g6gps2016.files.wordpress.com€¦ · web view · 2017-06-06semester 2 grade 6 revision pack....

semester 2 grade 6 revision packAnswer Section

MULTIPLE CHOICE

1. ANS: B PTS: 1 NAT: NT.CCSS.MTH.10.6.6.EE.1DOK: DOK 2

2. ANS: BIn an exponential expression, the base is the number being multiplied and the exponent is the number of times it is being multiplied. In this case, the number being multiplied is 5 and it is being multiplied 6 times. So,

.

FeedbackA Compare the number of factors in the given expression with the exponent in your

answer.B That’s correct!C Remember the difference between the base and the exponent.D Compare the number of factors in the given expression with the exponent in your

answer.

PTS: 1 NAT: NT.CCSS.MTH.10.6.6.EE.1 KEY: exponentsDOK: DOK 1

3. ANS: D PTS: 1 NAT: NT.CCSS.MTH.10.6.6.EE.2DOK: DOK 1

4. ANS: D PTS: 1 REF: 9470f521-9631-11dd-8a40-001185f11039OBJ: Evaluating Algebraic Expressions with Two Variables NAT: NT.CCSS.MTH.10.6.6.EE.2LOC: MTH.C.10.05.02.02.013 TOP: Variables and Algebraic ExpressionsKEY: algebraic expression | evaluate | substitute DOK: DOK 2

5. ANS: C PTS: 1 NAT: NT.CCSS.MTH.10.6.6.EE.2DOK: DOK 2


7. ANS: B PTS: 1 NAT: NT.CCSS.MTH.10.6.6.EE.2.aDOK: DOK 2

8. ANS: C PTS: 1 REF: 8ef70539-9631-11dd-8a40-001185f11039OBJ: Translating Words into Math NAT: NT.CCSS.MTH.10.6.6.EE.2.aLOC: MTH.C.10.05.02.02.019 TOP: Translating Between Words and MathKEY: expression | algebraic expression DOK: DOK 2


10. ANS: B PTS: 1 NAT: NT.CCSS.MTH.10.6.6.EE.2.cDOK: DOK 2

11. ANS: ASubtraction can be expressed by the statement “less than.” So, can be represented by “ less than 7.”

FeedbackA That’s correct!B Think about phrases that can represent the operation in the expression.

C Think about phrases that can represent the operation in the expression.D Think about which term is being subtracted from the other.

PTS: 1 NAT: NT.CCSS.MTH.10.6.6.EE.2.aKEY: writing expressions using letters and numbers DOK: DOK 1

12. ANS: DMarcus has apples, so Judy has 5 times apples. The phrase “times” indicates multiplication, so Judy has

apples.

FeedbackA Think about what operation “times” represents.B Think about what operation “times” represents.C Think about what operation “times” represents.D That’s correct!

PTS: 1 NAT: NT.CCSS.MTH.10.6.6.EE.2.a | NT.CCSS.MTH.10.K-12.MP.4KEY: writing expressions using letters and numbers DOK: DOK 1

13. ANS: B

The expression is the division of by 12.

FeedbackA This expression is a product.B That’s correct!C This expression is a sum.D This expression is a difference.

PTS: 1 NAT: NT.CCSS.MTH.10.6.6.EE.2.b KEY: quotientDOK: DOK 1

14. ANS: CAfter substituting 3 for in the expression , find .

Now, multiply by 6.

Finally, subtract 2.

FeedbackA Remember that evaluating exponents should be done before multiplication.B Remember that multiplication should be done before subtraction.C That’s correct!D Remember that evaluating exponents should be done before multiplication and

subtraction.

PTS: 1 NAT: NT.CCSS.MTH.10.6.6.EE.2.cKEY: evaluating expressions | order of operations DOK: DOK 1

15. ANS: A

First, substitute 4 for in the expression .

Then, evaluate the expression following the order of operations. First, find .

Now, multiply and divide from left to right.

Finally, subtract.

So, the value of at is .

