25.0 m monopole comparative study
TRANSCRIPT
-
7/30/2019 25.0 m Monopole Comparative Study
1/26
FAST PLANETS ENGINEERING DESIGN
Project Name:
Designed by: FCFalgui Date:
ANALYSIS OF MONOPOLE
SECTION 1Analysis Criteria:
Determine Wind Pressures
H = 45 m Heightof Monopole
V = 39 m/s Basic Design Wind speed for the structure
GH = 1.69 Gust Response of Monopole as per Section 2.3.4.2
To satisfy Section 2.3.9.3 , Calculate pressures on each section using two parts
SECTION PROPERTIES
h = 33.84 m Section base elevation
L = 11.28 m Length of section
DB = 0.752 m Bottom Diameter of Section
DM = 0.655 m Midpoint Diameter of Section
DT = 0.558 m Top Diameter of Section
CALCULATIONS
y1 = [(2DT + DM)/3(DT + DM)]*(L/2) Center of A1 of Section from midbase
y1 = 2.744830998 m
y2 = [(2DM + DB)/3*(DM + DB)]*(L/2) Center of A2 of Section from base
y2 = 2.755195451 m
A1 = (DT + DM)*(L/2)/2
A1 = 3.42066 sqm Area of Top Section
A2 = (DM + DB)*(L/2)/2
A2 = 3.96774 sqm Area of Bottom Section
z1 = h + L/2 + y1 Distance of center of A1 to base of section
z1 = 42.224831 m
z2 = h + y2 Distance of center of A2 to base of section
z2 = 36.59519545 m
Kz1 = (z1/10)^2/7 Exposure Coefficient at A1
Kz1 = 1.509145143 1 < Kz < 2.58
-
7/30/2019 25.0 m Monopole Comparative Study
2/26
Kz1 = 1.509 Input Value
Kz2 = (z2/10)^2/7 Exposure Coefficient at A2
Kz2 = 1.448691431 1 < Kz < 2.58
Kz2 = 1.448 Input Value
qz1 = 0.613*Kz1*v^2 Velocity Pressure at A1
qz1 = 1406.950857
qz2 = 0.613*Kz2*v^2 Velocity Pressure at A2
qz2 = 1350.076104
F1= GH*qz1*A1
F1 = 8133.463876 N
F1 = 8.133463876 kN
F2= GH*qz2*A2
F2 = 9052.909124 N
F2 = 9.052909124 kN
F1*z1 = 343.4341376 kN-m
F2*z2 = 331.2929788 kN-m
z equivalent = (F1*z1 + F2*z2)/(F1+ F2) Equivalent Distance of the center of the Secti
z equivalent = 39.25942468 m
qzequivalent = (F1 + F2)/(1.69*(A1 + A2) Equivalent Velocity Pressure of Section
qzequivalent = 1376.407812 kPa
Kzequivalent = (zequivalent/10)^2/7 Equivalent Exposure of the Section
Kzequivalent = 1.478072444
GH*qzequivalent*AT = 17186.37
C = (Kzequivalent^0.50)*V*Dp
C = 28.64507602 > 8.7 Table 1
CF = 0.72 Input value as per Table 1
-
7/30/2019 25.0 m Monopole Comparative Study
3/26
ONSULTANTS
-
7/30/2019 25.0 m Monopole Comparative Study
4/26
on to its base
-
7/30/2019 25.0 m Monopole Comparative Study
5/26
FAST PLANETS ENGINEERING DESIGN C
Project Name:
Designed by: FCFalgui Date:
ANALYSIS OF MONOPOLESECTION 2
Analysis Criteria:
Determine Wind Pressures
H = 45 m Heightof Monopole
V = 39 m/s Basic Design Wind speed for the structure
GH = 1.69 Gust Response of Monopole as per Section 2.3.4.2
