1505 lts paper 2 aiot dlp

7/25/2019 1505 Lts Paper 2 Aiot Dlp

http://slidepdf.com/reader/full/1505-lts-paper-2-aiot-dlp 1/36

READ THE INSTRUCTIONS CAREFULLY / œi; b u un ' d ; u l i<

GENERAL / l e ;:

1. This sealed booklet is your Question Paper. Do not break the seal till you are instructed to do so.

; g e k s g j c U / k i q f L r d k i z ' u i = g S A b ld h e q g j r c r d u r k s M + s tc r d b ld k f u n s Z ' k u f n ; k tk ; s A2. Use the Optical Response sheet (ORS) provided separately for answering the questions.

i z ' u k s a d k m Ÿ k j n s u s d s f y , v y x ls n h x ; h v k W I V h d y f j L i k a l ' k h V (v k s - v k j- , l-)(ORS) d k m i ; k s x d j s a A3. Blank spaces are provided within this booklet for rough work.

d P p s d k ; Z d s f y , b l i q f L r d k e s a [ k k y h L F k k u f n ; s x ; s g S a A4. Write your name and form number in the space provided on the back cover of this booklet.

, d i q f L r d k d s f i N y s i ` " B i j f n , x , L F k k u e s a v i u k u k e rF k k Q k W e Z u E c j f y f [ k ,A5. After breaking the seal of the booklet, verify that the booklet contains 36 pages and all the 20 questions in each

subject and along with the options are legible.

b l i q f L r d k d h e q g j r k s M + u s d s c k n œ i ; k tk ° p y s f d b le s a36 i ` " B g S a v k S j v k S j i z R ; s d f o " k ; d s lH k h 20 i z ' u v k S j m u d s m Ÿ k j f o d Y i

B h d ls i < + s tk ld r s g S A

QUESTION PAPER FORMAT AND MARKING SCHEME /i 'ui= d i :i v v du ; tu

:

6. The question paper has three parts : Physics, Chemistry and Mathematics. Each part has two sections.

b l i z ' u i = e s a r h u H k k x g S a % H k k S f r d f o K k u] j lk ; u f o K k u v k S j x f . k rA g j H k k x e s a n k s [ k . M g S a A7. Carefully read the instructions given at the beginning of each section.

i z R ; s d [ k . M d s i z k j E H k e s a f n ; s g q , f u n s Z ' k k s a d k s / ; k u ls i < + s A

8. Section-I / [ .M-I :

(i) Section-I(i) contains 8 multiple choice questions with one or more than one correct option.

Marking scheme : +4 for correct answer, 0 if not attempted and –2 in all other cases.

[ k . M -I(i) e s a8 c g q f o d Y i h ; i z ' u g S A f tu d s,d ; ,d l v d

f o d Y i lg h g S a A

v d ; tu: +4 lg h m Ÿ k j d s f y ,]0 i z ; k l u g h a d j u s i j rF k k –2 v U ; lH k h v o L F k k v k s a e s a A(ii) Section-I(ii) contains 2 ‘paragraph’ type questions. Each paragraph describes an experiment, a situation or a

problem. Two multiple choice questions will be asked based on each paragraph. One or more than one option

can be correct.

Marking scheme : +4 for correct answer, 0 if not attempted and –2 in all other cases.

[ k . M -I(ii) e s a2 ‘ v u q P N s n ’ i z k :i i z ' u g S A i z R ; s d v u q P N s n , d i z ; k s x] , d n ' k k vF k o k , d le L ; k d k s n ' k k Z r k g S A i z R ; s d v u

c g q f o d f Y i ; i z ' u i w N s tk ; x s A,d ; ,d l v d

f o d Y i lg h g k s ld r s g S a A

v d ; tu: +4 lg h m Ÿ k j d s f y ,]0 i z ; k l u g h a d j u s i j rF k k –2 v U ; lH k h v o L F k k v k s a e s a A

9. There is no questions in SECTION-II & III / [ k . M –II o III e s a , d H k h i z ' u u g h a g S10. Section-IV contains 8 questions. The answer to each question is a single digit integer ranging from

0 to 9 (both inclusive)

Marking scheme : +4 for correct answer and 0 in all other cases.

[ k . M -IV e s a8 i z ' u g S a A i z R ; s d i z ' u d k0 ls 9 r d ( n k s u k s a ' k k f e y ) d s c h p d k , d y v a d h ; i w . k k ± d g S A

v d ; tu: +4 lg h m Ÿ k j d s f y , rF k k0 v U ; lH k h v o L F k k v k s a e s a A

PAPER – 2

Test Type : ALL INDIA OPEN TEST (MAJOR) Test Pattern : JEE-Advanced

TEST # 12 TEST DATE : 15 - 05 - 2016

TARGET : JEE (ADVANCED) 2016

LEADER TEST SERIES / JOINT PACKAGE COURSE

Paper Code : 0000CT103115009

DISTANCE LEARNING PROGRAMME(Academic Session : 2015 - 2016)

Time : 3 Hours Maximum Marks : 240

Please see the last page of this booklet for rest of the instructions / œ i; ' u n ' d y, b l i rd d v re i B d i

D O N O T

B R E A K T H E S E A L S W I T H O U T B E I N G

I N S T R U C T E D T O D O S O B Y T H E I N V I G I L A T O R / u

d

d

v

u

n

'

d

c

u

e

g

u

r

M



ALL INDIA OPEN TEST/JEE (Advanced)/15-05-2016/PAPER-2

SOME USEFUL CONSTANTS A tomic No. H = 1, B = 5, C = 6, N = 7, O = 8, F = 9, Al = 13, P = 15, S = 16, Cl = 17, Br = 35,

Xe = 54, Ce = 58,

A tomic masses : H = 1, Li = 7, B = 11, C = 12, N = 14, O = 16, F = 19, Na = 23, Mg = 24,

Al = 27, P = 31, S = 32, Cl = 35.5, Ca=40, Fe = 56, Br = 80, I = 127,

Xe = 131, Ba=137, Ce = 140,

LTS-2/36 0000CT103115009

Note : In case of any correction in the test paper, please mail to [email protected] within 2 days along with Paper Code

& Your Form No.( u V

; f n b l i z ' u i = e s a d k s b ZCorrection g k s r k s œ i ; kPaper Code , o a v k i d s Form No. , o a i w . k ZTest Details d s lk F k 2 f n u d s v U n j [email protected] i j mail d j s a A)

Space for Rough Work / dP p d ; d y, L u

Boltzmann constant k = 1.38 × 10 –23 JK –1

Coulomb's law constant

1

= ×1

4

Universal gravitational constant G = 6.67259 × 10 –11 N–m2 kg –2

Speed of light in vacuum c = 3 × 108 ms –1

Stefan–Boltzmann constant

= 5.67 × 10 –8 Wm –2 –K –4

Wien's displacement law constant b = 2.89 × 10 –3 m–K

Permeability of vacuum µ0 = 4 × 10 –7 NA –2

Permittivity of vacuum

0 =

2

0

1

c

Planck constant h = 6.63 × 10 –34 J–s




P H Y S I C S

LTS-3/360000CT103115009

PART-1 : PHYSICS

H x

-1 :H rd oK u

SECTION–I(i) : (Maximum Marks : 32)

[ .M

– I(i) : ( v dre v d

: 32)

This section contains EIGHT questions. Each question has FOUR options (A), (B), (C) and (D). ONE OR MORE THAN ONE of these

four option(s) is (are) correct. For each question, darken the bubble(s) corresponding to all the correct option(s) in the ORS Marking scheme :

+4 If only the bubble(s) corresponding to all the correct option(s) is (are) darkened0 If none of the bubbles is darkened

–2 In all other cases

b l [ k . M e s av B i z ' u g S a i z R ; s d i z ' u e s a p k j f o d Y i(A), (B), (C) rF k k (D) g S a A b u p k j f o d Y i k s a e s a ls,d ; ,d l v d f o d Y i lg h g S a A i z R ; s d i z ' u e s a ] lH k h lg h f o d Y i ( f o d Y i k s a ) d s v u q :i c q y c q y s ( c q y c q y k s a ) d k s v k s -v k j- , l- e s v a d u ; k s tu k :

+4 ; f n f lQ Z lH k h lg h f o d Y i ( f o d Y i k s a ) d s v u q :i c q y c q y s ( c q y c q y k s a ) d k s d k y k f d ; k tk ; 0 ; f n d k s b Z H k h c q y c q y k d k y k u f d ; k g k s

–2 v U ; lH k h v o L F k k v k s a e s a1. In the circuit shown, K

1 is closed for a long time. Then K

1 is opened & K

2 is closed simultaneously.

The maximum voltage across capacitor is found to be 2 V. If L = 2H, C = 8µF, then(A) R = 250

(B) The maximum energy stored in capacitor is half of energy dissipated during growth of current inLR circuit.

(C) R = 125

(D) The maximum energy stored in capacitor is equal to maximum energy stored in inductor.