FeedbackA That’s correct!B Remember that evaluating exponents should be done before multiplication. C Remember that evaluating exponents should be done before multiplication. D Remember that multiplication should be done before subtraction.


16. ANS: D

First, substitute 5 for and 4 for in the expression .

Then, evaluate the expression following the order of operations. Multiply from left to right.

So, the value of at and is 10. Thus, the area of the triangle is 10.

FeedbackA

2 is equal to , not .

B

2.5 is equal to , not .C You added the base and height rather than multiplying.D That’s correct!

PTS: 1 NAT: NT.CCSS.MTH.10.6.6.EE.2.cKEY: evaluating expressions | area of a triangle | order of operationsDOK: DOK 1


18. ANS: A PTS: 1 NAT: NT.CCSS.MTH.10.6.6.EE.3DOK: DOK 1










28. ANS: A PTS: 1 REF: 9405d1ab-9631-11dd-8a40-001185f11039OBJ: Checking Solutions of Equations with Two Variables NAT: NT.CCSS.MTH.10.6.6.EE.9LOC: MTH.C.10.07.01.011 TOP: Graphing FunctionsKEY: equation | two variables DOK: DOK 2







35. ANS: B PTS: 1NAT: NT.CCSS.MTH.10.6.6.EE.2.c | NT.CCSS.MTH.10.6.6.G.1

DOK: DOK 136. ANS: D PTS: 1

NAT: NT.CCSS.MTH.10.6.6.EE.2.c | NT.CCSS.MTH.10.6.6.G.1DOK: DOK 1

37. ANS: A PTS: 1NAT: NT.CCSS.MTH.10.6.6.EE.2.c | NT.CCSS.MTH.10.6.6.G.1DOK: DOK 2

38. ANS: B PTS: 1NAT: NT.CCSS.MTH.10.6.6.EE.2.c | NT.CCSS.MTH.10.6.6.G.1DOK: DOK 2


40. ANS: B PTS: 1 REF: 92bf2d5d-9631-11dd-8a40-001185f11039OBJ: Application NAT: NT.CCSS.MTH.10.6.6.G.1LOC: MTH.C.12.12.02.001 | MTH.C.12.12.02.002TOP: Area of Rectangles and Parallelograms DOK: DOK 2

41. ANS: A

The area A of a triangle is given by the formula , where b is the length of the base and h is the height. The base of the given triangle is . The height of this triangle is

. So, the area is .

FeedbackA That’s correct!B The height of the triangle is not 10 mm.C The base of the triangle is not 12 mm. D The height of the triangle is not 10 mm and the base is not 12 mm.

PTS: 1 NAT: NT.CCSS.MTH.10.6.6.G.1 KEY: area | polygon | triangleDOK: DOK 2

42. ANS: B PTS: 1 REF: MLC20891NAT: NT.CCSS.MTH.10.6.6.G.2 | NT.CCSS.MTH.10.7.7.G.6 TOP: Volume of Rectangular PrismsKEY: volume | rectangular prism DOK: DOK 1

43. ANS: D

FeedbackA Do not add the dimensions of the prism. Recall that .B To multiply mixed numbers, first rewrite the mixed numbers as improper fractions.C You found the product of the length and height of the prism. Recall that .D That’s correct!

PTS: 1 NAT: NT.CCSS.MTH.10.6.6.G.2 KEY: volume | right rectangular prismDOK: DOK 1

44. ANS: C PTS: 1 REF: MMT10636 NAT: NT.CCSS.MTH.10.6.6.G.4TOP: Surface Area of a Prism KEY: prism | net | solid | pyramidDOK: DOK 1