To satisfy Section 2.3.9.3 , Calculate pressures on each section using two parts
SECTION PROPERTIES
h = 22.79 m Section base elevation
L = 11.05 m Length of section
DB = 0.929 m Bottom Diameter of Section
DM = 0.834 m Midpoint Diameter of Section
DT = 0.74 m Top Diameter of Section
CALCULATIONS
y1 = [(2DT + DM)/3(DT + DM)]*(L/2) Center of A1 of Section from midbase
y1 = 2.707507 m
y2 = [(2DM + DB)/3(DM + DB)]*(L/2) Center of A2 of Section from base
y2 = 2.712881 m
A1 = (DT + DM)*(L/2)/2
A1 = 4.348175 sqm Area of Top Section
A2 = (DM + DB)*(L/2)/2
A2 = 4.870288 sqm Area of Bottom Section
z1 = h + L/2 + y1 Distance of center of A1 to base of sectionz1 = 31.02251 m
z2 = h + y2 Distance of center of A2 to base of section
z2 = 25.50288 m
Kz1 = (z1/10)^2/7 Exposure Coefficient at A1
Kz1 = 1.381901 1 < Kz < 2.58
-
7/30/2019 25.0 m Monopole Comparative Study
6/26
Kz1 = 1.381 Input Value
Kz2 = (z2/10)^2/7 Exposure Coefficient at A2
Kz2 = 1.306672 1 < Kz < 2.58
Kz2 = 1.306 Input Value
qz1 = 0.613*Kz1*v^2 Velocity Pressure at A1
qz1 = 1287.607
qz2 = 0.613*Kz2*v^2 Velocity Pressure at A2
qz2 = 1217.679
F1= GH*qz1*A1
F1 = 9461.872 N
F1 = 9.461872 kN
F2= GH*qz2*A2
F2 = 10022.46 N
F2 = 10.02246 kN
F1*z1 = 293.531 kN-m
F2*z2 = 255.6015 kN-m
z equivalent (F1*z1 + F2*z2)/(F1+ F2) Equivalent Distance of the center of the Secti
z equivalent 28.18329 m
qzequivalent (F1 + F2)/(1.69*(A1 + A2) Equivalent Velocity Pressure of Section
qzequivalent 1250.663 kPa
Kzequivalent (zequivalent/10)^2/7 Equivalent Exposure of the Section
Kzequivalent 1.34452
GH*qzequivalent*AT = 19484.33
C = (Kzequivalent^0.50)*V*Dp
C = 26.61903 > 8.7 Table 1
CF = 0.72 Input value as per Table 1
-
7/30/2019 25.0 m Monopole Comparative Study
7/26
ONSULTANTS
-
7/30/2019 25.0 m Monopole Comparative Study
8/26
on to its base
-
7/30/2019 25.0 m Monopole Comparative Study
9/26
FAST PLANETS ENGINEERING DESIGN C
Project Name:
Designed by: FCFalgui Date:
ANALYSIS OF MONOPOLESECTION 3
Analysis Criteria:
Determine Wind Pressures
H = 45 m Heightof Monopole
V = 39 m/s Basic Design Wind speed for the structure
GH = 1.69 Gust Response of Monopole as per Section 2.3.4.2
To satisfy Section 2.3.9.3 , Calculate pressures on each section using two parts
SECTION PROPERTIES
h = 12.04 m Section base elevation
L = 10.75 m Length of section
DB = 1.1 m Bottom Diameter of Section
DM = 1.01 m Midpoint Diameter of Section
DT = 0.917 m Top Diameter of Section
CALCULATIONS
y1 = [(2DT + DM)/3(DT + DM)]*(L/2) Center of A1 of Section from midbase
y1 = 2.644266 m
y2 = [(2DM + DB)/3(DM + DB)]*(L/2) Center of A2 of Section from base
