minimum Temperature: -55 °F

Design Thickness Calculations

Design Thickness Calculations per Appendix 1-4(c)

t = PDoK

2SE + 2P(K - 0.1) =

300.00 * 30.0000 * 0.99

2 * 20000 * 0.70 + 2 * 300.00 * (0.99 - 0.1)

= 0.3123 + 0.1250 ( c o r r o s i o n ) + 0.0000 (ext. corrosion) + 0.0625(thin out) = minimum of 0.4998 i n .

Extreme Fiber Elongation Calculation per Paragraph UCS-79

elongation = 75t

Rf =

75 * 0.5000

5.0150 = elongation of 7.48 %

Nominal Head Thickness Selected = 0.5000 i n .Minimum Thickness after forming, ts (uncorroded) = 0.4375 i n .

DesignCalcs version: 2013.0 ©CEI 2013Page 3 of 48

Page 6: TWI Oilfield Fabrication - twi-fab.comtwi-fab.com/images/CW15011 DesignCalcs Reports.pdf · TWI Oilfield Fabrication 1560 ... 1106 West 2nd Street Suite 2 Williston, ND 58801 VESSEL

TWI Oilfield FabricationNozzle 1

C u s t o m e r : TAQA North LTDT.M. No: CW15011 Vessel Number: CW15011.1N u m b e r : 1 Mark Number: N1

ID Number: 1

Date Printed: 11/27/2012

Nozzle Design Information

Design Pressure: 300.00 PSI Design Temperature: 100 °FStatic Head: 0.00 PSI Nozzle Efficiency (E): 100 %

Nozzle Material: SA-106 Gr. B Joint Efficiency (E1): 1.00Factor B Chart: CS-2

External Projection: 5.0000 in. Allowable Stress at Design Temperature (Sn): 17100 PSIInternal Projection: 0.0000 in. Allowable Stress at Ambient Temperature: 17100 PSI

Inside Corrosion Allowance: 0.1250 in. Correction Factor (F): 1.00External Corrosion Allowance: 0.0000 in. Nozzle Path: None

Nozzle Pipe Size: 3 Nozzle Pipe Schedule: 160Nozzle ID (new): 2.6240 in. Nozzle Wall Thickness(new): 0.4380 in.

Nozzle ID (corroded): 2.8740 in. Nozzle Wall Thickness(corroded): 0.3130 in.External Limit of Reinforcement: 0.7825 in. Upper Weld Leg Size(Weld 41): 0.3130 in.Internal Limit of Reinforcement: 0.4700 in. Internal Weld Leg Size(Weld 43): 0.0000 in.

Parallel Limit of Reinf (2Lpar): 5.7480 in. Outside Groove Weld Depth: 0.5000 in.Minimum Design Metal Temperature

Min. Temp. Curve: B Pressure at MDMT: 300.00 PSIUCS-66(b) reduction: Yes Minimum Design Metal Temperature: -20 °FUCS-68(c) reduction: No Computed Minimum Temperature: -147 °F

Host Component: Shell 1 - Shell 1

Material: SA-516 Gr. 70 Shell wall thickness(new): 0.5000 in.Material Stress(Sv): 20000 PSI Shell wall thickness(corroded): 0.4375 in.

Nozzle Detail Information

Upper Weld Leg Size(Weld 41): 0.3130 in.

Nozzle Wall Thickness(tn): 0.4380 in.

Outside Groove Weld Depth: 0.5000 in.

Nozzle passes through the vessel, attached by a groove weld.Pipe Size: 3 Schedule: 160

Nozzle is adequate for UG-45 requirements.Opening is adequately reinforced for Internal Pressure.

Reinforcement calculations are not required per UG-36(c)(3)(a)See Uw-14 for exceptions.Weld Strength Paths are adequate.

DesignCalcs version: 2013.0 ©CEI 2013Page 4 of 48

Page 7: TWI Oilfield Fabrication - twi-fab.comtwi-fab.com/images/CW15011 DesignCalcs Reports.pdf · TWI Oilfield Fabrication 1560 ... 1106 West 2nd Street Suite 2 Williston, ND 58801 VESSEL

TWI Oilfield FabricationNozzle 1

T.M. No: CW15011 Vessel Number: CW15011.1N u m b e r : 1 Mark Number: N1

ID Number: 1

Date Printed: 11/27/2012

Required Shell Thickness per Paragraph UG-37(a)

tr = PRo

SE + 0.4P =

300.00 * 15.0000

20000 * 1 + 0.4 * 300.00 = 0.2237 i n .

Nozzle Required Thickness Calculations

Required Nozzle Thickness for Internal Pressure per Paragraph UG-37(a)

trn = PRn

SE - 0.6P =

300.00 * 1.4370

17100 * 1 - 0.6 * 300.00 = 0.0255 i n .

Strength Reduction Factors

fr1 = min ¥¦

Sn

Sv, 1.0000

§¨ = min

¥¦

17100

20000, 1.0000

§¨ = 0.8550 fr2 = min

¥¦

Sn

Sv, 1.0000

§¨ = min

¥¦

17100

20000, 1.0000

§¨ = 0.8550

UG-45 Thickness Calculations

Nozzle Thickness for Pressure Loading (plus corrosion)

ta = PRn

SE - 0.6P + Ca + ext. Ca =

300.00 * 1.4370

17100 * 1.00 - 0.6 * 300.00 + 0.1250 + 0.0000 = 0.1505 i n .

Nozzle Thickness for Internal Pressure (plus corrosion) Based on Host

tb1 = PRo

SE + 0.4P + Ca + ext. Ca =

300.00 * 15.0000

20000 * 1 + 0.4 * 300.00 + 0.1250 + 0.0000 = 0.3487 i n .

Minimum Thickness (plus corrosion) per Table UG-45tb3 = minimum thickness (Table UG-45) + Ca + ext. Ca = 0.3140 i n .

Nozzle Minimum Thickness Based on Host and Table UG-45tb = min[tb3, max(tb1, tb2)] = 0.3140 i n .

tUG-45 = max( ta, tb ) = 0.3140 i n .

Wall thickness = tn * 0.875(pipe) = 0.3832 is greater than or equal to UG-45 value of 0.3140

DesignCalcs version: 2013.0 ©CEI 2013Page 5 of 48

Page 8: TWI Oilfield Fabrication - twi-fab.comtwi-fab.com/images/CW15011 DesignCalcs Reports.pdf · TWI Oilfield Fabrication 1560 ... 1106 West 2nd Street Suite 2 Williston, ND 58801 VESSEL

TWI Oilfield FabricationNozzle 2

C u s t o m e r : TAQA North LTDT.M. No: CW15011 Vessel Number: CW15011.1N u m b e r : 2 Mark Number: N2

ID Number: 2

Date Printed: 11/27/2012

Nozzle Design Information

Design Pressure: 300.00 PSI Design Temperature: 100 °FStatic Head: 0.00 PSI Nozzle Efficiency (E): 100 %

Nozzle Material: SA-106 Gr. B Joint Efficiency (E1): 1.00Factor B Chart: CS-2

External Projection: 5.0000 in. Allowable Stress at Design Temperature (Sn): 17100 PSIInternal Projection: 0.0000 in. Allowable Stress at Ambient Temperature: 17100 PSI

Inside Corrosion Allowance: 0.1250 in. Correction Factor (F): 1.00External Corrosion Allowance: 0.0000 in. Nozzle Path: None

Nozzle Pipe Size: 3 Nozzle Pipe Schedule: 160Nozzle ID (new): 2.6240 in. Nozzle Wall Thickness(new): 0.4380 in.

Nozzle ID (corroded): 2.8740 in. Nozzle Wall Thickness(corroded): 0.3130 in.External Limit of Reinforcement: 0.7813 in. Upper Weld Leg Size(Weld 41): 0.3125 in.Internal Limit of Reinforcement: 0.4700 in. Internal Weld Leg Size(Weld 43): 0.0000 in.

Parallel Limit of Reinf (2Lpar): 5.7480 in. Outside Groove Weld Depth: 0.5000 in.Minimum Design Metal Temperature

Min. Temp. Curve: B Pressure at MDMT: 300.00 PSIUCS-66(b) reduction: Yes Minimum Design Metal Temperature: -20 °FUCS-68(c) reduction: No Computed Minimum Temperature: -155 °F

Host Component: Head 2 - Head 2

Material: SA-516 Gr. 70 Head wall thickness(new): 0.5000 in.Material Stress(Sv): 20000 PSI Head wall thickness - thin out (corroded): 0.3125 in.

Nozzle Detail Information

Upper Weld Leg Size(Weld 41): 0.3125 in.

Internal Weld Leg Size(Weld 43): 0.0000 in.

Nozzle Wall Thickness(tn): 0.4380 in.

Outside Groove Weld Depth: 0.5000 in.

Nozzle passes through the vessel, attached by a groove weld.Pipe Size: 3 Schedule: 160

Nozzle is adequate for UG-45 requirements.Opening is adequately reinforced for Internal Pressure.

Reinforcement calculations are not required per UG-36(c)(3)(a)See Uw-14 for exceptions.Weld Strength Paths are adequate.

DesignCalcs version: 2013.0 ©CEI 2013Page 6 of 48

Page 9: TWI Oilfield Fabrication - twi-fab.comtwi-fab.com/images/CW15011 DesignCalcs Reports.pdf · TWI Oilfield Fabrication 1560 ... 1106 West 2nd Street Suite 2 Williston, ND 58801 VESSEL

TWI Oilfield FabricationNozzle 2

T.M. No: CW15011 Vessel Number: CW15011.1N u m b e r : 2 Mark Number: N2

ID Number: 2

Date Printed: 11/27/2012

Required Head Thickness per Paragraph UG-37(a)

tr = P K1 Do

(2SE + 0.8P) =

300.00 * 0.8900 * 30.0000

(2 * 20000 * 1 + 0.8 * 300.00) = 0.1991 i n .

Nozzle Required Thickness Calculations

Required Nozzle Thickness for Internal Pressure per Paragraph UG-37(a)

trn = PRn

SE - 0.6P =

300.00 * 1.4370

17100 * 1 - 0.6 * 300.00 = 0.0255 i n .

