8a-ex

Upload: adnandj

Post on 14-Apr-2018

215 views

Category:

Documents


0 download

TRANSCRIPT

  • 7/27/2019 8a-ex

    1/3

    8a-ex. Stress Transformation Examples Ex. 8a.1 Ex. 8a.2

    Back | Index | Next

    Example 8a.1

    Given: A welded plate supports a force of P = 50

    kN. The width of the plate W = 200 mm, and the

    thickness, t = 50 mm. The weld is at 30 from thevertical.

    Req'd: Determine the Normal Stress and Average

    Shear Stress in the weld.

    Sol'n:

    Step 1. The axial stress in the plate is:

    sx = P/A = P/(Wt) = 5.0 MPa

    Step 2. The Stress Transformation Equations are:

    Here, sy and txy are both zero, so the equations simplify to:

    sx' = 0.5 sx(1+cos2q) = stress normal to weld

    sy' = 0.5 sx (1cos2q)

    tx'y' = 0.5 sx (sin2q) = Ave. shear stress parallel to weld

    Therefore : sx' = 3.75 MPa, sy' = 1.25 MPa, tx'y' = 2.17 MPa

    Or, the normal and shear stresses acting on the weld are:

    sw = 3.75 MPa, |tw| = 2.17 MPa

    Note: the Principal of Invariance for the normal stresses is satisfied:

    sx' + sy' = sx + sy = 3.75 MPa + 1.25 MPa = 5.00 MPa

    Example 8a.2

    Given: An element is subjected to the following stress:

    sx = 10 ksi; sy = 20 ksi; txy = 5 ksi.

    Req'd:

    (a) If the element is rotated q = 15, determine the new stresses.

    (b) Determine the Principal Stresses and their Angles.

    (c) Determine Maximum In-Plane Shear Stress, tmax, the angles of the

    x. Examples http://strengthandstiffness.com/8_transformation/page_8a-ex.ht

    d 3 27.7.2013 23:04

  • 7/27/2019 8a-ex

    2/3

    vectors that are normal to the faces on which they act, and the

    associated normal stresses. Stress Element

    Sol'n:

    Step 1. For the element rotated by 15 :

    sx' = 13.2 ksi, sy' = 16.8 ksi, tx'y' = 6.83 ksi

    Step 2. Principal Stresses and Principal Angles.

    The Principal Stresses are:

    and occur at angles rotated byqp:

    For the element:

    sI = 22.1 ksi at qI = 67.5 sII = 7.93 ksi at qII = 113

    Step 3. Maximum Shear Stress.

    The Maximum In-Plane Shear Stress is:

    and act on element faces that have outward pointing vectors

    rotated by qs from the x-axis:

    Thus:

    tmax,1 = 7.07 ksi on face: qs,1 = 22.5

    tmax,2 = 7.07 ksi on face: qs,2 = 113

    ss,x

    = ss,y

    = save

    = 15 ksi

    A positivetmax means the shear stress causes a counterclockwise

    rotation on the face defined by qs. ... the shear stress on the xs

    face is positive.

    x. Examples http://strengthandstiffness.com/8_transformation/page_8a-ex.ht

    d 3 27.7.2013 23:04

  • 7/27/2019 8a-ex

    3/3

    A negative tmax means the shear stress causes a clockwise

    rotation on the face defined by qs... the shear stress on the xsface is negative.

    Top Back | Index | Next

    Updated: 05/23/09 DJD

    x. Examples http://strengthandstiffness.com/8_transformation/page_8a-ex.ht

    d 3 27 7 2013 23:04