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Page 1: Utdallas.edu/~metin 1 Safety Inventories Chapter 11 of Chopra

1utdallas.edu/~metin

Safety Inventories

Chapter 11 of Chopra

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Why to hold Safety Inventory?

Desire for quick product availability– Ease of search for another supplier

– “I want it now” culture

Demand uncertainty – Short product life cycles

Safety inventory

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Measures

Measures of demand uncertainty– Variance of demand– Ranges for demand

Delivery Lead Time, L Measures of product availability

– Stockout, what happens? » Backorder (patient customer, unique product or big cost advantage) or

Lost sales.

– I. Cycle service level (CSL), % of cycles with no stockout

– II. Product fill rate (fr), % of products sold from the shelf

– Order fill rate, % of orders» Equivalent to product fill rate if orders contain one product

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Service measures: CSL and fr are different

CSL is 0%, fill rate is almost 100%

CSL is 0%, fill rate is almost 0%

inventory

inventory

time

time

0

0

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Replenishment policies

When to reorder? How much to reorder?

– Most often these decisions are related.

Continuous Review: Order fixed quantity when total inventory drops below Reorder Point (ROP).

- ROP meets the demand during the lead time L.- One has to figure out the ROP.Information technology facilitates continuous review.

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Demand During Lead time

variance).(mean,or ),,(Mostly

i. periodin demand 2 NRNormalD

D

iii

i

jijijijjii

jjiijiji

dDdDDDfRDRD

RDRDEDD

),())((

)})({(),cov(

,

2,

iiiiii dDDfDDER )()(

Dfor functionsdensity cumulative anddensity y probabilit F , iiif

iiiiiiiii dDDfRDRDEDVar )()(}){()( 222

nintegratio oflinearity by the )(11

L

ii

L

ii RDE

),cov(),cov()(1 11

2

1 11ji

L

i

L

ijj

L

ii

L

i

L

jji

L

ii DDDDDVar

tcoefficienn correlatio )/(2, jiji

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7utdallas.edu/~metin

Normal Density Function

Mean

95.44%

99.74%

x

)1,_,,(normdist:at x (cdf)function Cumulative

)0,_,,(normdist:at x (pdf)function Density

:functions lstatistica Excel

devstmeanx

devstmeanx

normdist(x,.,.,0)

Prob

normdist(x,.,.,1)frequency

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8utdallas.edu/~metin

Cumulative Normal Density

)_,,(norminv :prob""at cdf offunction Inverse

)1,_,,(normdist:at x (cdf)function Cumulative

:functions lstatistica Excel

devstmeanprob

devstmeanx

0

1

x

normdist(x,mean,st_dev,1)

prob

norminv(prob,mean,st_dev)

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Demand During Lead Time Determines ROP

Suppose that demands are identically and independently distributed. To mean identically and independently distributed, use iid.

),( then ),( If

)( and )(

2

1

2

2

11

LLRNDRND

LDVarLRDE

L

iii

L

ii

L

ii

1,,,Normdist,;1

LLRaLLRaFaDPL

ii

)(/)( :D ofn variatiooft Coefficien DEDVarcv

F is the cumulative density function of the demand in a single period, say a day. The second equality above holds if demand is Normal.

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Optimal Safety Inventory Levels

Lead Times

time

inventory

Shortage

An inventory cycle

ROP

Q

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I. Cycle Service Level: ROP CSL

),;(Level Service Cycle LLRROPFCSL

Cycle service level: percentage of cycles with stock out

ROP] timelead during [Demand inventory]t [Sufficien

inventory sufficient has cycle single ay that Probabilit0.7

7.0

otherwise 1 stockout, has cycle a if 0 Write10

1010111011

:cycles 10consider exampleFor

CSL

CSL

CSL

ROP: Reorder point

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I. Cycle Service Level for Normal Demands

ondistributi normal standard Obtaining )1,0(

StDev by the Dividing ),(

mean out the Taking ),(

),(

notation variance)(mean, Recall ),,(

)1,0(

2

2

2

R

R

N

R

R

R

R

R

L

LRROPNP

L

LRROP

L

LRLLRNP

LRROPLRLLRNP

ROPLLRNP

NLLRROPFCSL

The last equality is a property of the Normal distribution.