Strength Reduction Factors

fr1 = min ¥¦

Sn

Sv, 1.0000

§¨ = min

¥¦

17100

20000, 1.0000

§¨ = 0.8550 fr2 = min

¥¦

Sn

Sv, 1.0000

§¨ = min

¥¦

17100

20000, 1.0000

§¨ = 0.8550

UG-45 Thickness Calculations

Nozzle Thickness for Pressure Loading (plus corrosion)

ta = PRn

SE - 0.6P + Ca + ext. Ca =

300.00 * 1.4370

17100 * 1.00 - 0.6 * 300.00 + 0.1250 + 0.0000 = 0.1505 i n .

Nozzle Thickness for Internal Pressure (plus corrosion) Based on Host

tb1 = P K Do

(2SE + 2P(K - 0.1)) + Ca + ext. Ca =

300.00 * 0.9900 * 30.0000

(2 * 20000 * 1 + 2 * 300.00 * (0.9900 - 0.1)) + 0.1250 + 0.0000 = 0.3448 i n .

Minimum Thickness (plus corrosion) per Table UG-45tb3 = minimum thickness (Table UG-45) + Ca + ext. Ca = 0.3140 i n .

Nozzle Minimum Thickness Based on Host and Table UG-45tb = min[tb3, max(tb1, tb2)] = 0.3140 i n .

tUG-45 = max( ta, tb ) = 0.3140 i n .

Wall thickness = tn * 0.875(pipe) = 0.3832 is greater than or equal to UG-45 value of 0.3140

DesignCalcs version: 2013.0 ©CEI 2013Page 7 of 48

Page 10: TWI Oilfield Fabrication - twi-fab.comtwi-fab.com/images/CW15011 DesignCalcs Reports.pdf · TWI Oilfield Fabrication 1560 ... 1106 West 2nd Street Suite 2 Williston, ND 58801 VESSEL

TWI Oilfield FabricationNozzle 3

C u s t o m e r : TAQA North LTDT.M. No: CW15011 Vessel Number: CW15011.1N u m b e r : 3 Mark Number: N3

ID Number: 3

Date Printed: 11/27/2012

Nozzle Design Information

Design Pressure: 300.00 PSI Design Temperature: 100 °FStatic Head: 0.00 PSI Nozzle Efficiency (E): 100 %

Nozzle Material: SA-105 Joint Efficiency (E1): 1.00Factor B Chart: CS-2

External Projection: 6.0000 in. Allowable Stress at Design Temperature (Sn): 20000 PSIInternal Projection: 0.0000 in. Allowable Stress at Ambient Temperature: 20000 PSI

Inside Corrosion Allowance: 0.1250 in. Correction Factor (F): 1.00External Corrosion Allowance: 0.0000 in. Nozzle Path: None

Nozzle ID (new): 8.0000 in. Nozzle Wall Thickness(new): 0.8800 in.Nozzle ID (corroded): 8.2500 in. Nozzle Wall Thickness(corroded): 0.7550 in.

External Limit of Reinforcement: 1.0938 in. Upper Weld Leg Size(Weld 41): 0.3125 in.Internal Limit of Reinforcement: 1.0938 in. Internal Weld Leg Size(Weld 43): 0.0000 in.

Parallel Limit of Reinf (2Lpar): 16.5000 in. Outside Groove Weld Depth: 0.5000 in.Minimum Design Metal Temperature

Min. Temp. Curve: B Pressure at MDMT: 300.00 PSIUCS-66(b) reduction: Yes Minimum Design Metal Temperature: -20 °FUCS-68(c) reduction: No Computed Minimum Temperature: -117 °F

Host Component: Shell 1 - Shell 1

Material: SA-516 Gr. 70 Shell wall thickness(new): 0.5000 in.Material Stress(Sv): 20000 PSI Shell wall thickness(corroded): 0.4375 in.

Nozzle Detail Information

Upper Weld Leg Size(Weld 41): 0.3125 in.

Internal Weld Leg Size(Weld 43): 0.0000 in.

Nozzle Wall Thickness(tn): 0.8800 in.

Outside Groove Weld Depth: 0.5000 in.

Nozzle passes through the vessel, attached by a groove weld.Nozzle is adequate for UG-45 requirements.

Opening is adequately reinforced for Internal Pressure.Weld Strength Paths are adequate.

DesignCalcs version: 2013.0 ©CEI 2013Page 8 of 48

Page 11: TWI Oilfield Fabrication - twi-fab.comtwi-fab.com/images/CW15011 DesignCalcs Reports.pdf · TWI Oilfield Fabrication 1560 ... 1106 West 2nd Street Suite 2 Williston, ND 58801 VESSEL

TWI Oilfield FabricationNozzle 3

T.M. No: CW15011 Vessel Number: CW15011.1N u m b e r : 3 Mark Number: N3

ID Number: 3

Date Printed: 11/27/2012

Required Shell Thickness per Paragraph UG-37(a)

tr = PRo

SE + 0.4P =

300.00 * 15.0000

20000 * 1 + 0.4 * 300.00 = 0.2237 i n .

Nozzle Required Thickness Calculations

Required Nozzle Thickness for Internal Pressure per Paragraph UG-37(a)

trn = PRn

SE - 0.6P =

300.00 * 4.1250

20000 * 1 - 0.6 * 300.00 = 0.0624 i n .

Strength Reduction Factors

fr1 = min ¥¦

Sn

Sv, 1.0000

§¨ = min

¥¦

20000

20000, 1.0000

§¨ = 1.0000 fr2 = min

¥¦

Sn

Sv, 1.0000

§¨ = min

¥¦

20000

20000, 1.0000

§¨ = 1.0000

UG-45 Thickness Calculations

Nozzle Thickness for Pressure Loading (plus corrosion)

ta = PRn

SE - 0.6P + Ca + ext. Ca =

300.00 * 4.1250

20000 * 1.00 - 0.6 * 300.00 + 0.1250 + 0.0000 = 0.1874 i n .

Nozzle Thickness for Internal Pressure (plus corrosion) Based on Host

tb1 = PRo

SE + 0.4P + Ca + ext. Ca =

300.00 * 15.0000

20000 * 1 + 0.4 * 300.00 + 0.1250 + 0.0000 = 0.3487 i n .

Minimum Thickness (plus corrosion) per Table UG-45tb3 = minimum thickness (Table UG-45) + Ca + ext. Ca = 0.4440 i n .

Nozzle Minimum Thickness Based on Host and Table UG-45tb = min[tb3, max(tb1, tb2)] = 0.3487 i n .

tUG-45 = max( ta, tb ) = 0.3487 i n .

Wall thickness = tn = 0.8800 is greater than or equal to UG-45 value of 0.3487

DesignCalcs version: 2013.0 ©CEI 2013Page 9 of 48

Page 12: TWI Oilfield Fabrication - twi-fab.comtwi-fab.com/images/CW15011 DesignCalcs Reports.pdf · TWI Oilfield Fabrication 1560 ... 1106 West 2nd Street Suite 2 Williston, ND 58801 VESSEL

TWI Oilfield FabricationNozzle 3

T.M. No: CW15011 Vessel Number: CW15011.1N u m b e r : 3 Mark Number: N3

ID Number: 3

Date Printed: 11/27/2012

Limits of Reinforcement (UG-40)

Lpar = max(d, Rn + t + tn) = max(8.2500, 4.0000 + 0.4375 + 0.7550) = 8.2500 i n .Lnoro = min(2.5 t, 2.5 tn + te) = min(2.5 * 0.4375, 2.5 * 0.7550 + 0.0000) = 1.0938 i n .Lnori = min(2.5 t, 2.5 ti) = min(2.5 * 0.4375, 2.5 * 0.6300) = 1.0938 i n .

Nozzle Reinforcement Calculations (Internal Pressure)

A = max{C [d tr F + 2 tn tr F (1 - fr1)], 0} = max{1.0000 * [8.2500 * 0.2237 * 1.00 + 2 * 0.7550 * 0.2237 * 1.00 * (1 - 1.0000)], 0} = 1.8455 sq. in.

A1 = max[(2 Lpar - d) (E1 t - F tr) - 2 tn ( E1 t - F tr) (1 - fr1), 0] =max[(2 * 8.2500 - 8.2500) * (1.0000 * 0.4375 - 1.00 * 0.2237) - 2 * 0.7550 * (1.0000 * 0.4375 - 1.00 * 0.2237) * (1 - 1.0000), 0]

= 1.7639 sq. in.

A2 = max{2 min(ho, Lnoro) [min(tn, Lpar - 0.5 d) - trn] fr2, 0} = max{2 * min(6.0000, 1.0938) * [min(0.7550, 8.2500 - 0.5 * 8.2500) - 0.0624] * 1.0000, 0} = 1.5151 sq. in.

A3 = max{2 min(h, Lnori) min(ti, Lpar - 0.5 d) fr2, 0} = max{2 * min(0.0000, 1.0938) * min(0.6300, 8.2500 - 0.5 * 8.2500) * 1.0000, 0} = 0.0000 sq. in.

A41 = fr2 [ L412 - (L41 - L41pareff)2 - (L41 - L41noreff)2] =

1.0000 * [0.31252 - (0.3125 - 0.3125)2 - (0.3125 - 0.3125)2] = 0.0977 sq. in.

A42 = fr4 L42pareff L42noreff = 0.0000 * 0.0000 * 0.0000 = 0.0000 sq. in.

A43 = fr2 L43pareff L43noreff = 1.0000 * 0.0000 * 0.0000 = 0.0000 sq. in.

A5 = 0.0000 sq. in.

Area Available (Internal Pressure) = A1 + A2 + A3 + A41 + A42 + A43 + A5 = 3.3766 sq. in., which is >= A (1.8455)

DesignCalcs version: 2013.0 ©CEI 2013Page 10 of 48

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TWI Oilfield FabricationNozzle 4

C u s t o m e r : TAQA North LTDT.M. No: CW15011 Vessel Number: CW15011.1N u m b e r : 4 Mark Number: N4

ID Number: 4

Date Printed: 11/27/2012

Nozzle Design Information

Design Pressure: 300.00 PSI Design Temperature: 100 °FStatic Head: 0.00 PSI Nozzle Efficiency (E): 100 %

Nozzle Material: SA-106 Gr. B Joint Efficiency (E1): 1.00Factor B Chart: CS-2

External Projection: 8.0000 in. Allowable Stress at Design Temperature (Sn): 17100 PSIInternal Projection: 0.0000 in. Allowable Stress at Ambient Temperature: 17100 PSI

Inside Corrosion Allowance: 0.1250 in. Correction Factor (F): 1.00External Corrosion Allowance: 0.0000 in. Nozzle Path: None

Nozzle Pipe Size: 3 Nozzle Pipe Schedule: 160Nozzle ID (new): 2.6240 in. Nozzle Wall Thickness(new): 0.4380 in.

