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Unit #8 Radicals and the Quadratic Formula Lessons: 1 - Square Root Functions 2 - Solving Square Root Equations 3 - The Basic Exponent Properties 4 - Fractional Exponents Revisited 5 - More Exponent Practice 6 - The Quadratic Formula 7 - More Work with the Quadratic Formula

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  • Unit #8

    Radicals and the Quadratic Formula

    Lessons:

    1 - Square Root Functions

    2 - Solving Square Root Equations

    3 - The Basic Exponent Properties

    4 - Fractional Exponents Revisited

    5 - More Exponent Practice

    6 - The Quadratic Formula

    7 - More Work with the Quadratic Formula

  • Lesson 1: Square Root Functions and Graphs

    Square roots are the natural inverses of squaring . In other words, to find the square root of an input, we must

    find a number that when squared gives the input. Because of their important role in higher-level mathematics, it is

    important to understand their graphs, as well as their domains and ranges.

    Exercise #1: Consider the two functions and 3 2f x x g x x . (a) Graph 𝑦 = 𝑓(π‘₯) without the use of your

    calculator on the grid shown. Label its equation.

    (b) Using your calculator to generate a table of values, graph 𝑦 = 𝑔(π‘₯) on the same grid and

    label its equation. Start your table at π‘₯ = βˆ’10 to

    see certain x-values not in the domain of this

    function.

    (c) State the domain and range of each function below using set-builder notation.

    𝑓(π‘₯) = √π‘₯ 𝑔(π‘₯) = √π‘₯ + 3 βˆ’ 2

    Domain = Domain =

    Range = Range =

    Shifts in Graphs:

    We’ve seen in previous chapter that horizontal movement (left or right) is controlled by any constants inside

    with the x-term, and that vertical movement (up or down) is controlled by any constants grouped with the y-term

    or alone.

    Additionally, coefficients effect the graph by changing how wide or narrow the graph is, and can change the

    direction that a graph goes in. For example, 𝑦 = βˆ’π‘₯2 would open downwards because of the negative coefficient.

    These major shifts hold true for many function graphs, including the square root

    Exercise #2: Which of the following equations would represent the graph shown?

    (1) 𝑦 = βˆ’βˆšπ‘₯ + 4

    (2) 𝑦 = 4βˆ’ √π‘₯

    (3) 𝑦 = √π‘₯ βˆ’ 4

    (4) 𝑦 = βˆ’βˆšπ‘₯ βˆ’ 4

    y

    x

    y

    x

  • As we saw in the first exercise, the domains of square root functions are oftentimes limited due to the fact that

    square roots of negative numbers do not exist in the Real Number System. We shall see in Unit #9 how these

    square roots can be defined if a new type of number is introduced. For now, though, we are only working with real

    numbers.

    Recall: To determine the domain for these functions, we take the radicand (term(s) under the square root)

    and set it greater than or equal to zero, and solve.

    π’“π’‚π’…π’Šπ’„π’‚π’π’… β‰₯ 𝟎

    Exercise #3: Which of the following values of x does not lie in the domain of the function 𝑦 = √π‘₯ βˆ’ 5?

    Explain why it does not lie there.

    (1) π‘₯ = 6 (3) π‘₯ = 5

    (2) π‘₯ = 2 (4) π‘₯ = 7

    Exercise #4: Determine the domain for each of the following functions. Show an inequality that justifies you work.

    (a) 𝑦 = √π‘₯ + 2 (b) 𝑦 = √3π‘₯ βˆ’ 2 (c) 𝑦 = √8βˆ’ 2π‘₯

    Exercise #5: Consider the function 𝑓(π‘₯) = √π‘₯2+ 4π‘₯ βˆ’ 12.

    (a) Use your calculator to sketch the function on the axes

    given.

    (b) Set up and solve a quadratic inequality that yields the

    domain of 𝑓(π‘₯).

    y

    x

  • Lesson 1 Homework: Square Root Functions and Graphs

    1. Which of the following represents the domain and range of 𝑦 = √π‘₯ βˆ’ 5+ 7?

    (1) Domain: [βˆ’5, ∞) (3) Domain: (βˆ’7, ∞)

    Range: [7, ∞) Range: (5,∞)

    (2) Domain: [5, ∞) (4) Domain: [7, ∞)

    Range: [7, ∞) Range: [5, ∞)

    2. Which of the following values of x is not in the domain of 𝑦 = √1βˆ’ 3π‘₯?

    (1) π‘₯ =1

    3 (3) π‘₯ = 0

    (2) π‘₯ = βˆ’1 (4) π‘₯ = 4

    3. Which of the following equations 4. Which equation below represents the

    describes the graph shown below? graph shown below?

    (1) 𝑦 = √π‘₯ + 4+ 1 (1) 𝑦 = √π‘₯ βˆ’ 2βˆ’ 5

    (2) 𝑦 = √π‘₯ βˆ’ 4βˆ’ 1 (2) 𝑦 = βˆ’βˆšπ‘₯ + 2+ 5

    (3) 𝑦 = √π‘₯ + 4βˆ’ 1 (3) 𝑦 = βˆ’βˆšπ‘₯ βˆ’ 2+ 5

    (4) 𝑦 = √π‘₯ βˆ’ 4+ 1 (4) 𝑦 = √π‘₯ + 2+ 5

    5. Determine the domains of each of the following functions. State your answers in set-builder notation.

    (a) 𝑦 = √π‘₯ + 10 (b) 𝑦 = √3π‘₯ βˆ’ 5 (c) 𝑦 = √7βˆ’ 2π‘₯

    y

    x

    y

    x

  • 6. Set up and algebraically solve a quadratic inequality that results in the domain of each of the following. Verify

    your answers by graphing the function in a standard viewing window.

