warm-up date: 3/10/09 1. 4. 3. solve the system. solve the system. 2. solve by graphing. 4x – 2y =...
TRANSCRIPT
WARM-UP Date: 3/10/09
1.
4.
3. Solve the system.
Solve the system. 2. Solve by graphing.
4x – 2y = -10y = 2x + 5 {
3x + 4y = 2 5x + 9y = 1
{Solve the system.
12x + 4y = -8y = x + 2{
-3x = -2y – 37 x = 2y + 19
{
5( )
+ 20y
{ 3x + 4y = 2 5x + 9y = 1
15x-15x+
-7y = 7-7 -7
y = -1 3x + 4y = 2
3x + 4 (-1) = 2 3x – 4 = 2
+4 +4 3x = 63 3
x = 2
1. Solve the system.
Solution (1, -1)
= 10
-3( )
– 27y = -3
2. Find the solution to the systems by graphing.
12x + 4y = -8y = x + 2{
12x + 4y = -8-12x -12x
4y = -8 – 12x 4 4y = -2 – 3x
y = x + 2
Solution (-1, 2)
-3x = -2y – 37 x = 2y + 19{
-3(2y + 19) = -2y – 37 -6y – 57 = -2y – 37
+2y+2y-4y – 57 = -37
+57 +57 -4y = 20
-4 -4 y = -5
x = 2y + 19 x = 2(-5) + 19 x = 9
3. Use substitution to solve systems.
Substitute the x:
Substitute the y:
Solution: (9, -5) x, y
4. Solve by substitution. 4x – 2(2x + 5) = -10
4x – 2y = -10y = 2x + 5 {
4x – 4x – 10 0x – 10 = -10
-10 = -10
Is this a true?
= -10
YES
Infinite Solutions
Solving Word Problems with Systems
Name: Pd
Algebra 3/10/09
Word Problem Steps
1. Figure out what the question is.
2. Determine what the variables need to be.
3. Find key numbers.
4. Create Equations.
5. Solve.
Ex1: Paula went to get school supplies. If she buys 8 pencils and 5 notebooks it will cost $8.30. If she buys 12 pencils and 3 notebooks it will cost $5.70. Write a system describing the cost of a pencil, p, and notebook, n.
12p + 3n = 5.70{
p:cost of pencilsn:cost of notebooks
8p + 5n = 8.30
Ex2: Rob bought 15 concert tickets worth $322.50. Floor tickets cost $25 each while the balcony tickets cost $17.50 each. Write a system for the number of balcony seats, b and floor seats, f, purchased.
f + b = 15{
f: # of floor seatsb:# of balcony seats
25f + 17.50b = 322.50
Ex3: Micah has a total of $3.35 in dimes and quarters. If he has 14 coins, write an equation for finding the number of dimes, d, and quarters, q.
d + q = 14{
d:# of dimeq:# of quarter
0.10d + 0.25q = 3.35
Ex4: Jamie has 78 rock and country CDs in his collection. The number of country CDs he has is 7 less than 3 times the number of rock CDs he has. Write a system for finding the number of rock, r, and c, country CDs he has.
r + c = 78 {
c: # of country CDsr:# of rock CDs
c = 3r – 7
{ 7( )
Ex5: Fred went to the fruit stand to purchase oranges and bananas. He can purchase 5 oranges and 6 bananas for $2.05 or he can purchase 7 oranges and 8 bananas for $2.79. What is the cost of each orange and banana?
7R + 8B = 2.79
R: Cost of a orange
B: Cost of a banana
5R + 6B = 2.05
-5( )
-35R – 40B = -13.95+
2B = 0.40
2 2
B = 0.2
35R + 42B = 14.35
Bananas $0.20.
5R + 6B = 2.05
5R + 6(0.2) = 2.05
5R +1.2 = 2.05
B = 0.2
-1.2 -1.2
5R = 0.85
5 5
R = 0.17
Oranges $0.17
Ex5: Fred went to the fruit stand to purchase oranges and bananas. He can purchase 5 oranges and 6 bananas for $2.05 or he can purchase 7 oranges and 8 bananas for $2.79. What is the cost of each orange and banana?
-2( )
Ex6: At a small town baseball game there were 78 people. Children tickets were $2 and adult tickets were $7. If $421 was made at the game, how many adults went?
a + c = 78{
a: Number of adultsb: Number of children
7a + 2c = 421
-2a – 2c = -156 7a + 2c = 421
+
5a = 265
5 5
a = 53
53 adults
2B
B – 4
Ex7: Rachel and Bob work as part-time employees for a lawyer. Last weeks Rachel worked 4 hours less than Bob worked. Together they worked 38 hours total. How many hours did Bob and Rachel work?
R + B = 38{R: # hours Rachel worked
B: # hours Bob workedR = B – 4
+ B
– 4 = 38 + 4 +4
2B = 44 2 2
B = 22
= 38
Bob worked 22 hours.
R = B – 4
R = 22 – 4
R = 18
B = 22
Rachel worked 18 hours.
Ex7: Rachel and Bob work as part-time employees for a lawyer. Last weeks Rachel worked 4 hours less than Bob worked. Together they worked 38 hours total. How many hours did Bob and Rachel work?
8w
+ 6w
Ex8: The length of a rectangle is 4 meters less than three times its width. If the perimeter of the rectangle is 48 meters, then what is the value of the length (in meters)?
2W + 2L = 48{
L: length of a rectangle
W: width of a rectangle
L = 3w – 4
2w + 2(3w – 4) = 482w – 8
– 8 = 48 + 8 +8
8w = 56 8 8
w = 7
= 48
Width 7 meters.
L = 3(7) – 4
L = 21 – 4
L = 17
w = 7
Length is 17 m.
Ex8: The length of a rectangle is 4 meters less than three times its width. If the perimeter of the rectangle is 48 meters, then what is the value of the length (in meters)?
• Complete your practice packets to be turned in at the end of class
• If you finish early please begin your exit ticket and begin your homework.