Nozzle ID (corroded): 2.8740 in. Nozzle Wall Thickness(corroded): 0.3130 in.Developed Opening: 3.0355 in. Tangential Dimension L: 7.3059 in.

External Limit of Reinforcement: 0.7825 in. Upper Weld Leg Size(Weld 41): 0.3125 in.Internal Limit of Reinforcement: 0.4700 in. Internal Weld Leg Size(Weld 43): 0.0000 in.

Parallel Limit of Reinf (2Lpar): 6.6420 in. Outside Groove Weld Depth: 0.5000 in.Minimum Design Metal Temperature

Min. Temp. Curve: B Pressure at MDMT: 300.00 PSIUCS-66(b) reduction: Yes Minimum Design Metal Temperature: -20 °FUCS-68(c) reduction: No Computed Minimum Temperature: -147 °F

Host Component: Shell 1 - Shell 1

Material: SA-516 Gr. 70 Shell wall thickness(new): 0.5000 in.Material Stress(Sv): 20000 PSI Shell wall thickness(corroded): 0.4375 in.

Nozzle Detail Information

Upper Weld Leg Size(Weld 41): 0.3125 in.

Internal Weld Leg Size(Weld 43): 0.0000 in.

Nozzle Wall Thickness(tn): 0.4380 in.

Outside Groove Weld Depth: 0.5000 in.

tangential to the vessel wall, attached by a groove weld.Pipe Size: 3 Schedule: 160

Nozzle is adequate for UG-45 requirements.Opening is adequately reinforced for Internal Pressure.

Reinforcement calculations are not required per UG-36(c)(3)(a)See Uw-14 for exceptions.Weld Strength Paths are adequate.

DesignCalcs version: 2013.0 ©CEI 2013Page 11 of 48

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TWI Oilfield FabricationNozzle 4

T.M. No: CW15011 Vessel Number: CW15011.1N u m b e r : 4 Mark Number: N4

ID Number: 4

Date Printed: 11/27/2012

Required Shell Thickness per Paragraph UG-37(a)

tr = PRo

SE + 0.4P =

300.00 * 15.0000

20000 * 1 + 0.4 * 300.00 = 0.2237 i n .

Nozzle Required Thickness Calculations

Required Nozzle Thickness for Internal Pressure per Paragraph UG-37(a)

trn = PRn

SE - 0.6P =

300.00 * 1.4370

17100 * 1 - 0.6 * 300.00 = 0.0255 i n .

Strength Reduction Factors

fr1 = min ¥¦

Sn

Sv, 1.0000

§¨ = min

¥¦

17100

20000, 1.0000

§¨ = 0.8550 fr2 = min

¥¦

Sn

Sv, 1.0000

§¨ = min

¥¦

17100

20000, 1.0000

§¨ = 0.8550

UG-45 Thickness Calculations

Nozzle Thickness for Pressure Loading (plus corrosion)

ta = PRn

SE - 0.6P + Ca + ext. Ca =

300.00 * 1.4370

17100 * 1.00 - 0.6 * 300.00 + 0.1250 + 0.0000 = 0.1505 i n .

Nozzle Thickness for Internal Pressure (plus corrosion) Based on Host

tb1 = PRo

SE + 0.4P + Ca + ext. Ca =

300.00 * 15.0000

20000 * 1 + 0.4 * 300.00 + 0.1250 + 0.0000 = 0.3487 i n .

Minimum Thickness (plus corrosion) per Table UG-45tb3 = minimum thickness (Table UG-45) + Ca + ext. Ca = 0.3140 i n .

Nozzle Minimum Thickness Based on Host and Table UG-45tb = min[tb3, max(tb1, tb2)] = 0.3140 i n .

tUG-45 = max( ta, tb ) = 0.3140 i n .

Wall thickness = tn * 0.875(pipe) = 0.3832 is greater than or equal to UG-45 value of 0.3140

DesignCalcs version: 2013.0 ©CEI 2013Page 12 of 48

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TWI Oilfield FabricationNozzle 5

C u s t o m e r : TAQA North LTDT.M. No: CW15011 Vessel Number: CW15011.1N u m b e r : 5 Mark Number: N5

ID Number: 5

Date Printed: 11/27/2012

Nozzle Design Information

Design Pressure: 300.00 PSI Design Temperature: 100 °FStatic Head: 0.00 PSI Nozzle Efficiency (E): 100 %

Nozzle Material: SA-106 Gr. B Joint Efficiency (E1): 1.00Factor B Chart: CS-2

External Projection: 5.0000 in. Allowable Stress at Design Temperature (Sn): 17100 PSIInternal Projection: 0.0000 in. Allowable Stress at Ambient Temperature: 17100 PSI

Inside Corrosion Allowance: 0.1250 in. Correction Factor (F): 1.00External Corrosion Allowance: 0.0000 in. Nozzle Path: None

Nozzle Pipe Size: 3 Nozzle Pipe Schedule: 160Nozzle ID (new): 2.6240 in. Nozzle Wall Thickness(new): 0.4380 in.

Nozzle ID (corroded): 2.8740 in. Nozzle Wall Thickness(corroded): 0.3130 in.External Limit of Reinforcement: 0.7825 in. Upper Weld Leg Size(Weld 41): 0.3130 in.Internal Limit of Reinforcement: 0.4700 in. Internal Weld Leg Size(Weld 43): 0.0000 in.

Parallel Limit of Reinf (2Lpar): 5.7480 in. Outside Groove Weld Depth: 0.5000 in.Minimum Design Metal Temperature

Min. Temp. Curve: Pressure at MDMT: 300.00 PSIUCS-66(b) reduction: Yes Minimum Design Metal Temperature: -20 °FUCS-68(c) reduction: No Computed Minimum Temperature: -155 °F

Host Component: Shell 1 - Shell 1

Material: SA-516 Gr. 70 Shell wall thickness(new): 0.5000 in.Material Stress(Sv): 20000 PSI Shell wall thickness(corroded): 0.4375 in.

Nozzle Detail Information

Upper Weld Leg Size(Weld 41): 0.3130 in.

Nozzle Wall Thickness(tn): 0.4380 in.

Outside Groove Weld Depth: 0.5000 in.

Nozzle passes through the vessel, attached by a groove weld.Pipe Size: 3 Schedule: 160

Nozzle is adequate for UG-45 requirements.Opening is adequately reinforced for Internal Pressure.

Reinforcement calculations are not required per UG-36(c)(3)(a)See Uw-14 for exceptions.Weld Strength Paths are adequate.

DesignCalcs version: 2013.0 ©CEI 2013Page 13 of 48

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TWI Oilfield FabricationNozzle 5

T.M. No: CW15011 Vessel Number: CW15011.1N u m b e r : 5 Mark Number: N5

ID Number: 5

Date Printed: 11/27/2012

Required Shell Thickness per Paragraph UG-37(a)

tr = PRo

SE + 0.4P =

300.00 * 15.0000

20000 * 1 + 0.4 * 300.00 = 0.2237 i n .

Nozzle Required Thickness Calculations

Required Nozzle Thickness for Internal Pressure per Paragraph UG-37(a)

trn = PRn

SE - 0.6P =

300.00 * 1.4370

17100 * 1 - 0.6 * 300.00 = 0.0255 i n .

Strength Reduction Factors

fr1 = min ¥¦

Sn

Sv, 1.0000

§¨ = min

¥¦

17100

20000, 1.0000

§¨ = 0.8550 fr2 = min

¥¦

Sn

Sv, 1.0000

§¨ = min

¥¦

17100

20000, 1.0000

§¨ = 0.8550

UG-45 Thickness Calculations

Nozzle Thickness for Pressure Loading (plus corrosion)

ta = PRn

SE - 0.6P + Ca + ext. Ca =

300.00 * 1.4370

17100 * 1.00 - 0.6 * 300.00 + 0.1250 + 0.0000 = 0.1505 i n .

Nozzle Thickness for Internal Pressure (plus corrosion) Based on Host

tb1 = PRo

SE + 0.4P + Ca + ext. Ca =

300.00 * 15.0000

20000 * 1 + 0.4 * 300.00 + 0.1250 + 0.0000 = 0.3487 i n .

Minimum Thickness (plus corrosion) per Table UG-45tb3 = minimum thickness (Table UG-45) + Ca + ext. Ca = 0.3140 i n .

Nozzle Minimum Thickness Based on Host and Table UG-45tb = min[tb3, max(tb1, tb2)] = 0.3140 i n .

tUG-45 = max( ta, tb ) = 0.3140 i n .

Wall thickness = tn * 0.875(pipe) = 0.3832 is greater than or equal to UG-45 value of 0.3140

DesignCalcs version: 2013.0 ©CEI 2013Page 14 of 48

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TWI Oilfield FabricationLifting Lug 1

C u s t o m e r : TAQA North LTDT.M. No: CW15011 Vessel Number: CW15011.1

Mark Number: LL1

Date Printed: 11/27/2012

Lifting Lug Information

M a t e r i a l : SA-36 Design Temperature: 0 °FC o n d i t i o n : Material Stress (Hot): 16600 PSI

T y p e : Type 1 Material Stress (Cold): 16600 PSILength (L): 10.0000 in. Yield Strength: 36000 PSIT h i c k n e s s : 1.0000 in. R a d i u s : 2.0000 in.

Weld Joint Efficiency: 45 % Weld Leg: 10.0000 in.Shackle Hole Diameter: 1.1250 in. Shackle Hole Centerline Height: 2.0000 in.

Vessel Information

M a t e r i a l : SA-516 Gr. 70 Design Temperature: 100 °FC o n d i t i o n : Material Stress (Hot): 20000 PSI

R a d i u s : 15.0000 in. Material Stress (Cold): 20000 PSIT h i c k n e s s : 0.5000 in. Yield Strength: 38000 PSI

Vertical Lift Angle: 45 ° Impact Factor: 1.50W e i g h t : 1667.79 lb.

Design Calculations

Wi = W * I = 1667.79 * 1.50 = 2502Vertical Lift Force, Fv = Wi = 2502 = 2502 l b .Horizontal Lift Force, Fh = Wi * tan(n) = 2502 * tan(45) = 2502 l b .

