11x1 t07 01 definitions & chord theorems
TRANSCRIPT
Circle Geometry
Circle GeometryCircle Geometry Definitions
Circle GeometryCircle Geometry Definitions
Circle GeometryCircle Geometry Definitions
Radius:an interval joining centre to the circumference
radius
Circle GeometryCircle Geometry Definitions
Radius:an interval joining centre to the circumference
radius
Diameter:an interval passing through the centre, joining any two points on the circumference
diameter
Circle GeometryCircle Geometry Definitions
Radius:an interval joining centre to the circumference
radius
Diameter:an interval passing through the centre, joining any two points on the circumference
diameter Chord:an interval joining two points on the circumference
chord
Circle GeometryCircle Geometry Definitions
Radius:an interval joining centre to the circumference
radius
Diameter:an interval passing through the centre, joining any two points on the circumference
diameter Chord:an interval joining two points on the circumference
chordSecant: a line that cuts the circle
secant
Circle GeometryCircle Geometry Definitions
Radius:an interval joining centre to the circumference
radius
Diameter:an interval passing through the centre, joining any two points on the circumference
diameter Chord:an interval joining two points on the circumference
chordSecant: a line that cuts the circle
secant
Tangent: a line that touches the circle
tangent
Circle GeometryCircle Geometry Definitions
Radius:an interval joining centre to the circumference
radius
Diameter:an interval passing through the centre, joining any two points on the circumference
diameter Chord:an interval joining two points on the circumference
chordSecant: a line that cuts the circle
secant
Tangent: a line that touches the circle
tangent Arc: a piece of the circumference
arc
Sector: a plane figure with two radii and an arc as boundaries.
sector
Sector: a plane figure with two radii and an arc as boundaries.
sector
The minor sector is the small “piece of the pie”, the major sector is the large “piece”
Sector: a plane figure with two radii and an arc as boundaries.
sector
The minor sector is the small “piece of the pie”, the major sector is the large “piece”
A quadrant is a sector where the angle at the centre is 90 degrees
Sector: a plane figure with two radii and an arc as boundaries.
sector
The minor sector is the small “piece of the pie”, the major sector is the large “piece”
A quadrant is a sector where the angle at the centre is 90 degrees
Segment:a plane figure with a chord and an arc as boundaries.
segment
Sector: a plane figure with two radii and an arc as boundaries.
sector
The minor sector is the small “piece of the pie”, the major sector is the large “piece”
A quadrant is a sector where the angle at the centre is 90 degrees
Segment:a plane figure with a chord and an arc as boundaries.
segment
A semicircle is a segment where the chord is the diameter, it is also a sector as the diameter is two radii.
Concyclic Points:points that lie on the same circle.
A
B
CD
Concyclic Points:points that lie on the same circle.
concyclic points
A
B
CD
Concyclic Points:points that lie on the same circle.
concyclic points
Cyclic Quadrilateral: a four sided shape with all vertices on the same circle.
cyclic quadrilateral
A
B
CD
AB
AB
represents the angle subtended at the centre by the arc AB
AB
represents the angle subtended at the centre by the arc AB
AB
represents the angle subtended at the centre by the arc AB
represents the angle subtended at the circumference by the arc AB
AB
represents the angle subtended at the centre by the arc AB
represents the angle subtended at the circumference by the arc AB
AB
represents the angle subtended at the centre by the arc AB
represents the angle subtended at the circumference by the arc AB
Concentric circles have the same centre.
Circles touching internally share a common tangent.
Circles touching internally share a common tangent.
Circles touching externally share a common tangent.
Circles touching internally share a common tangent.
Circles touching externally share a common tangent.
Circles touching internally share a common tangent.
Circles touching externally share a common tangent.
Chord (Arc) Theorems
Chord (Arc) TheoremsNote: = chords cut off = arcs
Chord (Arc) TheoremsNote: = chords cut off = arcs
(1) A perpendicular drawn to a chord from the centre of a circle bisects the chord, and the perpendicular bisector of a chord passes through the centre.
