a real variable method for the cauchy transform, and analytic capacity
TRANSCRIPT
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Lecture Notes in Mathematics Edited by A. Dold and B. Eckmann
1307
Takafumi Murai
A Real Variable Method for the Cauchy Transform, and Analytic Capacity
Springer-Verlag Berlin Heidelberg NewYork London Paris Tokyo
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Author
Takafumi Mural Department of Mathematics, Col lege of General Education
Nagoya University Nagoya, 464, Japan
Mathematics Subject Classif ication ( t980): Primary 3 0 C 8 5 ; secondary 4 2 A 5 0
ISBN 3-540-19091-0 Springer-Verlag Berlin Heidelberg New York ISBN 0-387-19091-0 Springer-Verlag New York Berlin Heidelberg
This work is subject to copyright. All rights are reserved, whether the whole or part of the material is concerned, specifically the rights of translation, reprinting, re-use of illustrations, recitation, broadcasting, reproduction on microfilms or in other ways, and storage in data banks. Duplication of this publication or parts thereof is only permitted under the provisions of the German Copyright Law of September 9, 1965, in its version of June 24, 1985, and a copyright fee must always be paid. Violations fall under the prosecution act of the German Copyright Law. © Springer-Verlag Berlin Heidelberg 1988 Printed in Germany Printing and binding: Druckhaus Beltz, Hemsbach/Bergstr. 2146/3140-543210
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PREFACE
The purpose of this lecture note is to study the Cauchy transform on curves
and analytic capacity. For a compact set F in the complex plane ~, H~(F c)
denotes the Banach space of bounded analytic functions in ~U{o~}-F (= F c) with
supremum norm il-i!H ~. The analytic capacity of F is defined by
~,(r) = sup{If'(~>l; IIflIH~_<_ ~, f~H~<rc)>,
where f'(-) : lim z(f(z)-f(m)). We also define
y+(F) = s u p t ( ] / 2 r r ) / d>; ilcultH~ =< 1, Cu~H'(rC), u >= 0},
where
C~(z) = (1 /2~ i )7 l / ( g - z ) d>(¢) ( z ¢ ( t h e suppor t of ~ ) ) .
We are concerned wi th e s t i m a t i n g y ( - ) and y + ( . ) . To do t h i s , compact s e t s hav ing
finite l-dimension Hausdorff measure are critical. Hence we assume that P is a
finite union of mutually disjoint smooth arcs. Let i'} denote the l-dimension
Hausdorff measure (the generalized length). Let LP(F) (lip! ~) denote the L p
space of functions on F with respect to the length element Idzl, and let
LI(F) denote the weak L 1 space of functions on F. Put
p(r) = i n f ~ (E) / iE I, %(r ) = i n f ~r+(E)/I~i,
where the infimums are taken over all compact sets E in F.
transform on F is defined by
Hrf(z) = ( i / ~ ) p .v . IF f ( ¢ ) / ( ~ - z ) id~] ( z ~ r ) .
Then we see that
p+(F) __< p(F) =< Const p+(F) I/3, Const p+(F) __< I/]IHFIILI(F),LI(F ) <= Const p+(F),
where NHFILI(F),LI(F) is the norm of H F as an operator from LI(F) to LI(F) w
(Theorem D). HenceWthe study of y(F) is closely related to the study of H F-
Here is a history of the study of the Cauchy transform on Lipschitz graphs.
According to Professor Igari, the L 2 boundedness of the Cauchy transform on
Lipschitz graphs was first conjectured by Professor Zygmund in his lecture at
Orsay in 1960's. Let F = {(x,A(x)); xE~}, a(x) = A'(x), where • is the real
line. Let C[a] denote the singular integral operator defined by a kernel
I/{(x-y)+i(A(x)-A(y))}. Then the above conjecture means the following assertion:
C[a] is bounded (from L2(~) to itself) if aEL~(~). The operator C[a] is
formally expanded in the following form: (-~)H + En=0(-i)n Tn[a], where H is
the Hilbert transform and Tn[a] is the singular integral operator defined by a
The Cauchy(-Hilbert)
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IV
kernel (A(x)-A(x))n/(x-y) n+l. In 1965, Calderdn [3] showed that Tl[a] is
bounded if aeL~(~) (Theorem A). This theorem is very important and closely
related to the BMO(R) theory, where BMO(~) is the Banach space, modulo constants,
of functions on • of bounded mean oscillation. Coifman-Meyer [8], [9] studied
Tn[a], Calder6n [4] showed that C[a] is bounded if llallL~(~ ) is sufficiently
small, and consequently Coifman-McIntosh-Meyer [7] solved the above conjecture in
the affirmative (Theorem B). David [17] studied H F for continuous curves F. It
is already known [44] that IIC[a]IIL2(R),L2(E) ~ Const(l 4-~BMO(~)) (Theorem C)
and that the square root is best possible [18]. Jones-Semmes gives a simple proof
of Theorem B by complex variable methods. (See Appendix II.)
As a first step of the study of H F for discontinuous curves F, we begin
with a review of the study of C[a]. In CHAP. I, g proofs of Theorem A will be
given. Once this theorem is known, we can easily deduce Theorem B (cf. CHAP. II),
and hence Theorem A is very important in the study of C[a]. As is easily seen,
if f, g E L2(~) have analytic extensions f(z), g(z) to the upper half plane
(such that limy÷~ f(iy) = limy+~ g(iy) = 0), then the Poisson extension of
(fg)(x) to the upper half plane is identical with f(z)g(z). This simple property
of analytic functions is essential in a proof of Theorem A by complex variable
methods. We shall give, in CHAP. I, various interpretations of this property from
the point of view of real analysis (cf. Coifman-Meyer-Stein [13]). These proofs
are, of course, mutually very close, but each proof has proper applications and is
interesting in itself.
In CHAP. II, we shall give the proofs of Theorems B and C by perturbation. Our
method is an improvement of Calder6n's perturbation [4] and David's perturbation
[17]. Put
o(C[a]) = sup(i/lli)/llC[a](xlf)(x)l dx,
where XI is the characteristic function of I and the supremum is taken over all
intervals I and all real-valued functions f with llfllL~(~) ~ i. This quantity
is comparable to IIC[a]IIL~(~),BMO(~) and convenient for our perturbation.
Considering a suitable Calderdn-Zygmund decomposition of a primitive A(x) of a(x)
on I, we obtain an a-priori estimate of CI/iII)/IIC[a](xIf)(x) I dx by moderate
graphs. (See the figure in § 2.2.) Repeating this argument infinitely many times
and estimating infinitely many error terms, we see that the boundedness of C[a]
is consequently reduced to the boundedness of H. For the proof, Theorem A is
necessary. We shall also give a proof of Theorem A by perturbation [45]. Tools
which we use are only the Calder6n-Zygmund decomposition and the covering lemma.
For the proof of Theorem C, we put
= sup(i/IIl)fiIC[a](xif)(x)i 2 f(x) dx, ~(C[a])
where the supremum is taken over all intervals I and all real-valued functions
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f with 0 ~ f ~ i. Then o(C[a]) 2 ~ Const $(C[a]). Since
II C[a](xlf)(x)f(x) dx = 0, this quantity behaves like a linear functional of
a(x), and this gives an a-priori estimate better than o(C[a]). Our method is not
short but very simple, and this is applicable to various kernels.
In CHAP. III, we shall study H F for discontinuous graphs F and shall
compare y(-) with integralgeometric quantities. We first give the proof of
Theorem D. As is well-known, planar Cantor sets are useful to construct various
examples (cfo Denjoy [23], Vitushkin [52]). Let Q0 = [0,i]~ [0,I] and let Qn
(n$1) be the union of 4 n closed squares with sides of length 4 -n obtained from
Qn-1 with each component of Qn-i replaced by four squares in the four corners of
the component. Put Q= = ~ n= 0 Qn" Then y(Q=) = 0 and IQ~I > 0 (Garnett [28]).
This shows that two classes of null sets of y(.) and I'I are different. We shall
try to give grounds to this example. We may consider that Qn is a graph. (See the
figure in § 3.3.) Let Tsl,..,Sn (Sl,..,s n6~) be the singular integral operator
defined by a kernel
i/{(x-y)+i(Asl ,..,an(x) - Asl ,..,an(y))},
• = _ _ (x) = 0 where Asl,..,sn~X) = s k ((k-l)/n < x < k/n, igkin) and Asl,..,Sn
(x£ [0,i)). Then we see that
max{o(T ); s I .... s n6~} Sl~-',S n
is comparable to ~ (Theorem G), and, if we neglect constant multiples, 0 0
an n-tuple (Sl,..,s n) obtained from a graph {(x,A 0 0(x)); x E [0,i)} similar ~l,..~Sn
to Qm (m = (the integral part of (log n)/4)) is a solution of this extremal
problem. Hence planar Cantor sets are worst curves in a sense. We shall also
generalize Qn" A segument [0,i) is called a (thick) crank of degree 0 and a
finite union F of segments parallel to the x-axis is called a (thick) crank of n
degree n, if F n is obtained from a crank Fn_ 1 of degree n-i with each
component J of Fn_ 1 replaced by a finite number of segments Jl,..,J2p
(p=p(J)) parallel to the x-axis such that iJk! = 2-PlJ[, the distance between
Jk and J is less than or equal to 2-PIJI (i < k j 2 p) and the projections of
these segments to ~ are mutually disjoint and contained in the projection of J.
We shall show that, for any crank F of degree n, IIHFIIL2(F),L2(F ) ~ Const /~n
and that this estimate is best possible (Theorem E). To prove this, we define n+l
singular integral operators {Tk}~= 0 such that T O = (-z)H,
T n are mutually almost llz~= 0 TkIIL2(~),L2(E ) = liHrIIL2(F),L2(F) and { k}k=0
orthogonal. Hence we see that the meaning of ~nn is the central limit theorem.
We define integralgeometric quantities Cr (.) (0<~<i) as follows. Let
D(z,r) be the open disk of center z and radius r. For a compact set E,
NE(r,0 ) (r>0,101%~) denotes the (cardinal) number of elements of ENL(r,0),
where i(r,0) is the straight line defined by the equation x cos 0 + y sin O = r.
We put
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VI
Cr (E) = lima+ 0 Cr~S)(E),
Cr(C)(E) = inf f :{f~ Ns{o~=iD(Zk,rk)}(r,8)~ dr} d~ (g>0)
n where O{Uk=iD(Zk,rk)} is the boundary of U~=iD(Zk,r k) and the infimum is
N taken over all finite coverings {D(Zk,rk)}k= 1 of E with radii less than c.
Since y(E) ~ Const CrI(E), it is interesting to compare y(-) with Cr (')
(cf. Marshall [37]). As an application of Theorem E, we shall show that, for
0<~<i/2, there exists a compact set E such that y(E ) = i and Cr (E) = 0
(Theorem F). For the proof, we use a branching process. Let {Xn}:= 1 be a
sequence of independent random variables on the standard probability space
([O,l),8,Prob) such that Prob(X n = ±i) = 1/2 (n~l), and let S O = O, N
S n = Ek= 1 X k (n~l). We define a Galton-Watson process {Yn}n=O by Y0(X) = i,
Yn(X) = Yn_l(X) + Syn_l(x)(X) (n~l). Then we see that, for n~l, there exists
k ~ Prob(Yn=k). a crank Fn of degree n such that Cr (F n) is comparable to Xk= 0
This quantity is comparable to i/n I-~. Using the difference of order between
i/~nn (the central limit theorem) and i/n 1-e (the Galton-Watson process), we
construct the required set E .
I express my hearty thanks to Professors M.Ohtsuka, R.R.Coifman, P.W.Jones
who gave me the chance to lecture during the academic year 1986-1987, and I am
grateful to Professors S.Kakutani, T.Tamagawa, J.Garnett, S.Semmes, T.Steger,
G.David, C.Bishop for their variable comments and suggestions. I especially
express my appreciation to Professor W.H.J.Fuchs for his encouragement. I also
thank to Mrs. Mel D. for typing the manuscr:ipt. This note is dedicated to the
memory of my mother who died while I was staying at Yale University.
New Haven, July, 1987
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CONTENTS
CHAPTER I.
i.i.
1.2.
1.3.
1.4.
1.5.
1.6.
1.7.
1.8.
1.9.
i.i0.
1 .ii.
CHAPTER II.
2.1.
2.2.
2.3.
2.4.
2.5.
2.6.
2.7.
2.8.
2.9.
2.10.
CHAPTER III.
3.1.
3.2.
3.3.
3.4.
3.5.
3.6.
3.7.
APPENDIX I.
APPENDIX II.
The Calder6n commutator.( 8 proofs of its boundedness) ........... 1
Calder6n's theorem .............................................. i
Proof of (1.3) .................................................. 1
Area integral ................................................... 2
Good ~ inequalities ............................................. 4
BMO ............................................................. 6
The Coifman-Meyer expression .................................... 9
A tent space ................................................... ii
The McIntosh expression ........................................ 13
Almost orthogonality ........................................... 15
Interpolation .................................................. 21
Successive compositions of kernels ............................. 24
A real variable method for the Cauchy transform on graphs ...... 31
Coifman-McIntosh-Meyer's theorem ............................... 31
Two basic principles ........................................... 32
o-function ..................................................... 35
A-priori estimates ............................................. 39
Proof of Theorem A by perturbation ............................. 47
Proof of Theorem B by perturbation ............................. 50
Estimates of norms of E[ °] and ,C['] ......................... 53
Proof of (2.38) ................................................ 55
Proof of (2.39) ................................................ 61
Application of (2.38) .......................................... 68
Analytic capacities of cranks .................................. 71
Relation between ¥(.) and H ................................. 71
Vitushkin's example, Garnett's example, Calder6n's problem
and extremal problems .......................................... 79
The Cauchy transform on cranks ................................. 83
Proof of the latter half of Theorem E .......................... 91
Analytic capacities of fat cranks .............................. 99
Analytic capacity and integralgeometric quantities ............ 105
Proof of Theorem F ............................................ 112
An extremal problem ........................................... 117
Proof of Theorem B by P.W.Jones-S.Semmes ...................... 126
REFERENCES ................................................................... 129
SUBJECT INDEX ................................................................ 132
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CHAPTER I. THE CALDERON COMMUTATOR
(8 PROOFS OF ITS BOUNDEDNESS)
§i.i. Calder~n's Theorem (Calder~n [3])
Let L p (i ~ p ~ ®) denote the L p space on the real line @ with respect
to the 1-dimension Lebesgue measure I'I- Its norm is denoted by ll'llp° Let BMO
denote the Banach space, modulo constants, of functions f on ~ such that
IIflIBM O = sup(I/II I) 7ilf(x)-(f)ildx is finite, where the supremum is taken over all
L ~ (finite) intervals I and (f)I is the mean of f over I. For a ~ , we
define a kernel
(i.i) T[a](x,y) = {A(x) - A(y)} /(x-y) 2,
where A is a primitive of a. We write simply by
itself defined by the above kernel, i.e.,
T[a] the operator from L 2 to
(1.2) T[a]f(x) = lim 7Jx_y I,~ > e T[a](x,y)f(y)dy.
g+O
Calder~n showed
Theorem A ([3]). For any f ~ L 2, T[a]f(x) exists a.e.
(1.3) IIall" --< Const llT[a]ll2, 2
and
where
(1.4) llT[a]l12,2 ~ Const llalI~ ,
llT[a]l12,2 is the norm of T[a] (as an operator from L 2 to itself).
In §1.2, we show (1.3). In §1.3-i.ii, we show various proofs of (1.4).
§1.2. Proof of (1.3) (Coifman-Rochberg-Weiss [15])
For a set E c ~, X E denotes the characteristic function of E. We put
Ps (x) = 171+ {fl s (A(s)-A(t))dt}dsl (x 6 ~, s > 0), s
= , = (x-s, x). Then lim @ / 3 = Const lal a.e. where I+ s (x, x+s) I_s ~ ~ 0
We have, for almost all x,
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P (x) = Ill+ s ~l_s T[a](s,t) {(s-x) 2 + 2(s-x)(x-t) + (x-t) 2} dt} ds I
<= fl+ s [(s-x)2} T[a] XI_ (s)l + 21s-x I IT[a] {(x-')Xl s}(s)l
+ IT[a]{(x--) 2 X I } (s)l] ds -8
< C°nst[s5/211T[a]Xl II + g3/2 llT[a]{(x-')Xl }If -s 2 -e 2
+ s I/2 l{T[a]{(x-.)2~ }If 2] -g
-< Const llT[a]II2,2 {s5/211X I I] + s3/211(x-')X 11 2 _g 2 I_ s
3 + sl/2N(X-')~ I N2 } -<- ConstIIT[a]tI2,2 s ,
-g
and hence
lal = Const lira p /3 ConstHT[a]ll2, 2 s_~0 s
Thus we obtain (1.3).
a.e.
§1.3. Area integral ([3])
• ~ denote the In this section we show the proof of (1.4) by Calderon. Let C O
totality of infinitely differentiable functions with compact support, (',')
the inner product and Y = X (g > 0). Given real-valued functions (_~,~)c in C O and ~ > 0, we estimate
(TE[a]g,f) = f2Te[a]g(x)f(x)dx,
where Te[a] is an operator defined by a kernel Ys(x-y) T[a](x,y).
assume that A(x) = fx a(s)ds. Then A(x) = f ~ e(x-s)a(s)ds, where
e = X[0,~ ). We have
r (x-y) (T~[a]g,f) = f_~a(s)[ f-~f-i
denote
a,f,g
We may
{e(x-s)-e(y-s)}g(y)f(x)dydx]ds. (x-y) 2
Set
f_~ f(x) dx Im zl >0) 1 f+(z) = 2~i x-z - <0
We denote also by f+(x) (x ~ ~) the non-tangential limit of f±(z), respectively.
We define analogously g+(z), g±(x). Then f = f+ - f_, g = g+ - g_,
llf_+II 2 < IIfll 2 and llg±N 2 _-< Ilgil2. Let
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K0(x,y,s) = Y (x-y){e(x-s)-e(y-s)} /(x-y) 2, g
+ K~ (x,y,s) = {e(x-s)-e(y-s)} /(x-y ± is) 2,
K2(x,y,s) = s/{(x-s) 2 + (y-s) 2 + s2} 3/2
+ Then IK0(x,y,s) - K~(x,y,s) l ~ Const K2(x,y,s), We have
[(T~[alg,f)I = I f_~ a(s)[ /_i Ko(x,y's){g+(Y) - g-(Y)} f(x)dydx] ds I
+ =< If_; a(s)[ 7_= Kl(X,y,s)g+(Y)f(x)dydx] dsl
+ If_; a(s)[ f_; K~(x,y,s)g_(y)f(x)dydx] dsl
+ Const f_~ la(s) l [f_~ K2(x,y,s) {ig+(Y) I + Ig_(y)I} If(x) l dydx]ds
(= If_; a(s) kl(S)ds I + If_~ a(S)kl(S)dsl + Const 7_; Ia(s) Ik2(s)ds,say)"
+ We now estimate k~(s), k2(s). We have
= _ _ Kl(X,y,s)g+(y)dy} dx
= f ; f(x) {e(x-s) f ; g+(Y) dy - f = - - (x_y_is)2 s (x-y-is)
=-i
=-i
g+(Y) 2 dy } dx
f_; f(x) [ f 0 g+(s+it)/{(x-is)-(s+it)} 2 dt] dx
7~ g+(s+it) [ f_~ f(x)/{(x-is)-(s+it)}2 dx] dt
oo = 2~ f0 f+(s+i(t+s))g+(s+it) dt.
Let
F(z) = -i f; f~(z+i(t+s)) g+(z+it) dt (z E U),
where U = {(x,y); x E ~, Y > 0} . Then F is analytic in U and the non-
k~(s). Here is a main lemma necessary for tangential limit F(s) equals (i/2[i)
the proof of(l.4). Let Py(X) be the Poisson± kernel, i.e., Py(X) = y/{~(x2+y2)}.
For a differentiable function v(x,y) in U, we write
IVv(x,y)] = {)8v/Ox]2 + l~v/Oy12 }i/2.
Lemma i.i ([3]). For v E L I, we define
A(v)(x) = {ff IVv(~,D) l 2 d~ d~} I/2 (x E ~), A(x)
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where v~) = P * v~) and A(x) = {~); I~ - xl < n} • Then
llvll I ~ ConstilA(v)ll 1
Once this lena is known, (1.4) is deduced as follows. Since
F'(z) = f$(z + is)g+(z), we have A(F)(s) & A(f+)(s)m(g+)(s)
Const A(f+)(s) M g+(s), where m(g+)(s) = sup{Ig+~)l;(~) 6 A(x)}
M is the non-centered maximal operator (Journ~ [35, p.6]).
We have IIMg+ll2 ~ ConstlIg+II2 , Green's formula shows that
Thus we have, by Lemma 1.1,
and
(See Lemma 2,3.)
IIA(f+)II 2 = Constllf~l 2.
I~ a(s)k~(s)dsl ~ 2~ Ilall~ IIFJI 1
Const Hal< tlA(f+)Lt 2 !m(g+)lt 2
Const IlaIl~ llfIl2 Ilgll2 "
In the same manner, we have
We have
< s I f(x) I [ /Z k2(s) = fl (x_s)2+ ~2
Const M f(s) {Mg+(s) + Mg (s)} ,
ConstrlaH, IIA(F)Ii I
Const Ila!I~ I!f+II 2 !Ig+!I 2
I .~ i a(s)kl(s)ds I =< Const PFaII. ]lfll 2 ilgll 2
V(x-s ) + s 2
(x-s)2+(y-s)2+ s 2 {Ig+ (y) I+Ig-(y)I}dy]dX
and hence
S_~ la(s) Ik2(s) ds <- Const llali~ llfll 2 IIglI2 •
Consequently l(Te[a]g,f) i ~ Const IIall~ Ilfll 2 Ilgll 2 . Since f,g ( c O , g > 0 are
arbitrary, we have (1.4) for a 6 C O • In the general case, we can deduce
• o (1.4) from the boundedness of maximal operators T [b] (b ( C ) and Fatou's lemma.
(See Lemma 2.5.)
§1.4. Good k inequalities ([2], [26], [48])
In this section we give the proof of Lemma i.i by the so-called "good k
inequalities". We put m(v)(x) = sup{Iv(x,y) l; y > 0}. Fixing a sufficiently large
T, We prove
(1.5) ix; ~(v)(x) > ~x , A(v)(x) ~ ~/~ I
(Const/T 2) ix; m(x) > k I (X > 0).
Let W(k) = {x; re(x) > k}, 6(k) = IW(k) l . Then we can write W(k) = U]= I I k
with a sequence M k = {Ik} of mutually disjoint open intervals. It is
sufficient to show that, for each I ( M k ,
(1.6) IE I -<- (Const/2) lli,
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where E = {x ~ I; m(v)(x) > ~h , A(v)(x)
A(v)(~) ~ X/~ for some ~ ~I; otherwise
for any x ~ I, y ~ 2111 ,
X/~}. To do this we may assume that
E = ~. Since A(v)(~) ~ X/~ , we have,
(1.7) IV(a,y) - v(x,y)] ~ Const A(v)(~) =< Const k/~ ,
where a is the left endpoint of I. We choose • large enough so that the last
quantity in (1.7) is less than ~ . Since m(v)(a) ~ k, we have
Iv(x,y) l ~ 2X (x E I, y ~ 21If). Hence, for any x E E, there exists 0 < Yx < 21II
such that Iv(X,Yx) I = sup{Iv(x,y) l; y > yx } = ~. Let
J(x) = (x - (Yx/5), x + (Yx/5)), J(x) = {(~,yx); I~- xl < Yx/10} (x ~ E). Then,
for any (~,yx) ~ J(x), we have Iv(~,yx) I ~ Iv(x,Yx) I - Const A(v)(x)
~X - Const X/T ~ • ~/2. There exist a finite number of mutually disjoint
intervals ~{J(x )} such that IEI ~ 5 Z IJ(x )I (See §2.2.) Let
R = QO N U A(x ), where QO = {(~'~); ~ E I, 0 < ~ < 2111}, ~(x ) = {(~,~);
I~ - x~I < ~/i0, ~ > Yx } " Green's formula shows that
(1.8) f { ~n ]v12 - ~ 0-~L~ -L~ } ds = Const ff ~ ]VVl 2 d~ dr], OR R
where O/On is the inner normal derivative and ds is the length element. Let
~(v)(x) = {ff , IVvl 2 d~ d~} i/2 where ~*(x) = {(~,~); l~-xl < q/lO}. (x) N R
Then a geometric observation shows that AR(V)(X) ~ A(v)(x ) ~ k/~ , where x v
is a point which is nearest to x in {x }. Hence the right-hand side of (1.8) is
dominated by:
Const fl ~ (v)(x)2dx~C°nst(X/~)2]I] ~ Const k 2 ]I I.
We divide oR into the following three parts: DR 0 = 8R N U J(x ),
DR I = {(~,D); ~ ~ I, ~ = 2111}, 0R 2 = oR - (oR 0 U oRI). Note that
~IV v(~,~) I ~ Const X/~ on oR. By the definition of Yx (x ~ E), we have, for
any (~,D) ~ oR, Iv(~,~)I ~ ~X + Const X/~ ~ Const ~X • Thus
~-~-[~ds] < Const mlVvllvl ds IfDR ~ 8n = fOR
Const (k/~) ~k /oR ds ~ Const ~2 ill.
Since Iv(~,O) l G Const k on OR I, we have If0R I
Ivl 2 These estimates yield that4R 0UoR 2 On
O~/On ~ 0 on OR 2, 0H/0n = i on 0R 0 and
8~ Ivl 2 ds i ~ Const ~2 iii. 8n
ds G Const k 2 II[. Since
Iv(~,~)l ~ ~k12 on 8R 0, we have
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2 k21El = Const~8R 0 8~ Const/oRoU 8~ X2 < ~nn I vl 2ds = < OR 2 ~nn I vl 2ds =<C°nst I II ,
which shows (1.6). Consequently (1.5) holds.
By (1.5), we have, with a constant CO,
(1.9) 5(Tk) ~ ~(~I<) + (Colt 2) 6(k),
where 6(k) = Ix; A(v)(x) > h i . We now choose
quantity in (1.9) by dk from 0 to infinity.
[Im(v)II 1 ~ Const llA(v)lll, which gives llvll 1
proof of Lemma i.i.
= 2 C O and integrate each
Then we obtain
Const IiA(v)ll I. This completes the
§1.5. BMO (Fefferman-Stein [27])
Theorem A is closely related to the theory of BMO [27]. In this section, we show
the proof of Theorem A by Fefferman-Stein. We say that a non-negative measure
d~(x,y) in U is a Carleson measure with constant B if
/7 d~(x,y) ~ BIIl I ×(0,111)
for any interval I c R. The following two facts are elementary.
Lemma 1.2 ([27]). Let a ( BMO. Then yiV a(x,y) l 2~ dx dy 2
with constant Const IIalIBM 0 , where a(x,y) = P * a(x). Y
is a Carleson measure
Proof. Given an interval I, we put
a(1)(x) = (a(x) - (a)i) X ,(x), a(2)(x) = (a(x) - (a)l) X , (x), I I c
where (a)I = (i/IIl) /I a(y)dy and I is the double of I, i.e., the (open)
interval of the same midpoint as I and of length 21I I . Then
* a(1)(x) + P * a(2)(x) + (a) I a(x,y) = Py Y
( = a(1)(x,y) + a(2)(x,y) + (a)i , say).
John-Nirenberg's inequality [32] shows that Ila(1)ll2 ~ Const MalIBMO~--~T •
(See Lemma 2.5.) Hence we have, with ~ = I × (0,1If),
7f^ Y IVa(1)(x,Y)I 2 dx dy ~ f7 y IVa(1)(x,y)l 2 dx dy I U
= Const lla(1) II~ ~ Const IIalI~M 0 IIl.
Note that l(a)i. - (a)iI ~ Const jilaliBMO (j ~ I), where Ij is the interval of J
the same midpoint as I and of length 2JlIl. We have, for (x,y) E
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[Va(2)(x,y)l < Const
_-< Const Z j=l
=< Const Z j=l
=< Const( E j=l
and hence
1 a(2) (s)i ds fl *c (x_s) 2
-2 I ljl f l a(y)-(a)iI ds
lj+l-I j
-2 + I (a) - (a) I t} t I j I l l j + l I {ll aII BMO I . 3
j 2 -j) II~IBMO/I I] ,
ff^ y ''IVa(2)(x,y)l 2 dx dy ~ Const(IIallBMo/lll) 2' /f^ y dx dy I I
2 Const Ha]]BMO 111 .
Thus
ff^ y ''IVa(x,y) I 2 dx dy ~ Const {ff^ y ''lva(1)(x,y)I 2 dx dy I I
. 2 + dr^ y IVa(2)(x,y)l 2 dx dy} -<_ Const ! a~IBMO III.
I Q.E.D.
Lemma 1.3 ([35, p. 85]). Let d~(x,y) be a Carleson measure with constant
Then, for any f 6 L 2,
flu If(x'y) 12 d~(x,y) < Const BIIfH 2 (f(x,y) = P * f(x)). = 2 y
B.
Proof. Let W(K) = {(x,y) ~ U; If(x,y) l > k} , 8(k) = ffw(k) d~(x,y) ( k > 0).
Then the left-hand side of our lemma is dominated by
Const f~ kS(k)dk • If (x,y) ~ W(~), then
k ~ sup{If(~,~)l; Ix-El < ~} ~ cM f(x) for some constant C. Hence W(k) is
contained in W0(k) = U I x (0,1If) , where the union is taken over all components
I of {x; M f(x) > CX} • Thus
6(k) ~ ffw0(k ) d~(x,y) & BIx; Mf(x) > CX 1 ,
which gives
f~ X 8(k)dX ~ B f~ XIx; M f(x) > Ckldk
Const B llMflI~ ~ const B IlfIl~ . Q.E.D.
We now prove Theorem A. The Hilbert transform H
f(s) ds . lim fls-xl > ~ s-x Hf(x) = ~ ~ ~ 0
is defined by
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For a, f ~ C~, we have
(i.i0) T[a]f(x) = -~ H(af)(x) +~ [A,H]f'(x),
where [A,H]f' = A(Hf') - H(Af'). Since llH(af)II2 ~ llall~IlflI2, it is sufficient
< Const llalI~IifIl2 • we will prove a better inequality. to show that II[A,H]f'II 2 =
(i.ii) II[A,H]f'II 2 ~ Const IIalIBM 0 llfll 2 .
Without loss of generality we may assume that a, f
have, for any real-valued function g E C~,
([A,H]f',g) = ~_~ [A,H]f'(x)g(x)dx = (A,Hf''g + f'Hg)
are real-valued. We
= 4 im(A,f~ g+) = 4 Im(A,F') = -4 Im(a,F),
where
(1.12) F(x) = fx_~ f~(s)g+(s)ds = -i f~ f~(x+is)g+(x+is)ds.
* a(x,y), F(x,y) = Py * F(x). Since f$(z), g+(z) are analytic Let a(x,y) = Py
in U, we have ~0F (x,y) = f$(x+iy)g+(x+iy). Thus Lemmas 1.2, 1.3 and
Parseval's formula yield that
Oa OF l(a,F) l = Const l//U y ~ (x,y) 8~x (x,y) dx dy l
8a = Const Iff Y ~-x (x,y)f~(x+iy)g+(x+iy) dx dy I
U
Const {flU Ylf+(x+iy) 12 dx dy} I/2 {f7 U y IVa(x,y) 121g+(x+iy)12dx dY} I/2
Const IIf+II2 IIalIBM O fig+If 2 ~ Const IIalIBM O IIfll 2 llgll 2 •
This completes the proof of Theorem A.
Fefferman-Stein [27] showed also the following inequality, which is
essentially same as (l.ll).
Lemma 1.4 ([27]). Let a E BMO. Then iI[a,H]ll2,2 ~ Const IIaIIBM 0 •
Proof. Without loss of generality we may assume that a is real-valued.
for any real-valued functions f,g E C O ,
We have,
([a,H]f,g) = (a, Hf'g + fHg) = -4 Im (a,f+g+).
Let G(x) = f+(x)g+(x). Then Parseval's formula shows that, with
G(x,y) = P * G(x), a(x,y) = P * a(x), Y Y
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8a 8G l(a,f+g+)l = l(a,G)I = Const Iff y ~- (x,y) 8~x (x,y) dx dy I
U
Const {ff U
Y iVal2 I G I dx dy} 1/2 {77 U Y IVGI 2 I GI-1 dx dy }1/2.
Since log I G(x,y) 1 is subharmonic in U,
2 A log I GI (AIGI PJ-~4"[ = _ ) , ~ ,
and hence
~ 2 = ~,G, + ~ =< 2 A]G[.
This shows that
O,
flu y IVGI2 IGI-I dx dy ~ 2 flu
Since IG(x,y) i I/2 is subharmonic in
Hence Lemmas 1.2 and 1.3 yield that
f lu y IVa(x'y) I21G(x'Y)I dx dy
2 Const llallBM 0 IIGII I.
y &IGI dx dy = Const fIG11 I.
