x = 0 + - phase velocity: the velocity of a point of constant phase on the traveling waveform. think...
TRANSCRIPT
x = 0 +-
π£π=ππ₯ππ‘
>0 π=ππ£π
=1π=
2ππ
π=2π π =2ππ£π
π=π½π£π
π¦=cosππ (π₯ )=2ππ₯π
=Ξ² π₯
Think of a train carrying sinusoids. Each flatcar carries one sinusoid having length l.
If the train is not moving, the phase at any point x is:
If the train is moving:
π½=2ππ
x = 0 +-
π¦=cosππ (π₯ )|π‘=0=π½ π₯
Consider the position x = 0.
At time , the point on the train passing x = 0 will be the point on the train which was at when t = 0.
The phase associated with that point is :π (0 , οΏ½ΜοΏ½ )=π ( οΏ½ΜοΏ½ , 0 )=2π (βπ£π οΏ½ΜοΏ½π )=β π½π£ππ‘=βππ‘
For π₯ β 0 ,π (π₯ , π‘ )=π½ π₯βππ‘
π½=2ππ
π=π½π£π
οΏ½ΜοΏ½=βπ£π οΏ½ΜοΏ½
π¦=cos (π½ π₯βππ‘ )
π¦=cos (βποΏ½ΜοΏ½ )
x = 0 +-
π (π₯ )|π‘=0=π½ π₯π½=2ππ π=π½π£π π¦=cos (π½ π₯βππ‘ )
Our choice for the position of the origin, x = 0, was totally arbitrary!!
π¦=sin ( π½ π₯βππ‘ )=βsin (ππ‘βπ½ π₯ )
π¦=β cos (π½ π₯βππ‘ )=β cos (ππ‘βπ½ π₯ )
π¦=β sin (π½ π₯βππ‘ )=sin (ππ‘βπ½ π₯ )
ΒΏcos (ππ‘β π½ π₯ )
Any of these forms are valid for expressing a traveling wave moving in the positive x direction!
For traveling waves moving in the negative x direction, the sign on one of the terms of the phase expression must be reversed:
π¦=sin ( π½ π₯+ππ‘ )=βsin (βππ‘β π½ π₯ )
π¦=β cos (π½ π₯+ππ‘ )=βcos (βππ‘β π½ π₯ )
π¦=β sin (π½ π₯+ππ‘ )=sin (βππ‘β π½ π₯ )
π¦=cos (π½ π₯+ππ‘ )ΒΏcos (βπ π‘βπ½ π₯ )
The Cowboy WayA real cowboy uses complex exponentials. The preferred form for voltage waveforms is:
~π πΉ=π½+ΒΏπ π(π π‘β π½π₯ )ΒΏ
~π π =π½βπ π (π π‘+π½ π₯ )
β¦ for traveling waves moving in the positive x direction.
β¦ for traveling waves moving in the negative x direction.
Complex constants representing the magnitudes and reference phases of the traveling waves.
S
Train Station
x = xs
Dxs DS = -2Dxs
You
How many cars are in the station at any time?
π π=ππ
What do you see, standing at the station entrance?
You see each car coming out exactly nS (the fractional part of NS) cars ahead of each car going in.
The phase lead of the sinusoid coming out with respect to the phase of the sinusoid going in is equal to two pi times nS .
π π=2ππ πβ‘ 2π ππ
What has changed?
Only the observerβs position!
Each car coming out is exactly NS cars ahead of each car going in.
Ξππ=β 2 π½ Ξπ₯π
Voltage MaximaVoltage Minima
π2
π2π4