what are the odds notes

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What are the Odds??? The odds of a successful outcome of an event is the ratio of the probability of its success to the probability of its failure. Odds = P(s) P(f) Probability is a ratio of the desired to total possible The “odds” is the ratio of probability of success to probability of failures.

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Calculating odds of success/failure

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Page 1: What are the odds notes

What are the Odds???The odds of a successful outcome of an event is the ratio of the probability of its success to the probability of its failure.

Odds = P(s) P(f)

Probability is a ratio of the desired to total possible

The “odds” is the ratio of probability of success to probability of failures.

Page 2: What are the odds notes

What are the Odds???A game contains 24 cards that say “Move Ahead One Space” and 10 cards that say “Move Back One Space”. A card may be chosen randomly from anywhere in the deck of 34 cards. What is the probability of drawing a “Move Ahead” card?P(move ahead) = = (simplify)

P(move ahead) =

Page 3: What are the odds notes

What are the Odds???A game contains 24 cards that say “Move Ahead One Space” and 10 cards that say “Move Back One Space”. A card may be chosen randomly from anywhere in the deck of 34 cards. What are the odds that a player will move his or her token ahead one space on any given turn?P(success) = = (remember, we don’t divide fractions)

P(success) = • = (the 34’s cancel, now simplify)

P(success) =

See example 5 on Pg. 854 for an additional example.

Page 4: What are the odds notes

What are the Odds???Given a bag of 3 red chips, 5 blue chips, & 2 green chips, what are the odds of selecting two chips without replacement:a. Drawing 1 green & 1 blue chance of 1st green & 2nd blue = • ( ) = = so chance of success, which means chance of failure is

Odds of success/failure is

b. Drawing 2 blue chipschance of 1st blue & second blue = • = = chance of success = , which means chance of failure is Odds of success/failure is

Page 5: What are the odds notes

What are the Odds???Four male and 5 female students have been selected as equal qualifiers for 6 college scholarships. If the awarded recipients are to be chosen at random, what are the odds that three will be male and three will be female?First determine the total number of possible groups:

C(5, 3) number of groups of females = 10 C(4, 3) number of groups of males = 4

C(5, 3) • C(4, 3) = 4 • 10 = 40 possible groups of studentsTotal number of groups of 6 students - C(9, 6) = = 84The number of groups that do not have 3 males and 3 females is 84 – 40 = 44. Finally, determine the odds of 3 males & 3 males of all options:

P(s) = = • = = See example 6 on Pg. 855 for an additional example.

Page 6: What are the odds notes

What are the Odds???You have a batting average of 0.285. What are the odds of hitting the ball on your next at bat?

chance of success = .285, chance of failure = .715

Odds of hitting the ball on the next at bat: = = (simplified ÷ top and bottom by 0.005)