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Example: Finding CSL for given ROP

R = 2,500 /week; = 500L = 4 weeks; Q = 10,000; ROP = 16,000

ss = ROP – L R = Cycle service level,

Average Inventory = Average Flow Time =Average inventory/Thruput=

L timelead during demand of Stdev

F ROP L R L( ; , )

If you wish to compute Average Inventory = Q/2 + ss

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Safety Inventory: CSL ROP

L

LCSLFLCSLF

LRLLRCSLFss

LRROPss

LLRCSLFROPLLRROPFCSL

R

RR

L,0,1)Norminv(CS

)1,0;(),0;(

),,(

:demand ddistributenormally For

:stockSafety

),,(or ),,(

11

1

1

The last two equalities are by properties of the Normal distribution.

Very important remark: Safety inventory is a more general concept. It exists without lead time. It is the stock held minus the expected demand.

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Finding ROP for given CSL

R = 2,500/week; = 500

L = 4 weeks; Q = 10,000; CSL = 0.90

Factors driving safety inventory– Replenishment lead time

– Demand uncertainty

ss F CSL L

ROP L R ss

1 0 1( ; , )

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II. Fill rate:Expected shortage per cycle

ESC is the expected shortage per cycle ESC is not a percentage, it is the number of units, also see next page

ESC E

ESC x ROP f x dxx ROP

(max{

( ) ( )

Demand during lead time - ROP,0})

=

ROPDemand

ROPDemand

if

if

0

ROPDemandShortage

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Inventory and Demand during Lead Time

0

ROP

Demand During LT

LT

InventoryDLT: Demand During LT

0

0

ROPInventory=ROP-DLTUpside

down

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Shortage and Demand during Lead Time

0

ROP

Demand During LT

LTShortage

DL

T: D

eman

d D

urin

g L

T0

0

ROP

Shortage=DLT-ROP

Upsidedown

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Expected shortage per cycle First let us study shortage during the lead time

DLT. of pdf is f where)()(

))max(,0(shortage Expected

D

ROPD

D dDDfROPD

ROPDLTE

Ex:

4

1

4

110)}-(11max{0,

4

210)}-(10max{0,

4

110)}-(9max{0,

)()}(d)}(max{0,shortage Expected

Shortage? Expected ,

1/4 prob with 11

2/4 prob with 10

1/4 prob with 9

,10

11

10d

3

1i

33

22

11

dDPROPpROPd

pd

pd

pd

DROP

ii

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Expected shortage per cycle

If demand is normal:

Does ESC decrease or increase with ss, L? Does ESC decrease or increase with expected value of demand?

2170-172

)10(102

10

6

1)12(10

2

12

6

110

26

1

6

1)10(shortage Expected

Shortage? Expected ),12,6( ,10

2212

10

212

10

D

DD

DD

dDD

UniformDROP

Ex:

ESC ss normdistss

LL normdist

ss

L

1 0 11 0 1 0

, , , , , ,

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Fill Rate

Fill rate: Proportion of customer demand satisfied from stock Q: Order quantity

Q

ESCfr 1

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Finding the Fill Rate ss fr

= 500; L = 2 weeks; ss=1000; Q = 10,000; Fill Rate (fr) = ?

fr = (Q - ESC)/Q = (10,000 - 25.13)/10,000 = 0.9975.

ESC ss normdistss

LL normdist

ss

L

ESC normdist

nomdist

ESC

1 0 11 0 1 0

1000 1 1000 707 0 11

707 1000 707 0 1 0

2513

, , , , , ,

( ( / , , , )

( / , , , )

.

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Finding Safety Inventory for a Fill Rate: fr ss

If desired fill rate is fr = 0.975, how much safety inventory should be held?