    (a) 𝑦 = √π‘₯2 βˆ’4π‘₯ βˆ’ 5 (b) 𝑦 = √9βˆ’ π‘₯2

    7. Consider the function 𝑔(x) = βˆ’βˆšπ‘₯ + 5+ 3.

    (a) Graph the function y g x on the grid shown.

    (b) Describe the transformations that have

    occurred to the graph of y x to produce

    the graph of y g x . Specify both the transformations and their order.

    y

    x

  • Answers to Lesson 1 Homework

    1) (2)

    2) (4)

    3) (1)

    4) (3)

    5) (a) {π‘₯ β‰₯ βˆ’10} (b) {π‘₯ β‰₯5

    3} (c) {π‘₯ ≀

    7

    2}

    6) (a) (b) First the function is reflected in the x-axis. Then, the

    function is shifted 5 units to the left and shifted

    3 units up.

  • Lesson 2: Solving Square Root Functions

    Equations involving square roots arise in a variety of contexts, both applied and purely mathematical. As always,

    the key to solving these equations lies in the applications of inverse operations. Recall that a square and square

    root are inverses.

    Get the square root alone

    Square both sides

    Finish solving

    Check all answers for extraneous roots

    Oftentimes, roots are introduced by various algebraic techniques that for one reason or another are not valid

    solutions of the equations. These roots are known as extraneous and can always be found by calculator-checking

    within the original equation.

    Exercise #1: Solve each of the following square root equations. Check each equation for extraneous roots

    (a) √π‘₯ = 7 (b) √π‘₯ βˆ’ 3 = 5 (c) √2π‘₯ βˆ’ 1 = 4

    (d) 3√π‘₯ βˆ’ 4 = 20 (e) 2√π‘₯ + 5+ 7 = 13 (f) 5√3π‘₯ βˆ’ 2βˆ’ 4 = 36

    _____Exercise #2: Which of the following is the solution to 3√π‘₯

    2= 15?

    (1) π‘₯ = 12.5 (2) π‘₯ = 50

    (3) π‘₯ = 25 (4) π‘₯ = 4050

  • Another scenario arises when a square root expression is equal to a linear expression. The next exercise will

    illustrate both the graphical and algebraic issues involved.

    Exercise #3: Consider the system of equations shown below.

    𝑦 = √π‘₯ + 3 and 𝑦 = π‘₯ + 1

    (a) Solve this system graphically using the grid to the

    right.

    (b) Solve this system algebraically for only the x-values

    using substitution below.

    (c) Why does your answer from part (a) contradict what you found in part (b)?

    Exercise #4: Find the solution set of each of the following. Be sure to check your work and reject any extraneous

    roots.

    (a) √2π‘₯ βˆ’ 3 = π‘₯ βˆ’ 3 (b) 2π‘₯ = √π‘₯ + 6 βˆ’ 2

    y

    x

  • Lesson 2 Homework: Solving Square Root Functions

    1. Solve and check each of the following equations. As in the lesson, they are arranged from lesser to more

    complex.

    (a) √π‘₯ = 5 (b) √π‘₯ + 2 = 10 (c) √2π‘₯

    3= 6

    (d) 4√π‘₯ = 24 (e) 2√π‘₯ = 1 (f) √3π‘₯ = 4 = 8

    (g) 1

    2√π‘₯ βˆ’ 5 = 2 (h) √4π‘₯ βˆ’ 1+ 3 = 4 (i) 5√1βˆ’ 5π‘₯ βˆ’ 3 = 27

  • _____2. Which of the following values solves the equation √4π‘₯+19

    2= 2?

    (1) βˆ’9

    2 (2) βˆ’

    3

    4

    (3) 4

    3 (4)

    1

    2

    3. Solve and check each of the following equations for all values of x. Reject any extraneous roots.

    (a) π‘₯ βˆ’ 1 = √π‘₯ + 11 (b) √4π‘₯ + 36 = 2π‘₯ βˆ’ 6

    .

    (c) 6π‘₯ = 2√2π‘₯ + 17 βˆ’ 8 (d) √6π‘₯+4βˆ’1

    4= π‘₯

  • Answers to Lesson 2 Homework

    1)

    (a) x = 25 (b) x = 98 (c) x = 54 (d) x = 36 (e) 𝒙 =𝟏

    πŸ’

    (f) x = 20 (g) x = 196 (h) 𝒙 =𝟏

    𝟐 (i) 𝒙 = βˆ’πŸ•

    2) (2)

    3) (𝒂) 𝒙 = πŸ“;𝒙 β‰  βˆ’πŸ (𝒆𝒙𝒕𝒓𝒂𝒏𝒆𝒐𝒖𝒔 𝒓𝒐𝒐𝒕)

    (b) 𝒙 = πŸ•;𝒙 β‰  𝟎 (𝒆𝒙𝒕𝒓𝒂𝒏𝒆𝒐𝒖𝒔 𝒓𝒐𝒐𝒕)

    4) (𝒂) 𝒙 = {±𝟏

    πŸ‘}

    (b) 𝒙 =πŸ‘

    πŸ–; 𝒙 β‰  βˆ’

    𝟏

    𝟐 (𝒆𝒙𝒕𝒓𝒂𝒏𝒆𝒐𝒖𝒔 𝒓𝒐𝒐𝒕)

  • Lesson 3: The Basic Exponent Properties

    Exponents, which indicate repeated multiplication, are extremely important in higher-level mathematical study

    because of their importance in numerous areas. The rules they play by, known as the exponent properties, are

    critical to master. You should have seen these properties in previous math courses.