L

R

1V

C

K 1 K 2

i z n f ' k Z r i f j iF k e s aK 1 d k s y E c s le ; d s f y ; s c a n j [ k k x ; k g S A v cK 1 d k s [ k k s y d j m lh k . kK 2 d k s c a n d j f n ; k tk r k g S A la / k k f j = i j v f / k d r e o k s Y V r k2 V i k ; h tk r h g S A ; f nL = 2H, C = 8µF g S r c % &(A) R = 250

(B) la / k k f j = e s a la f p r v f / k d r e ≈ tk ZLR i f j iF k e s a / k k j k d h o ` f º d s n k S j k u O ; f ; r ≈ tk Z d h v k / k h g S A(C) R = 125

(D) la / k k f j = e s a la f p r v f / k d r e ≈ tk Z i z s j d d q . M y h e s a la f p r v f / k d r e ≈ tk Z d s c j k c j g S A

BEWARE OF NEGATIVE MARKING

HAVE CONTROL HAVE PATIENCE HAVE CONFIDENCE 100% SUCCESS

Space for Rough Work /dP p d ; d y, L u



P H Y S I C S


LTS-4/36 0000CT103115009


2. One mole of monoatomic ideal gas undergoes a cyclic process on PV diagram as shown. It is known

that rms speed of molecules at A = mean speed of molecules at C = most probable speed of molecules

at B. Temperature at A = 280 K. Then :-

(A) Work done by gas from B to C = (420 – 105 ) R ×

3

2(B) Work done by gas from C to A = (280 – 105) R

(C) B

A

P 3

P 8

(D)

C

A

V 3

V 8

A C

B

adiabatic

P

V

, d e k s y v k n ' k Z , d i j e k f . o d x S l f p = k u q lk jPV v k j s [ k i j p ÿ h ; i z ÿ e ls x q tj r h g S A ; g K k r g S f dA i j v . k q v k s a d h

o x Z e k / ; e w y p k y= C i j v . k q v k s a d h e k / ; p k y= B i j v . k q v k s a d h v f / k d r e la H k o p k y g S AA i j r k i e k u280 K g S A

r c % &

(A) B ls C r d x S l k j k f d ; k x ; k d k ; Z = (420 – 105 ) R ×3

2(B) C ls A r d x S l k j k f d ; k x ; k d k ; Z = (280 – 105) R

(C) B

A

P 3

P 8

(D)

C

A

V 3

V 8




P H Y S I C S

LTS-5/360000CT103115009


3. From a long cylinder of radius R, a cylinder of radius R/2 is removed, as shown. Current flowing in

the remaining cylinder is I. Magnetic field strength is :-

(A) zero at point A (B)I

02

3 R at point B (C)

I

0

3 R at point AA (D)

I

0

3 R at point B

I

R

A BR/2

f = T ; kR o k y s y E c s c s y u lsR/2 f = T ; k d k , d c s y u f p = k u q lk j d k V d j f u d k y f y ; k tk r k g S A ' k s " k c s y u s

Ë k k j kI g S A p q E c d h ; k s = lk eF ; Z g S % &

(A) f c U n qA i j ' k w U ; (B) f c U n qB i jI

02

3 R (C) f c U n qA i j

I

0

3 R (D) f c U n qB i j

I

0

3 R

4. Four identical charge particles are constrained to move along the x-axis. Identify possible configurations

of the particles that would leave one charge at rest at the origin, if the others were fixed in place.

p k j , d tS ls v k o s f ' k r d . kx- v k d s v u q f n ' k g h x f r d j ld r s g S A d . k k s a d s la H k k f o r f o U ; k l i g p k f u ; s f tle s

e w y f c U n q i j f o j k e k o L F k k e s a j g tk r k g S ; f n v U ; v i u s L F k k u i j f L F k j g k s a A

(A)3a

— 5

a

3a

QQ QQ x

y

(B)a

— 5

a/2

a

Q

Q QQx

y

(C)15a

–—

3a

5a

Q

Q

Q

Qx

y

(D)3a

–—

2a

4a

Q

Q

Q

Qx

y



P H Y S I C S


LTS-6/36 0000CT103115009


5. A thin uniform disc of mass M and radius R is rotating in a horizontal plane about an axis passing

through its centre and perpendicular to it with angular velocity . Another disc of same radius but of

mass M/4 is placed gently on the first disc coaxially. The both discs stick to each other. Then

(A)The angular velocity of the system will now finally change to

4

5

(B) The kinetic energy of the system will now finally change to2 21

MR 5

(C) The angular velocity of the system will now finally change to2

5

(D) The kinetic energy of the system will now finally change to2 22

MR 5

Ê O ; e k uM rF k k f = T ; kR o k y h , d i r y h le :i p d r h k S f r t r y e s a b ld s d s U Ê ls g k s d j x q tj u s o k y h b ld s y E c o

d s lk i s k d k s . k h ; o s x ls ? k w . k Z u d j j g h g S A le k u f = T ; k i j U r q Ê O ; e k uM/4 o k y h , d v U ; p d r h d k s i z F k e p d r h i j

/ k h j s ls le k k h ; :i ls j [ k f n ; k tk r k g S A n k s u k s a p d f r ; k ° , d& n w lj s ls f p i d tk r h g S A r c % &

(A) f u d k ; d k d k s . k h ; o s x v c v a r e s a i f j o f r Z r g k s d j4

5 g k s tk ; s x k A

(B) f u d k ; d h x f r t ≈ tk Z v c v a r e a s i f j o f r Z r g k s d j2 21

MR 5

g k s tk ; s x h A

(C) f u d k ; d k d k s . k h ; o s x v c v a r e s a i f j o f r Z r g k s d j2

5 g k s tk ; s x k A

(D) f u d k ; d h x f r t ≈ tk Z v c v a r e s a i f j o f r Z r g k s d j2 22MR

5 g k s tk ; s x h A




P H Y S I C S

LTS-7/360000CT103115009


6. X ray from a tube with a target A of atomic number Z shows strong K lines for target A and weak K

lines for impurities. The wavelength of K lines is

Z for target A and

1 and

2for two impurities.

Z

1

4

and Z

2

1

4

Screening constant of K lines to be unity. Select the correct statement(s)(A) The atomic number of first impurity is 2z – 1.

(B) The atomic number of first impurity is z + 1.

(C) The atomic number of second impurity is z 1

2

.

(D) The atomic number of second impurity isz

12

i j e k . k q ÿ e k a dZ o k y s y ;A ls f u f e Z r u y h ls f u x Z rX f d j . k s a y ;A d s f y ; s i z c yK j s [ k k , ° rF k k v ' k q f º; k s a d s f y ; s k

K j s [ k k , ° n ' k k Z r h g S A y ;A d s f y ; sK j s [ k k v k s a d h r j a x n S / ; ZZ o n k s v ' k q f º; k s a d s f y ; s1 o 2 g S AZ

1

4

o Z

2

1

4

y h f t; s A

K j s [ k k v k s a d k L ÿ h f u a x f u ; r k a d b d k b Z e k f u ; s A lg h dF k u@ dF k u k s a d k s p q f u ; s % &

(A) i z F k e v ' k q f º d k i j e k . k q ÿ e k a d2z – 1 g S A

(B) i z F k e v ' k q f º d k i j e k . k q ÿ e k a dz + 1 g S A

(C) f r h ; v ' k q f º d k i j e k . k q ÿ e k a d z 1

2

g S A

(D) f r h ; v ' k q f º d k i j e k . k q ÿ e k a dz 12 g S A



P H Y S I C S


LTS-8/36 0000CT103115009


7. If someone would eat 5 micro gram of the isotope of cesium 137Cs, how long (say t) would it take for

them to have only 25 % of the original amount of this isotope? Assume that cesium has a half-life of

10 days and a biological half-life (the time it takes for half of the original amount of the material to

leave the body) is 30 days. Determine also, how much mass (say m) would have decayed in the bodyup till then. Assume that biological half life is same for parent & daughter nuclei.

(A) t = 40 days (B) t = 15 days

(C) m = 2.5 micro gram (D) m = 1.25 micro gram

; f n d k s b Z O ; f D r lh f t; e d s le L F k k f u d137Cs d h 5 e k b ÿ k s x z k e e k = k d k s [ k k y s r k g S r k s b l le L F k k f u d d h

d s o y25 % c p u s e s a f d r u k le ;(t) y x s x k \ e k u k lh f t; e d h v/ k Z v k ; q10 f n u g S rF k k , d tS f o d v/ k Z v k ; q ( i n k F k Z

e w y e k = k d s v k / k s H k k x d k s ' k j h j ls f u d y u s e s a y x k le ;)30 f n u g S A b l le ; r d ' k j h j e s a f d r u k Ê O ; e k u(m) f o ? k f V r g k s p q d k g k s x k \ e k u k la r f r rF k k i q = h u k f H k d d s f y ; s tS f o d v/ k Z v k ; q le k u g k s r h g S % &

(A) t = 40 f n u (B) t = 15 f n u

(C) m = 2.5 e k b ÿ k s x z k e (D) m = 1.25 e k b ÿ k s x z k e




P H Y S I C S

LTS-9/360000CT103115009


8. Figure shows a square frame with a current in a uniform magnetic field of magnitude B in direction

shown. The sides are a × a. The net magnetic field at the center of the frame is 3B in magnitude.

