understanding electrical laws

Upload: oana-laura-stefan

Post on 09-Apr-2018

218 views

Category:

Documents


0 download

TRANSCRIPT

  • 8/8/2019 Understanding Electrical Laws

    1/51

    UNDERSTANDING ELECTRICAL

    NETWORKS

    UNDERSTANDINGUNDERSTANDING

    ELECTRICALELECTRICAL

    NETWORKSNETWORKS

    UNDERSTANDINGUNDERSTANDING

    ELECTRICALELECTRICAL

    NETWORKSNETWORKS

  • 8/8/2019 Understanding Electrical Laws

    2/51

    CONTENTS

    LAWS OFLAWS OF

    ELECTROMAGNETISMELECTROMAGNETISM

    BASIC VOCABULARYBASIC VOCABULARY

    LAWS OFLAWS OF

    ELECTROMAGNETISMELECTROMAGNETISM

    BASIC VOCABULARYBASIC VOCABULARY

  • 8/8/2019 Understanding Electrical Laws

    3/51

    PART 1: LAWS OF ELECTROMAGNETISM

    LAWS OFLAWS OF

    ELECTROMAGNETISMELECTROMAGNETISM

    LAWS OFLAWS OF

    ELECTROMAGNETISMELECTROMAGNETISM

  • 8/8/2019 Understanding Electrical Laws

    4/51

    Electrical Distribution Training - dc.-10 4

    Section 1: Variables and units

    Variables and units

    Physicallaws

    Theelectricarc

  • 8/8/2019 Understanding Electrical Laws

    5/51

    Electrical Distribution Training - dc.-10 5

    - multiples and submultiples of units

    Multiples

    103 106 109 1012

    k M G Tkilo mega giga tera

    Submultiples

    10-3 10-6 10-9 10-12

    m Q n p

    milli micro nano pico

  • 8/8/2019 Understanding Electrical Laws

    6/51

    Electrical Distribution Training - dc.-10 6

    - units ofmeasure 1/2

    Basic units

    Dimensional equation: examplesSpeed: LT-1 Acceleration: LT-2 Force: MLT-2

    Electric charge: IT Voltage: ML2T-3 I-1 ...

    L length metre m

    M mass kilogramme kg

    T time second s

    I electriccurrent ampere A

    These variables form the basis of all other units

  • 8/8/2019 Understanding Electrical Laws

    7/51

    Electrical Distribution Training - dc.-10 7

    - units ofmeasure 2/2

    Weight:

    1 gramme = 15.4 grains

    1 kilogramme = 2.2046 pounds1 ton = 0.9842 ton

    Length:

    1 centimetre = 0.3937 inch

    1 metre = 1.094 yards

    1 kilometre = 0.6214 mile

  • 8/8/2019 Understanding Electrical Laws

    8/51

    Electrical Distribution Training - dc.-10 8

    - main variables and related units

    force N Newtonenergy J Joule

    power W Watt

    acceleration m / s2

    pressure Pa Pascal

    moment of inertia

    kg.m2

    MECHANICAL

    electric charge C Coulomb

    voltage V Voltelectric field V / m

    impedance ; ohm

    resistance ;

    reactance ;

    inductance H Henry

    capacitance F Farad

    magnetic induction T Tesla

    magnetic field A / m

    magnetic flux Wb Weber

    permeability Q H / m

    permittivity I F / m

    conductance S Siemens

    resistivity ; . mfrequency Hz Hertz (s-1)

    pulsation rd / s

    ...

    ELECTRICAL

    Vs

    l

    U = R I

    R =

  • 8/8/2019 Understanding Electrical Laws

    9/51

    Electrical Distribution Training - dc.-10 9

    - sun-earth power emission

    10TW

    human activity

    180 .103 TW

    1400W / m2

    received 200TW

    photosynthesis

    35TW

    internal

    180 . 103 TWre-emitted

    loss of

    mass:

    4.109 kg /s

    390 .1012 TW

    radiation

    1000nucleargroups = 1 TW

  • 8/8/2019 Understanding Electrical Laws

    10/51

    Electrical Distribution Training - dc.-10 10

    Section 2: Physical laws

    Physical laws

    Theelectricarc

    Variablesandunits

  • 8/8/2019 Understanding Electrical Laws

    11/51

    Electrical Distribution Training - dc.-10 11

    - how is electrical energy produced?

