unit 7 length
TRANSCRIPT
Modul Bestari Matematik UPSRJPNS 2011
UNIT 7
LENGTH
Objective Questions
1. Convert 5 800 mm to cm.Tukarkan 5 800 mm kepada cm.A 0.58B 5.8C 58D 580
2. 8 m 72 cm + 6 m 19 cm =A 2 m 53 cmB 14 m 91 cmC 22 m 24 cmD 24 m 91 cm
3. 2160 cm – 98 cm =A 76. 4 cmB 118 cmC 2 062 cmD 2 602 cm
4. The length of a pencil box is 25 cm. What is the total length of 6 similar pencil boxes, in m?Panjang sebuah kotak pensel ialah 25 cm. Berapakah jumlah panjang 6 buah kotak pensel yang sama, dalam m?A 0.15B 1.5C 15D 150
5. cm + 21 cm = 5 021 cm
A 5B 50C 500D 5 000
6. 0.75 m – m = 0.56 mA 0.11B 0.19C 0.21
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Modul Bestari Matematik UPSRJPNS 2011
D 0.297. The total length of 9 similar pencils is 144 cm. What is the length of a pencil, in cm?
Jumlah panjang 9 batang pensel yang sama ialah 144 cm. Berapakah panjang sebatang pensel, dalam cm?A 14 B 16 C 17 D 18
8. Subtract 69 m from 91 m.Tolakkan 69 m daripada 91 m.A 160 mB 156 mC 100 mD 22 m
9. 4.3 cm × 1 000 =A 43 cmB 430 cmC 4 300 cmD 43 000 cm
10. 100.8 cm ÷ 6 =A 1.68 cmB 16.8 cmC 168 cmD 1680 cm
11. A rope measuring 96 m is cut into 8 equal parts. What is the length of each part?Seutas tali yang berukuran 96 m telah dipotong kepada 8 bahagian yang sama panjang. Berapakah panjang satu bahagian tali itu?A 11 mB 12 mC 13 mD 14 m
12. 7 m 98 cm – 5 m 89 cm =A 22 m 99 cm B 21 m 91 cmC 12 m 19 cmD 2 m 9 cm
13. Calculate 4 m 8 cm ÷ 4 =Hitungkan 4 m 8 cm ÷ 4 =A 1 m 2 cmB 4 m 4 cm C 8 m 12 cmD 16 m 32 cm
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Modul Bestari Matematik UPSRJPNS 2011
14. Find the difference between 8 cm 14 mm and 2 cm 8 mmCari perbezaan antara 8 cm 14 mm dan 2 cm 8 mmA 22 cm 99 mm B 20 cm 19 mmC 10 cm 22 mmD 6 cm 6 mm
15. Find the product of 1.25 m and 6 Cari hasil darab 1.25 m dan 6.A 70.5 m B 7.5 m C 7.05 mD 7.005 m
16. Convert 3.25 km to m Tukarkan 3.25 km kepada mA 325 mB 3 250 mC 32 500 mD 325 000 m
17. 9 km 700 m – 7 km 650 m =A 20 km 500 m B 16 km 150 mC 16 km 15 mD 2 km 50 m
18. 0.39 km × 100 =A 39 mB 390 mC 3 900 mD 39 000 m
19. 950 m ÷ 10 =A 0.95 kmB 0.095 kmC 0.0095 kmD 0.00095 km
20. 120.5 km – 75 m =A 45.5 km B 120.425 kmC 455 kmD 120 425 km
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Modul Bestari Matematik UPSRJPNS 2011
21. 1.25 km × 6 =A 0.75 mB 7.50 mC 750 mD 7 500 m
22. Find the difference between 0.9 km and 475 m.Cari beza antara 0.9 km dan 475 mA 385 mB 425 mC 474.1 mD 852.5 m
23. 1 957 m × 12 =A 23.484 kmB 234.84 kmC 2 348.4 kmD 23 484 km
24. 6 km 125 m + = 8 km 425 m
What must be written into the box above?Apakah yang perlu diisi dalam petak di atas?A 1 km 700 mB 2 km 300 mC 14 km 300 mD 14 km 550 km
25. 1.75 km ÷ 10 =A 0.175 mB 1.75 mC 17.5 mD 175 m
26.