(A) The torque on the frame is3 2

0

a B

2

(B) The potential energy of interaction of frame with the magnetic field is zero

(C) The total magnetic field at center of the loop will be 3 1 B if the magnetic dipole moment of

the frame is aligned parallel to the magnetic field.

(D) The total magnetic field at center of the loop will be 2 1 B if the magnetic dipole moment of

the frame is aligned anti parallel to the magnetic field.

I

B

f p = e s a , d / k k j k o k g h o x k Z d k j ›s e i f j e k . kB o k y s le :i p q E c d h ; k s = e s a f L F k r g S f tld h f n ' k k f p = e s a n ' k k Z

b ld h H k q tk ; s aa × a g S A ›s e d s d s U Ê i j d q y p q E c d h ; k s = d k i f j e k . k3B g S A

(A) ›s e i j c y k ? k w . k Z d k e k u3 2

0

a B

2

g S A

(B) ›s e d h p q E c d h ; k s = d s lk F k v U ; k s U ; f ÿ ; k d h f L F k f r t ≈ tk Z ' k w U ; g S A

(C) y w i d s d s U Ê i j d q y p q E c d h ; k s = 3 1 B g k s x k ; f n ›s e d k p q E c d h ; f / k z q o v k ? k w . k Z ] p q E c

le k U r j g k s A

(D) y w i d s d s U Ê i j d q y p q E c d h ; k s = 2 1 B g k s x k ; f n ›s e d k p q E c d h ; f / k z q o v k ? k w . k Z ] p q E c

i z f r le k U r j g k s A



P H Y S I C S


LTS-10/36 0000CT103115009

SECTION–I(ii) : (Maximum Marks : 16)

[ .M –I(ii) : ( v dre v d: 16)

This section contains TWO paragraphs. Based on each paragraph, there will be TWO questions Each question has FOUR options (A), (B), (C) and (D). ONE OR MORE THAN ONE of these

four option(s) is (are) correct. For each question, darken the bubble(s) corresponding to all the correct option(s) in the ORS Marking scheme :

+4 If only the bubble(s) corresponding to all the correct option(s) is(are) darkened0 If none of the bubbles is darkened


b l [ k . M e s an v u q P N s n g S a i z R ; s d v u q P N s n i jn i z ' u g S a i z R ; s d i z ' u e s ap f o d Y i(A), (B), (C) rF k k (D) g S a A b u p k j f o d Y i k s a e s a,d ; ,d l v d f o d Y i lg h g S a A i z R ; s d i z ' u d s f y ,] lH k h lg h f o d Y i ( f o d Y i k s a ) d s v u q :i c q y c q y s ( c q y c q y k s a ) d k s v k s -v k j- , - v a d u ; k s tu k :


–2 v U ; lH k h v o L F k k v k s a e s aParagraph for Questions 9 and 10

i 'u 9 ,o 10 d y; vu P N n

The spring of constant k = 50 N/m is unstretched when the slider of mass m = 2 kg passes through

position B. The slider is released from rest in position A. There is friction between slider and guide

whose work done from A to B is –11 J and from B to C is – 4 J. (Radius of guide R = 3m). The whole

system is in vertical plane. i z n f ' k Z r f p = e s a tcm = 2kg Ê O ; e k u d k L y k b M j f L F k f rB ls x q tj r k g S r k sk = 50 N/m f u ; r k a d o k y h f L i z a x v f o L r k f j r g k s r h g S A b l L y k b M j d k s f L F k f rA ls f o j k e k o L F k k ls N k s M + k tk r k g S A ; g k ° L y k b M j rF k k x k b M d s e/ ; ? k k j kA ls B r d tk u s e s a –11 J , o a B ls C r d tk u s e s a – 4J d k ; Z f d ; k tk r k g S A( x k b M d h f = T ; k R = 3m) ; g lE i w . k Z f u d k ; ≈ / o k Z / k j r y e s a g S A

A

m

B

4m

R

C

k

9. If speed of slider at position B and C are vB and v

C respectively then :-

; f n f L F k f rB o C i j L y k b M j d h p k y ÿ e ' k %vB o v

C g k s r k s % &

(A) vB = 6.5 m/s (B) v

B = 13 m/s (C) v

C = 16 m/s (D) v

C = 15 m/s

10. If the normal force at position B and C are NB and N

C respectively then :-

; f n f L F k f rB o C i j v f H k y E c c y ÿ e ' k % NB o NC g k s r k s % &(A) N

B = 112.67 N (B) N

B = 216.33 N (C) N

C = 150 N (D) N

C = 170 N




P H Y S I C S

LTS-11/360000CT103115009


Paragraph for Questions 11 and 12

i 'u 11 ,o 12 d y; vu P N n

Some phenomenon of light can be explained by wave theory and some other phenomenon show the

particle nature of light. De–Broglie proposed a hypothesis based on the dual nature of light. According

to De–Broglie each moving particle has a wave associated with it. This wave is known as De–Broglie

wave or matter wave and its wavelength is given byh

p . Actually this expression correlate wave

and particle nature. Wavelength () represents the wave nature and momentum (p) represents the

particle nature.

i z d k ' k d h d q N ? k V u k v k s a d h O ; k [ ; k r j a x f lºk a r ls rF k k d q N ? k V u k v k s a d h O ; k [ ; k i z d k ' k d h d

tk r h g S A i z d k ' k d h S r i z œ f r d s v k / k k j i j M h & c z k s X y h u s , d i f j d Y i u k n h A b ld s v u q lk j i z R ; s

:i e s a x f r d j r k g S A b l r j a x d k s M h & c z k s X y h r j a x ; k n z O ; r j a x d g r s g S a rF k k b ld h r j a x n S / ; Z h

p

g k s r h g S A o k L r o e s a ;

O ; a td r j a x rF k k d . k i z œ f r d k s i z n f ' k Z r d j r k g S A r j a x n S / ; Z r j a x i z œ f r d k s rF k k la o s x(p) d . k i z œ f r d k s i z n f ' k Z r

d j r k g S A

11. Proton, deutron and particles are accelerated through the same potential difference. Then the ratio of

their wavelength is

i z k s V k W u ] M ~ ; w V ™ k W u rF k k d . k k s a d k s le k u f oH k o k U r j k j k R o f j r d j u s i j m u d h r j a x n S / ; k s Z a d k v u q i k r g k

(A) 1: 2 : 1 (B) 1:1:1 (C) 1 : 2 : 2 2 (D) 2 2 : 2 : 112. When electron accelerated through the 150 volt potential difference. The wavelength associated

with it

tc b y s D V ™ k W u d k s150 o k s Y V f oH k o k U r j k j k R o f j r f d ; k tk r k g S r k s b lls la c a f / k r r j a x n S / ; Z g k s x h %(A) 1 Å (B) 2 Å (C) 1/2 Å (D) 4 Å

SECTION–II : Matrix-Match Type & SECTION–III : Integer Value Correct Type

[ .M

–II :e V D l& e y i d

&[ .M

–III :i . d e u lg i d

No question will be asked in section II and III / [ .M II ,o III e d b i 'u u g g A



P H Y S I C S


LTS-12/36 0000CT103115009


SECTION–IV : (Maximum Marks : 32)

[ .M–IV : ( v dre v d: 32)

This section contains EIGHT questions. The answer to each question is a SINGLE DIGIT INTEGER ranging from 0 to 9, both inclusive For each question, darken the bubble corresponding to the correct integer in the ORS Marking scheme :

+4 If the bubble corresponding to the answer is darkened0 In all other cases

b l [ k . M e s av B i z ' u g S a i z R ; s d i z ' u d k m Ÿ k j0 ls 9 r d] n k s u k s a ' k k f e y] d s c h p d k , d,dy v d ; i . d g S i z R ; s d i z ' u e s a ] v k s -v k j- , l- i j lg h i w . k k ± d d s v u q :i c q y c q y s d k s d k y k d j s a v a d u ; k s tu k :

+4 ; f n m Ÿ k j d s v u q :i c q y c q y s d k s d k y k f d ; k tk ; 0 v U ; lH k h v o L F k k v k s a e s a

1. A mass M = 8 kg is hanging vertically from a spring such that the extension in spring is 20 cm. A mass

of 1 kg gets torn from the original mass spontaneously and falls off. What is the maximum height

(in cm) reached by the remaining mass from its initial position?