    A rotating magnet near a circuit containing turns generates alternatingvoltage (Lenz'slaw)

    e

    = magnetic flux

    e =

    dt

    dJ

  • 8/8/2019 Understanding Electrical Laws

    12/51

    Electrical Distribution Training - dc.-10 12

    - an alternating variable can be

    represented by:

    A rotating vector

    A sine wave

    3T/2

    U 0

    2T

    T/2

    T0 T/2 T 3T/2 2T

    y = a sin U

    y y

    r

    U

    r

    UU

    rr

    U

  • 8/8/2019 Understanding Electrical Laws

    13/51

    Electrical Distribution Training - dc.-10 13

    - alternating current

    0 U[ T[ 2T[

    I

    t

    IdcIrms

    i = Idc . sin [t

    ... Sameapplies forvoltage

    Root mean square (rms) value: the value of direct current which

    would give off the same energy by Joule effect in a resistor

    I rms = Idc / V2

  • 8/8/2019 Understanding Electrical Laws

    14/51

    Electrical Distribution Training - dc.-10 14

    - Ohm's law applied to direct current

    Wire resistance: R = V l / sV = 1.8.10-8 ;.m copper

    V = 2.9.10-8 ;.m aluminium

    V= 100.10-8 ;.m nickel-chromium

    (alloy for resistors)

    I in A

    U in V

    R in ;

    U

    I R

    U = R I

    P in W

    in . m

    I in m

    S in m

    V ;

    P = U I = R I2 = U2/ R

  • 8/8/2019 Understanding Electrical Laws

    15/51

    Electrical Distribution Training - dc.-10 15

    - Ohm's law applied to alternating current (a.c.)

    z = impedance of the a.c. circuit witha frequency f

    [ = 2T f current pulsation

    RL

    Ci

    u

    u = z . i in complex numbers

    z

    iu

    equivalentcircuit

    XZ

    R

    z is a complex number the real partof which is the resistance R and

    imaginary part the reactance X

    z = R + j.X z in ;

    where X = L[ - 1/ C[ X in ;

    L: inductance in Henry f in HzC: capacitance in Farad

  • 8/8/2019 Understanding Electrical Laws

    16/51

    Electrical Distribution Training - dc.-10 16

    - Ohm's law applied to alternating current (a.c.)

    z

    iu

    z = R + j X

    z = (Z , J ) in polar form

    where Z2 = R2 + X2

    and tgJ= X / R

    z = Z e j J

    i = I e j [ t

    u = z . i = Z.I e j J . e j [ t

    = Z.I e j([ t + J) = U e j([ t + J)

    z

    i

    u

    JJU = ZI

    X

    R

    u = z . i in complex numbers

  • 8/8/2019 Understanding Electrical Laws

    17/51

    Electrical Distribution Training - dc.-10 17

    - active power and reactive power

    P(t) = U(t) . I(t) = U . I sin([t) sin([t N)

    P(t) = U . I cos N (1 cos2 [t) + U . I sin N sin (2[t)

    The integral cycle shows:

    S = U.I apparent power in VAQ = U.I.sinN reactive power in VAR

    P = U.I.cosN active power in W

    P Q

  • 8/8/2019 Understanding Electrical Laws

    18/51

    Electrical Distribution Training - dc.-10 18

    - do not confuse:

    "Line loss" and "Voltage drops "

    Source Load

    line

    z = R + j X

    V1 V2

    I

    Joule effect only depends on R

    P I Rline= .2

    (in Watts)

    Depends on R and X

    ( V = V1 -V2(in Volts)

  • 8/8/2019 Understanding Electrical Laws

    19/51

    Electrical Distribution Training - dc.-10 19

    - law of impedance combination

    z1

    z2

    Series:

    z = z1 + z2

    The impedances are added

    z1 z2

    (Admittance = inverse of impedance)

    Parallel:

    1 / z = 1 / z1 + 1 / z2

    z = z1. z2 / (z1+ z2)