    Recall Exponent Properties or Exponent Laws:

    1) (𝒙𝒂)(𝒙𝒃)= 𝒙𝒂+𝒃 2) 𝒙𝒂

    𝒙𝒃= π’™π’‚βˆ’π’ƒ; π’˜π’‰π’†π’“π’† 𝒙 β‰  𝟎

    3) (𝒙𝒂)𝒃= π’™π’‚βˆ™π’ƒ 4) (𝒙 βˆ™ π’š)𝒂 = 𝒙𝒂 βˆ™ π’šπ’‚ and (𝒙

    π’š)𝒂

    =𝒙𝒂

    π’šπ’‚

    5) π’™βˆ’π’‚=𝟏

    𝒙𝒂 and

    𝟏

    π’™βˆ’π’‚= 𝒙𝒂 6) π’™πŸŽ = 𝟏

    Exercise #1 (Property #1): Rewrite each of the following in simplest form:

    (a) π‘₯10 βˆ™ π‘₯3 = (b) (5π‘₯4)(6π‘₯3) = (c) π‘₯3𝑦2π‘₯6𝑦 =

    Exercise #2 (Property #2): Rewrite each of the following in simplest form:

    (a) π‘₯8

    π‘₯2= (b)

    6π‘₯10

    12π‘₯4= (c)

    2π‘₯6𝑦3

    8π‘₯𝑦2=

    Exercise #3 (Property #3): Simplify each of the following:

    (a) (π‘₯2)3 = (b) (𝑦4)6= (c) (π‘Ž1

    2)6

  • (d) Which of the following expressions is not equivalent to 30x ?

    (1) (π‘₯10)3 (3) π‘₯5 βˆ™ π‘₯6

    (2) (π‘₯6)5 (4) π‘₯10 βˆ™ π‘₯20

    Exercise #4 (Property #4): Rewrite each of the following as equivalent expressions:

    (a) (2π‘₯2)3 = (b) (3

    π‘₯2)4

    = (c) (βˆ’2π‘₯2𝑦5

    3𝑧3)3

    =

    Exercise #5 (Property #5): Rewrite each of the following without the use of negative exponents:

    (a) 32 (b) 4x (c)

    1

    π‘₯βˆ’3 (d)

    3π‘₯4𝑦10

    15π‘₯6𝑦9

    (e) 5π‘₯4π‘¦βˆ’3

    35π‘₯βˆ’2𝑦8 (f) (

    π‘₯10π‘¦βˆ’5

    3π‘₯βˆ’2𝑦)2

    Exercise #6 (Property #6): Simplify each of the following:

    (a) 05 (b) 03x (c) 4(2π‘₯)0=

    Handle the negatives

    Reduce the inside as

    much as possible

    Raise to the outside

    power

  • Lesson 3 Homework: The Basic Exponent Properties

    1. Express each of the following expressions in "expanded" form, i.e., do all of the multiplication and/or division

    possible and combine as many exponents as possible.

    (a) π‘₯3 βˆ™ π‘₯12 (b) 4π‘₯3 βˆ™ 5π‘₯5 (c) (βˆ’3π‘₯2𝑦)(5π‘₯7𝑦3) (d) (4π‘₯3𝑦6)(βˆ’7π‘₯4)

    (e) π‘₯9

    π‘₯3 (f)

    5π‘₯3𝑦7

    15π‘₯𝑦2 (g)

    π‘₯3

    π‘₯10 (h)

    10π‘₯4𝑦3

    25π‘₯8

    (i) (π‘₯5)8 (j) (10π‘₯3)0 (k) (βˆ’4π‘₯5)3 (l) (2π‘₯βˆ’2)4

    _____2. Which of the following is not equal to 2βˆ’2? Do not use your calculator to do this problem. Show your

    algebra.

    (1) 1

    4 (3) 0.25

    (2) βˆ’4 (4) 1

    22

    _____3. If the expression 1

    2π‘₯ was placed in the form π‘Žπ‘₯𝑏 where a and b are real numbers, then which of the following

    is equal to π‘Ž + 𝑏? Show how you arrived at your answer.

    (1) 1 (3) 1

    2

    (2) 3

    2 (4) βˆ’

    1

    2

  • _____4. If 𝑓(π‘₯) = 5π‘₯0 +4π‘₯βˆ’3 then 𝑓(π‘Ž) =

    (1) 12π‘Ž βˆ’ 5 (3) 1

    4π‘Ž3+5

    (2) 5+4

    π‘Ž3 (4) βˆ’12π‘Ž + 1

    _____5. Which of the following is equivalent to (4π‘₯8)

    3

    (6π‘₯5)2 for all π‘₯ β‰  0? Show the work that leads to your final answer.

