water tank design calc
TRANSCRIPT
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7/28/2019 Water Tank Design Calc
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Tank Piping Data :
Inside Dia = 2.3 m
EL of 50 NB overflow pipe = (+) 2.4 mMax water level considered as = (+) 2.4 m
Free board upto bottom of roof assumed = 0.4 m
RCC roof thickness = 0.15 m
i.e. (+) 2.95 m
EL of Top of Roof considered = (+) 3.10 m
Level of float pipe (BOP) (INLET) = (+) 2.20 m
Min. clearance reqd. from roof bottom = 0.4 m
Roof thickness = 0.15 m
i.e. (+) 2.75 m
Thus, Roof Top EL taken at (+) 3.10 m is OK
Capacity:
Finished bottom of tank EL = (+) 0.500 m
Max water level EL = (+) 2.40 m
Max water height (2.40 0.500) = 1.9 m
Gross capacity = 3.14/4 x (2.3)2x 1.9 = 7.9 m
2
Roof Slab: (150 mm thick)
Loading:-
DL Self wt of slab:(0.150X2.5) = 0.375 T/m2
50 thk. avg. screed conc.
(0.05X2.5) = 0.125 T/m2
0.500 T/m2
LL LL = 0.15 T/m2
Dust Load = 0.1 T/m2
0.25 T/m2
Total Load (0.50 + 0.25) = 0.75 T/m2
Circular Slab simply supported
Span (d) = (2.5 + 0.200) = 2.700 m
Moment at span / m =( wd2 /16) = 0.75X(2.7)2 = 0.34 T-m
16
Designing by Working Stress method, with M25 & Fe500
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Steel stress allowed = 1900 Kg/cm2
d reqd. = 0.34 X 105
= 5.22cm = 52.2 mm
12.44 X 100
Provide overall depth = 150 mm OK
Def= (150 25 4) = 121 mm = 12.1 cm
Ast Reqd = Moment = 0.34X105
= 1.66 cm2per meter
( stX j X d) 1900X0.89X12.1
Provide 8 Y @ 200mm c/c (2.51 cm2) at top bottom (bothways)
Shear:
= 0.506 T/m
X 2.7
100As = 100X2.51 = 0.20%
bd 100X12.1
Allowable Shear Stress Tc = 3.3 KN/mm2
Allowable Shear Force / m 3.3 X 100 X 12.1 = 3.9 T > 0.51 T OK
1000
2900 RL TOC 366.95 M
2300
2.325
RL (+) 364.475 M
FGL RL (+) 364.0 M
4000
Design of Wall: (200 Thk)
H2
= 2.3252
= 11.75
Dt 2.3 X .200
Fixed base, Free Top
Referring Table 9 of IS 3370 (part IV)
Taking value of H2/ Dt as 16 to be on the conservative side, co-efficients comes to be +0.641
Max Tension / m = (+) 0.641 X 1 X 2.325 X 2.3/2 = 1.64 T at 0.6H from top
(Horizontally)
Shear / m = /4 X (2.7)2
X 0.75
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Alternative Max hoop stress = pr / t = 2.325 X 1.15 = 13.36 T/m2
0.2
Max hoop tension / m = (13.36 X 0.200 X 1.00) = 2.67 T
From Table 10 of IS 3370 (Part IV)
Vertical Bm / m = (+) 0.0019 X 1.0 X (2.325)3
= 0.02 T-m
(Tension outside at 0.8H from top)
Vertical Bm / m = (-) 0.0079 X 1.0 X (2.325)3
= 0.09 T-m
(Tension Inside)
Now,
m = 280 = 11
3 X 8.50
For st = 1900 Kg/cm2
Value of k = 0.38
J = 0.87
Vertical reinforcement
d = (200 25 - 6) = 169 mm
Ast Reqd = 0.14X105
= 0.5 cm2
per meter
0.87X16.9X1900
Provide 12 Y @ 200mm c/c (5.65 cm2) on each face.
Check for Cracking:
For M25 RCC grade, R = M/bd2
= 3.11
With d1 / d = 169/200 = 0.845
Therefore, d reqd. = 0.14X105
= 6.70 cm = 67.0 mm
3.11X100
Thus provided overall depth considered as 200 mm is OK
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Horizontal Reinforcement:
Providing 10 Y @ 200 c/c on both face
Total reinforcement / m = 2 r = 2 X 3.14 X 1.25 = 7.86
Tensile stress in concrete due to hoop stress = Max Hoop Tension per meter X 103
Provided overall depth(cm) X 100 + (m -1) X Total Hori. reinfr / meter(cm2)
= = 1.38 kg / cm2
20.0 X 100 + (11 1) X 7.86 < 13.0 kg / cm2
Hence OK.
Tensile stress in steel = 2.86 X 103
= 363.86 kg / cm2 < 1500 kg / cm2
Hence OK.
7.86
200 mm thk
10 @ 200 c/c
12 mm @ 200c/c
12 mm @ 200 c/c
Extended some thickness & reinforcement upto the Base raft of foundation.
Tank Bottom Slab (200 mm thck)
Load on slab:
Max water load = 2.325 T / m2
s/w of slab (200Thk) = 0.200X2.5 = 0.5 T / m2
25thk finish = 0.025 X 2.4 = 0.06 T / m2
W = 2.885 T / m2
Circular Slab:
Circle dia (h) = 2.500 m
M = wh (1 + v) (3+ v) =dist of point considered from slab center
64 radius of slab
= wh2
(1.2) (3.2) X 12
= 1.250 / 1.250 = 1.00
64
= - wh2
2 v = poison's ratio = 0.20
64
= ( - ) wh2
32
M = 2.89 X 2.502
= 0.56 T-m
32 D = (200 25 10 5) = 160 mm
Ast Reqd = 0.56 X 105
= 2.12 cm2
0.87 X 16.0 X 1900
Provide 12 Y @ 200mm c/c (5.65 cm2) top & bottom bothways.
2.86 X 103
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Check for Cracking:
I = 100 X 203
+ (11 - 1 ) 5.65 X 2 X (2.68)^2
12
= 67478.3 cm4
Z = 67478.3 = 7711.80 cm3
8.75
Max tensile stress in concrete = 0.56 X 105
= 7.26 Kg/m2
< 18.0 kg / m2
Hence OK.
7711.8
Foundation Raft: (250 thk)
Wt of water: X 2.32
X 1.925 X 1 = 8 T
Wt of roof: X 2.72
X 0.75 = 4.29 T
Wt of tank bottom slab: X 2.32
X 0.5 = 2.07 T
Circular wall: X 2.5X 3.675 X .200 X 2.5 = 14.43 T
Wt of PCC below tank: X 2.32X 0.075 X 2.4 = 0.75 T
Wt of sand fill : X 2.32X 1.025 X 2.0 = 8.51 T
Wt of backfill in tank portion: X (4.002 2.7
2) X (0.75) X 1.8 = 9.23 T
Wt of raft : X 4.002X 0.250 X 2.5 = 7.85 T
Total 55.13 T
Gross Base Pressure = 55.13 = 4.38 T / m2
X 4.002
Provided 12 Y @ 200 c/c top & bottom bothways.
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