Diagarm 1 Rajah 1
Diagram 1 shows a road map. Find the distance, in km, from the mosque to John’s house passing through the school.Rajah 1 menunjukkan peta jalan. Cari jarak, dalam km, dari masjid ke rumah John melalui sekolahA 8.075 kmB 8.25 km C 7.25 km
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MosqueMasjid
SchoolSekolah John’s house
Rumah John7.25 km
825 m
Modul Bestari Matematik UPSRJPNS 2011
D 6.425 km
27. A plot of land of 1 500 m long is divided equally into 12 parts. Find the length, in km, of each part.Sebidang tanah yang panjangnya 1 500 m dibahagikan kepada 12 bahagian yang sama besar. Cari panjang, dalam km setiap bahagian.A 0.125 B 1.5 C 15 D 125
28.
Diagram 2 Rajah 2
In Diagram 2, PQ is 4 250 m longer than QR. Calculate the length of QR, in km.Dalam Rajah 2. PQ adalah 4 250 m lebih panjang daripada QR. Kira panjang QR, dalam km.A 107.69 B 22.69 C 10.769D 2.269
29. 0.035 km of rope is cut into 5 parts of the same length. Find the length of each part, in m.Seutas tali yang panjangnya 0.035 km telah dipotong kepada 5 bahagian yang sama panjang. Cari panjang setiap bahagian tali itu, dalam m.A 70 B 7C 0.7 D 0.07
30. Add 2.8 km and 412 m. Give the answer in m.Tambahkan 2.8 km dan 412 m. Berikan jawapan dalam m.A 4 148 B 3 212 C 414.8 D 3.212
Unit 7 Length Page 193
P Q R6 519 m
Modul Bestari Matematik UPSRJPNS 2011
UNIT 7
LENGTH
Subjective Questions
1. 1 cm = __________ mm
2. 1 m = ______________cm
3. 28 cm = _____________ mm
4. 20 m = ______________cm
5. 7.4 m = ___________ cm
6. 14 mm = ___________ cm
7. 807 cm = ___________ mm
8. 3 m 51 cm + 7 m 64 cm = _________ m _________ cm
9. 85 m 33 cm – 49 m 90 cm = _________ m ________ cm
10. Convert the height of the glass below in mm.Tukarkan tinggi gelas di bawah kepada mm.
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12 cm
Modul Bestari Matematik UPSRJPNS 2011
11. The length of the nail below is __________ cm.Panjang paku di bawah ialah ______ cm
12. 52 mm = ___________ cm
13. 5 cm + 20 cm = ______________ cm
14. 60 m – 20 m = ____________ m
15. 5. 4 cm x 100 = _______________ cm
16. 25 mm ÷ 5 = _____________ mm
17. Amy walks to the cake house from her house through the bookshop. How far does she walk altogether, in m?Amy berjalan ke kedai kek dari rumahnya melalui kedai buku. Berapa jauhkah dia berjalan, dalam m?
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350 m 670 m
Amy’s house Rumah Amy
BookshopKedai buku
Cake house Kedai kek
Modul Bestari Matematik UPSRJPNS 2011
18. What is the length of AB, in m?Apakah jarak AB, dalam m?
19. 5 006 m = ___________ km
20. 0.051 km = __________ m
21. 7.64 km + 0.04 km = ____________ m
22. 481 m + 865 m = ______________ km
23. 7.18 km – 1.03 km = _____________ m
24. 6 032 m – 1 153 m = _____________ km
25. 0. 003 km 2 = ____________ km
Unit 7 Length Page 196
1 020 m
550 m
A B C
Modul Bestari Matematik UPSRJPNS 2011
26. Diagram 26 shows a road map.Rajah 26 menunjukkan sebuah peta jalan.
Diagram 26 Rajah 26
What is the distance from X to Z through Y, in km?Apakah jarak dari X ke Z melalui Y, dalam km?
