09.12.16toki@osaka-groningen1 relativistic chiral mean field model for nuclear physics (ii) hiroshi...
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09.12.16 toki@osaka-groningen 1
Relativistic chiral mean field model for nuclear physics (II)
Hiroshi Toki
Research Center for Nuclear Physics
Osaka University
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Pion is important !! Yukawa introduced pion as a mediator of
nuclear interaction (1934) Meyer-Jensen introduced shell model for
finite nuclei (1949) Nambu-Jona-Lasinio introduced chiral
symmetry and its breaking for mass and pion generation (1961)
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Motivation for the second stage
Pion is important in nuclear physics. Pion appears due to chiral symmetry. Particles as nucleon, rho mesons,.. may
change their properties in medium. Chiral symmetry may be recovered
partially in nucleus. Unification of QCD physics and nuclear
physics.
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Spontaneous breaking of chiral symmetry
Quarks & gluons
Hadrons & nucleiConfinement, Mass generation
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Potential energy surface of the vacuum
Chiral order parameter
Yoichiro Nambu
Hosaka
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He was motivated by the BCS theory.
€
E p = ±(ε p2 + Δ2)1/ 2
€
E p = ±( p2 + m2)1/ 2
Nobel prize (2008)
€
εiψ i + Δψ ̃ i = E iψ i
−ε iψ ̃ i + Δ*ψ i = E iψ ̃ i
€
− r
σ ⋅ r
p ψ L + mψ R = E pψ Lr σ ⋅
r p ψ R + mψ L = E pψ R
€
Δ is the order parameter is the order parameter
€
m
Particle number Chiral symmetry
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Nambu-Jona-Lasinio Lagrangian
Mean field approximation; Hartree approximation
Fermion gets mass.
The chiral symmetry is spontaneously broken.
€
ψ ψ → ψ ψ cos(2α ) +ψ iγ 5ψsin(2α )
ψ iγ 5ψ →ψ iγ 5ψ cos(2α ) −ψ ψsin(2α )
€
ψ → e iαγ 5ψChiral transformation
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Chiral condensate is
The fermion mass is
The mass is similar to the pairing gap in the BCS formalism.The mass generation mechanism for a fermion.
m
G
Gc
€
1 =GcΛ
2
π 2
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The particle-hole excitation (pion channel): RPA
T =K
+ T
KJ(q)
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The pion mass is zero. Nambu-Goldstone mode has a zero mass.
The nucleon gets mass by chiral condensation.
There appears a massless boson; pseudo-scalar meson.
All the masses of particles are zero at the beginning, butthey are generated dynamically.Massless boson appears (Nambu-Goldstone boson) with pseudo-scalar quantum number.
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Bosonization (Eguchi:1974)
€
Lσ =1
2(∂ μσ )2 + (∂ μπ a )2
( ) −λ
4(σ 2 + π a 2) − v 2
( )2
Fermion field is quark
€
Z = Dψ Dψ exp i d4∫ x LNJL[ ]∫€
LNJL = iψ γ μ∂μψ + G ψ ψ( )
2+ ψ iγ 5τ
aψ( )2
[ ]
Auxiliary fields
€
σ =ψ ψ
€
π a =ψ iγ 5τaψ
€
Z = Dψ DψDσDπ a exp∫ i d4∫ x[ψ iγ μ∂ μψ
−ψ g0(σ + iγ 5τaπ a )ψ −
1
2μ0
2(σ 2 + π a 2)]
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Nuclear physics with NJL model
Auxiliary fields
€
σ =ψ ψ
€
π a =ψ iγ 5τaψ
SU2 chiral transformation
exp (aqa g5 )
€
σ → σ cos2θ + ˆ θ aπ asin2θ
π a → π a cos2θ − ˆ θ aσ sin2θ
€
LNJL = iψ γ μ∂μψ + G ψ ψ( )
2+ ψ iγ 5τ
aψ( )2
[ ]
Confinement (Polyakov NJL Mode)
€
Lσ =ψ iγ μ∂μ − g(σ + iτ aπ a )( )ψ
+1
2(∂ μσ )2 + (∂ μπ a )2
( ) −λ
4(σ 2 + π a2) − v 2
( )2
SU2c is doneSU3c is not yet done.
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Chiral sigma modelChiral sigma model
Linear Sigma Model Lagrangian
Polar coordinate
Weinberg transformation
Pion is the Nambu boson of chiral symmetry
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Non-linear sigma modelNon-linear sigma model
Lagrangian = fπ +
whereM = gσfπ M* = M + gσ
mπ2 = 2 + fπ mσ
2 = 2 +3 fπ
m = gfπ m
= m + g
~ ~
Free parameters are and
€
mσ
€
gω (Two parameters)
N
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Relativistic mean field model(standard)
Mean field approximation:
€
σ = σ + ′ σ
Then take only the mean field part, which is just a number.