    (1) 16

    9π‘₯14 (3)

    2

    3π‘₯14

    (2) 16

    9π‘₯4 (4)

    2

    3π‘₯4

  • Answers to Lesson 3 Homework

    1)

    (a) π‘₯15 (b) 20π‘₯8 (c) βˆ’15π‘₯9𝑦4 (d) βˆ’28π‘₯7𝑦6

    (e) π‘₯6 (f) 1

    3π‘₯2𝑦5 (g)

    1

    π‘₯7 (h)

    2𝑦3

    5π‘₯4

    (i) π‘₯40 (j) 1 (k) βˆ’64π‘₯15 (l) 16

    π‘₯8

    2) (2) Algebra required

    3) (4) Algebra required

    4) (2)

    5) (1)

  • Lesson 4: Fractional Exponents Revisited

    Recall that in Unit #4 we introduced the concept that roots could be represented by rational or fractional

    exponents.

    Recall we can also combine integer powers with roots with the following:

    Exercise #1: Rewrite each expression in the form bax where a and b are both rational numbers.

    (a) 5√π‘₯ (b) √π‘₯5

    4 (c)

    7

    √π‘₯3 (d)

    5

    3 √π‘₯10

    Exercise #2: Rewrite each of the following power/root combinations as a rational exponent in simplest form.

    (a) √π‘₯7 (b) √π‘₯64

    (c) (√π‘₯)6 (d) (√π‘₯

    3 )10

    _____Exercise #3: If 𝑓(π‘₯) = 10π‘₯32 ⁄ βˆ’ 24π‘₯βˆ’1, then which of the following represents the value of 𝑓(4)? Find the

    value without the use of a calculator. Show the steps in your calculation.

    (1) 36 (3) 54

    (2) 48 (4) 74

    _____ Exercise #4: Which of the following is not equivalent to π‘₯βˆ’7

    3⁄ ?

    (1) 1

    π‘₯73⁄ (3)

    1

    √π‘₯73

    (2) 1

    √π‘₯37 (4) √

    1

    π‘₯7

    3

    UNIT FRACTION EXPONENTS

    For n given as a positive integer: π‘Ž1𝑛⁄ = βˆšπ‘Ž

    𝑛

    π‘π‘œπ‘€π‘’π‘Ÿ

    π‘Ÿπ‘œπ‘œπ‘‘

    β€œpower over root”

    RATIONAL EXPONENT CONNECTION TO ROOTS

    For the rational number 𝑝

    π‘Ÿ, π‘Ž

    π‘π‘Ÿβ„ is equivalent to: βˆšπ‘Žπ‘

    π‘Ÿ or (βˆšπ‘Ž

    π‘Ÿ )𝑝

  • Variables are perfect

    roots if the exponent is

    divisible by the index

    Fractional exponents play by the same rules (properties) as all other exponents. It is, in fact, these properties that

    can justify many standard manipulations with square roots (and others). For example, simplifying roots.

    Exercise #5: Simplify each of the following roots. Show manipulations. Be thoughtful about the index being used!

    It may be helpful to write or calculate a list of perfect squares, cubes, etc

    (a) √28 (b) √π‘₯6𝑦11

    (c) √18π‘₯4 (d) √200π‘₯5𝑦3 (e) √147π‘₯9𝑦4

    (f) √163 (g) √108

    3 (h) √2503

    (i) √12π‘₯83

    (j) √1624 (k) √16π‘₯8

    4

    (l) √48π‘₯10𝑦54 (m) √64π‘₯12𝑦155

    SIMPLIFYING RADICALS

    βˆšπ‘Ž βˆ™ 𝑏 = βˆšπ‘Ž βˆ™ βˆšπ‘ or βˆšπ‘Ž βˆ™ 𝑏 𝑛 = βˆšπ‘Ž

    𝑛 βˆ™ βˆšπ‘π‘›

    ; try to keep π‘Ž as the largest perfect square divisor

  • Lesson 4 Homework: Fractional Exponents Revisited

    _____1. Which of the following is equivalent to π‘₯52⁄ ?

    (1) 5π‘₯

    2 (2)

    2π‘₯

    5 (3) √π‘₯5 (4) √π‘₯2

    5

    _____2. If the expression 1

    √π‘₯ was placed in π‘₯π‘Ž form, then which of the following would be the value of a?

    (1) -2 (2) 2 (3) 1

    2 (4) βˆ’

    1

    2

    _____3. Which of the following is not equivalent to √π‘₯9 ?

    (1) π‘₯3 (2) (√π‘₯)9 (3) π‘₯

    92⁄ (4) π‘₯4√π‘₯

    _____4. The radical expression √50π‘₯5𝑦3 can be rewritten equivalently as

    (1) 25π‘₯π‘¦βˆš2π‘₯𝑦 (3) 5π‘₯2π‘¦βˆš2π‘₯𝑦

    (2) 5π‘₯π‘¦βˆšπ‘₯𝑦 (4) 10π‘₯2π‘¦βˆš5π‘₯𝑦

    _____5. If the function 𝑦 = 12√π‘₯3 was placed in the form 𝑦 = π‘Žπ‘π‘₯ then which of the following is the value of π‘Ž βˆ™ 𝑏?