* (IGil/2)(x) U, we have IG(x,y)l ~ Py
flu y IVa(x'y) 12 PY * (IGIl/2)(x)2dx dy
Consequently, we have
l([a,H]f,g) I _-< Const IIalIBM O IIGITI _-< Const IIalIBM 0 llfll 2 llgll 2. Q .E.D.
§1.6, The Coifman-Meyer expression (Coifman-Meyer [8])
It is important to understand Theorem A from the point of view of real
analysis. Coifman-Rochberg-Weiss [15] showed Lemma 1.4 without using analytic
functions. Coifman-Meyer gave the following expression.
Lemma 1.5 ([8]). [A,H]f'(x)
= - Const f_~ [a_s,H]fs(X)/(l+s2)ds (a E BMO, f 6 C~),
where a = k * a, f = k * f, ks(X) = ~s/IXl l+is and S S S S .
E s = F((l+is)/2)/ {F(-is/2) IS} .
Proof.
where
We have, for a, f 6 C O,
[A,H]f'(x) = Const i 7 ~ 7_~ ei(~+q)x {sign~]- sign(~-~q)}
^ ^
a, f are the Fourier transform of a, f, respectively.
~(~) i~(~)d~ an
Note that
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{sign ~] - sign(~+q)} (~]/~) = - {sign ~] - sign(<+~q)} X(0,1)(l~]/~I). Since
I~]/~ I = Constf_~ I~]/ ~I is/(l+s2)ds ( ID/ ~I =< i),
%_s(~) = k_s(~)a(~) = I~I -is a<~) and fs(~) = I~ql is fe), we have
[A,H]f'(x) : - Const f~ [i/~ ~ e i~+~)x {sign~ - sign~+~])}
a_s(~) ~s~) d~ d~]]/(l+s 2) ds = -Const ~ ~ [a s,H]fs(X)/(l+s2)ds.
(In the case of a 6 BMO, f 6 CO, it is necessary to show the convergence of
the quantity in the right-hand side of Lemma 1.5. This will be shown later in the
proof of Theorem A.) Q.E.D.
Here is another lemma necessary for the proof of Theorem A.
Lemma 1.6 ([8]). llasllBMO & Const(l + Isl 3/4) II~IBM O.
Proof. Without loss of generality we may assume that s > 0. We put
a (I) = (a-(a) I) X i,, a (2) = (a - (a) I) XI, c . (See Lemma 1.2.) Then
a = a (I) + a (2), where a (j) = k * a (j) (j = 1,2). John-Nirenberg's inequality S S S S S
shows that IIa(1)II2 ~ ConstlIallBMO~I/~ , and hence
I la(1)(x)Idx & s lla~l)H2 ~V~ = lla<l)H2 ~ ~ Const [IalIBM O llI. I
Note that l~sl ~ Const(l + ~).
with x 0 = (the midpoint of I),
In the same manner as in Lemma 1.2, we have,
f la(2)(x) - a(2)(x0 ) I dx I
1 i I~sl f I fZ {Ix yl l+is l+is } a(2)(y)dyl dx
I - Ix0-Y I
Const {IZsl (i + sl/4)} f iX_xoll/4 {fl, c i I iXo_yi5/2 la(y)-(a)lldY} dx
= Const (I + s 3/4) !IaIIBM O Ill.
Thus we obtain
(la s - (as)ll) I ~ 2(la s - a~2)(Xo)l)l ~ Const (i + s 3/4) IIaIIBM O,
which gives the required inequality. Q.E.D.
Theorem A is deduced from Lemmas 1.4-1.6 as follows. Inequality (i.i0) shows
that it is sufficient to show that II[A,H]f'II 2 ~ Const llall~IIfll 2 • Lemmas 1.4-1.6
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11
yield that
II [A,H]f'II 2 ~ Const 7~ II[as,H]f32/(l + s2) ds
Const f£ I] [as,H]ll2, 2 ]Ifsl]2/( I + s2) ds
Const IIfll 2 fflIasllBMo/(l + s 2) ds
Const IIaHBMO llfll 2 ~ Const !lall~!Ifll 2 .
§1.7. A tent space (Coifman-Meyer-Stein [13], [14])
The essential part in the sections 1.3 and 1.5 is the proof of the inequality:
IIFII 1 ~ Const llfll 2 l!gll 2 (f, g E L2), where F(x) = fx ~ f$(s)g+(s) ds
( = - i /0 f$(x + is)g+(x + is)ds). Let R s (s E ~) denote the operator defined
by Rsh = ~s * h, where ~s(X) = s2x/(x 2 + s2) 2. Then we have
F(x) = Const /~ _ Rshs(X) ds/s, where hs(Y) = s f~(y + is)g+(y + is). From this
point of view, Coifman-Meyer-Stein introduces tent spaces and generalizes the above • I
inequality. As seen in the proof of the Tb theorem (Davld-Journe-Semmes [20]),
tent spaces are very useful. The following theorem is a special case of Coifman-
Meyer-Stein's theorem; we rewrite their theorem so that only the proof of
Theorem A can be given.
Theorem 1.7 ([13]). Let T be the Banach space of functions h(y,s) in
with norm llhll T = IIS(h)lll, where S(h)(x) = {7f~(x) lh(y,s)l 2 ayas/s" ~ i 241/2
A(x) = {(y,s); ly-xl < s}. For h E T, we put R(h)(x) = fO Rshs(X)ds/s'
hs(Y) = h(y,s). Then IIR(h)II 1 ~ Const llhll T.
Theorem A immediately follows from this inequality, since
risf~(y + is)g+(y + is)If T ~ IIA(f+)m(g+)I[ I ~ Const JifiI 2 prgll 2 .
Here are two lemmas necessary for the proof. For an interval I, we write
U
and
where
I,
= {(y,s); 0 < s < dis(y,lC)} (dis(',') is the distance).
For an open set ~ c ~, we write ~ = D ~, where the union is taken over all
components I of ~ . We say that p E T is a T-atom if, for some interval
(1.13) supp(p) c~, ff^ Ip(y,s) I 2 dy ds ~ I/iii, S
I
where supp(') is the support.
• < Const. Lemma 1.8 ([13]) For any T-atom p, IIR(p) ll I =
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12
Proof. Let p be a T-atom and let I be an interval satisfying (1.13).
for any b E L ~ with llblI~ ~ i, I (R(p),b)I ~ I (R(p),bl)I + I(R(p),b2)I
b 1 = b X i , and b 2 = b X I , c ( I * i s t h e d o u b l e o f I ) . S i n c e
IRsb2(Y) l ~ Const s/Ira I ((y,s) E I), we have
I(R(p),b2)I = Iff^ p(y,s) Rsb2(Y) ~ s I I
Then,
where
=< (Const/III) 7f^ Ip(y,s)l dy ds I
_< (Const/ill) {ff^ ip(y,s)l 2 dy ds }1/2 {ff^ s I I
s dy ds} I/2 ~ Const.
We have
I(R(p),bl)I ~ 77^ IP(Y,S) IIRsbI(Y)I dYadS I
{ff^ ip(y,s)12 ~ }1/2 {ff^ iRsbl(y) 12 d y ds }1/2 s s
I I
(l~/iil) {ff iRsbl(Y) l 2 dy ds}i/2 = Const Ilbli]2/~ s -
U Const.
Consequently we have I(R(p),b)[ ~ Const. Since b is arbitrary as long as
Hb]l® ~ i, we obtain HR(p)]] 1 ~ Const. Q.E.D.
Lemma 1.9 ([13]). Let h E T and let E be a subset of an interval I. Then
/f^ ^ ih(y,s) i 2 dYadS =< /I-E S(h)(x) 2 dx, l-g
where ~ = {x E I; MXE(X) > 1/2} .
Proof. A geometric observation shows that, for any (y,s) E ~ - ~, y c Y
Y O ~c ~ ~ , where Y = [y-s,y+s](C ~). Let x 0 E Y N ~c. Then
I Y N EI/IY 1 --< MXE(X 0) <-- 1/2, and hence I Y N ECI >-_ s. This shows that
fI-E S(h)(x)2dx = fI-E { ffa(x) Ih(y's) I2 dy ds 2 } dx s
> ff^ ]h(y,s)12 dy ds Q.E.D. ^ S
I--~
E k = {x; S(h)(x) > 2 k} ,
i T(k) ~ be k, let ~lj 7j=l
We now prove Theorem 1.7. Given h E T, we put
~k = {x; MXEk(X ) > 1/2} (k = O, ±i, ...). For each
the totality of components of ~k and let
p(k)(y,s)j = (2-k-I/iI(k) i)j h(y,s) xj(k)(y,s)
and
(j >-_ 1),
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13
where J J Then we obtain the following T-atomic decomposition of
Each
X! k) is the characteristic function of ~!k) _ ~!k) J
h:
h(y,s) = Z Z 2 k+l I£4~(k)j I~ P~k)(y,s)- k =-~ j =l
p(k)j is a T-atom, since supp(p~ k)) c i (k)j alia
ff~!k) I P~k)(y,s)I2 dYsdS = 2-2k-2 ll~k) l-2
J
~(k) = i!k) N ( j J ~k+l )"
f/^(k) ^(k) lh(y's) 12 ~y ds I, ~Q. s J J
2-2k-2 II!k) I-23 fl (k) E S(h)(x)2 dx =< i/ll~k) l
j - k+l
by Lemma 1.9. Hence Lemma 1.8 shows that
IIR(h)iI I --< k =-~E j=IE 2 k+l I jl(k) IIR(P~ k) )II I
Const Z E 2 k I I~ k) k =-~ j~l
= Const S 2klEk 1 k = -~
< Const llS(h)IIl = Const llhl] T .
This completes the proof of Theorem 1.7. As stated above, Theorem A is deduced from
this theorem.
~1.8. The Mclntosh expression (Coifman-Mclntosh-Meyer [7])
The proof of Theorem A in this section is a version of the method given in [7]
for the proof of Theorem B. (See Chapter II .) Here is an interesting expression
of T[a].
+~ I ds (a E L ~) , Len=na i.i0 ([7]). T[a] = f_Z I isD- Ma I + is D s where I is the identity operator, D = -i(8/8x) and M is the multiplier: a f -~ af.
Proof. Let a(x) = e igx, f(x) = e i~x (~, ~ E ~). Then we have
r[a]f(x) = (-~i) { ~+~ sign(~ + ~) - ~ sign ~ }
and
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14
I I J-~ { I + is D Ma I + is D
as f} (x) --
8
I (af) }(x) = 7-Z { I + is D
1 ds i+ is ~ S
1 1 ds J-- 1 + is(a+ ~) 1 + is ~ s
i f~ { i 1 ds = 7 1 + is(e + ~) 1 + is ~ } 2-
s
1 ~ ~ + ~ ~ } d s
= 7 f - ~ { (1 + i s ( ¢ + ~ ) ) 2 (1 + i s ~ )2 s
= (-~i) {~ + B sign(~ + B) - ~ sign $}.
Hence
I I ds T[a]f = f { I + is D M } f -- -~ a I + is D s
iax is complete in the space of functions f with norm Since {e }~ E
f_Zlf(x) 12/(I + x 2) dx < ~ , the required equality holds. (It is necessary to show
the convergence of the integral in the right-hand side. This will be given in
the proof of Theorem A.)
Let Ps = I /(~ + s2D2), %
in Lemma 1.2, we have
Lemma i.ii ([7]). Let a ~ BMO. 2
constant Const IIalIBM O •
Lemma i.i0 shows that
(1.14) T[a] = f - Z {PsMaPs
~ ds = -2i fO ~sMaPs s
Q.E.D.
= sD/(l + s2D 2) (s > 0). In the same manner as
2 dxds Then tQsa(~) I s is a Carleson measure with
- i %MaP s - i PsMaQs - QsMa~s } d Ss
-- - 2i fO PsMa % d Ss (= -2i L I - 2i L 2, say).
we see that
%= Q3 s P = -2 3- . S~s s ~s
Hence the integration by parts shows that
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L1 =fO [8Q + S { -% + 2 Ps%}]M a P d s s s
" " 8 ds = 870 ~ Ma Ps d Ss -70 {-% + 2 Ps%} Ma(SS~s Ps) ~ -
" -- 2 ds = 81"O Q3 s M a Ps d Ss + 270 { -% + 2%Ps }Ma Qs s-
( = 8 LII + 2 LI2, say).
QslI " Since IIPsll2,2 -< - Const, II 2,2 =< Const and 70 jIQsfJl Shwartz's inequality shows that ]IL12112, 2 =< Const llaIl~ •
] (g, Lllf) l = If; (~g, %MaPsf) d s is
; 2 2 ds }i/2 ~ 22 ds 1/2 {7 I]~g]12 s- {~0 ]]~MaPsfN -- }s
2 ds }1/2 = Const I]gl] 2 {7; I]%MaPsfN 2 ~- •
d s = Const IIfll 2 s 2
we have, for f,g E L 2,
We see that
{%MaPs}f = (%a)(Psf) + Ps {(Psa)(% f)} - %{(%a)(%f)} .
(To see this,use a(x) = e iax, f(x) = e i~x (~, ~ E R).) Hence we have
II%MaPsfI122 ~ Const {Ilall 2 ll%fII~ + II(%a)(~sf)II~ }.
Lemma I.ii shows that
7; II%MaPsflI22 d Ss =< Const Iiall 2 7; H%fH22 d Ss
+ Const flU ]Qsa(X) Psf(x) 12 dXsdS
_-< Const Ilall 2 llfIl~ + Const /7 ]Qsa(X) Ps * f(x)12 U
2 2 2 _-< Const {llall + IIaIIBMO} I]f]l -<_ Const IIall 2 llfll ,
which gives IILIIII2, 2 ~ Const llall, . Thus
the dual operator of LI, we have IIL 2 I12, 2
(1.4).
dx ds s
IILII]2,2 ~ Const Ilall~ . Since L 2 is
=If LIII2, 2 • Consequently, (1.14) gives
• s §1.9. Almost orthogonality (Davld-Journe [19])
David-Journ~ [19] showed the so-called T1 theorem. David-Journe-Semmes [20]
showed the so-called Tb theorem (cf. McIntosh-Meyer [40]). These theorems give
immediately Theorem A. Given 6 > 0, we use C 6 for various constants depending
only on 5 ; the value of C 6 differs in general from one occurrence to another.
For 0 < 5 ~ i, we say that a kernel K(x,y) (x # y; x,y E ~) is a 8-standard
kernel if there exists B > 0 such that
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We denote by
inequalities,
t K ( x , y ) l N B / I x - y l ,
I K ( x , y ) - K ( x ' , y ) l -<- BIx-x'l 6 / t x - y l 1+6 (Ix-x'l =< I x - y l / 2 ) ,
IK(x,Y) - K ( x , Y ' ) t =< BIy-Y ' I 5 / Ix -Yi 1+8 ( IY-Y'I =<- / x - y I / 2 ) -
m 8 (K) the minimum of constants B satisfying the above three
For the sake of simplicity, we assume that
(I.15)
(1.16)
K(x,y) is anti-symmetric, i.e., K(x,y) = -K(y,x),
Kl(x) = lim fg K(x,y) dy s ~0 < I x-yl < 1
+ lim fl Ix-yl < i/e K(x,y)dy exists a.e. s~ 0 <
We write simply K the operator defined by the kernel K(x,y). The following
theorem is a special case of the TI theorem; we rewrite the TI theorem so that only
the proof of Theorem A can be given.
Theorem 1.12 ([19]). Let K(x,y) be a 6-standard kernel satisfying (1.15) and
(1.16). Then IlK]f2, 2 ~ C 8 {IIKIlIBM 0 + ~8(K)} .
Integration by parts shows that T[a]l =~ H a. We see that
IIHaIIBM O ~ Const IIail~ and ~l(T[a]) ~ Const !fall . (See eemma 2.5.) Hence this
theorem immediately yields Theorem A.
Lemma 1.13 ([19]). For b ( BMO, there exists an anti-symmetric l-standard kernel
e(x,y) such that El = b, []elI2, 2 ~ Const IIBIIBM 0 and el(L) N Const I]BIIBM O.
Proof. Let L be an operator defined by
ds ef = 2 f; %{(~b)(Psf) } d~Ss + 2 f; Ps{(~b)(Qsf)} °~-
Then its kernel L(x,y) is given by
dt ds L(x,y) = Censt {// Vs(X-t)(Vs*b)(t)Us(t-y)
U s dt ds + flu Us(X-t)(Vs*b)(t)Vs(t-y) T } '
where Us(X) = (i/s)e -]Xi/s , v s(x) = sign(x/S)Us(X) (x ( ~, s > 0) and
L m
U = {(t,s); t ( ~, s > 0}. Then L(x,y) is anti-symmetric and
L1. = 2 f~ QQb d ss = b . U s
2 s i n c e I V s * b ( t ) ' t 2 d t d s / s i s a C a r t e s o n m e a s u r e w i t h c o n s t a n t C o n s t ITbtlBM 0 ,
we h a v e SLIt2, 2 ~ C o n s t HblIBM o .
I t r e m a i n s to p r o v e In t h e same manner a s i n el(L) ~ Const IIbIIBM 0 •
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Lemma 1.2, we have IIVs*bll = ~ Const IIblIBM O. Since IVs(X)l ~ Us(X),
dt ds [L(x,y)l ~ Const HDIIBM O flu Us(X-t)Us(t-Y) s
d t So i e -I/s ds Const IIBIIBM O S_~ (Ix-tl + it_yl) 2 s3
=< Const II bll BMO/I x-yl
Since lU's(X) I -<- Us(X)/S, IV's<X>I < Us(X)/S (x # 0), we have
dt ds 1 8~ L(x,y) I ~ Const IIBIIBM 0 fS U Us(X-t)Us(Y-t) 2
s
dt ~ i -i/s = Const llbIIBM 0 f~ (ix_tl + it_yl)3 f0 ~es
Const IIbllBMo/IX-yl 2
Thus c01(L) =< ConstllbIIBM O .
ds
Q.E.D.
Here is the main tool for the proof of Theorem 1.12.
operator L from L 2 to itself is anti-self adjoint if
any f, g ~ L 2.
We say that an
(ef,g) = -(f,Lg) for
Lemma 1.14 (Cotlar's Lemma [16]). Let @(t) be a function from [0, ~) to
itself and let {Lk}~=_N be anti-self adjoint operators from L 2 to itself such
that llejLkll2, 2 ~ o(lJ - kl) (j,k = O, il ..... iN). Then
llZ ~=_#kI12,2 < Const E 2N = k= 0 ~o(k) •
N Proof. The following proof is due to Fefferman [25]. Let L = Ek=_~ k. Then,
for any M g i, IIe2MII I/2M 2,2 = IIell2, 2. We have
L 2M = % .. -N~kl,...,k2M ~ N LklLk2 " Lk2M
Since
• 112, 2 • II HLklLk2 "" Lk2 M ~ PILklLk2ll2,2 " "]ILk2M_ILk2M 2,2
p(Ikl-k21) .,. @(Ik2M_I - k2M I)
and
IILkl...Lk2MII2,2 =< IILklIl2, 2 IILk2Lk3112,2 -.- IILk2M_ 2 Lk2M_III2,2 IILk2MII2,2
~ P(Ik2-k3 I) ... @(IkmM_2-k2M_l I) " P~ ,
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we have
2 IF Lkl..-Lk2 M H 2,2 ~ p(O) p(l kl-k21 )P(I k2-k31 ) ... p(l k2M_l-k2Ml )"
Thus
I}LN2,2 = IIL2~II/2M2,2
{Vp (0) z
-N~ kl,...,k2M
{gp(o) z -N ~ kl,...,k2M_l
• .. ~ { ~p(0)(2N+l)(2
~P(I kl-k21 )P(I k2-k31 ) -.-P(I k2M_l-k2Ml ) }II2M =< N
~P(I kl-k21 ).. ,P(I k2M_2-k2M_iI ) =< N
2N }i/2M ×(2 z Vp(j))
j=0
2N % OV~) 2M} 1 / 2M
j=O
2N < p(0) I/4M (2N+I) I/2M 2 Z I/p(j) .
j=0
Letting M tend to infinity, we obtain the required inequality. Q.E.D.
We now give the proof of Theorem 1.12. We may assume that K(x,y) is real-
valued. Since KI ~ BMO, we can define, by Lemma 1.13, an anti-symmetric kernel
e(x,y) so that KI = LI, llelI2, 2 ~ Const IIKIIIBM 0 and
~8(L) ~ ~I(L) ~ Const IIKII!BM O. Consider the kernel K(x,y) - L(x,y). Then this
is anti-symmetric and satisfies (K-L)1 = 0,
~08(K - L) _-< Const {IIKIIIBM O + ¢08(K) } .
Hence from the beginning, we assume KI = 0, and show IIKII2, 2 ~ C8~8(K).
this, we may assume that ~5(K) = i. Choosing h ( C~ so that
0 =< h(x) < i, h(x) = h(-x), supp(h) c [-i,i], []h[] 1 = i,
To do
we put
Kk(X,Y) = I_: i : K(x-s,y-t){hk(S)hk(t)- hk+l(S)hk+l(t)} ds dt (k = O,tl .... ),
where hk(X) = 2-~(2-kx). Then K k is anti-self adjoint, Kkl = 0 and
K = lim k ~ ~ Zk=_NN K k. We show that
(1.17) IKk(X,y) I & C 8 2-k/{l + Ix-yl2-k} I+6,
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8 (i.18) I ~-x Kk(X'Y) l < C8 2-2k/{i + Ix-yl2-k} 1+8
If Ix-yl ~ 4 ° 2 k, then we have
IKk(X,Y) l
= I 7_~ /_~{K(x-s,y-t)-K(x,Y)}{hk(S)hk(t)-hk+l(S)hk+l(t)}
Isl 6 + Itl~_ /_: /~ c 8 ix_ylZ+5 {hk(S)hk(t) + hk+l(S)hk+l(t)}
C8 28k/[x_yll+ 8 ~ C8 2-k/ {i + Ix-y[2-k} I+8
ds dt I
ds dt
Let I, J be two intervals in an interval L. Since K(x,y) is anti-symmetric,
we have /IN J fIN J K(s,t) ds dt = 0, and hence
(1.19) I /I {/J K(s't)ds}dtl = I/l-(In J) {$J K(s,t)ds} dt
+ / I N J { /J - ( INJ) K(s,t)ds}dt I < 2 / LI ds dt < Const ILl. = S +t =
Integration by parts and (1.19) show that, if Ix-yl < 4 " 2 k, then
IKk(X,Y) I
v = I /_~ /_~ {/~ /0 K(x-s,y-t)ds dt} {h~(u)h~(v)-h~+l(U>h~+l(V)} du dv I
/_~ / ~ (Const 2 k) {lh~(u)h~(v) I + lh~+l(U)h~+l(V)l} du dv
Const 2 -k < C 8 2-k/{l + Ix-yl2-k} I+8 =
Thus (1.17) holds. If Ix-yl ~ 4 " 2 k, then
18~ Kk(X,Y) l
_~ -~ - ' t dt I If ~ 7 "{K(x-s,y-t)-K(x,y)} {h{(S)hk(t) hk+l(S)hk+l( )} ds
/_~ /_~ C8-Jsl 6 + I t15 {lh~(s) lhk(t ) + lh~+l(S) lhk+l(t)} ds dt Ix_yj 1+5
C 8 2 (8-1)k ~ C 8 2-2k/ {I + Ix-yl2-k} I+8
If Ix-y[ < 4 • 2 k, then
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[fi ~(x,Y) [
~ V = [f_~ f_~ {fo f0 K(x-s,y-t)dsdt}{h~(u)h~(v) - h~+l(U)h~+l(V )} du dv [
Const 2 -2k ~ C 8 2-2k/{I + ]x-yl2-k} I+6 .
Thus (1.18) holds.
We now show that, for k ~ g,
(1.20)
where
[(KkKe)(x,y)[ -<- C 8 Pk,e(x-Y),
pk,g(s) = 2-(k+~)/2(i + [s[2-g) -(I/2)-8
+2 (~8/2) {2-2k]sll-(8/2) + 2-kls] -8/2} (i + [sl 2-k) -I-8 .
Let I be the interval of midpoint y and of length Ix-yl/2. By (1.17), we have
[fic Kk(X,s)K (s,y)ds[ ~ C 6 fic 2-k 2-g
(i + Jx-sI2-k) I+6 (i + Is-yl2-g) I+8 ds
2 -g/2 ® 2 -k C 6 -~ (x-y). (i + Ix-yl2-g) (I/2)+~ f 2-k)i+8 1/2 ds < (1 + Ix-sl Ix-sl = CsPk'~
By Kgl(y) = 0, we have
If I Kk(X,s)Kg(s,y)ds I ~ If I {Kk(X,s)-Kk(X,y)} Kg(s,y)ds I
+ IKk(X,y) f I K~(s,y)dsl
+ IKk(X,Y) / cK~(s,y)dsl I
= Jfl {Kk(X'S) - Kk(X'Y)} Kg(s,y)dsJ
( = Ll(X,y ) + L2(x,y), say).
By (1.17) and (1.18), we have
2-2k I Ll(X,y) ~ C 8 f I s-Yl
(i + Ix-yle-k) I+8
--< C 8 2-2k+(gS/2)
(i + Ix-yl2-k) I+6
2-~ (i + Is-yI2-g) I+8
fl Is-y1-6/2 ds _<- C 8 pk,g(x-y)
ds
and
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2 -k 2 L2(x,y ) -<_ C 6 f 2_Z)146 ds
(i + I x-yl2-k) I+ 5 I c (i + I s-yl
2-k+ (g 6 / 2 ) C 8 (i + Ix-yl 2-k) 146
flC Is-yl -I-(5/2) ds =< C 6 Pk,~(x-y)-
Thus (1.20) holds. Since llpk,~II 1 ~ C 8 2 -(k-g)/2, we have
!IKkKgll2, 2 ~ C 6 2 -(k-Z)/2 Hence Lemma 1.14 gives IIZ~=_N Kkll2, 2 ~ C 6 (N ~ I).
Letting N tend to infinity, we obtain IIKII2, 2 ~ C 5 . This completes the proof
of Theorem 1.12.
§i. I0. Interpolation (Lemarie [36])
In this section, we give a proof of Theorem 1.12 (in the case of K1 = 0)
by interpolation, which was given by Lemarie. For a 6 ~ with I~I < i,
let E denote the Banach space of distributions obtained from the completion of
C O with respect to the norm lllflll~ = {f_~ I~I ~ I~(~)I 2 d<} I/2, where ~ is the
Fourier transform of f (in the sense of distributions). For 0 < a < I, let
[E ,E_~] denote the Banach space of distributions f in E ~ E_~ with norm
llfIllnt,~ = {~ B(s,f)2 d s 2 }1/2 < = , $
where
B(s,f) = inf{(IIlgill2+s2ilihllI2 )i/2;_ f = g + h, g ~ E , h E E_~ }-
Lemarie showed the following two facts.
Lemma 1.15 ([36]). Let K(x,y) be a 6-standard kernel satisfying (1.15), (1.16)
~6(K) where and El = 0. Then, for any 0 < a < min{l,26}, IllKIll~,~ C , 6 ,
IIIKI~I~,~ is the norm of K as an operator from E to itself and C 6 is a
constant depending only on ~ and 6 .
Proof.
and 6. We may assume that ~8(K) = i. Note that
- I f (x)-f(y)~ INfHI~ = c a f_: f ~ ix_yil+~ dx dy
Given x, y E [, we write by I the interval of midpoint
21x-y I . By KI = O, we have
Throughout the proof, we use C 8 for various constants depending only on
(f E E a) .
(x+y)/2 and of length
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IKf(x) - Kf(y)l = I f~{K(x,s) - K(y,s)} f(s)dsl
I flK(x,s)(f(s)-f(x)) ds - f : K(y,s)(f(s)-f(y))dsl
ifI K(x,s)(f(s)-f(x))ds f I K(y,s)(f(s) - f(y))ds
+ f {K(x,s) - K(y,s)} (f(s) - f(x))ds - (f(x) - f(y)) f K(y,s)dsl i c i c
fI If(s) - f(x) I/Is-xl ds + fI If(s) - f(Y) I/Is-Yl ds
+ c~ ~ If(s)-f(x)l Ix-yl~lls-~l 1+s ds + If(x)-f(y)i Fie K(y,s)dsl
( = Ll(X,y) + L2(x,y) + C 5 L3(x,y) + L4(x,y) , say).
Hence
2 C f : f - : iKf(x)_Kf(y ) [,2 IllKfilla = a ix_y]l+~ dx dy
2 4 Lk(X ,y)
< C Z f ~ f : dx dy = a , 5 k=l -~ - I x-Y i I+~
Choosing 0 < ~ < 1/2 so that a + 2~ > i, we have
Ll(X,y) 2 =< Ca fls-xl < 21x-yl If(s)-f(x)12ls_×12(l-~ ), ds
and hence
' =< C a f ~ f " L 1 _® -~
= c N1flll~ .
I f ( s ) - f ( x ) l 2
Is_~12(1-~5
In the same manner D
2(1 + 6) Y > 1 and
{ J'21x-Yl > I~-xl
L~ ~ C IIIflll~ • Choosing 0 < T < i
(a - 26) + 2(1 + 6) Y < I, we have
4 ( = C 6 kE=l L~,
Ix_yll-2~
l~-yl l+a
so that
say).
dy } ds dx
L3(x,y)2 £ Cg, 6 f t s -x l > t~-yl12
and hence
, ~ If(s)-f(x)I 2 e 3 < Ca, 6 f ® f ~ i s_x -- - 12(1+6) (l-Y)
= %,5 I I If l l l~ •
[f(s)-f(x)l 2 25-2(i+~)~ + i Ix-yl is_xi2(l+6)(l-y)
{flx_yl/2< Is_xllX-y125-2(l+6)Y-~dY} dsdx
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Since lSlC K(y,s)dsl ~ i $1y-~l > Ix-yll2 K(y's)dsl + Const, we have
' < K(y,s)ds i + 1} . L 4 = C o n s t t l l f l l la ( sup i f l y - s t > y E ~t,~ >0
Given Y0 ( R, s > 0, we have, with J = (Y0 - s, Y0 + g) and J = (Y0-2g,Y0 + 2g),
+ !_, Sj $j l~c K(Y0's)dsl = lSjc K(Y0>s)ds ij I
= i ~ Sj {Sjc (K(Y0,S) - K(y,s))ds} dy
ds < (Const/IJi) Sj {S , ~ }dy
J -J
ly0-yl ~ + (Cs/iJi) Sj { Sj, c i1+6 as}
ly-s
2 Consequently we have Hence L 1 =< Ca, 8 lllfill~ .
gives the required inequality.
K(y,s)ds dyl
i fJI l f j { S j , _ j + S *c } l J
dy & C 8 .
IIIKflll~ ~ ca, ~ I l l f l l l~ , which
Q.E.D.
Lemma 1.16 ([36]). For any 0 < a < i, [E ,E_¢] = L 2. More precisely,
(I/C)NflI 2 ~ llfilint, ¢ ~ c a llflI 2 (f (L2).
Proof. Given f 6 L2~ s > O, we put
2 D f dt, h = 2 s -I/a D = -- S®-I/~ t2D 2 s SO t2D 2 gs ~ s r + "~ r +
f dt.
Then f = gs + hs and
IIfI!2Int,a = S; B(s,f) 2 ~ --< S 0 {Iilgslii2a S
I ~I dt) 2 4 E I_; S°_li= a s i + t2E
s-i/a _ill at)2 1 } l~(~)I 2 d E ] ds + ( S0 i + t2~ 2 IE I a
= c So E s_Z i'li dr) a s i + t2E 2 s
-lla = _ I~f d t ) 1 } I7 (< ) I 2 d E ] ds
+ ( SO 1 + t2~ ~ I~1 a
ds : c a S_l 11(O12 {7o (I'_~ -7 ) t2E2
t s i +
ds + S 2 liihsNi2a } --~ S
2 S
t -c~ - - I ~ I 1 - L dt} dK dt +dO(f0 ds) l+teiGi2
2 = C a d'_] If(E) l 2 d~ = C a IIfll 2 .
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Let f ~ [E ,E_~].
f = gs + hs and
For each s > 0, we choose gs ~ Ea' hs
lllgslll2 + s 2 lllhslll2 < 2B(s,f)2 Then -(l = °
E E so that -<l
2 II fll 2 = Const 7 0 II tD fll dt
2 ~- I + (tD)
Const J" { II tD g-a tl + II tD h _all } ~- I + (tD) 2 t r + (tD) 2 t
Const fO [ j'-~ (t~)2 (i + (t~)2) 2 {lgt_~(~)12 + lht- a(~)12 } d~ ] d tt
oo Const 70 [7_~ ~ {t a l~lalg _a(~)l 2 + t -a I~I -a IE _a(~)l 2} d~] d tt
t t
dt ca fo ( IIIg _JII 2 + t -2c~ ]llh -~1112~- ) 1-~ t t t
O -- < ~ = C-IIfi[2 Cc ~ f ([ilgsii[2 + s 2 iiihsiii2a ) ds Ca B(s f)2 as 2 = f0 ' --2 ~ Int,a " s s
Q.E.D.
