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f

XL

fo

f fo

R

Z

A copper coil is set just behind the wire loop of this circuit.

As the switch is closed,

1) a clockwise current is induced in the copper loop.2) a counter clockwise current is induced in the copper loop.3) no current appears in the copper loop.

A copper coil rests flat on a tabletop next to the wire loop of this simple circuit. As the switch is opened,

1) a clockwise current is induced in the copper loop.2) no current appears in the copper loop.

A copper coil is set just behind the wire loop of this circuit.

As the switch is opened,

1) a clockwise current is induced in the copper loop.2) a counter clockwise current is induced in the copper loop.3) no current appears in the copper loop.

Compared to the voltage drop across coil A, the voltage across coil B is

1) less than 6 V

2) 6 V

3) greater than 6 V

A B6 V

120 V

1 Amp

What is the voltage across the light bulb?1) 60 V2) 120 V3) 240 V

240 V 120 V

120 V

1 Amp

What is the voltage across the light bulb?1) 60 V2) 120 V3) 240 V

What is the current through the light bulb?1) 1/2 Amp2) 1 Amp3) 2 Amps

240 V 120 V

120 V

1 Amp

What is the voltage across the light bulb?

A) 60 VB) 120 VC) 240 V

What is the current through the light bulb?

A) 1/2 AmpB) 1 AmpC) 2 Amps

240 V

Twice as many loops voltage doubles.THEN: half as many loops, voltage halves

Power in = Power outVoltage out = 120 V 240 V 1 Amp = 120 V Iso I = 2 Amp

120 V

2) a counter clockwise current is induced in the copper loop.A clockwise current is created in the black wire loop, establishing a sudden magneticfield pointing down into the center of the copper coil. To counter this, the coil will try to create a field of its own pointing out. It does this with a counter clockwise current.

2) a counter clockwise current is induced in the copper loop.While current flows the wire loop’s field points into the screen within its center, but doubles back outside the loop. That means where the copper coil lies, the field initiallypoints out. When the switch is opened, this field suddenly vanishes. To counter the disappearance of flux, the coil tried to create its own, which requires a clockwiseinduced current.

• a clockwise current is induced in the copper loop.The coil tried to replace the flux that starts to disappear as soon as the switch is opened.

• less than 6 V The voltage across B is zero only a changing magnetic flux induces an EMF. Batteries provide DC current.

2) 120 V Twice as many loops voltage doubles. THEN: half as many loops, voltage halves

3)2 Amps Power in = Power out, Voltage out = 120 V 240 V 1 Amp = 120 V I so I = 2 Amp