    (1) βˆ’36 (3) 36

    (2) βˆ’4 (4) 4

    6. Rewrite each of the following expressions without roots by using fractional exponents.

    (a) √π‘₯5 (b) √π‘₯3 (c) √π‘₯

    7 (d) √π‘₯6

    (e) √π‘₯113

    (f) 1

    √π‘₯4 (g)

    1

    √π‘₯23 (h)

    1

    √π‘₯9

  • 7. Rewrite each of the following without the use of fractional or negative exponents by using radicals.

    (a) π‘₯16⁄ (b) π‘₯

    110⁄ (c) π‘₯

    βˆ’13⁄ (d) π‘₯

    βˆ’15⁄

    (e) π‘₯35⁄ (f) π‘₯

    βˆ’72⁄ (g) π‘₯

    94⁄ (h) π‘₯

    βˆ’211⁄

    8. Simplify each of the following square roots that contain variables in the radicand.

    (a) √8π‘₯9 (b) √75π‘₯16𝑦11 (c) 2π‘₯√18π‘₯7 (d) 3π‘₯2π‘¦βˆš98π‘₯5𝑦8

    9. Express each of the following roots in simplest radical form.

    (a) √16π‘₯83

    (b)√108π‘₯5𝑦103 (c) √64π‘₯12𝑦143 (d) √375π‘₯7𝑦113

    10. Mikayla was trying to rewrite the expression 25π‘₯12⁄ in an equivalent form that is more convenient to use. She

    incorrectly rewrote it as 5√π‘₯. Explain Mikalya's error.

  • Answers to Lesson 4 Homework

    1) (3)

    2) (4)

    3) (1)

    4) (3)

    5) (4)

    6) (a) π’™πŸπŸβ„ (b) 𝒙

    πŸπŸ‘β„ (c) 𝒙

    πŸπŸ•β„ (d) 𝒙

    πŸ“πŸβ„

    (e) π’™πŸπŸ

    πŸ‘β„ (f) π’™βˆ’πŸ

    πŸ’β„ (g) π’™βˆ’πŸ

    πŸ‘β„ (h) π’™βˆ’πŸ—

    πŸβ„

    7) (a) βˆšπ’™πŸ” (b) βˆšπ’™

    𝟏𝟎 (c) 𝟏

    βˆšπ’™πŸ‘ (d)

    𝟏

    βˆšπ’™πŸ“

    (e) βˆšπ’™πŸ‘πŸ“

    (f) 𝟏

    βˆšπ’™πŸ• (g) βˆšπ’™πŸ—

    πŸ’ (h)

    𝟏

    βˆšπ’™πŸπŸπŸ

    8) (a) πŸπ’™πŸ’βˆšπŸπ’™ (b) πŸ“π’™πŸ–π’šπŸ“βˆšπŸ‘π’š (c) πŸ”π’™πŸ’βˆšπŸπ’™ (d) πŸπŸπ’™πŸ’π’šπŸ“βˆšπŸπ’™

    9) (a) πŸπ’™πŸ‘ βˆšπŸπ’™πŸπŸ‘

    (b) πŸ‘π’™π’šπŸ‘ βˆšπŸ’π’™πŸπ’šπŸ‘ (c) πŸ’π’™πŸ’π’šπŸ’ βˆšπ’šπŸπŸ‘ (d) πŸ“π’™πŸπ’šπŸ‘ βˆšπŸ‘π’™π’šπŸ πŸ‘

    10) Mikalya raised both the x and the 25 to the 𝟏

    𝟐 power. However, only the x should be raised to the

    𝟏

    𝟐

    power. The correct answer should be πŸπŸ“βˆšπ’™. She would be correct if the original expression contained

    parentheses: (πŸπŸ“π’™)𝟏

    𝟐.

  • Lesson 5: Exponent Practice

    For further study in mathematics, especially Calculus,

    it is important to be able to manipulate expressions

    involving exponents, whether those exponents are

    positive, negative, or fractional. The basic laws of

    exponents, which you should have learned in Algebra

    1 and have used previously in this course, are shown

    to the right. They apply regardless of the nature of

    the exponent (i.e. positive, negative, or fractional).

    Make each step carefully & thoughtfully, keeping in mind the order in which you are working.

    Exercise #1: Simplify each of the following expressions. Leave no negative exponents in your answers.

    (a) π‘₯3βˆ™π‘₯4

    (π‘₯5)2 (b)

    (π‘₯2𝑦)4

    π‘₯5𝑦7

    (c) π‘₯βˆ’3𝑦4

    π‘₯βˆ’6𝑦 (d)

    (π‘₯βˆ’3π‘¦βˆ’4)2

    (π‘₯𝑦3)βˆ’4

    In the last exercise, all of the powers were integers. In the next exercise, we introduce fractional powers.

    Remember, though, that they will still follow the exponent rules above. If needed, use your calculator to help add

    and subtract the powers.

    Exercise #2: Simplify each of the following expressions. Write each without the use of negative exponents.