Theorem 1.12 is deduced as follows. We may assume that K1 = 0 and
~05(K) = i. We use Lemmas 1.15 and 1.16 with a = 6/2. Let f ~ L 2. Then,
for each s > 0, we can choose gs E E a, hsE E_a so that f = gs + hs'
Iligs III2 + IIIhs IiI2-a -<- 2 B(s,f) 2, by Lemma 1.15. Thus Lemmas 1.15 and 1.16 show that
[[Kfi[22 -< C6 [[Kfll~nt,a = 2 C6 /0 B(s'Kf)2 d s s
=< C6 J'o (INKgs [[12 + s2 [IIKhs Iii2-a ) ~ds s
2 + s 2 [IlhslIi2a)--2as < C fo B(s'f)2 __ds -<- C6 fO ([[[gsIiia - = 6 2 s s
= C 6 II fII2nt,c~ < c6 IlfIl~.
§i.ii Successive compositions of kernels
Meyer [41] also gave a proof of Theorem 1,12 from the point of view of
composition of kernels. Using his method, we show the following lemma which also
yields Theorem 1.12.
Lemma 1.17.
K1 = 0 and
(1.21)
Let K(x,y) be a 6-standard kernel satisfying (1.15), (1.16),
sup IK(x,y) I (i + Ix-yI) I+5 < ~.
x,y E
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We define kernels {K(n)(x,y)}~=l by
K(1)(x,y) = K(x,y), K(n)(x,y) = f_~ K(x,s)K(n-l)(s,y)ds (n a 2),
and define
~(K (n)) = sup { ~ I~ I K (n) Xl(X)dx I ; I interval} (n a I).
Then, for any 0 < s < 6,
~(K (n)) + ~8_s(K (n)) ~ C n ~6(K) n 8~g
where Cs,g is a constant depending only on 8, s.
Postponing the proof later, we now deduce Theorem 1.12 (in the case of
KI = 0) from this lemma. (This lemma plays the role of Cotlar's lemma.)
Without loss of generality, we may assume that K(x,y) is real-valued,
and K1 = 0. Using Kk(X,y) in §1.9, if necessary, we may assume that
satisfies (1.21). We put
i (1.22) ~(K) = sup { ~ o(l,K,f); f 6 Lreal,l I interval},
where, in general,
(1.23) Lreal,~ = {f 6 L~; llflI~ --< ~ , f real-valued } (6 > 0)
(1.24) o(l,K(n),f) = fl IK(n)(xI f)(x)l dx (n ~ i).
and
Then
IIKH2,2 <_ Const {o(K) + C8~08(K)} -<_ Const {o(K) + C 5} •
(See Lemma 2.5 in Chapter II.) For n >-_ I, f ~ Lreal,l and an interval
we have
1 n-i 1 / =IK(2n-l)(xif)(x)l 2 dx}i/2 ~f~ ~(I'K(2 )'f) =< {4 -=
_2 n 12 = {~ 7i f(x)~( )(Xlf)(x)dx} / --< { ~ o(l,K(2n),f)} I/2
and hence
i i n -n Tf ~ ~(l,K,f) _<- { ~ o(I,K (2) f)}2 .
~06(K) = I
K(x,y)
I,
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For a while, we assume that Xlf is a step function, saying
XI f = Zk=IN ~k Xlk (l~kl ~ I) I k interval, I k DIg = ~ (k # g)).
inequality and Lemma 1.17 show that
{ ~- ~(l,K(2n),f)} 2 ~ ~ 171 f(x) K <2n+l) (Xlf)(x)dxl
Then Shwartz's
1 N K(2~+I) ~T % I: I f(x) Xlk(X)dxl
k=l
N :on+l, :^n+l. N d
< i kEllflk Kk~ :X (x) dx I + ~5(K ~Z )) ~ k%l:l_ik{flk ~ }dx = ~f~ = I k =
~(K(2n+l)) (2 n+l) 2 n+l + Const N ~6(K ) ~ Const N C 6 ,
2n+l 2-n which shows that (i/If I) ~(l,K)f) ~ {Const N C 5 } . Letting n tend to
infinity, we have (i/II I) ~(l,K)f) ~ C 6. Since this inequality holds for any
N ~ i, ~k' Ik (i ~ k ~ N), we can remove the above assumption, i.e.,
(i/III) ~(l,K,f) ~ C 6 for the given f. Taking the supremum over all f ( e~eal,l
and all intervals I, we have ~(K) ~ C6, which implies Theorem 1.12.
We now give the proof of Lemma 1.17. Assuming that ~6(K) = i, we
inductively show that
~(K(n)) (K(n)) n (n g I) + ~8-e ~ CO '
C O is a constant depending only on 6, ~, and is determined later. Since
is anti-symmetric and ~6(K) = I, we have
~(K (I)) + ~5_8(K (I)) ~ 0 + ~5(K (I)) = I.
Suppose that the required inequality holds for n-l. For the sake of simplicity,
we use, from now, C for various constants depending only on 5, 8. First we
show that ~(K (n)) ~ CC~ -I For an interval I, we have
:I K(n) XI(x)dx = 7~ {:I :I K(x's)K(n-I)(s)Y) dx dy} ds
wheT e
K(x ,y)
7I {:I :I } + :ic {II fI } = LI + L2 '
dx
and
ILl1 ~ { I I IKXi(x) I2dx} I/2 {I I IK (n-l) ki(x) l 2 dx} I/2 .
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27
Since K(n-l)l = 0, we have
fl IK(n-I) El (x) 12 dx = fl IK(n-l) XlC(X) I2 dx
where
< =
< =
I
2 71 IK (n-l) X (x) l 2 dx + 2 71 IK (n-l) X , (x) l 2 dx I *c I -I
_2n-2 2 /I IK(n-l) Xl*c(X) 12dx + 2 C 0 71 (f * dx~_y T )2 dx
I -I
i,c(X) _2n-2, + C 2n-2 i i I, 2 fl I K(n-l) X I 2 dx + C C 0 Ill = 2 LI0 C O
is the double of I. Since
171 K (n-l) Xl,c(X)dx I ~ If I K (n-l) Xlc(x ) dx I + 171 K (n-l) X , (x)dx I I-I
n-l If I K(n-l) Xl(X)dxl + C O 71 ( 7 , ) dx
I -I
n-1 n-i ~(K (n-l)) III + C C O III < C C O III,
we have
2n-2 El0 ~ 2 71 IK (n-l) X ,c(X) - (K (n-l) X ,c)112 dx + C C O III
I I
< 2 _2n-2 = ii12 71 { fl ( fl*C IK(n-l)(x'y)-K(n-l)(s'y)Idy)ds}2 dx + C C 0 II
(cc~n-2/lli2) fl {fl ( /l*C - Ix~slS-¢ 2n-2 ii 1 ix_yll+8_e ) ds} 2 dx + C C O
CC~ n-2 l If.
2n-2 Thus fl IK(n-l) Xl (x) 12 dx -<_ C C O III. In the same manner,
fl IKXI (x) 12 dx ~ CIII, and hence Iell =< CCo -I iii. Consequently we have
If I KXi(x)dx I <= C C0-1 III. Since I is arbitrary, we obtain ~(K (n)) < CC0 -I
° -I Next we show that ~o6_e(K(n)) -<_ C C In the same manner as in the
estimate of ILII, we have
sup Iflx_y I > g K(n-l)(x,y)dyl ~ C CO-I , x ~ ~,e> 0
sup Iflx-y I > s K(x'y) dyl < C. ~E ~,c >0
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For x, y ( ~, we have
K(n)(x,y) = f ~ K(x,s)K(n-l)(s,y)ds
i + i + l : f I i + f l 2' + f I~ = LI L2 L3 '
I t 12, 1 ! is the interval of midpoint x and of length I x-yl 12 where I 1 ! =
interval of midpoint y and of length I x - y l / 2 and 13 (1~ U I~) c
have
is the
We
- ds n-i flx-yI IL~I ___ Co l Si ~ - -pT--~--~S ---~-~[- ~ c c o
= K (n-l) (s, y) dsl IL~I < I f i , ~ {K(x,s)-K(x,y)} K(n-1)(s,y>dsl + IK(x,Y)IIII~
....... n-1 o-l/l~_yl I s-yj ~ i i c c o ~ c c n-i fl ~ _-< c c o l x-yl 1+5 -T~_y T ds + ] ~ i ~ -
and
IL i l <-- Isq n-1
n-i 1 I s - x l S - s ds + C C 0
=< c c o $i i ~ ix_yll+~_ ~
I%-1 x T , Thus IK(n)(x,y>l _<- c c 0 llx-yl For x, y (
we have
K(x,s) {K (n-l) (s,y)-K (n-l) (x,y) }dsl + IK (n-l) (x,Y) I IfiiK(x,s)dsl
n-I c -_< c C 0 /[x-yl.
I ! = (X -- where I 1
31xTyl 13 (x - 4
with IX-X'I ~ t x - y I / 2 ,
K (n)(x,y) - K (n)(x',y) = f_®{K(x,s)-K(x ,s)} K (n-l)(s,y) ds
6 6 = II
= Z fl~ Z L k , k=l k=l
Ix-x'i Ix-xii i, = (x' Ix-x'L x,+ i~i[) 2 , x+ 2 )' I2 - 2 ' 2
3 x ~ 4 ,, I x - x ' l , y + ~ ' l , x + ) - (I~' U 12), I~ = (y - i0 i0 "
I'~ = (y - Ix-Y~4 ' y + Ix?--~i)4 - I~ and I~ = (I~ U...U I~) e. We have
- ~ i n-i , Ie~l < C C 0 1 fl~ ix_sll+8 -T-~ ds < c c O x-x 18/Ix-yl I+6
_n-i , 8-6 / 1+6-6 _-< c ~o Ix-x I I ~ - y l ,
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29
and
Since
= n-i ,,l~-x'l 8 f ~ ]-~cFfds IL~I < c c o ix_ytl_ ~
n-i _ l~-x'l 5 C C O Ix_yll+6 log(C ) C C~ -I Ix-x'18-g/Ix-yl l+8-s,
IL~I ~ Ifl~ {K(x,s)-K(x',s)-K(x,y) + K(x',y)} K(n-i)(s,y) ds j
+ IK(x,y) - K(x',y) l Ifl~ K(n-l)(s,y)dsl
n-~ s~ { _Isnyl ~ l~-yl ~ l C C 0 ix_yll+8 + } ds Ix'_yl I+8
n-i ix_x,18/ix_yll+8 + +
I x-y
-_< C C 0n-I ix_x,18-S/ix_yjl+8-s
EL = fl~ {K(x,s)-K(x',s)} {K(n-l)(s,y) - K(n-l)(x',y)} ds
+ K (n-l)(x',y) ~I~ {K(x,s) - K(x',s)} as = ELI + e~0 ,
L~ = ]I~ {K(x,s)-K(x',s)} {K(n-l)(s,y) - K(n-l)(x',y)} ds
+ K(n-l)(x''Y) fl~ {K(x,s)-K(x',s)} ds = e21 + L20
L~ = fI~ {K(x,s)-K(x',S)} {K (n-l)(s,y) - K (n-l)(x,y)} ds
+ {K(n-I)(x'Y) - K(n-l)(x''Y)} fI~' {K(x,s) - K(x',s)} ds
+ K(n-l)(x''Y) 7I~' {K(x,s) - K(x',s)} ds = LII + n12 + L"10.
IL~z I S C C~ -I $Z~ "Ix-x'j8 Js-x'jS-c " ix,_sl l+~ ix_yl I+6-~
c c o~-I l~_~,ls-~/ix_y11+8-~
,, i Is-x'l ~-~ Ie211 ~ C Cg -I fl~ ~ --ix_yll+8_g as
n-i 18-g/ l+8-g C C 0 Ix-x' Ix-yl ,
ds
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30
,, n-i i I s-xJ 6-s ]~111 _-< c c O Ii~, ]-~ i x_y l l+~_d
n-i I x-x' 16-81 i+s-5 s C C 0 I x-yl
ds
and
IL~21 ~ c~ -I Ix-x'16-8 {lli~ K(x,s)ds I +I ,, ds Ix-yP I+5-8 Ii I~'-sl
C C 0n-I Ix-x' 16-e/Ix-yl I+6-8
" = " O " U I~ , we have, with I 0 I 1 12
. . . X-X t 18-8 IK(n)(x,Y) - K(n)(x',y)I $ ILl0 + L20 + L30 I + C C~ -I x_yll+6_s
n-I _!x-x'[ 8-g = IK(n-l)(x',y)IIYI~ {K(x,s)-K(x',s)}dsl + C C O
18-g i n-i Jx-x[14_6_8 -< C Co -I ~_y~ I 71~ c {K(x,s)-K(x',s)}dsl + C C O Ix-Y
1 ..... Ix-x'18 ds + C n-i Ix-x'l 6-8
n-i ix_x,18-S/ix_yll+8-¢ C C O
Since K(n)(x,y) is either anti-symmetric or symmetric, we have also
n-i ly_y,18-g/ix_yil+8-g IK(n)(x,y) - K(n)(x,y')l ~ C C O
n-i Consequently, for x, y, y' ( IR with IY-Y'I ~ Ix-Yl/2. Thus ~8_g(K (n)) ~ C C O •
~(K(n)) ~8_¢(K(n) n-i ~8 s (K(n) n if + ) ~ C C O This shows that ~(K (n)) + _ ) a C O
C O is large enough. This completes the proof of Lemma 1.17.
In Chapter I, we showed 8 proofs of the boundedness of the CalderSn
commutator T[']. Since the Calder~n commutator is closely related to analycity
of functions, it seems necessary to give more proofs and to have a unified
understanding.
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CHAPTER II. A REAL VARIABLE METHOD FOR THE CAUCHY
TRANSFORM ON GRAPHS
§2.1. Coifman-Mclntosh-Meyer's Theorem ([7])
For a real-valued locally integrable function a, we define a kernel by
(2.1) C[a](x,y) = i/{(x-y) + i(A(x) - A(y))},
where A is a primitive of a. We write simply by C[a] the singular integral
operator defined by the kernel (2.1). This is called the Cauchy transform of
Calder~n on a graph {(x, A(x)); x E ~}. We put
Lreal~ = ~ >U 0 Lreal,~ = {a E L®; a is real-valued}.
(See (1.23).) Coifman-McIntosh-Meyer showed
Theorem B ([7]). The norm IIC[a]II2,2 is bounded if a E Lreal"
The operator C[a] is expressed formally in the following form
C[a] (-~)H + Z (-i) n = Tn[a], n=l
where Tl[a] = T[a] (the Calder~n commutator) and Tn[a] is the n-th Coifman-
Meyer commutator (n ~ 2), i.e., Tn[a ] is an operator defined by
(2.2) Tn[a](x,y) = (A(x) - A(y))n/(x-y) n+l.
Prior to this theorem, the following three theorems were shown. CalderSn showed
that llTl[a]II2, 2 ~ Const Ilall= (a E L~), Coifman-Meyer [9] showed that
(2.3) IITn[a]II2,2 ~ Const n! llalI~ (a E L ~, n ~ 2)
and Calder~n showed that
(2.4) IIC[a]ll2, 2 is bounded if llall~ (a E ereal) is small enough.
At present, there are three proofs of Theorem B; the original proof, a proof by the
Tb theorem [40] and a proof by perturbation. In this chapter, we show a self-
contained proof by perturbation. A proof by perturbation was first given by
Calder~n [4] and David [17]. Improving their methods and repeating a simple
perturbation method, we shall deduce Theorem B only from the boundedness of H
([17], [42], [45]). (See APPENDIX II.)
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32
§2.2. Two basic principles (Zygmund [54])
Here are two basic principles in real analysis.
Coverin$ Lemma. Let {~}X E A
IUxEA ~I < = • Then there exists a sequence
intervals such that
iux~ A ~I-< 5 k=iE lIXkl.
be a family of intervals in ~ such that
{I~k}k=la of mutually disjoint
The proof is as follows. Let IXI be an interval such that 211XII is
larger than the supremum of llxI over all X E A . Suppose that
~i' "''' ~k-i have been chosen. Let IXk be an interval such that 211~kl
larger than the supremum of II~I over all X E Ak_ I, where A 0 = A and
Ak_ 1 = {X E A ; Ik n IX. = ~ (i ~ j ~ k-l)} (k ~ 2). (If Ak_ 1 = ~, we stop our J
induction at k-l.)
Now we show that {IXk } is the required sequence. We first assume that
{IXk } is an infinite sequence. Since the intervals are mutually disjoint and
IUk= I IXk I < ~ , we have lim k ~ ~ llXk I = 0. For IX, there exists IX. 3
such that [IxI > 211X. I, which implies that X ~ A.. Hence j J
{j; X ~ Aj} # ~ . Let k be the smallest integer in the set. Then
IIxI ~ 211kk I , according to the definition of our choice. Since X ~ Ak,
we have 1% n Ixk # ~, which gives that I X c IXk , where IXk is the interval of
the same midpoint as and of length 51 I" Thus I~ k IX k
I UhE21 Ikl --< I U IXk I --< 5 % llXkl • k=l k=l
is
If {IXk } is a finite sequence, each I X intersects with U IXk" Hence,
in the same manner, we have the required inequality. This completes the proof of
this lemma.
Risin$ Sun Lemma. Let a be a function in an interval I such that
~ a(x) ~ ~ for any x E I, where ~ ~ O. Let A be a primitive of a. For
( ~ ~ T ~ ~ ), we define a function B in I by B(x) = inf ~(x), where
the infimum is taken over all functions ~ such that ~ ~ A, ~' ~ Y a.e. on I.
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33
Let b = B' and ~ = {x 6 I; A(x) # B(x)} = Uk= IIk, where {Ik}k= I
components of ~ . Then
(2.5) Y _-< b(x) _-< ~ a.e. on I,
(2.6) b(x) = Y (x 6 ~),
I (2.7) (a)l k _-< Y ((a)l k = ~ fl k a(s)ds, k >-_ i),
- (b)l i (2.8) I~I--< ~- T III ((b)l = "I~[ ~I b(s)ds).
are the
I
I
i z
Inequalities (2.5)-(2.7) are easily seen. We have
(b) I III = 71 b(s)ds = 71_62 + 7~
which gives (2.8). For the sake of convenience, we call this rising sun lemma RSL
of Type i (7-r~y,8-~e£~t); we shall use later various rising sun lemmas. For
an open set ~ , we denote by {I~ ,k}k=l its components. The following two lemmas
are also the rising sun lemmas for integrable functions.
Lemma 2.1 (The Calder~n-Zygmund decomposition [35, p. 12]). Let f E L I and
k > 0. Then there exists an open set ~ such that
= = ~c. I~I < llflll/k , (Ifl)l~,k k (k => i), If(x) l < k a.e. on
X TO see this, we put A(x) = f0 If(s) Ids (x > 0), and define a function B
in (0,~) by B(x) = sup ~(x), where the supremum is taken over all functions
such that ~ & A, ~' ~ k a.e. on (0,~). Let ~I = {x > 0; A(x) # B(x)}. Then
1 f~ If(s) Ids (Ifl) = ~ (k ~ i), l~ll ~ ~ • l~l,k
If(x) l ~ X a.e. on (0,®) - ~I "
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34
Considering f(-x), we obtain, in the same manner, an open set
Then ~i U {-x; x E ~2 } is the required open set.
In the same manner, we have
~2 in (0,~).
Lemma 2.2. Let f be an integrable function in an interval I and let k > 0
satisfy k > (Ifl)l. Then there exists an open set ~ in I such that
i I~I _-< ~ 71 If(x)I ds, (Ifl) I =<
~,k
If(x) l < k a.e. on I
(k>= i),
The (non-centered) maximal operator M is defined by Mf(x) = sup(Ifl) I, where
the supremum is taken over all intervals I containing x. For p > i, NMIIp,p
denotes the norm of M as an operator from L p to itself. The following lemma
is deduced from Covering Lemma.
Lemma 2 . 3 ([35, p.7]). IIMIIp,p ~ Cp (p > i).
For f ( L I, X > O, we put Ek = {x; Mf(x) > ~}. For each x ( EX, we
can choose an interval I x containing x so that (Ifl) I > ~ . Covering Lemma X
shows that there exists a sequence {Ixk}k=l of mutually disjoint intervals such
that IE~) ~ 5 %k= I Ilxk), which yields that
5 5 /i k if(s) ids ~ ~ [iflll " Ix; Mf(x) > ~I ~ ~ k~ I
For f ( L p and k > O, we define fx by fk(x) = f(x) if If(x) l > k/2
fk(x) = 0 if If(x) I ~ k/2. Then
HM f[] = Cp f0 xP-l]x; Mf(x) > k]dx
and
Cp 15 k p-I {Ix; Mfx(x) > X/21 + Ix; M(f-fk)(x) > k/2 I} dX
= Cp 75 xp-I ix ; MfN(x) > X / 2 ) dX
Cp /5 xp-2 llfkll I dX = Cp f~ xp-2 {fk/2 Ix;If(x) I > s I ds} dk
® 2s = Cp f0 Ix;If(x)] > sl { /0 xp-2 d~} ds = Cp llfll ,
which gives that IIMIIp,p Cp.
At last we note John-Nirenbergts inequality, which was used in Chapter I.
This is deduced from RSL. (For the proof of Theorem B, this is not necessary.)
Lemma 2.4 ([32]). Let f ( BMO and I be an interval. Then
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Ix E I; If(x)-(f)l I > k I =< exp(- Const >OIIl (7~_> l).
§2.3.
the sake of simplicity, we deal with only kernels
(See §i.9.) We use the notation ~(K), ff(l,K,f)
standard kernel, we define an operator K by
= K(x,y)f(y)dy I . K f ( x ) sup I f l x _ y 1 ' ' > g E > 0
-function ([8], [35], [54])
In this section, we show a fundamental inequality for standard kernels.
K(x,y) satisfying (1.21).
in (1.22), (1.24). For a
For
We show
Lemma 2.5 ([35], p. 49). Let K(x,y)
Then IIK I12, 2 ~ Const o(K) + C 6 ~5(K).
We begin by showing
be a 6-standard kernel (satisfying (1.21)).
(2.9) ~(K ) ~ Const if(K) + C 6 ~6(K),
where ~(K ) is the supremum of (l/Ill) /I K (Xlf)(x)dx over all f E Lreal,l
and intervals I. For ¢ > O, f E Lreal,l, an interval I and a point x on
I, we put J' = (x - s/2, x + s/2), J = (x - s, x + g), g = %1 fl J f and
h = XI_ J f. If 0 < ~ < IiI, we have, for any s E J' ,
Iflx-y I > s K(x'y)(XIf)(y)dyl = IKh(x) J ~ IKh(s) J + IKh(x)-Kh(s)J
IKh(s) I + C 5 ~5(K) ~ IK(Xlf)(s) I + IKg(s) l + C 6 ~6(K)
= IX ,(s)K(Xlf)(s)l + IKg(s) I + C O ~b(K), I
where I is the double of I. Taking first the square roots of the first
quantity and the last three quantities, and taking next their means over J' with
respect to s, we obtain
Iflx-Y I > s K(x'y)(XIf)(y)dyII/2
M(I X , K(XIf)II/2)(x) + (IKgll/2)j, + C 6 ~6(K) I/2.
I
If S = > III, then /Ix-yl > s K(x'Y)(XIf)(y)dy = 0. Hence this inequality holds
for all s > 0, which shows that this inequality holds with the first quantity
* (x)i/2 replaced by K (Xif) . Taking the squares of both sides of the resulting
inequality, and using Shwartz's inequality, we obtain
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K (Xif)(x) _-< Const M(IX , K(Xif ) I1 /2) (x) 2 I
1/2 2 + Const(iKg I )fl, + C 6 ~6(K).
Since
( M(IX ,K(Xlf) iI/2) < i IK(X (x) idx I 2) I = Const ~ fl* If)
< Const ~ {~(l,K,f) + ¢05(K) f , ( fl ~ dx} I -I
Const {~(K) + ~6(K)}
and
1/2.2 (IKgl )j, ~ (IKgl)j, & (IK(kj,g) l)j, + (IK(Xj_j,g))j,
we have
Let
~(K) + Const ~5(K),
(K*(XIf)) I ~ Const ~(K) + C 6 ~6(K), which implies (2.9).
f E L 2, K > 0. We show the following good k inequality:
* i (2.10) Ix; K f(x) > 3k, I@f(x) =< ~k I ~_ -~ Ix; K*f(x) > k I
where ~ > 0 is determined later. To prove this, it is sufficient to show that,
for each component I of {x; K f(x) > X} ,
* i Ix E I; K f(x) > 3X, Mf(x) ~ ~Ikl =< -~ llI.
If Mf(x) > ~k on I, this inequality evidently holds. Assuming that
M f(<) ~ ~k for some ~ E I, we prove
(2.11) Ix E I; K*f(x) > 3X} < 1 i1 l = - i O '
(See §1.4). Let g = Xjf and h = Xjcf, where J = (x 0 - 2II I, x 0 + 2III)
(x 0 is the left endpoint of I). Then we have
Ix E I; K*f(x) > 3X 1 < I X E I; K g(x) > k I
+ Ix E I; K*h(x) > 2k I (= L I + L2, say).
First we estimate L 2. Note that K h(x 0) ~ >~. For ~ > 0 and x E I, we have
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Iflx-y I > e K(x'y)h(y)dy -71x0_Y 1 > g K(x0'Y)h(y)dy I
~ I K(x,y) - K(x0,Y)IIN(Y)I dy + Const oos(K) Mf~)
=< C6 oos(K) Mf(~) =< C 5 oo 6(K) ~.
Since g > 0 is arbitrary, we have, with a constant C8,1 depending only on 5,
(2.12) K*h(x) <= K*h(x 0) + C 6,1 c°5(K) ~X
-<_ {i + CS,IOOs(K)~}k (x E I).
This shows that L 2 = 0 if C5 ,I oo5 (K) D < i. Next we estimate L I. By
Lemma 2.1, there exists an open set ~ = Uk= 1 I k (I k = ~,k ) such that
I~I < Ilglll/(100DX), (Igl)l k = 100~X
I g(x)I _<- i00~)~ a.e. on ~c
(k > I),
We define a function g by
f J g(x) (x ~ ~e),
\ L (x ~ I k, k ~ i).
(g) l k
Then llgll~ i00~. Put ~* ~ * * = Uk= I I k , where I k is the double of I k. Then
I~*I < 21~I =< llglll/(50 "qX) --< Mf(~)IJl/(50 ~X) =< 111/15"
*c For s > 0 and x ~ ~ , there exist at most two intervals (saying I I and 12 )
which intersect with the boundary of (x - s, x + s). We have, with
x k = (the midpoint of Ik),
I71x-y I > s K(x,y)(g(y) - g(y))dy I = If(i IN 12) n (x-s,x+g) c K(x,y)(g(y)-g(y))dY
+ % {K(x,y)-K(X,Xk)} (g(Y) - g(y))dy I I kc (x-s, x+s) e flk
< + (Igl)12} = Const oo6(K) {(Igl)ll
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+ C 0 co 6(K) Z (Igl) ~ C 6 co 6(K) ~ (i + A(x)). k=l (Ix-Xkl + Ilkl) I~5 I k
where &(x) : Sk= I "'[IkIl'~/(IX-Xk I + ''Ilkl) I+6. Since s > 0 is arbitrary, we
have
Since
J of
K g(x) ~ K g(x) + Cs~o6(K) q%(l + &(x)) (x e C'c).
supp(g) c J and I~l ~ III, the support of g is contained in the double
J. Hence (2.9) shows that
f , K g(x)dx =< f , K (X , g)(x)dx I-~ J J
--< ~(K ) llgll~ IJ*l =< {Const o(K) + C 0 ~8(K)} n~ Ill.
We have easily
I , {C 6 ~8(K) NX (i + 8(x)) } dx I-~
-<- c 6~8( K)~{l~i + I~i} ~_ c 0 ~8(K)~l~ l~J.
Consequently, we have, with an absolute constant C O and a constant C6, 2
depending only on 6,
(2.13) L I --< Ix E I - @ ; K g(x) > k I + I~*I
i * / , K g(x)dx + iII/15 I-~
i {K*~ T 7 , g(x) +c 0 ~8(K)n~(l +Mx))} dx + I~I/15 I-~
{(C O c(K) + C6, 2 ~8(K))~ + (1/15)} III .
Let
C6,1~6(K))-I ~6(K)) -I} = min {(2 , (30 C O c(K) + 30 C8, 2 •
Then (2,12) and (2.13) show that
• 1 l x E I; K f(x) > 3X l ~ L 1 + L 2 = L 1 ~ To III*
Thus (2.11) holds, which implies (2.10).
In the same manner as in §1.4, (2.10) yields that
llK*fll 2 ~ (Const/~) IIMfll 2 ~ {Const ~(K) + C 5 ~8(K)} llfH 2,
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3g
which implies the required inequality in our lemma.
~2.4. A-priori estimates
In this section, we show some inequalities which play important roles later.
For an operator T from L 2 to itself, we put
where
(2.14) ~0(T) = sup {~ $(I, T, XI); I interval},
(2.15) $(T) = sup { $(I, T, f); f ~ Lreal,l, I interval},
(2.16) ~(T) = sup {~ ~(I, T, f); 0 =< f <= i, I interval},
(2.17) ~(I, T, f) = fl IT(XI f)(x)I2 dx,
(2.18) $(I, T, f) = fl IT(Xlf)(x)I 2 f(x)dx.
For an open set ~ with I~I < ~ , we put
(2.19) ~(T;~) = sup { ~(l,T,f); f ( Lreal,l, I component of ~} .
For a 8-standard kernel K(x,y), we have easily o(K) ~ ~(K) I/2 ~- IIKII2, 2 ,
and hence, by Lemma 2.5,
(2.20) ~(K) I/2 -_< IIKII2, 2 ~_ Const ~(K) I/2 + C 8 0~8(K).
For a non-negative measure ~ on ~, we denote by (.,.) the inner product with
respect to ~ , i.e., (f,g) = f~ fg d~. (In the case of the 1-dimension
Lebesgue measure, we omit the suffix.) Here is an inequality necessary for the
proof of Theorem B.
Lemma 2.6. Let I be an (open) interval, ~ = Uk= 1 I k (I k = I2,k) be an
open set in I and let K(x,y), T(x,y) be two 8-standard kernels such that
K(x,y) = T(x,y) for any x, y ~ I - ~, x # y. Then, for any u, v ~ L 2
supported on ~ and a non-negative measure ~ with d~/dx ~ Lreal,l,
l(Ku,v) I =< I(ru,v) I + y~ I((K-r)(Xlk u), XlkV) 1 k=l
+ C8(co8(K) + cos(T)) HuPI~2 Ilvll,~2 ,
where
" 2 }1/2 (2.21) llwll,~2 = IIwll 2 + { E ]IXI~ wll 2
k=l (w = u,v; I k is the double of Ik).
Proof. Since XI_ ~ (K-T)(XI_~U) = 0, we have
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L 1
+ Z k=l
(= Z k=l
Let x k be an endpoint of I k
*¢ y ( (I k ) N Ij, k < j, then
I (Ku,v)~I --< I (Tu,v)~I + I ((K-T)(X~u), X~v)~I
+ ] ((K-T)(X~ u), Xl_~V)g[ + [ ((K-T) 0(I_ ~ u), X~v)~[
( = I (ru,v)~l + L I + L 2 + L3, say).
Without loss of generality, we may assume that
with Xk = Xlk (k > i),
=< Z ]((K-T)(XkU), XkV)~l k=l
® ~ k-I
Z l((K-T)(XkU), Xjv)~ I + Z Z j =k+l k=2 j =I
]((K-T)(XkU), XkV)~] + LII + LI2, say).
such that x k ( I -~ (k >-- i).
IIii _>- 1121 ->- . . . . We have,
l((K-T)~kU), Xjv)~I
If x ( I k,
IK(x,y) - T(x,y) I = IK(x,y) - K(Xk,X j) + T(Xk,X j) - T(x,y) l
C 8 llklS/[x-yl I+6
* c * then we have evidently (Here we assume xj ( (I k) . If xj ( I k,
IK(x,y) - T(x,y) l ~ C 8 llklS/Ix-yll+8.) Hence
LII --< Z f , l(K-T)(XkU)(X)V(x)Idx k=l Ik-I k
+ Z Z f *c I (K-T) (XkU) (x)v(x) ] dx k=2 j=k+l (I k ) N Ij
=< C8(¢o8(K) + ~6(T)) [ Z f * {flk dy} k=l Ik-I k
+ Z fl {fie I Ik]6 k= 2 k e ix_yll+8 lu(y) Idy} Iv(x) l dx ]
C8(¢o8(K) + cos(T)) { >~ k= l
+ Z lu(Y) l Mv(y)dy} k=2 fI k
I v ( x ) l dx
f , IH(X k u)(x)v(x)I dx Ik-I k
~- C6(es(K) + ¢o8(T)) lluII 2 llvIl,~ 2
_-< C8<¢o8(K) + ~8(T)) Ilull,~2 Iivli,22 •
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Using the adjoint kernel of
LI2 ~ C8(~8(K) + ~8(T)) HulI~2 llvll~2 *e
If x E I k, y ~ (I k ) n (I - ~), then
IK(x,y) - T(x,y) l = IK(x,y) - K(Xk,Y ) + r(xk,Y) - T(x,y) l
c 8 IIkIs/Ix-yI 1+8
Hence we have, in the same manner as in LII,
L 2 a Z f , [(K-T)(XkU)(X)V(x)Idx k=l Ik-I k
+ Z f * c l(K-T)(XkU)(X)V(X) I dx k=l (I k) n (i-~)
C8( ~8(K) + ~8(T)) lluIl,~2 IIvII,~2 .
using the adjoint kernel, we have also
n 3 ~ C8(~8(K)+ ~8(T)) lluN,~ 2 Ilvll*~2 •
Thus the required inequality holds.