Total Lift Force, Ft = Fv² + Fh² = 2502² + 2502² = 3538 l b .

Lug Stress Calculation

Sl = Ft

T * (2 * r' - d) =

3538

1.0000 * ( 2 * 2.0000 - 1.1250) = 1231 P S I

Shear Stress Ratio, Srl = Sl

0.4 * Sly =

1231

0.4 * 36000 = 0.0855

DesignCalcs version: 2013.0 ©CEI 2013Page 15 of 48

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TWI Oilfield FabricationLifting Lug 1

T.M. No: CW15011 Vessel Number: CW15011.1Mark Number: LL1

Date Printed: 11/27/2012

Lug Weld CalculationsLwl = 2 * (L + T) = 2 * (10.0000 + 1.0000) = 22.0000 i n .

Zwl = (T * L) + L²

3 = (1.0000 * 10.0000) +

10.0000²

3 = 43.3333 sq. in.

f1 = Ml

Zwl =

6411

43.3333 = 147.9 l b . / i n .

f2 = Fh

Lwl =

2502

22.0000 = 113.7 l b . / i n .

f3 = Fv

Lwl =

2502

22.0000 = 113.7 l b . / i n .

f = ((f1 + f3)² + f2²) = ((147.9 + 113.7)² + 113.7²) = 285.2 l b . / i n .fw = E * min(Sla, Sva) = 0.45 * min(16600, 20000) = 7470 P S I

WLa = f

fw =

285.2

7470 = 0.0382 i n .

Lug Weld Leg Ratio, WLRl = WLa

WL =

0.0382

10.0000 = 0.0038

DesignCalcs version: 2013.0 ©CEI 2013Page 16 of 48

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TWI Oilfield FabricationSaddle 1

C u s t o m e r : TAQA North LTDT.M. No: CW15011 Vessel Number: CW15011.1 N u m b e r : 1 Mark Number: SDL1

Date Printed: 11/27/2012

Saddle Design Information

Design Temperature: 100 °F Support Type: Type IMaterial: SA-36 Stiffener Quantity: 2

Condition: Material Stress (hot): 16600 PSILength (d): 26.8468 in. Material Stress (cold): 16600 PSI

Top Width (b'): 10.0000 in. Yield Strength: 36000 PSIBottom Width (bb'): 1.0000 in. Density: 0.2800 lb/in.^3

Outside Stiffener Thickness (tso): 0.5000 in. Web Plate Thickness (tw): 0.5000 in.Inside Stiffener Thickness (tsi): 0.2500 in. Vessel Centerline Height (h): 20.5000 in.

Saddle Angle of contact (n): 120.0 ° Elevation above grade (g): 0.0000 in.Dist. from saddle centerline to tang. line (A): 19.2000 in.

Support Design Condition: Shell unstiffened (A/R > 1/2)

Wear Plate Information

Design Temperature: 100 °FMaterial: SA-36 Material Stress (hot): 16600 PSI

Condition: Material Stress (cold): 16600 PSIExtension (jw): 2.0000 in. Use for S2: Yes

Width (bw): 15.0000 in. Use for S3: YesThickness (twp): 0.5000 in. Use for S5: Yes

Base Plate Information

Design Temperature: 100 °F Ultimate 28 Day Concrete Strength: 3000.00 PSIMaterial: SA-36 Yield Strength: 36000 PSI

Condition: Length (m): 29.0000 in.Width (bb): 1.0000 in. Thickness (tb): 0.3750 in.

Anchor Bolt Information

Material: SA-36 Material Stress (hot): 16600 PSICondition: Material Stress (cold): 16600 PSI

Size: 1" Number of Threads per in. : 8.0000Quantity: 2 Root Area: 0.5510 sq. in.

DesignCalcs version: 2013.0 ©CEI 2013Page 17 of 48

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TWI Oilfield Fabrication30"x96" 300 MAWP VT Sand Seperator

C u s t o m e r : TAQA North LTDT.M. No: CW15011 Vessel Number: CW15011.1

Date Printed: 11/27/2012

ASME Flange Design Information

Host Description Type Size M a t e r i a l ASME Material MAP(in.) Class Group (PSI)

Nozzle 1 ASME Flange 1 Slip On 3 S A - 1 0 5 300 1.1 740.00Nozzle 2 ASME Flange 2 Slip On 3 S A - 1 0 5 300 1.1 740.00Nozzle 3 ASME Flange 3 Slip On 8 S A - 1 0 5 300 1.1 740.00Nozzle 4 ASME Flange 4 Slip On 3 S A - 1 0 5 300 1.1 740.00Nozzle 5 ASME Flange 5 Slip On 3 S A - 1 0 5 300 1.1 740.00

DesignCalcs version: 2013.0 ©CEI 2013Page 18 of 48

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TWI Oilfield FabricationC u s t o m e r : TAQA North LTD

T.M. No: CW15011 Vessel Number: CW15011.1

Date Printed: 11/27/2012

Loading SummaryType Starting Point Ending Point Depth Density Wind Diameter

(in.) (in.) (in.) (lb./Ft^3) (in.)Liquid - - 12.0000 40.0000 -Liquid - - 30.0000 62.4000 -

DesignCalcs version: 2013.0 ©CEI 2013Page 19 of 48

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TWI Oilfield FabricationC u s t o m e r : TAQA North LTD

T.M. No: CW15011 Vessel Number: CW15011.1

Date Printed: 11/27/2012

Zick Analysis

IBC 2006 Wind Design Information

Basic Wind Speed (V): 100 MPH

IBC 2006 Seismic Design Information

Spectral Resp. Accel at short periods (Ss): 0.000 Spectral Resp. Accel. at a period of 1 s (S1): 0.000Response Modification Factor (R): 2.000

Occupancy Category: IV Site Class: DSeismic Design Category: A

Operating Pressurized Condition - Sustained Loads

Saddle Support Loads

QL = FLh

L - 2A =

0 * 20.5000

96.0000 - 2 * 19.2000 = 0 l b .

QT = 1.5 FT h

d =

1.5 * 0 * 20.5000

26.8468 = 0 l b .

QW = W

2 =

4032

2 = 2016 l b .

QN = QW = 2016 = 2016 l b .

Saddle Load for Vessel Stress Analysis

Q = QN = 2016 = 2016 l b .

Saddle Load for Support Stress Analysis

QS = QN = 2016 = 2016 l b .

DesignCalcs version: 2013.0 ©CEI 2013Page 20 of 48

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TWI Oilfield FabricationT.M. No: CW15011 Vessel Number: CW15011.1

Date Printed: 11/27/2012

Zick Calculations

Longitudinal Stress Due to Internal Pressure

Sp = P R

2 t =

300.00 * 14.7813

2 * 0.4375= 5068 P S I

Longitudinal Compressive Stress Due to External Pressure

Spe = -Pe R

2 t =

-0.00 * 14.7813

2 * 0.4375= 0 P S I

Longitudinal Bending Stress in the Shell at the MidpointZ1 = m R² t = 3.1416 * 14.7813² * 0.4375 = 300 i n . ³

S1 = K1 Q L

4 Z1 =

0.13386 * 2016 * 96.0000

4 * 300= 22 P S I

Longitudinal Bending Stress in the Shell in the Plane of the Saddle

S1' = K1' Q L

4 Z1 =

1.79288 * 2016 * 96.0000

4 * 300= 289 P S I

Saddle Plane Tangential Shear Stress

te = t + twp = 0.4375 + 0.5000 = 0.9375 i n .

S2 = ¡¢

K2 Q

R te

£¤

¡¢

L - 2 A

L + 4

3 H

£¤

= ¡¢

1.17074 * 2016

14.7813 * 0.9375

£¤

¡¢

96.0000 - 2 * 19.2000

96.0000 + 4

3 * 7.7500

£¤

= 92 P S I

S2w = ¡¢

K2w Q

R t

£¤

¡¢

L - 2 A

L + 4

3 H

£¤

= ¡¢

0.99596 * 2016

14.7813 * 0.4375

£¤

¡¢

96.0000 - 2 * 19.2000

96.0000 + 4

3 * 7.7500

£¤

= 168 P S I

Circumferential Stress at the Horn of the Saddlete² = t² + twp² = 0.4375² + 0.5000² = 0.4414 sq. in.

S3 = - ¡¢

Q

4 te (b + 1.56 R t)

£¤

- ¡¢

12 K3 Q R

L te²

£¤

= - ¡¢

2016

4 * 0.9375 * (10.0000 + 1.56 * 14.7813 * 0.4375)

£¤

- ¡¢

12 * 0.05285 * 2016 * 14.7813

96.0000 * 0.4414

£¤

= -484 P S I

Circumferential Stress at End of the Wear Plate

S3w = - ¡¢

Q

4 t (bw + 1.56 R t)

£¤

- ¡¢

12 K3w Q R

L t²

£¤

= - ¡¢

2016

4 * 0.4375 * (15.0000 + 1.56 * 14.7813 * 0.4375)

£¤

- ¡¢

12 * 0.04345 * 2016 * 14.7813

96.0000 * 0.4375²

£¤

= -906 P S I

DesignCalcs version: 2013.0 ©CEI 2013Page 21 of 48

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TWI Oilfield FabricationT.M. No: CW15011 Vessel Number: CW15011.1

Date Printed: 11/27/2012

Ring Compression in the Shell Over the Saddle

te = t + twp = 0.4375 + 0.5000 = 0.9375 i n .

S5 = K5 Q

te (b + 1.56 R t) =

0.76027 * 2016

0.9375 * (0.5000 + 1.56 * 14.7813 * 0.4375)= 366 P S I

Maximum Splitting Force

Fs = K8Qs = 0.20352 * 2016 = 410 l b .

Saddle Calculations

Base Plate Stress

SBP = 0.75 Qs bb

m tb² =

0.75 * 2016 * 1.0000

29.0000 * 0.3750²= 371 P S I

Concrete Bearing Stress

SC = Qs

bb m =

2016

1.0000 * 29.0000= 70 P S I

Saddle Splitting Force

ST Splitting = FS

ASaddle =

410

2.6875= 153 P S I

M Splitting = FS ¡¢

h - C2 - RW ¥¦

sin(n/2)

n/2

§¨£¤

= 410 * ¡¢

20.5000 - 4.4820 - 15.5000 * ¥¦

sin(1.0472)

1.0472

§¨£¤

= 1312 i n . - l b .

