9.2 using properties of matrices

23
Matrix- a rectangular arrangement of numbers in rows and columns Named with capital letters [ A ] Dimensions- row x column (2 x 4) 9.2 Using Properties of Matrices

Upload: liseli

Post on 10-Feb-2016

84 views

Category:

Documents


0 download

DESCRIPTION

9.2 Using Properties of Matrices. Matrix- a rectangular arrangement of numbers in rows and columns Named with capital letters [ A ] Dimensions- row x column (2 x 4). Element- each number in the matrix Named with lowercase letters and subscripts (a ₂ ₃ ) First number of subscript= row - PowerPoint PPT Presentation

TRANSCRIPT

Page 1: 9.2 Using Properties of Matrices

Matrix- a rectangular arrangement of numbers in rows and columns

Named with capital letters [ A ] Dimensions- row x column (2 x 4)

9.2 Using Properties of Matrices

Page 2: 9.2 Using Properties of Matrices

Element- each number in the matrix Named with lowercase letters and

subscripts (a₂₃) First number of subscript= row Second number of subscript=

column

Page 3: 9.2 Using Properties of Matrices

Using Matrices to Represent Points/Figures in Coordinate Planes

• Use 2 row matrices to represent the vertices on a 2-dimensional figure

• 1st row = x-coordinate• 2nd row= y-coordinate• Example: Point (2,3)= 2

3

Page 4: 9.2 Using Properties of Matrices

Represent figures using matricesWrite a matrix to represent the point or polygon.

a. Point A

b. Quadrilateral ABCD

Page 5: 9.2 Using Properties of Matrices

Represent figures using matricesSOLUTION

a. Point matrix for A

b. Polygon matrix for ABCD

x-coordinate

y-coordinate

–4

0

x-coordinates

y-coordinates

–4 –1 4 3

0 2 1 –1

A B C D

Page 6: 9.2 Using Properties of Matrices

Adding and subtracting matrices

5 15 5

0 11 –4=

6 – 1 8 –(–7) 5 – 0

4 – 4 9 – (– 2) –1 – 3=

5 + 1 –3 + 2

6 + 3 –6 + (– 4)=

6 –1

9 –10=

5 –3

6 –6

1 2

3 –4+

a.

6 8 5

4 9 –1–

1 –7 0

4 –2 3

b.

Page 7: 9.2 Using Properties of Matrices

In Exercises 3 and 4, add or subtract.3.[–3 7] + [2 –5]

SOLUTION

[–3 7] + [2 –5] =[–1 2 ]

4. 1 –4

3 –5–

2 3

7 8

SOLUTION

1 –4

3 –5–

2 3

7 8

–1 –7

–4 –13 =

Examples: Adding and subtracting matrices

Page 8: 9.2 Using Properties of Matrices

Represent a translation using matrices

The matrix represents ∆ABC. Find the image 1 5 3

1 0 –1matrix that represents the translation of ∆ABC 1 unit left and 3 units up. Then graph ∆ABC and its image.

SOLUTION

The translation matrix is

–1 –1 –1

3 3 3

Page 9: 9.2 Using Properties of Matrices

Represent a translation using matricesAdd this to the polygon matrix for the preimage to find the image matrix.

–1 –1 –1

3 3 3

Translation matrix

+1 5 3

1 0 –1

Polygon matrix

A B C0 4 2

4 3 2=

Image matrix

A′ B′ C′

Page 10: 9.2 Using Properties of Matrices

Multiplying matrices

Number of columns in matrix A= Number of rows in column B A X B = A B (mxn) x (nxp) (m x p) equal

1 0

4 5 Multiply 2 –3

–1 8 .

SOLUTION

The matrices are both 2 X 2, so their product is defined. Use the following steps to find the elements of the product matrix.

Page 11: 9.2 Using Properties of Matrices

Multiplying matricesSTEP 1

Multiply the numbers in the first row of the first matrix by the numbers in the first column of the second matrix. Put the result in the first row, first column of the product matrix.