The following three lemmas are corollaries of Lemma 2.6.
Lemma 2.7. Let I, ~, K(x,y) and
for any f E Lreal,l,
Proof.
we have
K(x,y) - T(x,y), we have, in the same manner,
Q.E.D.
T(x,y) be the same as in Lemma 2.6. Then,
~(I,K,f) 5 (~(I,T,f) + Z ~(Ik,K,f) k=l
+ C8(~(T;~)I/2 + oos(K) + o)8(T)) Ill.
using Lemma 2.6 with u = klf, v = X I K(XIf)/IK(XIf) I and d~ = dx,
~(l,K,f) = l(Ku,v) l <-- I(Tu,v) I + Z [((K-T)(XkU), XkV) I k=l
+ C8(~08(K) + ~os(T)) III _-< ~(l,T,f) + Z ~(l,K,f) k=l
+ C8(~(T;~)I/2 +~8(K) +~8(T)) lIl.
Lemma 2.8. Let
anti-symmetric
Q.E.D.
I, ~ be the same as in Lemma 2.6. Let K(x,y), T(x,y) be two
8-standard kernels such that K(x,y) = T(x,y)
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(x, y 6 1 - ~, x # y). Then, for any f 6 Lreal,l with 0-<- f < i,
(l,K,f) < ~(l,T,f) + Z k='i
~(Ik,K,f) + C 5 AI(K,T;~)III
where
AI(K,T;~) = {~(T~52) I/2 +~os(K) +~os(T)} {a(K) +a(T) +o~8(K) +~Os(T)}
Proof. Without loss of generality we may assume that supp(f) c I. Using
Lemma 2.6 with u = f, v = XIKf and d ~ = f dx, we have
~(l,K,f) < l(rf, XiKf)fdxI + Z ]((K-T)(Xkf), XkKf)fd x ] k=l
+ C8(~8(K ) + c08(T)) [Ifll,~ 2 11XiKfIl,~ 2 (= L 1 + L 2 + L3, say).
We have easily
L 3 =< C8( ~6(K) + ~8(T)) IIKII2, 2 t I]
_-< C6(~o6(K) + ~08(T))(a(K ) +¢o6(K))II I .< C 8 AI(K,T;~) ] I [ .
(See (2.22)). Since K(x,y), T(x,y) are anti-syn~netric, (Xkf(K-T)~k f))Ik
, ' = (the midpoint of Ik), (k ~ i). Hence we have with x k
L 2 = Z Iflk f(x)(K-T)(Xkf)(x) K{(X k + X , + X *c )f} (x)dx 1 k=l Ik-I k I k
<= z If k=l I k
+ ~o8(K) k=iZ flk l(K-r)(Xkf)(x) I (
+ k=IZ Iflk f(x)(K-r)(Xkf)(x) { K(X *e I k
=< Z $(Ik,K,f) + Z llXkT(Xkf)II 2 llK(Xkf)ll 2 k = l k= l
+ ~6(K) Z ll(K-r)(Xkf)II2 {fie ( f , k = l I k - I k
+ C 8 ~o6(K) k=iZ flk I (K-T) (Xkf) (x) I dx
--< Z ~(Ik,K,f) + Cs(~(T;a) I/2 + ~8(K)) (]IKII2, 2 k = l
--< Z ~(Ik,K,f) + C 8 AI(K,T;~) Ill. k = l
f(x)(K-T)(Xkf)(x) K(Xkf)(x) dxl
f. ~ ) dx I k- I k
f) (x) - K(X (~) dx Ik ef ) } 1
--~)2dx}i/2
+ IPTIF2, 2) I~I
= 0
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Using Lemma 2.6 with u = f, v = EiTf and d~ = f dx, we have
L I = l(Kf, XiTf)fdxl ~ ~(l,T,f) + Z I((K-T)(Xkf), XkTf)fd x 1 k=l
+ C6(~Os(K) + ~o6(T)) llfll,~ 2 IIXITflI,~ 2 (= ~(l,T,f) + Ell + LI2, say).
We have
LI2 -<- C8(~06(K) + ~5(T)) IITII2, 2 II! :< C 6 AI(K,T;~) Ii~. ~
In the same manner as in L 2,
LII = Z Ifik f(x)(K-T)(Xkf)(x ) T{(X k + X , + X ,c)f}(x) k=l Ik-I k I k
dx p
=< k=iZ I71k f(x)(K-T)(Xkf)(x) T(Xkf)(x) dx 1 + C 8 AI(K,T;~) Ill
+ liTIl2, 2) ~(T;~) I/2 III + C 8 AI(K,T;~) III (IIKII2, 2
c 8 AI(K,T;~) III.
Thus the required inequality holds.
Lemma 2.9. Let I, ~, K(x,y) and
E c [, we put K E = ~KME, where M E
define inductively K~ k) = ~4k-l)(k
define T~ k) in the same manner as
@(l'K~2)'f){1 ~ ~(I, TI(2), f)
Q.E.D.
T(x,y) be the same as in Lemma 2.8. For
where
is a multiplier: g ÷ XEg. We
i; K~ 0) is the identity operator).
K~ k). Then, for any f ( LTeal,l,
+ Z $(I k, K (2) f) + C 6 A3(K,T;~), k=l I k '
We
A3(K,T;~ ) = {$0(K) I/2 + $0(T) I/2 + ~(T;9) I/2 + ~6(K) +
× {o(K) + o(T) + ~8(K) + ~8(T)} 3.
ms(T)}
Proof. We divide the proof into several steps.
(First Step). We begin by showing that
(J) < C6(~(x ) + ~8(x))JlI 1 (2.22) fIX I fll,~ 2 =
For any g ( L 2 supported on I, we have, with
(i -<_ j ~ 3, X = K, T).
I k = (the double of I k) ,
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fl~ IXg(x) I 2 dx ~ 3 / , !X~ ** g)(x)I 2 dx
I k I k
+ 3 f , IX~ **c g)(x) - (X~ **c g))Ik I2 dx I k I k I k
+ 3 Ii~I l(X(Xlk**C g))Ik I2 = < 3 IlxiI~,2 IiXlk** glI~
2 )ikl 2 + C6 ~6(X) 2 ![Xk Mgll 2 + 6 llkl ](X(X **c g) I k
and
Thus
IXkl I(X(X **c g))Ik 12 ~ 211kl l(xg)Xkl2 + I k
=< 2 [Ikl l(Xg)ikl2 + C6(~(K ) +~6(K)) 2
211kl [(X(X ** g))ik 12 I k
fIX ** gll~" I k
% f , IXg(x)I 2 dx =< Const % Ilkl l(Xg)ikl2 k=l I k k=l
)2 ~g]122 + 2 + CS(~(K) + 0~6(K) % (ilk k IlK ** g]I 2 ) k =I I k
=< C6((~(K) + ~o6(K))2 {Hgt122 + % Ilk ** gll~ }, k=l I k
which shows that
HgiI,~ 2 _-< C6(a(K) + ~6(K)) llgIl**~2 ,
where II'II**~2 is defined by (2.21) with I~ replaced by I k . If j = i, we
put g = Xif. Then this inequality gives (2.22). If j = 2, we put g = Xif and
use the above argument. To estimate IIXifll**~2 , we use again the above argument
with I k replaced by the double of I k . Then we obtain consequently (2.22).
If j = 3, we put g = Xi(2)f and use the above argument 3 times. Then we obtain
(2 .22) .
(Second Step) . We show tha t , for any u, v E L 2 supported on I ,
(2.23) E I(XkU, Yiv) I ~ % I(Xk u, YkV) l + C 6 { ~6(Y)(~(X) + 0~6(X)) k=l k=l
+ $0(xll/2(~(Y) + o~6(Y))} Ilull 2 Ilvli,~ 2 (X = K, T; Y = K, T),
where X k ' Yk = Xik = Yik.
We have
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+
Z k=l
Z k=l
(XkU, YIV) I ~ Z l(XkU, YkV) l + Z l(XkU, Y(X , v))l k=l k=l Ik-I k
(XkU, Y(X *c v))I ( = Z I (XkU, YkV) I + L 1 + L 2, say). I k k=l
Put <k = (XkU)ik (k ~ i). Then
l~kl = I(uX k Xk)ikl ~ $0(X) I/2 { ~ ~I k lu(Y) l 2 dy} I/2 (k ~ i)
We have, with x k (the midpoint of Ik)
L 2 = Z Ill k (XkU(X) - ~k ) {f *c (Y(x,y) - Y(x{,y))v(y)dy} dx k=l I k
Y(X *c v)(x) dx I + ~k fl k ik
--< C b ~o6(Y) Z (IIXk(XkU) ~vll I + -}~kl fix k Mvll I) k=l
+ z l<kl(Hx k YvH 1 + [l×kY(× , v)HI) k=l Ik-I k
=< C 6 c°6(Y) (IIXli2, 2 + ~o(X) I/2) ilull 2 Iivll 2
+ C 6 $0(X) I/2 (NY[]2, 2 + c06(Y)) [lull 2 J[vH,e2
C 6 { ~b(Y)(o(X) + cob(X)) + ~0(X)I/2(o(Y) + cob(Y))} IIull 2 !Ivli,~22
and
L I e6(Y) Z Ilk IXkU(X) l ( I , dy) k=l Ik-I k
= Const e6(Y) Z I , Iv(Y) llHIXkUl(Y)IdY k=l Ik-I k
C 5 ~6(Y)(o(X) + ~b(X)) llull 2 Ilv![,~2 •
dx
Hence (2.23) holds.
(Third Step).
(2.24)
We show that
. (3):. ~ (2) l l(Kk f, t< I z) i -<- Z %(Ik' ~k ' f) k=l k=l
+ C 6 A3(K) Ill,
where
A3(K) = ($0(K) I/2 + ~6(K))(~(K) + ~6(K)) 3.
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. (2)f X = Y = K and using (2.22) we have Using (2.23) with u = Xlf, v = ~I '
Z I (Kk f, K~3)f) 1 -< Z" I (Kkf, K k K~2)f) I k=l k=l
+ % ($0(K) I/2 +~o6(K))(~(K) +o08(K))
(2)f)l + C 6 A3(K) III Z I (Kk (2)f, K I k=l
Using (2.23) with
fix if!I 2 II K~2) fll ~2 2
e o
u = Zk= 1 Kkf, v = Klf , X = Y = K, we have
Z I(Kk(2)f, K~2) f) I < l I(Kk(3)f, K I f)l + C 8 A3(K)IIl- k = l k = l
Using (2.23) 42)f, with u = Zk= I v = Xlf, X = Y = K, we have
% I " (3)~ (~k ~' Klf)l -<- % ~(Ik' 4 2)'f) + C8 A3(K) III" k = l k = l
Thus (2.24) holds.
(Fourth Step).
(2.25)
We show that
Z l(ZkT~J)f, K~3-J)f) I =< C 8 A3(K,T;~)III k=l
(i ~ j =< 3, Z = K, T).
C6{~6(T) (~(Z) + ~6(Z)) + ~0(Z)I/2(~(T) + ~8(T))} ]IK~2)fll 2 I]fll,~ 2
)2 C 6 a(T;e)I/2(~(Z) + ~o6(Z))(a(K) + ~Os(K) IIl
C 8 {~os(T)(o(Z ) + o~8(Z)) + $o(Z)I/2(o(T) + ~8(T))} (<~(K) + ~o8(K))2 III
If j = i, we use (2.23) with u = K~2)f,{ v = Xlf, X = Z, Y T. Then
Z I(ZkTI f,K~2)f) I = % I(ZkK~2)f, Tlf)I =< % l(ZkK~ 2)f, Tkf) l k=l k=l k=l
+
+
< C 8 AB(K, T; e) III.
If j = 2, we use (2.23) with u = Kif, v = Tif, X = Z, Y = T.
Z l(ZkT~2)f, Klf) I = Z l(ZkKlf, T~2)f)l k=l k=l
=< Z I(ZkKI f, TkTlf) I + C 8 AN(K , T; ~) III. k=l
Then
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Using (2.23) with u = Ek= I ZkKlf , v = f, X = Y = T, we have
Z I(Z k Klf, TkTlf)I = Z I(Tk Z k Elf, rlf) 1 k=l k=l
_-< Y [(rkZkKlf , Tkf) [ + C 6 A3(K,T;~ ) III =< C6A3(K,T; ~) [I[. k=l
If j = 3, we use (2.23) 3 times. Then, in the same manner, we obtain (2.25).
(Final Step). We now show the required inequality in our lemma. Without loss of
generality, we may assume that supp(f) c I. Using Lemma 2.6 with u = f,
v = K$3)f," d~ = dx and using (2.22), (2.24), we have &
(2.26)
+ Z I CCKk- Tk)f, K~3)f)[ + C8(~6(K) + ~6(T)) NfH,~ 2 l]K~3)fli,~2 k=l
I(rl f, K~3)f) I + % I(Kkf,K~B)f)I + C 6 A3(K,T;~) Ill k=l
< l(rlf ' K~3)f) I + ~ ~ (2) = ~(Ik, ~ ,f) + C 5 A3(K,T;~) [I[. k=l
Using Lemma 2.6 with u =Tlf , v = K~2)f and using (2.22), (2.25), we have
+ Z I((Kk - Tk)Tlf , K~2)f)l + C 8 A3(K,T;~) [I I k=l
~l(T~2)f, K~2) f) I + C 5 A3(K,T;~)l!I.
Repeating this argument 2 times~ we obtain
(2.27) i(T 2)f, K 2)f)i < 2), f) ÷ c6 A3(K,T )
Thus (2.26) and (2.27) give the required inequality in our lermna.
§2.5. Proof of Theorem A by perturbation ([45])
In this section, we deduce Theorem A from the boundedness of the Hilbert
transform and Lemma 2.9. (We do not use Cotlar's lemma nor the Fourier transform.)
Fixing 0 < s < 1/2, we define
S[a](x,y) = ks(x-y ) T[a](x,y),
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where
(s) = g
(IsIl~) - i ( ~ < Isl --< 2~)
(2S < !s I --< ll(2s))
(i - slsl) (1/(2s) < Isl <_- l/s).
We shall show that IIS[a]ll2, 2 $ Const flail, . Once this is known, Fatou's lemma
gives Theorem A. Without loss of generality, we may assume that a ( Lreal,l.
, ~ Const{o(S[a]) + I} Since ~l(S[a]) ~ Const Lemma 2.5 shows that Iis[a]II2, 2
Hence it is sufficient to show that
(2.28) ~S = sup {o(S[a]); a ( Lreal,l } < Const .
Let
- i (2) f); OS(2) = sup { ~[" ~(I, S[a]i ,
where S[a]~ 2) is defined in the same manner as K~ 2) in Lemma 2.9.
Shwartz's inequality shows that ~ <~ From the definition of = S(2)"
is finite. For a, f ( Lreal,l and an interval I, we show that
a, f ( Lreal,l , I interval},
Then
S[.], @ (2) S
2 )4 3 ~ 3 (2.29) i~ I ~(I, S[a]~ 2), f) = < {( ~ + 7 } ~S(2) + Const {~S + i}.
Considering -a if necessary, we may assume that (a) I $ O. RSL of Type 1
(-1/3-&.,l-a.) shows that there exists b E Lreal,l such that, with
= {x ( I; A(x) # B(x)} (B(x) = A(x0) + f~O b(s)ds, x 0 is the left endpoint of
I),
(2.30) -1/3 ~ b(x) ~ 1 a.e. on I, b(x) = -1/3
l-(b)I l-(a)I 3 (2.31) I~I ~ 1+(1/3) Ill ~ i+(i-7~ Ill ~ 7 III"
on ~,
(The function b obtained from RSL is defined only on I. Since (2.30), (2.31) are
independent of the behavior outside I, we may put b(x) = 1 (x (IC).) Since
A(x) = B(x) (x ( I -~), we have S[a](x,y) = S[b](x,y) (x, y E I -~). Using
Lemma 2.9 with K = S[a], T = S[b], 6 = i, we have
~(I, S[a]~2),f)= < $(I, S[b]~ 2), f) + Z ~(I k, S[a]~2 k), f) k = l
+ Const A3(S[a] , S[b]; ~) [I I,
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where ~ = Uk= I I k (I k = l~,k)-
dominated by (3/4) ~S(2) Ill . Put
S[D] = S[b] + (~/3)H, and hence
The second quantity in the above inequality is
= b - (1/3). Then II~II~ ~ 2/3 and
~ ( I , S[b]~2) , f ) =<- ~ ( I , S["~]~ 2) , f) + Const IIsEE]ll~, 2 III
3 =~ (2)4~s(2) i! I +Const {%+1} IIl.
Thus
, 2 )4 3 $ [I[ $(I, S[a]~ 2) f) ~ {( ~ + ~} S(2)
3 + Const {oS + i}III + Const A3(S[a], S[b]; ~) IIl.
It is necessary to estimate
for any interval J and x E J,
k (x-y) ] SIal Xj(x) I -<- Ifj ~x-y
Lemma 2.5 shows that
k (x-y) fj ifj g x-y
A3(S[a], S[b]; ~). Integration by parts shows that,
a(y)dy I + Const.
a(y)dy I dx ~ Const NH*(Xja)II 2 IJl I12
Const (~(H) + 1) IJl E Const IJl.
Hence we have (i/IJ I) ~(Ji S[a], Xj) ~ Const. Taking the supremum over all
~0(S[a]) & Const . In the same manner, ~0(S[b]) ~ Const. Since
b(x) = -1/3 on ~, we have, for g ~ Lreal,l ,
J,
and hence
~(I k, S[b], g) = Const $(I k, H, g) & Const Ilkl (k a i),
~(S[b]; ~) ~ Const. Consequently,
AB(S[a], S[b]; ~) ~ Const {~ (S[a]) + ~(S[D]) + 1} 3
3 Const (~S + i) ,
which gives (2.29).
Taking the supremum of (i/IIl) 5(I, S[a]~ 2), f)
and all intervals I, we obtain, by (2.29),
over all a, f 6 Lreal,l
2 )4 ¼ ~ 3 8S(2) ~ {( ~ + } ~S(2) + Const {o S + i}.
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Since (2/3) 4 + (3/4) < I and ~ ~ ~ ~S(2) , this inequality yields (2.28).
This completes the proof of Theorem A.
§2.6. Proof of Theorem B by perturbation ([17])
In this section, we deduce Theorem B from the boundedness of
two lemmas necessary for the proof.
H. Here are
Lemma 2.10 (Calder~n [4]). IITn[a]ll2,2 $ (Const) n llalI~ (n ~ i).
Proof. Fixing 0 < s < 1/2, we put
Since
Sn[a](x,y ) = X (x-y) Tn[a](x,y) g
el(Sn[a]) ~ Const n JPalI~, it is sufficient to show that
n+l (2.32) ~S = sup {~(Sn[a]); a ( ereal,l } ~ C O
n
for some absolute constant
So[-] = (-~)H.
(0 ~ k ~ n-l).
4
<~Sn -<- ~S (2) " n
C O (which will be determined later). Let k+l
Then ~So = ~(-[ H) ~ ~. Suppose that ffSk ~ C O
We d e f i n e ~S(2) in the same manner as ~S(2)" Then n
Let a, b, f, I, ~ be the same as in §2.5. Using Lemma 2.9 with
K = Sn[a], T = Sn[b] , 6 = i, we have
(2.33) ~(I, Sn[a]~ 2), f)= < ~(I, Sn[b]~ 2), f)+ Z ~(I k, Sn[a]~2), f) k=l
+ Const A3(Sn[a] , Sn[b];~ )llI.
Put b = (3/2)(b- (1/3)). Then
2 b* i Sn[b ] = Sn[ 3 + ~] =
I]b I[~ =< 1 and
n i n-k * (2)k Sk[b I k=0
By Lemma 2.5 and the assumption of our induction, we have
IISk[d]II2, 2 ~ Const {~Sk + ~l(Sk[d])}
Const (C~ + n) (d ( e~eal,l, 0 ~ k ~ n-l).
Hence, in the same manner as in §2.5, we obtain, by (2.33),
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~(I, Sn[a] 2) f) ~ { (~)4n + 4 } S (2) n
+ Const (C~ + n)~ S + n) 3 + Const (C~ + n) 4. n
Since a, f E Lreal,l and I
quantity replaced by @S(2) .
4 n ~S ~ ~ we have
n S (2) ' Sn n
are arbitrary, this inequality holds with the first
Since (2/3) 4n + (3/4) ~ 0.99 and
' Let =< C 0' (C + n) for some absolute constant C O •
C O max {2 C~, ,} Then ~S _n+l = • ~ Gn • This shows that (2.32) holds for all n
n ~ 0. This comple t e s the p roof of Lemma 2 .10 . Q.E.D.
Remark 2.11. It is known that
IITn[a]II~,BM 0 ~ Const {IiTn[a]II2, 2 + ~l(Tn[a])}
¢onst {I!Tn[a]!12, 2 + (n+l)} (n ~ O, a E Lreal,l),
IITn[a]II~,BMO L ~ where is the norm of Tn[a ] from to BMO. (See Lemma 2.5.)
The proof of Lemma 2.10 by Theorem 1.12 is as follows. Let a E Lreal,l
and n ~ i. Integration by parts shows that Tn[a]l = Tn_l[a]a. Hence
Theorem I shows that
IITn[a]H2, 2 ~ Const {IITn[a]IIIBM 0 + n}
= Const {liTn_l[a]aIIBM O + n} ~ Const {IITn_I[a]II~,BM O
Const {Hrn_l[a]II2,2 + n} ,
+ n}
which gives Lemma 2.10.
For a E Lreal, we define a kernel
(2.34) E[a](x,y) = 1 exp {i A(x)-A(y)_} , x-y x-y
where A is a primitive of a. The following lemma was first shown by
Coifman-McIntosh-Meyer [7]. A proof by perturbation was given by David [17].
Lemma 2.12.
Proof. Since
There exists an absolute constant N O such that
N O IIE[a]II2,2 ~ Const(l + llall=) (a E L~eal).
~l(E[a]) ~ Const (i + llall~), it is sufficient to show that
N O ~(E[a~) ~ Const (i + llall )
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for some absolute constant N O ~ i. We put
(2.35) aE(~) = sup {o(E[a]); a ( ereal,6} ( ~ > 0)
and show that
N O (2.36) ~E(~) -<_ Const(l + 6) ( ~ > 0).
Lemma 2.10 shows that, for any a ( Lreal,
i n = i
~(E[a]) = ~( Z nl Tn[a]) =< Z ~-f ~(Tn[a]) n=O n=O
-<- Z i n! (C°nst)n 11alln <= exp {Const(l + Iiaii®)} • n=0
Hence OE(~) < ~ for all ~ > 0 and ~E(1) ~ Const. Let
> i, a ( L~eal,~ , f ( Lreal,l and I be an interval. RSL of
Type i (-~/3- A.,B- a.) shows that there exists b ( Lreal such that, with
= {x ( I; A(x) # B(x)},
- 613 ~ b(x) ~ 6 a.e. on I, b(x) = - ~13 on ~ ,
6 - (b) I 3
Using Lemma 2.7 with K = E[a], T = E[b], 5 = i, we have
~(I, E[a], f) _~ a(l, E[b], f) + Z O(Ik, E[a], f) k=l
+ Const {$(E[b];e) I/2 + ~01(E[a]) + ~Ol(E[b])} Ill,
where I k = I~, k (k >_- i). Put ~ = b - (6/3). Then II{II~ =< 2~/3 and
~(I, E[b],f) = ~(I, E[~], f). We have 001(E[a]) + O~l(E[b]) =< Const ~ .
Since b(x) = -~/3 on ~, we have
D(E[b]; ~) = ~2~(H;~) =< Const.
Thus
~(I, E[a], f) ~ OE ( ) + ~E(~) + Const 6 ,
which yields that
~E(6) _-< OE( ) +~ aE(~) + Const ~ ,
that is,
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(2.37) OE(~) < 4 ~E(23 ~) + Const ~ .
Let n be the minimum of integers k->- 1 such that (2/3)k~ ~ I.
n =< (log ~)/(log 3/2) + Const. Inequality (2.37) shows that
n-i OE(~) =< 4n~E((2)~) + Const % 4 k (2)k3
k=0
-_< 4 n {~E(1) + Const (2)n ~}
_-< Const 4n_- < Const (i + ~) N0 ,
Then
where N O = (log 4)/(log 3/2). Thus (2.36) holds. This completes the proof of
Lemma 2.12. Q.E.D.
e-iXs e-S We now give the proof of Theorem B. Since i/(I + ix) = f0 ds
(x ~ ~), we have
C[a] = f~ E[-sa]e -s ds.
By Lemma 2.12, we have
IIC[a]I12,2 =< f0 IIE[-sa]ll2,2 e-s ds
N O N O Const f0 (I + sllall ) e -s ds _-< Const (i + IIall~)
This completes the proof of Theorem B.
§2.7. Estimates of norms of E[.] and C[.]
In this section, we show
Theorem C ([44]). For any real-valued function a in BM0,
(2.38) NE[a]II2,2 ~ Const (i + IIalIBMO ),
(2.39) IIC[a]I12,2 ~ Const (i +~IIalIBMO).
9 In [7], (2.38) was given with IIalIBM O replaced by IIalIBM O, and (2.39)
8 with __~MO replaced by IIaIIBM O. This theorem was established in was given
[44] via [42], [43], [50]. In this note, we deduce Theorem C from (2.36). We
use RSL repeatedly. (The sun also rises!) RSL in §2.2 is called of
Type i (y - r.,$ - a.) The lower bound of a(x) is independent of (2.5)-(2.8).
Let a(x), I, ~, ~ and A(x) be the same as in RSL in §2.2. For 0 ~ T ~ ~ ,
we define analogously B(x) by using the sun at the right upper infinity of angle
aretan y. Then
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~ b(x) ~ 7 a.e. on I, b(x) = 7 (x ( I k, k ~ i),
(a)ik ~ T (k g i), I~I ~ (-~) * (b)l III. (-~) + 7
This RSL is called of Type 2 (y-hay,~-dg6ee~). In this case ~ is
independent of the above estimates. For 0 ~ 7 ~ ~ , we define B(x) = sup @(x),
where the supremum is taken over all functions @ such that • ~ A, ~' ~ T
a.e. on !. We define b, ~ in the same manner. Then
--<- b(x) --< 7 a.e. on I, b(x) = 7 (x ( I k, k >_- i),
(-~) + (b) (a)i k I Ill. > y (k ~ i), I~I =< (-~) + 7
This RSL is called of Type 3 (y-r., ~-d.) . In this case ~ is independent
of the above estimates. For ~ ~ 7 ~ 0, we define B(x), in the same manner
as in Type 3, by using the sun at the lower right infinity of angle - arctan 171'
Then
7 ~ b(x) ~ ~ a.e. on I, b(x) = 7 (x ( I k, k ~ i),
- (b)l
(a)ik ~ T (k ~ i), I~I ~ ~ _ 7 llI.
This RSL is called of Type 4 (Y-~.,B - a.).
of the above estimates.
In this case, ~ is independent
Type 1 Type 2
Type 3 Type 4
RSL of Type j is reduced to RSL of Type i by a suitable affine transformation.
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§2.8. Proof of (2.38)
(First Step). We divide the proof into three steps. Recall ~E(~) defined by
(2.35). Put
~E(~) = sup {~(E[a]);a E Lreal,~} (~ > 0).
(See (2.16).) In this step, we show that, for ~ ~ i, 0 < 5 ~ i,
(2.40) ~E(~) ~ ~E(@~) + ~ ^ .l+e ~E~T ~) + (Cs/e) ~5{~E(~) + ~5} ,
where e (0 < e < i) is determined later. For a E Lreal,~, f E Lreal,
0 ~ f ~ i and an interval I, we study an a-priori estimate with respect to
~(I, E[a], f). Since ~(l,E[a],f) = ~(l,E[-a],f), we may assume that
L ~ > 0. RSL of Type i (- e~- ~., ~ - ~.) shows that there exists b ~ real (a) I = such that, with ~ = {x E I; A(x) # B(x)} = Ok= I I k (I k = l~,k).
- 6~ ~ b(x) =< ~ a.e. on I, b(x) = - e~ (x E I k, k > i),
(a)ik ~ - e~ (k = > i), I~I =< ~ +- ~ III ( ~ = (b)l)-
Using Lemma 2.8 with K = E[a], T = E[b], we have
~(I, E[a], f) -<_ ~(I, m[b], f) + % ~(Ik, E[a], f) k=l
+ C 6 AI(E[a] , E[b]; ~) IIl.
Since ~o6(E[a] ) _< C5 ~5, 0~6(E[b] ) < C5 ~6 and
~)i/2 $(E[b]; = Const $(H;~) I/2 < Const =
we have
and hence
AI(E[a ],E[b];~) = {&(E[b];~)I/2 + ~5(E[a]) + ~5(E[b]) }
× {~(E[a]) + ~(E[b]) + ~5(E[a]) + ~5(E[b])}
_<_ C5 F5 {~E(F) + ~5 } ,
~(I,E[a],f) < ~(I,E[b],f) + % k=l
$(ik,E[a ],f) + C5 ~5{~E(~) + ~5} ii1.
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< For each I k, we use~ RSL of Type 2 (e~ -&.,-6-d.).~ Since (a)~ - e~
t he re e x i s t b k ~ L rea l and an open se t ~k = U g = l l k , g in I k such tha t
-~ & bk(X) ~ e~ a.e. on I k, bk(X) = 8~ (x E ~k ),
(a) I ¢ e~ ( ~ I), k,g
-(-6 )+(bk) Ik ~+ (a)ik
=< -(-~) + e~ I Ikl < ~+ e~ i- e
IXkl --< "i + e IXk I"
Let bk = bk - (i -e)~/2). Then ll%k[l= =< (l +e)~/2 and
~(Ik,E[%k],f) = $(Ik,E[bk],f). Hence, by Lermma 2.8, we have
g(ik,E[a],f) < ~(Ik,E[bk],f) + Y $(Ik, g, E[a], f) g=l
l+e + % AI(E[a],E[bk]; g~k ) llkl =< ~E (T~) Ilkl
+ ~ g(Ik,g, E[a] ,f) + C 5 ~5 {OE(~) + ~5} i xkl ' g=l
which yields that
g(l,E[al,f) N $(l,E[b],f) + l+O ~E ( T ~) z l~kt
k=$
+ k=l% g=i% o(Ik' g, E[a],f) + C 5 ~5 {~E(~) + ~6}{ii I + k=lY llkl}.
For each Ik,~, we use RSL of Type i (-e~-&.,~-4.) Since (a) Ik,g
= in such that we obtain an open set ~k,~ U~=I Ik,g,m Ik,~
(a) ~ - e~, Z llk,~,ml < 1 - e I " Ik,g, m m= 1 = I + e llk,g
>--eF,
In the same manner as above,
i+@ ~(l,E[a],f) ~ ~(l,E[b],f) + ~E ( T ~)
^
% % % ~(Ik,g,m, E[a], f) k=Ig=l m=l
{ £ llkl + E Z llk,~l} k=l k=l ~=i
+ C5 ~5{aE(~) + ~5} {lll+ % llkl + % Z Ilk,~I} • k=l k=l g=l
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^
Since (a) I -<- - 8 ~ , c~(Ik,g,m, E[a], f) ^ k,& ,m
in ~(Ik,E[a],f). Repeating this argument,
is estimated in the same manner as
.i+@ l-e i-8 2 ~(l,E[a] ,f) =< ~(l,E[b] ,f) + E(~ - ~) I~I {1 + i~ ÷ (i~) + "}
l-e I-8 2 +C 8 p8 {~E(~) +~8} {JZj + I~I (I+~ + (i-~-) + ...)}
^ l+e~. ~-n ~(l,E[b],f) + OE(2-~-p) ~ + 8~
^ ^ ,l+e ~ - n = o(l,E[b] ,f) + OE<-- ~- ~) 2e~
l+e J iJ + (C5/8)~5{aE(~) + ~6} J xl 28
-I~I + (%/e) ~8{C~E(~) + ~8} I~I.
To estimate
There exist
~(l,E[b],f), we use RSL of Type 3 (85-r.,-e~-d.) to b(x)
r Oj=l ' in I such that c ( L eal and an open set ~' = ~ Ij
and I.