Ê O ; e k uM = 8 kg f d lh f L i z a x ls ≈ / o k Z / k j y V d j g k g S rF k k f L i z a x e s a f o L r k j20 cm g S A b l e w y Ê O ; e k u ls1 kg Ê O ; e k u

v y x g k s d j u h p s f x j tk r k g S A ' k s " k Ê O ; e k u k j k b ld h i z k j f E H k d f L F k f r ls i z k I r v f / k d r e ≈ ° p k b Z(cm e s a) K k r d h f t; s A

2. A hypothetical planet of uniform density has a tunnel along its radius as shown in figure. A ball is

dropped in the tunnel. It collides with the end elastically. Find the minimum time T from start, after

which the ball reaches back the surface of planet after dropping. (Neglect time of collision)

Fill T250

in OMR sheet. G = 203

× 10 –111 Nm2/kg2, = 800 kg/m3

le :i ? k u R o o k y s , d d k Y i f u d x z g e s a b ld h f = T ; k d s v u q f n ' k , d lq j a x f p = k u q lk j c u h g q b Z g S A b

f x j k ; h tk r h g S tk s f lj s ls i z R ; k L F k :i ls V d j k r h g S A x s a n d k s f x j k u s d s c k n ; g i z k j E H k ls f d r u sT i ' p k r ~ x z g

d h lr g i j y k S V v k r h g S \T

250 d k e k u K k r d h f t; s A la ? k Í d k y d k s u x . ; e k f u ; s AG =

20

3 × 10 –111 Nm2/kg2,

= 800 kg/m3 y h f t; s A

– 3R ——

2




P H Y S I C S

LTS-13/360000CT103115009

3. The time period of small oscillation of surface of liquid drop depends on its surface tension, density of

liquid and its mean radius. Find the time period by dimensional analysis. If we measure the mean

radius, it has error of 2%, surface tension and density both have an error of 1% . Find the percentage

error in measurment of time period.

Ê o c w a n d h lr g d s v Y i n k s y u d k v k o r Z d k y b ld s i ` " B r u k o] Ê o d s ? k u R o rF k k b ld h e k / ; f = T ; k

f o f e ; f o/ k h k j k v k o r Z d k y K k r d h f t; s A e k / ; f = T ; k d k s e k i u s i j b le s a2% = q f V rF k k i ` " B r u k o o ? k u R o n k s u k s1%

d h = q f V i k ; h tk r h g S A v k o r Z d k y d s e k i u e s a i z f r ' k r = q f V K k r d h f t; s A

4. Find the current 'i' required (in ampere) to have the temperature of cylindrical tungsten wire as 3000K

in steady state. Assume that the wire acts like a black body & its resistivity increases linearly with

temperature. (R = 0 at 0 K) (Take :d

dT = 368

10 m / K 9

, r = 2mm, 8 2 41710 W / m K

3 ). Fill

approximate value of 50 i in OMR sheet.

f d lh c s y u k d k j V a x L V u r k j d s r k i e k u d k s L F k k ; h v o L F k k e s a3000K d j u s d s f y ; s v k o ' ; d / k k j ki d h x . k u k , f E i ; j e s a

d h f t; s A e k u k r k j d ` " . k f i . M d h r j g O ; o g k j d j r k g S , o a b ld h i z f r j k s / k d r k r k i e k u d s lk F k j S f [ k d

(0 K i j R = 0 g S A) ( d

dT = 368

10 m / K 9

, r = 2mm, 8 2 41710 W / m K

3 y h f t; s A) 50 i d k y xH k x

e k u K k r d h f t; s A

5. A rat is running on ice with speed v = m/s. Suddenly he decides to turn by 90° and want to keep

running with the same speed throughout. What is the least amount of time (in sec) he needes for such

a turn? Suppose that rat’s feet can move independently. Coefficient of friction between rat’s feet and

ice is 0.125. (Given: 2 = g) , d p w g kv = m/s p k y ls c Q Z i j n k S M + j g k g S A v p k u d o g90° d k s . k i j e q M + u s d k f u . k Z ; d j r k g S rF k k v c o

p k y ls n k S M + r k j g u k p k g r k g S A b l i z d k j e q M + u s d s f y ; s m ls y x u s o k y k v k o ' ; d U ; w u r e le ; (sec e s a ) K k r d h f t; s A e k u k

p w g s d s i S j L o r a = :i ls n k S M + ld r s g S A p w g s d s i S j k s a o c Q Z d s e/ ; ? k " k Z . k x q . k k a d0.125 g S A( f n ; k g S %2 = g)




P H Y S I C S


LTS-14/36 0000CT103115009

6. In a car race sound singals emitted by the two cars are detected by the detector on the straight track at

the end point of the race. Frequency observed are 330Hz & 360 Hz and the original frequency is

300 Hz of both cars. Race ends with the separation of 100m between the cars. Assume both cars move

with constant velocity and velocity of sound is 330 m/s. Find the time taken by winning car (in sec).

, d d k j j s l e s a n k s d k j k s a k j k m R lf tZ r / o f u la d s r k s a d k s lh / k s iF k i j j s l d s v a f r e f c U n q i j , d la lw tk r k g S A n tZ d h x ; h v k o ` f Ÿ k330Hz o 360 Hz g S tc f d n k s u k s a d k j k s a d h e w y v k o ` f Ÿ k300 Hz g S A j s l d s v a r e s a n k s u k s a

d s e/ ; n w j h100m g k s r h g S A e k u k n k s u k s a d k j s a f u ; r o s x ls x f r d j r h g S rF k k / o f u d k o s x330 m/s g S A f o ts r k d k j k j k f y ; k

x ; k le ; (sec e s a) K k r d h f t; s A

7. A part of circuit in a steady state along with the currents flowing in the branches, values of resistance

etc., are shown in the figure. Calculate the energy stored (in µJ) in the capacitor C = (0.125F)

L F k k ; h v o L F k k e s a f L F k r f d lh i f j iF k d s , d H k k x d k s f p = e s a n ' k k Z ; k x ; k g S f tle s a ' k k [ k k v k s a s

d s e k u b R ; k f n H k h i z n f ' k Z r g S A la / k k f j =C = (0.125F) e s a la f p r ≈ tk Z(µJ e s a) K k r d h f t; s A

1A

2A

13V

5

1

4

3

34V

2A

C

1A

8. A point light source on the main optical axis OO' is at the point A form its image at point B. When the

source was placed at the point B, then its image formed at the point C. Determine the modules of the

focal length F (in cm) of lens, if AB = 1cm, and BC =1

2 cm.

i z n f ' k Z r f p = e s a , d f c U n q i z d k ' k L = k s r e q [ ; i z d k f ' k d v kOO' i j f c U n qA i j g S rF k k b ld k i z f r f c E c f c U n qB i j c u r k

g S A L = k s r d k s f c U n qB i j j [ k n s u s i j b ld k i z f r f c E c f c U n qC i j c u r k g S A y s a l d h Q k s d l n w j hF (cm e s a) d k i f j e k . k K k r

d h f t; s ; f nAB = 1cm o BC =1

2 cm g k s A

ABCO O'





C H E M I S T R Y

LTS-15/360000CT103115009

PART-2 : CHEMISTRY

H x-2 : l ;u oK u


[ .M


: 32)


four option(s) is (are) correct.

For each question, darken the bubble(s) corresponding to all the correct option(s) in the ORS

Marking scheme :

+4 If only the bubble(s) corresponding to all the correct option(s) is (are) darkened

0 If none of the bubbles is darkened


b l [ k . M e s av B i z ' u g S a i z R ; s d i z ' u e s a p k j f o d Y i(A), (B), (C) rF k k (D) g S a A b u p k j f o d Y i k s a e s a ls,d ; ,d l v d f o d Y i lg h g S a A

i z R ; s d i z ' u e s a ] lH k h lg h f o d Y i ( f o d Y i k s a ) d s v u q :i c q y c q y s ( c q y c q y k s a ) d k s v k s -v k j- , l- e s v a d u ; k s tu k :


–2 v U ; lH k h v o L F k k v k s a e s a1. Consider a section of 2-D lattice

R

Choose the correct statements about the lattice from the following -

(A) The packing fraction of the lattice is nearly 0.91(B) The co-ordination number of any atom in the lattice is 6

(C) If a circular atom is placed in the void of the lattice section shown (without distorting the lattice)

then, maximum diameter of such atom is 0.155 R.

(D) If another such layer is placed over the voids of the layer shown then distance between the two

layers should be2 2

R 3

(where R is radius)

2-D tk y d d s , d ls D ' k u i j f o p k j d h f t; s &

R

f u E u e s a l s tk y d d s c k j s e s a lg h dF k u k s a d k p ; u d h f t; s &

(A) tk y d d k la d q y u i z H k k t y xH k x0.91 g S

(B) tk y d e s a f d lh H k h i j e k . k q d h le U o ; la [ ; k6 g S

(C) ; f n , d o ` r h ; i j e k . k q d k s f n [ k k ; s x ; s tk y d ls D ' k u d h f j f D r e s a j [ k f n ; k tk ; s ( f c u k tk y d d k s f o d `

r k s , s ls i j e k . k q d k v f / k d r e O ; k l 0.155 R g S

(D) f n [ k k ; h x ; h i j r d h f j f D r ; k s a d s ≈i j ; f n n w l j h , s lh i j r j [ k n h tk ; s r k s n k s i j r k s a d s e/ ; n w2 2

R

3 g k s u h p k f g ; s ( tg k °R f = T ; k g S )



C H E M I S T R Y


LTS-16/36 0000CT103115009


2. 1 mole each of benzene and toluene are mixed (ideal solution) at a given temperature. A total of 1 mole

has vaporised, at given pressure. Then, which of the following must be true for this equilibrium mixture?