    The admittances are added

  • 8/8/2019 Understanding Electrical Laws

    20/51

    Electrical Distribution Training - dc.-10 20

    - the three-phase diagram

    N

    Ph3

    Ph2

    Ph1

    2V

    V3

    V1U23

    U12

    3

    2T

    3

    2T

    3

    2T

    U31

    V1, V2, V3 : single-phase voltages

    U12, U23, U31 : phase-to-phase voltages

    U12 = V2 - V1 in vectors

    in balanced three-phase operating

    conditions,

    U = V . 3V2 lagging of behind V13

    2T

    3 windings with phase displacement

    of120 (2T/ 3)

  • 8/8/2019 Understanding Electrical Laws

    21/51

    Electrical Distribution Training - dc.-10 21

    - why three-phase current?

    The most economical means of remotely transmitting movement:

    minimal number of windings to create a rotating magnetic field

    A.c. generator motor

  • 8/8/2019 Understanding Electrical Laws

    22/51

    Electrical Distribution Training - dc.-10 22

    - three-phase power diagram

    Active power

    Pa = U.I. cos J in W (= 3 VI cosN)

    Reactive power

    Pr = U.I. sin J in VAR

    Apparent power

    S = U.I. in VA (= 3 VI)

    3

    3

    3

    J

    Pa

    Pr

    J

    RII

    jXI

  • 8/8/2019 Understanding Electrical Laws

    23/51

    Electrical Distribution Training - dc.-10 23

    *Coulomb'slaw

    Two charges of the same sign repel each other

    Two charges of the opposite sign attract each other

    Concreteapplications:static electricity, capacitors...

    q M Er4TI r2

    q E =

    q q' FdF

    Electric field on point M created by a punctual load q

    Interaction face between two punctual electric loads

    q . q' F =

    4TI r2

    q in C

    E in V

    r in m

    d in m

    I in F/mI0 = dielectric constant of vacuum

    Ir= relative permittivity of ambient material

    Dielectric constant I!I0 . IrI = 10

    -7/ 4 T c0 = 8.85 . 10-12 F / m

  • 8/8/2019 Understanding Electrical Laws

    24/51

    Electrical Distribution Training - dc.-10 24

    *Kirchhof'slaw

    Concreteapplications:loop networks protection

    protection by open delta earth currentmeasurement

    7(u = 0

    Around a loop

    7 i = 0

    On a node

    N

    A

    B

    C D

    E

  • 8/8/2019 Understanding Electrical Laws

    25/51

    Electrical Distribution Training - dc.-10 25

    *Ampere'slaw

    I

    B

    r

    Concreteapplications: disturbance by proximity of a conductor

    Magnetic permeability Q = Q0.Qr

    Q0 = 4 T 10-7 = 12.6 . 10-7 0 in H/m

    Qr= 1 for vacuum, air, aluminium

    Qr= 600- 800 for iron

    I . Q0 . c02 = 1

    Q0IB =

    div B = 0

    An infinite rectilinear conductor, through which a current

    (I) flows, creates a magnetic induction B in the

    surrounding space

    B in T

    I in Ar in m

    2

    Tr

  • 8/8/2019 Understanding Electrical Laws

    26/51

    Electrical Distribution Training - dc.-10 26

    *Laplace'slawof force

    Concreteapplications:electromechanical forces motors

    F = i . dl 0 B

    F = i . dl . B . sin E

    I

    B

    E

    F

    An induction B exerts a force F on a

    conductor through which a current (I)

    flows

    Right hand

    Thumb

    Middle finger

    Index finger

  • 8/8/2019 Understanding Electrical Laws

    27/51

    Electrical Distribution Training - dc.-1027

    *Lenz'slaw

    Co

    ncrete

    applicatio

    ns: generator...