-8~ -_< C(X) K e8 a.e. on I ,
-(-e~) + (c) x P~ +n jlJ. ]e'I-<- ./-'(-e~) + e~ Jxj _-< 2ep
In the same manner as above,
~(l,E[b],f) =< ~(l,E[c],f) + Z j=l
^ ,l+e e~ + q, ~E (e~)Ill + ~E<--2 - ~) 2e~
~(l],E[b],f) + C 8 ~8 {OE(~) + ~8} ii I
Consequently,
i $(l,E[a],f) < {~E(e~) + SE (--2- ~) 2e~ + C8 ~8(~E(~) + ~6)} 7U =
+ { ~E<T ~ ) ^ ,i+8 ~28~- ~ + (C8/8)~5(~E(~) + ~5)}
1+8 ^ .l+e SE(e~) + -~- OEi_T ~ ) + (C8/8) ~6{~E(~) + ~8},
which gives (2.40).
(Second Step). In this step, from (2.40), we deduce
(2.41) ~E(~) ~ Const ~ ( ~ g i).
Let
1+8 l+e)k hX(e) = e ) ~ + - ~ - (----f-- (o< e< 1, ~.> o).
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Then ~(e) > i for any 0< e <!, k > 2 and
Hence we choose e = 1/3
an interval I, we have
i = h2(i/3 ) = min h2(0 ). 0<0<1
C in (2.40). For any a 6 eal,~' f E Lreal,l
~(l,E[a],f) _-< 3 ~(l,E[a], - - f + 2~ 2
3 ) + 3 ~(l,E[a], ~XI)
and
and hence
^ f + 2~ 1/2 ^ 2 ~i)i/2} 1/2 Const {q(l,E[a], ~ ) + a(l, E[a], ~ I I I
Const DE(7)I/21II, qE(~) ~ Const ~E(~) I12. Inequality (2.40), 0 = 113 shows that
(2.42) SE(~) =< ~E ( + 2 DE( ) + C5 ~8 + ~5} ( ~ ->_ i).
By (2,36),
(2.43) ~E(~) ~ Const {~E(~) + ~}2 _ ~ Const ~N ( ~ ~ i),
where N = 2N 0 + 2. Suppose that N ->_ 3. We put
N+I
= sup{ ~E(~) ~ 2 ~m ; i ~ ~ =< (3)m } (m = 3,4 .... ).
Then -c 3 -<_ Const. For any m >_- 4 and (3/2) m-I < ~ < (3/2) m, we have,
by (2.42), N+I N+I
~E(~ ) ~ 2 _<_ ~ 2 {~E(~3 ) + 2 ~E(23 -~) + C8( ~ + ~28)}
N+I N+I N+I N 2 2 + 2 + ~:m-1 + c8 (~ 2 +8 p28) }
3
N+I N+I N+I -(li2)
_<,{( ) 2 + 2( ) 2 } .~m_i + C6(~ +
8-(1/2) 2 (m-i)((i/2)-8)
~m-i + C5 ~ ~ Tm-i + C8(3)
Hence ~m ~ ~m-I C 8 (2/3) (m-I)((1/2)-8) We choose 8 + 1/4.
m-i ~m <= ~3 + Const Z (_~)k/4°3 <= Const,
k=3
)}
Then
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which gives that
~E(~)
i.e., (2.43) holds with N
obtain
~E(~) = <
Put
Then
above,
N+I 2 Const ~ ( ~_>- i),
replaced by (N+I)/2. Repeating this argument, we
Const 9 3 ( ~ ~ i).
~' = sup {~ ~-2; 1 = = m E(~) < 9 < (~)m } (m = 3,4 .... )
' < Const. Since (1/3) 2 + 2(2/3) 2 i, we have, in the same manner as ~3 = =
~'m -<- ~tm_l + C6 {(2)(m-I)((I/2)-6) + (3)(m-I)(2-6)}
T'm_l + C6 (Q)(m-l)((I/2)-6)9~ (m >= 4).
We put 6 = 1/4. Then ~t ~ Const, which yields that m
Since
(Final Step).
that
(2.44)
We have evidently
Ix-x'l ~ Ix-yl/2
~E(~) ~ Const 92 ( ~ a i)°
~E(~) ~ Const ~E(9) I/2, this shows (2.41).
At last, we deduce (2.38) from (2.41). Let a E Lreal.
~5(E[a]) ~ C 6 (i + ~25) ( ~ = IlalJBM 0, 0 < 5 ~ 1/2)
IE[a](x,y) I ~ 1/Ix-y] Let x, x', y ~ IR satisfy
We may assume that y < x < x'. We have
We show
fyX la(s ) _ (a)(x,x,) ] ds = < Const ~(x-y) log x'-y
which gives that
- X' - X X (a(s) -(a)(x,x,))ds I A(x)-A(Y)x-y A(x')x'- yA(y) I = I (~_y~(~,_y) /y
i X'-y f : ' (a(s) - (a)(x,xt))ds ]
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Thus
Xt--X Const
x-y {i + log ~ } ~ Const
xt_X
IE[a](x,y) - E[a](x',y) l X ! -- X < =
"(x-y)(x''y~
~(x'-x)i/2/(x-y) I/2.
1 I exp { i A(x),A(y) } - exp + x'-y x-y
{i A(x')-A(y) }I xV-y
x' - x 1
(x-y)(x'-y) + C6 I exp {i A(x)-A(Y-~)} - e X P x - y {i A(X'x!-A(J~)}I25
< x' - x i A(x)-A(y) _ A(x')-A(y) I 2 5 = (x-y)(x'-y) + C 6 ~ I x-y x'-y
x' - x (x' - x) 6 Const + C6 ~26
(x_y)2 (x_y)l + 6 C5(I + ~28)(x'-x)6/(x-y) I+6 .
For f E Lreal,l and an interval I, we estimate o(l,E[a],f). Let
a = a - (a) I. Then o(l,E[a],f) = ~(l,E[a],f). Le~=na 2.2 shows that there exists
an open set ~ = Uk= I I k (I k = IE, k) in I such that
< i )i k I~I = 2-~- ~i I~(s) Ids ~ III/2' (IaI ~ 2~ (k ~ i),
I a(x) l =< 2~ a.e. on I - ~ .
We put
~(x) (x ~ I- ~)
b(x) = ~(a0)ik (x ~ Ik' k > l ) ( x ~ ~).
e = Then b E real,2~ Using Lemma 2.7 with K = E[a], T = E[b], we have
~(l,E[a],f) = o(l,E[a],f)
<= o(l,E[b],f) + Z ~(Ik,E[a],f) + C 6 (i + ~25) ii I k=l
Z ~(Ik,E[a],f) + C 8 (I + ~26) iii. ~- ~E(2~) III + k= I
Repeating this discussion, we For each Ik, we use Lemma 2.2 with a - (a)ik.
have
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Thus
i 1 ~(I, E[a], f) =< qE(2~) ]I I {i +~+~+ ... }
i i + C 8 (i + ~ 26) III {i +~+~ + ... } =<_ {2 ~E(2~) + C 8 (i +~ 28) } IiI
o(E[a]) ~ 2 ~E(2~) + C 8 (i + ~28)
Const (i+ ~) = Const(l + IIaIIBMO).
Consequently, Lem~na 2.5 and (2.44) yield (2.38) in the ease where
a be a real-valued function in BMO. We put a E Lreal. Let
iax 1 an(X) = (x) Ia(x) I =< n (n->_ I).
- a(x) < -n
Since a n ~ Lreal , we have
IiE[an]II2, 2 ~ Const(l + IlanllBMO ) ~ Const(l + IIalIBMO).
Letting n tend to infinity, we obtain (2.38).
§2.9. Proof of (2.39)
Put
$C(~,~) = sup {~(C[a]); a ~ Lreal, ~ = a -<_ ~} (e _-< 0, ~ _-> 0).
We show that, for ~ ~ I, 0 < 8 ~ i,
^
(2.45) ~C(-~,~) ~ 2 ~C (- ~ , ~) + C 8 ~8{~C(~) + ~8}
where
~C(~) = sup {o(C[a]); a E LTeal,~} •
(Tchamitehian [51] showed that
¢~C(-~,~) -< 2 OC (- ~2' ~2 ) + C6 B6 (~ ->_ i).
Inequality (2.45) is an improvement of his inequality.) Here is a lemma necessary
for the proof of (2.45).
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Lemma 2.13. <~c(O,~)= ~C(--~,O) _-<- C 5 ~5 {Crc(~ ) + ~5} (# >_-- i , 0 < 6 -< i ) .
Proof. The first equality is evident. We define q > 0 by
6 = log 2/log(i/4q). For a E Lreal, 0 _-< a--< [3, f ~ eal,l' 0 -< f =< 1
interval I, we estimate ~(l,C[a],f). If (a)l < 2q~ , we use RSL of
Type 3 (4qB-/t.,0-d.). There exists b 6 L~eal such that, with
= {x 6 I; A(x) ~ B(x)} ,
and an
0 =< b(x) =< 4Q# a . e . on
Lemma 2.8 shows that
~(l,C[a],f) _-< $(l,C[b],f) +
+ c~ ~8 {~c(~) + ~ } IT I
I , I~1 < 0+2r]~3 { i I =< i i i / 2 . = o+~{3
^
Z ~(Io, k,~ C[a], f) k=l
$ C.c(0,{3 ) + c 6 ~ ( a c ( # ) + {3~)} Izl _< {C-c(O , 4q#) + y
If (a)l -> 2q~ ,
such that~ with
we use RSL of Type i (qB-A.,{3-a.).
= {x E I; A(x) # B(x)} ,
~ =< b(x) =< ~ a.e. on
Lemma 2.8 shows that
~(l,C[a],f)_~$(l,C[b],f) +
+c6 ~6{~c (~) +~8} II
There exists b ~ Lreal
- 2 ~ t I ] = 1 - ~ t i t .
ee
Z ~(I~, k, C[a],f) k=l
We have
- l _ ~ q
i f(y)dyl 2 dx ~(l,C[b],f) ~71 If I (x-y)+ i(B(xiiBiy))
I f=B-l(t) dtl2 ds
= fB(1) IfB(1) (B-l(s)-B-l(t)) + i(s-t) B'°B-I(t) B'°B-I(s)
(Const/~) ~(B(1),C[(B-I)'], foB-i/B'oB -I)
N O (Const/~) Const {i +If(B-I) ' XB(1)II ~ } II(foB-I/B'°B-I)XB(1)IIIIB(1)I
C6 ~-31B(1) I ~ C6 ~-2 i1 I ~ C6111 ,
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63
where B(1) = {B(x); x ~ I} and N O is the absolute constant in Lemma 2.12.
Hence, in this case,
~( i , C[a] , f ) < l-zq ~c(O,~) l l l + c5 p~{~c(~) + ~ } I I l • = l - ' q
Thus we have, in both cases,
i ~(I, C[a] f)
1 z_n_2_2n ~c(O,~)} + c5p6{~c(~) + ~5} , --< maX{~c(0'4~) + 25C (0'~)' i-~
which yields that
i ~c(O,~), ~ ~c(O,~)} $C (0'13) --< max{~;c(O'4"q~3) + "2 l -q
+ c ~ { ~ c ( ~ ) + ~ } .
If the second quantity in max {.,.} is larger than the first quantity, then
~c(O,~ ) ~ z_,_-_-n c8 ~ { ~ c ( ~ ) + ~6} = ca ~5{~c(~) + ~5} .
If the first quantity is larger than the second quantity, then
(2.46) $C(0,~) ~ 2 ~C(0,4~) + C6~6{~C(~) + ~6} .
Thus, in both cases, (2.46) holds. Let m be the smallest integer of
k such that (4~]) k ~ =< i. Then m _-< {log ~/log(I/4~)} + i. Inequality (2.46)
yields that
m-i ~C(0,~) --< 2 m ~c(O,(4~)m~) + C 6 Z 2k(4~])kS~8{~C((4~)k~) + (4~)k8 ~6}
k=0
2 m $C(0,i) + C 5 {I + 2m(4~) m6} ~6 {aC(~) + ~5}
C5(~8 + 2 TM) {OC(~) + ~6} ~ C6 ~6 {OC(~) + ~6 } . Q.E.D.
We now prove (2.45). For a ~ e~eal,~, f E e~eal, 0 ~ f ~ i and an
interval I, we estimate $(l,C[a],f). Since $(l,C[a],f) = $(l,C[-a],f), we
may assume that (a) I ~ 0. RSL of Type i (- e~-~.,6- ~.) (e = 1/2) shows
that there exists b E L~eal such that, with ~ = {x E I; A(x) # B(x)}
= U~= 1 I k (I k = l~,k),
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- ~ ~ b(x) ~ ~ a.e. on I, b(x) = - 85 (x (~),
- (b) I (a)ik ~ - 8~ (k > i) i~ I < ~ ~ @~ ii I ~ I I~I,
= ' = - l+e (e = I/2).
Lemma 2.8 shows that
g(l,C[a],f) ~ ~(l,C[b],f) + Z $(Ik,C[a],f) + C5~8{~C(B) + ~5} ii I k=l
gC(-6~,~)Ill + Z g(Ik,C[a],f) + C5~5{ffC(~) + ~8}III . k=l
For each k ~ I, we use RSL of Type 3 (0-&.,-~- d.). Since (a)l ~ - @~, there ~ k
exist b k 6 Lreal and an open set ~k = U~=I Ik,~ (Ik,g = l~k~ ~) in I k such that
- ~ ~ bk(X) ~ 0 a.e. on I k, bk(X) = 0 (x ( ~k ),
(a)ik, ~ 0 (~ ~ I),
Lemmas 2.8 and 2.13 show that
+ (bk)ik
B + 0
~(Ik,C[a],f) ~ ~(Ik,C[bk],f) + Z $(Ik,g,C[a],f) + C8~5{~C(~) + ~5} llkl g=l
--< ~C(-~,0) Ilkl + Z ~(Ik,g,C[a],f) + C5~5{~C(~) + ~5} llkl ~=i
--< Z $(ik,e,C[a],f) + C5 ~5 {OC(~) + ~5} iikl ' g=l
Thus
~(l,C[a],f) ~ $C(-8~,~)II] + Z Z $(Ik,g,C[a],f) k=l ~=I
Since
we have
+ csFS{Oc(F) + ~8}II j,
(a)ik,~ => 0 (k,~ >_- i), k=1% ~=IZ Ilk,~l = < ii +- 8e iii.
(a) I ~ 0, we can apply the above argument to Ik, 3 ° Repeating this, k,g
1
Tff c8~5(~c(~) l-e .l-e.2 $(l,C[a],f) ~ {$C(-@~,~) + + ~6)}{I + i~+ ~# + ...}
~!~ ~c(_ep,F ) + c5~5 {~c(~) + ~5},
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65
which gives
(2.47) ~c(_~,~) =< z+i2e ~c (-e~'~) + c~ ~ {Oc (~) + ~} (e = ~/2).
To estimate ~C(-8~,~), we study ~(l,C[a],f) for a ~ Lreal,
- 8~a ~ ~, f £ L~eal, 0 & f & i and an interval I. First we assume that
(a) I ~ 0. RSL of Type 3 (8~-r.,-@$-a.) shows that there exists b 6 Lreal
such that, with ~ = {x 6 I; A(x) # B(x)} = Uk= I I k (I k = l~,k),
- e~ = b(x) =< e~ a.e. on I, b(x) = e~ (x ~ ~),
e~ + (b) I e~_ ½ (a)l k a . . . . e~ (k > 1) I~I < e~ + g I~I ~ e~+e~ I~I = I~I'
Lemma 2.8 shows that
$(I,C[a],f) ~ $(l,C[b],f) + E k=l
$(ik,C[a],f) + C8~8{~C(~) + ~8} i i I
~c(-el3,el3) I~1 + k=l
~(Ik,C[a],f) + C858{~C(~) + ~8}II I.
For each k ~ i, we use RSL of Type I (O-r.,~-a.). Since (ak)ik a e~,
t h e r e e x i s t b k 6 L r e a l and an open s e t ~k = Ug=l Ik ,~ ( I k , g = I~ k ,g ) )
such that
0 ~ bk(X) & ~ a.e. on Ik, bk(X) = 0 (x 6 ~k ), (a) I ~ 0 k,i
- (bk) Ik II ~ ~ - e~ llkl = (l-e) llkl.
(9~=> l),
Lemmas 2.8 and 2.13 show that
~(ik,C[a],f ) _<_ $(Ik,C[bk],f ) + Z ~(Ik,&, C[a],f) g=l
+ C8~8 {C~C(~) + ~8}llkl --< Z ~(Ik,~,C[a],f) + C8~8{~C(~) + ~8}llkl • g=l
Thus
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$(l,C[a],f) ~ $C(-8~,@#) Ill + z z ~(Ik, g, C[a], f) k=l g=l
(a) I ~ 0 (k,g ~ i), % Z ilk,gl ~ i_~8 ill. k,g k=l g=l
Since (a) I ~ 0, we can apply the above argumen~ to Ik, ~. Repeating this, k,g
we have
1 (2.48) ~ G(I,C[a],f) _-_- {~-C(-@l~,e#) +C6~35(0C({3) +~6)}{1+ t2----~8 + (~)2+. . . }
Next we assume that
there exists b E Lreal
(I k : l~,k),
< 2 ~c(_e#,e#) + csp~{Cc(~) + #6} . = 1+0
(a) I > 0. RSL of Type4 (0- A.,6-G.) shows that
such that, with ~ = {x E I; A(x) # B(x)} = Uk= I I k
0 ~ b(x) ~ ~ a.e. on I, (a)Ik ~ 0 (k ~ 0).
Lemmas 2.8 and 2.12 show that
$(l,C[a],f) =< ~(l,C[b],f) + % k=l
--< Z k=l
~(ik,C[a],f) + C5~6{GC(~) + ~5} ]I]
$(Ik,C[a],f) + C5~5 {OC(~) + ~6}]I[.
Since (a) I ~ 0, we can apply the argument in the case of
estimate of k $(ik,C[a],f) ; we have
(a) ~ 0 to the I
2 $C(_@~,@~) I + C5~5 {GC(~) + ~5} llkl " ~(Ik'C[a]'f) ~ i-~ Ilk
Thus, in this ease also, (2.48) holds. Consequently,
2 ~c (-e~'~) ~i-~ $c (-°~'e~) + c6~{~c(~) + ~} (e = 1/2).
This estimate and (2.47) immediately yield (2.45).
In the same manner as in (Second Step) of the proof of (2.38), (2.45)
shows that G(C[a]) ~ Const(l +~/ilaIl~) (a ~ LTeal). From this inequality, we
now deduce
(2.49) G(C[a]) ~ Const(l + H~aI~BM O) (a is real-valued).
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For a E L~eal, f E L~eal,l and an interval I, we study ~(l,C[a],f).
Let 8 = IIaNBMO. Inequality (2.44) holds with E[.] replaced by C[-].
Lemma 2.2 shows that there exists an open set ~ = U" = k=l Ik (Ik I~, k) in
such that
121 ~ --~ fI la(s) - (a)II ds ~ III/2, (a - (a)i)Ik ~ 2~
la(x) - (a)iI ~ 2~ aoe. on I - ~.
(k a i),
We put
b(x) = (x { I k, k >_- i)
(a) I (x ~ R).
Then
Recall that
(See Lemma 2.10).
~(l,C[a],f) =< ~(l,C[b],f) + Z ~(Ik,C[a],f) k=l
+ c5(i + 825 ) Ill.
n in IITn[']ll2, 2 --< C O If" I. (n >= i) for some absolute constant C O .
If I(a)iI ~ 4 c O 8, then IIbll. ~ (2 + 4C0)~, and hence
~(l,C[a],f) ~ ~C(I + (2 + 4C0) ~) Ill ~ Const (i +v~) Ill.
If l(a)ll > 4c0~, we put b = b - (a) I. Then II~II. ~ 2 ~. We have
~(l,C[b],f) = fi ]I I f<Y~ dyldx X
(x-y)- i(a)l(X-y) + i fy b(s)ds
I -i ..... li-i(a)iI fl l(-~)H(Xlf)(x) + n= 1Z (l_i(a) I
-~ {~ + Z (i + l(a)l12) -n/2 c0n ii~ii~ } ii I =< Const llI. n=l
--)nTn[~](Xlf)(x)Idx
Thus
~(l,C[a],f) _~ Const(l + V~) III + Z ~(Ik,C[al,f). k=l
We can apply this argument to I k. Repeating this, we have
1 -[-+q-a(l, C[a], f) =< Const (i +V~),
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88
which gives (2.49). Lemma 2.5 and (2.49) yield (2.39). This completes the proof
of (2.39).
§2.10. Application of (2.38)
As is well-known, Theorems B and C are applicable to the higher dimensional
Neumann problem~ pseudo-differential operators and the estimate of analytic
capacity ([6], [I0]). (See Chapter III.) In this section, we show an immediate
application of (2.38). For a locally rectifiable curve F in the complex plane
¢, LP(F) denotes the Banach space of functions f on F with norm
IIfIILP(F ) = { IF f(z)IPldzl} I/p (lap<-).
The Cauchy(-Hilbert) transform on is defined by
f(~) Id~l • 1 lim f <-z (2.50) H F f(z) = ~ l<-zl > s S ~0
The norm of H F as an operator from LP(F) to itself is denoted by
IIHFI I We say that F is a chord-arc curve with constant M if, LP(F),LP(F) •
for any z, ~ 6 F, g(z,~) a Mlz-~l, where ~(z,~) is the length of F
between z and ~ . We show
Corollary 2.14. Let F be a chord-arc curve with constant M. Then
IIHFIIL2(F ),L2(F) a Const M 2.
Proof. Fixing z 0 6 F, we parametrize F so that
Let p
r= {z(t); t Em} , ~(z0,z(t)) = Jtf.
be an even function in C O such that
3 p(x) = 1 (la xaM), ~ Hp(k)rl =< Const,
k=O
supp(p) c [-M-l, -1/2] U [1/2, M+l].
Put h(z) = p(Izl)/z (z 6 ¢). Since Is-tl/M a Iz(s)-z(t)I ~ Is-tl (s,t 6 ~),
we have, with a(t) = Mz'(t)
1 M (Mz(s)-Mz(t))-I z(s)-z(t) s-t s-t
= ~s-t h(s-~it fts a(u)du) ( = M T¢[a,h](s,t), say).
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We have Iz'(t) I = 1 a.e. and
HFf(z(s)) = (-~) lira fls_~>g s -~ 0
z(s)-z(t)
= (-~) M T¢[a,h] {(faz)z'}(s)
Hence II~IIL2(F),L2(F ) = n M IIT~[a,h]II2, 2. Let
f(z(t))z'(t)dt
a.e.
F h(s + it) = f~= /~ e-i(sx+tY)h(x + iy)dx dy •
Then
Tc[a,h ] = Const ~_~ / ~ Fh(s+it) E[Re {a(s-it)}] ds dt
= Const ~_~ f_=Fh(s+it) {E[Re {a(s-it) } ] + ~ H} ds dr,
oo oo
since ~_~ /_ Fh(s+it)ds dt = Const h(0) = 0. Lemma 2.10 and (2.38) show that
II E[Re {a(s-it)} ] + ~ H!I2, 2 Const fiRe a(s-it)llBMO
Const M Is+itl ,
and hence
llTc[a,h ] N2,2 ~ Const M /_~ f_~ I Fh(s+it) I Is+itl ds dt.
Integration by parts shows that, for n = 2, 4,
I Fh(s+it) I n
= l(_is)-n f_~ f_~e-i(sx+ty) B n 8x
Const/Isl n .
h(x+iy) dx dy I
In the same manner, I Fh(s + it) I & Const/It[ n (n = 2, 4). Thus
[ Fh(s + it) l ~ Const/Is + itl n (n = 2,4 ) . We have
® f ® IFh(s+it)[ Is+itj ds dt = Ills+itl ~ i + ffls+itl > i
ds dt +ff ds dt Const {ffls+itl ~ 1 Is+itl Is+itpl Is+itl3 } ~ Const.
Consequently,
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70
lIH r = ~ M lIT¢[a,h]II2 llL2(r),L2(r)
Const M 2 f_Z f_Z IFh(s+it) I Is+itl as at
This completes the proof of Corollary 2.24,
Const M 2 .
Q.E.D.
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CHAPTER III. ANALYTIC CAPACITIES OF CRANKS
§3.1. Relation between ~'(.) and H
In this chapter, we study analytic capacity y(.) from the point of view of
integralgeometry and the Cauchy transform on graphs. We shall estimate 7(.) of
so-called cranks. For a compact set E in the complex plane ~, H'(E c) denotes
the Banach space of bounded analytic functions in ~ U {=} - E( = E c) with
supremum norm l!'il ~. The analytic capacity of E is defined by H
(3.1) T(E) = sup{If'(~) I ; Ilfll ~ l, f E H®(EC)}, H"
where f'(®) = lim z ~ ~ z(f(z) - f(=)), i.e., f'(') is the 1/z-coefficient of
the Taylor expansion at ~ ([29, p.6]). If f E H~(EC), II fll ~ ~ i, then H
g(z) = (f(z) - f(®))/(l - f(®) f(z)) ( E H=(Ee))
satisfies g(~) = 0, IigIl ~ & i and H
Ig'(®)I = I f'(~)I /(i - I f(~)l 2) _>_ If,(= ) I.
Hence, to estimate y('), we can restrict our attention to functions vanishing at
~. The Cauchy transform of a complex measure ~ in ¢ is defined by
i f~ i d~(~) (z ~ supp(~)). C ~(Z) = 2~i ~ ----q-"z--
We put
i (3.2) y+(E) = sup{-~- / d~; IIC~H ~ i, ~ ~ 0, supp(~)c E} .
H
Since (C~)'(') i f d~ we have Y(E) g T+(E). Let D(z,r) denote 2~i
the open disk of center z and of radius r. For s > 0, we put
IEIg = 2 inf Zk= I rk, where the infimum is taken over all coverings
{D(Zk,rk)}k= 1 of E with radii less than s. The generalized length of E
is defined by IEI = lim s ~ oIEls" If E c e, then the generalized length of E
equals its 1-dimenslon Lebesgue measure. We shall compare T(-), Y+(-) and
If. A set F c ¢ is called a locally chord-arc curve with constant M, if, for
any z £ F, there exists E > 0 such that Fn D(z,e) is a chord-arc curve with
constant M. A locally chord-arc curve is not, in general, connected. Let F be
a locally chord-arc compact curve with constant i00. We define
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(3.3) p(F) = inf y(E)/IEI, p+(r) = inf y+(E)/IEI,
where the infimums are taken over all compact sets E on F . Let LP(F),
N'II (i ~ p < ~) be the same as in §2.10. Let L~(F) be the L" space on L p (r)
r with supremum norm li "IIL~(F ) and let L (r) be the space of functions f
on F with norm
NflIL (F) = sup If( )l> ; >
The Cauchy transform H F on F is defined by (2.50). The norm of
operator from LI(F) to LI(F) is denoted by w HHFIIL1 (F) ,L~(F) "
relations among p(F), o+(F) and IIHFIILI(F),L I(F)"
Theorem D.
H F as an
Here are
(3.4) C°nst/IIHFIrLZ(F),L~(F) ~ p+(F) ~ Const/llHrHLl(F), L~(F),
1/3 (3.5) p+(F) ~ p(r) ~ Const p+(F) .
We begin by showing the second inequality in (3.4). Let f E L2(F),
llf H = i. For k > 0, - ~ < e ~ ~, we put Ll ( r )
Ek, e = {z ~ F; H F f (z ) ~ D(ke i e , k /4 )} ,
There exists a compact set Fk~ 8 in EX, ~ such that IFx,el ~ IEx,el/2. exists a non-negative measure
H k,e
Since IIC~II ~ i, we can write H ~
show that IIHFhN ~ Const. L~(F)
For z O ~ F such that
choose first ¢ > 0 so that
i00.
on FX, e such that
d~ ~ y+(Fx,e)/2.
d~ = hldz I with h 6 L~(F),
There
where
so that
0 <_- h <_- 2~. We
H F h(zo) exists (in the sense of (2.50)), we
F n D(Zo,¢ ) is a chord-arc curve with constant
Choose next 0 < e' < s so that, for any z E F c n D(Zo,¢'),
IH F h(z 0) - 2i C~(z)[ g ]H F h(z O) - 2i C(hId~])(z)[ + i,
is the restriction of h to F n D(Zo,g). Choose at last 0 < ¢" < g'
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[(<) IHr 7,(,o)-~- ~" I < i i <-- J--
r n D(z0,~") c ~ - z0
' ~¢ Since F n D(z0,¢) is a chord-arc curve with constant i00, there exists z 0
such "'4 < = - =< " = ~. Thus we have that s ~ I~ o z~'l<, ~"i2 and r n D(%,i0 -i° ~')
IH r h(z O) - 2i C ~(z~) I ~ IH r ~(z o) - 2i c<~Id~l)<z6>l + i
--< I ~- m IdOl r r r n D(Zo,¢")C ~ - z 0 ~- ~ - z~
I < 1 1 + 2
=< 2 s t=o - =6t r n (D(=o,~)-D(~o,~")) t ~ - =oi I~ - %t Idol
+ 21 F N D(Zo,~")
Since IIC~II =< i, we have H"
r, TIH r h}i ~ Const. L~(F)
Sinc e
1 Id~l + 2 _<- Const.
IH F h(zo) [ -<- Const. Since ~F h(z) exists a.e. on
we have
1 1 7+(Fk,e) ~ -~- I F hldzl k,e - T+(Fk '9 ) '
k ~ Y+(Fx, e) =< ~ I I F k e i0 hldzll
k,e
i iiFk,@ hldz 1 ~-- (H F f) h Idzll + ~ IFk,@
k < ~ II F f(H F h)Idzll + 7 %(Fx,e) = 2n
k Const IIfIILl + ~ T+(Fk,e) ,
(r)
which gives
y+(Fk, e) ~ Const llfIILi(F)/k ~ Const/k .
Since
IEk,@l ~ 21Fk,eI ~ 2 y+(Fk ,e ) /p+( r ) ~ Cons t / (k p+( r ) ) ,
we have
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Since
Iz ~ r; l~ r f(z) l > k I ~_ I U n=0
.4)n = ~ {const/(X p+(r))} Z (g n=O
k > 0 is arbitrary,
i00 u E I
k=l (5/4)nk, 2nk/100
Const/(k p+(F)).
IIH r flIL~(r ) ~ Const/ o+(r) (f ~ L2(F), llfNLl(r) = i).
A standard argument shows that this inequality holds with f replaced by any
g E LI(F), IIglILI(F ) = i. Hence the second inequality in (3.4) holds.
The proof of the first inequality in (3.4) was essentially given by Davie [21],
Marshall [37] and Davie-¢ksendal [22]. Here is a tool for the proof.
Lemma 3.1 (the separation theorem [53, p. 108]). Let P, Q be two compact
convex sets in the Banach space C(F) of continuous functions on F with norm
II'IIL.(F). Then there exists a complex measure ~ on F such that, for any
f E P, g E Q,
Re fF
Since F
~0 > O
z E F.
f d~ > Re fF g d~.
is a locally chord-arc compact curve with constant i00, there exists
such that F N D(z,s 0) is a chord-arc curve with constant i00 for any 8 Let H F (0 < s < SO/2) be an operator defined by
H r~ f(z) = ~i f f(~l Id~I (f e El(F)) r n D(z,c) c ~ - z
We show that there exists an absolute constant C O such that
H s (3.6) II FII ~ ~ C 0 (= C0m 0, say). LI(F) ,e~(F) llHrllnl(r) ,L~(F)
2g be a maximal operator defined by Let M F
i if(~) i id~l MF2g f(z) = 0 < nsup~ 2s ~ /F(z,n)
where F(z,~) = F N D(z,~). Then
IIMISlILI(F ) i ~ ~ Const. ,n (F)
For f ~ LI(F) with IIftlLl(F) ~ i, we put
(f E LI(F)),
E = {z ~ F; IH F f(z) I = < k ' M2~F f<z) = < k} •
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Then
l r - El ~ {tlHrltLl(r),L!(D
(m 0 + Const)/k
+ NM~lld(r),L~(r) Const mO/k.
} / x
Let z 0 E E. Then, for any z ~ E N D(ZO,e/2),
IH~ f(z) I ~ IH~ f(z) - Hrf(z) 1 + IH r f(z) I
< 1 l f (~ ) Id~II + k
=< 1w[ ] fF(Zo,g) - f (~)~- z IdYll + Const M2F g f ( z )
i ifF(zo,8 ) f(<) ]d~] I + Const k . -< ~ ~-z
+k
Hence we have
[H~ f(z)[= lHr(~0,~ ) fo(Z)[ + C~ k (z E E n r(z0,~/2)),
' is an absolute constant. where fo is the restriction of f to F(zo,S) and C O
Since F(zo,g) is a chord-arc cu=ve with constant i00, Corollary 2.14 shows that
IJHF(zo,s)H LI(F),L~(F ) ~ Const. (See also (2.10).) Thus
Iz ~ E n r(z0,~12); IH~ f(z)I > (% + l)xl
Iz E E 0 £(ZO,S/2); ]HF(zo,s)fo(Z)l > k I ~ (Const/k)IIfOllel(r(Zo,~))
n We choose a finite covering {D(Zk,g/2)}k=l of r so that z k E F
n XF(Zk,~)IIL.(£) < Const, where XF(zk,g ) is the (i ~ k ~ n) and llZk= 1 =
characteristic function of F(Zk,S)° Then
g Iz ~r; IH r f(zll >(%+i) xI
~- Iz ~E;PH~ f(z)I >(%+l)Xl + n
=~ Z ]z ( E fl F(Zk,S/2);IH F f(z) 1 > k=l
n
_<- (Const/k) k=IZ IF(zk,e ) If(~)l Id~l
IF - E l
(% + 1)~J
+
+ Const mo/k
Const mo/k & Const mo/k,
which gives (3.6).