[Given : ºBenzeneP x ; º

TolueneP y ]. Assume X, U, V", U', Z, V', Z' are various points on the curve.

(A) Total vapour pressure < x y2

(B) Total vapour pressure = x y

(C) In the graph,

U V''U'

V'Z'

ZY

X

T=const.

X =1Ban X =1Tol

v

0.5

P

the vapour pressure of equilibrium mixture may correspond to point V".

(D) If in the graph given in option(C), external pressure is isothermally increased, then last trace of

liquid will disappear at point Z.

f n ; s x ; s r k i ÿ e i j c s a th u rF k k V k W y q b Z u i z R ; s d d s1 e k s y d k s b l i z d k j f e y k ; k tk ; s (v k n ' k Z f o y ; u) f d f n ; s x ; s n

i j d q y 1 e k s y o k " i h d ` r g k s tk ; s r k s b l lk E ; f eJ . k d s f y ; s f u E u e s a ls d k S u lk lg h g k s u k p k f g ; s

[ f n ; k g S %ºP x c a s th u ; ºP y V k W y q b Z u ]. e k u s d hX, U, V", U', Z, V', Z' o ÿ i j f H k U u& f H k U u f c U n q g S A

(A) d q y o k " i n k c<x y

2

(B) d q y o k " i n k c= x y

(C) v k j s [ k e s a ]

U V''U'

V'Z'

ZY

X

T=const.

X =1Ban X =1Tol

v

0.5

P

lk E ; f eJ . k d k o k " i n k c f c U n qV" ls l E c f U / k r g k s ld r k g S(D) v k j s [ k(C) e s a f n ; s x ; s v k j s [ k e s a ; f n] c k ‚ ; n k c le r k i h ; :i ls c < r k g S r k s n z o d h v f U r e e k = k ]Z i j

f o y q I r g k s x h A




C H E M I S T R Y

LTS-17/360000CT103115009


3. During electro-osmosis of As2S

3 sol

(A) Sol particles move towards anode (B) Sol particles do not move in either direction

(C) Sol particles move towards cathode (D) Dispersion medium moves towards cathode

As2

S3

lk W y d s o S |q r i j k lj . k d s n k S j k u

(A) lk W y d s d . k , s u k s M d h v k s j x f r d j r s g S a(B) lk W y d s d . k f d lh H k h f n ' k k e s a x f r u g h a d j r s

(C) lk W y d s d . k d S F k k s M d h v k s j x f r d j r s g S a(D) i f j k s i . k e k / ; e d S F k k s M d h v k s j x f r d j r k g S a

4. Which of the following order is/are CORRECT ?

(A) N2O

3 (unsym) > N

2O

4 N – N bond length)

(B) N2O

3(unsym) < N

2O

4(N – N bond length)

(C) P –F(axial)

bond length < P – F(equatorial)

bond length in PF5

(D) N – N bond length in N2H

4 > N – N bond length in N

2F

4

f u E u e s a ls d k S u lk ÿ elg g S @ g S a \

(A) N2O

3 (unsym) > N

2O

4 N – N c a / k y E c k b Z

(B) N2O

3(unsym) < N

2O

4 N – N c a / k y E c k b Z

(C) PF5 e s aP –F

( v k h ; ) c a / k y E c k b Z< P – F

( f o " k q o r h ; ) c a / k y E c k b Z

(D) N2H

4 e s a N – N c a / k y E c k b Z> N

2F

4 e s a N – N c a / k y E c k b Z

5. Which of the following statements are CORRECT ?

(A) M(AA)3 has 3 stereo isomers (B) In Fe(CO)5 E.A.N. is 36(C) pn is bidentate unsymmetrical ligand (D) In [FeF

6]3–

0 > P

f u E u e s a ls d k S u ls dF k ulg g S \

(A) M(AA)3 d s 3 f = f o e le k o ; o h g k s r s g a S (B) Fe(CO)

5 e s aE.A.N, 36 g S

(C) pn, f n U r q d v le f e r f y x s . M g S (D) [FeF6]3– e s a

0 > P g S



C H E M I S T R Y


LTS-18/36 0000CT103115009


6. Which of the following reactions(s) involves carbanion intermediate ?

f u E u e s a ls d k S u lh v f H k f ÿ ; k v k s a e s a d k c Z Ω . k k ; u e/ ; o r h Z l f E e f y r g k s r k g S &

(A)ONa

O

NaOH, CaO(B)

O(i) CH MgBr 3

(ii) aq. acid

(C)

Cl

NO2

(i) aq. NaOH

(ii) H O2(D)

OHConc. H SO2 4

7. If (R) gives positive iodoform test then major product (T) is :

; f n (R) / k u k R e d v k ; k s M k s Q k e Z i j h k . k n s r k g S r k s e q [ ; m R i k n(T) g S &

+Cl

AlCl3 (P)O , h2 v

(Q) dil. (R) + SH SO2 4

Zn (T)

(A)

OH

(B)

CH –CH2 3

(C) (D) CH –C–CH –CH3 2 3

O

8. Which of the following reaction(s) will produce aromatic product ?

f u E u e s a ls d k S u lh v f H k f ÿ ; k , s a , s j k s e S f V d m R i k n c u k ; s x h &

(A) + Na (B)Conc. H SO2 4

O O

(C) + AlBr 3

Br

(D)

O O NH –NH2 2




C H E M I S T R Y

LTS-19/360000CT103115009



[ .M –I(ii) : ( v dre v d: 16)

This section contains TWO paragraphs.

Based on each paragraph, there will be TWO questions

Each question has FOUR options (A), (B), (C) and (D). ONE OR MORE THAN ONE of thesefour option(s) is (are) correct.


Marking scheme :

+4 If only the bubble(s) corresponding to all the correct option(s) is(are) darkened



b l [ k . M e s an v u q P N s n g S a

i z R ; s d v u q P N s n i jn i z ' u g S a

i z R ; s d i z ' u e s ap f o d Y i(A), (B), (C) rF k k (D) g S a A b u p k j f o d Y i k s a e s a,d ; ,d l v d f o d Y i lg h g S a A i z R ; s d i z ' u d s f y ,] lH k h lg h f o d Y i ( f o d Y i k s a ) d s v u q :i c q y c q y s ( c q y c q y k s a ) d k s v k s -v k j- , -

v a d u ; k s tu k :

+4 ; f n f lQ Z lH k h lg h f o d Y i ( f o d Y i k s a ) d s v u q :i c q y c q y s ( c q y c q y k s a ) d k s d k y k f d ; k tk ;

0 ; f n d k s b Z H k h c q y c q y k d k y k u f d ; k g k s


i 'u 9 ,o 10 d y; vu P N n

A '20 vol' H2

O2

solution undergoes decomposition. The decomposition is measured by titrating the

solution against KMnO4

(standardised) in acidic medium. Following data was obtained.

Time (mins) Vol. of KMnO4 used (ml)

0 20

5 15

10 11.25

Given : [ln 2 = 0.7 ; ln 3 = 1.1]

, d '20 vol' H2O

2 f o y ; u d k f o ? k V u g k s j g k g S A f o ? k V u d k s f o y ; u d s v E y h ; e k / ; e e s aKMnO

4( e k u d h d ` r)

d s f o :ºv u q e k i u k j k e k i k tk r k g S f u E u v k ° d M s a i z k I r g k s r s g S a A

le ; ( f e f u V ) i z ; k s x e s a f y ; s x ; sKMnO4 d k v k ; r u (ml)

0 20

5 15

10 11.25

f n ; k g S %[ln 2 = 0.7 ; ln 3 = 1.1]



C H E M I S T R Y


LTS-20/36 0000CT103115009


9. The time (in minutes) required for the decomposition to be half completed.

v k / k k f o ? k V u i w . k Z g k s u s e s a v k o ' ; d le ; ( f e f u V e s a ) g S &

(A) 11.67 min (B) 5.84 min (C) 2.92 min (D) 23.34 min

10. When the time for half completion is reached then,11.35

2 ml of such H

2O

2 sample is titrated against

0.1M KMnO4 in acidic medium. Find the volume of KMnO

4 used.

tc v f H k f ÿ ; k d s v k / k s i w . k Z g k s u s d k le ; v k r k g S r k s , s lsH2O

2 u e w u s d s11.35

2 ml d k s v E y h ; e k / ; e e s a0.1M KMnO

4

d s f o :ºv u q e k f i r f d ; k tk r k g S ] r k s i z ; k s x e s a v k ; sKMnO4 d k v k ; r u K k r d h f t; s \

(A) 20 ml (B) 33.33 ml (C) 100 ml (D) 50 ml




C H E M I S T R Y

LTS-21/360000CT103115009


i 'u 11 ,o 12 d y; vu P N n

C D+ A B

Red ppt.WhiteBlack

NH OH4 K CrO2 4

Na CO2 3

E Yellow

C F+ G+Black Yellow Gas

C D+ A B

y k y v o k s lQ s n d k y k

NH OH4 K CrO2 4

Na CO2 3

E i h y k

C F+ G+

d k y k i h y k x S l 11. Which of the following statements is/are CORRECT.

(A) 'A' does not show disproportionation reaction in ammonia solution.