y2 = 2.649289 m
A1 = (DT + DM)*(L/2)/2
A1 = 5.178813 sqm Area of Top Section
A2 = (DM + DB)*(L/2)/2
A2 = 5.670625 sqm Area of Bottom Section
z1 = h + L/2 + y1 Distance of center of A1 to base of sectionz1 = 20.05927 m
z2 = h + y2 Distance of center of A2 to base of section
z2 = 14.68929 m
Kz1 = (z1/10)^2/7 Exposure Coefficient at A1
Kz1 = 1.220041 1 < Kz < 2.58
-
7/30/2019 25.0 m Monopole Comparative Study
10/26
Kz1 = 1.22 Input Value
Kz2 = (z2/10)^2/7 Exposure Coefficient at A2
Kz2 = 1.116127 1 < Kz < 2.58
Kz2 = 1.116 Input Value
qz1 = 0.613*Kz1*v^2 Velocity Pressure at A1
qz1 = 1137.495
qz2 = 0.613*Kz2*v^2 Velocity Pressure at A2
qz2 = 1040.647
F1= GH*qz1*A1
F1 = 9955.576 N
F1 = 9.955576 kN
F2= GH*qz2*A2
F2 = 9972.892 N
F2 = 9.972892 kN
F1*z1 = 199.7016 kN-m
F2*z2 = 146.4947 kN-m
z equivalent (F1*z1 + F2*z2)/(F1+ F2) Equivalent Distance of the center of the Secti
z equivalent 17.37194 m
qzequivalent (F1 + F2)/(1.69*(A1 + A2) Equivalent Velocity Pressure of Section
qzequivalent 1086.876 kPa
Kzequivalent (zequivalent/10)^2/7 Equivalent Exposure of the Section
Kzequivalent 1.17092
GH*qzequivalent*AT = 19928.47
C = (Kzequivalent^0.50)*V*Dp
C = 19.90435 > 8.7 Table 1
CF = 0.72 Input value as per Table 1
-
7/30/2019 25.0 m Monopole Comparative Study
11/26
ONSULTANTS
-
7/30/2019 25.0 m Monopole Comparative Study
12/26
on to its base
-
7/30/2019 25.0 m Monopole Comparative Study
13/26
FAST PLANETS ENGINEERING DESIGN C
Project Name:
Designed by: FCFalgui Date:
ANALYSIS OF MONOPOLESECTION 4
Analysis Criteria:
Determine Wind Pressures
H = 45 m Heightof Monopole
V = 39 m/s Basic Design Wind speed for the structure
GH = 1.69 Gust Response of Monopole as per Section 2.3.4.2
To satisfy Section 2.3.9.3 , Calculate pressures on each section using two parts
SECTION PROPERTIES
h = 0 m Section base elevation
L = 11.85 m Length of section
DB = 1.269 m Bottom Diameter of Section
DM = 1.168 m Midpoint Diameter of Section
DT = 1.067 m Top Diameter of Section
CALCULATIONS
y1 = [(2DT + DM)/3(DT + DM)]*(L/2) Center of A1 of Section from midbase
y1 = 2.917875 m
y2 = [(2DM + DB)/3(DM + DB)]*(L/2) Center of A2 of Section from base
y2 = 2.921574 m
A1 = (DT + DM)*(L/2)/2
A1 = 6.621188 sqm Area of Top Section
A2 = (DM + DB)*(L/2)/2
A2 = 7.219613 sqm Area of Bottom Section
z1 = h + L/2 + y1 Distance of center of A1 to base of sectionz1 = 8.842875 m
z2 = h + y2 Distance of center of A2 to base of section
z2 = 2.921574 m
Kz1 = (z1/10)^2/7 Exposure Coefficient at A1
Kz1 = 0.965475 1 < Kz < 2.58
-
7/30/2019 25.0 m Monopole Comparative Study
14/26
Kz1 = 1 Input Value
Kz2 = (z2/10)^2/7 Exposure Coefficient at A2