    (a) π‘₯13⁄ βˆ™π‘₯

    12⁄

    π‘₯16⁄

    (b) (π‘₯

    12⁄ )

    5

    π‘₯32⁄ βˆ™π‘₯3

    (c) (4π‘₯

    23⁄ )

    3

    32π‘₯8

    EXPONENT LAWS

    1. π‘₯π‘Ž βˆ™ π‘₯𝑏 = π‘₯π‘Ž+𝑏 5. π‘₯βˆ’π‘Ž =1

    π‘₯π‘Ž and

    1

    π‘₯βˆ’π‘Ž= π‘₯π‘Ž

    2. π‘₯π‘Ž

    π‘₯𝑏= π‘₯π‘Žβˆ’π‘ 6. (π‘₯π‘Ž)𝑏 = π‘₯π‘Žβˆ™π‘

    3. (π‘₯ βˆ™ 𝑦)π‘Ž = π‘₯π‘Ž βˆ™ π‘¦π‘Ž and (π‘₯

    𝑦)π‘Ž

    =π‘₯π‘Ž

    π‘¦π‘Ž

    4. π‘₯π‘š

    𝑛 = √π‘₯π‘šπ‘› 7. π‘₯0 = 1

    (For integers m and n)

  • To be fully simplified, an expression should not contain negative exponents and should not contain fraction

    exponents.

    Exercise #3: Rewrite each expression below in its simplest form

    (a) π‘₯53⁄ (b)

    π‘₯52⁄

    π‘₯43⁄ (c)

    1

    π‘₯βˆ’3

    2⁄

    (d) π‘₯3

    √π‘₯ (e) (8π‘₯5)

    23⁄ (f)

    (27π‘₯)13⁄

    6√π‘₯

    Consider the real number component and the variable component individually. Be thoughtful about what is

    actually happening to which piece:

    _____Exercise #4: Which of the following is equivalent to √8π‘₯73

    ?

    (1) 8π‘₯73⁄ (3) 2π‘₯

    37⁄

    (2) 2π‘₯73⁄ (4) 8π‘₯

    37⁄

    _____Exercise #5: The expression 1

    √4π‘₯ is the same as

    (1) 1

    2π‘₯βˆ’1

    2⁄ (3) 4π‘₯12⁄

    (2) 2π‘₯βˆ’1

    2⁄ (4) 1

    2π‘₯12⁄

  • Lesson 5 Homework: Exponent Practice

    1. Rewrite each of the following expressions in simplest form and without negative exponents.

    (a) π‘₯3π‘₯7

    (π‘₯2)3 (b)

    5π‘₯4

    25π‘₯10 (c)

    (π‘₯3𝑦4)2

    (π‘₯3𝑦)3 (d)

    (2π‘₯3)5

    8π‘₯βˆ’4

    _____2. Which of the following represents the value of π‘Žβˆ’4

    π‘βˆ’2 when π‘Ž = 3 π‘Žπ‘›π‘‘ 𝑏 = 2?

    (1) 4

    9 (2)

    4

    81

    (3) 1

    36 (4)

    1

    3

    3. Simplify each expression below so that it contains no negative exponents. Do not write the expressions using

    radicals.

    (a) π‘₯72⁄ 𝑦

    12⁄

    π‘₯34⁄ 𝑦2

    (b) (π‘₯

    13⁄ )

    4

    π‘₯βˆ’2

    3⁄ (c) (5π‘₯

    23⁄ 𝑦

    βˆ’12⁄ )(2π‘₯2π‘¦βˆ’3)

    _____4. Which of the following represents the expression 24 π‘₯

    βˆ’12⁄

    6π‘₯52⁄

    written in simplest form?

    (1) 4

    π‘₯3 (3)

    π‘₯2

    4

    (2) 4π‘₯3 (4) 4π‘₯2

  • 5. Rewrite each of the following expressions using radicals. Express your answers in simplest form.

    (a) (4π‘₯)32⁄ (b) π‘₯

    βˆ’23⁄ (c) (π‘₯4)

    35⁄

    34 5x

    (d) √π‘₯3

    √π‘₯ (e)

    √π‘₯βˆ™π‘₯2

    π‘₯53⁄

    (f) (2√π‘₯)

    3

    24π‘₯

    _____6. Which of the following is equivalent to 5√π‘₯

    20π‘₯3?

    (1) 1

    4√π‘₯3 (3)

    1

    4 √π‘₯25

    (2) 4

    √π‘₯5 (4)

    1

    4√π‘₯5

    _____7. When written in terms of a fractional exponent the expression √π‘₯βˆ™π‘₯

    π‘₯βˆ’2 is

    (1) π‘₯72⁄ (3) π‘₯

    βˆ’12⁄

    (2) π‘₯52⁄ (4) π‘₯βˆ’

    32⁄

    _____8. Expressed as a radical expression, the fraction π‘₯13⁄ π‘₯

    12⁄

    π‘₯βˆ’1 is

    (1) 1

    √π‘₯6 (3) √π‘₯

    611

    (2) 1

    √π‘₯611 (4) √π‘₯

    116

  • Answers to Lesson 5 Homework

    1) (a) π’™πŸ’ (b) 𝟏

    πŸ“π’™πŸ” (c)

    π’šπŸ“

    π’™πŸ‘ (d) πŸ’π’™πŸπŸ–

    2) (2)

    3) (a) π’™πŸπŸ

    πŸ’β„

    π’šπŸ‘πŸβ„

    (b) π’™πŸ (c) πŸπŸŽπ’™

    πŸ–πŸ‘β„

    π’šπŸ•πŸβ„

    4) (1)

    5) (a) πŸ–π’™βˆšπ’™ (b) 𝟏

    βˆšπ’™πŸπŸ‘ (c) 𝒙

    πŸβˆšπ’™πŸπŸ“

    (d) 𝟏

    βˆšπ’™πŸ” (e) βˆšπ’™

    πŸ“πŸ” (f) βˆšπ’™

    πŸ‘

    6) (4)

    7) (1)

    8) (4)

  • Lesson 6: The Quadratic Formula

    There are three main paths to solving for the roots (solutions, zeros, x-intercepts) of a trinomial equation: Factoring (although not all are factorable!) Completing the square Quadratic Formula

    Exercise #1: Solve the following quadratic using the given method.