Chord (Arc) TheoremsNote: = chords cut off = arcs
(1) A perpendicular drawn to a chord from the centre of a circle bisects the chord, and the perpendicular bisector of a chord passes through the centre.
A
BO
X
Chord (Arc) TheoremsNote: = chords cut off = arcs
(1) A perpendicular drawn to a chord from the centre of a circle bisects the chord, and the perpendicular bisector of a chord passes through the centre.
chord bisects centre, from BXAXA
BO
X
Chord (Arc) TheoremsNote: = chords cut off = arcs
(1) A perpendicular drawn to a chord from the centre of a circle bisects the chord, and the perpendicular bisector of a chord passes through the centre.
chord bisects centre, from BXAXA
BO
XOXAB :Data
Chord (Arc) TheoremsNote: = chords cut off = arcs
(1) A perpendicular drawn to a chord from the centre of a circle bisects the chord, and the perpendicular bisector of a chord passes through the centre.
chord bisects centre, from BXAXA
BO
XOXAB :DataBXAX :Prove
Chord (Arc) TheoremsNote: = chords cut off = arcs
(1) A perpendicular drawn to a chord from the centre of a circle bisects the chord, and the perpendicular bisector of a chord passes through the centre.
chord bisects centre, from BXAXA
BO
XOXAB :DataBXAX :Prove
Proof: Join OA, OB
Chord (Arc) TheoremsNote: = chords cut off = arcs
(1) A perpendicular drawn to a chord from the centre of a circle bisects the chord, and the perpendicular bisector of a chord passes through the centre.
chord bisects centre, from BXAXA
BO
XOXAB :DataBXAX :Prove
Proof: Join OA, OB RBXOAXO given 90
Chord (Arc) TheoremsNote: = chords cut off = arcs
(1) A perpendicular drawn to a chord from the centre of a circle bisects the chord, and the perpendicular bisector of a chord passes through the centre.
chord bisects centre, from BXAXA
BO
XOXAB :DataBXAX :Prove
Proof: Join OA, OB RBXOAXO given 90
HBOAO radii
Chord (Arc) TheoremsNote: = chords cut off = arcs
(1) A perpendicular drawn to a chord from the centre of a circle bisects the chord, and the perpendicular bisector of a chord passes through the centre.
chord bisects centre, from BXAXA
BO
XOXAB :DataBXAX :Prove
Proof: Join OA, OB RBXOAXO given 90
HBOAO radii SOX common is
Chord (Arc) TheoremsNote: = chords cut off = arcs
(1) A perpendicular drawn to a chord from the centre of a circle bisects the chord, and the perpendicular bisector of a chord passes through the centre.
chord bisects centre, from BXAXA
BO
XOXAB :DataBXAX :Prove
Proof: Join OA, OB RBXOAXO given 90
HBOAO radii SOX common is RHSBXOAXO
Chord (Arc) TheoremsNote: = chords cut off = arcs
(1) A perpendicular drawn to a chord from the centre of a circle bisects the chord, and the perpendicular bisector of a chord passes through the centre.
chord bisects centre, from BXAXA
BO
XOXAB :DataBXAX :Prove
Proof: Join OA, OB RBXOAXO given 90
HBOAO radii SOX common is RHSBXOAXO
matching sides in 'sAX BX
(2) Converse of (1)The line from the centre of a circle to the midpoint of the chord at right angles.
(2) Converse of (1)The line from the centre of a circle to the midpoint of the chord at right angles.
A
BO
X
(2) Converse of (1)The line from the centre of a circle to the midpoint of the chord at right angles.
chord tomidpoint, tocentre joining line ABOXA
BO
X
(2) Converse of (1)The line from the centre of a circle to the midpoint of the chord at right angles.
chord tomidpoint, tocentre joining line ABOXA
BO
XBXAX :Data
(2) Converse of (1)The line from the centre of a circle to the midpoint of the chord at right angles.
chord tomidpoint, tocentre joining line ABOXA
BO
XBXAX :DataOXAB :Prove
(2) Converse of (1)The line from the centre of a circle to the midpoint of the chord at right angles.
