8.2 f test - university of minnesota duluthrregal/documents/stat5411/5411... · 2006. 9. 7. ·...
TRANSCRIPT
.- 8.2 F test
We want to compare treatment groups.
Fishing line t = 3 groups
Stren Trilene XL Trilene XT11.1 11.5 11.611.1 11.3 11.8
11.1 11.4 11.7
Treatment Groupi=l i=2 i-3
j = 1 Yll Y21 Y31j = 2 Y12 Y22 Y32
MeanYl,nlYl.
Y3,nsY3.
Y2,n2
th.
A dot (.) means sum or average over index"nl- - L.Jj=lYlj
Yl. - nl
y.. = overall mean
- - Ei Ej Yij - EtniiJi.Y.. - E ni - ni
= weighted average of Yi.'s2-
For most of the semester, we are assuming normal populations with equal variances...: <r/
\ //~L\
}A. 3
~(j"
t;fA~ /v.-1-
-
Population Sample SampleMean Size Mean
P,l nl Yl.J.t2 n2 Y2.
P,3 n3 Y3.
- - - - - - - - - - - -- - - - - -
To estimate (72,we pool sample variance:
82 - (nl-l)s~+(n2-1)s~+(n3-1)s~w - (nl-l)+(n2-1)+(na-l)
a weighted average (w stands for within group variance).We want to test Ho : J..Ll= J..L2 = J..L3 = .. .= J.Ltwhere t = # of treatment groups.Assuming all measurements are independent as in a completely randomized design.
Tyec.l + , T r~o-.t ~- 1 reo--t- ~
'I XI.>' 0 c) ~ -)t7'- ~
"'" )< 0 }(:. 0 .x * () ~ ~.- -_._- '---'--' ' - - '.---'---'--------
\-JI.
I
~~-
I
dJ~How much evidence we have for different J.L'Sdepends on how spread out (variable)the sample means are relative to the variability of individual points.
V ar(y' 8) = r:(~s.y,)2
y. = mean of all y values.
If J..L'Sare equal, V ar(y's) ~ ~ where n is the number of replicates in each group.If the J..Li'sare not equal, E(Var(y's)) > 0-2
Regardless of the J..Li'S,E( 8~) = 0-2.
F - nVar(y's)- ~- 2 - 2Sw Sw
F ~ 1 if J..Li'sare equal and~ > 1 if J..Li'Sare not equal
If the J..Li'sare equal, F has a Fisher's F distribution with t -1 df in the numeratorand r:(ni - 1) df in the denominator.
F test compares two variances, the variance of the sample means and the withingroup variance.ANOVA= Analysis of Variance.
For unequal ni
(- -
)2 0'2Y. - Y ~ -, .. niF = Eni(Yi-y_,)2 / 82t-l W
- ~- ----
.. Th~ terms in the F test are called mean squares.MSB = Eni(jJi-y..)2 = SSB
t-l . dfB
MSW - ~ni-l)8~ - ssw- (ni-l) - dfwSSW = ~ (n' - 1)~(Yij-yiJ2 = ~ ~ (y" - Y-. )
2~ ni-l ~3~.
This is an error sum of squares. error = Yij-Yi.. where Yij = jth value from the ith group
SSB + SSW = TSS (Total Sum of Squares)
TSS = ~ ~(Yij - y..)2= ~ ~ [(Yij - Yi.)+ (Yi.- y..)]2
= ~ ~(Yij - Yi.)2+ ~ ~(Yi. - y..)2+ ~ ~ (Yij- Yi.)(Yi.- y..)~ ~(Yi. - y..)2= ~ ni(Yi. - y..)2= SSB
~ ~ (Yij - Yd (Yi.- y..)= ~(Yi. - y..)~(Yij - Yi.)= ~(Yi. - y..) X 0
TSS = SSB + SSW
dfTotal = df B + df w
= (t - 1) + ~~=l(ni- 1)
= t -1 + ~ni - t
= (~ni) - 1
ANOVA Table
Source df sa MS FTreatments t - 1 SSB MSB MSB/MSWWithin ~(ni -1) SSW MSW = s~Total (~ni) - 1 TSS
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