(B) 'G' gives reaction with acidified dichromate.

(C) Sulphide salt of metal presenting in 'C' is soluble in aqua regia

(D) 'A' gives green colour ppt with KI (not in excess)

f u E u e s a ls d k S u ls dF k ulg g S @ g S a \(A) v e k s f u ; k f o y ; u e s a'A' f o " k e k u q i k r u v f H k f ÿ ; k i z n f ' k Z r u g h a d j r k g S(B) 'G', v E y h ; M k b ÿ k s e s V d s lk F k v f H k f ÿ ; k n s r k g S(C) 'C' e s a m i f L F k r / k k r q d k lY Q k b M y o . k , D o k j s f t; k e s a f o y s ; ' k h y g S(D) 'A' , KI ( v k f / k D ; e s a u g h a) d s lk F k g j s j a x d k v o k s i n s r k g S

12. Which of the following statement(s) is/are INCORRECT for compound 'B' .

(A) In anionic part of compound B central atom has maximum oxidation state.

(B) B is Ag2CrO

4

(C) Anionic part of compound B has tetra-hedral shape

(D) Cationic part is monatomic specie.

f u E u e s a ls d k S u ls dF k u ; k S f x d'B' d s f y ,xyr g S @ g S a \(A) ; k S f x dB d s Ω. k k ; f u d H k k x e s a d s U n z h ; i j e k . k q v f / k d r e v k W D lh d j . k v o L F k k j [ k r k g S A(B) B, Ag

2CrO

4 g S

(C) ; k S f x dB d s Ω . k k ; f u d H k k x d h v k d ` f r p r q " Q y d h ; g S(D) / k u k ; f u d H k k x] , d y i j e k f . o ; L i h ' k h t g S

SECTION–II : Matrix-Match Type & SECTION–III : Integer Value Correct Type [ .M–II : e V D l& e y i d & [ .M–III : i . d e u lg i d




C H E M I S T R Y


LTS-22/36 0000CT103115009



[ .M

–IV : ( v dre v d

: 32)

This section contains EIGHT questions.

The answer to each question is a SINGLE DIGIT INTEGER ranging from 0 to 9, both inclusive

For each question, darken the bubble corresponding to the correct integer in the ORS

Marking scheme :

+4 If the bubble corresponding to the answer is darkened

0 In all other cases

b l [ k . M e s av B i z ' u g S a

i z R ; s d i z ' u d k m Ÿ k j0 ls 9 r d] n k s u k s a ' k k f e y] d s c h p d k , d,dy v d ; i . d g S

i z R ; s d i z ' u e s a ] v k s -v k j- , l- i j lg h i w . k k ± d d s v u q :i c q y c q y s d k s d k y k d j s a



1. For the given latimer diagram

(such that x > y > z)

Ax+

E = 10V3

0

AZ+E = 2V1

0E = 3V2

0

Ay+

Find the value ofy 7z

x

f n ; s x ; s y s f V e j f p = . k d s f y ; s ]

( f tle s a x > y > z )

Ax+

E = 10V3

0

AZ+E = 2V1

0E = 3V2

0

Ay+

y 7z

x

d k e k u K k r d h f t; s A




C H E M I S T R Y

LTS-23/360000CT103115009


2. A H-like species has electron present in an excited state 'S' having 2 radial nodes. Number of nodal

planes for such a state is 3. If the energy of the state is same as that of 2nd excited state of Li2+ , then,

find the oxidation state of the H-like species, being talked about.

, d H- d s le k u L i h ' k h t e s a b y S D V ™ k s u m Ÿ k s f tr v o L F k k'S' e s a m i f L F k r g S A f tld s2 f = T ; h ; u k s M g S a , o a3 u k s M y r y g S

; f n v o L F k k d h ≈ tk ZLi2+ d h 2nd m Ÿ k s f tr v o L F k k d s le k u g S ] r k sH- le k u L i h ' k h t f tld s c k j s e s a ≈ i j c r k ; k x ; k

g S ] d h v k W D lh d j . k v o L F k k K k r d h f t; s A

3. Find the number of reactions, which give N2.

(I) (NH4)

2Cr

2O

7 (II) Ba(N

3)

2

(III) NH4Cl

(IV) 8NH3 (excess) + 3Cl

2

f u E u e s a ls , s lh v f H k f ÿ ; k v k s a d h la [ ; k c r k b ; s tk s N2 n s r h g a S A

(I) (NH4)

2Cr

2O

7 (II) Ba(N

3)

2

(III) NH4Cl

(IV) 8NH3 ( v k f / k D ; ) + 3Cl

2

4. Find the number of complexes/ion, which are low spin.

K 3[Fe(CN)

6], [Co(NH

3)

6]+3, [CoF

6]3– , [Mn(CN)

6]3–

f u E u e s a ls , s ls la d q y k s a @ v k ; u k s a d h la [ ; k c r k b ; s tk s f u E u p ÿ . k g S a A

K 3[Fe(CN)

6], [Co(NH

3)

6]+3, [CoF

6]3– , [Mn(CN)

6]3–

5. Number of moles of CO2

evolved during following reaction are :

f u E u v f H k f ÿ ; k d s n k S j k u m R lf tZ rCO2 d s e k s y k s a d h la [ ; k g S &

(i) O / H O3 2 2

(ii) gentle heat



C H E M I S T R Y


LTS-24/36 0000CT103115009


6. How many stereoisomers of following compound (M), individually can be used to form diastereomeric

mixture with (+) 2-methyl butanoic acid :

f u E u ; k S f x d(M) d s f d r u s f = f o e ~ le k o ; f o ; k s a d k ] i ` F k d& i ` F k d :i ls(+) 2- e s f F k y C ; w V s u k s b Z d v E y d s lk F k

d j k d j f o o f j e le k o ; o h f eJ . k c u k u s d s f y ; s i z ; k s x f d ; k tk ld r k g S A

CH –CH=CH–CH–CH=CH–CH3 3

OH

(M)

7. Number of compounds which consumes odd number of moles of CH3COCl / pyridine with per mole

of it.

, s ls ; k s f x d k s a d h la [ ; k c r k b ; s f tu d s i z f r e k s y d s f y ; sCH3COCl / f i j h f M u d s e k s y k s a d h f o " k e la [ ; k [ k p Z g k s

(i)

CH –OH2

CH –OH2

CH –OH2

(ii) NH2

HO OH (iii) CH –OH2

CH –OH2

(iv)

CHO

CH OH2

H

HOHH

H

OH

OH

OH

(v)

O

OH OH OHOH(vi)

OH OH

O

O

8. Total number of possible alkene obtained on dehydrohalogenation of (+) 2-chlorobutane with alc. KOH.

(+) 2- D y k s j k s C ; w V s u d k , s Y d k s g k W f y ;KOH d s lk F k f o g k b M ™ k s g S y k s tu h d j . k d j k u s i j i z k I r lE H k o , s Y d h

D ; k g S \




M A T H E M A T I C S

LTS-25/360000CT103115009

PART-3 : MATHEMATICS

H x

-3 :x . r


[ .M


: 32)




Marking scheme :

+4 If only the bubble(s) corresponding to all the correct option(s) is (are) darkened



b l [ k . M e s av B i z ' u g S a i z R ; s d i z ' u e s a p k j f o d Y i(A), (B), (C) rF k k (D) g S a A b u p k j f o d Y i k s a e s a ls,d ; ,d l v d f o d Y i lg h g S a A

i z R ; s d i z ' u e s a ] lH k h lg h f o d Y i ( f o d Y i k s a ) d s v u q :i c q y c q y s ( c q y c q y k s a ) d k s v k s -v k j- , l- e s v a d u ; k s tu k :


–2 v U ; lH k h v o L F k k v k s a e s a

1. If tangents are drawn from a point P(2,0) to the curve2 x

1 y3

which touches the curve at A and B,

then-

(A) AB is equal to 5

(B) area of triangle PAB is equal to5 5

4(C) triangle PAB is an equilateral triangle

(D) acute angle between the tangents is equal to1 5

tan4

; f n f c U n qP(2,0) ls o ÿ 2 x1 y

3 i j [ k h a p h x b Z L i ' k Z j s [ k k ; s a ] tk s o ÿ d k sA rF k kB i j L i ' k Z d j r h g S ] r c-

(A) AB c j k c j 5 g k s x k A

(B) f =H k q t PAB d k k s = Q y5 54

g k s x k A

(C) f =H k q t PAB le c k g q f =H k q t g k s x k A

(D) L i ' k Z j s [ k k v k s a d s e/ ; U ; w u d k s . k1 5tan

4

g k s x k A






LTS-26/36 0000CT103115009


2. Let a,b (a b) are two non-zero complex numbers satisfying 2 2 2 2a b a b 2a b , then-

(A)a

b is purely real (B)

a

b is purely imaginary

(C) |arg(a) – arg(b)| = (D) arg a arg b2

e k u ka,b (a b) n k s v ' k w U ; lf E eJ la [ ; k ; s a g S ] tk s2 2 2 2a b a b 2a b d k s lU r q " V d j r h g S ] r c -

(A)a

b ' k q º o k L r f o d g k s x k A (B)

a

b ' k q º d k Y i f u d g k s x k A

(C) |arg(a) – arg(b)| = (D) arg a arg b2

3. TP and TQ are pair of tangents drawn to parabola y2 = 4x at P(x1,y

1) and Q(x

2,y

2) where y

1y

2 > 0.