Given 0 < ~ < gO/2 and a compact set E c F, we put
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F = {f E L'(F); 0 ~ f(z) ~ i,
IE f(z)IdzI ~ IEl/2, supp(f) c E} ,
P = {H i f; f ( F}, Q = {g E C(F); [Igile.(r ) ~ 3 Como},
where mo = NHFIILI(F),L]w(F) and C O is the constant in (3.6). We show that
P n Q # @. Suppose that P N Q = @. Since P, Q are compact and convex in
C(F), Lemma 3.1 shows that there exists a measure ~ on F such that
Re /F HFs f d~ > Re IF g d~ (f E ~ g (Q)
Taking the supremum of Re IF g d~ over all g E Q, we have
Re IF H F ~ f d~ ~ 3 C0m 0 IFid~I (f E F)
which implies that
where
- Re IF f go IdzI { 3 Com 0 (f E F),
1 d~(<). g0(z) = (7 i r Id~l) -I fr, I< - zp > ~ < - z
By (3.6), we have, for any h E LI(F) with IIhIILI(F ) ~ i,
I z ( F;IH ~ h(z) I ~ 2 Como/IEiI ~ IEI/2.
e is uniformly bounded, this inequality holds with Since the kernel of H F
h Idzl replaced by any measure ~ with fFld~I ~ I. Hence
I z E F; Igo(z)I ~ 2 Como/iEiI ~ IEI/2.
Let F = {z E E; Igo(z) I ~ 2 Como/iEl} and let
function. Then X F E F . Hence we have
X F be its characteristic
3 Com 0 _-< - Re fF XF go fdzI --< IF Igo (z) I Idzl
2 Com 0 --< ~ fF I dz] =< 2 Como,
which is a contradiction. Thus P N Q # ~.
Since P N Q # ~, there exists f~ E L'(F) such that
IIH F f¢ile®(F ) <= 3 tom O. Let {On}n= I
= ~i >-- e2 >-- "''' limn -~ ~ Sn 0 and
fs E F, be a sequence of positive numbers such that
gn {f IdzI}~=l converges weakly (as a
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77
sequence of measures). Then the limit is absolutely continuous with respect to
Idzl; we write by fOidz I. We have fO 6 ~ We show that
IIH r fOllL~(r ) ~ Const m O. Let z 0 E F and let e k, e e satisfy
0 < 2s e < e k < SO/2. Then, for any z E F(ZO,ek/2),
Sk St fee(K) Id~lt 1% f %)I ~ ! Imr_F<Zo,Ck) -- Z
i imr, 1 1 ) fse(~) IdYll e k < I~ - Z o l < eO/2 ( ~ - Z 0 ~ - z
+ ! ISr, ( 1 1 ) fee(K) IdYll _ F(Zo,CoI2) ~ - z 0 ~ - z
! s O c~ If fee(<) IdYll + Const M F f (Zo)
- ~ F -F(z0,c k) ~ - z
e e / 2 f (~) Idol Const (e k s 0) fF_F(Zo,ao/2 )
! If r fee(~) - r ( z o , C k ) ~ - z
s t Let fk denote the restriction of
z E F(ZO,ek/2),
!~ if r- r(Zo,~k) ~ - z
IdYll + Const {i + (ek/t~)Irl}.
fee to F(Zo,ek). Then, for any
e t s t s t Id~ll = IH r f (z) -H r fk(z) l
~e ~e 3 Com 0 + IH F fk (z) I
which shows that
Ck t~ s~ s~ I HF f (Zo) l ~ IHF fk (z) l + 3 Com 0
+ Const {i + (%l~)Irl} (z E F(Zo,Sk/2)).
By (3.6), we have
s t s t Iz E r; IH r fk (z) I g
10 -3 Ir(Zo,~k) I
s t s t This shows that the generalized length of {z E F(z0,gk/2); IH F fk (z) I
is larger than or equal to IP(Zo,Sk/2) I/2. Hence the mean of
103 Com 0 ] < 10 -3 st = rlf k NLI(F )
1 7 Ir(ZO'Sk/2)I "
< 103Como } =
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¢g sg IHF fk (z) l over this set is dominated by Const mo, which shows that
[H r f (Zo)l -<_ Const m 0 + 3 C0m 0 + Const {1 + ( 8 k / S 2 ) [ F I }
= / 2 < Const {m 0 + (¢k 80 ) Irl } "
Since z 0 ( F is arbitrary,
ii. " f"Jl Const {m 0 + ( S k / g ~ ) ) F I } .
Letting first 8 tend to infinity, and letting next k tend to infinity, we have
[[HF 0 ~ Const m 0. f IIL.(F )
Now let d~ 0 = f01dz [ . Since f0( F, [[H r f0[[L.(F ) ~ Const mo, the
maximum modulus principle shows that
1 [[c~°lt --<Cxm0' ~ fE d~° ~- [EI/Cl' supp(~ °) c E, H ®
where C 1 is an absolute constant. Let 00 = O/(Clm0). Then
Hence
00 I~ ->_ O, supp(~ 00) c E, tlc~°°ll H ®
< 1. =
d , ° ° ,
which shows that T+(E)/IE 1 ~ Const m 0. Taking the infimum over all compact sets
E c F, we obtain the first inequality in (3.4).
The first inequality in (3.5) is evident. At last we show the second
inequality in (3.5). Let f ~ L2(F), llfIILl(r ) = i. For k > 0, - ~ < O ~ ~,
we put
EX, e = {z ~ F; H F f(z) ( D(ke i0, pk/4)}
There exists a compact set FX, 0 in EX, 0 such that C
exists g (H (Fk, 0) such that
I lg l l . ~ z, g ( - ) = 0, I g ' ( - ) l ~ y ( F k , 0 ) / 2 . H
We can write g = C(hldzl) with h (L~(F) satisfying
(o = ~(r)).
tFk,o l ~ IEk,o I/2" There
llhllL~(r)< 2~, I1~' r hllL~(r) ~ Const, supp(h) c Fk, 0
Since
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1 Y(Fk, e) -~ [g'(~)l = ~2~ IfF>~,0 hldzt I =< Y(Fk,@)'
we have
k 1 IfFk,e Xe ie hldzl l
l [ fFk ,o p% fFk, 0 -< 2"--~ (Hrf) h Idzll + lhlJdzl
--< 2T Jfr f HF h Idzl l + k
-< Const llfllLl(r ) + E 7(Fk,e),
I Fk, 0 1
which gives y(Fk,o) ~ Const plflILl(r)/k = Const/k. Since
IEx,0] ~ 21Fk,ol ~ y(Fk,0)/p ~ Const/(pk),
we have, with q = (the integral part of 103/p),
Iz ~ r; IH r f(z)l > xl q
[ U U n=0 k=l E{l+(p/4)}n%,2~k/ql
Const/(p3k),
which gives that
= < Const/p(F) 3 II H F ]ILl (F) ,L~(F)
This inequality and the first inequality in (3.4) immediately yield the second
inequality in (3.5).
§3.2. Vitushkin's example, Garnett's example, Calder~n's problem and extremal
problems ([5], [28], [46], [52])
Painlev~ showed that the analytic capacity of a compact set of zero
g e n e r a l i z e d l e n g t h i s equa l to ze ro , For a compact s e t E of f i n i t e p o s i t i v e n
g e n e r a l i z e d l e n g t h , we can choose a f i n i t e c o v e r i n g {D(Zk,rk) }k=l of E so
t h a t Znk=l r k -< IEI" Then, f o r any f ( H~(E c) w i t h IlfllH~ ~ 1,
i I f f (~) d~ [ 1 f' (~) ] = 2--~ 0 {Uk=ID(Zk,rk) }
n Const Z r k _-< Const [El,
k=l
which gives
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(3.7) Y(E) =< ConstlE 1 .
This inequality immediately yields Palnleve's theorem. Vitushkin [52] constructed
an example P such that Y(P®) = 0, IP I > 0. The set P is defined as
follows. Let P0 = [0,I]. We divide P0 into two non-overlapping closed segments
[0,1/2], [i/2,1]. Fixing their midpoints, we rotate these two segments so that
the resulting two segments are perpendicular to the x-axis. (The midpoints of the
resulting segments are on ~.) Let PI be the union of these two segments. We
divide each segment (of P1 ) into two non-overlapping closed segments of equal
length. Fixing their midpoints, we rotate these four segments so that the
resulting four segments are perpendicular to the y-axis. Repeating this
discussion, we define Pn; Pn is a union of 2 n closed segments of length 2 -n.
We put P nn= 0 Uk=nP k. Garnett [28] also constructed an example Q~ such
that y(Q ) = O, IQ~I > 0. The set Q~ is defined as follows. Let
Q0 = [0,I] x [0,i]. Let QI be the union of four closed squares with sides of
length 1/4 in the four corners of Q0" In the same manner, Qn is defined from
Qn-i with each component of Qn-i replaced by four closed squares with sides of
length 4 -n in the four corners of the component. We put Q~ = Nn=0 Qn"
There are several proofs of y(Q ) = 0. Supposing that the non-trivial
Ahlfors function [29, p. 18] of Q exists, Garnett [28] showed a contradiction.
Using Besicovitch's set theory [i], Mattila [38] also gave an indirect proof. A
direct proof from the point of view of the construction of Garabedian functions
[29, p. 19] is given in [46]. This method is applicable to estimate Y(') of
various sets.
It is sufficient to construct a sequence {(R n,fn )}n=10000~ of pairs of
and f (H=(R~) so that R o fn(~) = i and compact sets R n n n Qn'
78Rn [fn(Z) l Idzl ~ Const/(log n).
If such a sequence exists, we have, for any g (H~(Q~), IIgll ~ i, g(~) = 0, H ~
Ig'(~)l = 2~i I fORn g(z) dz I 2--~i I fSRn g(Z)fn(Z) dz I
i ~2-~ fDR Ifn(Z) lldzl ~ Const/(log n),
n
which shows that y(Qn ) ~ Const/(log n) o Thus y(Q ) = 0. The pair (Rn,f n)
is constructed as follows. We denote by m the integral part of (log n)/2.
For a closed square Q with sides parallel to the coordinate axes, ~(Q)
denotes its lower left corner and g(Q) denotes the length of a side. Let Q_,
Q+ denote two closed squares in Q with sides parallel to the coordinate axes
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such that 2(Q_) = £(Q+) = 4-mg(Q), g(Q_) = ¢(Q) and the upper right corners of 4 k
Q+ and Q are identical. For k > 0, we can write Qk = U j=l Qk,j with k 4_k. components {Qk,j}4_1. Note that %(;Qk,j ) = We define inductively 4 m + 1
j-1 4m compact sets {Vk}k= 0 by V 0 = (Q0)_U (Q0)+,
V k =U E~ ~k (Qkm'~)-U (Qkm'~)+ (i < k < 4m),
where ~k {i < ~ < 4 km, k-i ~} Let ~0 {i} We now put = - - " Qkm,~N (U j=0 V j) = . = . 4 m 4 TM
(3.8) Rn = {k=0 ~ V k} 0 Q(4m+l) m, fn (z) = k=0~ %E~kH u(4km(z - E(Qkm,%))),
where
u(z) = exp[e i~/4 4 -m { - - - 1 + 1 }]~ z_(e i~/4 4-m/~) z_l_i+(e i~/4 4-m//~)
Then (Rn,fn) satisfies the required conditions. (See [46].)
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Calder~n [5] suggests to study C[a] for a ~ L °° real" This problem seems very hard;
in effect, Theorem D and Garnett's example immediately yield {IIC[a]II2,2; a E Lreal}
I = = o~ (See Remark 3.16.) Let Qn {(2-i)z/3; z 6 Qn }. (We rotate and contract
! V 4n Qn.) Then Qn is a union of 4 n squares {Qn,j }j=l with sides of length
(/5/3)4-n; the sides of Qn,j are not parallel to the coordinate axes. Let In, j be
the projection of Qn,j to ~R and let Qn,j be the segment in Qn,j whose n
projection to ~ colnsides with In, j (i ~ j ~ 4n). The intervals {In,j}4=l
are mutually non-overlapping, the length of each interval is 4 -n and their 4 n ,,,
union equals [0,i]. Let F n = Uj= I Qn,j , where Qn~,j is the closed sub-segment
of Qn,j of the same midpoint as Qn,j such that IQn,jl = IQn,jl/2. Then F n
is a locally chord-arc compact curve with constant i. Since
IFn I = vr~-/6 and y(Qn ) = (vr~/3)Y(Qn) , Theorem D shows that
IIHFnIL lw ~ Const/p (F n) -_> Const/p(F n) (3.9) l(r n) ,L (F n)
_a Const IFnl/Y(Fn) = Const/y(Fn)
>= Const/Y(Qn) = Const/Y(Qn).
We see that
llH r IIi < Const {l]HFnlIL2(rn) + i} . n L (r n) ,Lwl(rn ) ,L2(Fn )
,,, 4 n (See (3.18).) Since the projections of {Qn,j}j= I to ~ are mutually disjoint,
we can define a graph {(x, An(X)); x 6 ~} containing F n such that
A'n (= an) ~ Lreal." Since an(X) = 1/3 a.e. on the projection of Fn to ~R,
IIHFnIIL2(Fn),L2(Fn ) ~ Const llC[an]II2, 2 .
Thus (3.9) shows that
I/Y(Q n) ~ Const{IiC[an]II2, 2 + i}.
Since lim n ~ Y(Qn ) = y(Q ) = 0, this gives that {IIc[a]II2,2; a E L~eal} =-.
It is very important to give various reasonable grounds to Vitushkin-Garnett's
examples. From this point of view, we consider the following extremal problem.
Let I 0 = [0,I). For s I, ..., s n E ~, we define
TSl ..... sn(X,y) = i/{(x-y) + i(Asl ..... an(X) - Asl ..... sn(Y) )} ,
where
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As I ..... sn(X) = I 0
s k
(x ¢ I 0)
k-i k 1 <- k < n) (--~-_~ x < n . . . .
Our extremal problem is the following:
ex(~(n) = max {~(Tsl ,...,sn); Sl, ..., s n
We see that
( m} (n _~ i).
Const iV~og(n+l) & ex (n) ~ Const ~og(n+l)
(See Appendix I.) We define a function
A~(x) = E 10m k= I Sk(X) (x 6 I0), where m
and
gk(X) =
(n ~ i).
A 0 on ~ by A~(x) = 0 (x ~ I 0) and n
is the integral part of (log n)/(log i0)
0 (j-l)10 -k ~ x < j i0 -k, i ~ J ~ i0 k j is odd
i0 -k j is even.
Let TAO(X,y) be the kernel associated with A O.n
n
~(T 0 ) ~ Const I/~ = Const ~og(10m). A n
(See (3.14).) Hence r 0 = {(x, A~(x)); x ~ I 0 } n
respect to ex ( n ) . The g r a p h F 0 i s s i m i l a r t o ~ n
that
Then
is one of the worst graphs with
Qm" Hence Theorem D suggests
Problem 3.2. Const T(F~) ~ min {T(Fsl .... ,Sn); s I ..... Sn6 ~}
Const T(F~) (n g i),
= {(x, A (x)); x ( I 0} • where Fsl,...,s n Sl"'''Sn
§3.3. The Cauchy transform on cranks
As a first step of harmonic analysis on discontinuous graphs, it is natural to
begin with worst graphs. We say that a set E c ¢ is thick, if there exists
M > 0 such that, for any z ( E, r > 0,
I/M ~ IE n D(z,r) I/r ~ M.
The 1-dimension Caldergn-Zygmund decomposition is applicable to thick sets. Hence
thick sets are also natural objects. From the point of view of §3.2 and
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"thick sets", we define (thick) cranks.
An interval i in I 0 = [0,i) is called a dyadic interval if I is
expressed in the form I = [(j-l)2 -g, j2 -g) with integers g >-_ 0, 1 = < j = < 2 g. A m
finite sequence R = {Ik}k= 1 of mutually disjoint dyadic intervals is called a m
covering (of I0) if I 0 = Uk= 1 I k, For a positive integer q and two coverings
n ~ m R' = {lj}j=l, = {Ik}k=l, we write by R'< R if each I'~ is expressed as a
q J
union of at least 2 q elements of R of same length. A segment I 0 is called a (thick)
crank of degree 0. For a positive integer n, a graph F = {(x, ~(x));x E I 0 }
is called a (thick) crank of degree n, if there exist n coverings R I, ... R n
and n functions AI, ..., A n on I 0 such that
(3.10) I 0 <q R I ~q ... ~ R for some n tuple 1 2 qn n
(ql .... , qn ) of positive integers,
(3.11) A F = A I + ...+ An,
(3.12) on each element I of Rk,
)~(x) I ~ Ill (i ~ k ~ n).
A k is a constant and
For two positive integers n, q and two real numbers =, ~ less than or equal to
i, we define a crank
F(n,q,e,~) = {(x, ~(n,q,a,~)(x)); x E I 0 }
by
~(n,q,~,~) = A(q'~'~) + .... + A(q'a'~) n
A(q,a,~)(x ) =I ~2-qk
k (~2_qk
(x E [(j-l)2 -qk, j 2-qk), j odd)
(x E [(j-l)2 -qk, j 2-qk), j even).
We show
Theorem E. Let F be a crank of degree n. Then
(3.13) IIHFNL2(F ) s Const V~. ,L2(F)
There exists an absolute constant ~0 such that, if
(3.14) lIHF(n) llL2(F(n ) ~ Const V~n ),L2(F(n))
I~ - ~I 2 ~ D0/q, then
(r(n) = r(n,q,~,~), n ~ i).
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85
In this section, we give the proof of the first half of Theorem E. For
a crank F = {(x, AF(x)); x ~ I0}, we put AF(x) = 0 outside I 0 and define a
kernel
TF(X,y) = I/{(x-y) + i(AF(x) - AF(Y)) }
For f E L2(F), we have
(x # y, x, y ~).
H F f(x + i AF(X))
= 1 1 - ~ p.v. f0 TF(x'Y)f(Y + i AF(y))dy a.e. on I 0,
and hence
(3.15) IIHFIIL2(F) ~ ! lIT FI12,2. ,L2(F)
Here are three lemmas necessary for the proof of (3.13).
Le~mma 3.3. Let F be a crank of degree n. Then
Proof.
NTFII2, 2
Evidently,
_-< Const {~(TF) + I} .
(3.16) I TF(x,Y) I =< i/Ix-yl .
For any dyadic interval I, we have
(3.17) ITF(x,Y) - TF(x',Y) I --< Const II I/ Ix-y 12
(x, x' 6 I, y ~ I = (the double of I)).
This is shown as follows. Let R I, ..., R n be the coverings associated with F
and let AI, ..., An be the functions associated with AF. We denote by m I
the smallest integer of k (i =< k ~ n) such that R k has an element contained
in I. Then, for any x, x ~ 6 I,
IAk(X ) - Ak(X')l
< J 0 (i ~ k < m I)
= I 2ml-k+l • III (ml~ k ~ n).
Thus
ITr(x,y) - rr(x',y) 1 ~ Constl(x + i At(x)) - (x' + i Ar(x')) ! /Ix-yl 2
n
<= Const{Ix-x' I + Z IAk(X) - Ak(X')l} /Ix-yl 2 k=m I
ConstllI/Ix-yl 2.
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The proof of this lemma is analogous to the proof of Lemma 2.5; (3.16) and (3.17)
play the same role as el(.). In the same manner as in the proof of (2.9), we
obtain
~(T~) ~ Const {~(TF) + i}.
J' = (x - (~/2), x + (e/2)) by the largest dyadic interval in J'
Using this inequality, we obtain
(Replace
containing x.)
(3.18) Ix; T~ f(x) > 3 k, J~ f(x) ~ ~ k I
i I x; T~ f(x) > k I (f E L 2, k > O) <
= i00
where ~ = C O {~(TF) + i} and C O is a suitable constant. (Replace
{Ik}k= 1 by a suitable sequence of dyadic intervals.) Inequality (3.18)
immediately yields IITFII2, 2 ~ Const {~(T F) + i}.
For a non-negative integer n, we put
o(n) = sup {~(TF); F crank of degree & n} ,
~(n) = sup {$(I O, TF,f); f E Lreal, 0 ~ f a i,
F crank of degree ~ n} .
Q.E.D.
supp(f) c I 0. Let F be a crank of degree n, R 1 .... , Rn be n coverings
satisfying (3.10) and let A I, ... A be n functions satisfying (3.11) ' n
(3.12). Put
Then
and
F' = {(x, AF,(X)); x ~ I0} , A F, = A 1 + ...+ An_g_l ,
m
Rn_ g = {Ik}k= I.
F' is a crank of degree n -~ - i. We have
$(I 0, T F, f) = (TFf , TFf)fd x = ~(I0, TF,, f)
+ ((T r - Tr,)f, TFf)fd x + (TF,f, (T r - TF,)f)fd x
We show
Lemma 3.4. For two positive integers n, g with g ~ n-l,
(3.19) ~(n) ~ $(g) + ~(n -g - i) + Const ~(n).
Proof. Let f E Lreal, 0 ~ f ~ i. Without loss of generality we may assume that
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((T F - TF,)f , TFf)fd x m
= Z flk(T F - Tr,)(X k=l
ik f)(x) TF(Xlkf)(x) f(x)dx
m
Z flk(TF - TF')~Ik f)(x) TF~ c f)(x) f(x)dx k=l I k
m E f c (rr - TF')(Xlkf)(x) rrf(x) f(x)dx k=l I k
( = L I + L 2 + L3, say).
Since TF,(x,y) = i/(x-y) (x,y E I k, i _-< k =< m) and ~(n) ->- Const, we have, by
Lemma 3.3,
m m
ILl1 ~ Z ~(I k, T F, f) + ~ % flk IH(Xlkf)(x) Tr(Xlkf)(x)Idx k=l k=l
m
Z ~(I k, k=l
TF, f) + Const IITFII2,2
m
E k=l
^
~(Ik, TF, f) + Const o(n).
Extending coordinates, we see that, for each Ik, there exist
0 ~ fk ~ i and a crank F k of degree g such that
$(I k, T F, f) l lkl ~(I 0 , fk ). = , TFk
L ~ fk ~ real'
Hence
m
ILl1 ~ % llkl ~(I0, fk ) + Const o(n) k= I TF k '
~(~) + Const a(n).
Recall (3.16) and (3.17). Since TF(X,y ) - TF,(x,y) is anti-symmetric, we
* = (the double of Ik) have, with x k = (the midpoint of Ik) , I k
m
IL21 = I Z 7!k(T F - TF,)(Xlkf)(x) k=l
× {TF(× *c f)(x) - TF(× *c f)(xk)} f(x) dx I k I k
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m
+ Z flk(T F - TF,)(Xlkf)(x ) TF(× , f)(x) f(x)dx I k=l Ik-I k
m =<- Const Z Ilk I(T F - rF,)(Xlkf)(x)l Mf(x) dx
k = l
m
+ k=iZ Ilk I(T F - TF,)(Xlkf)(x) I (/ik_l k ~ ) dx
_-< Const lIT F - TF,II2, 2 =< Const ~(n).
We have
IL31 ~ j,k;j#kZ Ii j {flk ITr(x,y ) - Tr,(x,Y) idY } ITFf(X) I dx
z fi~ {71, c j,k;j#k cN lj j n I k
ITF(X,y) - TF, (x,y)IdY}ITFf(x) I dx
+ Z {I * c I TF(x,y)-TF,(x,Y) IdY} ITFf(x) I dx $1kC* N I. (lj -lj) N I k j ,k;j#k J
+ Z I , {Ilk ITF(X,Y) - TF,(x,y) IdY} ITFf(X) Idx j,k;j#k (Ik-I k) N lj
= L31 + L32 + L33,
m
[L331 ~ z f, k=l Ik-I k
{flk ITF(X'Y) - Tr,(x,y) Idy } ITFf(x) idx
m
2 Z f , (flk ~ ) ITFf(x) idx k=l Ik-I k
m ~ ) 3 dx}i/3 2 Z {f , (flk {I .
k=l Ik-I k Ik-I k
m Const Z Ilk II/3 {7 , ITFf(x) I 3/2 dx} 2/3
k=l I k
m 1/3 m dx}2/3 Const ( Z llkl) { E I . ITFf(x) I 3/2 k=l k=l I k
m llk 12 Const { I_~ ( Z ) ITFf(x) l 3/2 dx} 2/3
k=l (X-Xk)2 +llk 12
ITFf(x) I 3/2 dx} 2/3
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89
m
Const {f ( Z k=l (X-Xk)
IIk 12 )4}I/6 {7 ~ITFf(x) l 2 dx} I/2
T llk 12
I[Trf] [ < Const ][TF] [ < Const ~(n), Const 2 = 2~2 =
m
IL3,21 ~ Z {7 , ITF(x,Y) - TF,(x,y) IdY} ITrf(x) Idx j=l flj lj-lj
m
7i j dy i d x =< 2 z (7 , ]~ ) ITrf(x) j=l I.-i.
J ]
Const IITFfll 2 ~ Const o(n)
and
IL311 l~(x) - Ar,(x) I + IAF(y)-AF,(y) I
Z fI~ {f *c ~, n ~k Ix - yl 2 j,k;j#k c N lj ]
m n Z 71. I Z A (x) l (71,c dy ) iTFf(x) idx
j=l 3 ~=n-g ~ . Ix-yl 2 J
dy}ITFf(x) Idx
Const
+ Const
Const /i 0 ITFf(X)]dx + Const f ~ ( Z - k= I iX_Xkl 2
m n
Z fik {Tik I Z A (y) I/Ix-yl 2 dy} ITrf(x) Idx k= I c ~=n-g
m
lljl (fl, c dy ) irFf(x) idx j=l flj • Ix_yl 2
]
m
Z J" *c IIkl (7I k dy ) id x k=l I k Ix-Yl 2 ITrf (x)
m llk 12
+ Ilk 12 )ITF f(x) Idx
Const IITrfll 2 ~ Const ~(n).
Thus
IL31 ~ Censt ~(n).
Consequently,
l((r r _ rF,)f, rFf)fdxl ~ ILII + Ie21 + IL31 ~ ~(g) + Const ~(n).
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In the same manner, we have
I(TF, f, (T r - TF,)f)fdx[
m
Ik=IZ Ilk TF,(Xlkf)(x) (T F - TF,)(Xlkf)(x) f(x)dxl + Const ~(n).
Since TF,(x,y) = i/(x-y) (x,y E I k, 1 ~ k ~ m), the first quantity in the right-
hand side is dominated by Const ~(n). Thus
3(10, Tr, f) ~ ~(Io, TF, , f) + $(g) + Const ~(n)
~(n -g- I) + ~(g) + Const c(n),
which gives (3.19).
Lemma 3.5. a(n) 2 ~ Const ~(n) (n $ 0).
Proof. We see that, for any crank F , ~(TF) 2 ~ Const $(TF).
(See(Second Step) in §2.8.) Hence it is sufficent to show that
Q.E.D.
(3.20) sup {$(Tr); F crank of degree n} ~ Const $(n).
Since $(0) ~ Const, (3.20) holds for n = 0. Let F be a crank of degree
n g 1 and let f E L~eal, 0 ~ f ~ i. For any dyadic interval I, there exist
a crank F I of degree ~ n and fI ~ LTeal' 0 ~ fI ~ 1 such that
~(I, TF, f) = III $(I0, TFI,fI ). Hence (i/IIl) $(I, T F, f) ~ $(n). For any
non-dyadic interval I c I0, there exist mutually disjoint two dyadic intervals
I I, 12 such that Jill = tI21 ~2JII, ~I IUI 2 Then
~--~i $(I, TF, f) = ~i 3(11 U 12, T r, Xlf)
~ {3(11' T r, Xlf) + $(I 2, T r, Xlf)
+ (if2 dy )2 d i) 7i I ix_y I dx + 7i 2(7I 1 ix_y I
Const {~(n) + i} ~ Const $(n).
2 dx}
For any interval I c ~, we have
Thus
1 $(I 0 N I, TF,f) + Const ~ Const ~(n). 1 $(I, TF,f) ~ ill
$(TF) ~ Const ~(n), which gives (3.20).
In the same manner as in Lemmas 3.4 and 3.5, we have
Q.E.D.
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91
Lemma 3.6. o(n) ~ ~(n-l) + Const (n ~ i).
We now give the proof of (3.13). Since ~(0) ~ Const, Lemmas 3.4 and
3.6 show that ~(n) < - for all n ~ i. By Lemmas 3.4 and 3.5, we have, for
any non-negative integer m,
~(2 m) ~ ~(2 m-l) + $(2 m-I - i) + Const ~(2 m)
_<- 2 $(2 m-l) + Const ~(2 m) =<...
m =< 2 m $(i) + Const Z 2 m-k ~(2 k) =< 2 TM $(i) + Const 2 m ~(2 TM)
k=l
_<- Const 2 m ~(2m) I/2,
which shows that $(2 m) -<_ Const 2 2m, Hence
m 2m_k ~(2 m) -_< 2 m ~(i) + Const E ~(k) I/2 k=l
m -_< 2 m $(I) + Const % 2 m-k 2 k = < Const(m+l)2 TM-
k=l
Consequently,
m 2m_k ~(k) 1/2 ~(2 TM) <= 2 m $(i) + Const Z k=l
m 2k/2 2 m. <_- 2 m ~(i) + Const % 2m-k~/-~ -<_ Const
k=l
For an integer n g i, we choose a non-negative integer m so that
= 2 m+l . 2 m < n < Then
$(n) ~ $(2 m+l) & Const 2 m+l ~ Const n,
Consequently, Lemmas 3.3 and 3.5 yield (3.13).
§3.4. Proof of the latter half of Theorem E
The following idea is essentially due to David [18, Chap. III].
q, ~, ~, we write
F(n) = F(n, q, e, ~) A n = A (q'~'~) (n e i). n -
We put
T (x,y) = TF(n)(X,y) x-y '
~0 (n) = ~(I0' T0n' XI O) (ng i).
Fixing
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92
Here are two lemmas necessary for the proof.
Lemma 3.7. ~0(I) ~ [~ - ~12/1o0. Proof. Let x ( [(k0-l)2-q, k02-q) (k 0 is odd). Then
0 ( ~ ) [ = I T 1 ×i0 1710 1 i ~} dy I { (x-y) + i(Al(X)-Al(Y)) x-y
Z f dy I k even [(k-l)2-q,k2 -q) {(x-y) + i(a-~)2-q}(x-y)
>= ~ - ~12 -q I Re Z I I k even [(k-l)2-q,k2 -q)
- #12 -q Z 7 dy ......
k even [(k_l)2-q,k2-q) (x_y)2 + (~_~)2 2-2q
=
f2-q +I - ~12- q dy > I S _ BI/10.
2- q y2 + (~_6)2' 2-2q =
In the same manner, we have, for any x ( [(ko-l)2-q, k02-q) (k 0
IT~ XIo(X) I a Is - ~I/lO.
Thus
~ 0 XI0) > ( ~ )2 dx > Is - ~12/I00. ~°(I) = $(I°' t1' = I[o lO =
is even),
Q.E.D.
Lemma 3.8. For two positive integers n, g with g ~ n - i,
(3.21) T0(n) e ~0(~) + ~0(n - g) - Const q-l~-~-.
Proof. We write
I k = [(k-l)2 -qg, k2 -qg ) (i ~ k ~ 2qg).
We have
= t 2 ~ o ( ~ ) ~ o ( n ) Izo Ir~ ×~o(X) dx =
+ fl0(T~- T~)(x) T 0 (x) dx + 0 (T~ T~) dx XI 0 n XI 0 fl 0 TZ Xl0(X) - XI0(X)
= T0(g) + L 1 + L 2,
2 qg 0 T~(x,y)dy} dx
L I = k=iZ /ik {/ik(T~(x,y) - Tg(x,y))dy}{flk
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2 qg Z k=l
0 T~(x,y)dy}dx flk {flk (T~(x,y) - T~(x,y))dy} {flo_l k
2 q&
k=IE fl0-1 k {fl k (Tn 0(x'y) - TO(x'y))dY} T0n XI O(x) dx
= LII + LI2 + LI3.