chord tomidpoint, tocentre joining line ABOXA
BO
XBXAX :DataOXAB :Prove
Proof: Join OA, OB
(2) Converse of (1)The line from the centre of a circle to the midpoint of the chord at right angles.
chord tomidpoint, tocentre joining line ABOXA
BO
XBXAX :DataOXAB :Prove
Proof: Join OA, OB SBXAX given
(2) Converse of (1)The line from the centre of a circle to the midpoint of the chord at right angles.
chord tomidpoint, tocentre joining line ABOXA
BO
XBXAX :DataOXAB :Prove
Proof: Join OA, OB SBXAX given SBOAO radii
(2) Converse of (1)The line from the centre of a circle to the midpoint of the chord at right angles.
chord tomidpoint, tocentre joining line ABOXA
BO
XBXAX :DataOXAB :Prove
Proof: Join OA, OB SBXAX given SBOAO radii
SOX common is
(2) Converse of (1)The line from the centre of a circle to the midpoint of the chord at right angles.
chord tomidpoint, tocentre joining line ABOXA
BO
XBXAX :DataOXAB :Prove
Proof: Join OA, OB SBXAX given SBOAO radii
SOX common is SSSBXOAXO
(2) Converse of (1)The line from the centre of a circle to the midpoint of the chord at right angles.
chord tomidpoint, tocentre joining line ABOXA
BO
XBXAX :DataOXAB :Prove
Proof: Join OA, OB SBXAX given SBOAO radii
SOX common is SSSBXOAXO
matching 's in 'sAXO BXO
(2) Converse of (1)The line from the centre of a circle to the midpoint of the chord at right angles.
chord tomidpoint, tocentre joining line ABOXA
BO
XBXAX :DataOXAB :Prove
Proof: Join OA, OB SBXAX given SBOAO radii
SOX common is SSSBXOAXO
matching 's in 'sAXO BXO AXBBXOAXO straight 180
(2) Converse of (1)The line from the centre of a circle to the midpoint of the chord at right angles.
chord tomidpoint, tocentre joining line ABOXA
BO
XBXAX :DataOXAB :Prove
Proof: Join OA, OB SBXAX given SBOAO radii
SOX common is SSSBXOAXO
matching 's in 'sAXO BXO AXBBXOAXO straight 180
90
1802
AXO
AXO
(2) Converse of (1)The line from the centre of a circle to the midpoint of the chord at right angles.
chord tomidpoint, tocentre joining line ABOXA
BO
XBXAX :DataOXAB :Prove
Proof: Join OA, OB SBXAX given SBOAO radii
SOX common is SSSBXOAXO
matching 's in 'sAXO BXO AXBBXOAXO straight 180
90
1802
AXO
AXO
OX AB
(3) Equal chords of a circle are the same distance from the centre and subtend equal angles at the centre.
(3) Equal chords of a circle are the same distance from the centre and subtend equal angles at the centre.
A
B
O X
C DY
(3) Equal chords of a circle are the same distance from the centre and subtend equal angles at the centre.
centre fromt equidistan chords, OYOX
A
B
O X
C DY
(3) Equal chords of a circle are the same distance from the centre and subtend equal angles at the centre.
centre fromt equidistan chords, OYOX centreat s' subtend chords CODAOB
A
B
O X
C DY
(3) Equal chords of a circle are the same distance from the centre and subtend equal angles at the centre.
centre fromt equidistan chords, OYOX
Data: , ,AB CD OX AB OY CD centreat s' subtend chords CODAOB
A
B
O X
C DY
(3) Equal chords of a circle are the same distance from the centre and subtend equal angles at the centre.
centre fromt equidistan chords, OYOX
Data: , ,AB CD OX AB OY CD OYOX :Prove
centreat s' subtend chords CODAOB
A
B
O X
C DY
(3) Equal chords of a circle are the same distance from the centre and subtend equal angles at the centre.
centre fromt equidistan chords, OYOX
Data: , ,AB CD OX AB OY CD OYOX :Prove
Proof: Join OA, OC
centreat s' subtend chords CODAOB
A
B
O X
C DY
(3) Equal chords of a circle are the same distance from the centre and subtend equal angles at the centre.