45. ANS: D PTS: 1 NAT: NT.CCSS.MTH.10.6.6.NS.6KEY: rational number | coordinate plane DOK: DOK 1

46. ANS: B PTS: 1 NAT: NT.CCSS.MTH.10.6.6.NS.6.bDOK: DOK 1

47. ANS: D PTS: 1 NAT: NT.CCSS.MTH.10.6.6.NS.6.bDOK: DOK 1

48. ANS: C PTS: 1 REF: 90d8e4a7-6ab2-11e0-9c90-001185f0d2eaOBJ: Drawing Polygons in the Coordinate PlaneNAT: NT.CCSS.MTH.10.6.6.NS.6.b | NT.CCSS.MTH.10.6.6.NS.6.c | NT.CCSS.MTH.10.6.6.NS.8 | NT.CCSS.MTH.10.6.6.G.3 TOP: Polygons in the Coordinate PlaneKEY: coordinate geometry | graph DOK: DOK 2


50. ANS: A PTS: 1 NAT: NT.CCSS.MTH.10.6.6.NS.6.cKEY: coordinate plane | point DOK: DOK 1



53. ANS: BThe point is halfway between and .

0 1 2 3 4 50–1–2–3–4–5

–3.5

FeedbackA Notice that the distance between each tick mark is 0.5 unit.

B That’s correct!C Notice the point is to the left of 0 on the number line.D Notice the point is to the left of 0 on the number line.

PTS: 1 NAT: NT.CCSS.MTH.10.6.6.NS.6.c KEY: rational numbers | number linesDOK: DOK 1

54. ANS: B PTS: 1 NAT: NT.CCSS.MTH.10.6.6.RP.3.aDOK: DOK 2

55. ANS: B PTS: 1 NAT: NT.CCSS.MTH.10.6.6.RP.3.aDOK: DOK 2

56. ANS: B PTS: 1 REF: 96c2a28f-9631-11dd-8a40-001185f11039OBJ: Using Proportions to Find Percents of Numbers NAT: NT.CCSS.MTH.10.6.6.RP.3.cLOC: MTH.C.09.05.005 TOP: Percent of a NumberKEY: percent | multiplication DOK: DOK 1

57. ANS: D PTS: 1 NAT: NT.CCSS.MTH.10.6.6.RP.3.cDOK: DOK 2

58. ANS: C PTS: 1 REF: 91380215-9631-11dd-8a40-001185f11039OBJ: Finding DiscountsNAT: NT.CCSS.MTH.10.6.6.RP.3.c | NT.CCSS.MTH.10.7.7.EE.3LOC: MTH.C.09.05.04.001 TOP: Applying PercentsKEY: discount DOK: DOK 2

59. ANS: CTo find the amount of the bill, first rewrite the percent as a fraction with denominator 100.

Use the fact that percent times the whole equals the part. Write an equation using for the cost of the bill,

.Solve for .

Thus, the bill is $17.00.

FeedbackA Change the percent to a fraction or decimal before calculating the bill.B The percent of the tip times the bill gives the amount of the tip.C That’s correct!D Change the percent to a fraction or decimal before calculating the bill.

PTS: 1 NAT: NT.CCSS.MTH.10.6.6.RP.3.c | NT.CCSS.MTH.10.6.6.RP.3KEY: percent | tip on a bill DOK: DOK 1

60. ANS: C PTS: 1 REF: 91380215-9631-11dd-8a40-001185f11039OBJ: Finding DiscountsNAT: NT.CCSS.MTH.10.6.6.RP.3.c | NT.CCSS.MTH.10.7.7.EE.3LOC: MTH.C.09.05.04.001 TOP: Applying PercentsKEY: discount DOK: DOK 2

61. ANS: B

To find 5% of 200, first rewrite 5% as a fraction with denominator 100.

Now multiply this rate and 200, . So, 5% of 200 is 10.

FeedbackA Multiply the amount by the percent instead of dividing the percent by the amount.B That’s correct!C Multiply by the percent instead of dividing the amount by the percent.D Change the percent to a fraction or decimal before multiplying.

PTS: 1 NAT: NT.CCSS.MTH.10.6.6.RP.3.c | NT.CCSS.MTH.10.6.6.RP.3KEY: percent DOK: DOK 1

62. ANS: CTo find 120% of 50, first rewrite 120% as a fraction with denominator 100.

Now multiply this rate and 50, . So, 120% of 50 is 60.