27. Diagram 27 shows the location of houses A, B, C.Rajah 27 menunjukkan lokasi rumah A, B, C.
Diagram 27 Rajah 27
Find the difference in the distance from house A to house B and the distance from house B to house C, in km.Cari perbezaan jarak dari rumah A ke rumah B dan jarak rumah B ke rumah C, dalam km.
28. 567 m = ___________ km
29. 0.640 km = __________ m
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X Z
Y
17 km8 km
A
C
B
881 km
602 km
Modul Bestari Matematik UPSRJPNS 2011
30. 30 km + 4 km = ____________ m
31. 866 m + 200 m = ______________ km
32. 8.80 km – 2.30 km = _____________ m
33. 7489 m – 298 m = _____________ km
34. 388 m 6 = ____________ m
35. 0.400 km ÷ 4 = _____________ km
36. Diagram 36 shows the positions of three houses P, Q and R along a street.Rajah 36 menunjukkan kedudukan tiga buah rumah P, Q dan R sepanjang sebatang jalan.
3.27 km
P 1.93 km Q R
Diagram 36
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Modul Bestari Matematik UPSRJPNS 2011
Rajah 36 Calculate the distance, in km, between Q and R?Hitungkan jarak, dalam km, antara Q dan R
37. Diagram 37 shows the location of houses T, U and V.Rajah 37 menunjukkan lokasi rumah T, U dan V.
Diagram 37 Rajah 37
Find the total distance, in km, from house T to house U and the distance from house U to house V.Cari jumlah jarak, dalam km, antara rumah T ke rumah U dan rumah U ke rumah V.
38. Calculate 3.27 km – 216 m. Give your answer in m.Hitungkan 3.27 km – 216 m. Berikan jawapan anda dalam m.
39. 7.26 km ÷ 3 = Express your answer in m.Tukarkan jawapan anda dalam m.
40. 18.03 km – 386 m = Give your answer in km.Berikan jawapan anda dalam km.
Unit 7 Length Page 199
T
V
U
6661 km
321 km
Modul Bestari Matematik UPSRJPNS 2011
41. The distance from P to Q is 7 times the distance from Q to R. The distance from Q to R is 9.465 km. What is the distance from P to Q?Jarak dari P ke Q ialah 7 kaloi jarak dari Q ke R. Jarak dari Q ke R ialah 9.465 km. Berapakah jarak dari P ke Q?
42. Mr Wong stays in Lok Kawi. He works in Inanam. He has to pass Putatan before reaching Inanam. The distance from Lok Kawi to Putatan is 7.8 km, while the distance from Putatan to Inanam is 20 km 750 m. How far is Mr Wong’s house from his office?En. Wong tinggal di Lok Kawi. Dia bekerja di Inanam. Dia perlu melalui Putatan sebelum sampai ke Inanam. Jarak dari Lok Kawi ke Putatan ialah 7.8 km, sementara jarak dari Putatan ke Inanam ialah 20 km 750 m. Berapa jauhkah pejabat En.Wong dari rumahnya?
43. The perimeter of a basketball court is 127.5 m. Ranjit ran 9 rounds around the basketball court. How many kilometres did he run? Give your answer in three decimal places.Perimeter sebuah gelanggang bola keranjang ialah 127.5 m. Ranjit lari 9 pusingan mengelilingi gelanggang itu. Berapa kilometer Ranjit telah lari. Berikan jawapan anda dalam tiga tempat perpuluhan.
44. In a map, 2 cm represents 2.5 km. What distance does 7 cm on the map represents?Dalam sebuah peta, 2 cm mewakili 2.5 km. Apakah jarak yang diwakili oleh 7 cm di atas peta itu?