    A conductive circuit forms a ring around a

    surface through which the induction varies;

    this circuit is subjected to an electromotive

    force E along the circuit

    E = - dJ/ dt

    B variable(increasing)

    E

  • 8/8/2019 Understanding Electrical Laws

    28/51

    Electrical Distribution Training - dc.-1028

    *Amperesand Laplaceslaws

    Concreteapplications: electrodynamic forces busbar

    withstand withdrawable circuit breaker arm

    I I

    Force of repulsion

    ---> loop effect

    Proportional to the

    product of the currents

    I I

    Force of attraction

  • 8/8/2019 Understanding Electrical Laws

    29/51

    Electrical Distribution Training - dc.-1029

    *Lenzsand Laplaceslaws

    C

    on

    crete

    application

    s: energym

    eters electric brakesover-heating of cubicle side panels by Eddy currents

    Circular currents induced in the metal frames by a variation in magnetic

    flux:

    Aluminium

    disk

  • 8/8/2019 Understanding Electrical Laws

    30/51

    Electrical Distribution Training - dc.-1030

    *Voltage dropcalculation

    Concreteapplications: a very useful professional rule

    Voltage drop in vectors V1- V2 = z . I = (R + j.X).IAs an absolute value this is very close to AB = AH + HB

    Whence (V = R I cos J + X I sin JREMARK:the voltage dropmaybe negative....

    Source Load

    line

    z = R + jX

    V2

    Z , N

    V1

    I

    ( V

    N V2

    V1

    R.I

    X.I

    I

    A H B

    $ (V

  • 8/8/2019 Understanding Electrical Laws

    31/51

    Electrical Distribution Training - dc.-10 31

    Section 3: The electric arc

    The electric arc

    Variablesandunits

    Physicallaws

  • 8/8/2019 Understanding Electrical Laws

    32/51

    Electrical Distribution Training - dc.-10 32

    - the electric arc

    The arc is created when the voltage between two conductors is higher asthe maximum dielectric withstand value of the medium separating them

    Irreversible deterioration in solid insulating materials

    Ionisation of the medium separating the contacts

    air SF6 gas

    oil

    vacuum: vapourization of the metal of the contacts

    The ionised insulating medium becomes temporarily conductive

    Presence of an arc voltage depending on the ionised mediumand on the nature of electrodes

  • 8/8/2019 Understanding Electrical Laws

    33/51

    Electrical Distribution Training - dc.-10 33

    - breaking techniques: the puffer technique

    Moving

    contact

    Fixed

    contact

    I

    Flow ofcurrent

    Separationof contacts

    & arcing

    Lengthening ofthe arc &

    blow-out

    Extinction ofthe arc as the

    current reaches

    zero

  • 8/8/2019 Understanding Electrical Laws

    34/51

    Electrical Distribution Training - dc.-10 34

    - breaking techniques: the vacuum technique

    Moving

    contact

    Fixed

    contact

    I

    Flow of

    current

    Initial

    RMF AMF

    Diffuse

    U net

    Constricted

    Arc control Interruption

  • 8/8/2019 Understanding Electrical Laws

    35/51

    PART 2: BASIC VOCABULARY

    BASIC VOCABULARYBASIC VOCABULARY BASIC VOCABULARYBASIC VOCABULARY

    Backtothebeginningofthepart"Lawsof Electromagnetism"

  • 8/8/2019 Understanding Electrical Laws

    36/51

    Electrical Distribution Training - dc.-10 36

    Section 1: Electrical definitions

    Electrical definitions

    Apparatus functions

    Typesof networks

  • 8/8/2019 Understanding Electrical Laws

    37/51

    Electrical Distribution Training - dc.-10 37

    - voltages

    Three voltage values define the equipment operating characteristics

    rated voltage is the maximum value of the voltage which the

    equipment can withstand in normal operation

    rated insulation level determines the dielectric withstand to

    overvoltage and impulse voltage

    - it depends on the rated voltage

    service voltage is the voltage applied to the terminals of the equipment

  • 8/8/2019 Understanding Electrical Laws

    38/51

    Electrical Distribution Training - dc.-10 38

    - voltages

  • 8/8/2019 Understanding Electrical Laws

    39/51

    Electrical Distribution Training - dc.-10 39

    - currents

    Two current values define the equipment operating characteristics:

    rated normal current is the value of the current that the equipment can

    withstand permanently without exceeding the temperature allowed by the

    standard

    rated short-time withstand current is the value of the short-circuit

    current to be withstood for one second (or sometimes three seconds)

    the peak value of t

    he rated s

    hort-time

    withstand current is equal to2.5 times its rms value

    Two current values define the network operating characteristics:

    service current is the circuit load value calculated from the consumption

    of the connected apparatus

    short-circuit current is the overcurrent due to a fault or faulty operationon the circuit: Isc

  • 8/8/2019 Understanding Electrical Laws

    40/51

    Electrical Distribution Training - dc.-10 40

    - frequency

    There are two frequencies normally used in the world:

    50 Hz in Europe

    60 Hz in NorthAmerica.

    Some countries use both frequencies:

    Saudi Arabia...