    Express your answers in simplest radical form.

    (a) completing the square. (b) the quadratic formula.

    π‘₯2βˆ’ 6π‘₯ + 1 = 0 π‘₯2 βˆ’ 6π‘₯ + 1 = 0

    _____Exercise #2: Which of the following represents the solutions to the equation π‘₯2 βˆ’10π‘₯ + 20 = 0?

    (1) π‘₯ = {5±√10} (3) π‘₯ = {βˆ’5±√10}

    (2) π‘₯ = {βˆ’5±√5} (4) π‘₯ = {5±√5}

    Quadratic Formula: π‘₯ =βˆ’π‘Β±βˆšπ‘2βˆ’4π‘Žπ‘

    2π‘Ž

    Notice that factoring

    would not work in this

    case. There are no

    numbers which multiply

    to +1 and add to -6!

    Notice that factoring

    would not work in this

    case. There are no

    numbers which multiply

    to +20 and add to -10!

    Make a conclusion: When a trinomial is NOT factorable, the roots will contain:

  • Exercise #3: Solve the following quadratic using the given method.

    (a) factoring (b) the quadratic formula

    2π‘₯2+ 11π‘₯ βˆ’ 6 = 0 2π‘₯2+ 11π‘₯ βˆ’ 6 = 0

    Exercise #4: Solve each of the following quadratics by using the quadratic formula. Place all answers in simplest

    form.

    (a) 3π‘₯2+ 5π‘₯ + 2 = 0 (b) π‘₯2 βˆ’8π‘₯ + 13 = 0

    (c) 2π‘₯2 βˆ’2π‘₯ βˆ’ 5 = 0 (d) 5π‘₯2+ 8π‘₯ βˆ’ 4 = 0

  • Lesson 6 Homework: The Quadratic Formula

    1. Solve each of the following quadratic equations using the quadratic formula.

    Express all answers in simplest form.

    (a) π‘₯2+7π‘₯ βˆ’ 18 = 0 (b) π‘₯2 βˆ’2π‘₯ βˆ’ 1 = 0

    (c) π‘₯2 +8π‘₯ + 13 = 0 (d) 3π‘₯2βˆ’ 2π‘₯ βˆ’ 3 = 0

    (e) 6π‘₯2βˆ’ 7π‘₯ + 2 = 0 (f) 5π‘₯2 + 3π‘₯ – 4 = 0

    Remember the conclusion made at the end of exercise two above. Circle a big green circle around any

    trinomial that must have been factorable, based on your solutions.

    π‘₯ = βˆ’π‘Β± βˆšπ‘2βˆ’ 4π‘Žπ‘

    2π‘Ž

  • _____2. Which of the following represents all solutions of π‘₯2 βˆ’4π‘₯ βˆ’ 1 = 0?

    (1) {2±√5} (3) {2 ±√10}

    (2) {2±√5} (4) {βˆ’2±√12}

    _____3. Which of the following is the solution set of the equation 4π‘₯2 βˆ’12π‘₯ βˆ’ 19 = 0?

    (1) {5

    2±√3} (3) {

    3

    2±√7}

    (2) {βˆ’2

    3±√2} (4) {βˆ’

    7

    3±√6}

    _____4. Rounded to the nearest hundredth the larger root of π‘₯2 βˆ’22π‘₯ + 108 = 0 is

    (1) 18.21 (3) 6.74

    (2) 13.25 (4) 14.61

  • 5. Algebraically find the x-intercepts of the function 𝑦 = π‘₯2βˆ’4π‘₯ βˆ’ 6. Express your answers in simplest radical

    form.

    6. A missile is fired such that its height above the ground is given by β„Ž = βˆ’9.8𝑑2+38.2𝑑 + 6.5, where t represents

    the number of seconds since the rocket was fired. Using the quadratic formula, determine, to the nearest tenth

    of a second, when the rocket will hit the ground.

  • Answers to Lesson 6 Homework

    1) (a) 𝒙 = {βˆ’πŸ—,𝟐} (b) 𝒙 = {𝟏± √𝟐} (c) 𝒙 = {βˆ’πŸ’Β±βˆšπŸ‘}

    (d) 𝒙 = {𝟏±√𝟏𝟎

    πŸ‘} (e) 𝒙 = {

    𝟏

    𝟐,𝟐

    πŸ‘} (f) 𝒙 = {

    βˆ’πŸ‘Β±βˆšπŸ–πŸ—

    𝟏𝟎}

    (You should have circled two questions)

    2) (1)

    3) (3)

    4) (4)

    5) 𝒙 = {𝟐± √𝟏𝟎}

    6) 𝒕 = {βˆ’πŸ‘πŸ–.πŸΒ±βˆšπŸπŸ•πŸ.πŸŽπŸ’

    βˆ’πŸπŸ—.πŸ”}

    𝒕 = {βˆ’πŸŽ.πŸπŸ”πŸ‘πŸ‘,πŸ’.πŸŽπŸ”πŸπŸ}

    Since the time must be positive, we reject the negative time.