45. The length of a roll wire is 0.015 km. Fuad cuts it into three parts. The length of the first
part is m5
43 while the second part measures 6.04 m. Find the length, in m, of the third
part.Panjang segulung dawai ialah 0.015 km. Fuad potong dawai itu kepada tiga bahagian.
Panjang bahagian pertama ialah m5
43 manakala bahagian kedua berukuran 6.04 m.
Cari panjang, dalam m, bahagian ketiga.
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Modul Bestari Matematik UPSRJPNS 2011
46. After cutting 20 pieces of ribbons, each measuring 4.2 m, Husniza has 88.5 m of ribbon left. Find the length, in m, of the original piece of ribbon.Selepas memotong 20 helai reben, yang berukuran 4.2 m setiap satu, Reben Husniza masih tinggal 88.5 m. Cari panjang asal reben itu, dalam m.
47. Mr Goon drove for km2
13 before he stopped for a rest. Then he drove another 5 km
900 m to reach his house. What is the total distance, in km, covered by Mr Goon?
En. Goon memandu sejauh km2
13 sebelum dia berhenti untuk rehat. Kemudian, dia
memandu 5 km 900 m untuk sampai ke rumahnya. Berapakah jumlah jarak, dalam km, yang dilalui oleh En. Goon?
48. The length of a roll wire is 216 m. Find the length, in km, of 8 similar rolls of copper wire.Panjang segulung dawai ialah 216 m. Cari panjang, dalam km, 8 gulung dawai yang sama panjang.
49. Azlan jogged 5 km a day. If he jogs 5 days with the same distance, how far did he jog, in m, in five days?Azlan berjoging 5 km sehari. Jika dia berjoging selama 5 hari dengan jarak yang sama, berapa jauhkah dia berjoging, dalam m, dalam 5 hari.
50. Amir has a rope which measures 7.26 m long. He cuts the rope into 3 equal parts. Find the length, in cm, of each rope.Amir ada seutas tali yang berukuran 7.26 m panjang. Dia potong tali itu kepada 3 bahagian yang sama panjang. Cari panjang, dalam cm, setiap tali itu.
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Modul Bestari Matematik UPSRJPNS 2011
UNIT 7
LENGTH
Sample Answers
21. 7.64 km + 0.04 km = ____________ m
7.64 km 7.68km × 1000 = 7680 m + 0.04 km 7.68 km
48. The length of a roll wire is 216 m. Find the length, in km, of 8 similar rolls of copper wire.Panjang segulung dawai ialah 216 m. Cari panjang, dalam km, 8 gulung dawai yang sama panjang.
216 m 1728m ÷ 1000 = 1.728 km × 8 1728 m
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Modul Bestari Matematik UPSRJPNS 2011
UNIT 7
LENGTH
Answers for Objective Questions
UNIT 7
LENGTH
Answers for Subjective Questions
Questions No.
Suggested AnswersSub
MarksTotal
MarksRemarks
1 10 P1 1
2 100 P1 1
328 cm × 10280 mm
K1N1
2
420 m × 1002 000 cm
K1N1
2
57.4 m × 100740 cm
K1N1
2
614 mm ÷ 101.4 cm
K1N1
2
Unit 7 Length Page 203
1 D 11 B 21 D2 B 12 D 22 B3 C 13 A 23 A4 B 14 D 24 B5 D 15 B 25 D6 B 16 B 26 A7 B 17 D 27 A8 D 18 D 28 D9 C 19 B 29 B10 B 20 B 30 B
PETUNJUK: P – PengetahuanK – KaedahN – Nilai
Modul Bestari Matematik UPSRJPNS 2011
Questions No.
