uncertainty and consumer behavior …riiiisk….. uncertainty and risk risk is associated to...
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Uncertainty and Risk
Risk is associated to uncertain events. Uncertainty refers to unknown outcomes of stochastic
variables i.e. dices’ throw. Two cases:
Dices: known distribution Unknown distributions: … what the future brings?
A Game
1, 2, 3, 4 s (shine) 5, 6 r (rain) Three dices three days Options
sss ssr srr rrr Probabilities
P(s) = 2/3 P(r) = 1/3
A Game You are given 10 units of money You have to gamble 2 units each time (5 times) Your betting options:
If the outcome doesn’t fit with your bet, you give back the money
At least 1s At least 2s At least 2r 3r
-75% -50% -25% -0%
Distribution Probability
At least 1s: P(3s) + P(2s) + P(1s)
At least 2s: P(3s) + P(2s)
At least 2r: P(2r) + P(3r)
0,296
0,444
0,222
0,037
0
0,25
0,5
3s 2s-r s-2r 3r
3r: P(3r)
Example
Your choice
At least 1s
At least 2s
At least 2r
3r Actual Outcome
First Round
Second Round
Third Round
Fourth Round
Fifth Round
PayoffFinal Payoff
3,50
-2
-0,25
-0,25
-2
-2
-6,50
Theory of Probability P(3s) =?
P(s) = 2/3 P(3s) = P(s) P(s) P(s)
P(2s and r)=? P(s) = 2/3 P(r) = 1/3 ssr srs rss P(2s and r) = 3P(s)P(s)P(r)
P(s and 2r)=? P(s and 2r) = 3P(s)P(r)P(r)
P(3r) =? P(3r) = P(r)P(r)P(r)
P(3s) =2/3*2/3*2/3 = 8/27 P(3s) = 8/27= 0,296
P(2s and r)= 3*2/3*2/3*1/3 = 12/27 P(2s and r) = 12/27 = 0,444
P(s and 2r)= 3*2/3*1/3*1/3 = 6/27 P(s and 2r) = 6/27 = 0,222
P(3r) = 1/3*1/3*1/3 = 1/27 P(3r) = 1/27 = 0,037
The Expected Value of the Distribution
0,296
0,444
0,222
0,037
0
0,25
0,5
0 1 2 3
<x> = 0*p(3s) + 1*p(2s and r) + 2*p(s and 2r) + 3*p(3r)
<x> = 0*0,296 + 1*0,444 + 2*0,222 + 3*0,037 = 1,00
<x> = n*p(r) = 3*1/3
<x>
The Variance of the Distribution
2<x> = (0 -1)2 P(3s)+ (1-1)2 P(2s and r)+ (2 -1)2 P(s and 2r) + (3 -1)2 P(3r)
2<x> = 1*0,29 + 0*0,44 + 1*0,22 + 22*0,037
2<x> = 0,29 + 0,22 + 4*0,037
2<x> = 0,658
2<x> = nP(s)P(r)
2<x> = 3*2/3*1/3
0,296
0,444
0,222
0,037
0
0,25
0,5
0 1 2 3
<x>
22<x><x>