If 1

2

x16

x , then the locus of point T is a parabola whose-

(A) focus is25

,016

(B) vertex is (0,0)

(C) length of shortest focal chord is25

4(D) equation of director circle is 16x + 25 = 0

L i ' k Z j s [ k k v k s a d s ; q X eTP rF k kTQ, i j o y ; y2 = 4x d s f c U n qP(x1,y

1) rF k kQ(x

2,y

2) i j [ k h a p s x ; s g S ] tg k °y

1y

2 > 0 g S A

; f n 1

2

x 16x

g S ] r k s f c U n qT d k f c U n q iF k , d i j o y ; g S ] f tld k @ f tld h-

(A) u k f H k25

,016

g k s x h A (B) ' k h " k Z (0,0) g k s x k A

(C) y ? k q Ÿ k e u k H k h ; th o k d h y E c k b Z25

4 g k s x h A (D) f u ; k e d o ` Ÿ k d k le h d j . k16x + 25 = 0 g k s x k A

4. In an equilateral triangle, if inradius is a rational number, then-

(A) perimeter is always rational (B) area is always irrational

(C) circumradius is always rational (D) exradii are always rational le c k g q f =H k q t e s a ] ; f n v U r% f = T ; k , d i f j i s ; la [ ; k g S ] r c-

(A) i f j e k i ln S o i f j e s ; g k s x k A (B) k s = Q y ln S o v i f j e s ; g k s x k A

(C) i f j f = T ; k ln S o i f j e s ; g k s x h A (D) c k · f = T ; k ln S o i f j e s ; g k s x h A





LTS-27/360000CT103115009


5. Consider m

x x

nxn 2

n e 1 ex , x 0,

e

. Then -

(A) area enclosed by the graph of y = ƒ(x) and the x-axis is 1 square unit

(B) number of solutions of the equation ƒ(x) = ƒ –1(x) are 2.

(C) mlim m ƒ mx

is equal to 0.

(D) If r 1

g x ƒ rx

, then range of g(x) is (1,).

e k u k

x x

nxn 2

n e 1 ex ,x 0,

e

g S A r c-

(A) y = ƒ(x) d s v k j s [ k rF k kx- v k k j k i f j c º k s = Q y1 o x Z b d k b Z g k s x k A

(B) le h d j . k ƒ(x) = ƒ –1

(x) d s g y k s a d h la [ ; k2 g k s x h A(C)

mlim m ƒ mx

= 0

(D) ; f n r 1

g x ƒ rx

g S ] r k sg(x) d k i f j lj (1,) g k s x k A

6. If sin2(2x) + cos2(3y) + tan2(4z) + sin(2x) . cos(3y) + cos(3y) . tan(4z) + tan(4z) . sin(2x) < 0,

where x,y,z 0,2

, then possible value of (x + y + z) is-

; f n sin2(2x) + cos2(3y) + tan2(4z) + sin(2x) . cos(3y) + cos(3y) . tan(4z) + tan(4z) . sin(2x) < 0,

g S ] tg k °x,y,z 0,2

g S ] r k s(x + y + z) d s lE H k o e k u g k s a x s-

(A)11

12

(B)

7

6

(C)

5

4

(D)

3

2





LTS-28/36 0000CT103115009


7. Let y = ƒ(x) be a function satisfying the differential equation,2x 2dy

e 2xydx

such that 1

ƒ 02

,

then (Note : e denotes Napier's constant)

(A) ƒ(x) is bounded (B)

1

0

1ƒ x dx

2

(C)

1

0

e 1 ƒ x dx 1 (D) range of ƒ(x) is1

0,2

e k u ky = ƒ(x) , d Q y u g S ] tk s v o d y le h d j . k2x 2dy

e 2xydx

d k s b l i z d k j lU r q " V d j r k g S f d 1

ƒ 02

g S ]

r c ( u V: e u s f i ; j v p j d k s O ; D r d j r k g S)

(A) ƒ(x) i f j c º g k s x k (B) 1

0

1ƒ x dx

2

(C) 1

0

e 1 ƒ x dx 1 (D) ƒ(x) d k i f j lj1

0,2

g k s x k A

8. For the function2

x 1ƒ(x)

x 1

, which of the following hold(s) good ?

(A) Range of ƒ(x) is1

, (1, )2

.

(B) ƒ has a local maxima but no local minima.

(C) ƒ is continuous and differentiable everywhere in its domain.

(D)xlim ƒ(x) 1

Q y u2

x 1ƒ(x)

x 1

d s f y ,] f u E u e s a ls d k S u lk @ d k S u ls lR ; g k s x k @ g k s a x s \

(A) ƒ(x) d k i f j lj1

, (1, )2

g k s x k A

(B) ƒ d k , d L F k k u h ; m f P p " B f c U n q ] i j U r q L F k k u h ; f u f E u " B f c U n q u g h a g k s x k A(C) ƒ b ld s i z k U r e s a lo Z = la r r rF k k v o d y u h ; g k s x k A

(D)xlim ƒ(x) 1





LTS-29/360000CT103115009



[ .M –I(ii) : ( v dre v d: 16)

This section contains TWO paragraphs.

Based on each paragraph, there will be TWO questions

Each question has FOUR options (A), (B), (C) and (D). ONE OR MORE THAN ONE of these



Marking scheme :

+4 If only the bubble(s) corresponding to all the correct option(s) is(are) darkened



b l [ k . M e s an v u q P N s n g S a i z R ; s d v u q P N s n i jn i z ' u g S a i z R ; s d i z ' u e s ap f o d Y i(A), (B), (C) rF k k (D) g S a A b u p k j f o d Y i k s a e s a,d ; ,d l v d f o d Y i lg h g S a A i z R ; s d i z ' u d s f y ,] lH k h lg h f o d Y i ( f o d Y i k s a ) d s v u q :i c q y c q y s ( c q y c q y k s a ) d k s v k s -v k j- , - v a d u ; k s tu k :



i 'u 9 ,o 10 d y; vu P N n

Let z1 = 3 and z

2 = 7 represents two points M and N respectively on complex plane. Let the curve

C1 be the locus of point P(z) satisfying |z – z

1|2 + |z – z

2|2 = 10 and the curve C

2 be the locus of point

Q(z) satisfying |z – z1|

2

+ |z – z2|

2

= 16. e k u kz

1 = 3 rF k kz

2 = 7 lf E eJ le r y e s a ÿ e ' k % n k s f c U n q v k s aM rF k k N d k s n ' k k Z r k g S A e k u k o ÿC

1, f c U n qP(z) d k

f c U n q iF k g S ] tk s|z – z1|2 + |z – z

2|2 = 10 d k s l U r q " V d j r k g S rF k k o ÿC

2, f c U n qQ(z) d k f c U n q iF k g S ] tk s

|z – z1|2 + |z – z

2|2 = 16 d k s lU r q " V d j r k g S A

9. The locus of point from which tangents drawn to C1 and C

2 are perpendicular is-

m l f c U n q d k f c U n q iF k ] f tllsC1 rF k kC

2 i j [ k h a p h x b Z L i ' k Z j s [ k k ; s a y E c o r g S ] g k s x k-

(A) |z – 3| = 2 (B) z 5 5 (C) |z – 5| = 3 (D) |z – 5| = 4

10. The least distance between two curves C1 and C

2 is-

n k s o ÿ k s aC1 rF k kC2

d s e/ ; U ; w u r e n w j h g k s x h-

(A) 1 (B) 2 (C) 3 (D) 4





LTS-30/36 0000CT103115009



i 'u 11 ,o 12 d y; vu P N n

There are four boxes B1,B

2,B

3 and B

4. Box B

i has i cards and on each card a number is printed, the

numbers are from 1 to i. A box is selected randomly, the probability of selecting box Bi is

i

10 anda card is drawn. Let E

i represent the event that a card with number i is drawn.

e k u k p k j c k W D l B1,B

2,B

3 rF k kB

4 g S A c k W D l B

i e s ai d k M Z g S rF k k i z R ; s d d k M Z i j , d la [ ; k v a f d r g S ] tk s1 ls i r d

d s e/ ; g S A , d c k W D l ; k n ` P N ; k p q u k tk r k g S A c k W D l Bi d s p q u s tk u s d h i z k f ; d r k

i

10 rF k k , d d k M Z f u d k y k tk r k

g S A e k u kEi la [ ; k i o k y s d k M Z d k s f u d k y u s d h ? k V u k d k s n ' k k Z r k g S A

11. P(E1) is equal to-

P(E1) d k e k u g k s x k-

(A)1

10(B)

1

5(C)

1

4(D)

2

5

12. P(B3/E

2) is equal to-

P(B3/E

2) d k e k u g k s x k-

(A)1

4(B)

1

3(C)

1

2(D)

2

3

SECTION–II : Matrix-Match Type & SECTION–III : Integer Value Correct Type [ .M–II : e V D l& e y i d & [ .M–III : i . d e u lg i d






LTS-31/360000CT103115009


[ .M

–IV : ( v dre v d

: 32)

This section contains EIGHT questions.