SB Splitting = M C1

I =

1312 * 0.5180

23.0695= 29 P S I

Bolting Shear Stress

Sb = FBolt

Nb Ab =

0

2 * 0.5510= 0 P S I

Saddle Support Stiffener Stresses

Location Length Compressive Stress Bending Stress Allowable Stress Stress Ratio in. PSI PSI PSI RST

Outside 12.3750 146 0 21600 0.0068

DesignCalcs version: 2013.0 ©CEI 2013Page 22 of 48

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TWI Oilfield FabricationT.M. No: CW15011 Vessel Number: CW15011.1

Date Printed: 11/27/2012

Vessel Stress Ratio Calculations

Any ratio greater than 1 represents an overstressed condition

R1t = S1 + Sp

SShell E =

22 + 5068

20000 * 0.70= 0.3636

R1C = -S1

- Min(SShell, BShell) =

-22

-Min(20000,16588)= 0.0013

R1t' = S1' + Sp

SShell E =

289 + 5068

20000 * 0.70= 0.3826

R1C' = -S1'

- Min(SShell, BShell) =

-289

-Min(20000,16588)= 0.0174

R2 = S2

0.8 SShell =

92

0.8 * 20000= 0.0058

R2W = S2W

0.8 SShell =

168

0.8 * 20000= 0.0105

R3 = S3

- ( 1.25 SShell) =

-484

- (1.25 * 20000)= 0.0194

R3w = S3W

- ( 1.25 SShell) =

-906

- (1.25 * 20000)= 0.0362

R5 = S5

0.5 YShell =

366

0.5 * 38000= 0.0193

DesignCalcs version: 2013.0 ©CEI 2013Page 23 of 48

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TWI Oilfield FabricationT.M. No: CW15011 Vessel Number: CW15011.1

Date Printed: 11/27/2012

Saddle Stress Ratio Calculations

Any ratio greater than 1 represents an overstressed condition

RBase Plate = SBP

0.6 YBase Plate =

371

0.6 * 36000= 0.0172

RConcrete = SC

0.25 SConcrete =

70

0.25 * 3000= 0.0933

RWeb = ST Splitting

0.6 YSaddle +

SB Splitting

0.66 YSaddle =

153

0.6 * 36000 +

29

0.66 * 36000= 0.0083

RST = Sstc + Sstb

0.6 YSaddle =

146 + 0

0.6 * 36000= 0.0068

RBolt = SB

0.8 SBa =

0

0.8 * 16600= 0.0000

DesignCalcs version: 2013.0 ©CEI 2013Page 24 of 48

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TWI Oilfield FabricationT.M. No: CW15011 Vessel Number: CW15011.1

Date Printed: 11/27/2012

Operating Unpressurized Condition - Sustained Loads

Saddle Support Loads

QL = FLh

L - 2A =

0 * 20.5000

96.0000 - 2 * 19.2000 = 0 l b .

QT = 1.5 FT h

d =

1.5 * 0 * 20.5000

26.8468 = 0 l b .

QW = W

2 =

4032

2 = 2016 l b .

QN = QW = 2016 = 2016 l b .

Saddle Load for Vessel Stress Analysis

Q = QN = 2016 = 2016 l b .

Saddle Load for Support Stress Analysis

QS = QN = 2016 = 2016 l b .

DesignCalcs version: 2013.0 ©CEI 2013Page 25 of 48

Page 28: TWI Oilfield Fabrication - twi-fab.comtwi-fab.com/images/CW15011 DesignCalcs Reports.pdf · TWI Oilfield Fabrication 1560 ... 1106 West 2nd Street Suite 2 Williston, ND 58801 VESSEL

TWI Oilfield FabricationT.M. No: CW15011 Vessel Number: CW15011.1

Date Printed: 11/27/2012

Zick Calculations

Longitudinal Stress Due to Internal Pressure

Sp = P R

2 t =

0.00 * 14.7813

2 * 0.4375= 0 P S I

Longitudinal Compressive Stress Due to External Pressure

Spe = = 0 P S I

Longitudinal Bending Stress in the Shell at the MidpointZ1 = m R² t = 3.1416 * 14.7813² * 0.4375 = 300 i n . ³

S1 = K1 Q L

4 Z1 =

0.13386 * 2016 * 96.0000

4 * 300= 22 P S I

Longitudinal Bending Stress in the Shell in the Plane of the Saddle

S1' = K1' Q L

4 Z1 =

1.79288 * 2016 * 96.0000

4 * 300= 289 P S I

Saddle Plane Tangential Shear Stress

te = t + twp = 0.4375 + 0.5000 = 0.9375 i n .

S2 = ¡¢

K2 Q

R te

£¤

¡¢

L - 2 A

L + 4

3 H

£¤

= ¡¢

1.17074 * 2016

14.7813 * 0.9375

£¤

¡¢

96.0000 - 2 * 19.2000

96.0000 + 4

3 * 7.7500

£¤

= 92 P S I

S2w = ¡¢

K2w Q

R t

£¤

¡¢

L - 2 A

L + 4

3 H

£¤

= ¡¢

0.99596 * 2016

14.7813 * 0.4375

£¤

¡¢

96.0000 - 2 * 19.2000

96.0000 + 4

3 * 7.7500

£¤

= 168 P S I

Circumferential Stress at the Horn of the Saddlete² = t² + twp² = 0.4375² + 0.5000² = 0.4414 sq. in.

S3 = - ¡¢

Q

4 te (b + 1.56 R t)

£¤

- ¡¢

12 K3 Q R

L te²

£¤

= - ¡¢

2016

4 * 0.9375 * (10.0000 + 1.56 * 14.7813 * 0.4375)

£¤

- ¡¢

12 * 0.05285 * 2016 * 14.7813

96.0000 * 0.4414

£¤

= -484 P S I

Circumferential Stress at End of the Wear Plate

S3w = - ¡¢

Q

4 t (bw + 1.56 R t)

£¤

- ¡¢

12 K3w Q R

L t²

£¤

= - ¡¢

2016

4 * 0.4375 * (15.0000 + 1.56 * 14.7813 * 0.4375)

£¤

- ¡¢

12 * 0.04345 * 2016 * 14.7813

96.0000 * 0.4375²

£¤

= -906 P S I

DesignCalcs version: 2013.0 ©CEI 2013Page 26 of 48

Page 29: TWI Oilfield Fabrication - twi-fab.comtwi-fab.com/images/CW15011 DesignCalcs Reports.pdf · TWI Oilfield Fabrication 1560 ... 1106 West 2nd Street Suite 2 Williston, ND 58801 VESSEL

TWI Oilfield FabricationT.M. No: CW15011 Vessel Number: CW15011.1

Date Printed: 11/27/2012

Ring Compression in the Shell Over the Saddle

te = t + twp = 0.4375 + 0.5000 = 0.9375 i n .

S5 = K5 Q

te (b + 1.56 R t) =

0.76027 * 2016

0.9375 * (0.5000 + 1.56 * 14.7813 * 0.4375)= 366 P S I

Maximum Splitting Force

Fs = K8Qs = 0.20352 * 2016 = 410 l b .

Saddle Calculations

Base Plate Stress

SBP = 0.75 Qs bb

m tb² =

0.75 * 2016 * 1.0000

29.0000 * 0.3750²= 371 P S I

Concrete Bearing Stress

SC = Qs

bb m =

2016

1.0000 * 29.0000= 70 P S I

Saddle Splitting Force

ST Splitting = FS

ASaddle =

410

2.6875= 153 P S I

M Splitting = FS ¡¢

h - C2 - RW ¥¦

sin(n/2)

n/2

§¨£¤

= 410 * ¡¢

20.5000 - 4.4820 - 15.5000 * ¥¦

sin(1.0472)

1.0472

§¨£¤

= 1312 i n . - l b .

SB Splitting = M C1

I =

1312 * 0.5180

23.0695= 29 P S I

Bolting Shear Stress

Sb = FBolt

Nb Ab =

0

2 * 0.5510= 0 P S I

Saddle Support Stiffener Stresses

Location Length Compressive Stress Bending Stress Allowable Stress Stress Ratio in. PSI PSI PSI RST

Outside 12.3750 146 0 21600 0.0068

DesignCalcs version: 2013.0 ©CEI 2013Page 27 of 48

Page 30: TWI Oilfield Fabrication - twi-fab.comtwi-fab.com/images/CW15011 DesignCalcs Reports.pdf · TWI Oilfield Fabrication 1560 ... 1106 West 2nd Street Suite 2 Williston, ND 58801 VESSEL

TWI Oilfield FabricationT.M. No: CW15011 Vessel Number: CW15011.1

Date Printed: 11/27/2012

Vessel Stress Ratio Calculations

Any ratio greater than 1 represents an overstressed condition

R1t = S1 + Sp

SShell E =

22 + 0

20000 * 0.70= 0.0016

R1C = -S1

- Min(SShell, BShell) =

-22

-Min(20000,16588)= 0.0013

R1t' = S1' + Sp

SShell E =

289 + 0

20000 * 0.70= 0.0206

R1C' = -S1'

- Min(SShell, BShell) =

-289

-Min(20000,16588)= 0.0174

R2 = S2

0.8 SShell =

92

0.8 * 20000= 0.0058

R2W = S2W

0.8 SShell =

168

0.8 * 20000= 0.0105

R3 = S3

- ( 1.25 SShell) =

-484

- (1.25 * 20000)= 0.0194

R3w = S3W

- ( 1.25 SShell) =

-906

- (1.25 * 20000)= 0.0362

R5 = S5

0.5 YShell =

366

0.5 * 38000= 0.0193

DesignCalcs version: 2013.0 ©CEI 2013Page 28 of 48

Page 31: TWI Oilfield Fabrication - twi-fab.comtwi-fab.com/images/CW15011 DesignCalcs Reports.pdf · TWI Oilfield Fabrication 1560 ... 1106 West 2nd Street Suite 2 Williston, ND 58801 VESSEL

TWI Oilfield FabricationT.M. No: CW15011 Vessel Number: CW15011.1

Date Printed: 11/27/2012

Saddle Stress Ratio Calculations

Any ratio greater than 1 represents an overstressed condition

RBase Plate = SBP

0.6 YBase Plate =

371

0.6 * 36000= 0.0172

RConcrete = SC

0.25 SConcrete =

70

0.25 * 3000= 0.0933

RWeb = ST Splitting

0.6 YSaddle +

SB Splitting

0.66 YSaddle =

153

0.6 * 36000 +

29

0.66 * 36000= 0.0083

RST = Sstc + Sstb

0.6 YSaddle =

146 + 0

0.6 * 36000= 0.0068

RBolt = SB

0.8 SBa =

0

0.8 * 16600= 0.0000

DesignCalcs version: 2013.0 ©CEI 2013Page 29 of 48

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TWI Oilfield FabricationT.M. No: CW15011 Vessel Number: CW15011.1

Date Printed: 11/27/2012

Empty Pressurized Condition - Sustained Loads

Saddle Support Loads

QL = FLh

L - 2A =

0 * 20.5000

96.0000 - 2 * 19.2000 = 0 l b .

