warm up solve each proportion
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9 27. 3 5. 6 x. x 3.5. x 75. 2.4 8. x 6. 8 7. =. =. =. =. Warm Up Solve each proportion. 1. 2. x = 45. x = 20. 3. 4. x = 4. x = 2. Copy in your spiral. Essential Question: How do you find an unknown value by using indirect measurement? Spi: 706.4.1. - PowerPoint PPT PresentationTRANSCRIPT
Course 3
5-7 Indirect Measurement
Warm UpSolve each proportion.
x75
35
=1. 2.48
6x
=2.
x6
9 27
=3. 87
x3.5
=4.
x = 45 x = 20
x = 2 x = 4
Course 3
5-7 Indirect Measurement
Essential Question: How do you find an unknown value by using indirect measurement?
Spi: 706.4.1
Copy in your spiral
Course 3
5-7 Indirect Measurement
Vocabulary
indirect measurement
Sometimes, distances cannot be measured directly. One way to find such a distance is to use indirect measurement, a way of using similar figures and proportions to find a measure.
Copy in your spiral
Course 3
5-7 Indirect Measurement
Additional Example 1: Geography Application
Triangles ABC and EFG are similar.
Triangles ABC and EFG are similar. Find the length of side EG.
B
A C
3 ft
4 ft
F
E G
9 ft
x
Copy in your spiral
Course 3
5-7 Indirect Measurement
Additional Example 1 Continued
ABAC = EF
EG Set up a proportion.
Substitute 3 for AB, 4 for AC, and 9 for EF.
3x = 36 Find the cross products.
The length of side EG is 12 ft.x = 12
Triangles ABC and EFG are similar. Find the length of side EG.
34 = 9
x
3x3 = 36
3 Divide both sides by 3.
Copy in your spiral
Course 3
5-7 Indirect Measurement
Check It Out: Example 1
Triangles DEF and GHI are similar.
Triangles DEF and GHI are similar. Find the length of side HI.
2 in
E
D F
7 in
H
G I
8 in x
Course 3
5-7 Indirect Measurement
Check It Out: Example 1 Continued
DEEF = GH
HI Set up a proportion.
Substitute 2 for DE, 7 for EF, and 8 for GH.
2x = 56 Find the cross products.
The length of side HI is 28 in.
x = 28
27 = 8
x
2x2 = 56
2 Divide both sides by 2.
Triangles DEF and GHI are similar. Find the length of side HI.
Course 3
5-7 Indirect Measurement
• Indirect Measurement video
Course 3
5-7 Indirect Measurement
A 30-ft building casts a shadow that is 75 ft long. A nearby tree casts a shadow that is 35 ft long. How tall is the tree?
Additional Example 2: Problem Solving Application
11 Understand the Problem
The answer is the height of the tree.
List the important information:
• The length of the building’s shadow is 75 ft.
• The height of the building is 30 ft.
• The length of the tree’s shadow is 35 ft.
Copy in your spiral
Course 3
5-7 Indirect Measurement
Additional Example 2 Continued
Use the information to draw a diagram.22 Make a Plan
h
Draw dashed lines to form triangles. The building with its shadow and the tree with its shadow form similar right triangles.
Solve3375 feet
30 feet
35 feet
Course 3
5-7 Indirect Measurement
30 75
= h35
Solve33
Corresponding sides of similar figures are proportional.
75h = 1050 Find the cross products.
The height of the tree is 14 feet.
h = 14
75h75 = 1050
75 Divide both sides by 75.
Additional Example 2 Continued
Course 3
5-7 Indirect Measurement
Since = 2.5, the building’s shadow is
2.5 times its height. So, the tree’s shadow should also be 2.5 times its height and 2.5 of 14 is 35 feet.
44 Look Back
75 30
Additional Example 2 Continued
Course 3
5-7 Indirect Measurement
A 24-ft building casts a shadow that is 8 ft long. A nearby tree casts a shadow that is 3 ft long. How tall is the tree?
Check It Out: Example 2
11 Understand the Problem
The answer is the height of the tree.
List the important information:
• The length of the building’s shadow is 8 ft.
• The height of the building is 24 ft.
• The length of the tree’s shadow is 3 ft.
Course 3
5-7 Indirect Measurement
Use the information to draw a diagram.22 Make a Plan
h
Draw dashed lines to form triangles. The building with its shadow and the tree with its shadow form similar right triangles.
Solve33
3 feet
8 feet
24 feet
Check It Out: Example 2 Continued
Course 3
5-7 Indirect Measurement
24 8
= h3
Solve33
Corresponding sides of similar figures are proportional.
72 = 8h Find the cross products.
The height of the tree is 9 feet.
9 = h
728 = 8h
8 Divide both sides by 8.
Check It Out: Example 2 Continued
Course 3
5-7 Indirect Measurement
Since = , the building’s shadow is
times its height. So, the tree’s
shadow should also be times its
height and of 9 is 3 feet.
44 Look Back
8 24
1 3
1 3
1 3
1 3
Check It Out: Example 2 Continued
Course 3
5-7 Indirect Measurement
1. Vilma wants to know how wide the river near her house is. She drew a diagram and labeled it with her measurements. How wide is the river?
2. A yardstick casts a 2-ft shadow. At the same
time, a tree casts a shadow that is 6 ft long. How
tall is the tree?
Lesson Quiz
7.98 m
9 ft
w
7 m
5 m
5.7 m
Course 3
5-7 Indirect Measurement
Course 3
5-7 Indirect Measurement
Tree = 3.3 m
Park to House = 15 m. You need to add the missing value (10) and the distance from red-light to park (5).
Course 3
5-7 Indirect Measurement
200 ft 21 ft
37.5 m 13.5 m
4.2ft
103.3 ft
Course 3
5-7 Indirect Measurement
• There are 2 ways to solve #15. Either turn everything into inches first, then go back to feet or plug in the answers in the proportion and see which fractions are closest to each other.
Course 3
5-7 Indirect Measurement
• Use Indirect Measurement
• MAPS In the figure, ΔGHK ΔJIK. Find ∼the distance across the forest.
48 mi
Course 3
5-7 Indirect Measurement
Homework: • Worksheet practice 11-6