6 - air breathing engines - turbojet
TRANSCRIPT
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Turbojet
nozzleintakecompressor
combustorturbine
i 1
2 3 4 e
a a
u, Pa
ui, Pi
Pi< Paui> u
u, Pa ui, Pi
Pi> Paui< u
u, Pa ui, Pi
Pi= Paui= u
before intake (subsonic)
ai: air is brought to intake from far upstream (where pressure
is ambient pressure and relative velocity is flight speed) with
possible acceleration or deceleration
i1: air is decelerated as it passes through the intake (diffuser)and reaches compressor inlet
12: air is compressed in a dynamic compressor
23: air (gases) is heated by burning fuel
34: air (gases) is expanded through a turbine, just enough toobtain power to drive the compressor
4e: air (gases) is accelerated and exhausted through the
exhaust nozzle (if not fully expanded, PePa)
design
point
high
speed
low
speed
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Ideal JetPropulsion Cycle
nozzleintakecompressor
combustorturbine
i 1 2 3 4 ea a
In ideal jet propulsion cycle the gases are expanded in a turbine to a pressure such that the
power produced by the turbine is just sufficient to drive the compressor
Due to flight speed, some compression can be achieved in diffuser, prior to compressor entry
Assume:o compression (diffuser+compressor) and expansion (turbine+nozzle) is adiabatic and
reversible, i.e. isentropic
o Intake entry pressure (Pi) = ambient pressure (Pa), nozzle is fully expanded (Pe= Pa)
o Heat addition (combustor) is isobaric (simple frictionless heaters)
o Velocities through sections 14 (in compressor, combustor and turbine) are negligibleo Working fluid is air (calorically perfect, constant cp) with constant specific heat ratio ()
Ideal Brayton cycle: Isentropic compression
(compressor) and expansion (turbine),
Isobaric heat addition (combustor) and heatrejection (closed cycle)
Open cycleTemperature(T)
Specific entropy (s)
intake
compressor
turbine
nozzle
fully expanded (Pe= Pa)under expanded (Pe> Pa)
a
1
2
3
4
ee
iPican be Pa, depending on
the flight speed and design speed
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Intake
Intake (i1), ambient conditions at i:
o As velocity at 1 (compressor inlet) is assumed 0, P1and T1are the stagnationpressure (isentropic flow) and temperature for conditions a, i and 1
o No shaft work or heat transfer in the intake
1
/
Ambient: temperature (Ta) and pressure (Pa)
Flight speed (u) = /Ma
0, adiabatic 0, neglected 0, neglected
0
0, no shaft
work
i=a 1
Ta, Pa
,
T1, P1
diff
user
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Compressor
Compressor (12):
o Isentropic compression (adiabatic+reversible) with given pressure ratio (rp= P2/P1),
also velocities in the compressor are assumed negligibleo No heat transfer in the compressor (adiabatic), the shaft work done on the
compressor results in the enthalpy rise of air
/
0, adiabatic0, neglected 0, neglected
compressor
1 2
T1, P1
T2, P2
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Combustor
Combustor (23):
o With given fuel air ratio
and heating value of fuel , assuming f
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Turbine
Turbine (34):
o Turbine supplies just enough power to supply the compressor requirement:
o Since the process is adiabatic (no heat transfer), work (shaft) done by the turbine
results in enthalpy drop (assuming same air flow rate, )
o At the end of the turbine we still have high temperature and pressure gas to be
further expanded in the nozzle to generate high velocity stream
3 4
T3, P3
T4, P4
turbine
0, adiabatic0, neglected 0, neglected
equating compressor and turbine work
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Nozzle
Nozzle (4e), fully expanded (Pe= Pa):
o At nozzle inlet we have high pressure (P4) and temperature (T4) gas
o Nozzle inlet is assumed to have near zero velocity, nozzle exit at velocity (ue)
o In the nozzle there is no work or heat interaction, hence stagnationtemperature is constant
o The process is assumed to be isentropic
for fully expanded case
ambient pressure
2
1
using:
2 nozzle4 e
T4, P4
Te, Pe = Pa
0, adiabatic 0, neglected 0, neglected
0
0, no shaft
work
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Example (ideal jet propulsion cycle)
Given:
Turbojet flight speed (u) = 260 m/s
Ambient pressure (Pa) = 35 kPa, ambient temperature (Ta) = 40 C (233 K)
Compressor pressure ratio (rp) = 10, turbine inlet temperature T3= 1100 C (1373 K) Mass flow rate of air ( ) = 45 kg/s
cP= 1.005 kJ/kgK (1005 J/kgK), specific heat ratio (= 1.4)
Heating value of fuel (QR) = 45 MJ/kg
Find:
Velocity of gases at nozzle exit (ue) Propulsion efficiency (p)
Thermal efficiency (th)
Overall efficiency (o)
Solution:
Compressor inlet (diffuser outlet) condition (velocity ~ 0): process a1
233
267
/
35
./ .
56.4
Thrust (Th) Thrust power (Thu)
Rate of addition of kinetic energy
Chemical energy consumption rate
Fuel air ratio (f)
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Example (ideal jet propulsion cycle)
Combustor inlet (compressor outlet) condition (velocity ~ 0): process 12
10 56.4 564
/
267 10 . /. 515
Turbine inlet (combustor outlet) condition (velocity ~ 0): process 23
1373 564
Nozzle inlet (turbine outlet) condition (velocity ~ 0): process 34
1373 515 267 1125
564
..
281
Nozzle exit condition (fully expanded, Pe= Pa): process 4e
1125
..
620
2 2 1005 1125 620 1007 /
1.4 287 620 500 m/s ~2
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Example (ideal jet propulsion cycle)
Solution:
//
41%
Propulsion efficiency:
Thermal efficiency:
//
//
55%
Overall efficiency:
0.41 0.55 22.5%
Unusable enthalpy percentage:
45%
Thrust:
45 1007 260 33.6
Thrust power:
33615 260 8.74
Chemical energy consumption rate:
45 1005 1373 515 38.8
Fuel air ratio (f):
Assuming heating value (QR) = 45 MJ/kg:
0.02
Rate of addition of kinetic energy:
/ 2 /2
45 1007/2 260/2 21.30
Fuel flow rate is only 2% of air flow rate