Clearly ESC = (1 - fr)Q = 250

Try some values of ss or use goal seek of Excel to solve

0,1,0,

7077071,1,0,

7071250

ssnormdist

ssnormdistss

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Evaluating Safety Inventory For Given Fill Rate

Fill Rate Safety Inventory

97.5% 67

98.0% 183

98.5% 321

99.0% 499

99.5% 767

Safety inventory is very sensitive to fill rate. Is fr=100% possible?

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Factors Affecting Fill Rate

Safety inventory: If Safety inventory is up, – Fill Rate is up

– Cycle Service Level is up.

Lot size: If Lot size Q is up, – Cycle Service Level does not change. Reorder point,

demand during lead time specify Cycle Service Level.

– Expected shortage per cycle does not change. Safety stock and the variability of the demand during the lead time specify the Expected Shortage per Cycle. Fill rate is up.

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To Cut Down the Safety Inventory

Reduce the Supplier Lead Time– Faster transportation

» Air shipped semiconductors from Taiwan

– Better coordination, information exchange, advance retailer demand information to prepare the supplier

» Textiles; Obermeyer case

– Space out orders equally as much as possible Reduce uncertainty of the demand

– Contracts– Better forecasting to reduce demand variability

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Lead Time Variability

2222

11

:)( )( L

L

ii

L

ii sRLDVarLRDE

Supplier’s lead time may be uncertain:

timelead of Variance time.lead Average 2 sL

22211 )1,0;()1,0;( sRLCSLFCSLFss L

0,1,0;1,1,0;1

LL

L

ssnomdist

ssnormdistssESC

The formulae do not change:

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Impact of Lead Time Variability, s

R = 2,500/day; = 500

L = 7 days; Q = 10,000; CSL = 0.90

StDev of LT ss Jump in ss

0 1695 -

1 3625 1930

2 6628 3003

3 9760 3132

4 12927 3167

5 16109 3182

6 19298 3189

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Methods of Accurate Response to Variability

Centralization

– Physical, Laura Ashley

– Information

» Virtual aggregation, Barnes&Nobles stores

– Specialization, what to aggregate

Product substitution

Raw material commonality - postponement

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Centralization: Inventory Pooling

K

iji

ji

K

ii

CK

ii

CDDRR

11

22

1

),cov(2)(;

),(111 RD

),( CC

R

Which of two systems provides a higher level of service for a given safety stock? Consider locations and demands:

),(333 RD

),(222 RD

),(444 RD

With k locations centralized, mean and variance of

K

ii

C DD1

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Sum of Random Variables Are Less Variable

K

ii

K

ii

C

11

2

K

ii

K

ii

K

i

K

jii

jiiC

1

2

11 1

2 2

When they are independent, cov(Di,Dj)=0

When they are perfectly positively correlated, cov(Di,Dj)=σi σj

When they are perfectly negatively correlated, cov(Di,Dj)= - σi σj

K

ii

K

ii

K

i

K

jii

jiiC

11

2

1 1

2 2

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Factors Affecting Value of Aggregation

When to aggregate? Statistical checks: Positive correlation and Coefficient of Variation. – Aggregation reduces variance almost always except when products are

positively correlated

– Aggregation is not effective when there is little variance to begin with. When coefficient of variation of demand is relatively small (variance w.r.t. the mean is small), do not bother to aggregate.

In real life, – Is the electricity demand in Arlington and Plano are positively or negatively

correlated? Is there an underlying factor which affects both in the same direction? Note that a big portion of electricity is consumed for heating/cooling.

– Are the Campbell soup sales over time positively or negatively correlated? How many soups can you drink per day?

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Impact of Correlation on Aggregated Safety Inventory (Aggregating 4 outlets)

Safety stocks are proportional to the StDev of the demand. With four locations, we have total ss proportional to 4*σ

If four locations are all aggregated, ss proportional to 4*σ with correlation 1 ss proportional to 2*σ with correlation 0

Benefit=SS before - SS after / SS before

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Impact of Correlation on Aggregated Safety Inventory (Aggregating 4 outlets)

0

0.1

0.2

0.3

0.4

0.5

0.6

0 0.2 0.4 0.6 0.8 1

Benefit

Benefit=(SS before - SS after) / SS before

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EX 11.8: W.W. Grainger a supplier of Maintenance and Repair products

About 1600 stores in the US Produces large electric motors and

industrial cleaners Each motor costs $500; Demand is iid

Normal(20,40x40) at each store Each cleaner costs $30; Demand is iid

Normal(1000,100x100) at each store Which demand has a larger coefficient of

variation? How much savings if motors/cleaners

inventoried centrally?