€
σ =σ
=δ0ω
€
π a = 0
The pion mean field is zero. Hence, the pion contributionis zero in the standard mean field approximation.
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Relativistic mean field model(pion condensation)
€
π a = π a Ogawa, Toki, et al.Brown, Migdal..
Since the pion has pseudo-scalar (0-) nature, the parityand charge symmetry are broken.
In finite nuclei, we have to project out spin and isospin,which involves a complicated projection.
Dirac equation
€
mπ2π a = gπ∇ i ψ iγ 5γ iψ
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€
Ψ=Ψ(σ ,ω)⊗Ψ(N)Mean field approximation for mesons.
€
Ψ(N) = C0 RMF + Ci
i
∑ 2p − 2hi
Nucleons are moving in the mean field and occasionally broughtup to high momentum states
due to pion exchange interaction
€
σ
€
σ
h h
p p
Brueckner argument
Relativistic Chiral Mean Field Model(powerful method)Wave function for mesons and nucleons
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Why 2p-2h states are necessary for pion (tensor)interaction?
€
σ
€
σ
G.S.
Spin-saturated
The spin flipped states are alreadyoccupied by other nucleons.
Pauli forbidden
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Energy minimization with respect tomeson and nucleon fields
€
δΨ H Ψ
Ψ Ψ= 0
€
δE
δσ= 0
δE
δω= 0
(Mean field equation)
€
δE
δψ i(x)= 0
δE
δCi
= 0
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Hartree-Fock
G-matrix component
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Numerical results (1)
4He12C16O
Ogawa TokiNP 2009
Adjust binding energyand size
Tensor
Spin-spin
Pion
Total
12C
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Numerical results 2
The difference between 12C and 16O is 3 MeV/N.
The difference comes from low pion spin states (J<3).This is the Pauli blocking effect.
P3/2
P1/2
C
O
S1/2
Pion energy Pion tensor provides large attraction to 12C
OC
Cumulative Individual contribution
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Chiral symmetry
Nucleon mass is reducedby 20% due to sigma.
We want to work out heavier nuclei for magic number.Spin-orbit splitting should be worked out systematically.
Ogawa TokiNP(2009)
Not 45% as discussedin RMF model.
N
€
One half is from sigma meson and the other half isfrom the pion.
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Nuclear matterHu Ogawa TokiPhys. Rev. 2009
€
ψ ψ
E/A
Total
Pion
€
Σ ~ 50MeV
Total
€
ψ ψ
€
σ
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Deeply bound pionic atom
Toki Yamazaki, PL(1988)
Predicted to exist
Found by (d,3He) @ GSIItahashi, Hayano, Yamazaki..Z. Phys.(1996), PRL(2004)
Findings: isovector s-wave
€
b1
b1(ρ )=1− 0.37
ρ
ρ 0
€
fπ2mπ
2 = −2mq ψ ψ
€
ψ ψ
ψ ψ=1− 0.37
ρ
ρ 0
€
b1 ∝1
fπ2
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Suzuki, Hayano, Yamazaki..PRL(2004)
Optical model analysisfor the deeply bound state.
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Summary-2
NJL model provides the linear sigma model. Pion (tensor) is treated within the relativistic
chiral mean field model. JJ-magic is produced by pion. Nucleon mass is reduced by 20% Deeply bound pionic atom seems to verify
partial recovery of chiral symmetry.
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Summary
Pion is important in Nuclear Physics. Pion is a Goldstone-Nambu boson of chiral symmetry
breaking. By integrating out the quark field with confinement, we
can get sigma model Lagrangian. Relativistic chiral mean field model is able to work out
the sigma model Lagrangian. We have now a tool to unify the quark picture with the
hadron picture and describe nucleus from quarks.
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Joint Lecture Groningen-Osaka Spontaneous Breaking of Chiral Symmetry in Hadron Physics30 Sep 09:00- CEST/16:00- JST Atsushi HOSAKA07 Oct 09:00- CEST/16:00- JST Nuclear Structure21 Oct 09:00- CEST/16:00- JST Nasser KALANTAR-NAYESTANAKI28 Oct 09:00- CET/17:00- JST Low-energy tests of the Standard Model25 Nov 09:00- CET/17:00- JST Rob TIMMERMANS02 Dec 09:00- CET/17:00- JST Relativistic chiral mean field model description of finite nuclei09 Dec 09:00- CET/17:00- JST Hiroshi TOKI16 Dec 09:00- CET/17:00- JST + WRAP-UP/DISCUSSION