Kz2 = 0.703593 1 < Kz < 2.58
Kz2 = 1 Input Value
qz1 = 0.613*Kz1*v^2 Velocity Pressure at A1
qz1 = 932.373
qz2 = 0.613*Kz2*v^2 Velocity Pressure at A2
qz2 = 932.373
F1= GH*qz1*A1
F1 = 10433.07 N
F1 = 10.43307 kN
F2= GH*qz2*A2
F2 = 11376.02 N
F2 = 11.37602 kN
F1*z1 = 92.25836 kN-m
F2*z2 = 33.23588 kN-m
z equivalent (F1*z1 + F2*z2)/(F1+ F2) Equivalent Distance of the center of the Secti
z equivalent 5.754217 m
qzequivalent (F1 + F2)/(1.69*(A1 + A2) Equivalent Velocity Pressure of Section
qzequivalent 932.373 kPa
Kzequivalent (zequivalent/10)^2/7 Equivalent Exposure of the Section
Kzequivalent 0.853937
GH*qzequivalent*AT = 21809.09
C = (Kzequivalent^0.50)*V*Dp
C = 38.45403 > 8.7 Table 1
CF = 0.72 Input value as per Table 1
-
7/30/2019 25.0 m Monopole Comparative Study
15/26
ONSULTANTS
-
7/30/2019 25.0 m Monopole Comparative Study
16/26
on to its base
-
7/30/2019 25.0 m Monopole Comparative Study
17/26
FAST PLANETS ENGINEERING DESIGN C
Project Name:
Designed by: FCFalgui Date:
ANALYSIS OF MONOPOLESECTION 5
Analysis Criteria:
Determine Wind Pressures
H = 25 m Height of Monopole
V = 39 m/s Basic Design Wind speed for the structure
GH = 1.69 Gust Response of Monopole as per Section 2.3.4.2
To satisfy Section 2.3.9.3 , Calculate pressures on each section using two parts
SECTION PROPERTIES
h = 0 m Section base elevation
L = 0 m Length of section
DB = 0 m Bottom Diameter of Section
DM = 0 m Midpoint Diameter of Section
DT = 0 m Top Diameter of Section
CALCULATIONS
y1 = [(2DT + DM)/3(DT + DM)]*(L/2) Center of A1 of Section from midbase
y1 = 0 m
y2 = [(2DM + DB)/3(DM + DB)]*(L/2) Center of A2 of Section from base
y2 = 0 m
A1 = (DT + DM)*(L/2)/2
A1 = 0 sqm Area of Top Section
A2 = (DM + DB)*(L/2)/2
A2 = 0 sqm Area of Bottom Section
z1 = h + L/2 + y1 Distance of center of A1 to base of section
z1 = 0 m
z2 = h + y2 Distance of center of A2 to base of section
z2 = 0 m
Kz1 = (z1/10)^2/7 Exposure Coefficient at A1
Kz1 = 0
-
7/30/2019 25.0 m Monopole Comparative Study
18/26
Kz2 = (z2/10)^2/7 Exposure Coefficient at A2
Kz2 = 0
qz1 = 0.613*Kz1*v^2 Velocity Pressure at A1
qz1 = 0
qz2 = 0.613*Kz2*v^2 Velocity Pressure at A2
qz2 = 0
F1= GH*qz1*A1
F1 = 0 N
F1 = 0 kN
F2= GH*qz2*A2
F2 = 0 N
F2 = 0 kN
F1*z1 = 0 kN-m
F2*z2 = 0 kN-m
z equivalent (F1*z1 + F2*z2)/(F1+ F2) Equivalent Distance of the center of the Secti
z equivalent #DIV/0! m
qzequivalent (F1 + F2)/(1.69*(A1 + A2) Equivalent Velocity Pressure of Section
qzequivalent #DIV/0! kPa
Kzequivalent (zequivalent/10)^2/7 Equivalent Exposure of the Section
Kzequivalent #DIV/0!
GH*qzequivalent*AT = #DIV/0!