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Use CSL=0.95 Supply lead time L=4 weeks for motors and cleaners

L L,0,1)Norminv(CS ss :demand ddistributenormally For For a single store

Motor safety inventory=Norminv(0.95,0,1) 2 (40)=132Cleaner safety inventory=Norminv(0.95,0,1) 2 (100)=329Value of motor ss=1600(132)(500)=$105,600,000

Value of cleaner ss=1600(329)(30)=$15,792,000

Standard deviation of demands after aggregating 1600 storesStandard deviation of Motor demand=40(40)=1,600Standard deviation of Cleaner demand=40(100)=4,000

For the aggregated storeMotor safety inventory=Norminv(0.95,0,1) 2 (1600)=5,264Cleaner safety inventory=Norminv(0.95,0,1) 2 (4,000)=13,159Value of motor ss=5264(500)=$2,632,000Value of cleaner ss=13,159(30)=$394,770

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EX. 11.8: Specialization: Impact of cv on Benefit From 1600-Store Aggregation , h=0.25

Motors Cleaner Mean demand/wk 20 1,000 SD of demand 40 100 Disaggregate cv 2 0.1 Value/Unit $500 $30 Disaggregate ss value $105,600,000 $15,792,000 Aggregate cv 0.05 0.0025 Aggregate ss value $2,632,000 $394,770 Inventory cost savings $102,968,000 $15,397,230 Holding Cost Saving $25,742,000 $3,849,308 Saving / Unit 2574200/(1600*20*52)=$15.47 $0.046

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Slow vs Fast Moving Items

Low demand = Slow moving items, vice versa.– Repair parts are typically slow moving items

Slow moving items have high coefficient of variation, vice versa. Stock slow moving items at a central store

Buying a best seller at Amazon.com vs. a Supply Chain book vs. a Banach spaces book, which has a shorter delivery time?

- Why cannot I find a “driver-side-door lock cylinder” for my 1994 Toyota Corolla at Pep Boys?

- Your instructor on March 26 2005.

- “Case Interview books” are not in our s.k.u. list. You must check with our central stores.

- Store keeper at Barnes and Nobles at Collin Creek, March 2002.

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Product Substitution Manufacturer driven Customer driven

Consider: The price of the products substituted for each other and the demand correlations

One-way substitution – Army boots. What if your boot is large? Aggregate?

Two-way substitution: – Grainger motors; water pumps model DN vs IT. – Similar products, can customer detect specifications.

If products are very similar, why not to eliminate one of them?

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Component Commonality. Ex. 11.9

Dell producing 27 products with 3 components (processor, memory, hard drive)

No product commonality: A component is used in only 1 product. 27 component versions are required for each component. A total of 3*27 = 81 distinct components are required.

Component commonality allows for component inventory aggregation.

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Max Component Commonality Only three distinct versions for each component.

– Processors: P1, P2, P3. Memories: M1, M2, M3. Hard drives: H1, H2, H3 Each combination of components is a distinct product. A

component is used in 9 products. Each way you can go from left to right is a product.

P1

P2

P3

M1

M2

M3

H1

H2

H3

Left Right

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Example 11.9: Value of Component Commonalityin Safety Inventory Reduction

0

50000

100000

150000

200000

250000

300000

350000

400000

450000

1 2 3 4 5 6 7 8 9

SS

# of products a component is used in

Aggregation provides reduction in total standard deviation.

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Standardization

Standardization – Extent to which there is an absence of variety in a product,

service or process

The degree of Standardization? Standardized products are immediately available to

customers Who wants standardization?