FeedbackA Multiply by the percent instead of dividing.B Double check how you converted the percent into a fraction or decimal.C That’s correct!D Change the percent to a fraction or decimal before multiplying.


63. ANS: CTo find the whole, first rewrite 56.25% as a fraction with denominator 100.

Use the fact that percent times the whole equals the part. Write an equation using for the missing number,

.Solve for .

So, 56.25% of 300 is 168.75.

FeedbackA Change the percent to a fraction or decimal before calculating the whole.B Change the percent to a fraction or decimal before calculating the whole.C That’s correct!D Use the fact that percent times the whole equals the part.


64. ANS: C PTS: 1NAT: NT.CCSS.MTH.10.7.7.EE.3 | NT.CCSS.MTH.10.6.6.NS.7DOK: DOK 2

65. ANS: C PTS: 1 REF: 8e7d6c7f-9631-11dd-8a40-001185f11039OBJ: Writing Numbers in Exponential Form NAT: NT.CCSS.MTH.10.6.6.EE.1LOC: MTH.C.10.05.03.01.005 TOP: Exponents KEY: exponent | exponential formDOK: DOK 1




69. ANS: B PTS: 1 NAT: NT.CCSS.MTH.10.6.6.EE.1KEY: compare | exponents DOK: DOK 2

70. ANS: AFirst, expand both exponential terms. When expanding , the base is 3 and it is being multiplied 2 times, so

. In the expression , the base is 3 and it is being multiplied 5 times, so . So, multiplying the two expressions together results in

.

FeedbackA That’s correct!B Do not multiply the bases or the exponents.C Do not multiply the exponents.D Do not multiply the bases.

PTS: 1 NAT: NT.CCSS.MTH.10.6.6.EE.1KEY: exponents | expanding exponential expressions DOK: DOK 1



73. ANS: A PTS: 1 NAT: NT.CCSS.MTH.10.6.6.EE.2.aDOK: DOK 2

74. ANS: A PTS: 1 NAT: NT.CCSS.MTH.10.6.6.EE.2.aDOK: DOK 2


76. ANS: D PTS: 1 NAT: NT.CCSS.MTH.10.6.6.EE.2.aDOK: DOK 2

77. ANS: B PTS: 1 NAT: NT.CCSS.MTH.10.6.6.EE.2.bDOK: DOK 2

78. ANS: D PTS: 1 NAT: NT.CCSS.MTH.10.6.6.EE.2.cDOK: DOK 1

79. ANS: D PTS: 1 NAT: NT.CCSS.MTH.10.6.6.EE.2.cDOK: DOK 2

80. ANS: BThe phrase “more than” indicates addition. So “ more than 8” is the sum of 8 and , which is equivalent to the expression .

FeedbackA Think about what operation “more than” represents.B That’s correct!C Think about what operation “more than” represents.D Think about what operation “more than” represents.

PTS: 1 NAT: NT.CCSS.MTH.10.6.6.EE.2.aKEY: writing expressions with letters and numbers DOK: DOK 1

81. ANS: A

First, substitute 4 for in the expression .

Then, evaluate the expression following the order of operations. First, find .

Now, multiply and divide from left to right.

Finally, subtract.

So, the value of at is .

FeedbackA That’s correct!B Remember that evaluating exponents should be done before multiplication. C Remember that evaluating exponents should be done before multiplication. D Remember that multiplication should be done before subtraction.



83. ANS: C PTS: 1 REF: MLC10052NAT: NT.CCSS.MTH.10.6.6.EE.5 | NT.CCSS.MTH.10.6.6.EE.7 | NT.CCSS.MTH.10.8.8.EE.7

TOP: Equations and Mental Math KEY: whole | divide | multiply | solve | equationDOK: DOK 1



86. ANS: D PTS: 1 NAT: NT.CCSS.MTH.10.6.6.EE.6KEY: write expressions DOK: DOK 2

87. ANS: BThe phrase “less than” indicates subtraction is used. So, 4 less than a number is represented by the expression .

FeedbackA The expression for the value of should be in terms of .B That’s correct!C This expression represents the value of .D This expression represents the value of as 4 more than .