  • 8/8/2019 Understanding Electrical Laws

    41/51

    Electrical Distribution Training - dc.-10 41

    Section 2: Apparatus functions

    Apparatus functions

    Typesof networks

    Electricaldefinitions

  • 8/8/2019 Understanding Electrical Laws

    42/51

    Electrical Distribution Training - dc.-10 42

    - safety functions: isolating, earthing

    DESIGNATION FUNCTION Switching on-off Closing and breaking

    AND SYMBOL the service currents the faulted currents

    Disconnector

    insulate NO NO

    Earthing switch

    insulate NO NO(to be able toclose on c/c)

  • 8/8/2019 Understanding Electrical Laws

    43/51

    Electrical Distribution Training - dc.-10 43

    - control functions

    NO

    NO

    NO

    DESIGNATION FUNCTION Switching on-off Closing and breaking

    AND SYMBOL the service currents the faulted currents

    YES

    Switch on-off

    not insulate

    Switch

    NO

    NO

    NO

    YESSwitch on-off

    insulate

    Disconnector switch

    NO

    NO

    NOYESSwitch on-offnot insulate

    Contactor

  • 8/8/2019 Understanding Electrical Laws

    44/51

    Electrical Distribution Training - dc.-10 44

    -protection functions

    DESIGNATION FUNCTION Switc ing on-off Closing and breaking

    AND SYMBOL theservicec rrents the fa lted c rrents

    Protect

    not ins late

    YES YESFixed circ it-breaker

    DESIGNATION FUNCTION Switching on-off Closing and breaking

    AND SYMBOL theservicec rrents the fa lted c rrents

    Switch on-off

    Protect - ins latein withdrawn

    position

    YESYESWithdrawablecirc it-breaker

    DESIGNATION FUNCTION Switching on-off Closing and breaking

    AND SYMBOL theservicec rrents the fa lted c rrents

    Protect

    not ins late YES(once)

    NO

    Fuse

  • 8/8/2019 Understanding Electrical Laws

    45/51

    Electrical Distribution Training - dc.-10 45

    Section 3: Types of networks

    Types of networks

    Electricaldefinitions

    Apparatus functions

  • 8/8/2019 Understanding Electrical Laws

    46/51

    Electrical Distribution Training - dc.-10 46

    - two types of configuration

    MV distribution networks may be either:

    overhead or underground

    radial or loop configuration

  • 8/8/2019 Understanding Electrical Laws

    47/51

    Electrical Distribution Training - dc.-10 47

    - radial configuration

  • 8/8/2019 Understanding Electrical Laws

    48/51

    Electrical Distribution Training - dc.-10 48

    - open loop configuration

  • 8/8/2019 Understanding Electrical Laws

    49/51

    Electrical Distribution Training - dc.-10 49

    - networks

    The networkiseverywherein thelandscape...

    andin everybuildingaswell

  • 8/8/2019 Understanding Electrical Laws

    50/51

    Electrical Distribution Training - dc.-10 50

    -public energy network

    LVconsumer

    MVconsumer(tertiary,

    small industry)

    HVconsumer

    (heavy industry)

    EHVnational

    MVlocal

    LVlocal

    HVregional

  • 8/8/2019 Understanding Electrical Laws

    51/51

    Electrical Distribution Training - dc.-10 51

    END OF TRAINING

    Thanks for the time you have spent on this training course

    We hope it will be useful for your job

    For any further information, you can contact us by e-mail:

    [email protected]

    And, of course, the whole Electrical Distribution Training team

    remains at your disposal