    It will take approximately 4.1 seconds for the rocket to hit the ground.

  • Lesson 7: More Quadratic Formula

    The quadratic formula (shown above) is extremely useful because it allows us to solve quadratic equations,

    whether they are prime or factorable. In this lesson, we will get more practice using this formula.

    Exercise #1: Consider the quadratic function 𝑓(π‘₯) = π‘₯2 βˆ’4π‘₯ βˆ’ 36.

    (a) Algebraically determine this function’s x-intercepts using

    the quadratic formula. Write the answers in simplest

    radical form AND to the nearest hundredth

    (b) Find the vertex of this parabola

    (c) Sketch a graph of the quadratic on the axes given. Use the ZERO command on your calculator to verify your

    answers from part (b). Label the zeros on the graph.

    20

    50

    y

    x

    Quadratic Formula: 𝒙 =βˆ’π’ƒΒ±βˆšπ’ƒπŸβˆ’πŸ’π’‚π’„

    πŸπ’‚

  • _____ Exercise #2: Which of the following sets represents the x-intercepts of 𝑦 = 3π‘₯2 βˆ’19π‘₯ + 6?

    (1) {1

    2,7

    3}

    (2) {2βˆ’βˆš5,2 +√5}

    (3) {1

    6βˆ’βˆš

    17

    2,1

    6+ √

    17

    2}

    (4) {1

    3, 6}

    Exercise #3: (Revisiting the Crazy Carmel Corn Company) – Recall that the Crazy Carmel Corn company modeled

    the percent of popcorn kernels that would pop, P, as a function of the oil temperature, T, in degrees Fahrenheit

    using the equation

    𝑃 = βˆ’1

    250𝑇2+ 2.8𝑇 βˆ’ 394

    The company would like to find the range of temperatures that ensures that at least 50% of the kernels will pop.

    Write an inequality whose result is the temperature range the company would like to find. Solve this inequality

    with the help of the quadratic formula. Round all temperatures to the nearest tenth of a degree.

  • Exercise #4: Find the intersection points of the linear-quadratic system shown below algebraically using the

    quadratic formula. Then, use you calculator to help produce a sketch of the system. Label the intersection points

    you found on your graph.

    𝑦 = 4π‘₯2βˆ’ 6π‘₯ + 2 and 𝑦 = 6π‘₯ βˆ’ 3

    Note: The fact that the solutions to this system were rational numbers indicates that the quadratic equation in

    Exercise #4 could have been solved using factoring and the Zero Product Law

    5

    15

    y

    x

  • Lesson 7: More Quadratic Formula

    _____1. Which of the following represents the solutions to π‘₯2 βˆ’4π‘₯ + 12 = 6π‘₯ βˆ’ 2?

    (1) π‘₯ = {4±√7} (3) π‘₯ = {5±√22}

    (2) π‘₯ = {5±√11} (4) π‘₯ = {4±√13}

    _____2. The smaller root, to the nearest hundredth, of 2π‘₯2βˆ’ 3π‘₯ βˆ’ 1 = 0 is

    (1) 0.28 (3) 1.78

    (2) 0.50 (4) 3.47

    _____3. The x-intercepts of 𝑦 = 2π‘₯2 +7π‘₯ βˆ’ 30 are

    (1) π‘₯ = {βˆ’7±√191

    2} (3) π‘₯ = {βˆ’6,

    5

    2}

    (2) π‘₯ = {βˆ’3,5} (4) π‘₯ = {βˆ’3±√131}

    Solve the following equation for all values of x. Express your answers in simplest radical form.

    4) 4π‘₯2 βˆ’4π‘₯ βˆ’ 5 = 8π‘₯ + 6 5) 9π‘₯2 = 6π‘₯ + 4

    π‘₯ = βˆ’π‘Β±βˆšπ‘2βˆ’ 4π‘Žπ‘

    2π‘Ž

  • 6. Algebraically solve the system of equations shown below. Note that you can use either factoring

    or the quadratic formula to find the x-coordinates, but the quadratic formula is probably easier.

    𝑦 = 6π‘₯2+ 19π‘₯ βˆ’ 15 π‘Žπ‘›π‘‘ 𝑦 = βˆ’12π‘₯ + 15

    7. The Celsius temperature, C, of a chemical reaction increases and then decreases over time

    according to the formula 𝐢(𝑑) = βˆ’1

    2𝑑2 +8𝑑 + 93, where t represents the time in minutes. Use

    the Quadratic Formula to help determine the amount of time, to the nearest tenth of a minute, it

    takes for the reaction to reach 110 degrees Celsius.

  • Answers to Lesson 7 Homework

    1) (2)

    2) (1)

    3) (3)

    4) π‘₯ = {3Β±2√5

    2}

    5) π‘₯ = {1±√5

    3}

    6) {(βˆ’6,87), (5

    6, 5)}

    7) 𝑑 = {βˆ’8±√30

    βˆ’1}

    𝑑 β‰ˆ {2.5, 13.5}

    It will take approximately 2.5 minutes for the chemical reaction to reach 110Β° Celcius.