3.01 – review of lines flashing back to grade 10
TRANSCRIPT
3.01 – Review of 3.01 – Review of LinesLines
3.01 – Review of 3.01 – Review of LinesLines
Flashing Back to Grade 10Flashing Back to Grade 10
Goals for this Mini-Unit• Be able to find the equation of a
line through two points• Know how parallel and
perpendicular lines are related• Find the intersection of lines• Prove that line segments form
certain geometric shapes
Goals for this Mini-Unit
• Relate line segments to chords of circles
• Find the centre of a circle• Find the radius of a circle• Apply the distance and midpoint
formulae in circles
Review of Lines• Every straight line follows the
equation y = mx + b• m is the slope – a measure of how
steep the line is• m = rise = Δ y run Δ x• b is the y-intercept
Finding the Eq’n of a Line
• If a line has a slope of -3 and passes through the point (8, 1), what is its equation?
• y = -3x + b• 1 = -3(8) + b• 1 = -24 + b b = 25• y = -3x + 25
Finding the Eq’n of a Line
• A line passes through the points (3, 2) and (9, 12). Find its equation.
3
52
)3(3
52
3
53
5
6
10
39
212
b
b
b
bxy
m
33
5 xy
Working with Slopes• The symbol || means ‘parallel’• Parallel lines are always the same
distance apart; they never touch; their equations have the same slope
• The lines y = 2x + 10 and y = 2x – 5 are parallel – we can tell because they both have a slope of 2.
Working with Slopes• The symbol ┴ means ‘perpendicular’• Perpendicular lines intersect (cross) at
right angles; their equations have slopes which are negative reciprocals
• The lines y = ¼x – 20 and y = -4x + 1 are perpendicular, because ¼ and -4 are negative reciprocals of each other.
A Note on Naming• Typically in this unit we will be dealing
with line segments rather than lines. These are distinguished by putting a line over the two letters representing its endpoints.
• Often you will find several slopes – use subscripts to keep them identified.
Example• Refer to p. 222 of the textbook – we
are going to do #1 as an example.
• Our first step is to plot GOLD to see which sides ought to be parallel, and which are perpendicular.
6
4
2
-2
-4
-6
-8
-10
-12
-10 -5 5 10 15
G
O
L
D
Example• We expect GO to be parallel to LD
5
125
1238
66
GO
GO
GO
m
m
m
5
1249
111
LD
LD
m
m
Same slope, they are parallel
Example• We also expect OL to be parallel to
GD.
12
512
593
16
OL
OL
OL
m
m
m
12
548
116
GD
GD
m
m
Same slope, they are parallel
Example• In finding these 4 slopes, we can also
show that adjacent sides are perpendicular.
• is the negative reciprocal of
• Adjacent sides are therefore ┴
5
1212
5