PTS: 1 NAT: NT.CCSS.MTH.10.6.6.EE.6KEY: writing expressions | define variables DOK: DOK 1

88. ANS: BFirst solve .

Now determine which equation also has 7 as the solution.

Substitute 7 for in each equation and determine if the result is a true statement.

Since 7 is a solution of , has the same solution as the equation .

FeedbackA The solution of this equation is 2, which is not the same as the solution of .B That’s correct!C The solution of this equation is 5, which is not the same as the solution of .D The solution of this equation is 8, which is not the same as the solution of .

PTS: 1 NAT: NT.CCSS.MTH.10.6.6.EE.7 | NT.CCSS.MTH.10.6.6.EE.5KEY: solving equations DOK: DOK 1

89. ANS: AThe total number of shirts in the drawer is the number of blue shirts plus the number of green shirts. The total number of shirts in the drawer is equal to 11. So, .

FeedbackA That’s correct!B The total number of shirts is not the product of the number of green and blue shirts.C The total number of shirts is not the number of green shirts subtracted from the number

of blue shirts. D

The total number of shirts is not of the number of green shirts.

PTS: 1 NAT: NT.CCSS.MTH.10.6.6.EE.7 KEY: solving equationsDOK: DOK 1

90. ANS: D PTS: 1 NAT: NT.CCSS.MTH.10.6.6.NS.6.cKEY: coordinate plane | point DOK: DOK 1

91. ANS: BThe point is halfway between and .

0 1 2 3 4 50–1–2–3–4–5

–3.5

FeedbackA Notice that the distance between each tick mark is 0.5 unit.B That’s correct!C Notice the point is to the left of 0 on the number line.D Notice the point is to the left of 0 on the number line.

PTS: 1 NAT: NT.CCSS.MTH.10.6.6.NS.6.c KEY: rational numbers | number linesDOK: DOK 1



94. ANS: C PTS: 1 REF: 8efbc9f5-9631-11dd-8a40-001185f11039OBJ: Writing an ExpressionNAT: NT.CCSS.MTH.10.6.6.EE.2 | NT.CCSS.MTH.10.6.6.EE.6 | NT.CCSS.MTH.10.6.6.EE.9LOC: MTH.C.10.05.02.02.019 TOP: Translating Between Tables and ExpressionsDOK: DOK 1

95. ANS: BThe balance of the savings account starts at and drops to after the first week. Since money is being withdrawn at a constant rate, the balance is decreasing by every week. Since Peter finds the balance based on the number of weeks, the balance depends on the number of weeks money is being withdrawn. So, the independent variable is and the dependent variable is .

FeedbackA Notice that the balance decreases each week.B That’s correct!C The balance is dependent on the time passed.

D The balance is dependent on the time passed.

PTS: 1 NAT: NT.CCSS.MTH.10.6.6.EE.9KEY: independent variable | dependent variable | analyzing tablesDOK: DOK 1


97. ANS: D PTS: 1NAT: NT.CCSS.MTH.10.6.6.EE.2.c | NT.CCSS.MTH.10.6.6.G.1DOK: DOK 1

98. ANS: B

The area A of a rhombus is given by the formula , where is the length of one diagonal and is the length of the other diagonal. For the given rhombus, = 14 cm and = 24 cm. So, the area of the rhombus is 168 cm2.

FeedbackA The area of a rhombus is one-half the product of the lengths of the diagonals.B That’s correct!C

You did not include a factor of when finding the area.D

You included a factor of 2, not , when finding the area.

PTS: 1 NAT: NT.CCSS.MTH.10.6.6.G.1 KEY: area | rhombusDOK: DOK 1

99. ANS: C

The length of the brick is . So, cubes can fit along the length of the brick.

FeedbackA This is the number of cubes that can fit along the width. B This is the number of cubes that can fit along the height. C That’s correct!D This is the total number of cubes that can fit in the brick.

