algebra 2 traditional 9-14-2012. rfa 9-14 1) solve the following absolute value equality: 2+|x-8| =...
TRANSCRIPT
Algebra 2 Traditional9-14-2012
Representing the solutions of equalitiesYou can think of the solution(s) to a
given equation as solution sets.Equation Set notation Interval
notation3x+1 = 10
2x + 1 = 2x + 1
3x+4 = 3x – 7
Representing the solutions of equalitiesYou can think of the solution(s) to a given
equation as solution sets.Equation Set notation Interval
notation3x+1 = 10 {3} [3]
2x + 1 = 2x + 1 {x| x is a real number}
3x+4 = 3x – 7 { } ( )
( ,
Representing the solutions of in-equalities-2x + 4 > 8-2x > 4X < -2
{x| x<-2} (set builder notation)(-∞, -2) (interval notation)Number line (Draw below)
Quick final note…If an inequality includes an “or
equal to” part, that part remains even if you need to flip the inequality.
3 27
9
x
x
Before the next section: Operations with SetsGoals:
◦Know what it means to find the “intersection” and “union” between multiple sets.
◦Be able to graph unions and intersections on number lines
◦Define what an empty set, or “null” set is
Union & IntersectionsUnion: the set of elements in one set,
another, or both means the union of sets
“A” and “B”
Intersection: The set of elements that are in two sets at the same time
means the intersection of sets “F” and “G”
A B
F G
Pictorial Representations
Null or Empty SetsSets with no
elements in them are called null or empty sets.
{ } OR
Union and Intersection on the number lineUnion
x<4 OR x>0
Intersection
x<4 AND x>0
Absolute Value InequalitiesEverything you EVER wanted to know
about |2x-3|=, <, or > 9!
Type of Absolute Value
Problem|ax+b|
What it means in terms of distance
What kind of solution you are going to
get
|ax+b|=k
A specific distance “k” (to the left or right) away from zero on number line
|ax+b|>k
Two inequalities that won’t
overlap (so link them with a “U”)
|ax+b|<k
ax+b is BETWEEN “k” distance from zero to the left
and “k” distance to the right
Type of Absolute Value
Problem|ax+b|
What it means in terms of distance
What kind of solution you are going to
get
|ax+b|=k
A specific distance “k” (to the left or right) away from zero on number line
Two specific solutions
(assuming k>0)
|ax+b|>k
ax+b must be AT LEAST “k”
distance away from zero on number line
Two inequalities that won’t
overlap (so link them with a “U”)
|ax+b|<k
ax+b is BETWEEN “k” distance from zero to the left
and “k” distance to the right
Two inequalities that intersect, so
find the intersection
interval
Group Work/HWGroup Work:1.7 1-14
Homework1.715-43 oddTest early next week on chapter
1!