1 0

4 5

2 –3

–1 8

1(2) + 0(–1) ?=

? ?

Page 12: 9.2 Using Properties of Matrices

Multiplying matrices

1 0

4 5

2 –3

–1 8

STEP 2

Multiply the numbers in the first row of the first matrix by the numbers in the second column of the second matrix. Put the result in the first row, second column of the product matrix.

1(2) + 0(–1) 1(–3) + 0(8)=

? ?

Page 13: 9.2 Using Properties of Matrices

Multiplying matricesSTEP 3

Multiply the numbers in the second row of the first matrix by the numbers in the first column of the second matrix. Put the result in the second row, first column of the product matrix.

1(2) + 0(–1) 1(–3) + 0(8)=

4(2) + 5(–1) ?

1 0

4 5 –1 8

2 –3

Page 14: 9.2 Using Properties of Matrices

Multiplying matricesSTEP 4

Multiply the numbers in the second row of the first matrix by the numbers in the second column of the second matrix. Put the result in the second row, second column of the product matrix.

=4(2) + 5(–1) 4(–3) + 5(8)

1(2) + 0(–1) 1(–3) + 0(8)1 0

4 5

2 –3

–1 8

Page 15: 9.2 Using Properties of Matrices

Multiplying matricesSTEP 5

Simplify the product matrix.

2 –3

3 28=

4(2) + 5(–1) 4(–3) + 5(8)

1(2) + 0(–1) 1(–3) + 0(8)

Page 16: 9.2 Using Properties of Matrices

Multiplying MatricesUse the matrices below. Is the product defined? Explain.

–3

4A = B = [2 1] C =

6.7 0

–9.3 5.2

6. AB

Yes; the number of columns in A is equal to the number of rows in B.

ANSWER

Page 17: 9.2 Using Properties of Matrices

Multiplying MatricesUse the matrices below. Is the product defined? Explain.

1. BA

ANSWER

Yes; the number of columns in B is equal to the number of rows in A.

–3

4A = B = [2 1] C =

6.7 0

–9.3 5.2

Page 18: 9.2 Using Properties of Matrices

Multiplying MatricesUse the matrices below. Is the product defined? Explain.

2. AC

ANSWER

No; the number of columns in A is not equal to the number of rows in C.

–3

4A = B = [2 1] C =

6.7 0

–9.3 5.2

Page 19: 9.2 Using Properties of Matrices

Examples of Multiplying MatricesMultiply.

1 0

0 1

3 8

–4 7

SOLUTION

=0(3) + 1(–4) 0(8) + 1(7)

1(3) + 0(–4) 1(8) + 0(7)1 0

0 1

3 8

–4 7=

3 8

–4 7

Page 20: 9.2 Using Properties of Matrices

Solve a real-world problemSOFTBALL

Two softball teams submit equipment lists for the season. A bat costs $20, a ball costs $5, and a uniform costs $40. Use matrix multiplication to find the total cost of equipment for each team.

Page 21: 9.2 Using Properties of Matrices

Solve a real-world problem

First, write the equipment lists and the costs per item in matrix form. You will use matrix multiplication, so you need to set up the matrices so that the number of columns of the equipment matrix matches the number of rows of the cost per item matrix.

SOLUTION

Page 22: 9.2 Using Properties of Matrices

Solve a real-world problem

EQUIPMENT COST TOTAL COST

Bats Balls Uniforms Dollars Dollars

Women

MenUniforms

13 42 16

15 45 18

BatsBalls

205

40

Women

Men

?

?=

=

Page 23: 9.2 Using Properties of Matrices

Solve a real-world problem

You can find the total cost of equipment for each team by multiplying the equipment matrix by the cost per item matrix. The equipment matrix is 2 3 and the cost per item matrix is 3 1, so their product is a 2 1 matrix.

13 42 16

15 45 18

205

40

13(20) + 42(5) + 16(40)=

15(20) + 45(5) + 18(40)=

1110

1245

The total cost of equipment for the women’s team is $1110, and the total cost for the men’s team is $1245.

ANSWER