centre fromt equidistan chords, OYOX
Data: , ,AB CD OX AB OY CD OYOX :Prove
Proof: Join OA, OC given CDAB
centreat s' subtend chords CODAOB
A
B
O X
C DY
(3) Equal chords of a circle are the same distance from the centre and subtend equal angles at the centre.
centre fromt equidistan chords, OYOX
Data: , ,AB CD OX AB OY CD OYOX :Prove
Proof: Join OA, OC given CDAB chord bisects
21 ABAX
centreat s' subtend chords CODAOB
A
B
O X
C DY
(3) Equal chords of a circle are the same distance from the centre and subtend equal angles at the centre.
centre fromt equidistan chords, OYOX
Data: , ,AB CD OX AB OY CD OYOX :Prove
Proof: Join OA, OC given CDAB chord bisects
21 ABAX
centreat s' subtend chords CODAOB
chord bisects 21 CDCY
A
B
O X
C DY
(3) Equal chords of a circle are the same distance from the centre and subtend equal angles at the centre.
centre fromt equidistan chords, OYOX
Data: , ,AB CD OX AB OY CD OYOX :Prove
Proof: Join OA, OC given CDAB chord bisects
21 ABAX
SCYAX
centreat s' subtend chords CODAOB
chord bisects 21 CDCY
A
B
O X
C DY
(3) Equal chords of a circle are the same distance from the centre and subtend equal angles at the centre.
centre fromt equidistan chords, OYOX
Data: , ,AB CD OX AB OY CD OYOX :Prove
Proof: Join OA, OC given CDAB chord bisects
21 ABAX
SCYAX RCYOAXO given 90
centreat s' subtend chords CODAOB
chord bisects 21 CDCY
A
B
O X
C DY
(3) Equal chords of a circle are the same distance from the centre and subtend equal angles at the centre.
centre fromt equidistan chords, OYOX
Data: , ,AB CD OX AB OY CD OYOX :Prove
Proof: Join OA, OC given CDAB chord bisects
21 ABAX
SCYAX RCYOAXO given 90
centreat s' subtend chords CODAOB
chord bisects 21 CDCY
HOCOA radii
A
B
O X
C DY
(3) Equal chords of a circle are the same distance from the centre and subtend equal angles at the centre.
centre fromt equidistan chords, OYOX
Data: , ,AB CD OX AB OY CD OYOX :Prove
Proof: Join OA, OC given CDAB chord bisects
21 ABAX
SCYAX RCYOAXO given 90
centreat s' subtend chords CODAOB
chord bisects 21 CDCY
HOCOA radii RHSCYOAXO
A
B
O X
C DY
(3) Equal chords of a circle are the same distance from the centre and subtend equal angles at the centre.
centre fromt equidistan chords, OYOX
Data: , ,AB CD OX AB OY CD OYOX :Prove
Proof: Join OA, OC given CDAB chord bisects
21 ABAX
SCYAX RCYOAXO given 90
matching sides in 's OX OY
centreat s' subtend chords CODAOB
chord bisects 21 CDCY
HOCOA radii RHSCYOAXO
A
B
O X
C DY
A
B
O
C D
A
B
O
C D
CDAB :Data
A
B
O
C D
CDAB :DataCODAOB :Prove
A
B
O
C D
CDAB :DataCODAOB :Prove
Proof: given CDAB
A
B
O
C D
CDAB :DataCODAOB :Prove
Proof: given CDAB radii DOCOBOAO
A
B
O
C D
CDAB :DataCODAOB :Prove
Proof: given CDAB radii DOCOBOAO
SSSCODAOB
A
B
O
C D
CDAB :DataCODAOB :Prove
Proof: given CDAB radii DOCOBOAO
matching 's in 's AOB COD SSSCODAOB
A
B
O
C D
CDAB :DataCODAOB :Prove
Proof: given CDAB radii DOCOBOAO
matching 's in 's AOB COD SSSCODAOB
Exercise 9A; 1 ce, 2 aceg, 3, 4, 9, 10 ac, 11 ac, 13, 15, 16, 18