PTS: 1 NAT: NT.CCSS.MTH.10.6.6.G.2 KEY: right rectangular prismDOK: DOK 1

100. ANS: DThe area of the rectangles with side lengths 4.5 ft and 2 ft is .The area of the rectangles with side lengths 4.5 ft and 3 ft is .The area of the rectangles with side lengths 3 ft and 2 ft is .

Since there are two rectangles of each size, multiply each area by 2. So, the total surface area of the figure is

.

FeedbackA The surface area is not the product of the dimensions.B Don’t forget that there are two faces each with the same dimensions.C Don’t forget the combined area of the faces with dimensions 4.5 ft by 3 ft.D That’s correct!

PTS: 1 NAT: NT.CCSS.MTH.10.6.6.G.4 | NT.CCSS.MTH.10.K-12.MP.4KEY: rectangular prism | surface area DOK: DOK 1

SHORT ANSWER

1. ANS:729

PTS: 1 NAT: NT.CCSS.MTH.10.6.6.EE.1 DOK: DOK 12. ANS:

PTS: 1 NAT: NT.CCSS.MTH.10.6.6.EE.2 KEY: write expressionsDOK: DOK 2

3. ANS:88.43

PTS: 1 NAT: NT.CCSS.MTH.10.6.6.EE.2.c DOK: DOK 24. ANS:

a. There are lions.b. There are bears. ( is also acceptable.)

Rubrica. 1 pointb. 1 point

PTS: 2 NAT: NT.CCSS.MTH.10.6.6.EE.2.a | NT.CCSS.MTH.10.K-12.MP.4KEY: writing expressions using letters and numbers DOK: DOK 2

5. ANS:

PTS: 1 REF: 9437bc51-9631-11dd-8a40-001185f11039OBJ: Writing Equations from Function Tables NAT: NT.CCSS.MTH.10.6.6.EE.9LOC: MTH.C.10.07.01.01.006 TOP: Tables and FunctionsKEY: equation | function table DOK: DOK 1

6. ANS:

PTS: 1 NAT: NT.CCSS.MTH.10.6.6.EE.2.c | NT.CCSS.MTH.10.6.6.G.1

DOK: DOK 27. ANS:

Rubric1 point for answer; 1 point for work using the formula

PTS: 2 NAT: NT.CCSS.MTH.10.6.6.G.2 KEY: volume | right rectangular prismDOK: DOK 1

8. ANS:Quadrant II

PTS: 1 NAT: NT.CCSS.MTH.10.6.6.NS.6.b DOK: DOK 19. ANS:

PTS: 1 NAT: NT.CCSS.MTH.10.6.6.NS.6.c KEY: coordinate plane | pointDOK: DOK 1

10. ANS:


11. ANS:Answers could include any two of the following (the order in which y and 85 appear in each phrase is important):

y subtracted from 8585 minus ythe difference of 85 and yy less than 85take away y from 85

PTS: 1 REF: 8f2b794d-9631-11dd-8a40-001185f11039NAT: NT.CCSS.MTH.10.6.6.EE.2 LOC: MTH.C.10.05.02.02.020TOP: Translating Between Words and Math KEY: expression | algebraic expressionDOK: DOK 1

12. ANS:


x-axis

PTS: 1 REF: M1.11.EN.CTA.39NAT: NT.CCSS.MTH.10.6.6.NS.6.b | NT.CCSS.MTH.10.6.6.NS.6.cKEY: graphing coordinates | quadrants DOK: DOK 1

14. ANS:Quadrant I

PTS: 1 REF: M1.11.EN.CTA.40NAT: NT.CCSS.MTH.10.6.6.NS.6.b | NT.CCSS.MTH.10.6.6.NS.6.cKEY: graphing coordinates | quadrants DOK: DOK 1

15. ANS:


16. ANS:

; 0


45 cm

PTS: 1 NAT: NT.CCSS.MTH.10.6.6.G.1 DOK: DOK 218. ANS:


22

PTS: 1 NAT: NT.CCSS.MTH.10.6.6.EE.2 | NT.CCSS.MTH.10.6.6.EE.2.cDOK: DOK 2

20. ANS: and


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