28march2012 jaturapat pakkawanit 532118042

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[INC 281 MULTIDISCIPLINARY WORKSHOP WEEKLY REPORT]] March 28, 2012 Name- Surname Jaturapat Pakkawanit Student ID. 53211804 Group Name Bork-Korn-Thai Engineering Team Members Golf,Champ,Bank,June Product Design Team Members P.Dook-Dik,P.Friend,P.L,P.Ake Weekly Progress Calculating Ripple Voltage (Vripple) The output from a full wave bridge rectifier looks like this: If we add a smoothing capacitor the capacitor charges up to the peak value of voltage and the output stays steady at this value … until you connect a load to the power supply (RL). Now the output will look like this: As the output voltage from the bridge drops the capacitor discharges through the load and so a ripple voltage, Vripple, appears on the output from the supply .The size of this voltage depends on the load resistance, RL, the size of the smoothing capacitor, C, and the peak value of the output voltage, Vp, and is given by: where ∆t is the time between successive peaks of the output waveform from the rectifier circuit. This will be 10ms if the ac frequency is 50Hz and a full wave bridge rectifier circuit is used. (But 20ms if a half wave rectifier circuit is used; the question could specify a different supply frequency, eg 60Hz, which would also affect ∆t.) This formula is an approximation and assumes that the ripple voltage is small. If the ripple voltage exceeds ~10% this formula becomes increasingly inaccurate. Engineering Analysis Department of Control System and Instrumentation Engineering KING MONGKUT’s UNIVERSITY OF TECHNOLOGY THONBURI

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Page 1: 28march2012 jaturapat pakkawanit 532118042

[ ] March 28, 2012

Name-Surname Jaturapat PakkawanitStudent ID. 53211804

Group Name Bork-Korn-ThaiEngineering

Team MembersGolf,Champ,Bank,June

Product Design Team Members

P.Dook-Dik,P.Friend,P.L,P.Ake

Weekly ProgressCalculating Ripple Voltage (Vripple)The output from a full wave bridge rectifier looks like this:

If we add a smoothing capacitor the capacitor charges up to the peak value of voltage and the output stays steady at this value … until you connect a load to the power supply (RL). Now the output will look like this:

As the output voltage from the bridge drops the capacitor discharges through the load and so a ripple voltage, Vripple, appears on the output from the supply .The size of this voltage depends on the load resistance, RL, the size of the smoothing capacitor, C, and the peak value of the output voltage, Vp, and is given by: where ∆ t is the time between successive peaks of the output waveform from the rectifier

circuit. This will be 10ms if the ac frequency is 50Hz and a full wave bridge rectifier circuit is used. (But 20ms if a half wave rectifier circuit is used; the question could specify a different supply frequency, eg 60Hz, which would also affect ∆ t .)

This formula is an approximation and assumes that the ripple voltage is small. If theripple voltage exceeds ~10% this formula becomes increasingly inaccurate.Engineering Analysis

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KING MONGKUT’s UNIVERSITY OF TECHNOLOGY THONBURI