uts 2017 - arthurlimantara.files.wordpress.com · rekayasa transportasi copyright © 2017 by. ir....
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![Page 1: UTS 2017 - arthurlimantara.files.wordpress.com · REKAYASA TRANSPORTASI Copyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT 13 SUPPLY 9 10 8 12 0 12 7 21 23 0 14 11 9 19 0 5](https://reader031.vdocument.in/reader031/viewer/2022020305/5c935e4a09d3f2e3628ce1b1/html5/thumbnails/1.jpg)
1 REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT
UTS 2017PEMBAHASAN
![Page 2: UTS 2017 - arthurlimantara.files.wordpress.com · REKAYASA TRANSPORTASI Copyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT 13 SUPPLY 9 10 8 12 0 12 7 21 23 0 14 11 9 19 0 5](https://reader031.vdocument.in/reader031/viewer/2022020305/5c935e4a09d3f2e3628ce1b1/html5/thumbnails/2.jpg)
REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT
2
SUPPLY & DEMAND
PABRIK SUPPLY
W 6.000X 7.000Y 8.000Z 5.000
TOTAL 26.000
KOTA DEMAND
A 6.000B 4.000C 5.000D 7.000
TOTAL 22.000
![Page 3: UTS 2017 - arthurlimantara.files.wordpress.com · REKAYASA TRANSPORTASI Copyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT 13 SUPPLY 9 10 8 12 0 12 7 21 23 0 14 11 9 19 0 5](https://reader031.vdocument.in/reader031/viewer/2022020305/5c935e4a09d3f2e3628ce1b1/html5/thumbnails/3.jpg)
REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT
3
BIAYA TRANSPORTASI
KEDARI
A B C D
W 9 10 8 12X 12 7 21 23Y 14 11 9 19Z 5 7 7 5
![Page 4: UTS 2017 - arthurlimantara.files.wordpress.com · REKAYASA TRANSPORTASI Copyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT 13 SUPPLY 9 10 8 12 0 12 7 21 23 0 14 11 9 19 0 5](https://reader031.vdocument.in/reader031/viewer/2022020305/5c935e4a09d3f2e3628ce1b1/html5/thumbnails/4.jpg)
REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT
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SUPPLY
9 10 8 12 0
12 7 21 23 0
14 11 9 19 0
5 7 7 5 0
DEMAND 26.0006.000 4.000 5.000 7.000 4.000
X
Y
Z
D Dummy
6.000
7.000
8.000
5.000
A
W
B CKE
DARI
![Page 5: UTS 2017 - arthurlimantara.files.wordpress.com · REKAYASA TRANSPORTASI Copyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT 13 SUPPLY 9 10 8 12 0 12 7 21 23 0 14 11 9 19 0 5](https://reader031.vdocument.in/reader031/viewer/2022020305/5c935e4a09d3f2e3628ce1b1/html5/thumbnails/5.jpg)
REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT
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SUPPLY
9 10 8 12 0
12 7 21 23 0
14 11 9 19 0
5 7 7 5 0
DEMAND 26.0006.000 4.000 5.000 7.000 4.000
X
Y
Z
D Dummy
6.000
7.000
8.000
5.000
A
W
B CKE
DARI
6.000
1.000
6.0002.000
3.0004.000
4.000
![Page 6: UTS 2017 - arthurlimantara.files.wordpress.com · REKAYASA TRANSPORTASI Copyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT 13 SUPPLY 9 10 8 12 0 12 7 21 23 0 14 11 9 19 0 5](https://reader031.vdocument.in/reader031/viewer/2022020305/5c935e4a09d3f2e3628ce1b1/html5/thumbnails/6.jpg)
REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT
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HASIL PERHITUNGAN
Z = 6.000 (9) + 4.000 (7) + 3.000 (21) +2.000 (9) + 6.000 (19) + 1.000 (5) + 4.000(0)
Z = 282.000
![Page 7: UTS 2017 - arthurlimantara.files.wordpress.com · REKAYASA TRANSPORTASI Copyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT 13 SUPPLY 9 10 8 12 0 12 7 21 23 0 14 11 9 19 0 5](https://reader031.vdocument.in/reader031/viewer/2022020305/5c935e4a09d3f2e3628ce1b1/html5/thumbnails/7.jpg)
REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT
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SUPPLY
9 10 8 12 0
12 7 21 23 0
14 11 9 19 0
5 7 7 5 0
DEMAND 26.0006.000 4.000 5.000 7.000 4.000
X
Y
Z
D Dummy
6.000
7.000
8.000
5.000
A
W
B CKE
DARI
6.000
1.000
6.0002.000
3.0004.000
4.000