QT = 1.5 FT h

d =

1.5 * 0 * 20.5000

26.8468 = 0 l b .

QW = W

2 =

1512

2 = 756 l b .

QN = QW = 756 = 756 l b .

Saddle Load for Vessel Stress Analysis

Q = QN = 756 = 756 l b .

Saddle Load for Support Stress Analysis

QS = QN = 756 = 756 l b .

DesignCalcs version: 2013.0 ©CEI 2013Page 30 of 48

Page 33: TWI Oilfield Fabrication - twi-fab.comtwi-fab.com/images/CW15011 DesignCalcs Reports.pdf · TWI Oilfield Fabrication 1560 ... 1106 West 2nd Street Suite 2 Williston, ND 58801 VESSEL

TWI Oilfield FabricationT.M. No: CW15011 Vessel Number: CW15011.1

Date Printed: 11/27/2012

Zick Calculations

Longitudinal Stress Due to Internal Pressure

Sp = P R

2 t =

300.00 * 14.7813

2 * 0.4375= 5068 P S I

Longitudinal Compressive Stress Due to External Pressure

Spe = -Pe R

2 t =

-0.00 * 14.7813

2 * 0.4375= 0 P S I

Longitudinal Bending Stress in the Shell at the MidpointZ1 = m R² t = 3.1416 * 14.7813² * 0.4375 = 300 i n . ³

S1 = K1 Q L

4 Z1 =

0.13386 * 756 * 96.0000

4 * 300= 8 P S I

Longitudinal Bending Stress in the Shell in the Plane of the Saddle

S1' = K1' Q L

4 Z1 =

1.79288 * 756 * 96.0000

4 * 300= 108 P S I

Saddle Plane Tangential Shear Stress

te = t + twp = 0.4375 + 0.5000 = 0.9375 i n .

S2 = ¡¢

K2 Q

R te

£¤

¡¢

L - 2 A

L + 4

3 H

£¤

= ¡¢

1.17074 * 756

14.7813 * 0.9375

£¤

¡¢

96.0000 - 2 * 19.2000

96.0000 + 4

3 * 7.7500

£¤

= 35 P S I

S2w = ¡¢

K2w Q

R t

£¤

¡¢

L - 2 A

L + 4

3 H

£¤

= ¡¢

0.99596 * 756

14.7813 * 0.4375

£¤

¡¢

96.0000 - 2 * 19.2000

96.0000 + 4

3 * 7.7500

£¤

= 63 P S I

Circumferential Stress at the Horn of the Saddlete² = t² + twp² = 0.4375² + 0.5000² = 0.4414 sq. in.

S3 = - ¡¢

Q

4 te (b + 1.56 R t)

£¤

- ¡¢

12 K3 Q R

L te²

£¤

= - ¡¢

756

4 * 0.9375 * (10.0000 + 1.56 * 14.7813 * 0.4375)

£¤

- ¡¢

12 * 0.05285 * 756 * 14.7813

96.0000 * 0.4414

£¤

= -182 P S I

Circumferential Stress at End of the Wear Plate

S3w = - ¡¢

Q

4 t (bw + 1.56 R t)

£¤

- ¡¢

12 K3w Q R

L t²

£¤

= - ¡¢

756

4 * 0.4375 * (15.0000 + 1.56 * 14.7813 * 0.4375)

£¤

- ¡¢

12 * 0.04345 * 756 * 14.7813

96.0000 * 0.4375²

£¤

= -340 P S I

DesignCalcs version: 2013.0 ©CEI 2013Page 31 of 48

Page 34: TWI Oilfield Fabrication - twi-fab.comtwi-fab.com/images/CW15011 DesignCalcs Reports.pdf · TWI Oilfield Fabrication 1560 ... 1106 West 2nd Street Suite 2 Williston, ND 58801 VESSEL

TWI Oilfield FabricationT.M. No: CW15011 Vessel Number: CW15011.1

Date Printed: 11/27/2012

Ring Compression in the Shell Over the Saddle

te = t + twp = 0.4375 + 0.5000 = 0.9375 i n .

S5 = K5 Q

te (b + 1.56 R t) =

0.76027 * 756

0.9375 * (0.5000 + 1.56 * 14.7813 * 0.4375)= 137 P S I

Maximum Splitting Force

Fs = K8Qs = 0.20352 * 756 = 154 l b .

Saddle Calculations

Base Plate Stress

SBP = 0.75 Qs bb

m tb² =

0.75 * 756 * 1.0000

29.0000 * 0.3750²= 139 P S I

Concrete Bearing Stress

SC = Qs

bb m =

756

1.0000 * 29.0000= 26 P S I

Saddle Splitting Force

ST Splitting = FS

ASaddle =

154

2.6875= 57 P S I

M Splitting = FS ¡¢

h - C2 - RW ¥¦

sin(n/2)

n/2

§¨£¤

= 154 * ¡¢

20.5000 - 4.4820 - 15.5000 * ¥¦

sin(1.0472)

1.0472

§¨£¤

= 493 i n . - l b .

SB Splitting = M C1

I =

493 * 0.5180

23.0695= 11 P S I

Bolting Shear Stress

Sb = FBolt

Nb Ab =

0

2 * 0.5510= 0 P S I

Saddle Support Stiffener Stresses

Location Length Compressive Stress Bending Stress Allowable Stress Stress Ratio in. PSI PSI PSI RST

Outside 12.3750 54 0 21600 0.0025

DesignCalcs version: 2013.0 ©CEI 2013Page 32 of 48

Page 35: TWI Oilfield Fabrication - twi-fab.comtwi-fab.com/images/CW15011 DesignCalcs Reports.pdf · TWI Oilfield Fabrication 1560 ... 1106 West 2nd Street Suite 2 Williston, ND 58801 VESSEL

TWI Oilfield FabricationT.M. No: CW15011 Vessel Number: CW15011.1

Date Printed: 11/27/2012

Vessel Stress Ratio Calculations

Any ratio greater than 1 represents an overstressed condition

R1t = S1 + Sp

SShell E =

8 + 5068

20000 * 0.70= 0.3626

R1C = -S1

- Min(SShell, BShell) =

-8

-Min(20000,16588)= 0.0005

R1t' = S1' + Sp

SShell E =

108 + 5068

20000 * 0.70= 0.3697

R1C' = -S1'

- Min(SShell, BShell) =

-108

-Min(20000,16588)= 0.0065

R2 = S2

0.8 SShell =

35

0.8 * 20000= 0.0022

R2W = S2W

0.8 SShell =

63

0.8 * 20000= 0.0039

R3 = S3

- ( 1.25 SShell) =

-182

- (1.25 * 20000)= 0.0073

R3w = S3W

- ( 1.25 SShell) =

-340

- (1.25 * 20000)= 0.0136

R5 = S5

0.5 YShell =

137

0.5 * 38000= 0.0072

DesignCalcs version: 2013.0 ©CEI 2013Page 33 of 48

Page 36: TWI Oilfield Fabrication - twi-fab.comtwi-fab.com/images/CW15011 DesignCalcs Reports.pdf · TWI Oilfield Fabrication 1560 ... 1106 West 2nd Street Suite 2 Williston, ND 58801 VESSEL

TWI Oilfield FabricationT.M. No: CW15011 Vessel Number: CW15011.1

Date Printed: 11/27/2012

Saddle Stress Ratio Calculations

Any ratio greater than 1 represents an overstressed condition

RBase Plate = SBP

0.6 YBase Plate =

139

0.6 * 36000= 0.0064

RConcrete = SC

0.25 SConcrete =

26

0.25 * 3000= 0.0347

RWeb = ST Splitting

0.6 YSaddle +

SB Splitting

0.66 YSaddle =

57

0.6 * 36000 +

11

0.66 * 36000= 0.0031

RST = Sstc + Sstb

0.6 YSaddle =

54 + 0

0.6 * 36000= 0.0025

RBolt = SB

0.8 SBa =

0

0.8 * 16600= 0.0000

DesignCalcs version: 2013.0 ©CEI 2013Page 34 of 48

Page 37: TWI Oilfield Fabrication - twi-fab.comtwi-fab.com/images/CW15011 DesignCalcs Reports.pdf · TWI Oilfield Fabrication 1560 ... 1106 West 2nd Street Suite 2 Williston, ND 58801 VESSEL

TWI Oilfield FabricationT.M. No: CW15011 Vessel Number: CW15011.1

Date Printed: 11/27/2012

Empty Unpressurized Condition - Sustained Loads

Saddle Support Loads

QL = FLh

L - 2A =

0 * 20.5000

96.0000 - 2 * 19.2000 = 0 l b .

QT = 1.5 FT h

d =

1.5 * 0 * 20.5000

26.8468 = 0 l b .

QW = W

2 =

1512

2 = 756 l b .

QN = QW = 756 = 756 l b .

Saddle Load for Vessel Stress Analysis

Q = QN = 756 = 756 l b .

Saddle Load for Support Stress Analysis

QS = QN = 756 = 756 l b .

DesignCalcs version: 2013.0 ©CEI 2013Page 35 of 48

Page 38: TWI Oilfield Fabrication - twi-fab.comtwi-fab.com/images/CW15011 DesignCalcs Reports.pdf · TWI Oilfield Fabrication 1560 ... 1106 West 2nd Street Suite 2 Williston, ND 58801 VESSEL

TWI Oilfield FabricationT.M. No: CW15011 Vessel Number: CW15011.1

Date Printed: 11/27/2012

Zick Calculations

Longitudinal Stress Due to Internal Pressure

Sp = = 0 P S I

Longitudinal Compressive Stress Due to External Pressure

Spe = = 0 P S I

Longitudinal Bending Stress in the Shell at the MidpointZ1 = m R² t = 3.1416 * 14.7813² * 0.4375 = 300 i n . ³

S1 = K1 Q L

4 Z1 =

0.13386 * 756 * 96.0000

4 * 300= 8 P S I

Longitudinal Bending Stress in the Shell in the Plane of the Saddle

S1' = K1' Q L

4 Z1 =

1.79288 * 756 * 96.0000

4 * 300= 108 P S I

Saddle Plane Tangential Shear Stress

te = t + twp = 0.4375 + 0.5000 = 0.9375 i n .