The answer to each question is a SINGLE DIGIT INTEGER ranging from 0 to 9, both inclusive

For each question, darken the bubble corresponding to the correct integer in the ORS

Marking scheme :

+4 If the bubble corresponding to the answer is darkened

0 In all other cases

b l [ k . M e s av B i z ' u g S a

i z R ; s d i z ' u d k m Ÿ k j0 ls 9 r d] n k s u k s a ' k k f e y] d s c h p d k , d,dy v d ; i . d g S

i z R ; s d i z ' u e s a ] v k s -v k j- , l- i j lg h i w . k k ± d d s v u q :i c q y c q y s d k s d k y k d j s a



1. Let matrix

1 1 1 1

1

301 2015tan sec 2016 cot

3 2

1 1 4 1M cot tan tan 2sin sec 2016 cos

2 3 3 2016

2009 301cos cos 1 sec

2 3

,

then det.(2MT + adj.M) is equal to

e k u k v k O ; w g

1 1 1 1

1

301 2015tan sec 2016 cot

3 2

1 1 4 1M cot tan tan 2sin sec 2016 cos

2 3 3 2016

2009 301cos cos 1 sec

2 3

g S ]

r k sdet.(2MT + adj.M) d k e k u g k s x k Space for Rough Work /

dP p d ; d y, L u





LTS-32/36 0000CT103115009


2. Let P(x) be a polynomial satisfying 2

5x

x .P xlim 6

2x 3

. If P(1) = 3, P(3) = 7 and P(5) = 11, then the

value of P 6 5P 4

29

is equal to

e k u kP(x) , d c g q i n g S ] tk s 2

5x

x .P xlim 6

2x 3

d k s lU r q " V d j r k g S A ; f nP(1) = 3, P(3) = 7 rF k kP(5) = 11 g S ] r k s

P 6 5P 4

29

d k e k u g k s x k

3. Let P be the 7th term from the beginning and Q be the 7th term from the end in the expansion of

n

3

3

13

4

where n N. If

Q12

P , then n is equal to

e k u kn

3

3

13

4

, ( tg k ° n N ) d s i z lk j e s aP i z k j E H k ls7 o k ° i n rF k kQ v U r% ls7 o k ° i n g S A ; f n

Q12

P g S ]

r k sn d k e k u g k s x k

4. Number of triplets (a,b,c) of positive integers satisfying the equation

3 2 2

2 3 2

2 2 3

a 1 a b a c

ab b 1 b c 11

ac bc c 1

is equal to

le h d j . k

3 2 2

2 3 2

2 2 3

a 1 a b a c

ab b 1 b c 11

ac bc c 1

d k s lU r q " V d j u s o k y s / k u k R e d i w . k k ± d f = d k s a(a,b,c) d h la [ ; k g k s x h





LTS-33/360000CT103115009


5. Tangents are drawn from any point on the hyperbola 4x2 – 9y2 = 36 to the circle x2 + y2 – 9 = 0.

If the locus of the mid-point of the chord of contact is

22 2 2 2x y x y

9 4 9

, then is equal to

v f r i j o y ; 4x2

– 9y2

= 36 i j f L F k r f d lh f c U n q ls o ` Ÿ kx2

+ y2

– 9 = 0 i j L i ' k Z j s [ k k ; s a [ k h a p h x b Z g S A ; f n L

d s e/ ; f c U n q d k f c U n q iF k2

2 2 2 2x y x y

9 4 9

g S ] r k s d k e k u g k s x k

6. If and are the roots of the equation x2 – 6x + 12 = 0,

then the value of

8

24

8

126

2 1

is equal to

; f n rF k k le h d j . k x2 – 6x + 12 = 0 d s e w y g k s ] r k s

8

24

8

126

2 1

d k e k u g k s x k





LTS-34/36 0000CT103115009

Space for Rough Work / dP p d ; d y, L u

7. Let1

x 1 y 2 z 3L :

3 1 3

be a line and P : 4x + 3y + 5z = 50 be a plane. L

2 is the line in the plane

P and parallel to L1. If the equation of plane containing both the lines L

1 and L

2 and perpendicular to

plane P is 14x – by + 5z + d = 0 (b,d R), then (b – d) is equal to

e k u k1

x 1 y 2 z 3L :

3 1 3

, d j s [ k k g S rF k kP : 4x + 3y + 5z = 50 , d le r y g S A L

2 le r y P e s a , d j s [ k k g S ]

tk s L1 d s le k U r j g S A ; f n n k s u k s a j s [ k k v k s aL

1 rF k kL

2 d k s j [ k u s o k y s le r y d k le h d j . k ] tk s le r yP d s y E c o r

g S ]14x – by + 5z + d = 0 (b,d R) g k s ] r k s(b – d) d k e k u g k s x k

8. Let y = ƒ(x) be a real- valued differentiable function on R (the set of all real numbers) such that

ƒ(1) = 1. If ƒ(x) satisfies xƒ'(x) = x2 + ƒ(x) – 2, then the area bounded by ƒ(x) with x-axis between

ordinates x = 0 and x = 3 is equal to

e k u kR e s a( lH k h o k L r f o d la [ ; k v k s a d k le q P p ; ) y = ƒ(x) , d o k L r f o d e k u v o d y u h ; Q y u b l i z d k j g S f d ƒ(1) = 1 g S A ; f nƒ(x), xƒ'(x) = x2 + ƒ(x) – 2 d k s lU r q " V d j r k g S ] r k sƒ(x), x v k rF k k d k s f V ; k s ax = 0 rF k kx = 3 d s

e/ ; i f j c º k s = Q y g k s x k





LTS-35/360000CT103115009




OPTICAL RESPONSE SHEET / v V dy i l ' V:

11. The ORS is machine-gradable and will be collected by the invigilator at the end of the examination.

v k s - v k j- , l- e ' k h u& tk ° P ; g S rF k k ; g i j h k k d s le k i u i j f u j h k d d s k j k , d = d j f y ; k tk ; s x k A12. Do not tamper with or mutilate the ORS. / v k s - v k j- , l- d k s g s j& Q s j@ f o œ f r u d j s a A13. Write your name, form number and sign with pen in the space provided for this purpose on the original. Do not write

any of these details anywhere else. Darken the appropriate bubble under each digit of your form number.

v i u k u k e] Q k W e Z u E c j v k S j v k s - v k j- , l- e s a f n , x , [ k k u k s a e s a d y e ls H k j s a v k S j v i u s g L r k k j d j s a A b uv k S j u f y [ k s a A Q k W e Z u E c j d s g j v a d d s u h p s v u q :i c q y c q y s d k s d k y k d j s a A

DARKENING THE BUBBLES ON THE ORS / v v ,l i c yc y d d y d u d o:

14. Use a BLACK BALL POINT PEN to darken the bubbles in the upper sheet.

≈ i j h e w y i ` " B d s c q y c q y k s a d k sd y c y o b V dye ls d k y k d j s a A15. Darken the bubble COMPLETELY / c q y c q y s d k si . :i l d k y k d j s a A16. Darken the bubbles ONLY if you are sure of the answer / c q y c q y k s a d k sr d k y k d j s a tc v k i d k m Ÿ k j f u f ' p r g k s A

17. The correct way of darkening a bubble is as shown here :

c q y c q y s d k sd y d j u s d k m i ; q D r r j h d k ; g k ° n ' k k Z ; k x ; k g S:

18. There is NO way to erase or "un-darken" a darkened bubble

d k y s f d ; s g q ; s c q y c q y s d k s f e V k u s d k d k s b Z r j h d kug g S A19. The marking scheme given at the beginning of each section gives details of how darkened and not darkened

bubbles are evaluated.

g j [ k . M d s i z k j E H k e s a n h x ; h v a d u ; k s tu k e s ad y d; x; rF k kd y u d; x, c q y c q y k s a d k s e w Y ; k a f d r d j u s d k r j h d k f n x ; k g S A

20. Take g = 10 m/s2 unless otherwise stated.

g = 10 m/s2 i z ; q D r d j s a ] tc r d f d v U ; d k s b Z e k u u g h a f n ; k x ; k g k s A

I HAVE READ ALL THE INSTRUCTIONS

AND SHALL ABIDE BY THEM

e u l un ' d i< y; g v e m ud

vo'; i yu d: x d: x A

____________________________

Signature of the Candidate / i d g r

I have verified the identity, name and roll

number of the candidate, and that question

paper and ORS codes are the same.

e u i d i p; u e v Q e u c d i

y; d i 'u i= r v v ,l d M n u le u g A

____________________________

Signature of the invigilator / u d d g r

NAME OF THE CANDIDATE / i d u e.................................................................................

FORM NO / Q e u c..............................................

Corporate Office : CAREER INSTITUTE, “SANKALP”, CP-6, Indra Vihar, Kota (Rajasthan)-324005

1505 lts paper 2 aiot dlp

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