– The day we sell standard products is the day we lose a significant portion of our profit

– A TI manager on November 1, 2005

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Advantages of Standardization

Fewer parts to deal with in inventory & manufacturing

– Less costly to fill orders from inventory

Reduced training costs and time

More routine purchasing, handling, and inspection procedures

Opportunities for long production runs, automation

Need for fewer parts justifies increased expenditures on perfecting designs and improving quality control procedures.

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Disadvantages of Standardization

Decreased variety results in less consumer appeal.

Designs may be frozen with too many imperfections remaining.

High cost of design changes increases resistance to improvements

– Who likes optimal Keyboards?

Standard systems are more vulnerable to failure

– Epidemics: People with non-standard immune system stop the plagues.

– Computer security: Computers with non-standard software stop the dissemination of viruses.

Another reason to stop using Microsoft products!

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Inventory–Transportation Costs: Eastern Electric Corporation: p.427

Major appliance manufacturer, buys motors from Westview motors in Dallas

Annual demand = 120,000 motors

Cost per motor = $120; Weight per motor 10 lbs.

Current order size = 3,000 motors

» 30,000 pounds = 300 cwt

– 1 cwt = centum weight = 100 pounds; Centum = 100 in Latin.

Lead time = 1 + the number of days in transit

Safety stock carried = 50% of demand during delivery lead time

Holding cost = 25%

Evaluate the mode of transportation for all unit discounting based on shipment

weight

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AM Rail proposal: Over 20,000 lbs at 0.065 per lb in 5 days

For the appliance manufacturer– No fixed cost of ordering besides the transportation cost – No reason to transport at larger lots than 2000 motors, which

make 20,000 lbs.» Cycle inventory=Q/2=1,000» Safety inventory=(6/2)(120,000/365)=986» In-transit inventory

All motors shipped 5 days ago are still in-transit 5-days demand=(120,000/365)5=1,644

– Total inventory held over an average day=3,630 motors– Annual holding cost=3,630*120*0.25=$108,900– Annual transportation cost=120,000(10)(0.065)=$78,000

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Inventory–Transportation trade off: Eastern Electric Corporation, see p.426-8 for details

Alternative (Lot size)

Transport Cost

Cycle Inventory

Safety Inventory

Transit Inventory

Inventory Cost

Total Cost

AM Rail (2,000)

$78,000 120000(0.65)

1,000 986 1,644 120000(5/365)

$108,900 $186,900

Northeast Trucking (1,000)

$90,000 500 658 986 $64,320 $154,320

Golden (500)

$96,000 120000(0.80)

250 658 986 120000(3/365)

$56,820 $152,820

Golden (2,500)

$86,400 1,250 658 986 $86,820 $173,220

Golden (3,000)

$78,000 1,500 658 986 $94,320 $172,320

Golden (4,000)

$67,500 2,000 658 986 $109,320 $176,820

If fast transportation not justified cost-wise, need to consider rapid response

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Physical Inventory Aggregation: Inventory vs. Transportation cost: p.428

HighMed Inc. producer of medical equipment sold directly to doctors

Located in Wisconsin serves 24 regions in USA As a result of physical aggregation

– Inventory costs decrease

– Inbound transportation cost decreases» Inbound lots are larger

– Outbound transportation cost increases

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Inventory Aggregation at HighMed

Highval ($200, .1 lbs/unit) demand in each of 24 territories H = 2, H = 5

Lowval ($30/unit, 0.04 lbs/unit) demand in each territory L = 20, L = 5

UPS rate: $0.66 + 0.26x {for replenishments}

FedEx rate: $5.53 + 0.53x {for customer shipping}

Customers order 1 H + 10 L

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Inventory Aggregation at HighMed

Current Scenario

Option A Option B

# Locations 24 24 1

Reorder Interval 4 weeks 1 week 1 week

Inventory Cost $54,366 $29,795 $8,474

Shipment Size 8 H + 80 L 2 H + 20 L 1 H + 10 L

Transport Cost $530 $1,148 $14,464

Total Cost $54,896 $30,943 $22,938

If shipment size to customer is 0.5H + 5L, total cost of option B increases to $36,729.