0 T~(x,y) = 0 (x, y EIk, 1 ~ k =< 2 q~)- and Note that
n
T (x,y) = [(x-y) + i Z = g+l
(A (x) - A (y))]-i 1 x-y
(x, y E I k, i ~ k ---- 2 qg)
Hence, extending the coordinate axes, we have
2 qg 2 q&
= k=iZ flk [flk T~(x,y)dy] 2 ^ dx = k=iZ Ilk] ~0(n - L) = ~0(n - £). LII
Let p be the integer such that q4 2q4 < p ~ and (log p)/log 2 is an
integer. For each i ~ k ~ 2 qg, we write I k = Ik, 1 U... U I , 2 k,p 2
where P {Ik,j}j= 1 are mutually disjoint dyadic intervals of length p-2 2q~
Let ~k denote the closed interval of the same midpoint as I k and of length
(i + p-l) Ilkl , and let Ik, j denote the closed interval of the same midpoint
as Ik, j and of length (i + p-4) llk,jl . We have, with
x k = (the midpoint of Ik) , Xk, j = (the midpoint of Ik,j) ,
2 qg
LI2 = k=iZ flk {fiE T~(x,y)dy} {fl0_l k T~(x,y)dy} dx
2 qg
k=iE fl k {flk T~(x,y)dy} {f(l 0 N ~k)-Ik T~(x,y)dy}dx
2 qg
z {Ilk k=l fl k % .(T~(x,y)-T~(Xk,Y))dy}dx T~(x,y)dy} {fl0_(10 N i k)
= LI21 + LI22 ,
ILl211 2 qg dy
2 k=iZ fie Iflk Tn0(X,y)dy I (fik_l k ~ ) dx
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2 q& 2 q8 Z ~(Ik ' T O )}i/2 { Z k= I n' XI k k= I
fl k (f~k_l k ~ )2 dx}i/2
Const {f~ log 2 <i + ~s )ds} I/2 ~0(n - 8) 1/2
Const p-i/2 ~o(n _ ~)i/2
and
LI2 2 =
2qZ p2 Z Z k=l j =i
S I {71 rO(x,y)dy){fiO_(iOnik)(TOn(x,y)-TOn(~k,Y))aY> dx k,j k,j
2q~ p2
Z E Z {/I } {fI0-(l 0 Nik)} k=l j=l f(l k N Ik,j)-Ik, j k,j
2qg p2
Z Z f ~c {fI k } {fI0-(~ 0 n ik)} k=l j=l I k 0 k,j '3
= L1221 + L1222 + L1223 •
Since n 2 IX-Xk,j I +t ~ (A~(x>-A~(Xk, j) ) 1
~=~+I ........... ]TnO(x,y) - T0n(Xk,j, Y)] _-< [x_y I IXk, j - y]
Cons¢ {p-2 2-q8 + 2-q(8+i)} / ]Xk, j _ y12
Const p-2 2-q%/iXk,j _ yi2
(3.13) shows that
2qg p2
IL12211 = I Z Z k=l j=i
(x ( Ik, j, y £ ~),
fik,j{fIk, j T~(x,y)dy}
× {fi0_(i 0 fl I k)
2q8 p2 -2 2-qg
Const Z Z fI Ifik,j T~(x,y)dy] (f~ P dy) dx k=l j=l k,j ~ IXk,j-Y] 2
2q~ p2 Const p-i Z Z fIk, j]fI T~ (x'y)dyl
k=l j =i k,j
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Const p-i NT~H2, 2 ~ Const p-i ff .
Since
ITnO(x,y) - TOn(xk,Y) I ~ Const p 2-q~llxk-y[ 2 (x E I k, y E ~k ) ,
<_- [-2 [TO(x,y)] =< Const 2-q(g+l)/Ix-yl2 Const 2 -q(e+l) p8 llk, j
~C =< Const pl0 2-q/llk,jl (x 6 leo Ik, j, y ~ Ik, j)
we have
2 qg [L1222] =< Const E
k=l
~_ Const p2 fol
2 P ~-~ P 2 -q~ Z f g (flk'j )(flk IXk -y]2 j=l Ik,j-lk,j
log(l + p-4s-l) ds ~ Const/p
dy)dx
and
2qg p2
[L1223 [ =< Const Z Y f ~c (Const pl02-q)(f~ k=l j=l I k 0 k,j k
2 q~ =~ Const p14 2- q E fl k dx =< Const p14 2- q .
k=l
p 2 -q~ 2 dy) dx
I Xk-Y I
Thus, by (3.13),
ILl21 ~ILI211 + IL12211 + IL12221 + IL1223 I
Const {p-i/2 ~0(n - ~)i/2 + p-i/~ + p-i + p14 2- q }
= Const p-i/2 ~ e)i/2 < {~o(n - + V~ } ~ Const~/q.
Since
iT0n(X,y) 0 2-q(g+l) / - rg(x,y) I _~ Const Ix-yl 2
~C Const p2 2- q llkl/{iX_Xkl2 + llk12 } (x E I k, y EIk),
we have, in the same manner as in the estimate of IL331 in §3.3,
2 qg ILl31 _-< Const k=i% f(lo nik)_Ik ( fi e ~ ) IT0n Xlo(X) lax
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2 q~ i lkl 2 + Const p2 2-q { % n
sz0 k=l Ix-x~I 2 + tlkl 2 } LT°×I0 (x)l 2 qg
Const { Z ~ ( ~ )3 dx}i/3 k=l fIk-I k IIk
dx
2 qg × { Z f~k IT0 X10(x) 13/2 dx}2/3
k= 1 n
+ 2qg l lkl 2 )
Const p2 2- q {flo ( Z 2 2 k=l I X-Xkl + llkl
Const
2 dx}i/2{/io ITn~IO(x) 12dx}I/2
2 q~ i, ~ ~i/3 {fl0/P log3(l + s)aS~ { Z k=l
n X10(x) 13/2 7~k I T0 dx} 2/3
+ Const p2 2- q 1IT,ll2, 2
Const (p-i/4 + p2 2-q)NT~II2,2 =< Const q-iVan
Thus
L I ~ LII - ILl2 [ - ILl31 ~ ~o(n - g) - Const q-l~/~.
In the same manner,
2 qg IL21 _~ Ik=iZ /ik {flk TO(x,y)dy} {flk(TO(x,y) - TO(x,y))dy} dxl
+ Const q-l~-~n.
Since T~(x,y) ~ 0 (x, y 6 I k, 1 ~ k & 2q&), IL21 & Const q-l~nn. Consequently,
~0(n) ~ ~O(g) + L I - IL21 ~ ~O(g) + ~o(n - g) - Const q-l~-~. Q.E.D.
We now give the proof of (3.14). Lemmas 3.7 and 3.8 show that, for any
positive integer m,
~0(2 m) ~ 2 ~0(2 m-l) - Const q-i 2m/2 ~ ...
-I m~l 2k 2(m_k)/2 2 m ~0(i) - Const q k=0
2 m {I~ - ~12/i00 - COnst/q} .
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For any integer n ->_ 2, we choose a positive integer m so that
2 m- i 2 m . < n ~ Then
-i ~0(n) >__ ~0(2 m-l) + ~o(n - 2 m-l) - Const q V~
2 m-I {I= - ~12/i00 - Const/q}
~V~{I~ - ~12/200 - Const/q} .
- Const q-iV~
Thus (3.14) holds if ~0 is large enough. This completes the proof of the
latter half of Theorem E.
Corollary 3.9. For any crank F of degree n ~ I, p(F) ~ p+(r) ~ Const/~-~.
If Is - fll 2 ~ q0/q, then p(r(n)) I/3 ~ Const p+(r(n)) ~ Const/~-
(F(n) = r(n,q,~,~), n g i), where ~0 is the constant in Theorem E.
Proof. For any crank F of degree n ~ i, we have
NHrII1 1 ~ const HTFfIL l ,L~(~)" L (F),Lw(r) (~)
Since ~ is a locally chord-arc compact curve with constant i, Theorem D is
valid for F . Thus Theorem D, Lemma 3.3 and (3.13) yield the required
inequalities. The latter half is also deduced from Theorem D, Lemma 3.3 and
(3.14). Q.E.D.
David [18, Chap. III] showed that (2.39) is best possible in the following
sense:
(3.22) sup {IIC[a]II2,2; a 6 Lreal,M } >= Const I/M (M ->_ 1).
This is deduced from Theorem E as follows. We showed that
IITF0(n ) Xl0112 ->_ ConstV~ (n > i) ,
where Fo(n) = F(n, i + (the integral part of ~0 ) , i, 0). Adding some segments
parallel to the y-axis to Fo(n), we define an arc A n with endpoints 0 and
Then IAnl ~ Const n. There exists a Lipsehitz graph
A n = {(x, f0 b (s)ds); x ~ I0} such that IA ~ C O n and
IFo(n) U Amn - Fo(n) n A*n I ~ s, where C O is an absolute constant and
0 < g < 1/2 is determined later. We have
1.
Sio Ib~(~)ldx ~ IA~I ----c o n
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98
Lemma 2.2 shows that there exists an open set ~ = Uk= 1 I k (I k = I~, k) in I 0
such that
[~J ~ ~, (Ib~l)ik & Con/8 (k a i),
Ib~(x) I ~ Con/8 a.e. on I 0 - ~ .
We put
C(x>= I * (x ( I k, k ~ i) (bn) Ák
and A n = {(x, f0 bn (s)ds); x ( I0}. Then lib n I]. N C 0 n/g .
projection of F0(n) N A n to ~ and let F - I 0 - E. Since
Let E be the
X :x( :o' (s> s :o C (s>ds) = ),i ..,
we have IF1 ~ 2s. From the definition, C[b n ](x,y) = TF0(n)(X,y) (x,y 6 E).
Hence T h e o r e m E s h o w s t h a t
{rE IC[b~ *] ×E (x)]2dx}l/2 = {rE Irr0(n> ×E (x)12 dx}l/2
=> {rE ITFo(n) ×I O(x) 12 dx}i/2 - {fIoITpo(n) XF (x) 12 dx}i/2
{Const n - /F ITF0(n) Xl0(X) 12 dx}i/2 - Const V~V~.
By (3.13) and (3.18), we have
TF0 )if TF0 )) + l} ~ Const V~, II (n 4,4 ~ Const{o( (n
and hence,
7F ITFo(n ) ×lo(X) l 2 dx _-< IITF0(n)II4) 4 IFI 1/2 =< Const nV~.
Thus
Choosing
{fl0 IC[b~*] XE(X) I 2 dx} I/2 g Const~n- {(i - ConstV~c ) I/2 -
sufficiently small, we have
Const VT}.
** ** 112 Constq-f (n > i), bn (Lreal,C0n/e) llC[bn ] ,2 >= =
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99
which yields (3.22).
§3.5. Analytic capacities of fat cranks
For p > 0, z 6 ¢ and E c ¢, we write [pE + z] = {~ + z; ~ 6 E}.
With 0 ~_ ~ -<- i/i00 and a segment J c ¢ parallel to the x-axis, we associate
the closed segment J(~) of the same midpoint as J, parallel to the x-axis
and of length (i + ~) IJl. With a positive integer q ~_ 2, 0 ~ ~ --< I/I00
and a segment J c C parallel to the x-axis, we associate
2q-i
J(q,~) = U {[J2k_l(~) + i 2-qlJl] U J2k(@)} , k=l
2 q where {Jk}k= 1 are mutually non-overlapping segments on J of length 2-qlJl;
these are ordered from left to right. The set J(q,~) is a union of 2 q closed
segments of length 2-q(l + ~) IJl. A segment F 0 = [0,i] is called a crank n = of type O. For a finite sequence {~j }j=0' ~0 0 of non-negative numbers
less than or equal to i/i00, a finite union F of closed segments parallel to n
the x-axis is called a (fat) crank of type {~j }j=O if there exists a crank
n-i such that F' = Uk=l~ Jk ({Jk}k=l£ are components of F') of type {~J }j=0
F = U Jk(qk , ~n ) k=l
for some g-tuple (ql' "''' q~)
2. We write simply F'[(ql ' ...
of positive integers larger than or equal to
T . , q&;~n )
Proposition 3.10. Let F be a crank of type {~j}~=O ' ~0 = 0. Then
n U 1 }-I. (3.23) T(T) ~ Const { Z H
~=I j=0 (l+~j)
At present, the estimate of T(F) from above is unknown. The method in
[29, p. 87] and (3.8) do not yield satisfactory inequalities. The following
n be n+l cranks such that proof of (3.23) is standard. Let {F }~= 0
r 0 [ r I [ ... [ r (. ;~i) (. ;~2) (. ;+n) n
We put
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1 0 0
h (z) = j=0 (i + ~j) '
g (z) = Im ~I" hp(z) P
1 = --~ Im p.v. /F
where Im denotes the imaginary part.
I--< ~ = < n,
h (~) Id~I (z E r , 0 = < ~ ~ n),
Then go ~ 0. We show that, for any
(3.24) il g~II N fig ill + const ~ .
L (F) - ~- L (Fp_l) j=0 (i + ~j)
Jk with components We can write F _ I = Uk= 1 {Jk}k= 1 of
= can write F Uk= 1 Jk(qk , ~ ) with some ~-tuple (ql' "''' q~)"
z 0 E Jk0(qk0,~ ) and let z 0 be the point on Jk0 nearest to z 0.
F i'
Let
Then
and
Ig (z 0) - g~_l(Z~)
i
1 +I 7
Im fjk 0
E k#k 0
I i fJk0(qk0,~ ) h (~) ~ Im ~ z0
h~_l(~) , Id~l I
- z 0
h(~) h i(~)
{Im 7jk(qk,@~ ) ~ _ z0-- ]d~I - Im 7Jk ~-±- z~
= L (I) + L (2), say.
Id~l~l
We can write
G 0
U Jk0(qk0 '~) = j=l
G 0 with its components {Tj }j=l ;
x-coordinate of their midpoints are increasing.
qk yj (G 0 = 2 0)
these components are ordered so that the
Without loss of generality, we
may assume that cY0/2
z0 ~ Uj=I Y2j-I "
h i (~) - Id~I Im fj
k 0 ~- z 0
G0/2 Since {Y2j}j=I are disjoint and
h (~) Id~I 0, ......... =
= Im /U°0/2j 1 Y2j-i
I Z 0
we have
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101
L (I) h(~) 1
-- IIm I ~012 ~ - z 0 Uj=I T2j
-i (~0 IJkol
=< ! f~ 2 - - (x-Re z0) + (~011Jk01) 2
= ~ 1
( i + _ ® j ) " j = O
Id IL
dx
For 1 ~ k ~ g, 0 ~ v ~ ~ -i, 7k(V) denotes the component of Fv generating
Jk" In particular, Yk(~-l) = Jk (i ~ k ~ g). We put
where
h ( ~ )
L(2)v = k Z( G !fJk(qk'~b ). ~ -~ Zo--- Id~l
hb-l(~)-, Id~II (i ~ v ~ W-I), fJk ~ - z 0
Gv = {i ~ k & ~; k # k 0, Yk(V-l) = Yk0(V-l), Tk(V) # 7k0(V)}.
Then
h (~) h_l(~) - L (2) =< k#k0Z Ifjk(qk,@# > _ b_ z0 Id~l . . . . /Jk ~ -----*--z 0 Id~ll = v=l ~Zl L(2)~ "
We now estimate L(2)'v Note that ITk(V) I = IYk0(V) I (k (Gv) . A geometric
observation s h o w s t h a t , f o r a n y k ( G ,
(3.25) dis(J k U Jk(qk,@ ), Jk0 U Jk0(qk0,@ )) ~ diS(Yk(V), Tk 0(v))
- 2 l~k0(~)l 2-2 2-4 ~f
{(1 + ~v+l ) + (l+ ¢~,+l) (l+ @v+ 2) ...
2-2(~-v) } + Tl (I + %j) j =v+l
=> diS(Yk(V), Yko(V)) - 2 IYko(V) I
3 => diS(Yk(V ), Yk0(~)) - ~ IYko(V) l
1.01 .i.01.2 { --7- + ~--#-~ + "'" }
Since
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102
= h_l(~) Id~l /jk(qk,¢~ ) h (~) Jd~ I Ijk
we have, with z k = (the midpoint of Jk )' Qk = Jk U Jk(qk,@ ),
Ifjk(qk,¢~ ) i i L (2) = Z { ~ - Zo , } h (~)Id~I v k (G z k - z 0
v
+ { i * 1 } h l(~ ) idol 1 IJk z k - z 0 ~ - z 0
Const Z k ~G
~-i = Const N
j=O
The segment Tk0(V - i)
{(JJkl + IJk01) dis(Q k, Qk0 )-2 7jk h~-l(~) Id~l}
i Z {(IJk] + ]Jk01)IJkl diS(Qk,Qk0)-2}. (i + Cj) k E G
!
' 2qv generates 2 qv components {km}m= 1 of r of
v
length IYk0(V) I , where q~ = log {(i + ~v) IYk0(V-l) I/ IYk0(V) l} /log 2.
We may assume that k I = 7ko(V). Let
q'
G = {k ~ G ; k m } (2 m ~ 2 v ) v,m v = Yk(V) ~ - "
q~
2 v Then G = G . We have
v Urn=2 v,m
Z (IJkl + IJkol)IJkl k(G
v~m
~_ Ikil 2 -2(~-i-v) N (i + ¢j) Z IJkl v< j -< ~-i k (G - v,m
= Ik112 2 -2(~-I-~) ~ (i + @j)2 _-< ikli2 v<j_- < ~-i
where N (i + ~j) denotes v< j _~ ~-i
observation and (3.25) show that
i if v =D -i.
2 -(~-I-~) ,
Hence a geometric
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103
L (2) =< Const H j=0
~-i -<_ Const
j=O (i + @j)
v
2qv 1 % Z (IJkJ + IJk0l)IJkl diS(Qk,Qk0)-2
(i + ~j) m= 2 k # G v,m
v
2qv 1 % diS(km,)~l)-2 Z (IJkl + IJko I) IJkl
m=2 k ~G v,m
2q~ i)Vl I 2 2-(~-l-v ) y, dis(Xm,kl)-2
m=2
~-i 1 --< Const
j=0 (i + ~j)
~-i i I~i 12 2 -(~-l-v) Z ( 1 2 Const H (i + @j) ) j=O k=l I Xll k
~-i --< Const H 1 2_(~_i_~).
j=O ( i + ~j)
Tbus
* (i) L(2) Ig (z0) I ~-I g _l(zO) I + L + E
v= I V
1 ~-i 1 =< IIg~_IIIL~(F ~ 1 ) + n + Const H (i + ~j)
_ j=0 (l + ~j) j=0
_-< IIg~_lll ~ + Const H (i + ~j) " L (r _ I) j=0
Since z 0 ~ F is arbitrary, we obtain (3.24).
By (3.24) and go m 0, we have
n llIm H F hnll ~ Const E H 1
n L°°(rn ) ~=i j=0 (i + ~j)
(= Const ~n' say).
Evidently,
fF hn(~) Id~I = i, IIhnli n L °~ (Fn)
on r so that Hence we can define a non-negative function h n n
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104
Ir hn(<) I d<[ = 80/<n ' n
llhn*NL'(rn) + lllm"r h$1L~(r # S l,
h:(<) = 0
h*(<) n
at endpoints of each component of F , n
is c o n t i n u o u s l y d i f f e r e n t i a b l e a l o n g F n ,
where 6 0 is an absolute constant. Let
h (<) ^* i n I d<T hn(Z) = 2~i fF ~ - z ' - ' '
Ii
u (z) = Im h:(z) Vn(Z) = Re h*(z) n ' n '
(3.26) fn(Z) = {I - exp(h:(z))} /{i + exp(~:(z))} (z ~ Fn).
Then f is analytic outside F and n n
: 1 h:(<) {d~ 1 : 60/(2 <n ) Ifn (')I 2~ fF * n
The nontangential limit of fUn(Z) I at each point on Fn is dominated by
llIm HFn h~llL~O(Fn) _< 1.
Since fUn(Z) I is subharmonic in F c and continuous on n
sup F c fUn(Z) [ =< i. Hence, for any z ~ F n, z (
n
U {~}, we have
I fn(Z) I 2 1 + exp(2 Vn(Z)) - 2 exp(Vn(Z))COS(Un(Z))
i, 1 + exp(2 v (z)) + 2 exp(vn(Z))COS(Un(Z))
n
which shows that IifnllH~ ~ i. Consequently,
n T(r n) a If'(-)I ~ 601(2 ~n ) = Const{ Z H I
n ~=i j=0 (i + _ ~j)
-i.
This completes the proof of Proposition 3.10.
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105
§3.6. Analytic capacity and integralgeometric quantities
Let L(r,@) (r > 0, -~ < e ~ ~) denote the straight line defined by the
equation x cos @ + y sin @ = r. For a compact set E C ~, we write
NE(r,@) = #{E N L(r,@)}, where #{E A L(r,O)} is the (cardinal) number of
elements of E n g(r,8). For e > 0 and 0 < a ~ i, we put
Cr(e)(E)~ = i n f f _~ { f~ N a { u ~ = l D ( Z k , r k ) } ( r , @ ) ~ dr} dS,
where t h e in f imum i s t a k e n o v e r a l l f i n i t e c o v e r i n g s { D ( Z k ' r k ) k=l
r a d i i l e s s t h a n e . We pu t
of E with
Cr (E) = lim Cr(e)(E) (0 < ~. < i), ~ + 0
Bu(E) = l i m l i m Cr ( ¢ ) ( E ) . c ÷ O a ÷ O
If E c D(0,1), then Bu(E)/2~ is called the Buffon needle probability; this
is the probability (measured by dr d@/2~) of needles L(r,O) (0 < r < i,
I01 ! ~) intersecting with E. Suppose that E is a locally chord-arc compact
curve. Then Crofton's formula [49, p.13] shows that CrI(E ) = Coust I E I. By
(3.7), we have T(E) ~ Const CrI(E ). From this point of view, it is interesting
to compare ~(.) with Cr (.) (and with Bu(.)). It is known that there exists
a compact set E such that y(E) = 1 and Bu(E) = 0 (cf. Jones-Mural [34]).
We shall show
Theorem F. For any 0 < ~ < 1/2, there exists a compact set E such that
y(E) = 1 and Cr (E) = 0.
Acknowledgement. The author expresses his thanks to Professor Kakutani who
communicated (3.28), and Professors Coifman, Steger who suggested to use the
Galton-Watson process [30] for the estimate of Cr (.). According to Professor
Kakutani, various integralgeometric formulae are used for surgeries, since
X-rays react to, for example, cancers outside bodies. RSL is the first stopping
time of the sun's rays (or needles). Hence it is interesting to try to give an
integralgeometric proof of Theorem C,
In this section, we study Cr (.). For 0 < ~ < I, let (X~}~= I be a
sequence of independent random variables on the standard probabillty space
(PO,S,Prob) (F 0 = [0,1]) such that
eroh(X~ = l ) = e r o b ( X ~ = - 1 ) = / 2 ,
Prob(X~ = 0) = 1 - B (n a 1 ) . H
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106
We put
S~0 = 0' S~n = X~l + "''+ X~n (n > I).
This is a model of random walks. We define a Galton-Watson process {Yn}n= 0
(3.27) y0~(x) = i, y~n(X)= y~n_l(X)+ S~y~n_l(x) (X) (n ->- i, x E F0).
by
Then Prob(y~ n >_- 0) = i (n >_- 0). We put
c (n) = 2 ~+I fO/2 { Z k=l
k s b~n)(t(e))}cos Od@ (n >__ l, 0 ~ <~ < i),
where
b(kn)(6) = Prob(Y~n = k),
t(8) = ~ tan e (0 ~ e < arctan i)
Itane- 2j I (arctan (2j-l) i e < arctan(2j+l), j ~ i).
First we show
Lemma 3.11. ca(n ) _-< Const/(~ n I-~)
The proof of this lemma is standard.
{bk(J)(6)}k=O is defined by P~(x) = Zk= 0 b(J)(~) x k.
(3.28) P~ (x) = P~j-I ( ~2 + (i- 6)x + ~2 x2 ).
In effect, (3.27) shows that, for any
(3.29) b(J)(~) = Prob(y~ = k) =
(j-l) (6) = Z b~ ~=0
(n ~ i, 0 < ~ S 1).
The generating function of
Then
k_a0,
w
Prob(y~_ IJ =g) Prob(S p~ = k - g) Z g=O
z(~) ~' (~) h(1-~) ~2(-~) ~3 , el! g2 ! g3 !
where Z(~) is the summation taken over all triples (~i' g2' g3 ) of
non-negative integers such that ~1 + g2 + g3 = g ' g2 + 2 g3 = k. The
xk-eoeffieient of P~(x) is b~J)(x) and the xk-coefficient of J
P~_I ( 3+ (i- 6)x + ~x 2 ) is equal to the last quantity in (3.29).
(3.28) holds. Let
Thus
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107
vj(~) = I 1 (i - x) -a 8-- P~ j(x) dx (0 ~ j ~ n) ~j(~) ~x -
where ( n {~j ~)}j=0 are inductively defined by 40(~) = 0,
~j(~) = ~ +(i-9)~j_l(X)+ ~ ~j_l(X) 2
Since
1 1 (i - x)-a(k x k-l) dx a fl-(i/k) (i - x)-~(k x k-l) dx fo
k ~ a_ Const i - ~ (k ~_ 2),
we have
Z k=l
k s bln)(~) ~ Const (i - a) v0(~).
Since
(l-~)-a = {i- (~ +(1-~)x+ ~x 2)}-= (o=~i),
(3.28) shows that
vj(~) = f~j(~) (i- x)-~{(l-~) + ~x} ~ P~n_j_l(~2 +(l-~)x + ~2 x2)dx
~l ~l-(~ + ~ - ~ + ~ ~-°~(~-~+ ~ ~ ~ +(~-~+ ~d~ ~j (~) n-j-l~2
= Vj+l(~),
a n d hence
v0(~) ~ Vl(~) ~ . . . ~ Vn(~)
1 -a % p~0(x)dx = ii = f~n(~ ) (i- x) ~- _
We have easily I 1 - ~n(~) I -<- Const/( ~ n). Thus
Z k a b(kn)(~) <= Const/(~n) l-a k=l
(i - ~n(~)) I-~.
Consequently, we have, with e. = arctan j (j ~ 0), J
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108
c (n) _-< Const n ~-I 0/2 f t(@) ~-I cos6 d@
Const n cr-I { 81 I0 (tan Q)a-lcos @ d@ +
Const n ~-I { I I Y dy 0 (i + y2) 3/2
" @2j+l Itan 8- 2j I ~-1 j fl I 82 j-I
" i .... y~-i + Z I_ I 3/2 dy ~ Const/(~ nl-~).
j=l {i + (y + 2j) 2}
cos @ d@}
This completes the proof of Lemma 3.11.
Let F' and F be two cranks such that n = (the degree of
(the degree of F') ~ i. If there exist an n-tuple (A I, ..., A n )
such that
r) -
of cranks
r' = A I [ A 2 [ --- [ A n = r
(0-1; ") (0`2; ") (Qn; ")
for some n-tuple (0`i' ~)' t {q(~) g .... = }k~l of finite sequences
integers, we write F' [[ F and
of positive
~(F',F) = gin {q~);{ 1 s k -< g , i _-< ~ < n} .
Note that, for any crank F ,
Cry(F) = 2 ~ I_~ ~ {I~ NF(r,0)~ dr} dG (0 ~ ~ ~ i).
Lemma 3.12. For 0 ~ g ~ i, 0 ~ ~ ~ i, gO ~ 1
crank F* of degree n such that n
and n ~ i, there exists a
(3.30) ~(F0' r'n) => g0' ICr~(r*n) - C~ (n) l < C ,
where F 0 = [0,i].
Proof. For a finite increasing sequence 0` = {qk}gk=l of positive integers,
we put gap(~ = min {qk - qk-l; 1 =< k =< g} , where qo = O. Let
~n = (0`1 ..... h), ~ = {qi~) }k~l be an n-tuple of finite increasing
sequences of positive integers such that
q~) q(~) q~)
~i = i, ~ = 2 + 2 2 + ...+ 2 ~-i (2 --< ~ --< n),
we put gap(~n) = min{gap(~); i ~ ~ ~ n} . With ~n' we associate n cranks
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109
r~ = F(Q 1 . . . . . Q)
* * (i) r I = FI(QI) = r0(q 1
been defined so that
(1 & ~ & n) as follows. Let
,0) ( F 0 = [0,i]). Suppose that rl, r2, ..., r _ I have
r k has gk componen t s (1 N k N g - l ) . Then F _ 1 i s
expressed in the form r _i = Uk ~ j ~1) with its components
{ji~-1))~-i "k=l ; these are ordered so that the x-coordinates of their midpoints
are increasing. We put
, , g~-i ji~_l) (qi~_l),o) " r = r(% . . . . . %) = u
k=l
The set rn(~n) is a crank of degree n. We now s~udy Cr~(rn(~n)). We have,
with 0j = arctan j, 0 ~ 0j < ~/2 (j ~ 0),
" (r,O) ~ dr} de 2-~ Cr~(rn*(@n)) " f-n{fo Nr*(~n)n
- O. -eJ-i 70 } Z {I J I 0 +I j=l 0j -i -Oj
+ i s]
( = Z {dj(~n ) + d j(~n )} j=l.
+ do(~n) , say).
i
tan 0 1-tan 0 tan 0 1-tan 0 4 4 4 4
L(x cos e,e)
For 0 < 6 < @i' we put ~0)(@) = 0,
Ix ~ r0; ~ , (x c o s e , e ) = kl r(Q I . . . . . 0.~)
(k_>- 0, i < ~ =<- n).
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110
Then bk(~)(e) = 0 (k>= 2~ + 1 , 0 ~_ ~ ~ n). We have
b~0)(e) = 1 = Prob(y0an 8 = i)
bk(1)(e) = Prob(ylan @ = k) (0- -< k ~ - 2).
Let 1 ~ j ~ 2 ~-I, 2 ~ ~ ~ n. To a component V of {x E F0; N , (x cosS, e)=j},
there correspond j components j(~-l) , ..-, j(~-l) of F* F~-I v I vj ~-I
which intersect with L(x cos 8,8) for all x E V; these are ordered so that the
x-coordinates of their midpoints are increasing. If (~) is sufficiently %1 large, then
Ix ~ V; # {j(~-l) ((~) ~i %1.
,0) fl L(x cos e , e ) } = k
- IV I Prob(Slan 8 = k_l) 1
is sufficiently small for all 0 =< k--< 2. If (~) q(~) - (~) %l' ~2 %1
sufficiently large, then
are
-IvI Prob(S~ an e = k-2) I
is sufficiently small for all 0 ~ k & 4. Repeating this argument, we see that,
- q(~) are sufficiently large, then if ~ ' ~V 2 - qv 1 ..... qVj ~-i
.stan 8 = k-j)l llx v; {r nL<xcos0,e) =kl-lvIProb j is sufficiently small for all 0 ~ k ~ 2j. Hence, if gap(Q) is sufficiently
)
large, then
l lX 6 F0; , (x cos @,e) j, , cos N N (x 8,8) kl F F ~-i
- bj~(~-l)(8) Prob(S tan3 8 = k - J)l
is sufficiently small for all 0 -_< k =< 2j. If gap(Q) is sufficiently large,
then
I x ~ F0; NF, (x cos e,e) = 0, N , (x cos 8,e) >= i I F
~-I
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111
( = JJx ~ £0; N , (x cos 8,8) = 0, N , (x cos 8,0) >_ 1 J F £ ~-i
_ ~-i)(8 ) Prob(s;an 0 >__ l) j)
is sufficiently small. Thus there exists a positive integer p~(e)
if gap(%) ~ p (@), then
J lx ~ F0; , (x cos O,O) j, N , (x cos @,O) I N k F_ 1 F
- b(~-l)(0). Prob(S tan. @ = k - j)J =< g 2 -3n3 3 3
such that,
for all 0 _~ k -~ 2j, 0 -~ j =< 2g-l. This yields that
2~-i ~tbk~) (e) _ z ~(~-i) (e). erob(stan O = k - J)Jl K j=O ] 3 I
2~-I
j Z {ix E r0; N , (x cos 8,0) = j, N , (x cos 8,0) = kJ j=0 £ r ~-i
_ ~-i)(%) Prob(s~an 8= k- j)}J
=< s(2 g-I + i)2 -3n3 -_< Const s 2 -2n3 (0 _<- k -<_ 2~).
Put p(O) = max{p (8); 1 _~ ~ =< n} . If
2 n
Z Ibk (n)(0) - bk (n)(tan 0) I k=0 k=0
2 n 2 n-I J ~!n-l)(e) Prob(S. tan O <= Z z
k=0 j 0
2n-i
Z Prob(Yn_itan 8 = j)Prob(sjan 8 = k-j) j=0
2n-i
gap(~ n) ->- p(8), then
2 n = E Ib (n)(o) - Prob(Yn tan 8
=k-j)
_-< (2n+l) ~(n-l) _ , . tan 0 Z Jbj (8) - wroD[Yn_ 1
j=0 =j)
n 2 ~_...=< H (2 ~ + i) Z
~=2 j =0
+ Const
= k) t
+ Const ~ (2 n + i)2 -2n3
+ Const 6(2n+I) 2 -2n3
,. tan e ~!l)(o) _ ~r°DiYl = j)j 3
n
~=2
2_2n3 3 . . . . 2 -n (2 ~ + i) (2 n + i)} < Const ~ ,
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112
which shows that
(r,@) a dr - Z k ~ " (n)(tan @)cos @ I If~ NF~(~n) k = l b k
2 n
Iro" N , (x cos @,9) g COS @ dx Z k g b~n)(tan" e)eos e I F k=l n
2 n
= I Z k~ ~k~(n)(@) - b~n)(tan @)} cos @I k=l
3 = 2 ~n 2-n < Const s ~ Const ~ .