Suggested AnswersSub
MarksTotal
MarksRemarks
7807 cm × 108 070 mm
K1N1
2
8 3 m 5 1 cm+ 7 m 6 4 cm1 1 m 1 5 cm
K1N1
2
9K1N1
2
1012 cm × 10120 mm
K1N1
2
11 5.4 P1 1
1252 mm ÷ 105.2 cm
K1N1
2
13K1N1
2
14K1N1
2
15 5.4 cm × 100540 cm
K1N1
2
Unit 7 Length Page 204
1
8 5 m 3 3 cm- 4 9 m 9 0 cm
3 5 m 4 3 cm
5+ 2 0
2 5
6 0 m- 2 0 m
4 0 m
Modul Bestari Matematik UPSRJPNS 2011
16 25 mm ÷ 55 mm
K1N1
2
17K1N1
2
Questions No.
Suggested AnswersSub
MarksTotal
MarksRemarks
18K1N1
2
19 5.006 kmK1N1
2
20 51 mK1N1
2
21
7.68 km × 1 0007 680 m
K1N1
2
22K1N1
2
23
6.150 km × 1 0006 150 m
K1K1N1
3
Unit 7 Length Page 205
1
12 9 0
1
3 5 0 m+ 6 7 0 m
1 0 2 0 m
1 0 2 0 m- 5 5 0 m
4 7 0 m
7 . 6 4 k m+ 0 . 0 4 k m
7 . 6 8 k m
0 . 4 8 1 k m+ 0 . 8 6 5 k m
1 . 3 4 6 k m
7 . 1 8 0 k m- 1 . 0 3 0 k m
6 . 1 5 0 k m
Modul Bestari Matematik UPSRJPNS 2011
24
4 879 m ÷ 1 0004.879 km
K1K1N1
3
25 0.003 km × 20.006 km
K1N1
2
26 8 km + 17 km25 km
K1N1
2
Questions No.
Suggested AnswersSub
MarksTotal
MarksRemarks
27 881 km – 602 km279 km
K1N1
2
280.567 km
P11
29640 m
P11
3030 km + 4 km34 km × 1 00034 000 m
K1N1
2
31866 m + 200 m1 066 m ÷ 1 0001.066 km
K1N1
2
328.80 km – 2.30 km6.50 km × 1 0006 500 m
K1N1
2
337 489 m – 298 m7 191 m ÷ 1 0007.191 km
K1N1
34 388 m × 62 328 m
K1N1
2
35 0.400 km ÷ 40.100 km
K1N1
2
36 3.27 km – 1.93 km1.34 km
K1N1
2
Unit 7 Length Page 206
121295
6 0 3 2 m- 1 1 5 3 m
4 8 7 9 m
Modul Bestari Matematik UPSRJPNS 2011
37 321 km + 6 661 km6 982 km
K1N1
2
383.27 km – 216 m3 270 m – 216 m3 054 m
K1N1
2
397.26 km ÷ 37 260 m ÷ 32 420 m
K1N1
2
40 18.03 km – 0.386 km17.644 km
K1N1
2
Questions No.
Suggested AnswersSub
MarksTotal
MarksRemarks
41 9.465 km × 766.255 km
K1N1
2
427.8 km + 20 km 750 m7.8 km + 20.75 km28.55 km
K1N1
2
439 × 127.5 m 1 147.5 m ÷ 1 0001.1475 km1.148 km (three decimal places)
K1K1N1
3
44
1 cm on the map represents;2.5 km ÷ 21.25 km
7 cm represents;7 × 1.25 km8.75 km
K1
K1N1
3
45
0.015 km = 15 m
m5
43 = 3.80 m
15 m – 3.80 m – 6.04 m5.16 m
K1
K1N1
3
4620 × 4.2 m 84.0 m + 88.5 m172.5 m
K1K1N1
3
47km
2
13 + 5 km 900 m
3.5 km + 5.9 km
K1
K1
3
Unit 7 Length Page 207
Modul Bestari Matematik UPSRJPNS 2011
9.4 km N1
488 × 216 m = 1 728 m1 728 m ÷ 1 0001.728 km
K1K1N1
3
495 km × 5 = 25 km25 km × 1 00025 000 m
K1K1N1
3
507.26 m ÷ 3 = 2.42 m2.42 m × 100242 cm
K1K1N1
3
Unit 7 Length Page 208