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Summary of Cycle and Safety Inventory

Reduce Buffer Inventory

Economies of ScaleSupply / Demand

VariabilitySeasonal

Variability

Cycle Inventory Safety Inventory Seasonal Inventory

Match Supply & Demand

•Reduce fixed cost•Aggregate across products•Volume discounts•Promotion on Sell thru

•Quick Response measures•Reduce Info Uncertainty•Reduce lead time•Reduce supply uncertainty

•Accurate Response measures•Aggregation•Component commonality and postponement

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Mass customization:– A strategy of producing standardized goods or services,

but incorporating some degree of customization– Modular design– Delayed differentiation

Mass Customization

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Mass Customization I: Customize Services Around Standardized Products

DEVELOPMENT PRODUCTION MARKETING DELIVERY

Deliver customized services aswell as standardized productsand services

Market customized services with standardizedproducts or services

Continue producing standardized products or services

Continue developing standardized products or services

Source: B. Joseph PineWarranty for contact lenses:

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Mass Customization II: Create Customizable Products and Services

DEVELOPMENT PRODUCTION MARKETING DELIVERY

Deliver standard (but customizable) productsor services

Market customizable products or services

Produce standard (but customizable) products or services

Develop customizable products or services

Customizing the look of screen with windows operating system Gillette sensor adjusting to the contours of the face

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Mass Customization III: Provide Quick Response Throughout Value Chain

DEVELOPMENT PRODUCTION MARKETING DELIVERY

Reduce Delivery Cycle Times

Reduce selection and order processing cycle times

Reduce Production cycle time

Reduce development cycle time

Skiing parkas manufactured abroad vs. in the U.S.A.:

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Mass Customization IV: Provide Point of Delivery Customization

DEVELOPMENT PRODUCTION MARKETING DELIVERY

Deliver standardize portion

Market customized products or services

Produce standardized portion centrally

Develop products where point of delivery customization is feasible

Point of deliverycustomization

Paint mixingLenscrafters for glasses.

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Mass Customization V: Modularize Components to Customize End Products

DEVELOPMENT PRODUCTION MARKETING DELIVERY

Deliver customized product

Market customized products or services

Produce modularized components

Develop modularized products

Computer industry, Dell computers:

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Modular Design

Modular design is a form of standardization in which component parts are subdivided into modules that are easily replaced or interchanged.

– Good example: Dell uses same components to assemble various computers.

– Bad example: Earlier Ford SUVs shared the lower body with Ford cars.– Ugly example:

It allows:

– easier diagnosis and remedy of failures

– easier repair and replacement

– simplification of manufacturing and assembly

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Types of Modularity for Mass Customization

Component Sharing Modularity, Dell

Cut-to-Fit Modularity, Gutters that do not require seams

Bus Modularity, E-books

Mix Modularity, Paints

Sectional Modularity, LEGO

+ =

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Periodic ReviewOrder at fixed time intervals (T apart) to raise total inventory

(on hand + on order) to Order up to Level (OUL)

Inventory

OUL

LT

T

LT

T+LT

OUL must cover the Demand during

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Periodic Review Policy: Safety Inventory

T: Reorder interval

R: Standard deviation of demand per unit time

L+T: Standard deviation of demand during L+T periods

OUL: Order up to level

ssOUL

CSLFss

TL

RLT

R

R

LT

LT

LT

LT

)1,0;(

)(

1

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Example: Periodic Review Policy

R = 2,500/week; R = 500L = 2 weeks; T = 4 weeks; CSL = 0.90What is the required safety inventory?

Factors driving safety inventory– Demand uncertainty– Replenishment lead time– Reorder interval

1570)1,0;(1

LTCSLFss

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Periodic vs Continuous Review

Periodic review ss covers the uncertainty over [0,T+L], T periods more than ss in continuous case.

Periodic review ss is larger. Continuous review is harder to implement, use it for

high-sales-value per time products