There exists a positive integer Pl such that the measure of
2 -n" F = {0 < @ < @i; P(@) > Pl } is less than s If gap(~n) ~- PI'
01 " k ~ . (n)(tan @) cos @ d@ I Idl(Qn)- fO Z b k k=l
@i If0 {/O N , (r,@) ~ dr - % k s bk(n)
F k = l n
(tan @) cos @} d@ I
l{f F + /(0,01)_ F} { } de I
Const 2 ~n IFI + Const s & Const s .
then
For an integer j # I, we can choose, in the same manner as above, a positive
integer pj such that, if gap(~ n) ~ pj, then
81Jl Z k ~ " (n)(t(@)) @ del < s /(i + j2), I dj (~)-Teljl_l k=l o k cos =
where 8_1 = 0. This shows that if gap(~n)
holds.
is sufficiently large, then (3.30)
Q.E.D.
§3.7. Proof of Theorem F ([34])
Here are three lemmas necessary for the proof. From now on, we fix
0< ~< 1/2.
t O = = of degree n Lemma 3.13. For > 1 and n > i, there exist a crank F n
and a non-negative function w on F such that w is a constant on each n n n
component of F n,
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113
(3.31)
~(r 0, r[) ~ ~0' cr(r[) ~ ClI(~ n~-~),
llWnll i * I, llWnll ~ ~ C I, film H , w~lle.(F~ ) ~ Cn~'n~, L (F n) L (r[) F n
where C 1 is an absolute constant.
P r o o f . Leamms 3 . 1 1 and 3 . 1 2 show t h a t t h e r e e x i s t s a c r a n k F of d e g r e e n n
s a t i s f y i n g t h e f i r s t two i n e q u a l i t i e s i n ( 3 . 3 1 ) . I n e q u a l i t y ( 3 , 1 3 ) shows t h a t
II~rn, IIL2(Fn),L 2(Fn) ~ ConstV~-,
which yields
tlHFn, fiLl(m) ,L~(Fn ) ~ Const V~.
Thus, in the same manner as in the proof of Theorem D, we obtain a non-negative
F* f u n c t i o n on s a t i s f y i n g t h e l a s t t h r e e i n e q u a l i t i e s i n ( 3 . 3 1 ) . T a k i n g t h e n
mean o v e r e a c h componen t o f F , we o b t a i n t h e r e q u i r e d f u n c t i o n w • Q.E.D, n n
Lemma 3 . 1 4 . L e t ~0 ~ 1 and n ~ 1. L e t r m be a c r a n k of t y p e {6j}~= 0 _
and w be a non-negative function on F such that w is a constant m m m • .m+n
on each component of F m. Then there exists a crank Fm+ n of type 16j~j= 0
with ~j = 0 (ra+l N j N ~ - n ) and a n o n - n e g a t i v e f u n c t i o n wm+ n on Fm+ n
such that Wm+ n is a constant on each component of Fm+ n,
rm [[ rm+n' c(rm' Fm+n) >= gO'
Cr (Fm+ n) -<- C 1 IFml/(~ n l-a ),
IlWm+nllL 1 = IlWml]L1 " , IlWm+nll ~ C 1 llWmll . ' (rm+n) (Fm) L'(Fm+n) L (r m)
(3.32) tl~m H r win+nil ~ lllm HFmWmllL®(Fm) + C2g-~ llwmll . , m+n L'(Fm+n) L (F m)
where
Proof.
g {Zk}k= 1
C 1 is the constant in Lemma 3.13 and C 2 is an absolute constant.
= g Jk with its components {Jk}k= I. Let We can write r m Uk= I
j be the left endpoints of { k}k=l, respectively. We put
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114
g
Fro+ n = U A k, A k = [IJkIF n + Zk], k=l
Wm+n(Z ) = Wn*((Z-Zk)/IJkl) Wm(Zk) (z E A k, i -<_ k =< ~),
where F and w are the crank and the function in Lemma 3.13, n n m+n
respectively. Then Fm+ n is a crank of type {~j }j=0 such that
F m [[ Fm+n, L(Fm, Fm+n) m gO" The second inequality in (3.31) shows that
Cr (rm+ n) -~ Z Cr (A k) = Z IJkl Cr (rn*) --< C l Irml/(a nl-~). k=l k=l
In the same manner as in Proposition 3.10, we have (3.32). Q.E.D.
In the same manner, we have
m g0 be a crank of type {6j}j= 0 , w be a Lemma 3,15. Let ~ i, n ~ i, r m m
non-negative function on F m such that w m is a constant on each component m+n
of Fm, and let {~j}j=m+l be non-negative numbers less than or equal to m+n
i/I00, Then there exist a crank of type {~j}j=0 and a non-negative
function Wm+ n on Fm+ n such that Wm+ n is a constant on each component
of Fm+n' Fm [[ Fm+n' ~(Fm' Fm+n) ~ g0'
llWm+nIILl (rm+n) llWmllLl (Fm) '
m+n
llWm+nIIe.(Fm+n ) =<-IIWmI[e,(Fm ) / H #=m+l (I + ~ ),
II Im Wm+nll ~ -~ llIm H r Wmll ~ HFm+n L (Fm+ n) m L (F m)
m+n j + Elwll . z {i/ ~ (I+%)}
L (F m) j=m+l ~=m+l
We now construct the required compact set E. Choose a positive number
~0 and a positive integer n o ->_ 2 so that ~0/2 < i - (i/n 0 ) and ~m
~0(i - e) > i. Let Pm be the integral part of (i01/i00) 0 (m >_- I). We
define a sequence {mk}k= 0 of non-negative integers by m 0 = 0, m I = n o
mk+ I non ~ + = Pn0mk
and define a sequence {~j}~=0
(k ~ i),
of non-negatlve numbers by
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115
Cj
0 (O < j -<- m I)
i/i00 (m k< j _~ nomk) k->_ i)
0 (n0n k < j =< ink+l, k>= i).
Let [ = {~k}k=i be an increasing sequence of positive integers which will be
determined later. Using Lemma 3.14 with gO = ~i' n = m l, F 0 and w 0 m i, we
obtain a crank rml and a non-negative functlOnn m wml" Using Lemma 3.15 with
- {¢j}j=ml+l, we obtain a crank rnoml gO = &!' n = (n O l)ml, rml, wml and 0 1
= = Pn0ml, • ) and a non-negative function Wn0ml Using Lemma 3.14 with t 0 ~2 n
rn0ml and Wn0ml, we obtain a crank rm2 and a non-negative function Wm2.
Repeating this argument, we obtain a sequence {Fmk}~=l of cranks and a
sequence {wmk}k=l of non-negative functions such that, for k a 2,
r~ [[ r~+ l, ~(r~, r~+ l) >-_ ~k'
llw k = i, ]i® , -< IlLl(r~) ilwmk L (r k)
II Im HF~ wmk Ii L'(r~) =< C0 V~I
k-i nomv j v Z + Z C O
v=l j =mv+l
nomk, 1 k
c o / n (]_ + ¢~) , ~=0
{L / 11 ( i + ¢ ) } + FL=O
n0mk_ I
Cra(r~) =< C O H (I + 4~ )/(~ PnOmk 1 ~=0
k-i nomv v+lDv-6----- .~
Z C 0 Pnomv/ ~=i ~=i
),
(l + ¢~),
where £~ = rmk and C O = max{Cl, C2}.
and show that T(E([)) ~ Const. Let k $ 2.
m nomv_ I (v ~ 2) and m I = no, we have m v
n0mk_ 1 k / n (i + ¢9
Ilw m I1. , ~ c 0 mk-l+l k L (rk) ~=
k I01 )-(no-l)mk-i = C 0 ( ~-~ ~ Const.
We put E([) = Nj= 1
Then Ilwmkllel (r~)
v
n o (v ~ l),
uLj = i. Since
and hence
Since
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116
~Pnom---~/
nom ~
n (i + ~) ~=0
.lOl.~onomv/2 .i01 -(no-l)mv uonst(l-- ~) ~)
.i01. -{(l-(i/no))-(~O/2)}nomv Const (I--~) (v >= i),
we have
wmkllL®(F ~ Const. II Im HF~ ~)
Thus, in the same manner as in (3.26), we obtain an analytic function
fk ~ H~(FI c) such that
llfkllH ~ ~ i, lfi(~)l e Const.
Since k ~ 2 is arbitrary, we obtain an analytic function f (H~(E([) c)
such that
llfll _<- l, If'(-)l ->_ Const, H ~
which shows that Y(E([)) ~ Const.
Let
.101.(1-(l-a)~o)n0mk gk = (C0/~) ~i--OO ) (k ~ 2).
Then limk ~ ® gk = 0 and
Cr (F~) i01 n0mk-i .101.-(l-~)~0n0mk-i (2c0/~)(i~) ~
2 gk_ 1 .
We can inductively choose ~0 = {gk}k= I0 ®
Cr(i/k)(E([0))~ ~ 2 gk-l' which shows that
satisfies Y(E) > 0 and Cr (E) = 0.
so that, for any k ~ 2,
Cr (E([0)) = 0. Thus E = E([ O)
Remark 3.16. Throughout the note, we use Theorem D to estimate Y(') from
below. Here is a weaker inequality than Theorem D. Let F be a locally chord-arc
curve. Then
> + llHr(f dz/Idzl)[l 2(r ) Y(F) = Const I 7 r f dzI2/{Irfll 2(F)
(cf. [29, p. 19]). This is also useful to estimate Y(r) from below. In effect,
we can deduce (3.23) and {IIC[a]I12,2; a ( ereal} = ~ from this inequality.
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APPENDIX I. AN EXTREMAL PROBLEM
For s I .... , s n E ~, we define
(x,y) = i/{(x-y) + i(Asl ' (x) - A (y)}, Ts I, ..., s n ..., s n s I' --., s n
where
A (x) s I, ..., s n
0 x ~ I 0 : [0,i)
k-i k -- < x < -- 1 < k < n). Sk ( n = n' = =
Put
(4.1) ex (n) = max {~(Tsl ' s n E ~} • ..., s ); Sl' .... n
(See (1.22).) We show
Theorem G. Const ~TOg(n+l) ~ ex (n) ~ Const~g(n+l) (n ~ i).
The first inequality is shown in §3.4. We prove the second inequality. For
a positive integer n, F denotes the totality of sets E c ~ such that n
E c U~=_ [I 0 + ik/n], E has a finite number of components and their projections
to I 0 are mutually disjoint, For E E Fn, we define a function AE(X) on
by x + iAE(X ) E E (x E pr(E)) and AE(X) = 0 (x ~ pr(E)), where pr(E) is
the projection of E to I O. We define a kernel by
TE(X,y) = i/{(x-y) + i(AE(X ) - AE(Y)) } .
Here are three lemmas necessary for the proof.
Lemma 4.1. Let E E Fn and let W I, W 2 be two disjoint subsets of
such that AE(X) ~ 0 on W I and AE(X) ~ 0 on W 2. Then, for any
(4.2) fW 1 IrE(XW2f)(x)I 2 dx ~ Const IIXw2fiI ~ .
pr(E)
f E L 2 ,
' by Proof. We define an operator T E
g ~ f_~ g(y)/{(x-y) - i A(y)} dy.
' Then we have Let T E'' denote the adjoint operator of T E
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118
I T"g(x)I < H*g(x) + Const Mg(x),
llp = < C (p > i). Since < C (p > i). Hence lIT~Ilp,p which shows that nT~ ,P P = P
AE(X) - AE(Y) ~ AE(X) ~ 0 (x 6 W I, y 6 W2), we have, in the same manner as in
the proof of (2.9),
f)(x) I < Const {M(T~f)(x) I TE(Xw2 =
+ IIrE[14/3,4/3' M(I Xw2fl 4/3)(x)3/4}
which gives (4.2).
Put
(x £ Wl),
where
1 co
~(n) = sup {T'/UT-6TT'Ip~tLjl ~(E,f); E E u ~-' f 6 Lreal, 0 ! f <- i},
~(E,f) = /pr(E) ITE(Xpr(E) f)(x)I2 f(x)dx.
Lemma 4.2. For any n ~ I, ~(n) < ~.
Proof. For E £ FI, we put G = pr(E) G' = pr(E N {Im z = ~}) '
(D = O, ±i, ...). Then, for any f 6 Lreal, 0 ! f ! I,
f(Y) dy - Z i I TE(XG f)(x) - fG~ x - y ~=-~ 1 + i(k-~) /G'~ f(Y) dyl
Const Z (x 6 G~, k = 0, ±i, ...). ~=-~ (k-~) 2 + 1
Hence
which shows that
For E E Fn,
~(E,f) ~ Const ( Z fG IH(x G f)(x)i 2 dx
i fG' f(y)dy] 2 + + z I G llz k=-~ ~=-~
Const ~ {IGkl + IfG, f(y)dyl 2 k=-~
~(i) ~ Const. co
f ~ Lreal, 0 ! f $ I,
z z } k =-oo U=- °° (k-~) 2 + 1
+ 1 G~I } --< C o n s t I G1,
we put G' = [n pr(E)],
E k = {z - k; z 6 [n El, k ~ Re z < k+l},
~.x + k. fk(x) = ~[--~---) (0 <_ k _< n-I).
Then
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119
Since
~(E,f) = _111 fG' I fG' f(y/n) ,d~ (x - y) + i(n AE(--Xn) - n AE(Y))
n 1 { ~ ~(Ek,f k) + C }.
<= n n k = l
co
E k E FI' fk E Lreal, 0 < f < i, we have ~(n) < co.
2 f(~) dx
Q .E .D.
Lemma 4,3.
Proof. For
The following Lemma is analogous to Lemma 3.4.
~(22n) ~ 2 ~(2 n) + Const ~(22n) I/2 (n ~ i).
E E F22 n, we define
F = U (the projection of E N {(k-l)2 -n ~ Im z < k 2 -n}
to the line Im z = (k-l)2-n).
Then F E F . Let 2 n
G = pr(E),
G. = pr(E [~ {(j-l)2 -n _< Re z < j 2-n}), j
Gj, k = pr(E n {(j-l)2 -n _<_ Re z < j 2 -n, (k-l)2 -n <Im z < k 2-n})
(j = 1 ..... 2 n, k = O, +i, ...).
We have, for f 6 Lreal, 0 ~ f $ i,
~(E,f) = ~(F,f)
+ I G (T E - TF)(XGf)(x ) TE(XGf)(x) f(x)dx
+ I G TF(XGf)(x) (T E - TF)(XGf)(x) f(x)dx
= ~(F,f) + L (I) + L (2)
and
2 n L (I) =
j=l 2 n
+Z j=i
IG (T E - TF)(XG f)(x) TE(XG f)(x) f(x)dx J 3 ]
fG (TE - TF)(XG f)(x) TE(XG_G f)(x ) f(x)dx J J J
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120
2 n Z
j=l IG_G. (T E -TF)(XG.f)(x) TE(XGf)(x) f(x)dx
J J
L I + L 2 + L 3.
For i <_- j _<- 2 n, there exists E!j ( F2n, F'j E F I and f.3 E L "real, 0 =< fj
such that I Eli = I F ]I = 2niGjl,
IG" ITE(XG. f) (x) 12 J J
fG. I TF(XG. f)(x) 1 2 ] J
f(x)dx = 2 -n <(E],fj)
f(x)dx = 2 -n ~(F],fj).
Hence
ILII _-<
2 n + z
j=l
2 n
Z IG ITE(XG.f)(x)I 2 f(x)dx j=l j j
{IG. ITF(XG f)(x)i2f(X)dx}i/2{IG.ITE(XG.f)(x)i2f(x) dx} I/2 J J J J
2-n
<(2 n)
2 n 2 n % ¢(E',fj)j + 2 -n Z
j =i j =I <(F~,fj) I/2 <(E],fj) I/2
2 n 2 n Z IgjI + ~(i) I/2 ~(2n) I/2 Z IGjI
j =i j =i
= IGI {~(2 n) + ~(i) I/2 <(2n) I/2} .
Since F2n c F22n, we have <(2 n) ~ <(22n). Thus Lemma 4.2 yields that
}LII ~ IGI {~(2 n) + Const <(22n) I/2} .
Let xj = (j-l)2 -n and Gj = Gj_ 1 U Gj U Gj+ I (i ~ j ~ 2n), where G O
Then, for any x E G - G., J
2-n I (T E - T F)(X Gjf)(X) I --< Const fG.3 (x_y)2 + 2-2n
2-niGj I _-< Const - .
(x-xj)2 + 2-2n
For any g E L 2, we have
f(y)dy
=< 1
=~.
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121
2 n 2-nlGjl
I~Z Z g(x)dxl j=l (x-xj) 2 + 2 -2n
2 n 2-n Const ~ fG. {f ~ 2-2n
j=l 3 - (x-Y) 2 +
Const ~G M g(x) dx ~ Const ~ llgll 2 ,
Ig(x) Idx} dy
which shows that
Thus
2 n 2-nl G4 j ii Z a 2_2n. iI 2 _<_ Const ~ . j=l (--x j)2 +
2 n
IL31-_< Z j = l
2 n
<= Const
{7 G ~ + ~ } I(TE_TF)(XG f)(X)TE(XGf)(x)l f(x)dx - j fGj-Gj j
2-nlcj j iTE(XGf)(x)if(x)dx 2 2-2n j=l 7G-Gj (x-xj) +
2 n dy_ ) ITE(XGf)(x)I f(x)dx
+ 2 % ~G. -G. (~G 3 j = l J J " Ix-Y[
2 n 2-nlGj I ITE(XGf) (x) I f (x)dx -<_ Const fG { Z 2
j=l (x-xj) + 2 -2n-}
2 n + 2 % {fG.-G. (fG --~ )2dx}i/2 {fG,ITE(Xgf)(x)12 f(x)dx}i/2
j=l 3 3 J 3
2 n =< Const ~(E,f) I/2 + Const E ~IGjl {~ ITm(×Gf)(x)12f( x)dx}I/2
j=l 3
_-< Const ~V~ ~(E,f) I/2 + Const ~ ~(E,f) I/2
_<- Const IGI ~(22n) I/2
Let
Then
G. = Gj U Gj 3 ,k ,k-i ,k U Cj,k+ I (j = 1 .... , 2 n, k = 0, -+i, ...).
2 I%
IL21 =< I E Z j =i k =-~
(TE-TF)(X G f)(x) TE(X G ~ f)(x) f(x)dxl fGj ,k j ,k - J
2 n f)(x) TE(XG_~ f)(x) f(x)dxl + I Z Z ~gj (TE-TF)(XG. U gj
j=l k =-" ,k 3 ,k-i ,k+l 3
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122
2 n
I S Z fG (TE-TF)(XG _~" f)(x) TE(XG_~ f)(x) f(x)dx I j=l k =-- j,k J ],k J
2 n
lj=iS /Gj (TE-TF)(XGjf)(x) TE(X~ _G f)(x)j J f(x)dx I
L21 + L22 + L23 + L24°
We have 2 n
IL241 =< 2 Z {7G. I(TE-TF)(XG f)(x)l 2 f(xldx} I/2 j=l 3 3
dy )2 dx}i/2 ~ Const IGI ~(22n) I/2. × {fg. (fG.-G.
3 J J
Note that ~(2 2n) ->_ ~(i) > Const. Since
I(T E - TF)(XG _~" f)(x)l J J,k
" 2nlGj ,~I < Const (x ~ G ), _-< Const S 2 = j , k
g=-~ (k-u) + i
we have 2 n ,
IL23 I ~ Const S S ~G ITE(XG_ ~ f)(x) I f(x)dx j=i k =-- j ,k j
2 n
= Const E fg. ITE {(XG - XG.-G. - XG.)f}(x)l f(x)dx k =I J 3 J J
=< Const Igl {~(22n) I/2 + i} -<_ Const IGl ~(22n) I/2.
Lemma 4.1 shows that
2 n f)(x)l 2 dx} I/2
IL221 ~ { E E fGj I(TE-TF)(XG UGj j=l k =-- ,k j,k-i ,k+l
2 n x { Z fG. ITE(XG-G. f)(x)12 f(x)dx}i/2
j=l j j
2 n Const { Z S IGj U Gj f(x)2 dx}i/2
j=l k =-- ,k-i ,k+l
× {~(E,f) + 2 n Z f~, ITE(X~ f)(x)12f(x)dx} I/2
j=l 3 3
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123
Const IGI ~(22n) I/2.
Since (TE-TF)(x,y) is anti-symmetric, we have
(TE-TF) (X G f) (x)f (x)dx = 0. fGj ,k j ,k
For Gj, k # ~, we choose a point xj, k on G.j,k. Then
IL211 = I Z (TE-TF)(XC. f)(x) j,k;Gj,k # ~ fGj,k j,k
x {TE(XG_~j f) (x) - TE(XG_~.jf)(xj,k )} f(x)dx
Const Z /Gj,k I(TE-TF)(X G f)(x)If(x)dx j,k;Gj,k# ~ j,k
Const IGl ~(22n) I/2.
Consequently,
IL(1) I ~ Igl {~(2 n) + Const ~(22n) I/2} .
In the same manner,
2 n IL(2) I ~ j=l% 7GJ ITF(XGjf)(X)TE(XGjf)(x)If(x)dx + Const IGI ~(22n) I/2
Since the first quantity in the left hand side of the above inequality is
dominated by Const IGI ~(22n) I/2, we obtain IL(2) l = < Const IGI ~(22n) I/2
Thus
~(E,f) ~ ~(F,f) + IGI {~(2 n) + Const ~(22n) I/2}
IGI {2 ~(2 n) + Const ~(22n) I/2} ,
which yields the required inequality.
We now prove the second inequality in Theorem G.
that
n ~(22n-i) n ~(22 ) =< 2 + Const ~(22 )1/2
~(220) n-i 2k 2 n-k 1/2 2 n + Const E ~(2 )
k=O
n-i 2k ~(22n-k) i/2 } Const {2 n + 7
k=O
Q.E.D.
Lemmas 4.2 and 4.3 show
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124
which yields that ~(22n) < Const 2 n. (See the proof of (2.43).)
denote the integer satisfying 2 n -<_ n < 2 n.
n ~(2 n) =< ~(22 ) =< Const 2 n _-< Const n.
Then
For E E F n and f E Lreal, 0 ~ f ~ i, we put F = [n2
g(x) = f(x 2 n/n). Then F E F Hence we have 2gn "
~(E,f) 2 n gn) = -- ~(F,g) ~ Const IF1 <(2 n
Const IEI gn ~ Const IEI log(n+l),
-g n E ] and
Let n
which gives that
(4.3) ~(n) ~ Const log(n+l) (ng i).
For s I, ..., s n E ~ we put
n
E(s I ..... s n) = U k = i
^ k-1 k {x + Sk, - n- =< x < n },
where ~k = (the integral part of nsk)/n. Then we have, for an interval
I c I 0 and f E Lreal, 0 ~ f ~ i,
,f) ~ Const {3(1, TE(~I ' , Sn ), f) +llI} • ~(I, Tsl ..... Sn ...
Hence (4.3) shows that $(I, T ,f) ~ Const [I[ log(n+l). Since s I, ..., s n
Tsl ..... sn(X,y) = i/(x-y) (x, y ~ I0) , this inequality gives
^
~(Tsl ' .--, Sn) ~ Const log(n+l). Consequently,
) ~ Const $(T )1/2 ~ Const~log(n+l). °(Tsl, ..., s n s I, ..., s n
Since s I, ..., s n E ~ are arbitrary, the second inequality in Theorem G holds.
This completes the proof of Theorem G.
Let BMO(F) denote the Banach space of functions f on a finite union F
of segments, modulo constants, with norm
1 IIfIIBMo(£) = sup ~£ N D(z,2r) I- /£ N D(z,r) If(z) - (f)r N D(z,r) IidzI '
is the mean of f over r n D(z,r) with respect to Idzl where (f)r N D(z,r)
and the supremum is taken over all z E ¢, r > O° Put
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125
r = {(x, A I 0) Sl' .... Sn Sl' .-., sn(X)); x E .
Corollary 4.4. Const'~og(n+l)
Theorem G immediately yields
max{IIH r II
Sl, ..., s n L (FSl ' ), BM0(Fsl ' ) °°'~ S N °''~ S n
; s I, ..., s n ~ ~ }
=< Const ~log(n+l) (n ~ i) ,
where IIHpII , is the norm of H F L (F),BM0(F)
BM0(F).
as an operator from L'(F) to
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APPENDIX II. PROOF OF THEOREM B BY
P. W. JONES-$. SEMMES
Quite recently, P. w. Jones-S.Semmes gave a proof of Theorem B by complex
variable methods. The following note is their lecture in M~y, 1987. (The author
expresses his thanks to P. W. Jones-S.Semmes who permitted the author to write
here their proof (cf. P.W. Jones [33]). Here is a fact obtained by C. Kenig.
Lemma 4.5. Let F = {x + iA(x); x ( ~} be a Lipschitz graph and
= {z 6 ~; Im z > A(Re z)} . Then, for any g (L2(F) having an analytic
extension, say simply g(z) (z (~), to ~ ,
(4.4) IIglIL2(F ) ~ C M {ifzig'(z)I 2 dis(z,F)d~(z)} I/2,
where d a is the area element and C M is a constant depending only on
M = IA'II.
For z ( ~, we write
Cf(z) = C(f d~IF)(z) (z £ ~)
* L2(F) z = z - 2i(Im z - A(Re z)). For f 6 , we put
, i.e.,
1 f(~) d~. ~f(z) = 2hi IF ~ - z
For z ( F, we write by ~f(z) the nontangentlal limit of
at z. For z 6 F U ~, we have
Cf(~) (~ ~ ~ )
~f(z) = - i ~ (Cf) i (z + i t ) d r = ~ (Cf)"(z + i t ) t dt
1 I~ {I F (If)'(< + it/2)t d~} dt 2~i (z+(it/2) - ~)2
2 (Cf)'(w) ~-y IIi --- -- {Im w - A(Re w)} {~ + iA'(Re w)} do(w)
(z - w*) 2
Let {Qk}i= 1 be a sequence of mutually disjoint cubes (with sides parallel to
the coordinate axes) such that ~ = Ok=l Qk' dk/CM ~ Z(Qk ) ~ CMdk (k { i), where
6(Qk ) is the length of a side of Qk and d k = diS(Qk,F). Then
(Cf)'(w) {Im w - A(Re w)}{~ + iA'(Re w)} do(w), - SSQk (= - w*) 2
IfQk Ilm w - A(Re w) I do(w) ~ C M diS(Qk,F) 3 (k ! i).
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127
Hence
~ " dk 2 (4.5) ][CfIIL2(F ) --< C M sup I] Z Ck(~f)'(z k) ( , ) I]L2(F),
k=l z - z k
where the supremum is taken over all sequences co
{Ck}k= 1, {Zk}k= 1 such t h a t [Ckl ~ d k, z k E Qk (k ~ i). Let M 2 denote the 2~dimension maximal operator.
For two sequences {Ck}k= I, {Zk}k= 1 satisfying the above condition, we define a
function h(~) on C by
h(~) = Ck(Cf)'(z k) dk I/2 ( ~ E Qk' k ~ i), h(~) = 0 ( ~ E ¢ - ~).
Then Lemma 4.5 shows that
(4.6) " dk )2
l[ Z C k ( ~ f ) ' ( z k) ( -- , k=l z - z k IIL2(F)
2
I k Ck(Cf)'(Zk) --dk * 3 12 =< CM {ff~ =El (z - z k) dis(z,F) do(z)} I/2
C M {ff~ ]ff¢ h(~)] IN ~]I/211m z~ I/2 ]z - ~*[3 da(~)12 da(z)}i/2
CM {ff~ M2 h(z) 2 d~(z)}i/2 ~ CM {ffc lh(z) 12 d~(z)}I/2
" ]2 dk}i/2 " C M { Z ICk(Cf)'(z k) ~ C M { Z k=l k=l
l(~f),(Zk)i 2 , 3 . 1 / 2 a k ) •
Let G
Then
denote the totality of sequences {~k}k= I such that
12 .3~i/2 (4.7) [ Z l(Cf)'(z k) ak# k=l
2j = sup {I Z (Cf)'(Zk) ak de '
k=l
Lemma 4.4 shows that, for any {~k}k=l E G,
(4.8) I k=iZ (Cf)'(Zk) ek dk2 I - 2~i
i < IIftl II z = 2~ L2(F) k= I
< C M llf[IL2(r ) { ff¢_f~
{~k}k=l E G} .
[ f r f(z) Z k=l
2 d k
ek - II L2(F) (z Zk )2
2 dk 12
IkZ=l ~k (z - Zk )3
k=l ~k~2dk = i.
2 d k
dz I ~k 2 (Z - z k)
dis(z,F) do(z) }1/2
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128
{ Z I~k 12 d k } l / 2 < IlfllL~(n. CM Ilfllc2(r) k=l = ct~
Thus (4.5)-(4.8> show that Ilcfll ~ cM Ilfll , which yields Theorem B. L2(F) L2(F)
The proof of Lemma 4.5 by P.W.Jones-S.Se~nes is as follows. Put
A = Ilgll~2(r) , B = ff~ Ig'(z)I 2 dis(z,F) do,z). Let ~(z) be a conformal one
to one mapping form the upper half plane U to ~. Then
A = f ~ Ig ° ~(x)1 2 I~'(x) i dx
S = flu Ig'° ¢(z) 12 dis(¢(z),r) l¢'(z) l 2 do(z)
Koebe's i/4-theorem shows that dis(~(z),F) ~ l~'(z) l(Im z)/4 (z 6 U), and hence
flu Ig'° ~(z) 12 l~'(z) I3 y do(z) ~ Const B.
Since larg ~'(x) I ~ g/2 - (i/M) (x ~ ~), Green's formula shows that
A ~ C M [f_~ Ig o ~(x) I 2 ~'(x) dx I
= CM [ffu A(Ig o O(z) I 2 ~'(z)) y do(z) I
i C M {flu [g'° ~(z) 12 [O'(z) 13 y do(z)
+ ffu ](g'o ¢)(z)(g o ¢)(z)]l¢'(z)[ 2 ]¢"(z)] y do(z)}
=< CM[B + Bl/2{fYuig ° ~(z) 12[~'(z)l ~ (z) 2 y do(z) I/2].
We can write ~'(z) = e V(z) with an analytic function V(z) in U. Then
V E BMO since Im V ~ L ~. Thus
I¢"(z)/¢'(z)l 2 y dy dx ( = Iv'(s)I 2 y dx dy )
is a Carleson measure in U. Since g o @(z) e V(z)/2 is analytic in U,
~"(z) 2 }1/2 AI/2. {flu [g ° ~(z) 12]~'(z)I ~(z) y do(z) ~ C M
Thus A g CM(B + BI/2AI/2), which yields the required inequality.
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SUBJECT INDEX
Ahlfors function 80
analytic capacity y(E) 71
Area integral 2
BMO 1
Buffon needle probability 105
Bu(E) 105
Calderdn commutator T[a] 1
Calder6n's problem 82
Calder@n's theorem 1
Calderdn-Zygmund decomposition
Carleson measure 6
Cauchy-Hilbert transform H F 68
Cauchy transform C 71
chord-arc curve 68
Coifman-Meyer expression 9
Coifman-Meyer-Stein's theorem ii
Cotlar's lemma 17
Covering Lemma 32
crank 83
Crofton's formula 105
126
Cra(E) 105
E[a] 51
E 21
ex (n) 83 o
fat crank 99
Galton-Watson process 106
Garabedian function 80
Garnett's example 80
generalized length 71
Good % inequalities 4
Green's formula 5
Hilbert transform 7
integralgeometric quantity 105
33
Interpolation 21
John-Nirenberg's inequality
locally chord-arc 71
LP( - ) 68
Lreal 31
L(r,0) i05
L~(.) 72 maximal operator M 34
Mclntosh expression 13
NE(r,6) 105
Poisson kernel 3
Prob 105
Rising Sun Lemma 32
separation theorem 74
T-atom 1.1
T-atomic decomposition 13
Tb theorem 15
tent space ii
T1 theorem 16
Tn[a] 31
Vitushkin's example 80
¥+(E) 71
8-standard kernel 15
I(F',F) 108
~(E,f) 118
~(n) 118
p(F) 72
p+(F) 72
o-function 35
aC(g) 61
$C(~,B) 61
OE(B) 52
~E(~) 55 o(l,K,f) 25
34
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133
$(I,T,f) 39
@(I,T,f) 39
~(K) 25
~(n) 86
$0(T) 39
~(T) 39
@(T) 39
3(T ;~-~) 39
~0(n) 91
@(n) 86
co6(K) 16