C = (Kzequivalent^0.50)*V*Dp
C = #DIV/0! > 8.7 Table 1
CF = 0.72 Input value as per Table 1
-
7/30/2019 25.0 m Monopole Comparative Study
19/26
ONSULTANTS
-
7/30/2019 25.0 m Monopole Comparative Study
20/26
on to its base
-
7/30/2019 25.0 m Monopole Comparative Study
21/26
FAST PLANETS ENGINEERING DESIGN C
Project Name:
Designed by: FCFalgui Date:
ANALYSIS OF MONOPOLESECTION 5
Analysis Criteria:
Determine Wind Pressures
H = 45 m Heightof Monopole
V = 39 m/s Basic Design Wind speed for the structure
GH = 1.69 Gust Response of Monopole as per Section 2.3.4.2
To satisfy Section 2.3.9.3 , Calculate pressures on each section using two parts
SECTION PROPERTIES
h = m Section base elevation
L = m Length of section
DB = m Bottom Diameter of Section
DM = m Midpoint Diameter of Section
DT = m Top Diameter of Section
CALCULATIONS
y1 = [(2DT + DM)/3(DT + DM)]*(L/2) Center of A1 of Section from midbase
y1 = 0 m
y2 = [(2DM + DB)/3(DM + DB)]*(L/2) Center of A2 of Section from base
y2 = 0 m
A1 = (DT + DM)*(L/2)/2
A1 = 0 sqm Area of Top Section
A2 = (DM + DB)*(L/2)/2
A2 = 0 sqm Area of Bottom Section
z1 = h + L/2 + y1 Distance of center of A1 to base of sectionz1 = 0 m
z2 = h + y2 Distance of center of A2 to base of section
z2 = 0 m
Kz1 = (z1/10)^2/7 Exposure Coefficient at A1
Kz1 = 0
-
7/30/2019 25.0 m Monopole Comparative Study
22/26
Kz2 = (z2/10)^2/7 Exposure Coefficient at A2
Kz2 = 0
qz1 = 0.613*Kz1*v^2 Velocity Pressure at A1
qz1 = 0
qz2 = 0.613*Kz2*v^2 Velocity Pressure at A2qz2 = 0
F1= GH*qz1*A1
F1 = 0 N
F1 = 0 kN
F2= GH*qz2*A2
F2 = 0 N
F2 = 0 kN
F1*z1 = 0 kN-m
F2*z2 = 0 kN-m
z equivalent (F1*z1 + F2*z2)/(F1+ F2) Equivalent Distance of the center of the Secti
z equivalent #DIV/0! m
qzequivalent (F1 + F2)/(1.69*(A1 + A2) Equivalent Velocity Pressure of Section
qzequivalent #DIV/0! kPa
Kzequivalent (zequivalent/10)^2/7 Equivalent Exposure of the SectionKzequivalent #DIV/0!
GH*qzequivalent*AT = #DIV/0!
C = (Kzequivalent^0.50)*V*Dp
C = #DIV/0! > 8.7 Table 1
CF = 0.72 Input value as per Table 1
-
7/30/2019 25.0 m Monopole Comparative Study
23/26
ONSULTANTS
-
7/30/2019 25.0 m Monopole Comparative Study
24/26
on to its base
-
7/30/2019 25.0 m Monopole Comparative Study
25/26
FAST PLANETS ENGINEERING DESIG
Project Name:
Designed by: FCFalgui Date:
ANALYSIS OF MONOPOLE
Analysis Criteria:
Determine Wind Pressures
H = 45 m Heightof Monopole
V = 39 m/s Basic Design Wind speed for the structure
GH = 1.69 Gust Response of Monopole as per Section 2.3.4.2
Qualifying Criteria for Force Coefficient, CF for Cantilevered Tubular pole Structures as per Se
C = iz^0.50)*V*Dp
C = 0 > 8.7 Table 1
CF = 0.72 Input value as per Table 1
F = qz*GH*CF*AR
OTM = F*zequivalent
SUMMARY
SECTION AG AR GH*qZ*AG F zequivalent OTM
1 7.3884 7.61005 17186.373 12.7454 39.2594247 500.378
2 9.2184625 9.49502 19484.32864 14.4496 28.1832913 407.237
3 10.849438 11.1749 19928.46839 14.779 17.3719445 256.739
4 13.8408 14.256 21809.09209 16.1736 5.75421661 93.0665
5 0 0 0 0 0 0
6 0 0 0 0 0 0
-
7/30/2019 25.0 m Monopole Comparative Study
26/26
CONSULTANTS
ction 2.3.5.2