S2 = ¡¢

K2 Q

R te

£¤

¡¢

L - 2 A

L + 4

3 H

£¤

= ¡¢

1.17074 * 756

14.7813 * 0.9375

£¤

¡¢

96.0000 - 2 * 19.2000

96.0000 + 4

3 * 7.7500

£¤

= 35 P S I

S2w = ¡¢

K2w Q

R t

£¤

¡¢

L - 2 A

L + 4

3 H

£¤

= ¡¢

0.99596 * 756

14.7813 * 0.4375

£¤

¡¢

96.0000 - 2 * 19.2000

96.0000 + 4

3 * 7.7500

£¤

= 63 P S I

Circumferential Stress at the Horn of the Saddlete² = t² + twp² = 0.4375² + 0.5000² = 0.4414 sq. in.

S3 = - ¡¢

Q

4 te (b + 1.56 R t)

£¤

- ¡¢

12 K3 Q R

L te²

£¤

= - ¡¢

756

4 * 0.9375 * (10.0000 + 1.56 * 14.7813 * 0.4375)

£¤

- ¡¢

12 * 0.05285 * 756 * 14.7813

96.0000 * 0.4414

£¤

= -182 P S I

Circumferential Stress at End of the Wear Plate

S3w = - ¡¢

Q

4 t (bw + 1.56 R t)

£¤

- ¡¢

12 K3w Q R

L t²

£¤

= - ¡¢

756

4 * 0.4375 * (15.0000 + 1.56 * 14.7813 * 0.4375)

£¤

- ¡¢

12 * 0.04345 * 756 * 14.7813

96.0000 * 0.4375²

£¤

= -340 P S I

DesignCalcs version: 2013.0 ©CEI 2013Page 36 of 48

Page 39: TWI Oilfield Fabrication - twi-fab.comtwi-fab.com/images/CW15011 DesignCalcs Reports.pdf · TWI Oilfield Fabrication 1560 ... 1106 West 2nd Street Suite 2 Williston, ND 58801 VESSEL

TWI Oilfield FabricationT.M. No: CW15011 Vessel Number: CW15011.1

Date Printed: 11/27/2012

Ring Compression in the Shell Over the Saddle

te = t + twp = 0.4375 + 0.5000 = 0.9375 i n .

S5 = K5 Q

te (b + 1.56 R t) =

0.76027 * 756

0.9375 * (0.5000 + 1.56 * 14.7813 * 0.4375)= 137 P S I

Maximum Splitting Force

Fs = K8Qs = 0.20352 * 756 = 154 l b .

Saddle Calculations

Base Plate Stress

SBP = 0.75 Qs bb

m tb² =

0.75 * 756 * 1.0000

29.0000 * 0.3750²= 139 P S I

Concrete Bearing Stress

SC = Qs

bb m =

756

1.0000 * 29.0000= 26 P S I

Saddle Splitting Force

ST Splitting = FS

ASaddle =

154

2.6875= 57 P S I

M Splitting = FS ¡¢

h - C2 - RW ¥¦

sin(n/2)

n/2

§¨£¤

= 154 * ¡¢

20.5000 - 4.4820 - 15.5000 * ¥¦

sin(1.0472)

1.0472

§¨£¤

= 493 i n . - l b .

SB Splitting = M C1

I =

493 * 0.5180

23.0695= 11 P S I

Bolting Shear Stress

Sb = FBolt

Nb Ab =

0

2 * 0.5510= 0 P S I

Saddle Support Stiffener Stresses

Location Length Compressive Stress Bending Stress Allowable Stress Stress Ratio in. PSI PSI PSI RST

Outside 12.3750 54 0 21600 0.0025

DesignCalcs version: 2013.0 ©CEI 2013Page 37 of 48

Page 40: TWI Oilfield Fabrication - twi-fab.comtwi-fab.com/images/CW15011 DesignCalcs Reports.pdf · TWI Oilfield Fabrication 1560 ... 1106 West 2nd Street Suite 2 Williston, ND 58801 VESSEL

TWI Oilfield FabricationT.M. No: CW15011 Vessel Number: CW15011.1

Date Printed: 11/27/2012

Vessel Stress Ratio Calculations

Any ratio greater than 1 represents an overstressed condition

R1t = S1 + Sp

SShell E =

8 + 0

20000 * 0.70= 0.0006

R1C = -S1

- Min(SShell, BShell) =

-8

-Min(20000,16588)= 0.0005

R1t' = S1' + Sp

SShell E =

108 + 0

20000 * 0.70= 0.0077

R1C' = -S1'

- Min(SShell, BShell) =

-108

-Min(20000,16588)= 0.0065

R2 = S2

0.8 SShell =

35

0.8 * 20000= 0.0022

R2W = S2W

0.8 SShell =

63

0.8 * 20000= 0.0039

R3 = S3

- ( 1.25 SShell) =

-182

- (1.25 * 20000)= 0.0073

R3w = S3W

- ( 1.25 SShell) =

-340

- (1.25 * 20000)= 0.0136

R5 = S5

0.5 YShell =

137

0.5 * 38000= 0.0072

DesignCalcs version: 2013.0 ©CEI 2013Page 38 of 48

Page 41: TWI Oilfield Fabrication - twi-fab.comtwi-fab.com/images/CW15011 DesignCalcs Reports.pdf · TWI Oilfield Fabrication 1560 ... 1106 West 2nd Street Suite 2 Williston, ND 58801 VESSEL

TWI Oilfield FabricationT.M. No: CW15011 Vessel Number: CW15011.1

Date Printed: 11/27/2012

Saddle Stress Ratio Calculations

Any ratio greater than 1 represents an overstressed condition

RBase Plate = SBP

0.6 YBase Plate =

139

0.6 * 36000= 0.0064

RConcrete = SC

0.25 SConcrete =

26

0.25 * 3000= 0.0347

RWeb = ST Splitting

0.6 YSaddle +

SB Splitting

0.66 YSaddle =

57

0.6 * 36000 +

11

0.66 * 36000= 0.0031

RST = Sstc + Sstb

0.6 YSaddle =

54 + 0

0.6 * 36000= 0.0025

RBolt = SB

0.8 SBa =

0

0.8 * 16600= 0.0000

DesignCalcs version: 2013.0 ©CEI 2013Page 39 of 48

Page 42: TWI Oilfield Fabrication - twi-fab.comtwi-fab.com/images/CW15011 DesignCalcs Reports.pdf · TWI Oilfield Fabrication 1560 ... 1106 West 2nd Street Suite 2 Williston, ND 58801 VESSEL

TWI Oilfield FabricationT.M. No: CW15011 Vessel Number: CW15011.1

Date Printed: 11/27/2012

Test Condition

Saddle Support Loads

QL = FLh

L - 2A =

0 * 20.5000

96.0000 - 2 * 19.2000 = 0 l b .

QT = 1.5 FT h

d =

1.5 * 0 * 20.5000

26.8468 = 0 l b .

QW = W

2 =

4032

2 = 2016 l b .

QN = QW = 2016 = 2016 l b .

Saddle Load for Vessel Stress Analysis

Q = QN = 2016 = 2016 l b .

Saddle Load for Support Stress Analysis

QS = QN = 2016 = 2016 l b .

DesignCalcs version: 2013.0 ©CEI 2013Page 40 of 48

Page 43: TWI Oilfield Fabrication - twi-fab.comtwi-fab.com/images/CW15011 DesignCalcs Reports.pdf · TWI Oilfield Fabrication 1560 ... 1106 West 2nd Street Suite 2 Williston, ND 58801 VESSEL

TWI Oilfield FabricationT.M. No: CW15011 Vessel Number: CW15011.1

Date Printed: 11/27/2012

Zick Calculations

Longitudinal Stress Due to Internal Pressure

Sp = P R

2 t =

300.00 * 14.7500

2 * 0.5000= 4425 P S I

Longitudinal Compressive Stress Due to External Pressure

Spe = = 0 P S I

Longitudinal Bending Stress in the Shell at the MidpointZ1 = m R² t = 3.1416 * 14.7500² * 0.5000 = 342 i n . ³

S1 = K1 Q L

4 Z1 =

0.13368 * 2016 * 96.0000

4 * 342= 19 P S I

Longitudinal Bending Stress in the Shell in the Plane of the Saddle

S1' = K1' Q L

4 Z1 =

1.79458 * 2016 * 96.0000

4 * 342= 254 P S I

Saddle Plane Tangential Shear Stress

te = t + twp = 0.5000 + 0.5000 = 1.0000 i n .

S2 = ¡¢

K2 Q

R te

£¤

¡¢

L - 2 A

L + 4

3 H

£¤

= ¡¢

1.17074 * 2016

14.7500 * 1.0000

£¤

¡¢

96.0000 - 2 * 19.2000

96.0000 + 4

3 * 7.7500

£¤

= 87 P S I

S2w = ¡¢

K2w Q

R t

£¤

¡¢

L - 2 A

L + 4

3 H

£¤

= ¡¢

0.99596 * 2016

14.7500 * 0.5000

£¤

¡¢

96.0000 - 2 * 19.2000

96.0000 + 4

3 * 7.7500

£¤

= 147 P S I

Circumferential Stress at the Horn of the Saddlete² = t² + twp² = 0.5000² + 0.5000² = 0.5000 sq. in.

S3 = - ¡¢

Q

4 te (b + 1.56 R t)

£¤

- ¡¢

12 K3 Q R

L te²

£¤

= - ¡¢

2016

4 * 1.0000 * (10.0000 + 1.56 * 14.7500 * 0.5000)

£¤

- ¡¢

12 * 0.05285 * 2016 * 14.7500

96.0000 * 0.5000

£¤

= -428 P S I

Circumferential Stress at End of the Wear Plate

S3w = - ¡¢

Q

4 t (bw + 1.56 R t)

£¤

- ¡¢

12 K3w Q R

L t²

£¤

= - ¡¢

2016

4 * 0.5000 * (15.0000 + 1.56 * 14.7500 * 0.5000)

£¤

- ¡¢

12 * 0.04345 * 2016 * 14.7500

96.0000 * 0.5000²

£¤

= -698 P S I

DesignCalcs version: 2013.0 ©CEI 2013Page 41 of 48

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TWI Oilfield FabricationT.M. No: CW15011 Vessel Number: CW15011.1

Date Printed: 11/27/2012

Ring Compression in the Shell Over the Saddle

te = t + twp = 0.5000 + 0.5000 = 1.0000 i n .