![Page 8: UTS 2017 - arthurlimantara.files.wordpress.com · REKAYASA TRANSPORTASI Copyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT 13 SUPPLY 9 10 8 12 0 12 7 21 23 0 14 11 9 19 0 5](https://reader031.vdocument.in/reader031/viewer/2022020305/5c935e4a09d3f2e3628ce1b1/html5/thumbnails/8.jpg)
REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT
8
SUPPLY
9 10 8 12 0
12 7 21 23 0
14 11 9 19 0
5 7 7 5 0
DEMAND 26.0006.000 4.000 5.000 7.000 4.000
X
Y
Z
D Dummy
6.000
7.000
8.000
5.000
A
W
B CKE
DARI
6.000
4.000
3.0005.000
3.0004.000
1.000
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REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT
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HASIL PERHITUNGANITERASI 1
Z = 6.000 (9) + 4.000 (7) + 3.000 (0) + 5.000(9) + 3.000 (19) + 4.000 (5) + 1.000 (0)
Z = 204.000
![Page 10: UTS 2017 - arthurlimantara.files.wordpress.com · REKAYASA TRANSPORTASI Copyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT 13 SUPPLY 9 10 8 12 0 12 7 21 23 0 14 11 9 19 0 5](https://reader031.vdocument.in/reader031/viewer/2022020305/5c935e4a09d3f2e3628ce1b1/html5/thumbnails/10.jpg)
REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT
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SUPPLY
9 10 8 12 0
12 7 21 23 0
14 11 9 19 0
5 7 7 5 0
DEMAND 26.0006.000 4.000 5.000 7.000 4.000
X
Y
Z
D Dummy
6.000
7.000
8.000
5.000
A
W
B CKE
DARI
6.000
4.000
3.0005.000
3.0004.000
1.000
![Page 11: UTS 2017 - arthurlimantara.files.wordpress.com · REKAYASA TRANSPORTASI Copyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT 13 SUPPLY 9 10 8 12 0 12 7 21 23 0 14 11 9 19 0 5](https://reader031.vdocument.in/reader031/viewer/2022020305/5c935e4a09d3f2e3628ce1b1/html5/thumbnails/11.jpg)
REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT
11
SUPPLY
9 10 8 12 0
12 7 21 23 0
14 11 9 19 0
5 7 7 5 0
DEMAND 26.0006.000 4.000 5.000 7.000 4.000
X
Y
Z
D Dummy
6.000
7.000
8.000
5.000
A
W
B CKE
DARI
3.000
1.000
3.0005.000
3.000 4.000
4.000
3.000
![Page 12: UTS 2017 - arthurlimantara.files.wordpress.com · REKAYASA TRANSPORTASI Copyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT 13 SUPPLY 9 10 8 12 0 12 7 21 23 0 14 11 9 19 0 5](https://reader031.vdocument.in/reader031/viewer/2022020305/5c935e4a09d3f2e3628ce1b1/html5/thumbnails/12.jpg)
REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT
12
HASIL PERHITUNGANITERASI 2
Z = 3.000 (9) + 3.000 (12) + 3.000 (12) +4.000 (7) + 5.000 (9) + 3.000 (19) + 1.000(5) + 4.000 (0)
Z = 234.000
![Page 13: UTS 2017 - arthurlimantara.files.wordpress.com · REKAYASA TRANSPORTASI Copyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT 13 SUPPLY 9 10 8 12 0 12 7 21 23 0 14 11 9 19 0 5](https://reader031.vdocument.in/reader031/viewer/2022020305/5c935e4a09d3f2e3628ce1b1/html5/thumbnails/13.jpg)
REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT
13
SUPPLY
9 10 8 12 0
12 7 21 23 0
14 11 9 19 0
5 7 7 5 0
DEMAND 26.0006.000 4.000 5.000 7.000 4.000
X
Y
Z
D Dummy
6.000
7.000
8.000
5.000
A
W
B CKE
DARI
3.000
1.000
3.0005.000
3.000 4.000
4.000
3.000
![Page 14: UTS 2017 - arthurlimantara.files.wordpress.com · REKAYASA TRANSPORTASI Copyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT 13 SUPPLY 9 10 8 12 0 12 7 21 23 0 14 11 9 19 0 5](https://reader031.vdocument.in/reader031/viewer/2022020305/5c935e4a09d3f2e3628ce1b1/html5/thumbnails/14.jpg)
REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT
14
SUPPLY
9 10 8 12 0
12 7 21 23 0
14 11 9 19 0
5 7 7 5 0
DEMAND 26.0006.000 4.000 5.000 7.000 4.000
X
Y
Z
D Dummy
6.000
7.000
8.000
5.000
A
W
B CKE
DARI
3.000
1.000
5.000
3.000 4.000
4.000
6.000
![Page 15: UTS 2017 - arthurlimantara.files.wordpress.com · REKAYASA TRANSPORTASI Copyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT 13 SUPPLY 9 10 8 12 0 12 7 21 23 0 14 11 9 19 0 5](https://reader031.vdocument.in/reader031/viewer/2022020305/5c935e4a09d3f2e3628ce1b1/html5/thumbnails/15.jpg)
REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT
15
HASIL PERHITUNGANITERASI 3
Z = 6.000 (12) + 3.000 (12) + 4.000 (7) +3.000 (14) + 5.000 (9) + 1.000 (5) + 4.000(0)
Z = 228.000
![Page 16: UTS 2017 - arthurlimantara.files.wordpress.com · REKAYASA TRANSPORTASI Copyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT 13 SUPPLY 9 10 8 12 0 12 7 21 23 0 14 11 9 19 0 5](https://reader031.vdocument.in/reader031/viewer/2022020305/5c935e4a09d3f2e3628ce1b1/html5/thumbnails/16.jpg)
REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT
16
SUPPLY
9 10 8 12 0
12 7 21 23 0
14 11 9 19 0
5 7 7 5 0
DEMAND 26.0006.000 4.000 5.000 7.000 4.000
X
Y
Z
D Dummy
6.000
7.000
8.000
5.000
A
W
B CKE
DARI
4.000
5.000
2.000
5.000
1.0004.000
3.000
2.000
![Page 17: UTS 2017 - arthurlimantara.files.wordpress.com · REKAYASA TRANSPORTASI Copyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT 13 SUPPLY 9 10 8 12 0 12 7 21 23 0 14 11 9 19 0 5](https://reader031.vdocument.in/reader031/viewer/2022020305/5c935e4a09d3f2e3628ce1b1/html5/thumbnails/17.jpg)
REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT
17
HASIL PERHITUNGANITERASI 4
Z = 4.000 (9) + 2.000 (12) + 2.000 (12) +4.000 (7) + 1.000 (0) + 5.000 (9) + 1.000(0)+ 5.000 (5)
Z = 182.000
![Page 18: UTS 2017 - arthurlimantara.files.wordpress.com · REKAYASA TRANSPORTASI Copyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT 13 SUPPLY 9 10 8 12 0 12 7 21 23 0 14 11 9 19 0 5](https://reader031.vdocument.in/reader031/viewer/2022020305/5c935e4a09d3f2e3628ce1b1/html5/thumbnails/18.jpg)
18 REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT.
CONTOH SOAL
Perumahan
B = rambu
A
C
REL
V
Hitunglah:Besarnya batas kecepatan pada rambu di B?Bila diketahui:Kecepatan mobil di A=120 km/jam.Waktu PIEV AB = 0,8 detikWaktu PIEV BC = 1,0 detik
![Page 19: UTS 2017 - arthurlimantara.files.wordpress.com · REKAYASA TRANSPORTASI Copyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT 13 SUPPLY 9 10 8 12 0 12 7 21 23 0 14 11 9 19 0 5](https://reader031.vdocument.in/reader031/viewer/2022020305/5c935e4a09d3f2e3628ce1b1/html5/thumbnails/19.jpg)
19 REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT.
CONTOH SOAL
Jarak AB = 148,14 mJarak BC + pengamanan = 186,25 mJarak pengaman = 5 m.Perlambatan mobil 2 m/dt2
![Page 20: UTS 2017 - arthurlimantara.files.wordpress.com · REKAYASA TRANSPORTASI Copyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT 13 SUPPLY 9 10 8 12 0 12 7 21 23 0 14 11 9 19 0 5](https://reader031.vdocument.in/reader031/viewer/2022020305/5c935e4a09d3f2e3628ce1b1/html5/thumbnails/20.jpg)
20 REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT.
JAWABAN
B = rambu
A
C
REL
V
DE
tPIEV
tC
AD St = Vo x t
mxSt 67,268,03600
000.120
![Page 21: UTS 2017 - arthurlimantara.files.wordpress.com · REKAYASA TRANSPORTASI Copyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT 13 SUPPLY 9 10 8 12 0 12 7 21 23 0 14 11 9 19 0 5](https://reader031.vdocument.in/reader031/viewer/2022020305/5c935e4a09d3f2e3628ce1b1/html5/thumbnails/21.jpg)
21 REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT.
JAWABANJarak AB = AD + DB
148,14 = 26,67 + DBDB = 148,14 – 26,67 mDB = 121,47 m
DB St = Vo .t – ½ a t2
2221
3600
000.12047,121 xtxxt
047,12133,33t2 t
165,4
165,29
0)165,429,165)(t(
2
1
t
t
t
![Page 22: UTS 2017 - arthurlimantara.files.wordpress.com · REKAYASA TRANSPORTASI Copyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT 13 SUPPLY 9 10 8 12 0 12 7 21 23 0 14 11 9 19 0 5](https://reader031.vdocument.in/reader031/viewer/2022020305/5c935e4a09d3f2e3628ce1b1/html5/thumbnails/22.jpg)
22 REKAYASA TRANSPORTASICopyright © 2017 By. Ir. Arthur Daniel Limantara, MM, MT.
JAWABAN
DB Vt = Vo – a.t
t1= 29,165
T2= 4,165
165,2923600
000.120tV
mungkin tidak33,5833,33 tV
165,423600
000.120tV
km/jam9010
900
km/jam10
3625
m/det25
33,833,33
t
t
t
t
V
xV
V
V