aiesec exos d'exam math i
TRANSCRIPT
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8/13/2019 AIESEC Exos d'exam Math I
1/4
f(x) =ex +exx
ca
f(x)dx=
ba
f(x)dx+
cb
f(x)dx
a < b < c.
2
4 |x+ 2|dx=
c
12
f(x)dx= 0
f(x)
f(x) =
x
x
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8/13/2019 AIESEC Exos d'exam Math I
2/4
0
ex
1 +exdx=
a+1a
2(x a)e(xa)2
dx=
T
T1
ln(x)
x2 dx=
limT
T1
ln(x)
x2 dx=
A
B
C
3x2 + 7x+ 2
(x+ 1)2(x+ 3)=
A
x+ 1+
B
(x+ 1)2+
C
x+ 3.
10
3x2 + 7x+ 2
(x+ 1)2(x+ 3)dx=
xn
xn= 1
(n+ 1)5n
xn= n+ 2
(n+ 1)n
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8/13/2019 AIESEC Exos d'exam Math I
3/4
xn=4n
n2
yn=4n
n
+
zn =
4n +n
4n + 2n
.
f(x, y) =e(x3
3+xy2)
Y =f(K, L) = Kln aK+L +bK3L1
a R+
b R+
f(x; y) =x ln(xy) 2y x,
xy >0.
x2 +y2 +z2 = 10
P(0;1;3)
f(x; y) =e(yx2).
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8/13/2019 AIESEC Exos d'exam Math I
4/4
t+ 3x+ 3y+ 5z = 12x+ 4t+ 2y = 1
6z+ x+y+ 8t = 44y = 3.
Ay=b
A
f
xyz
=
x+ 3y+ z4x+ 2y+z8x+y+ 4z
.
f
v=
xyz
f(v) =
101122
.