S5 = K5 Q

te (b + 1.56 R t) =

0.76027 * 2016

1.0000 * (0.5000 + 1.56 * 14.7500 * 0.5000)= 324 P S I

Maximum Splitting Force

Fs = K8Qs = 0.20352 * 2016 = 410 l b .

Saddle Calculations

Base Plate Stress

SBP = 0.75 Qs bb

m tb² =

0.75 * 2016 * 1.0000

29.0000 * 0.3750²= 371 P S I

Concrete Bearing Stress

SC = Qs

bb m =

2016

1.0000 * 29.0000= 70 P S I

Saddle Splitting Force

ST Splitting = FS

ASaddle =

410

2.6875= 153 P S I

M Splitting = FS ¡¢

h - C2 - RW ¥¦

sin(n/2)

n/2

§¨£¤

= 410 * ¡¢

20.5000 - 4.4820 - 15.5000 * ¥¦

sin(1.0472)

1.0472

§¨£¤

= 1312 i n . - l b .

SB Splitting = M C1

I =

1312 * 0.5180

23.0695= 29 P S I

Bolting Shear Stress

Sb = FBolt

Nb Ab =

0

2 * 0.5510= 0 P S I

Saddle Support Stiffener Stresses

Location Length Compressive Stress Bending Stress Allowable Stress Stress Ratio in. PSI PSI PSI RST

Outside 12.3750 146 0 21600 0.0068

DesignCalcs version: 2013.0 ©CEI 2013Page 42 of 48

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TWI Oilfield FabricationT.M. No: CW15011 Vessel Number: CW15011.1

Date Printed: 11/27/2012

Vessel Stress Ratio Calculations

Any ratio greater than 1 represents an overstressed condition

R1t = S1 + Sp

SShell E =

19 + 4425

20000 * 0.70= 0.3174

R1C = -S1

- Min(SShell, BShell) =

-19

-Min(20000,16588)= 0.0011

R1t' = S1' + Sp

SShell E =

254 + 4425

20000 * 0.70= 0.3342

R1C' = -S1'

- Min(SShell, BShell) =

-254

-Min(20000,16588)= 0.0153

R2 = S2

0.8 SShell =

87

0.8 * 20000= 0.0054

R2W = S2W

0.8 SShell =

147

0.8 * 20000= 0.0092

R3 = S3

- ( 1.25 SShell) =

-428

- (1.25 * 20000)= 0.0171

R3w = S3W

- ( 1.25 SShell) =

-698

- (1.25 * 20000)= 0.0279

R5 = S5

0.5 YShell =

324

0.5 * 38000= 0.0171

DesignCalcs version: 2013.0 ©CEI 2013Page 43 of 48

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TWI Oilfield FabricationT.M. No: CW15011 Vessel Number: CW15011.1

Date Printed: 11/27/2012

Saddle Stress Ratio Calculations

Any ratio greater than 1 represents an overstressed condition

RBase Plate = SBP

0.6 YBase Plate =

371

0.6 * 36000= 0.0172

RConcrete = SC

0.25 SConcrete =

70

0.25 * 3000= 0.0933

RWeb = ST Splitting

0.6 YSaddle +

SB Splitting

0.66 YSaddle =

153

0.6 * 36000 +

29

0.66 * 36000= 0.0083

RST = Sstc + Sstb

0.6 YSaddle =

146 + 0

0.6 * 36000= 0.0068

RBolt = SB

0.8 SBa =

0

0.8 * 16600= 0.0000

DesignCalcs version: 2013.0 ©CEI 2013Page 44 of 48

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TWI Oilfield FabricationC u s t o m e r : TAQA North LTD

T.M. No: CW15011 Vessel Number: CW15011.1

Date Printed: 11/27/2012

MDMT Report by ComponentsDesign MDMT is -20 °F

Component Material Curve Pressure MDMT

Shell 1 SA-516 Gr. 70 B 300.00 PSI -50 °F Nozzle 3 SA-105 B 300.00 PSI -117 °F Nozzle 1 SA-106 Gr. B B 300.00 PSI -147 °F Nozzle 5 SA-106 Gr. B 300.00 PSI -155 °F Nozzle 4 SA-106 Gr. B B 300.00 PSI -147 °FHead 1 SA-516 Gr. 70 C 300.00 PSI -55 °FHead 2 SA-516 Gr. 70 C 300.00 PSI -55 °F Nozzle 2 SA-106 Gr. B B 300.00 PSI -155 °F

Component with highest MDMT: Shell 1.

Computed MDMT = -50 °F

The required design MDMT of -20 °F has been met or exceeded for the calculated MDMT values.

ASME Flanges Are Not Included in MDMT Calculations.

DesignCalcs version: 2013.0 ©CEI 2013Page 45 of 48

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TWI Oilfield Fabrication30"x96" 300 MAWP VT Sand Seperator

C u s t o m e r : TAQA North LTDT.M. No: CW15011 Vessel Number: CW15011.1

Date Printed: 11/27/2012

MAWP Report by Components

Vessel Component VesselMAWP MAWP MAWP

Design Static New & Cold Hot & Corroded Hot & Corroded Component Pressure Head UG-98(a) UG-98(b) UG-98(a)Shell 1 300.00 PSI 0.00 PSI 472.97 PSI 378.66 PSI 378.66 PSI Nozzle 1 300.00 PSI 0.00 PSI 532.61 PSI 391.77 PSI 391.77 PSI ASME Flange Class: 300 Gr:1.1 300.00 PSI 0.00 PSI 740.00 PSI 740.00 PSI 740.00 PSI Nozzle 3 300.00 PSI 0.00 PSI 508.38 PSI 421.03 PSI 421.03 PSI ASME Flange Class: 300 Gr:1.1 300.00 PSI 0.00 PSI 740.00 PSI 740.00 PSI 740.00 PSI Nozzle 4 300.00 PSI 0.00 PSI 506.61 PSI 378.66 PSI 378.66 PSI ASME Flange Class: 300 Gr:1.1 300.00 PSI 0.00 PSI 740.00 PSI 740.00 PSI 740.00 PSI Nozzle 5 300.00 PSI 0.00 PSI 532.61 PSI 391.77 PSI 391.77 PSI ASME Flange Class: 300 Gr:1.1 300.00 PSI 0.00 PSI 740.00 PSI 740.00 PSI 740.00 PSIHead 1 300.00 PSI 0.00 PSI 419.34 PSI 300.24 PSI 300.24 PSIHead 2 300.00 PSI 0.00 PSI 419.34 PSI 300.24 PSI 300.24 PSI Nozzle 2 300.00 PSI 0.00 PSI 546.57 PSI 397.78 PSI 397.78 PSI ASME Flange Class: 300 Gr:1.1 300.00 PSI 0.00 PSI 740.00 PSI 740.00 PSI 740.00 PSI

NC = Not Calculated Inc = Incomplete

Summary

Component with the lowest vessel MAWP(New & Cold) : Head 1The lowest vessel MAWP(New & Cold) : 419.34 P S I

Component with the lowest vessel MAWP(Hot & Corroded) : Head 1The lowest vessel MAWP(Hot & Corroded) : 300.24 P S I

Pressures are exclusive of any external loads.

Flange pressures listed here do not consider external loadings

DesignCalcs version: 2013.0 ©CEI 2013Page 46 of 48

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TWI Oilfield FabricationC u s t o m e r : TAQA North LTD

T.M. No: CW15011 Vessel Number: CW15011.1

Date Printed: 11/27/2012

Summary Information

Dry Weight Flooded WeightShell 1245.58 lb. 3539.05 lb.Head 265.60 lb. 496.15 lb.Nozzle 156.61 lb. 156.61 lb.ASME Flange 110.00 lb. 110.00 lb.

_________________ _________________T o t a l s 1777.79 lb. 4301.80 lb.

Volume Shell 274.53 Gal.Head 27.64 Gal.Nozzle 2.67 Gal.

_________________T o t a l s 304.85 Gal.

Area Shell 62.83 Sq. Ft.Head 13.17 Sq. Ft.Nozzle 4.32 Sq. Ft.

_________________T o t a l s 80.33 Sq. Ft.

DesignCalcs version: 2013.0 ©CEI 2013Page 47 of 48

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TWI Oilfield FabricationC u s t o m e r : TAQA North LTD

T.M. No: CW15011 Vessel Number: CW15011.1

Date Printed: 11/27/2012

Hydrostatic Test Information Par. UG-99(b)Gauge at Top

Component Const. x STest / SDesign x Pressure = Component Hydro Test Pressure

Head 1 1.3 x 20000 / 20000 x 300.00 = 390.00Head 2 1.3 x 20000 / 20000 x 300.00 = 390.00Nozzle 1 1.3 x 17100 / 17100 x 300.00 = 390.00Nozzle 2 1.3 x 17100 / 17100 x 300.00 = 390.00Nozzle 3 1.3 x 20000 / 20000 x 300.00 = 390.00Nozzle 4 1.3 x 17100 / 17100 x 300.00 = 390.00Nozzle 5 1.3 x 17100 / 17100 x 300.00 = 390.00Shell 1 1.3 x 20000 / 20000 x 300.00 = 390.00

Calculated Test Pressure: 390.00 PSI

Special Notes:

This calculation assumes one chamber.

This calculation is limited by the lowest component pressure per chamber.

DesignCalcs version: 2013.0 ©CEI 2013Page 48 of 48

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Table of Contents

Shell 1 1

Head 1 2

Head 2 3

Nozzle 1 4

Nozzle 2 6

Nozzle 3 8

Nozzle 4 11

Nozzle 5 13

LiftLug Information 15

Saddle Information 17

ASME Flanges 18

Attachment/Loading Information 19

Zick Information - Saddle: Saddle 1 20

MDMT Summary 45

MAWP Summary 46

Summary Information 47

Hydrostatic Test Information Par. UG-99(b) 48